Answer:
The power of the kettle is P = 1 watt.
Explanation:
The definition of power is:
Power equals the quotient between work and time, or:
P = w/t.
In this case, we know that the work is:
w = 1J
And the time is:
t = 1 s
Then the power will be:
P = 1J/1s = 1 J/s
Also knowing that:
1 J/s = 1 W
(w is the unit for Watt)
We can conclude that the power of the kettle is:
P = 1 W
Question 15 (1 point
[01.03)
Which statement is true going
Oo
Ос
Gravity is the force of attraction between two dojeas with mask and is tecedent on the distance been these objes
Granty is the force that resesto dojects that have opposite charges. It is dependent upon the charges of the objec
Greity is a force that keeps dojects moving in space. The less the objects wegs, the former out in space gauty will pull the
Object
Gravity is the force of resistance to a change in position. The greater the distance been objects, the greater tis force will
Oo
Explanation:
The true statement about gravity is that it is the force of attraction between two objects with masses and also, based on the distance between these objects.
Gravity is a force of attraction.
The best scientific overview of the force of gravity is given by the Newton's law of universal gravitation which states that "the force of gravity between two objects is directly proportional to the product of their masses and inversely proportional to the square of the distance between them",
So, gravitational force of attraction is dependent on mass and the distance between two bodies.
a convex mirror has a focal length of -12 cm. a lightbulb with diameter of 6 cm is placed 60 cm from the mirror
Here the focal length of the convex mirror as -12 cm, a light bulb with a diameter of 6 cm is placed 60 cm from the mirror. Hence, the image distance is -60 cm, and the image height is 6 cm.
To find the image distance and height, we will use the mirror formula for a convex mirror, which is given as follows;1/f = 1/v + 1/u. Where, f = focal length of the convex mirror;
v = the image distance;
u = the object distance
If the object distance is positive, it means the object is placed in front of the mirror, and if it is negative, it means the object is placed behind the mirror. The focal length of a convex mirror is always negative, as given above.
Therefore, u = -60 cm and f = -12 cm.
Plugging in the values in the mirror formula, we get:1/-12 = 1/v + 1/-60=> -5/60 = 1/v - (1/60) => -5/60 = (60 - v)/60=> v = -300/5= -60 cm
The image distance is -60 cm, which means the image is virtual and erect. The negative sign indicates that the image is formed behind the mirror.
To find the image height, we use the magnification formula:
m = -v/u= -(-60)/(-60)= 1
The magnification is 1, which means the image is of the same size as the object. The height of the light bulb is 6 cm, so the height of the image will also be 6 cm.
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A train travelled from Hong Kong to Beijing. It travelled at an average speed of 160 km/h in the first 4 hours. After that, it travelled at another average speed of 180 km/h. If the distance between Hong Kong to Beijing is 1180 km, what was the total time for the whole journey?
Answer: 7 hours
Explanation:
h=hours
160*4=640
1180-640=180h
180h=540
h=3
3+4=7 hours
Answer:
7h
Explanation:
4.160=640km
1180-640=540km
540:180=3h
3+4=7h
Distinguish between kinectic energy and potential energy
Answer:
kinectic energy-in physics kinetic energy of an object is the energy that it possesses due to its motion
it is defined as the work needed to accelerate a body of a given mass from rest to its started velocity.having gained this energy during its accelerationThe body maintains this kinetic energy unless its speed changes.
potential energy-in physics potential energy is the energy held by an object because of its position relative to other objects,its electric charge,or other factors
in the case of a bow and arrow ,when archer does work on the bow drawing the string back some if the chemical energy of the archer's body is transformed into elastic potential energy in the bent limb of bowAnswer:
Hey!
Well KINETIC ENERGY is...
the energy generated by the / of the object is that it possesses due to its motion...
POTENTIAL ENERGY is...
The energy held by an object because of its position relative to other objects, its electric charge, or other factors...
Explanation:
So in easier terms, KINETIC ENERGY is just the ENERGY GENERATED BY THE OBJECT'S MOVEMENT and...
POTENTIAL ENERGY IS THE TOTAL AMOUNT OF ENRGY THAT THE OBJECT HOLDS (due to an electric charge etc)
Hope this helps!
How much work is done by a man if he moves a distance of 15m by applying the force of 20N? Find his power if he does the work in 2 seconds. (answer - 300 joule,150w)
Work= Distance × Force
15 metre × 20 N
300 Joule
Now ,
Power,
2 seconds = 300/2
150 watt
We know that
Unit of Work is Joule
Unit of Power is watt
So,
Work - 300 joule
Power= 150 watt
Which statement is true of
buoyancy?
A. Buoyancy takes up space.
B. Buoyancy causes things to sink.
C. Buoyancy acts in the opposite direction of
gravity.
Answer:
c
Explanation:
because the gravity are expectation
what is the function of layer of air trapped under the hovercraft
Answer:b
Explanation:
The air trapped under the hovercraft is used to provide the lift force by creating a cushion of pressurised air under the hovercraft.
What is friction?Friction is a type of force that resists or prevents the relative motion of two physical objects when their surfaces come in contact.
The friction force prevents any two surfaces of objects from easily sliding over each other or slipping across one another. It depends upon the force applied to the object.
A hovercraft is machine used to uplift the heavy object by using the lift force of the air trapped under the hovercraftcraft used to provide the pressure that is utilised for the uplifting of the heavy bodies.
The layer of air trapped under the hovercraft provide the necessary cushion for the proper functioning of the hovercraft , the pressure of the trapped layer of air has slightly higher pressure than the atmospheric air.
Thus,the function of layer of air trapped under the hovercraft is to reduce the amount of friction when hovercraft provide movement and uplift object over rough surfaces.
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A tuning fork of frequency 200 hertz can resonate if an incident sound wave has a frequency of
200 hertz.
100 hertz.
both of these
neither of these
A tuning fork of frequency 200 hertz can resonate if an incident sound wave has a frequency of 200 hertz.
The phenomenon of resonance occurs when an object vibrates at its natural frequency in response to an external stimulus of the same frequency. In this case, the tuning fork has a natural frequency of 200 Hz. When an incident sound wave with the same frequency of 200 Hz reaches the tuning fork, it causes the fork to vibrate with a larger amplitude.
This resonance amplifies the sound produced by the tuning fork. The length constraint requires the explanation to be concise, which highlights the basic concept of resonance between the incident sound wave and the tuning fork's natural frequency.
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Suppose a vehicle begins at rest at t=0 and accelerates at a rate given by the equation a(t) = (15 m/s^) t . Assume nonuniform acceleration.
Find the velocity a 3 seconds.
Find the displacement at 3 seconds.
Must show work.
Answer:
See below
Explanation:
Since it is non-uniform acceleration ( it varies with time as given)
The integral of acceleration is velocity
so integrate between 0 and three 15 m/s^2 t
= 1/2 ( 15 t^2 ) + k between 0 and 3 ( k is a constant we will ignore)
= 67.5 - 0 = 67.5 m/s velocity
the integral of velocity is displacement
1/2 (15t^2 ) integrated becomes 1/6 15 t^3 from 0 to 3 ( ignoring a constant again)
1/6 * 15 * (3^3 ) = 67.5 meters displacement
THANX for those who noted my errors in my first posted response !!
an excited nucleus emits a gamma-ray photon with an energy of 2.70 mev . part a what is the photon’s energy in joules? express your answer in joules.What is the photon's frequency? Express your answer in hertz.
The photon's energy in joules is 4.32 x \(10^{-13\) J, and its frequency is 6.53 x \(10^{20\) Hz.
To convert the energy of the gamma-ray photon from MeV to joules, use the conversion factor:
1 MeV = 1.602 x \(10^{-13\) J.
Multiply the given energy by this factor:
2.70 MeV x 1.602 x \(10^{-13\) J/MeV = 4.32 x \(10^{-13\) J.
To find the frequency, use the Planck's equation:
E = hν,
where
E is energy,
h is Planck's constant (6.63 x \(10^{-34\) J s), and
ν is the frequency.
Rearrange the equation to solve for frequency:
ν = E/h.
Substitute the energy in joules: ν = (4.32 x \(10^{-13\) J) / (6.63 x \(10^{-34\) J s) = 6.53 x \(10^{20\) Hz.
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The frequency of the gamma-ray photon is 6.53 x \(10^{20\) Hz.
The energy of a gamma-ray photon can be converted from electronvolts (eV) to joules (J) using the conversion factor:
1 eV = 1.602 x \(10^{-19\)J
Therefore, the energy of the gamma-ray photon with an energy of 2.70 MeV (mega-electronvolts) can be calculated as follows:
E = 2.70 MeV x 1,000,000 eV/1 MeV x 1.602 x \(10^{-19\) J/eV
E = 4.33 x \(10^{-13\) J
So the energy of the gamma-ray photon is 4.33 x \(10^{-13\) J.
The frequency of the gamma-ray photon can be calculated using the equation:
E = hf
where E is the energy of the photon, h is Planck's constant (6.626 x 10^-34 J s), and f is the frequency of the photon. Rearranging this equation to solve for f, we get:
f = E/h
Substituting the value of E we just calculated and the value of h, we get:
f = (4.33 x\(10^{-13\) J)/(6.626 x \(10^{-34\) J s)
f = 6.53 x \(10^{20\) Hz
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Problem 4:
A body fell vertically from the top of a tower. It covered 123.1 m in the final two seconds
before hitting the ground. Determine the height of the tower rounding your answer to the
nearest two decimal places. Let the acceleration due to gravity g=9.8 m/s2.
Answer:
v2^2 - v1^2 = 2 g s fundamental formula
v2 = v1 + 2 g = v1 + 19.8 increase in velocity in 2 sec
v1^2 + 39.6 v1 + 392 - v1^2 = 2 * 9.8 * 123.1 = 2412.76
v1 = (2412.76 - 392) / 39.6 = 51.03
v2 = 51.03 + 19.6 = 70.63
T = 70.63 / .8 = 7.207 sec time to fall height of tower
S = 1/2 g T^2 = 4.9 * 7.207^2 = 254.5 m
(Note v2^2 - v1^2 = 70.63^2 - 51.03^2 = 2385 m
2385 / (2 * 9.8) = 122 m (close to 123.1 as was given
A force of 15 newtons is used to push a box along the floor a distance of 3 meters. How much was done?
Answer:
\(45 J\)
Explanation:
The equation for work is:
\(Work=Force*Distance\)
We can substitute the given values into the equation:
\(Work=15N*3m\\Work=45Nm\\Work=45J\)
Answer:
45 J
Explanation:
w =fd
w = 15(3)
.Part A Theory Please study orbital motion concept and answer the following questions. 1. Describe and discuss the Newton's law of gravity. 2. What is orbital motion? List equations of circular orbit: orbital period T, orbital speed v, orbital mechanical energy, and potential energy. 3. The orbit of International Space station is almost circular with radius r = 6770 km and mass m = 4.20 x 105 kg. Calculate its period T (min), orbital speed (km/s), and orbital mechanical energy (J). G = 6.674 x 10-11 Nm²/kg?, Mass of Earth Me = 5.972 x 1024 kg. Radius of Earth: Re = 6.37 x 106m
Newton's law of gravity describes the force of attraction between two objects due to their masses. Orbital motion refers to the motion of an object around another object under the influence of gravity. The equations for a circular orbit include the orbital period T, orbital speed v, orbital mechanical energy, and potential energy.
Newton's law of gravity states that the gravitational force between two objects is directly proportional to the product of their masses and inversely proportional to the square of the distance between their centers.
Mathematically, it can be expressed as F = G * (m₁ * m₂) / r², where F is the gravitational force, G is the gravitational constant, m₁ and m₂ are the masses of the objects, and r is the distance between their centers.
Orbital motion occurs when an object moves around another object in a closed path due to the gravitational force. In a circular orbit, the equations are as follows:
1. Orbital period (T) is the time taken for one complete revolution and is given by T = 2π * √(r³ / (G * M)), where r is the radius of the orbit, G is the gravitational constant, and M is the mass of the central object.
2. Orbital speed (v) is the speed at which the object moves along its orbit and is given by v = √(G * M / r).
3. Orbital mechanical energy (E) is the sum of kinetic and potential energies and is given by E = - (G * M * m) / (2r), where m is the mass of the orbiting object.
4. Potential energy (U) is the energy associated with the position of the object in the gravitational field and is given by U = - (G * M * m) / r.
For the International Space Station (ISS) with a radius r = 6770 km and mass m = 4.20 x 10⁵ kg, we can calculate its period, orbital speed, and orbital mechanical energy using the given values and constants.
To find the period T, we use the equation T = 2π * √(r³ / (G * M)), where M is the mass of the Earth and G is the gravitational constant.
To find the orbital speed v, we use the equation v = √(G * M / r).
To find the orbital mechanical energy E, we use the equation E = - (G * M * m) / (2r).
By substituting the given values into the equations and using the provided values for G, Me, and Re, we can calculate the period, orbital speed, and orbital mechanical energy of the ISS.
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what is the round-trip time (rtt) latency in milliseconds for cisco dna center across the intra-cluster link?
The round-trip time (RTT) latency in milliseconds for Cisco DNA Center across the intra-cluster link is typically less than 5 milliseconds.
RTT latency is a measure of the time it takes for a signal to travel from one point in a network to another and back again. In the case of Cisco DNA Center, this measurement is taken across the intra-cluster link, which connects the different components of the DNA Center cluster.
It is important to note that RTT latency can vary depending on a variety of factors, including network congestion and the distance between the two points.
However, in general, the RTT latency for Cisco DNA Center across the intra-cluster link is very low, typically less than 5 milliseconds. This ensures that the different components of the DNA Center cluster can communicate with each other quickly and efficiently.
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For the circuit shown, which of the following statements is true?
Answer:
ΔV1 = ΔV2 = I1 R1 = I2 R2
The first answer is correct - the voltage drop is the same across either resistor
I = I1 + I2 because the current splits on entering the resistors
star a and star b have measured stellar parallax of 0.58 arc second and 0.73 arc second, respectively. which star is closer?
Star B is closer than star A, because 1/ 0.58 = 1.72 pc, while 1/.73 = 1.36 pc.
What is stellar parallax and distance measurement using stellar parallax?To calculate the distances to nearby stars, astronomers employ a phenomenon known as parallax. The apparent displacement of an object due to a change in the viewer's point of view is known as parallax. The distances between close stars can be calculated using this phenomenon. A nearer star will seem to move against the farther-off background stars as the Earth revolves around the Sun. By measuring a star's position once, then again six months later, astronomers can establish the apparent shift in location of that star. The apparent motion of the star is referred to as stellar parallax.
A straightforward correlation exists between the distance of a star and parallax angle:
\(d=\frac{1}{p}\)
The distance d and parallax angle p are both measured in parsecs and arcseconds, respectively.
Stellar parallax of star A= 0.58 arcseconds
Stellar parallax of star B= 0.73 arcseconds
So, on applying the formula,
The distance of the star A= 1.72pc
And the distance of the star B= 1.36pc
Therefore, star B is closer than star A.
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Fill in the blanks….
Answer:
An object is considered to be accelerating if the object is changing its rate in speed, decreases in speed, or changes the object's direction
What impact parameter will give a deflection of 1 degree for an alpha particle of energy 7. 7 MeV incident on a gold nucleus (Z = 79)
The impact parameter that will give a deflection of 1 degree for an alpha particle of energy 7.7 MeV incident on a gold nucleus (Z = 79) is 9.38 x \(10^{-14}\) m.
The formula used to calculate impact parameter (b) is given by;
`b = [(z1*z2*\(e^2\))/(4πε0m\(v^2\))](cot(θ/2))`
Where, z1 and z2 are the atomic numbers of the interacting nuclei, e is the charge of an electron, ε0 is the permittivity of free space, m is the mass of the alpha particle, v is the velocity of the alpha particle, θ is the scattering angle.
The angle of deflection is 1 degree which is equal to 0.01745 radians. Given that an alpha particle of energy 7.7 MeV is incident on a gold nucleus (Z = 79).
The mass of the alpha particle (m) = 4u
Energy of the alpha particle (E) = 7.7 MeV
Charge of the alpha particle (e) = 2e
Atomic number of the gold nucleus (Z) = 79
Velocity of the alpha particle (v) can be calculated using the formula for kinetic energy given by;
`K = (1/2)\(mv^2\)
`Where, K is the kinetic energySubstitute the values to find v;`7.7*\(10^6\) eV = (1/2) * 4u * \(v^2\)``v = \(\sqrt{[(2*7.7*10^6)/(4*931.5*10^6)]`}\)
`v = 0.0132 m/s`
Now substitute all the known values in the formula for impact parameter;
b = [(z1*z2*\(e^2\))/(4πε0\(mv^2\))](cot(θ/2))`
= \([(79*2*1.6*10^{-19})^2/(4\pi *8.85*10^{-12}*4*3.14*0.0132*4*1.66*10^{-27})](cot(0.008725))\)`
= 9.38*\(10^{-14} m\)`
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scientists now believe that comets falling to early earth played a role in the evolution of life. what role did these comets play?
Scientists propose that comets falling to early Earth played a significant role in the evolution of life by delivering organic compounds and water to the planet. This hypothesis is known as the "cometary impact theory" or "panspermia theory."
Comets are icy bodies composed of various volatile compounds, including water, organic molecules, and complex carbon-based compounds. When comets collide with a planet's atmosphere or surface, they can release these materials into the environment.
Here's how comets could have contributed to the evolution of life on Earth:
1. Delivery of Organic Compounds: Comets are believed to contain complex organic molecules, including amino acids, nucleobases, and sugars—building blocks of life. These organic compounds may have formed in the early solar system or within the comets themselves. When comets impacted the Earth, they could have deposited these organic compounds, enriching the planet's early environment with the necessary ingredients for life.
2. Supply of Water: Comets are predominantly composed of ice, including frozen water. Early Earth was hot and arid, with limited water availability. The impact of comets brought substantial amounts of water to the planet, contributing to the formation of oceans, lakes, and other bodies of water. Water is essential for the emergence and sustenance of life as we know it.
3. Energy Sources: Cometary impacts also released significant amounts of energy in the form of heat and shockwaves. This energy could have catalyzed chemical reactions and provided the necessary energy for the synthesis of complex organic molecules or the activation of prebiotic reactions.
4. Protection of Organic Material: Comets may have acted as protective vessels, shielding the organic material they carried from destructive processes such as ultraviolet radiation and harsh conditions in space. This protection could have increased the chances of organic compounds surviving the journey through the Earth's atmosphere and reaching the surface intact.
While the exact mechanisms and extent of cometary involvement in the origin of life are still subjects of ongoing scientific research and debate, the idea that comets played a role in delivering organic compounds and water to early Earth is supported by evidence from meteorite analysis, spacecraft observations, and laboratory experiments.
In summary, comets falling to early Earth are believed to have brought organic compounds, water, and energy, potentially contributing to the development of the conditions necessary for life to emerge and evolve.
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During a certain time interval, a constant force delivers an average power of 4 watts to an object. If the object has an average speed of 2 meters per second and the force acts in the direction of motion of the object, the magnitude of the force is:____.
A) 16N
B) 8N
C) 6N
D) 4N
E) 2N
The magnitude of the force of the object which has the power of 4 watts and a velocity is 2 m/s is 2N.
The power of the object = 4 Watts
The velocity of the object = 2 m/s
The force of the object can be found using the formula,
P = Fv
where P is the power
F is the force
v is the velocity
Let us rearrange the equation,
F = P/v
Let us substitute the known values in the above equation, we get
F = 4 / 2
= 2 N
The magnitude of the force of the object is 2N.
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A bus Starts from rest. If the acceleration of bus become 10 m/s2 after 15 sec Calculate the final Velocity of the bus
fill the blank. Whenever the net force on an object is zero, its acceleration ................
Whenever the net force on an object is zero, its acceleration is zero.Whenever the net force on an object is zero, its acceleration is zero. This means that the object is either at rest or moving at a constant velocity.
The net force on an object can be determined by summing up all the individual forces acting on it, and if the net force is zero, then the object is in a state of balanced forces, which results in a constant velocity or no acceleration. It is important to note that an object can still be in motion even if the net force on it is zero, as long as it is moving at a constant velocity.
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how do you find the total magnification of a microscope
The answer to the question of finding the total magnification of a microscope is the product of the magnifying power of the eyepiece and the magnifying power of the objective.
it is important to note that a microscope is an optical instrument that uses a lens or a combination of lenses to produce magnified images of small objects. The magnification produced by a microscope is the ratio of the size of the image to the size of the object.
The total magnification of a microscope is the magnification produced by the objective lens and the eyepiece. The objective lens is responsible for producing an enlarged image of the specimen on the stage of the microscope. The magnified image is then further enlarged by the eyepiece, which produces an image that is seen by the observer.
To find the total magnification of a microscope, you need to multiply the magnification of the objective lens by the magnification of the eyepiece. The magnification of the objective lens is usually engraved on the lens itself, while the magnification of the eyepiece is usually printed on it.
Once you know the magnification of both the objective and the eyepiece, you can simply multiply them to find the total magnification of the microscope.
In conclusion, to find the total magnification of a microscope, you need to multiply the magnification of the objective lens by the magnification of the eyepiece. The magnification produced by a microscope is the ratio of the size of the image to the size of the object.
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what is the s. i unit of current
Answer:
The SI unit of current is Ampere(A)
Answer:
Ampere ( A)
Explanation:
the S.I unit of current is Ampere(A)
What force is needed to give a 0.25 kg arrow an acceleration of 196 m/s² question 10 options: 0.25n 49n 196n 748n
The force that is needed to accelerate the arrow is 49 Newtons.
To determine magnitude of the force needed to give a 0.25 kg arrow an acceleration of 196 m/s², we can use the equation of force:
F = ma
where F is the force, m is the mass, and a is the acceleration.
Given that m = 0.25 kg and a = 196 m/s², we can substitute these values into the equation and solve for F:
F = (0.25 kg)(196 m/s²)
F = 49 N
So the force needed to give a 0.25 kg arrow an acceleration of 196 m/s² is 49 N. This is the correct answer out of the options given.
To arrive at this answer we used Newton's second law of motion, which states that the force acting on an object is equal to the mass of the object multiplied by its acceleration. Thus, we were able to use the equation "F = ma" (where F is force, m is mass and a is acceleration) to solve for the force required to accelerate the arrow at 196 m/s².
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The gravitational field strength on Earth is 10 N/kg. What is the gravitational potential energy of a 5 kg mass raised to a height of 3m?
PLEASE HELPP
Answer:
The gravitational potential energy is 150J
Explanation:
P. E=mgh
=5*10*3
the light-collecting area of an 8-meter telescope is _____ times that of a 2-meter telescope.
Answer:
16
Explanation:
The 8-meter telescope has 16 times the light-collecting area of the 2-meter telescope.
The light-collection area of the 8-meter telescope is 16 times greater than that of the 2-meter telescope.
What is Telescope?A telescope is a tool to view distant objects through the electromagnetic radiation to view distant objects through electromagnetic radiation that they emit, absorb, or reflect. The term "telescope" now refers to a broad range of instruments capable of detecting various regions of electromagnetic radiation, and in some cases other types of detectors, in addition to the original meaning of the word, which was only an instrument used to see objects using lenses, reflective surfaces, or a combination of both, to observe distant objects.
Telescopes using glass lenses were the first practical telescopes ever made, and they were developed in the Netherlands at the start of the 17th century. They were employed in astronomy and terrestrial applications.
The first refracting telescope was created several decades before the plane mirror, which employs mirrors to gather and focus light.
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What kind of motion does a torque tend to impart to an object?
A torque tends to impart rotational motion to an object and is responsible for keeping the object in rotation.
Torque in rotational motion is the same as force in linear motion. It is the main factor that maintains an object's rotation. An object rotates at an acceleration inversely proportional to its moment of inertia when a torque is applied to it. Torque is mathematically determined by:
Γ= Ia
where, I is the moment of inertia and a is the acceleration with which the object rotates. Torque has both magnitude and direction and is, thus, a vector quantity. Torque is expressed in Newton metre or Nm.
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What is the equivalent resistance (total resistance) of the series circuit shown?
Answer:
In a series circuit, the equivalent resistance is the algebraic sum of the resistances. The current through the circuit can be found from Ohm's law and is equal to the voltage divided by the equivalent resistance. The potential drop across each resistor can be found using Ohm's law.
Explain why the flux you measure from a light bulb will decrease with the square of the distance, but the flux from a good laser pointer does not depend on distance at all?
The flux of light, which is the amount of light energy per unit area, spreads out as it travels away from its source. This spreading is known as "spreading loss" and is responsible for the decrease in flux with distance.
For a light bulb, the light is emitted in all directions and spreads out in a spherical pattern. The flux at any given distance is spread over a larger area as the distance from the bulb increases, and so the flux decreases with the square of the distance. This is known as the inverse-square law.
For a good laser pointer, the light is emitted in a very narrow, collimated beam. The beam spreads out very little as it travels away from the source, so the flux does not decrease with distance as much as for a light bulb. Additionally, the intensity of the laser beam decreases with distance, but not as quickly as for a light bulb.
As a result, the flux from a good laser pointer does not depend on distance to a significant extent.
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