The reaction of Chromium with the Fe3C to form Cr23C6 at high temperature decreases the corrosion resistance of alloys.
Stainless steels are most commonly used for their corrosion resistance. The presence of high chromium content is so beneficial to the wet corrosion resistance of stainless steel. It is also highly beneficial to their high temperature strength and resistance to increasing temperatures.
At high temperature, Chromium reacts with the Fe3C produces Cr23C6 which decreases the corrosion resistance of alloys so we can conclude that decrease occur in the corrosion resistance when the Chromium reacts with the Fe3C at high temperature.
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What are the respective concentrations (M) of Mg2+and Cl-afforded by dissolving 0.325 mol MgCl2 in water and diluting to 250 mL?A) 0.0013 and 0.0013B) 0.0013 and 0.0026C) 1.30 and.1.30D) 1.30 and 2.60E) 2.60 and 2.60
Answer: D) 1.30 and 2.60
Explanation:
Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.
\(Molarity=\frac{n\times 1000}{V_s}\)
where,
n = moles of solute
\(V_s\) = volume of solution in ml
molarity of \(MgCl_2\) = \(\frac{0.325\times 1000}{250ml}=1.30 M\)
\(MgCl_2\rightarrow Mg^{2+}+Cl^{-}\)
As 1 mole of \(MgCl_2\) dissociates to give one mole of \(Mg^{2+}\) and two moles of \(Cl^-\) ions .
Molarity of \(Mg^{2+}\) = 1.30 M
Molarity of \(Cl^{-}\) = \(1.3 M\times 2=2.60M\)
22. What is the molar mass of oxygen (O2)?
A- 15.9994 g/mol
B- 1.204 x 1024 g/mol
C- 6.02 x 1023 g/mol
D- 31.9988 g/mol
Answer:
D- 31.9988 g/mol
Explanation:
The molar mass of a substance is the mass in grams of one mole of the substance. For a compound, the molar mass is the gram - formula mass or gram - molecular weight. It is determined by the addition of its component atomic masses;
To find molar mass of O₂;
Atomic mass of O = 15.9994g/mol
Molar mass of O₂ = 2(15.9994) = 31.9988g/mol
PLS HELP!
For which properties can a student design an investigation of the electrostatic forces between molecules in a substance?
A. melting point and boiling point, but not surface tension and vapor pressure
B. surface tension and vapor pressure, but not melting point and boiling point
C. boiling point, but not melting point, surface tension, or vapor pressure
D. melting point, boiling point, surface tension, and vapor pressure
To determine the melting point of ice, which procedure would best help measure the melting point temperature?
A. Mix ice with water until equilibrium is reached but some ice remains that is no longer melting.
B. Mix ice with water until equilibrium is reached but some ice remains that is still melting.
C. Mix ice with water until just before equilibrium is reached but some ice remains that is no longer melting.
D. Mix ice with water until just before equilibrium is reached but some ice remains that is still melting.
Answer:
1. D: melting point, boiling point, surface tension, and vapor pressure
2. I’m not too sure about the second one. Maybe D Mix ice with water until just before equilibrium is reached but some ice remains that is still melting. However I am unsure. So do not take my word for it
Explanation:
The properties that a student can design an investigation of the electrostatic forces between molecules in a substance are melting point, boiling point, surface tension, and vapor pressure.
To determine the melting point of ice, which procedure would best help measure the melting point temperature is to Mix ice with water until equilibrium is reached but some ice remains that is still melting.
Intermolecular forces are regarded as the forces of attraction or repulsion that exist or act between close particles of atoms, molecules, or ions.
The slow heating rate at the melting point is important in order to get an the measurement.
When an individual heat ice, its temperature often rises, but as soon as the ice starts to melt, the temperature stays constant until all the ice has melted.
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What would happen in the future if global warming is not addressed properly?
Answer and Explanation:
If the future did not address global warming properly, then the world will become too hot faster than it should, and the days will get extremely hot, and in the distant future, lead to our extinction.
To address this problem, we can spread the awareness about it, get people to think open minded and not think that global warming is a joke, and plant trees, which takes in the carbon dioxide we exhale.
#teamtrees #PAW (Plant And Water)
a saline solution begins to freeze at -1.13 degrees. Express the concentration of NaCl in this solution in mass%. Kf for water is 1.86C degree/m.
The Percentage mass of NaCl is 1.78%.
What is the percent mass concentration of the NaCl in saline solution.The percent mass concentration of NaCl in the saline solution is determined from the molality of the solution.
The molality of the solution is further obtained from the freezing point depression formula.
The freezing point depression formula is given as follows:
ΔT = Kf * m * iwhere;
ΔT is the freezing point changeKf is a constantm is the molality of the solutioni is the van't Hoff factorFor the solution of NaCl;
ΔT = 0 - (-1.13) = 1.13
Kf = 1.86 °/m
i = 2
m = ΔT/(Kf * i)
m = 1.13/(1.86 * 2)
m = 0.3038 mol/kg
molar mass of NaCl = 58.5 g/mol
Mass of NaCl = 0.3038 * 58.5 = 17.8 g in
Percentage mass of NaCl = (17.8/1000) * 100
Percentage mass of NaCl = 1.78%
In conclusion, the percent mass of NaCl is obtained from the molality of the solution.
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how do you balance this equation
2h2s+3o2+so2
The balanced equation is: 4 \(H_2S\)+ 3 \(O_2\)→ 4 \(SO_2\)+ 8 \(H_2O\)
The given chemical equation is unbalanced. To balance it, we need to adjust the coefficients in front of each chemical species until the number of atoms on both sides of the equation is equal.
The unbalanced equation is:
2 \(H_2S\)+ 3 \(O_2\)→ \(SO_2\)
Let's start by balancing the sulfur (S) atoms. We have two sulfur atoms on the left side and one sulfur atom on the right side. To balance the sulfur, we can place a coefficient of 2 in front of the \(SO_2\):
2 \(H_2S\)+ 3 \(O_2\)→ 2 \(SO_2\)
Now, let's balance the hydrogen (H) atoms. We have four hydrogen atoms on the left side (2 from each \(H_2S\)) and none on the right side. To balance the hydrogen, we can place a coefficient of 4 in front of the water (H2O) on the right side:
2 \(H_2S\)+ 3 \(O_2\)→ 2 \(SO_2\)+ 4 \(H_2O\)
Finally, let's balance the oxygen (O) atoms. We have six oxygen atoms on the right side (3 from \(O_2\) and 3 from 2 \(SO_2\)) and three on the left side (2 from \(H_2S\)). To balance the oxygen, we can place a coefficient of 3/2 in front of the O2:
2 \(H_2S\)+ (3/2) \(O_2\)→ 2 \(SO_2\)+ 4 \(H_2O\)
To remove the fractional coefficient, we can multiply all coefficients by 2:
4 \(H_2S\) + 3 \(O_2\)→ 4 \(SO_2\)+ 8 \(H_2O\)
Now the equation is balanced, with an equal number of atoms on both sides. The balanced equation is:
4 \(H_2S\)+ 3 \(O_2\)→ 4 \(SO_2\)+ 8 \(H_2O\)
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Which statement defines the enthalpy of solution?
the total number of particles in a solution
the phase change from a solid to a liquid
o the difference in characteristics between reactants and products
the change in energy when one substance dissolves in another
Answer:
the change in energy when one substance dissolves in another
Explanation:
The enthalpy changes are the heat changes accompanying physical and chemical changes. Actually, an enthalpy change is the difference between the sum of the heat contents of products (final state) and sum of the heat contents of reactants (initial state).
There are basically two types of heat changes that accompanies are reaction which are:
Exothermic changes Endothermic changesTherefore, the change in energy when one substance dissolves in another defines the enthalpy of solution.
Enthalpy of solution is the heat liberated or absorbed when one mole of a substance (solute) is dissolved in a specified volume of solvent (water).
Write the chemical formula for this molecule
Answer:
C2H4O
Explanation:
The chemical molecular formula is C2H4O.
Also note*: Acetaldehyde is the chemical name for this structural formula.
What evidence other than the
CMB provides support for the Big Bang theory
Evidence other than the CMB provides support for the Big Bang theory is redshift proposed by Edwin Hubble.
The redshift that was suggested by Edwin Hubble is yet another piece of evidence that supports the Big Bang idea. His finding confirmed the theory that the universe is expanding as a result of the other galaxies' light's redshift.
Edwin Hubble declared in 1929 that nearly all galaxies looked to be revolving away from us. He discovered that the cosmos was actually expanding, with all of the galaxies moving apart. The spectrum of a galaxy was seen to change toward red due to this occurrence.
Edwin Hubble made two significant changes to our knowledge of the universe over the span of five years, contributing to the development of the Big Bang theory. He first showed that the universe is far bigger than previously believed before proving that it is expanding.
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True or false water molecules are polymers
Paul Cezanne's Still Life with Apples in a Bowl (1879-83) represents a break with the tradition of using ____in art.
value
modeled forms
local color
linear perspective
as the altitude increases what happens to the angle of insolation
Answer:
the angle gets closer to 90 degrees
Explanation:
hope this helped :)
Calculate the freezing point of a solution that contains 8.0 g of sucrose (C12H22O11) in 100 g of H2O. Kf for H2O = 1.86C/m
Group of answer choices
A. 0.44 degrees Celsius
B. 0.044 degrees Celsius
C. 0.39 degress Celsius
D. 0.22 degress Celsius
The freezing point of the sucrose solution is -0.435°C.
What is the freezing point of the solution?The freezing point of the solution is determined from the freezing point depression formula below:
ΔT = mKf(H₂O)Kf(H₂O) = 1.86 Cm
m is molality of solution = moles of solute/mass of solvent
moles of sucrose = 8.0/342.3 = 0.0233 moles
m = 0.0233/0.1 = 0.233 molal
ΔT = 0.233 m * 1.86°C/m.
ΔT = 0.435 °C.
Freezing point of sucrose solution = 0°C - 0.435°C
Freezing point of sucrose solution = -0.435°C.
In conclusion, the freezing point of sucrose solution is determined from the freezing point depression.
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At 25 degrees Celsius, 50g of sugar is soluble in 100ml of water. If I add 55g of sugar to
25-degree water, what will my solution look like and what will the ratio of dissolved to
undissolved solute be? If I heat up the solution, what will my solution look like and what will
the ratio of dissolved to undissolved solute be? If I then slowly cool the mixture to 25 degrees
again, what will my solution look like and what will the ratio be? Finally, if I add one seed
crystal to the mixture, what will my solution look like and what will my ratio be?
At 25 degrees Celsius, with 50g of sugar, the solution will appear clear and homogeneous, with all the sugar dissolved. The ratio of dissolved sugar to undissolved sugar will be 50:0, as all the sugar has dissolved.
If an additional 55g of sugar is added to the 25-degree water, the solution will become supersaturated. This means that the water cannot dissolve all the sugar, resulting in the excess sugar remaining undissolved as solid particles at the bottom of the container. The solution will appear cloudy, and the ratio of dissolved sugar to undissolved sugar will be 50:5, as only 50g of the added sugar can dissolve.
When the solution is heated, the solubility of sugar increases. As a result, more sugar will dissolve, and the solution will become clear again. The ratio of dissolved sugar to undissolved sugar will approach 105:0 as the temperature increases and more sugar dissolves.
If the heated solution is slowly cooled back to 25 degrees Celsius, the solubility of sugar decreases. This will cause the excess sugar to come out of the solution and form solid crystals, which will be visible as sugar particles. The solution will appear cloudy again, and the ratio of dissolved sugar to undissolved sugar will depend on the amount of sugar that remains dissolved after cooling.
Adding a seed crystal to the mixture provides a surface for sugar crystals to form, resulting in the rapid crystallization of the remaining dissolved sugar. The solution will become saturated with sugar crystals, and the ratio of dissolved sugar to undissolved sugar will be close to 0:55, as most of the sugar will have crystallized. The solution will appear cloudy with a significant amount of sugar crystals present.
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which issue is a limitation of using synthetic polymers
Answer: As trash, Synthetic Polymers are not biodegradable. Landfills can easily fill up with synthetic polymers. Plastics can be made into different products. Recycling synthetic polymers is costly.
Explanation: Hope this helps in any way possible!
The main issues of using synthetic polymers include toxicity poor biocompatibility etc. Synthetic polymers stay non-degradable for ling time and make the surface polluted.
What are synthetic polymers?Natural polymers are naturally made substances such as cellulose, starch, glycogen etc. Polymers made by man are called synthetic polymers. Synthetic polymers are diverse and are made through several polymerization techniques.
PVC, polyethylene, polyesters Teflon etc. are very common polymers in daily life. A major class of synthetic polymers include plastics which are major pollutants nowadays.
Most of the synthetic polymers are non-biodegradable and will cause landfill issues. Some them are toxic in nature and might cause several health issues. Blending them with biodegradable polymers is a solution for this.
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What is the number of C atoms in 0.247 mol of C.
The number of C atoms in 0.247 mol of C is 1.48 X 10²³ .
The number of C atoms in 1 mol of C is 6.02 X 10²³, which is also called Avogadro’s number .
so, The number of C atoms in 0.247 mol of C is _
0.247x6.02x10²³= 1.48 X 10²³.
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C6H12O6 + 602 → 6CO2 + 6H₂O
The most efficient ratio is
1 C6H12O6 6 02.
Which set of reactants will be the most
efficient (least wasteful of materials) for
the reaction?
A. 1.0 mol C6H12O6 and 3.0 mol O₂
B. 1.5 mol C6H₁2O6 and 3.0 mol O₂
C. 3.0 mol C6H₁2O6 and 6.0 mol O₂
D. 0.5 mol C6H₁2O6 and 3.0 mol O₂
Answer:
D
Explanation:
The ratio of C6H12O6 (which will be referred to as "the carb") to oxygen is 1 to 6, so if we find an answer which has the same ratio, it should be chosen. A is 1:3
B is even worse with a ratio of the carb to oxygen of 1:2
C is the same as B, 1:2
D has a ratio of the carb to oxygen of 1:6, which is what we are looking for.
PLEASE HELP!!!!!!!
Answer:
2nd option
Explanation:
what type of molecule are these and what is the strongest IMFs in between?
Answer:
CH2O is formaldehyde a covalent compound and its intermolecular forces are week
KCl is an ionic compound formed by electrostatic force of attraction between positive and negative charge. Ionic compounds also exists in three dimensional crystal lattic that is why intermolecular forces in KCl is stronger.
Moreover melting point of KCl is higher than CH2O
Explanation:
Name the enzymes and coenzymes that catalyze the process of catecholamines inactivation. Explain their mechanism of action.
Answer:
Coenzyme Definition
A coenzyme is an organic non-protein compound that binds with an enzyme to catalyze a reaction. Coenzymes are often broadly called cofactors, but they are chemically different. A coenzyme cannot function alone but can be reused several times when paired with an enzyme.
Functions of Coenzymes
An enzyme without a coenzyme is called an apoenzyme. Without coenzymes or cofactors, enzymes cannot catalyze reactions effectively. The enzyme may not function at all. If reactions cannot occur at the normal catalyzed rate, then an organism will have difficulty sustaining life.
When an enzyme gains a coenzyme, it then becomes a holoenzyme or active enzyme. Active enzymes change substrates into the products an organism needs to carry out essential functions, whether chemical or physiological. Coenzymes, like enzymes, can be reused and recycled without changing reaction rates or effectiveness. They attach to a portion of the active site on an enzyme, which enables the catalyzed reaction to occur. When an enzyme is denatured by extreme temperature or pH, the coenzyme can no longer attach to the active site.
Types of Enzymes
Cofactors are molecules that attach to an enzyme during chemical reactions. In general, all compounds that help enzymes are called cofactors. However, cofactors can be broken down into three subgroups based on chemical makeup and function:
Coenzymes
These are reusable non-protein molecules that contain carbon (organic). They bind loosely to an enzyme at the active site to help catalyze reactions. Most are vitamins, vitamin derivatives, or form from nucleotides.
group 1 and 2 on the periodic table consist of what
Answer:
I believe its Alkaline Earth Metals or Meterials
Explanation:
Sugar dissolves in water. Which statement best describes what is happening? (1 point) Sugar stays together but in a liquid form that can no longer be seen in the water. Sugar stays together but in a liquid form that can no longer be seen in the water. Sugar slowly melts, turning from a solid to a liquid and combining with the water. Sugar slowly melts, turning from a solid to a liquid and combining with the water. The water molecules in sugar will separate from each other and combine with the water, releasing the sweetness into the water. The water molecules in sugar will separate from each other and combine with the water, releasing the sweetness into the water. A large collection of sugar molecules break into individual molecules and disperse in the water.
What is the volume of 1g of ice in cm3?
Answer:
What is the volume of 1g of ice in cm3?
What is the volume of 1g of ice in cm3?
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What is the volume of 1g of ice in cm3?
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Explanation:
How many bonds are in NH4¹+?
2
3
5
4
Answer:
3 Covalent Bonds and 1 Co ordinate Bond
Explanation:
4 bonds are in NH4¹+
NH4¹+ is the ammonium ion, which consists of a central nitrogen atom (N) and four hydrogen atoms (H). Nitrogen is located in group 15 of the periodic table and has 5 valence electrons. Hydrogen, on the other hand, has 1 valence electron.
To achieve a stable electron configuration, nitrogen needs to share electrons with the hydrogen atoms. Each hydrogen atom can form a single bond with the nitrogen atom by sharing its valence electron.
In NH4¹+, all four hydrogen atoms form single bonds with the central nitrogen atom. These bonds are represented by lines connecting each hydrogen atom to the nitrogen atom.
So, NH4¹+ has 4 bonds. Each bond represents a pair of electrons shared between the nitrogen atom and a hydrogen atom. The bonding arrangement ensures that the nitrogen atom has a complete octet (eight valence electrons) and each hydrogen atom has two electrons, following the stable configuration of helium.
The "+1" charge on NH4¹+ indicates that the ion has lost one electron, resulting in a positive charge. However, the number of bonds remains the same regardless of the charge.
Therefore, the correct answer is 4 for the number of bonds in NH4¹+.
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Is magnetite organic?
Answer: organic
Explanation:
Given the following chemical reaction answer the following questions:
CO(g)+H2O(g)⇌CO2(g)+H2(g) at 25.0°C and 1 atm.
ΔH = −41.0 kJ/mol
ΔS° = −42.3 J/(mol·K)
(Question): What is the value of ΔG (kJ/mol) at 25.0°C and 1 atm? (hint: convert ΔS° to kJ/mol·K)
The value of ΔG° for the reaction CO(g) + H₂O(g) ⇄ CO₂(g) + H₂(g), when ΔH° = -41.0 kJ/mol and ΔS° = -42.3 J/K*mol, at 25.0°C and 1 atm, is -28.40 kJ/mol.
The reaction is:
CO(g) + H₂O(g) ⇄ CO₂(g) + H₂(g) (1)
Gibbs free energy for reaction (1) is given by:
\( \Delta G^{\circ} = \Delta H^{\circ} - T\Delta S^{\circ} \)
Where:
ΔH°: is the enthalpy of the reaction = -41.0 kJ/mol
ΔS°: is the entropy of the reaction = -42.3 J/K*mol
T: is the temperature = 25.0 °C = 298 K
The value of ΔG° is:
\( \Delta G^{\circ} = \Delta H^{\circ} - T\Delta S^{\circ} = -41.0 kJ/mol - 298 K(-42.3 \frac{J}{K*mol}*\frac{1 kJ}{1000 J}) = -28.40 kJ/mol \)
Therefore, the value of ΔG° is -28.40 kJ/mol.
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When the equation below is balanced, what is the coefficient for ammonia gas?
_NH3(g) + _O2(g) → _N2(g) + _H2O(g)
Answer:
4NH3(g) + 3O2(g) → 2N2(g) + 6H2O(g)
Explanation:
What is an extensive property that can be calculated?
A Boiling point
B Volume
C Viscosity
D Specific Heat
sample of brown dye from a lolly is placed at the origin on a strip of a chromatography plate. The solvent front moves 15.0 cm from the origin. A blue component of the dye moves 5 cm and a red component 3 cm in the same time. Calculate the Rf values of the two components
The Rf value for the blue component is approximately 0.333, and the Rf value for the red component is 0.2.
The Rf value, or the retention factor, is a ratio used in chromatography to quantify the migration distance of a component relative to the migration distance of the solvent front. It is calculated using the formula:
Rf = (distance moved by the component) / (distance moved by the solvent front)
Given the information provided:
Distance moved by the blue component = 5 cm
Distance moved by the red component = 3 cm
Distance moved by the solvent front = 15 cm
Now we can calculate the Rf values for the blue and red components:
Rf_blue = (distance moved by the blue component) / (distance moved by the solvent front)
= 5 cm / 15 cm
= 1/3
≈ 0.333
Rf_red = (distance moved by the red component) / (distance moved by the solvent front)
= 3 cm / 15 cm
= 1/5
= 0.2
Therefore, the Rf value for the blue component is approximately 0.333, and the Rf value for the red component is 0.2.
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you dont have to explain the answers to each one i just need to know the answers
The first step to answer this question is to balance the given equation, to do it assign 2 as the coefficients of NaOH and H2O:
\(2NaOH+H_2SO_4\rightarrow2H_2O+Na_2SO_4\)8. To find the number of moles used to neutralize the river water we have to multiply the volume used by the concentration of the NaOH solution, remember that this volume has to be converted to liters first and that M=mol/L:
\(2.5mL\cdot\frac{1L}{1000mL}\cdot\frac{0.1mol}{L}=0.00025mol\)There are 0.00025moles of NaOH in the solution.
9. According to the given reaction, 2 moles of NaOH react with 1 mole of H2SO4. Using this ratio we can find the number of moles of sulfuric acid in the river:
\(0.00025molNaOH\cdot\frac{1molH_2SO_4}{2molNaOH}=0.000125molH_2SO_4\)There are 0.000125moles of H2SO4 in the river.
10. To find the concentration in the river, divide the amount of moles by the volume of the river in liters:
\(\frac{0.000125molH_2SO_4}{250mL\cdot\frac{1L}{1000mL}}=0.0005M\)The concentration of H2SO4 in the river is 0.0005M
11. For every mole of H2SO4, there are 2 moles of H+, it means that the concentration of H+ ions is:
\(0.0005M\cdot\frac{2molH^+}{1molH_2SO__4}=0.001M\)The concentration of the H+ ions in the river is 0.001M
12. Use the given formula to find the pH of the solution:
\(\begin{gathered} pH=-log\lbrack H^+] \\ pH=-log(0.001M) \\ pH=3 \end{gathered}\)The pH of the river solution is 3.
13. Fish can tolerate neutral values of pH, those are within the range of 6.5-7.5. It means that these fish can't tolerate the acidity of this river.