A laser is used in eye surgery to weld a detached retina back into place. The wavelength of the laser beam is 581 nm, and the power is 1.5 W. During surgery, the laser beam is turned on for 0.050 s. During this time, how many photons are emitted by the laser?

The tank division's total displacement from the base is approximately 75.9 miles at a bearing of W67.4S.

To calculate the total displacement of the tank division, we need to find the vector sum of the two legs of their journey.

We can see that the tank division travelled 30 miles to the west (W30) and then 70 miles to the north (N70), so their total displacement is the vector sum of these two legs.

To add vectors, we need to break them down into their horizontal and vertical components.

For the first leg, the tank division travelled 30 miles to the west, so its horizontal component is -30 (since it's to the left of the base) and its vertical component is 0 (since it didn't travel up or down).

For the second leg, the tank division travelled 70 miles to the north, so its horizontal component is 0 (since it didn't travel left or right) and its vertical component is 70 (since it travelled directly north).

Now we can add these components to get the total displacement:

Horizontal component = -30 + 0 = -30

Vertical component = 0 + 70 = 70

So the total displacement is a vector with a horizontal component of -30 and a vertical component of 70.

We can use the Pythagorean theorem to find the magnitude of this vector:

|displacement| = √((-30)² + 70²) ≈ 75.9 miles

And we can use trigonometry to find the direction of this vector:

\(\theta = tan^{-1}\dfrac{70} { -30}\)

θ ≈ -67.4°

So the tank division's total displacement from the base is approximately 75.9 miles at a bearing of W67.4S.

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The gravitational force F between two bodies of respective masses M and m and distance R is

\(F = G\dfrac{Mm}{R^2}\)

where G ≈ 6.7 × 10⁻¹¹ m³/(kg•s) is the universal gravitational constant.

8.1.1. Let M = mass of Earth, m = mass of person, and R = radius of Earth. At point C, the distance between the center of the Earth and the person is 3R, so the gravitational force has magnitude

\(F = G \dfrac{\left(6.0\times10^{24}\,\mathrm{kg}\right) \left(50\,\mathrm{kg}\right)}{3\times6.4\times10^6\,\mathrm m} \approx \boxed{1.0\times10^9 \,\mathrm{N}}\)

8.1.2. Using the same values for M and m, now take R = radius of Earth + 10³ m. Then the gravitational force is

\(F = G \dfrac{\left(6.0\times10^{24}\,\mathrm{kg}\right) \left(50\,\mathrm{kg}\right)}{\left(6.4\times10^6+10^3\right)\,\mathrm m} \approx \boxed{3.1\times10^9 \,\mathrm{N}}\)

Answer:

240 C

Explanation:

Given:

To find:

Solution: Formula relating Q, I and t is given as:

Thus, 240 Coulomb charge will pass through the wire.

Answer:

For a given system, there can be particular transformations for which the explicit equations of motion are the same for both the old and new variables. Transformations for which the equations of motion are invariant, are called invariant transformations. It will be shown that if the Lagrangian does not explicitly contain a particular coordinate of displacement  qi, then the corresponding conjugate momentum,  pi, is conserved. This relation is called Noether’s theorem which states “For each symmetry of the Lagrangian, there is a conserved quantity".

Answer:

those are all correct. The arrows are matched correctly

Answer:

40 m

Explanation:

vf = vo + at            f = final  o = original  

0 = 20 - 5t       t = 4 seconds

Average speed = ( 20 - 0 ) / 2 = 10 m/s for    4 seconds = 40 meters

or

df = do + vo t   + 1/2 a t^2

   = 0 + 20 (4) - 1/2 (5)(4^2) = 40 meters

The correct option is b) Observations of the amount of hydrogen in the universe.

What is big bang theory?

The Big Bang Theory is the most popular theory about how the cosmos came into being. Simply expressed, it claims the universe as we know it began with an unimaginably hot and dense single point that expanded and contracted over the course of the following 13.7 billion years, first at incomprehensible speeds and then at a more palpable rate, to the still-expanding cosmos that we know today.

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Answer:

a) 2250 J

b) 0 J

c) 2250 J

Explanation:

a) Since, the process is isochoric

the change in internal energy

\(\Delta U = n C_v(T_f-T_i)\)

Here, n = 0.2 moles

Cv = 12.5 J/mole.K

We have to find T_f so we can use gas equation as

\(\frac{P_1V_1}{P_2V_2} =\frac{T_i}{T_f}\\Since, V_1=V_2 [isochoric/process]\\\Rightarrow \frac{P_{atm}}{4P_{atm}} = \frac{300}{T_f} \\\Rightarrow T_f = 1200 K\)

So,  \(\Delta U= 0.2\times12.5(1200-300)\\=2250 J\)

b) Since, the process is isochoric no work shall be done.

c) By first law of thermodynamics we have

\(\Delta U = Q-W\\Since, W = 0\\\Delta U = Q\\Therefore, Q = 2250 J\)

Since, Q is positive 2250 J of heat will flow into the system.

Answer:

Walking –We can walk only if we apply frictional force. Friction is what holds your shoe to the ground. The friction present on the ice is very little, this is the reason why it is hard to walk on the slippery surface of the ice.

Writing – A frictional force is created when the tip of the pen comes in contact with the surface of the paper. Rolling friction is what comes into play while writing with a ballpoint pen while sliding friction arises when one writes with a pencil.

Skating – A thin film of water under the blade is necessary to make the skate slide. The heat generated by the skate blade rubbing against the surface of ice causes some of the ice to melt right below the blade where the skater glides over the ice. This water acts as a lubricant reducing friction.

Lighting a matchstick – When the head of the matchstick is rubbed against a rough surface, heat is generated and this heat converts red phosphorous to white phosphorous. White phosphorous is highly inflammable and the match stick ignites. Sometimes, matchsticks fail to ignite due to the presence of water. Water lowers friction.

Driving of the vehicle on a surface- While driving a vehicle, the engine generates a force on the driving wheels. This force initiates the vehicle to move forwards. Friction is the force that opposes the tyre rubber from sliding on the road surface. This friction avoids skidding of vehicles.

Applications of breaks in the vehicle to stop it- Friction braking is the most widely used braking method in vehicles. This process involves the conversion of kinetic energy to thermal energy by applying friction to the moving parts of a vehicle. The friction force resists the motion and in turn, generates heat. This conversion of energy eventually bringing the velocity to zero.

Flight of aeroplanes- Drag is the force that opposes the forward motion of the aeroplane. The friction which resists the motion of an object moving through a fluid or immobile in a moving fluid, as occurs when we fly a kite. The friction of the air is created as it meets and passes over an aeroplane and its components. Drag is generated by air impact force, skin friction and displacement of the air.

Drilling a nail into the wall- Friction is responsible for fixing of nails in a wall. As the nail is driven into the wall, the nearby material to the nail of the wall gets compressed. This exerts a force on the nail. This force is the friction that converts the normal force exerted by the compressed layers of the wall into the resisting shear force. In this manner the friction cause nails and screws to hold on to walls.

The dusting of the carpet by beating it with a stick- When the carpet is beaten with the stick, the dust comes out. The dust is carried off by the wind or falls on the floor. The carpet exhibits a little static friction that holds the dust to the carpet.  When the carpet is beaten, it will overcome the friction and the carpet will move away from the dust making the carpet free from dust.

Sliding on a garden slide- We know that friction is a force that is present whenever two objects rub against each other. In case of a slide in the garden such as a slide and a person’s backside rub each other’s surface. Without friction, a slide would accelerate the rider too quickly, resulting in possible injury due to the fall. The friction reduces the velocity of the sliding person and makes him stop.

Hope that helps! :D Sorry if it's too lengthy...

Explanation:

Answer:

The dart won't hit within 1.00 cm of the bullseye

Explanation:

First, we need to calculate the time that the dart takes to hit the dartboard. This can be calculated using the distance of 5.7 m and the horizontal speed of 21.3 m/s, so

Then, with this time we can calculate the change in height of the dart, using the following equation

Where vo is the initial vertical velocity, so vo = 0 m/s, g is the gravity, so g = 9.8 m/s², and t is 0.268 s.

So, replacing the values, we get:

Since Δy is greater than 1 cm, the dart will not hit within 1.00 cm of the bullseye. So, to adjust the shot, you should release the dart from 35.09 cm above.

(a)The units for weight are typically expressed in Newtons (N), while mass is measured in kilograms (kg).

(b)The weight of Curiosity on Earth is approximately 8820 Newtons.

a) The relationship between weight (P) and mass (m) is given by the formula P = m * g, where g represents the acceleration due to gravity. The units for weight are typically expressed in Newtons (N), while mass is measured in kilograms (kg).

b) To calculate the weight of Curiosity on Mars, we need to determine the acceleration due to gravity on Mars. The acceleration due to gravity on Mars is approximately 3.71 m/s². Using the weight formula, we have P = m * g = 900 kg * 3.71 m/s² = 3339 N. Therefore, the weight of Curiosity on Mars is approximately 3339 Newtons.

c) The weight of Curiosity on Earth is significantly greater compared to its weight on Mars. On Earth, the acceleration due to gravity is approximately 9.8 m/s². Using the weight formula, we have P = m * g = 900 kg * 9.8 m/s² = 8820 N. Therefore, the weight of Curiosity on Earth is approximately 8820 Newtons.

The difference in weight between Earth and Mars is important because weight is directly related to the force of gravity. The greater weight on Earth indicates a stronger gravitational force, which affects the overall dynamics and requirements for missions like Curiosity.

It affects the launch and landing processes, the structural integrity of the spacecraft, the fuel and energy requirements, and the ability to conduct experiments and operate the robotic systems effectively. Understanding these differences is crucial for mission planning, spacecraft design, and mission success.

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Answer:

coherent

Explanation:

...the laser light sticks together in a tight beam....does not disperse

Answer:

B. Coherent

Explanation:

The term that best describes the light generated by a laser is B) coherent. Lasers produce light that is coherent, meaning that the waves of light are in phase with one another, and travel in a narrow, concentrated beam. This is in contrast to light produced by other sources, which is typically diffused and travels in many different directions.

The length of wire whose resistivity is 3 x 10^-6ohm, and radius is 0.2 mm, with a given value of 15.552 resistance is 6.5268 m.

Given data: r = 0.2 mm = 0.2 x 10^-3m Resistivity = 3 x 10^-6 ohm R = 15.552 ohm

Formula Used: Resistivity (ρ) = (RA)/L

Where, R is resistance, A is the area of cross-section, L is the length of the wire.

Resistance (R) = ρ (L/A)

Multiplying A on both sides, we get

Resistance (R) x A = ρ L ... equation (1)

Area of the cross-section of a wire of radius (r) is given by, A = πr^2

where, π is a constant whose value is 3.14

Substituting the given values, we get

A = πr^2= π (0.2 x 10^-3m)^2= 1.2566 x 10^-7 m^2

Substituting the values of R, A and ρ in equation (1), we get

Length of wire (L) = (Resistance x Area) / Resistivity= (15.552 ohm x 1.2566 x 10^-7 m^2) / (3 x 10^-6 ohm)= 6.5268 m

Therefore, the length of wire whose resistivity is 3 x 10^-6ohm, and radius is 0.2 mm, with a given value of 15.552 resistance is 6.5268 m.

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Considering the Coulomb's Law, the magnitude of the charge on each particle is 4.2426 C.

Coulomb's law or law of electrostatics is the relationship between the interactions of electric charges, that is, it explains the force experienced by two electric charges at rest.

This law says that the electric force with which two point charges at rest attract or repel each other is directly proportional to the product of the magnitude of both charges and inversely proportional to the square of the distance that separates them, expressed mathematically as:

\(F=k\frac{Qq}{d^{2} }\)

where:

The force is attractive if the charges are of opposite sign and repulsive if they are of the same sign.

In this case, you know that:

Replacing in the Coulomb's Law:

\(1.8x10^{-8} N=9x10^{9} \frac{Nm^{2} }{C^{2} }\frac{Qq}{(0.3 m)^{2} }\)

Being Q=q:

\(1.8x10^{-8} N=9x10^{9} \frac{Nm^{2} }{C^{2} }\frac{q^{2} }{(0.3 m)^{2} }\)

Solving:

1.8×10⁻⁸ N÷ 9×10⁹ \(\frac{Nm^{2} }{C^{2} }\)= q²÷ (0.3 m)²

2×10⁻¹⁸ C²/m²= q²÷ (0.3 m)²

2×10⁻¹⁸ C²/m²= q²÷ 0.09 m²

2×10⁻¹⁸ C²/m² ×0.09 m²= q²

1.8×10⁻¹⁹ C²= q²

√1.8×10⁻¹⁹ C²= q

4.2426 C= q= Q

Finally, each charge has a value of 4.2426 C.

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No. That won't help. It's not even true.

Answer:

B. Mass would be the same but its weight would be less on the Moon.

Explanation:

The mass of a body can be expressed as the quantity of matter it contains. While the weight of a body is the extent of the gravitational force impressed on the body by a massive body.

Thus, the mass of a body is constant either on the Earth or on the Moon. But the weight would be less on the Moon because the gravitational force on the Moon is far less than that on the Earth. Therefore the weight would be less on the Moon.

The appropriate option is B.

The mass will remain same on both moon and Earth, but weight will be lesser on Moon than Earth. Hence, option (B) is correct.

The prime focus to solve this problem is the mass and weight of an object. The mass of a body can be expressed as the quantity of matter it contains. While the weight of a body is the extent of the gravitational force impressed on the body by a massive body.

So, the mass of a body is constant either on the Earth or on the Moon. But the weight of an object will depend on the mass and the gravitational acceleration.

W = mg

Here, W is weight, m is mass and g is gravitational acceleration.

Weight would be less on the Moon because the gravitational force on the Moon is far less (due to lower value of g) than that on the Earth. Therefore the weight would be less on the Moon.

Thus, we can conclude that the mass will remain same on both moon and Earth, but weight will be lesser on Moon than Earth. Hence, option (B) is correct.

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Answer:

v = 0.059 m/s

Explanation:

To find the final speed of Olaf and the ball you use the conservation momentum law. The momentum of Olaf and the ball before catches the ball is the same of the momentum of Olaf and the ball after. Then, you have:

\(mv_{1i}+Mv_{2i}=(m+M)v\)  (1)

m: mass of the ball = 0.400kg

M: mass of Olaf = 75.0 kg

v1i: initial velocity of the ball = 11.3m/s

v2i: initial velocity of Olaf = 0m/s

v: final velocity of Olaf and the ball

You solve the equation (1) for v and replace the values of all variables:

\(v=\frac{mv_{1i}}{m+M}=\frac{(0.400kg)(11.3m/s)}{0.400kg+75.0kg}=0.059\frac{m}{s}\)

Hence, after Olaf catches the ball, the velocity of Olaf and the ball is 0.059m/s

As you were holding the block down and in place, the spring exerted an upward force that balanced the downward push by your hand and its own weight. So this restoring force has a magnitude of R such that

R - 50 N - (3 kg) g = 0   =>   R = 79.4 N

As soon as you remove your hand, the block has acceleration a such that, by Newton's second law,

R - (3 kg) g = (3 kg) a   =>   a = (79.4 N - (3 kg) g) / (3 kg) ≈ 16.7 m/s^2

pointing upward.

Answer:

15m/s

Explanation:

Divide distance by time

Answer:

one of the object is at rest after the collision

The box accelerates to the right due to the applied force of 35 N in the +x direction.

Newton's second law states that the acceleration of an object is directly proportional to the net force applied to it and inversely proportional to its mass. In this case, the net force acting on the box is 35 N in the +x direction, and its mass is 15 kg. Therefore, we can calculate the acceleration using the formula:

acceleration = net force / mass

acceleration = 35 N / 15 kg = 2.33 m/s² (rounded to two decimal places)

Since the box is not accelerating up or down, we can conclude that the force applied is only causing the box to accelerate in the horizontal direction.

Other forces such as gravity and friction are not considered in this scenario. Thus, the 15 kg box will experience an acceleration of approximately 2.33 m/s² in the +x direction due to the applied force of 35 N.

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The statement that describes the transformation of the graph of function f onto the graph of function g is: The graph shifts 2 units right and 7 units down.

To determine the transformation of the graph of function f onto the graph of function g, we compare the two functions f(x) and g(x) and observe the changes in the equations.

The function f(x) = (1/x - 3) + 1 represents a reciprocal function that is shifted vertically 1 unit up and horizontally 3 units to the right. The reciprocal function is reflected about the line y = x.

The function g(x) = (1/(1 + 4)) + 3 simplifies to g(x) = 4 + 3 = 7, which is a constant function representing a horizontal line at y = 7.

By comparing the equations, we can see that the transformation from f(x) to g(x) involves the following changes:

The term 1/x in f(x) is replaced by the constant 1/(1 + 4) in g(x), resulting in a vertical shift of 7 units up.

The term -3 in f(x) is replaced by 3 in g(x), resulting in a vertical shift of 3 units up.

The +1 in f(x) is replaced by +3 in g(x), resulting in an additional vertical shift of 2 units up.

Therefore, the overall transformation is a shift of 2 units to the right and 7 units down.

Hence, the correct statement is: The graph shifts 2 units right and 7 units down.

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The mass of a substance is not directly related to latent heat. Instead, latent heat is a parameter that describes the amount of energy required or released during a phase shift of a substance.

Latent heat can be thought of as hidden energy that is supplied or extracted to change the state of a substance without changing its temperature or pressure.

Latent heat is energy released or absorbed, by a body or a thermodynamic system, during a constant-temperature process—typically a first-order phase transition.

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Answer:

Q = 1386  J

Explanation:

Mass, m = 60 g = 0.06 kg

Specific heat of copper, c=385 J/kg K

It is heated from 20°C to 80°C.

We need to find the heat absorbed. It can be given by the formula as follows :

\(Q=mc\Delta T\\\\Q=0.06\times 385 \times (80-20)\\\\Q=1386\ J\)

So, 1386  J of heat is absorbed.

Answer:

my mom

Explanation:

she gave birth to me!

Answer: Wu Lien-teh, was a Malayan physician renowned for his work in public health, particularly the Manchurian plague of 1910–11.

Explanation:

X_X

Answer:

  F = 520 N

Explanation:

For this exercise the rotational equilibrium equation should be used

          Σ τ = 0

Let's set a reference system with the origin at the back of the refrigerator and the counterclockwise rotation as positive. On the x-axis it is horizontal directed outward, eg the horizontal y-axis directed to the side and the z-axis vertical

Torque is

             τ = F x r

the bold indicate vectors, we analyze each force

the applied force is horizontal along the -x axis, the arm (perpendicular distance) is directed in the z axis,

The weight of the body is the vertical direction of the z-axis, so the arm is on the x-axis

                 -F z + W x = 0

                 F z = W x

                 F =  \(\frac{x}{z}\)  W

The exercise indicates the point of application of the force z = 1.5 m and the weight is placed in the center of mass of the body x = 0.6 m, we are assuming that the force is applied in the wide center of the refrigerator

let's calculate

                 F = 1300 0.6 / 1.5

                 F = 520 N