The mass of the solid is calculated to be 118.28g.
How to calculate mass?The mass of a substance can be calculated using the following formula:
Density = mass ÷ volume
According to this question, a liquid solvent is added to a flask containing an insoluble solid. The total volume of the solid and liquid together is 77.0 mL. The liquid solvent has a mass of 29.4 g and a density of 0.865 g/mL.
First, we calculate the volume of the liquid as follows:
0.865 = 29.4/volume
volume = 29.4/0.865
volume of the liquid solvent = 33.99mL
Volume of the solid = 77.0mL - 33.99mL = 43.01mL
Mass of the solid = 43.01mL × 2.75 g/mL
Mass of the solid = 118.28g
Therefore, the mass of the solid is 118.28g
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Please help me.
The answer is not either 100 or 10ml I don’t understand this anymore
The volume (in mL) of 0.100 M Na₂CO₃ needed to produce 1.00 g of CaCO₃ is 100 mL
How do i determine the volume of Na₂CO₃ needed?First, we shall determine the mole in 1.00 g of CaCO₃. Details below:
Mass of CaCO₃ = 1.00 g Molar mass of CaCO₃ = 100.09 g/mol Mole of CaCO₃ =?Mole = mass / molar mass
Mole of CaCO₃ = 1 / 100.09
Mole of CaCO₃ = 0.01 mole
Next, we shall obtain the mole of Na₂CO₃. Details below:
Na₂CO₃ + CaCl₂ -> 2NaCl + CaCO₃
From the balanced equation above,
1 mole of CaCO₃ were obtained from 1 mole of Na₂CO₃
Therefore,
0.01 moles of CaCO₃ will also be obtain from 0.01 mole of Na₂CO₃
Finally, we shall determine the volume of Na₂CO₃ needed. Details below:
Molarity of Na₂CO₃ = 0.10 MMole of Na₂CO₃ = 0.01 moleVolume of Na₂CO₃ =?Volume = mole / molarity
Volume of Na₂CO₃ = 0.01 / 0.1
Volume of Na₂CO₃ = 0.1 L
Multiply by 1000 to express in mL
Volume of Na₂CO₃ = 0.1 1000 =
Volume of Na₂CO₃ = 100 mL
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An aqueous solution known as Ringer's lactate is administered intravenously to trauma victims suffering from blood loss or severe burns. The solution
contains the chloride salts of sodium, potassium, and calcium and is also 4.75 mM in sodium lactate (NaC3H5O3).
How many grams of sodium lactate are needed to prepare 8.50 liters of Ringer's lactate?
The mass of sodium lactate required to prepare 8.50 liters of Ringer's lactate is 4.5 g.
From the question, we are told that the solution contains 4.75 mM in sodium lactate (NaC3H5O3). This solution is administered intravenously to trauma victims suffering from blood loss or severe burns.
But we know that;
Number of moles = concentration × volume
And;
Number of moles = mass/molar mass
mass/molar mass = concentration × volume
Concentration = 4.75 × 10^-3 M
Volume = 8.50 liters
Molar mass of NaC3H5O3 = 112.06 g/mol
Mass = concentration × volume × molar mass
Mass = 4.75 × 10^-3 M × 8.50 liters × 112.06 g/mol
Mass = 4.5 g
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If the amount of radioactive phosphorus-32 in a sample prepared for treatment of leukemia decreases from 1.2g to 0.30g in 28.6 days, what is the half-life of phosphorus-32? Express the answer in 2 significant figures.
The half-life of the phosphorus-32, given the data is 14.3 days
What is half-life?Half-life is the time taken for half a material to decay.
Determination of the number of half-lives that has elapsedWe'll begin by obtaing the number of half-lives that has elapsed. This can be obtained as follow:
Original amount (N₀) = 1.2 gAmount remaining (N) = 0.3 gNumber of half-lives (n) =?2ⁿ = N₀ / N
2ⁿ = 1.2 / 0.3
2ⁿ = 4
Express 4 in index form
2ⁿ = 2²
n = 2
Thus, 2 half-lives has elapsed.
How to determine the half-lifeNumber of half-lives (n) = 2Time (t) = 28.6 daysHalf-life (t½) =?The half-life of the phosphorus-32 can be obtained as follow:
t½ = t / n
t½ = 28.6 / 2
t½ = 14.3 days
Thus, the half-life of the phosphorus-32 14.3 days
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Which technique can be used to remove air bubbles from a syringe? a) Hold the syringe downward, shake vigorously for 10 seconds, and expel the bubbles through the needle using the syringe plunger. Hold the syringe upright, provide a firm tap or flick to the b) barrel, and expel the bubbles through the needle using the syringe plunger. Hold the syringe upright, shake vigorously for 10 seconds, c) and expel the bubbles through the needle using the syringe plunger. Hold the syringe downward, provide a firm tap or flick to the d) barrel, and expel the bubbles through the needle using the syringe plunger.
Answer:
Point the syringe upright and tap firmly to move the bubbles to the top and expel by pushing the plunger
Explanation:
If you hold the syringe upside down the bubbles will end up at the bottom of the syringe by the plunger since they float up when tapped
A piece of silver wire has a mass of 53.91 grams. How many moles of
silver are in the wire?
89 year old toys girl who have some starter pets plez im new
Consider the following chemical equilibrium:
N2 (g) + 3H2 ⇌ 2NH3
Now write an equation below that shows how to calculate Kp from Kc for this reaction at an absolute temperature .
Answer:
Kp = Kc (RT) ^(-2)
Explanation:
For the reaction;
N2 (g) + 3H2 ⇄ 2NH3(g)
We can write;
Kc = [NH3]^2/[N2] [H2]^3
But
Kp = pNH3^2/pN2 . PH2^3
To convert from Kc to Kp
Kp = Kc (RT) ^Δn
where Δn is the change in number of moles going from reactants
to products.
For this reaction;
Δn = 2- (3+1) = -2
Kp = Kc (RT) ^(-2)
how many s orbitals are there for silver?
5 electron orbits
I hope this helps
3. A representation of one unit of KCl in water is shown below. (The water molecules are intentionally not shown.)
what is wrong with the representation?
The representation is showing potassium atom (K) and Chlorine atom (Cl) when it ought to show their ions i.e potassium ion (K⁺) and Chlorine ion (Cl¯)
Dissociation equation for KClWhen potassium chloride, KCl dissolves in water, it dissociate to produce potassium ion (K⁺) and Chlorine ion (Cl¯) as shown below:
KCl(aq) —> K⁺(aq) + Cl¯(aq)
The representation given in the question is only showing potassium atom (K) and Chlorine atom (Cl). This makes it wrong as dissolution of ionic compounds in water will results in the corresponding ions of the element that makes up the compound
Please see attached photo
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Milk of magnesia, which is an aqueous suspension of magnesium hydroxide, is used as an antacid in the reaction below. How many molecules of HCl would have to be present to form 34.52 g of MgCl₂?
Mg(OH)₂(s) + 2 HCl(aq) → 2 H₂O(l) + MgCl₂(aq)
Approximately 4.37 x 10^23 molecules of HCl would be required to form 34.52 g of MgCl₂.
To determine the number of molecules of HCl required to form 34.52 g of MgCl₂, we need to use the molar mass and stoichiometry of the balanced equation:
Mg(OH)₂(s) + 2 HCl(aq) → 2 H₂O(l) + MgCl₂(aq)
The molar mass of MgCl₂ is 95.21 g/mol.
First, we need to calculate the number of moles of MgCl₂ formed:
Moles of MgCl₂ = mass of MgCl₂ / molar mass of MgCl₂
Moles of MgCl₂ = 34.52 g / 95.21 g/mol
Moles of MgCl₂ = 0.363 mol
According to the balanced equation, the stoichiometric ratio between HCl and MgCl₂ is 2:1. Therefore, the moles of HCl required can be calculated as follows:
Moles of HCl = 2 * Moles of MgCl₂
Moles of HCl = 2 * 0.363 mol
Moles of HCl = 0.726 mol
To calculate the number of molecules, we need to use Avogadro's number, which is approximately 6.022 x 10^23 molecules/mol.
Number of molecules of HCl = Moles of HCl * Avogadro's number
Number of molecules of HCl = 0.726 mol * 6.022 x 10^23 molecules/mol
Number of molecules of HCl = 4.37 x 10^23 molecules
Therefore, approximately 4.37 x 10^23 molecules of HCl would be required to form 34.52 g of MgCl₂.
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La función de la levadura en quimica
Explanation:
las levaduras son pequeños organismos unicelulares que se alimentan de azúcares simples y los descomponen en dióxido de carbono, alcohol (etanol, específicamente), moléculas de sabor y energía. El proceso se conoce como fermentación.
the process of dissolved solute particles being surrounded by water molecules in an aqueous solution is called
The process of dissolved solute particles being surrounded by the water molecules in an aqueous solution is called solvation or hydration.
Solvation occurs when water molecules surround and interact with solute particles, usually ions or polar molecules, forming a stable solution. The water molecules surround the solute particles, with their polar ends facing the solute, creating a layer of water molecules around the solute particles, effectively dispersing and stabilizing them throughout the solution.
Solvation is a key process in many chemical and biological reactions that occur in aqueous solutions, as it helps to facilitate the dissolution of solutes and influences their properties and behavior in solution.
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--The given question is incomplete, the complete question is
"The process of dissolved solute particles being surrounded by water molecules in an aqueous solution is called ----------- ."--
Which refers to the passing of a wave through an object?
sound
O interference
O transmission
O frequency
O sound
The term that refers to the passing of a wave through an object is "transmission."
Transmission refers to the process by which a wave passes through an object or medium. In the context of sound, transmission occurs when sound waves travel through different substances, such as air, water, or solids.
When a sound wave encounters an object, it can be transmitted through it, reflected off it, or absorbed by it, depending on the properties of the object and the medium through which the sound is traveling.
For example, when you speak into a microphone, the sound waves produced by your voice travel through the air and are transmitted to the microphone's diaphragm. The diaphragm converts the sound waves into electrical signals, which can then be amplified and reproduced as sound through speakers.
In summary, transmission is the term used to describe the passage of a wave, such as a sound wave, through an object or medium. It is an essential concept in understanding how waves interact with their surroundings and how sound propagates through different materials.
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The pressure inside a tire is measured as 28.0 pounds/inches^2. What is its pressure in newtons/centimeters^2
The pressure inside the tire is approximately 1.970796 newtons per square centimeter (N/cm²) when measured in those units.
To convert the pressure from pounds per square inch (psi) to newtons per square centimeter (N/cm²), we need to use the conversion factors between these units.
First, let's convert pounds to newtons:
1 pound = 0.45359237 kilograms
1 kilogram = 9.80665 newtons
Next, let's convert square inches to square centimeters:
1 square inch = 6.4516 square centimeters
Now, we can perform the conversion:
1 psi = (0.45359237 kg) × (9.80665 N/kg) / (6.4516 cm²)
≈ 0.070307 N/cm²
Therefore, the pressure inside the tire of 28.0 psi is approximately equal to 28.0 × 0.070307 N/cm², which is approximately 1.970796 N/cm².
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Complete the chart on the characteristics of bonds
Answer:
Face value. Corporate bonds normally have a par value of $1,000, but this amount can be much greater for government bonds.
Interest. ...
Coupon or interest rate. ...
Maturity. ...
Issuers. ...
Rating agencies. ...
Tools and tips.
9. Nitric acid, HNO3, is extensively used in the manufacture of fertilizer. A bottle containing 75.0 ml of nitric acid solution is labeled 6.0 M HNO3.
a. How many moles of HNO3 are in the bottle?
b. A reaction needs 5.00g of HNO3. How many ml of solution are required?
(Molar mass of HNO3 = 63.01 g /mol)
a)There are 0.45 moles of HNO₃ in the bottle.
b)Approximately 13 ml of the solution are required for the reaction.
a. To find the number of moles of HNO₃ in the bottle, we can use the formula:
moles = concentration (M) x volume (L)
Given that the concentration of the nitric acid solution is 6.0 M and the volume is 75.0 ml, we need to convert the volume to liters:
75.0 ml = 75.0 ml x (1 L/1000 ml) = 0.075 L
Now, we can calculate the number of moles:
moles = 6.0 M x 0.075 L = 0.45 moles
So, there are 0.45 moles of HNO₃ in the bottle.
b. To determine the volume of solution required for 5.00 g of HNO3, we need to use the molar mass of HNO3 to convert grams to moles:
moles = mass (g) / molar mass (g/mol)
Given that the molar mass of HNO₃ is 63.01 g/mol and the mass required is 5.00 g, we can calculate the number of moles:
moles = 5.00 g / 63.01 g/mol ≈ 0.079 moles
Now, we can use the concentration to find the volume:
volume (L) = moles / concentration (M)
volume (L) = 0.079 moles / 6.0 M ≈ 0.013 L
Finally, we need to convert the volume to milliliters:
volume (ml) = 0.013 L x (1000 ml/1 L) ≈ 13 ml
So, approximately 13 ml of the solution are required for the reaction.
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4. How many feet are in 3.45 km?
Answer:
11318 feet and 10.771 inches
Explanation:
there is 3280.84 in one Km
just do 3280.84x3.45
In a common reaction in living things, glucose combines with oxygen to form carbon dioxide and water vapor. In an experiment on this reaction, the masses of glucose, oxygen, and carbon dioxide are measured. This data table shows the measurements. What is the mass of the water vapor? please help
Multiply the number of moles of glucose by the molar mass of water (18.015 g/mol) to find the mass of water vapor produced.
To determine the mass of water vapor produced in the reaction, we need to analyze the data provided in the data table. The reaction mentioned is the process of cellular respiration, where glucose (C6H12O6) combines with oxygen (O2) to produce carbon dioxide (CO2) and water (H2O). We can use the principle of conservation of mass to calculate the mass of water vapor produced.The data table should provide the initial masses of glucose and oxygen, as well as the final mass of carbon dioxide. From these measurements, we can calculate the mass of water vapor.First, determine the number of moles of glucose and oxygen by dividing their respective masses by their molar masses. Then, use the balanced equation for cellular respiration to determine the mole ratios between glucose, oxygen, carbon dioxide, and water.
The balanced equation for cellular respiration is:
C6H12O6 + 6O2 -> 6CO2 + 6H2O
Based on this equation, we know that for every mole of glucose, 6 moles of water are produced.In conclusion, by using the principles of conservation of mass and stoichiometry, you can calculate the mass of water vapor produced in the reaction based on the given measurements.
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Give the formula of Plaster of Paris And some of its uses..
:))
Differentiate between acids and bases on the basis of their pH values Give an example of each type. Please help worth 100 points!!!!!!!
Answer: Well 0-7 is acid, and 0-3 is a strong acid. 4-7 is a weak acid. 8-11 is strong base. 12-14 is weak base!
Explanation:
As you move from left to right in the third period of the periodic table…
A. Each group loses an outer electron
B. Each group gains an outer electron
C. Each group gains a neutron
D. The number of outer electrons remains constant across the period
Answer:
B
Explanation:
2.8.1 Na
2.8.2 Mg
and so on and so forth
Write the equation for the alpha decay of C-11.
Write the equation for the beta decay of Be-10
HELP HELP HELP
Answer:
We know that in the decay process the sum of molecular number as well as molecular weight should be constant.
The following three reaction are as follows
1 .
Explanation:
What substances is a liquid at room temperature
Answer:
Only two elements are liquid at standard conditions for temperature and pressure: mercury and bromine. Four more elements have melting points slightly above room temperature: francium, caesium, gallium and rubidium.
Explanation:
Answer:
Explanation:
Only two elements are liquid at standard conditions for temperature and pressure: mercury and bromine. Four more elements have melting points slightly above room temperature: francium, caesium, gallium and rubidium.
The Urbana wastewater treatment plant discharge permit limits the discharge of ammonia/ammonium (NH3/NH4 ). To meet this permit, the ammonium is converted to nitrate (NO3 - ) by biological nitrification in trickling filter towers. The solution entering the nitrification towers contains 15 mg/L of NH4 as N. Write a balanced reaction for the oxidation of NH4 to nitrate,
Answer:
Explanation:
The conversion of ammonium ion into nitrate ion is a two step process which is written below .
2 NH₄⁺ + 3 O₂ = 2NO₂⁻ + 4 H⁺ + 2H₂O
2NO₂⁻ + O₂ = 2 NO₃⁻
This is a two step reaction . These steps are managed by different class of bacteria.
a) what is the color of dilute phenolphthalein solution in acidic solution? ___b) what is the color dilute phenolphthalein solution at the end point of an acid-base titration? ____ c) what is the color of dilute phenolphthalein solution in strong basic solution? ____
Answer:
Explanation:
Clear or colorless
Faint (light) pin
Dark pink
What forms of energy are produced when
fossil fuels burn?
When fossil fuels burn, several forms of energy are produced, including:
Heat energy: The primary form of energy released during fossil fuel combustion is heat. Fossil fuels contain chemical energy stored for millions of years, and when they burn, this energy is released in the form of heat. The heat energy can be harnessed for various purposes, such as heating buildings or generating steam to drive turbines.
Light energy: Burning fossil fuels can also produce light energy in the form of flames or glowing embers. This light energy is a byproduct of combustion.
Mechanical energy: Heat generated by burning fossil fuels can be converted into mechanical energy. This is typically achieved by using heat to produce steam, which drives a turbine connected to a generator. The rotating turbine converts the heat energy into mechanical energy, which is further transformed into electrical energy.
Electrical energy: Through the process described above, burning fossil fuels can ultimately generate electrical energy. The mechanical energy produced by the turbine is converted into electrical energy by the generator. Electrical energy can power various devices, appliances, industries, and infrastructure.
It's critical to note that while burning fossil fuels can produce useful forms of energy, it also results in the release of carbon dioxide and other greenhouse gases. This contributes to climate change and environmental concerns. As a result, there is a global shift towards cleaner and renewable energy sources to mitigate these negative impacts.
How many atoms are in 12 g of Carbon-12 (12C)?
There are approximately 6.022 × 10^23 atoms in 12 grams of Carbon-12 (12C).
The number of atoms in a given amount of a substance can be calculated using Avogadro's number, which represents the number of atoms or molecules in one mole of a substance. Avogadro's number is approximately 6.022 × 10^23.
Carbon-12 is a specific isotope of carbon, with an atomic mass of 12 atomic mass units (amu). One mole of Carbon-12 has a mass of 12 grams. Since one mole of any substance contains Avogadro's number of particles, in the case of Carbon-12, it contains 6.022 × 10^23 atoms.
Therefore, if we have 12 grams of Carbon-12, which is equal to one mole, we can conclude that there are approximately 6.022 × 10^23 atoms in this amount of Carbon-12.
In summary, 12 grams of Carbon-12 contains approximately 6.022 × 10^23 atoms. Avogadro's number allows us to relate the mass of a substance to the number of atoms or molecules it contains, providing a fundamental concept in chemistry and enabling us to quantify and understand the microscopic world of atoms and molecules.
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How many particles are there in 0.057 moles of lithium bromide made
There are 3.44 x 10^{22} particles in 0.057 moles of lithium bromide.
What chemical compound is lithium bromide known by?The lithium bromide formula also known as the lithium monobromide formula or Bromo lithium formula is explored. It is a counterion bromide-based salt of lithium.
we have to use Avogadro's constant,
Avogadro's constant, is approximately equal to 6.022 x 10^{22} particles per mole.
we can use the following formula:
number of particles = moles x Avogadro's constant
Substitute the values,
number of particles = 0.057 moles x 6.022 x 10^{23} particles/mol
Simplifying the equation
number of particles = 3.44 x 10^{22} particles
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forgot how to solve this
The value of the equilibrium constant, Kc is 0.33.
The correct option is A.
What is the value of the equilibrium constant, Kc?The balanced chemical equation for the oxidation of NO by O2 is:
2 NO (g) + O2 (g) → 2 NO2 (g)
From the stoichiometry of the equation, we see that the mole ratio of NO to O2 consumed is 2:1. Therefore, if 3 moles of O2 are present at equilibrium, then 1.5 moles of NO have been consumed:
1.5 moles NO = 15.0 moles NO (initial) - 3.0 moles NO2 - 3.0 moles O2
Using the law of mass action, we can express the equilibrium constant (Kc) for the reaction as:
Ke = ([NO2]^2 / [NO]^2 [O2])
We know that at equilibrium, [O2] = 3.0 moles / 1.0 L = 3.0 M. To calculate [NO2], we need to use the stoichiometry of the equation and the fact that 1.5 moles of NO are consumed at equilibrium:
2 mol NO → 2 mol NO2
1.5 mol NO → 1.5 mol NO2
Therefore, [NO2] = 1.5 mol NO2 / 1.0 L = 1.5 M. Substituting the values into the equilibrium constant expression, we get:
Ke = ([NO2]^2 / [NO]^2 [O2])
Ke = (1.5 M)^2 / (1.5 M)^2 (3.0 M)
Ke = 0.333
Therefore, the answer is (a) 0.33.
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Grady is doing an experiment about the solubility of sugar. He puts 100 milliliters of water in each of three beakers. He leaves the first beaker at room temperature, heats the second beaker to 60°C, and heats the third beaker until the water boils at 100°C.
To the first beaker, he adds sugar, one spoonful at a time, until not all of the sugar can dissolve when he stirs it. He records the number spoonfuls that dissolved. Then he repeats the same process of adding sugar and stirring for the beakers of hot water and boiling water
Variables within an experiment many be altered in order to produce specific outcomes such as a reaction rate. The reaction rate is a measure of how fast a chemical reaction can happen. The increase in temperature increases the collision of molecules, such as the solid sugar solute and and the water molecules, which act as a solvent. Agitation, such as stirring, also increases the solubility by increasing collisions.
This continues until the solution becomes too saturated.
between ethane, ethene and ethyne which is having shortest bond?
As you can see the picture, in the three given compounds i.e. ethane, ethene and ethyne, ethyne have shortest bond. Bond length of ethyne is very short when compared to the ethane and ethene. Shorter the bond, bond strength will be more. Hence, our answer is ethyne.
Answer:
ethyne has shortest bond