A long, thin solenoid has 900 turns per meter and radius 2.50 cm. The current in the solenoid is
increasing at a uniform rate of 60.0 A/s. What is the magnitude of the induced electric field at a
point near the center of the solenoid and (a) 0.500 cm from the axis of the solenoid; (b) 1.00 cm
from the axis of the solenoid?
Answers
A) The magnitude of induced electric field 0.5 cm is \(1.7\times 10^{-4} V/m\)
B) the magnitude of induced electric field 1.0 cm is \(3.4 \times 10^{-4} V/m\)
As per given in the question,
number of turns of a thin solenoid ( n) is 900
the change in current in solenoid ( \(\frac{di}{dt}\) ) is 60
radius of the solenoid ( r ) is 2.5cm
by using the formula of solenoid
\(B = \mu_0ni\)
where
B is the solenoid magnetic flux
N is the number of turns
I is the current
\(\mu_0\) is the magnetic constant
\(\frac{db}{dt} =\mu_0n\frac{di}{dt}\)
=> (4\(\pi\) x \(10^{-7}\)) ( 900) (60)
=>\(\frac{db}{dt}\) = 0.068 T/s
Using the derived electric field equation,
E = \(\frac{r}{2} (\frac{db}{dt} )\)
a) electric field at 0.5 cm is
\(E=(\frac{0.5\times10^{-2} }{2} )(0.068)\)
=> 1.7 x \(10^{-4}\) V/m
b) electric field at 1.0 cm is
\(E=(\frac{1\times10^{-2} }{2} )(0.068)\)
=> 3.4 x \(10^{-4}\) V/m
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Related Questions
The average reaction time is 1.5 seconds?
True
False
Answers
Answer:
false
Explanation:
The average reaction time for humans is 0.25 seconds to a visual stimulus, 0.17 for an audio stimulus, and 0.15 seconds for a touch stimulus.
Anyone can help?? I need this done before 9am please!!
Answers
Answer:
The slopes for each of the four line segments are \(a_{A} = 6\,\frac{m}{min^{2}}\), \(a_{B} = 0\,\frac{m}{min^{2}}\), \(a_{C} = -4\,\frac{m}{min^{2}}\) and \(a_{D} = 2.667\,\frac{m}{min^{2}}\), respectively.
Explanation:
There are four line segments:
(i) Line A: \(v(0\,min) = 0\,\frac{m}{min}\), \(v(10\,min) = 60\,\frac{m}{min}\)
(ii) Line B: \(v(10\,min) = 60\,\frac{m}{min}\), \(v(15\,min) = 60\,\frac{m}{min}\)
(iii) Line C: \(v(15\,min) = 60\,\frac{m}{min}\), \(v(40\,min) = -40\,\frac{m}{min}\)
(iv) Line D: \(v(40\,min) = -40\,\frac{m}{min}\), \(v(55\,min) = 0\,\frac{m}{min}\)
The slope of each line segment represents the acceleration of the particle, which can calculated by the geometrical concept of secant line. Hence, we proceed to determine the acceleration associated with each line segment:
Line A
\(a_{A} = \frac{v(10\,min)-v(0\,min)}{10\,min-0\,min}\)
\(a_{A} = \frac{60\,\frac{m}{min}-0\,\frac{m}{min}}{10\,min-0\,min}\)
\(a_{A} = 6\,\frac{m}{min^{2}}\)
Line B
\(a_{B} = \frac{v(15\,min)-v(10\,min)}{15\,min-10\,min}\)
\(a_{B} = \frac{60\,\frac{m}{min}-60\,\frac{m}{min} }{15\,min-10\,min}\)
\(a_{B} = 0\,\frac{m}{min^{2}}\)
Line C
\(a_{C} = \frac{v(40\,min)-v(15\,min)}{40\,min-15\,min}\)
\(a_{C} = \frac{-40\,\frac{m}{min}-60\,\frac{m}{min} }{40\min-15\,min}\)
\(a_{C} = -4\,\frac{m}{min^{2}}\)
Line D
\(a_{D} = \frac{v(55\,min)-v(40\,min)}{55\,min-40\,min}\)
\(a_{D} = \frac{0\,\frac{m}{min}-\left(-40\,\frac{m}{min} \right) }{55\,min-40\,min}\)
\(a_{D} = 2.667\,\frac{m}{min^{2}}\)
The slopes for each of the four line segments are \(a_{A} = 6\,\frac{m}{min^{2}}\), \(a_{B} = 0\,\frac{m}{min^{2}}\), \(a_{C} = -4\,\frac{m}{min^{2}}\) and \(a_{D} = 2.667\,\frac{m}{min^{2}}\), respectively.
Which interaction has the highest electrostatic potential energy?
O A +2 and -2 particle separated by a distance of 5 nm.
O A +1 and -2 particle separated by a distance of 5 nm.
O A +2 and +2 particle separated by a distance of 10 nm.
O A +2 and -2 particle separated by a distance of 10 nm.
O A +2 and +2 particle separated by a distance of 100 nm.
O A +1 and -2 particle separated by a distance of 10 nm.
O A +2 and +2 particle separated by a distance of 5 nm.
Answers
Answer:
The interaction with the highest electrostatic potential energy is:
A +1 and -2 particle separated by a distance of 5 nm.
Explanation:
The electrostatic potential energy between two charged particles depends on the magnitude of their charges and the distance between them. The formula for calculating electrostatic potential energy is:
U = k * (q1 * q2) / d
where U is the electrostatic potential energy, k is Coulomb's constant, q1 and q2 are the magnitudes of the charges, and d is the distance between them.
In the given options, the interaction between +1 and -2 particles separated by a distance of 5 nm has the highest electrostatic potential energy because the charges have a higher magnitude (compared to other options) and they are close to each other, resulting in a stronger electrostatic force of attraction. The other options either have smaller charges, larger distances, or both, leading to lower electrostatic potential energy.
what is microeconomics
Answers
Answer:
Microeconomics is a part of economics and the study of decisions made by people and businesses regarding the allocation of resources, and prices at which they trade goods and services.
Microeconomics helps business planning i.e. helps the business community to plan their costs, production, etc. in anticipation of demand in order to maximize profits. Microeconomics is useful in explaining how market mechanism determines the price in a free market economy.
A room of volume 33 m³ contains air having
an average molar mass of 43.5 g/mol.
If the temperature of the room is raised
from 16.4°C to 25°C, what mass of air will
leave the room? Assume that the air pressure
in the room is maintained at 121.8 kPa.
Answer in units of kg.
Answers
The mass of air that will leave the room is 2.1 kg.
What is the number of moles of air in the room?
The number of moles of air in the room is calculated by applying Ideal gas law as shown below.
PV = nRT
where;
P is the pressure of the roomV is the volume of the air = 33m³ = 33,000 Ln is the number of moles of the airR is ideal gas constant = 8.314 kPa.L/K.molT is temperature of the roomWhen the temperature = 25⁰C = 298 K
n = PV / RT
n = (121.8 x 33,000) / (8.314 x 298)
n = 1,622.3 moles
when the temperature = 16.4⁰C = 289.4 K
n = PV / RT
n = (121.8 x 33,000) / (8.314 x 289.4)
n = 1,670.5 moles
difference in number of moles = 1,670.5 moles - 1,622.3 moles = 48.22 moles
mass of the air that will leave the room = 43.5 g/mol x 48.22 moles = 2,097.73 g = 2.1 kg
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Suppose glucose and hemoglobin are diffusing in water. A small amount of each is released simultaneously. How much time (in s) passes before the glucose is 8.30 s ahead of the hemoglobin? Such differences in arrival times are used as an analytical tool in gas chromatography.
Answers
Given:
Time = 8.30 s ahead of the hemoglobin
For the equation of both glucose and hemoglobin:
\(\begin{gathered} \sqrt{2D_gt_g}=\sqrt{2D_h(t_g+\Delta t)} \\ \\ D_gt_g=D_h(t_g+\Delta t) \\ \\ D_gt_g=D_ht_g+D_h\Delta_t \end{gathered}\)Rewrite the equation for tg:
\(\begin{gathered} D_gt_g-D_ht_g=D_h\Delta_t \\ \\ t_g(D_g-D_h)=D_h\Delta_t \\ \\ t_g=\frac{D_h\Delta_t}{D_g-D_h} \\ \\ \end{gathered}\)Where:
Dh is the diffusion coefficient of hemoglobin = 6.9 x 10⁻¹¹ m²/s
Dg is the diffusion coefficient of glucose = 6.7 x 10⁻¹⁰ m²/s
Δt = 8.30 seconds
Substitute these values for the variables in the equation and solve:
\(\begin{gathered} t_g=\frac{6.9\times10^{-11}*8.30}{6.7\times10^{-10}-6.9\times10^{-11}} \\ \\ t_g=\frac{5.727\times10^{-10}}{6.01\times10^{-10}} \\ \\ t_g=0.953\text{ seconds} \end{gathered}\)Therefore, the time that passes before the glucose is 8.30 s ahead of the hemoglobin is 0.953 seconds.
ANSWER:
0.953 seconds
Two charges are separated by 0.50 m. One of the charges, Q1, has twice the magnitude of the other, Q2. The distance that separates them is maintained. The magnitude of the electrostatic force that Q1 exerts on Q2 is _____ the magnitude of the electrostatic force that Q2 exerts on Q1. A) the same asB) half as much asC) doubleD) quadruple
Answers
According to Coulomb's law,
The magnitude of the electrostatic force on the charge Q_1 due to the charge Q_2 is,
\(F_{12}=\frac{kQ_1Q_2}{d^2}\ldots\text{.}\mathrm{}(1)\)where k is the electrostatic force constant and d is the distance between the charges,
The magnitude of the electrostatic force on the charge Q_2 due to the charge Q_1 is,
\(F_{21}=\frac{kQ_2Q_1}{d^2}\ldots\ldots\text{.}(2)\)From the equation (1) and (2),
The electrostatic force on charge Q_2 due to the charge Q_1 is the same as the electrostatic charge on Q_1 due to the charge Q_2.
Hence, option A is the correct answer.
Which of the following objects will have more kinetic energy?
Kinetic Energy =
(Joules)
12 x mass x (velocity)?
(kg) (m/s)
KE = 12 mv
O A 6 kg ball thrown a 8 m/s.
O A 2 kg ball thrown at 15 m/s.
O A 4 kg ball thrown at 10 m/s.
Answers
Exercise 1 - Questions 1. Hold the grating several inches from your face, at an angle. Look at the grating that you will be using. Record what details you see at the grating surface. 0 Words 2. Hold the diffraction grating up to your eye and look through it. Record what you see. Be specific. 0 Words 3. Before mounting the diffraction grating, look through the opening that you made for your grating. Record what you see across the back of your spectroscope.
Answers
Answer:
1) on the surface you can see the slits with equal spacing, on the one hand and on the other hand it is smooth.
2)If the angle is zero we see a bright light called undispersed light
For different angles we see the colors of the spectrum
3) must be able to see the well-collimated light emission source
Explanation:
1) A diffraction grating (diffraction grating) is a surface on which a series of indentations are drawn evenly spaced.
These crevices or lines are formed by copying a standard metal net when the plastic is melted and after hardening is carefully removed, or if the nets used are a copy of the master net.
The network can be of two types of transmission or reflection, in teaching work the most common is the transmission network, on the surface you can see the slits with equal spacing, on the one hand and on the other hand it is smooth.
The number of lines per linear mm determines which range of the spectrum a common value can be observed to observe the range of viable light is 600 and 1200 lines per mm.
2) when looking through the diffraction grating what we can observe depends on the relative angle between the eye and the normal to the network.
If the angle is zero we see a bright light called undispersed light
For different angles we see the colors of the spectrum, if it is an incandescent lamp we see a continuum with all the colors in the visible range and if it is a gas lamp we see the characteristic emission lines of the gas.
3) Before mounting the grid on the spectrometer, we must be able to see the well-collimated light emission source, this means that it is clearly observed.
The spectrometers have several screws to be able to see the lamp clearly, this is of fundamental importance in optical experiments.
Robert, my neighbor, a forty-five-year-old blacksmith is seven feet tall, and eats all day long. What does he weigh?
Answers
The neighbour weighs Iron. As he is a blacksmith, iron is the only thing he weighs the whole day.
What is a riddle?A riddle is a statement, question or phrase having a double or veiled meaning, put forth as a puzzle to be solved.
If Robert, your neighbor, a forty-five-year-old blacksmith is seven feet tall, and eats all day long, based on these statements, we can explain the riddle as Robert weighs iron for the fact that he is a blacksmith, iron is the only thing he weighs the whole day.
Thus, the correct explanation for the riddle is " The neighbour weighs Iron. As he is a blacksmith, iron is the only thing he weighs the whole day.
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Question 5 of 10
Which of the following is most likely to happen when energy is transferred to
an object?
O A. The force on the object will decrease.
O B. The object will begin to move.
O C. The object will stay exactly the same.
O D. The mass of the object will increase.
Answers
Answer:
B: The object will start moving
Explanation:
If energy is transferred the object will definitely change so it can't be a. If you add energy the object will have more force so it cant be c. The mass of an object can't increase just by giving an object energy so it cant be d
Please match the units with the type of measurement.
1.Distance
2.Power
3.Energy
4.Resistance
5.Force
1. Watt
2. Ohm
3. Lightyear
4. Newton
5. Joule
Answers
Answer:
1distance --------- lightyear
2power------------- watt
3energy ----------- joule
4resistance ------ Ohm
5Force---------------- Newton
Entropy can only be decreased in a system if ?
Answers
Answer:
heat is removed.
Explanation:
hope this helps.
Answer:
energy is removed.
Because entropy is a dynamicquality realting to the system being unavaliable to do conversions because of the energy measures being low.
If the velocity of a particle is nonzero, can the particle’s acceleration be zero? Explain.
Answers
If a particle's velocity is nonzero, then its acceleration can be zero, because acceleration is the rate of change of velocity. If the velocity is constant and does not change, the acceleration is zero.
What is acceleration?The rate of change of an object's velocity with respect to time is defined as acceleration. Vector quantities are accelerations. The orientation of an object's acceleration is determined by the orientation of its net force.
Because velocity is both a speed and a direction, there are only two ways to accelerate: modify your speed or your direction—or both.
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1) A squirrel falls from a tree. After a brief rest, the squirrel begins to accelerate until it reaches a velocity of
5.8 m/s. If the squirrel ran a total of 15 m, what would be its acceleration ?
Answers
so; 15/5.8 = 2.5862069 s
In a simple model of the hydrogen atom, the electron moves in a circular orbit of radius 0.053 nm around a stationary proton. Part A How many revolutions per second does the electron make
Answers
We know charge of the electron which for both Q1 and Q2, e = 1.60 x 10^-19 C
The Coulombs Constant k = 9.0 x 10^9
Radius r = 0.053 x 10^-9m = 5.3 x 10^-11 m
Mass of the Electron = 9.11 x 10^-31
F = k x Q1 x Q2 / r^2 = m x v^2 / r(centripetal force)
ke^2 / r^2 = m x v^2 / r => v^2 = ke^2 / m x r
v^2 = ((1.60 x 10^-19)^2 x 9.0 x 10^9) / (9.11 x 10^-31 x 5.3 x 10^-11 )
v^2 = 4.77 x 10^12 = 2.18 x 10^6 m/s
Since one orbit is the distance,
one orbit = circumference = 2 x pi x r; distance s = v x t.
v x t = 2 x pi x r => t = (2 x 3.14 x 5.3 x 10^-11) / (2.18 x 10^6)
t = 33.3 x 10^-11 / 2.18 x 10^6 = 15.27 x 10^-17 s
Revolutions per sec = 1 / t = 1 / 15.27 x 10^-17 = 6.54 x 10^15 Hz
Two blocks are connected to identical ideal springs and are oscillating on a horizontal frictionless surface. Block A has mass m, and its motion is represented by the graph of position as a function of time shown above on the left. Block B’s motion is represented above on the right. Which of the following statements comparing
block B to block A is correct?
(A) Because block B covers more distance per cycle than block A, block B takes more time to complete each
cycle.
(B) Because the spring attached to block B is initially stretched a greater distance, the spring constant is smaller
and therefore block B has a slower average speed than block A does.
(C) Because block B has more mass, it has a slower average speed than block A does.
(D) Because block B has more mass, its acceleration is smaller than that of block A at any given displacement
from the equilibrium position.
Answers
Hi there!
We can begin by identifying key characteristics of both graphs.
Graph A.
Looking at the graph, we can see that the maximum distance (amplitude) is 10 cm (0.1 m). Additionally, its period (T) is 2 seconds (one full cycle).
We also know that:
\(T = 2\pi \sqrt{\frac{m}{k}}\)
We can use this equation to compare with the other graph. Notice how the period does NOT depend on how far the spring is stretched. We can eliminate choice A for this reason.
Graph B.
The amplitude is 20 cm (0.2 m), and each period is 4 seconds.
We can now eliminate choice B because the springs are identical, so their spring constants are equal. Distance stretched has no impact on the spring constant.
For the other choices, we must look at forces and work.
Recall that:
Spring potential energy = \(\frac{1}{2}kx^2\)
Kinetic energy = \(\frac{1}{2}mv^2\)
Using the work-energy theorem:
\(\frac{1}{2}kx^2 = \frac{1}{2}mv^2\)
Even if the mass of Block B is greater, its displacement is larger than that of Block A. Since displacement is squared in this equation, it would have a greater effect on the speed. Thus, Choice C is incorrect.
Using Hooke's Law:
\(\Sigma F = -kx\\\\ma = -kx\\\)
\(a = \frac{-kx}{m}\)
If the mass is greater, the acceleration will be smaller. Choice D is correct.
How many significant figures are there in each of the following?
(a) 85.8 + 0.9
Answers
Answer:
86.7
Explanation:
sana makatulong yung answer ko
What are the two types of precipitation?
In precipitation, rainwater can fall as either
Answers
In precipitation, Rainwater can fall as either Liquid or Solid.
Precipitation is a part of the water cycle. Precipitation falls to the floor as snow and rain. It subsequently evaporates and rises back into the surroundings as a gas. In clouds, it turns back into a liquid or stable water, and it falls to Earth again
The water cycle shows the non-stop motion of water within the Earth and its surroundings. it's miles a complex system that consists of many one-of-a-kind techniques. Liquid water evaporates into water vapor and condenses.
There are four fundamental ranges in the water cycle. they are evaporation, condensation, precipitation, and collection. permit's examined every one of these ranges. Evaporation: that is whilst warm temperature from the sun causes water from oceans, lakes, streams, ice, and soils to upward push into the air and grow to be water vapor.
Disclaimer: your question is incomplete, please see below for the complete question.
Liquid
Steam cloud
2nd half
Steam
Solid
Cloud
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While sliding a couch across a floor, Hannah and Andrea exerts forces FH and FA on the couch. Hannah's force is due north with a magnitude of FH = 59 N and Andrea's force is θ = 22° east of north with a magnitude of FA = 155 N. In this problem, use a coordinate system with y directed north and x directed east.
Part (a) Find the net force in the y-direction in Newtons.
Part (b) Find the net force in the x-direction in Newtons.
Part (c) Calculate the angle in degrees north of east of the net force exerted on the couch by Hannah and Andrea, F HAF→HA.
Part (d) Hannah and Andrea's housemates, David and Stephanie disagree with the move and want to prevent its relocation. Their combined force F DSF→DS must be equal and opposite to that of FHAF→HA. What is the magnitude in Newtons of the force F DSF→DS which will prevent the relocation?
Answers
Answer:
a) 202.7 N
b) 58.1 N
c) 74.1º N of E.
d) 210.9 N
Explanation:
a)
The net force exerted in the y-direction, will be the sum of FH (which is directed northwards) and the y-component of FA.Since the magnitude of FA is 155 N and the angle of FA with the y-axis, is 22º (E of N), we can find the N-S component of FA, just applying the the definition of cosine, to the triangle defined by FA, the y- axis and a segment parallel to the x- axis between FA and the y-axis, as follows:\(F_{Ay} = F_{A} * cos \theta = 155 N* cos 22 = 143.7 N (1)\)
⇒ Fy = FH + FAy = 59 N + 143.7 N = 202.7 N (2)
b)
We can proceed exactly in the same way for the x-axis. Since FH is directed due North, it has no component along the x-axis.So, Fx is directly the component of FA along the x-axis, which can be found applying the definition of sine to the same triangle than in a) as follows:\(F_{x} = F_{A} * sin \theta = 155 N* sin 22 = 58.1 N (3)\)
c)
Taking the same triangle than in a) and b), we can apply the definition of tangent, in order to find the angle between F and the x-axis, as follows:\(tg \theta = \frac{F_{y}}{F_{x}} = \frac{202.7N}{58.1N} = 3.5 (4)\)
⇒ θ = tg⁻¹ (3.5) = 74.1º N of E. (5)
d)
In order to be equal and opposite to the combined force FH+FA, it must have the same magnitude.This magnitude can be found applying the Pythagorean Theorem to the same triangle that we used in a), b) and c):\(F_{DS} = \sqrt{(F_{x} ^{2} +F_{y} ^{2})} = \sqrt{(58.1N)^{2}) + (202.7N)^{2} } = 210.9 N (6)\)
In a circus act, a 55.5 kg clown with 2.5 m/s horizontal velocity jumps into the air and is caught by a 72.5 kg clown, who was initially at rest. The clown is sitting on a sheet of ice, and moves off at some new velocity, after the two clowns are stuck together. How much kinetic energy is lost during this process?
Answers
Given that the mass of clown 1 is m1 = 55.5 kg
Mass of clown 2 is m2 = 72.5 kg
The initial velocity of clown 1 is
\(v_i1\text{ = 2.5 m/s}\)The initial velocity of clown 2 is zero as it is at rest.
\(v_i2\text{ = 0 m/s}\)After the collision, the mass of the clown will be added up as they are stuck together.
So, the mass after the collision will be
\(m1+m2\text{ = 128 }kg\)According to conservation of momentum,
\(m1v_i1+m2v_i2=(m1+m2)v_f\)Here, v_f is the final velocity that is after the collision.
Substituting the values, the final velocity will be
\(\begin{gathered} v_f=\frac{m1v_i1+m2v_i2}{\mleft(m1+m2\mright)} \\ =\frac{55.5\times2.5+72.5\times0}{128} \\ =1.08\text{ m/s} \end{gathered}\)Kinetic energy lost during this process will be
\(\begin{gathered} \Delta K.E.\text{ = }K.E._{f\text{inal}}-K.E._{\text{initial}} \\ =\frac{1}{2}(m1+m2)(v_f)^2-\frac{1}{2}m1(v_i1)^2 \\ =\frac{1}{2}\times128\times(1.08)^2-\frac{1}{2}\times55.5\times(2.5)^2 \\ =\text{ 74.65-172.5} \\ =-97.85\text{ J} \end{gathered}\)Here, the negative sign indicates the loss in kinetic energy.
Thus, 97.85 J kinetic energy is lost during this process.
3.) A boat is moving south at 15.0, a passenger is walking north along the boat deck at 4.0 and throws a
rock north at 3.0, what is the velocity of the rock when viewed from the boat and the shore? (2)
Answers
Therefore, the velocity of the rock when viewed from the boat will be:
Vrock (boat) = Vrock (passenger) + Vpassenger (boat)
Vrock (boat) = 3.0 m/s north + (-4.0 m/s south)
Vrock (boat) = -1.0 m/s south
So, when viewed from the boat, the velocity of the rock will be 1.0 m/s south.
When viewed from the shore, the velocity of the rock will be equal to the velocity of the boat relative to the shore (15.0 m/s south) plus the velocity of the rock relative to the boat (which we calculated as -1.0 m/s south).
Therefore, the velocity of the rock when viewed from the shore will be:
Vrock (shore) = Vrock (boat) + Vboat (shore)
Vrock (shore) = -1.0 m/s south + (-15.0 m/s south)
Vrock (shore) = -16.0 m/s south
So, when viewed from the shore, the velocity of the rock will be 16.0 m/s south.
Describe what the motion of the rigid system will be if:
a. The first condition for equilibrium is not satisfied.
b. The second condition for equilibrium is not satisfied.
c. Neither condition for equilibrium is satisfied.
Answers
The motion of the rigid system will be (a) linear (b) rotational (c) both linear and rotational
The first condition for equilibrium states that the body must have a net force of zero. This means that when the net force acting on a body is not zero the body will continue to move in a straight path and the motion of the rigid body will be linear.
The second condition for equilibrium states that the body must have zero net torque acting on the body for achieving equilibrium. torque is the rotational equivalent of force. Therefore, when the net torque is not zero, the rigid body keeps rotating which leads to a rotational motion.
When both the conditions of equilibrium are not satisfied the rigid body does not achieve the static equilibrium.
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If a wire of resistance r is stretched to double its length, by what factor does the power dissipated in the wire change (assuming it is hooked up to the same voltage source)? show what R does, Formula: P=V^2/R
Answers
When the length of the wire is doubled while connected to the same voltage source, the power dissipated in the wire falls by a ratio of 4.
The resistance of the wire increases as it is stretched to double its length. This can be seen from the formula for resistance, which is R = ρL/A, where ρ is the resistivity of the material, L is the length, and A is the cross-sectional area of the wire. When the length is doubled, the resistance will also double.
If the wire is hooked up to the same voltage source, the power dissipated in the wire can be calculated using the formula P = V²/R. Here, V is the voltage and R is the resistance. Since R has doubled, the power dissipated will decrease by a factor of 4. This can be seen by substituting 2R for R in the formula:
P' = V²/(2R) = (1/4)(V²/R) = (1/4)P
Therefore, the power dissipated in the wire decreases by a factor of 4 when its length is doubled while it is hooked up to the same voltage source.
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Speed is the rate of change of position expressed as____ Traveled per unit of time
Answers
Answer:
distance
Explanation:
Speed is the rate of change of position expressed as distance travelled per unit of time
HELLLLPPPPPPPPPPPPPPPPPPPPPP PLZZZZ AND THANK YOU
Answers
Answer:
The parents and offspring all have phenotype ww. That leaves 100% probability of short wings and 0% long wings.
Explanation:
If long wings are a dominant trait, that means short wings are recessive. If two short winged flies are crossed, each of their phenotypes are ww. Therefore, each of their offspring also have phenotype ww, or short wings.
Please help I will mark brainlest .
Answers
Answer:
lithium atom
Explanation:
If you search up lithium atom the same atom will come out.
Sorry if it's wrong.
Problem B.2: Escaping a Star (6 Points) It takes many years for a photon produced in a star's centre to reach its surface and escape into space. This is due to its constant interaction with other particles. To estimate the time it takes for a photon to escape a star's interior, we assume that the photon is deflected in equal time intervals into a random direction in a two-dimensional space (i.e., a random walk): At each step i, the photon moves a constant distance in an angle, thus changing its position: cos(4) sin(y) Ai, - c (a) Determine the distance R(n) from the centre (0,0) after n steps.
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Answer:
This problem involves the concept of a random walk, which is a mathematical model of a path consisting of a succession of random steps.
The question asks for the distance, R(n), from the center of a star after n steps of a photon, assuming a 2D random walk.
The random walk in two dimensions has a step length of A_i and the direction of the steps is uniformly distributed in [0, 2π). The change in position after each step can be written in Cartesian coordinates (Δx, Δy), where Δx = A_i cos(θ_i) and Δy = A_i sin(θ_i).
The displacement from the center after n steps is given by the vector sum of all the individual steps. This vector sum can be written in terms of its Cartesian coordinates, (X, Y), where X = Σ Δx and Y = Σ Δy. This sum over n random vectors is itself a random variable. The net displacement R(n) from the center of the star after n steps is given by the magnitude of the net displacement vector:
R(n) = √(X² + Y²)
Because each step is independent and has a random direction, the expected value of the cosine and sine for any step is zero. This means that the expected values of X and Y are both zero.
However, the mean square displacement is not zero. Because the steps are independent, the mean square displacement in each direction is additive. For a 2D random walk:
<X²> = Σ <(Δx)²> = n <(A cos θ)²> = n A²/2
<Y²> = Σ <(Δy)²> = n <(A sin θ)²> = n A²/2
Because <X²> = <Y²>, we can write:
<R²> = <X²> + <Y²> = n A²
So, the root mean square distance (the square root of the mean square displacement) after n steps is:
R(n) = √(<R²>) = √(n) * A
Therefore, the distance R(n) that the photon is expected to be from the center of the star after n steps grows as the square root of the number of steps, with each step having a length A. Please note that this result holds for a 2D random walk. A real photon in a star would be performing a 3D random walk, which would have slightly different characteristics.
An object if mass 30 kg is falling in air and experiences a force due to air resistance of 50 newtons.
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Hi there!
On the object, we know that there are two forces working on the object:
-Force due to gravity (Mg)
-Force due to air resistance
Let the positive direction of the force be downwards (direction of the acceleration)
We can write the summation of forces as:
∑F = Mg - Fa
Plug in values. Let g ≈ 10 m/s²
∑F = 30(10) - 50 = 250N
Find the acceleration using the formula:
∑F = m · a
∑F/m = a
Plug in values:
250/30 = 8.33 m/s²
A student holds Two iron magnets, one in each hand
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Since the like poles a magnet repels, the two south poles would repel more strongly. Option C
What is the magnetic field?The magnetic field is the region in space where the influence of the magnet is felt. We know that a magnet is able to exert a magnetic force on another magnet that happens to enter in to its magnetic field. It is also clear that like poles of magnet repel while unlike poles of a magnet attract.
In this case, a student holds two iron magnets, one in each hand. the south pole of one magnet is pointed toward the south pole of the other magnet; as the magnets get closer to each other, they will repel since they are like poles.
Learn more about magnets:https://brainly.com/question/2841288
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Missing parts;
A student holds two iron magnets, one in each hand. the south pole of one magnet is pointed toward the south pole of the other magnet. as the magnets get closer to each other, they will-
A) attract more strongly
B) attract more weakly
C) repel more strongly
D) repel more weakly