a locker is in the shape of right rectangular prism. its dimensions are as shown.what is the surface area of this locker?

The value of the trigonometric expression sin c - cos c is: s - r

The three most common trigonometric ratios are:

sin x = opposite/hypotenuse

cos x = adjacent/hypotenuse

tan x = opposite/adjacent

We are given that:

sinb = r and cos b = s

Thus, from the diagram attached, we can see that:

sin B = rh/h = r

cos B = sh/h = s

Thus, using trigonometric ratios, we can equally say that:

cos C = rh/h = r

sin C = sh/h = s

Thus:

sin c - cos c = s - r

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Answer:

Step-by-step explanation:

The angles <JKL, <EKL, and <JKE form a full angle which means their sum is equal to 360:

134 + 21x + 6 + 5x = 360 add like terms

140 + 26x = 360 subtract 140 from both sides

26x = 220 divide both sides by 26

x = 8.4 approximately

to find the angle m<JKL replace x with the value we found.

The rational number that can be used to represent the number of points needed for Abraham to get an A will be 1.5.

It should be noted that a rational number is the number that can be written as a fraction. It can be while numbers and decimals have well.

Therefore, since Abraham needs one-half of a point to get an A– in Math, the rational number that can be used to represent the number of points needed for Abraham to get an A willbe 1.5.

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To show that det U = 1, we can use the fact that U'U = I, which implies that U^-1 = U'. Taking the determinant of both sides, we have det U^-1 = det(U') = (det U)^T, where T denotes transpose. But det(U') = det U since U is a square matrix. Therefore, (det U)^2 = det(U'U) = det(I) = 1. Taking the positive square root, we get det U = 1 or -1.

However, the problem statement specifies that det U = 11, which is not possible since det U can only be 1 or -1 for a matrix satisfying U'U = I. Therefore, there must be an error in the problem statement.
To show that det U = 1 when U'U = I. Here's the answer using the provided terms:

Since U'U = I, we can apply the determinant to both sides of the equation:

det(U'U) = det(I)

Now, we use the property that det(AB) = det(A) * det(B), so:

det(U') * det(U) = det(I)

The determinant of the identity matrix is 1, so:

det(U') * det(U) = 1

For an orthogonal matrix like U, det(U') = det(U)^(-1), therefore:

det(U)^(-1) * det(U) = 1

Since det(U)^(-1) * det(U) = 1, it implies that det(U) = 1.

So, the correct option to achieve the desired result is B. det(U') * det(U) = 1.

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Answer:

C) \(-14w+12\)

Step-by-step explanation:

\(10-7w-13-7w+15\)

Group the similar terms together:

\(-7w-7w+10-13+15\)

Add/Subtract the w:

\(-14w+10-13+15\)

Add/Subtract the numbers:

\(-14w+12\)

.............Option B)

Answer:

The answer is 6y - 5x = 18

Step-by-step explanation:

This tells us that c and k must be related such that ck = -0.03.This differential equation tells us that the rate of change of q with time (dq/dt) is equal to a negative constant, -0.03.

This differential equation tells us that the rate of change of q with time (dq/dt) is equal to a negative constant, -0.03. This means that q is decreasing over time. Therefore, c and k must be related such that ck = -0.03, since this constant is the product of c and k. This tells us that c and k must be related, but does not tell us the exact value of either c or k.

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The function that has a greater slope will be B. The broccoli function has the greater slope, which shows that the cost per pound of broccoli is greater than the cost per pound of cauliflower.

It should be noted that a linear function simply means a function whose graph is a straight line.

From the information given, the slope will be:

= (y2 - y1(/(x2 - x1)

= (3.6 - 3)/(3 - 2.5)

= 1.2

The slope for broccoli is 1.2

The slope of the cauli flower will be:

= (3.20 - 2.75)/(3.20 - 2.75)

= 1

Therefore, the broccoli function has the greater slope, which shows that the cost per pound of broccoli is greater than the cost per pound of cauliflower.

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Answer:

B

Step-by-step explanation:

right on 2022 edg

The smallest number of bags the groundskeeper must buy to cover the field is 165 bags.

Area of a circle is the region occupied by the circle in a two-dimensional plane. It can be determined easily using a formula, A = πr²

A groundskeeper needs grass seed to cover a circular field, 290 feet in diameter. A store sells 50 pound bags of grass seed. One pound of grass seed covers about 400 square feet of field.

The smallest number of bags the groundskeeper must buy to cover the field.

Diameter of the field = 290 feet

Radius = 145 feet

Area of the circular field = πr²

= 3.14 ×145²

= 66018.5ft²

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Answer:

x = - 3, x = - 2, x = 0

Step-by-step explanation:

Given

x³ + 5x² + 6x ← factor out x from each term

= x(x² + 5x +6) ← factor the quadratic

Consider the factors of the constant term (+ 6) which sum to give the coefficient of the x- term (+ 5)

The factors are + 2 and + 3 , since

2 × 3 = + 6 and 2 + 3 = + 5 , thus

x² + 5x + 6 = (x + 2)(x + 3) , and

f(x) = x³ + 5x² + 6x = x(x + 2)(x + 3)

To find the zeros equate f(x) to zero, that is

x(x + 2)(x + 3) = 0

Equate each factor to zero and solve for x

x = 0

x + 2 = 0 ⇒ x = - 2

x + 3 = 0 ⇒ x = - 3

Zeros from least to greatest are x = - 3, x = - 2, x = 0

Answer: sampling variation

Step-by-step explanation: took the quiz

The margin of error is given by the sampling variation of the proportion of customers

The most accurate type of probability sampling is random sampling. Each person in a population has an equal probability of getting selected for the sample thanks to this method of sampling.

This kind of sampling is perfect for highly controlled investigations where it is unacceptable to have human bias in the selection of the sample.

Each sampling unit in a population has an equal probability of being included in the sample when using simple random sampling (SRS). As a result, each potential sample has an equal probability of being chosen.

Given data ,

Let the margin of error be represented as A

where the value of A is

The confident interval is = 96 %

And , the value of sample is of 200 customers

where the warranty claims from 0.15 to 0.28

So , the cell phone screen protector maker can be 96% confident that the interval from 0.15 to 0.28 captures true proportion of customers who file a warranty claim

Therefore , it is a sampling variation

Hence , the situation is a sample variation

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Answer:

inequality

Step-by-step explanation:

because we are talking about gender and social class. hope it helps

Answer:

should be 1006

Step-by-step explanation:

2/5th of a number is 40% of that number.

In order to calculate the percentage of a given number that is equal to 2/5 of that number, we must first convert the fraction to percentage form, which is as follows:

= 2/3 * 100

= 0.4 * 100

= 40%

We will use the following example to validate the aforementioned process:

Assume that it is 50.

First, 2/5 of 50 equals 2/5 * 50, or 20.

Second, 40% of 50 equals 40/100 * 50 = 0.4 * 50 = 20.

The equality of the two results is evident.

2/5 of a number is therefore 40% of that number.

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The question is incomplete;

\dfrac25 start fraction, 2, divided by, 5, end fraction of a number is what percentage of that number?

Answer:

Step-by-step explanation:

1. Elimination

2. zero solutions

0 ≠ 7

The probability of rolling exactly a 1 when a dice is picked randomly from two 4-sided dice and three 6-sided dice is 0.4 or 40%.

To calculate the probability of rolling exactly a 1 when a dice is picked randomly from two 4-sided dice and three 6-sided dice, we need to determine the total number of dice and the number of dice that have a 1 as a possible outcome.

There are two 4-sided dice and three 6-sided dice, so the total number of dice is 2 + 3 = 5.

Out of these five dice, we need to determine how many have a 1 as a possible outcome.

Among the two 4-sided dice, there is only one die (out of two) that has a 1 as a possible outcome.

Among the three 6-sided dice, there is also one die (out of three) that has a 1 as a possible outcome.

Therefore, there are a total of two dice that have a 1 as a possible outcome.

The probability of rolling exactly a 1 when a dice is picked randomly is calculated by dividing the number of favorable outcomes (two dice) by the total number of possible outcomes (five dice):

Probability = Number of favorable outcomes / Total number of possible outcomes

Probability = 2 / 5

Probability = 0.4

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The general solution to the original differential equation is:  

y(t) = \(C1 e^t cos t + C2 e^t sin t + (1/2)ex sin t + (1/4)ex sin(2t) + (1/4)ln|\)

We first solve the associated homogeneous differential equation:

\(2y'' - 4y' + 4y\) = 0

The characteristic equation is\(r^2\) - 2r + 2 = 0, which has roots r = 1 ± i. Therefore, the general solution to the homogeneous equation is:

\(y_h(t) = e^t(\)C1 cos t + C2 sin t)

To use the method of variation of parameters to find the particular solution to the original equation, we assume that the solution has the form:

\(y_p(t) = u(t)e^t cos t + v(t)e^t sin t\)

where u(t) and v(t) are functions to be determined.

\(y_p''(t) \\\\2u'(t)e^t cos t + 2v'(t)e^t sin t + 2u(t)e^t cos t - 2v(t)e^t sin t - 2u(t)e^t sin t - 2v(t)e^t cos t\)

\(y_p'(t) = u'(t)e^t cos t + v'(t)e^t sin t + u(t)e^t cos t + v(t)e^t sin t\)

Substituting these into the original equation and simplifying, we get:

\(2u'(t)e^t cos t + 2v'(t)e^t sin t = ex sec x\)

We need to find u'(t) and v'(t) such that this equation holds for all t. To do this, we take the derivative of the assumed solution with respect to t and equate coefficients of cos t and sin t separately:

\(u'(t)e^t cos t + v'(t)e^t sin t + u(t)e^t cos t + v(t)e^t sin t = 0 (1)\\v'(t)e^t cos t - u'(t)e^t sin t + u(t)e^t sin t - v(t)e^t cos t = ex sec x (2)\)

Solving equation (1) for u'(t) and v'(t) and substituting into equation (2), we get:

\(v(t) = ∫ [ex sec x / (e^(2t))] dt\\u(t) = -∫ [ex sec x / (e^(2t))] tan t dt\)

Evaluating the integrals, we get:

\(v(t) = (1/2)ex tan x - (1/2)ln|cos x| + C1\\u(t) = (1/4)ex [sin(2t) - 2cos(2t)] + (1/4)ln|cos x| tan x + C2\)

where C1 and C2 are arbitrary constants.

The general solution to the original differential equation is:  

y(t) = \(C1 e^t cos t + C2 e^t sin t + (1/2)ex sin t + (1/4)ex sin(2t) + (1/4)ln|\)

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The required set for Au(BnC) is \(\{2,3,5,8\}\)

Given the following set A={2,3,5,8}, B= {3,5,7} and C= {2,4,8}

We are to find the following expression:

\(An(BuC)\)

First, we need to find BUC

BUC = {2, 3, 4, 5, 7, 8}

Taking the intersection between A and BUC, this is expressed as;

\(An(BuC)= \{2,3,5,8\}\)

Hence the required set for Au(BnC) is \(\{2,3,5,8\}\)

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simplify the numbers that have like terms so 6pq - 5pq is 1pq

now you have pq (you can get rid of the one)

the equation should look like this: pq + 8p2q

if you wanna factor that, it'll be pq(8p+1)

Answer:

Hmm it has to be to divide the coordinates by 2

Step-by-step explanation:

Lets say you have (10, 8), and the other coordinate is (0, 0). If you divide 10 by 2 you get 5, and 8 by 2 you get 4, so what you get is (5, 4), which is the midpoint.

Answer:phone A

Step-by-step explanation:

phone A is the cheapest

The maximum value of z is 0, and the values of the decision variables are x1 = 0, x2 = 10, x3 = 0, x4 = 0.

maximize: z = c1x1 + c2x2 + ... + cnxn

subject to

a11x1 + a12x2 + ... + a1nxn ≤ b1

a21x1 + a22x2 + ... + a2nxn ≤ b2

am1x1 + am2x2 + ... + amnxn ≤ bmxi ≥ 0 for all i

In our case,

the given LP is:maximize: z = 36x1 + 30x2 - 3x3 - 4x

subject to:

x1 + x2 - x3 ≤ 5

6x1 + 5x2 - x4 ≤ 10

xi ≥ 0 for all i

We can rewrite the constraints as follows:

x1 + x2 - x3 + x5 = 5  (adding slack variable x5)

6x1 + 5x2 - x4 + x6 = 10  (adding slack variable x6)

Now, we introduce the non-negative variables x7, x8, x9, and x10 for the four decision variables:

x1 = x7

x2 = x8

x3 = x9

x4 = x10

The objective function becomes:

z = 36x7 + 30x8 - 3x9 - 4x10

Now we have the problem in standard form as:

maximize: z = 36x7 + 30x8 - 3x9 - 4x10

subject to:

x7 + x8 - x9 + x5 = 5

6x7 + 5x8 - x10 + x6 = 10

xi ≥ 0 for all i

To apply the simplex algorithm, we initialize the simplex tableau as follows:

  |  Cj   |   x5   |   x6   |   x7   |   x8   |   x9   |   x10  |    RHS  |

---------------------------------------------------------------------------

z |  0    |   0    |   0    |  36    |   30   |   -3   |   -4   |    0    |

---------------------------------------------------------------------------

x5|   0   |   1    |   0    |   1    |   1    |   -1   |   0    |    5    |

---------------------------------------------------------------------------

x6|   0   |   0    |   1    |   6    |   5    |   0    |   -1   |   10    |

---------------------------------------------------------------------------

Now, we can proceed with the simplex algorithm to find the optimal solution. I'll perform the iterations step by step:

Iteration 1:

1. Choose the most negative coefficient in the 'z' row, which is -4.

2. Choose the pivot column as 'x10' (corresponding to the most negative coefficient).

3. Calculate the ratios (RHS / pivot column coefficient) to find the pivot row. We select the row with the smallest non-negative ratio.

Ratios: 5/0 = undefined, 10/(-4) = -2.5

4. Pivot at the intersection of the pivot row and column. Divide the pivot row by the pivot element to make the pivot element 1.

5. Perform row operations to

make all other elements in the pivot column zero.

After performing these steps, we get the updated simplex tableau:

  |  Cj   |   x5   |   x6   |   x7   |   x8   |   x9   |   x10  |    RHS  |

---------------------------------------------------------------------------

z |  0    |   0    |  0.4   |  36    |   30   |   -3   |   0    |   12    |

---------------------------------------------------------------------------

x5|   0   |   1    |  -0.2  |   1    |   1    |   -1   |   0    |   5     |

---------------------------------------------------------------------------

x10|   0  |   0    |   0.2  |   1.2  |   1   |   0    |   1    |   2.5   |

---------------------------------------------------------------------------

Iteration 2:

1. Choose the most negative coefficient in the 'z' row, which is -3.

2. Choose the pivot column as 'x9' (corresponding to the most negative coefficient).

3. Calculate the ratios (RHS / pivot column coefficient) to find the pivot row. We select the row with the smallest non-negative ratio.

Ratios: 12/(-3) = -4, 5/(-0.2) = -25, 2.5/0.2 = 12.5

4. Pivot at the intersection of the pivot row and column. Divide the pivot row by the pivot element to make the pivot element 1.

5. Perform row operations to make all other elements in the pivot column zero.

After performing these steps, we get the updated simplex tableau:

  |  Cj   |   x5   |   x6   |   x7   |   x8   |   x9   |   x10  |    RHS  |

---------------------------------------------------------------------------

z |  0    |   0    |  0.8   |  34    |   30   |   0    |   4    |   0     |

---------------------------------------------------------------------------

x5|   0   |   1    |  -0.4  |   0.6  |   1    |   5   |   -2   |   10    |

---------------------------------------------------------------------------

x9|   0   |   0    |   1    |   6    |   5    |   0   |   -5   |   12.5  |

---------------------------------------------------------------------------

Iteration 3:

No negative coefficients in the 'z' row, so the optimal solution has been reached.The optimal solution is:

z = 0

x1 = x7 = 0

x2 = x8 = 10

x3 = x9 = 0

x4 = x10 = 0

x5 = 10

x6 = 0

Therefore, the maximum value of z is 0, and the values of the decision variables are x1 = 0, x2 = 10, x3 = 0, x4 = 0.

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The positions through which the equation of f^-1(x) travels are: (4, 1), (6, 4)

A mathematical statement called an equation is comprised of two expressions joined together with the equal sign.

A formula would just be 3x - 5 = 16, for instance.

When this equation is solved, we observe that the value of the variable x is 7.

So, (1, 4) and (4, 6) are points through which the equation of f(x) goes.

If the f (x) equation contains (x, y).

Therefore, the f^-1(x) equation is as follows: (y, x).

Here, the f (x) equation passes through the following points: (1, 4) and (4, 6).

So, (4, 1) and (6, 4) are the points through which the equation of f^-1(x)  goes through.

Therefore, the positions through which the equation of f^-1(x) travels are:

(4, 1), (6, 4)

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Correct question:
If the equation of f(x) goes through (1,4) and (4,6), what points does f^-1(x) go through?

Answer:

x = 1.2

y = 4.6

(1.2, 4.6)

Answer:

(-1 \(\frac{1}{5}\), 4 \(\frac{3}{5}\))

Step-by-step explanation:

the system of equations is:

y = -3x + 1

y = 2x + 7

Answer:

\(cotA=\frac{2x}{5}\)

Step-by-step explanation:

Answer:

\(\text{cotA} =\frac{2x}{5}\)

Step-by-step explanation:

cotA = (Adjacent side) ÷ (Opposite side)

The measure of the Adjacent side = 2x

The measure of the Opposite side = 5

Then

\(\text{cotA} =\frac{2x}{5}\)

In the given polygon we have: Slope of A'B' = 5, Length of A'D' = 8.4, Length of C'D' = 5.4, Slope of B'C' = 0.25.

Resizing an item uses a transition called dilation. Dilation is used to enlarge or contract the items. The result of this transformation is an image with the same shape as the original. However, there is a variation in the shape's size. The initial shape should be stretched or contracted during a dilatation. The phrase "scale factor" describes this transition.

Enlargement is the term used when a dilatation results in a larger image.

Reduction occurs when a dilatation results in a smaller picture.

When the polygon ABCD is dilate by 1.2 units the slope of the segments of the polygon remains the same, whereas the length of the segments are multiplied by 1.2 units.

Thus.

Slope of A'B' = 5

Length of A'D' = 8.4

Length of C'D' = 5.4

Slope of B'C' = 0.25

Hence, in the given polygon we have: Slope of A'B' = 5, Length of A'D' = 8.4, Length of C'D' = 5.4, Slope of B'C' = 0.25.

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The required area of the parallelogram and pentagon is 91 unit² and 75 unit².

The surface area of any shape is the area of the shape that is faced or the Surface area is the amount of area covering the exterior of a 3D shape.

A parallelogram in is shown in figure 1 with the dimensions height = 7 and base = 13,
Area of the parallelogram  = 13 × 7 = 91 unit²

Now,
A pentagon is shown in figure 2,
Area of the pentagon = 5 [1/2 × height × side]
                                 = 5 [1/2 × 5 × 6]

                                 = 75 suqare units.

Thus, the required area of the parallelogram and pentagon is 91 unit² and 75 unit².

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