Empirical formula for your substance is C3H7. I'll demonstrate a different method for calculating the amount of carbon in moles.
What does GCSE empirical formula mean?The simplest entire number quantity of atoms from each component is the empirical formula for the compound. It is empirically determined utilizing data from experiments. For instance, while glucose has the chemical formula C 6H 12O 6, the chemical equation is CH 2O.
How does the empirical formula inform us?Molecular formulae display the quantity of each type of atom found in a molecule, while structural formulas display the simplest whole-number relationship between the atoms in a compound. Empirical formulations display the simplest whole-number relationship between the atoms in a compound.
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Suppose that you put a mass of 10 g of hydrochloric acid and 20 g of magnesium bicarbonate into the reaction; however, you only weigh a product of 5g wet magnesium chloride. Is mass conserved in this reaction? Where would the other products have gone? Explain your reasoning.
Answer:
It would be around 10 grams
Explanation:
6+4
Which two elements non the periodic table are in the same period
What measurements have the same number of significant figures as the measured number
0.1060?
Answer: 0.3224, 7342, 54.32
Explanation:
0.1060 has 4 sig figs (1060 is 4 digits after the decimal point)
How does an atom of tellerium become an ion.
Answer: Element Tellurium (Te), Group 16, Atomic Number 52, p-block, Mass 127.60. ... defined as being the charge that an atom would have if all bonds were ionic.
What ion does tellurium form?
Te+4
Tellurium, ion (Te4+) | Te+4 - PubChem.
Explanation: Tellurium is a chemical element with the symbol Te and atomic number 52. It is a brittle, mildly toxic, rare, silver-white metalloid.
Tellurium
Tellurium Element - Visual Elements Periodic Table
Discovery date 1783
Discovered by Franz-Joseph Müller von Reichenstein
Origin of the name The name is derived from the Latin 'tellus', meaning Earth.
Allotropes
Te
Tellurium
52127.60
Fact box
Group 16 Melting point 449.51°C, 841.12°F, 722.66 K
Period 5 Boiling point 988°C, 1810°F, 1261 K
Block p Density (g cm−3) 6.232
Atomic number 52 Relative atomic mass 127.60
State at 20°C Solid Key isotopes 130Te
Electron configuration [Kr] 4d105s25p4 CAS number 13494-80-9
ChemSpider ID 4885717 ChemSpider is a free chemical structure database
1. Consider NH3.If it dissolves in water(i) NH3 + H20 + NHẤ4+ H2O(ii)NH3 + H2O → NH+3 + OH-(iii) NH3 + H2O + NH+4+ OH-(iv) NH3 + H2O → NH+4+ OH-Which represents the dissolution of NH3 in water(a) i(b) ii (c) iii (d) iv (e) iii and iv2. HOA2+H20 . → H3O+ + OA-CIn this reaction:(i) OA c is the conjugate base of H2O(ii)OA-c is the conjugate base of HOAc (iii) H3O+ is theсconjugate base of HOA.(iv) H3O+ is the conjugate acid of H2O(a) i(b) ii (c) iii (d) iv (e) none3. Arrange the following according to increasing acid strength(i) Ka= 2.5 + 10-15(ii) Ka= 9.0 + 10-9(iii) pKa= 7.5(iv) % dissociation =100(a) iv, iii, ii, i2(b) ii, I, iii, iv(c) i, iii, iv, ii(d) i, ii, iii, iv(e) iii, iv, ii, i2
1. Ammonia is a colorless gas with a chemical formula of NH3, when it comes in contact with water, it will be transformed into Ammonium ion and it will produce one hydroxide ion, and this is why Ammonia will present a more basic (pH) behavior, the reaction that represents this behavior is:
NH3 + H2O -> NH4+ + OH-
Number 4 is the only one that represents it well
Number 3 has the same reaction but since there is a plus sign instead of an arrow, I consider it wrong.
which reagents can be used to convert an aldehyde to a carboxylic acid
To convert an aldehyde to a carboxylic acid, oxidation of the aldehyde functional group is required.
There are several reagents that can be used for this conversion:
1. Strong Oxidizing Agents:
- Potassium permanganate (KMnO4): In the presence of acidic conditions, KMnO4 can oxidize aldehydes to carboxylic acids.
- Chromic acid (H2CrO4): It is a strong oxidizing agent that can convert aldehydes to carboxylic acids.
2. Tollens' Reagent:
Tollens' reagent, also known as silver mirror reagent, is a solution of silver nitrate (AgNO3) and ammonia (NH3) in water. It can oxidize aldehydes to carboxylic acids under mild conditions. It produces a silver mirror on the inner surface of the reaction vessel.
3. Jones Reagent:
Jones reagent consists of a solution of chromium trioxide (CrO3) in diluted sulfuric acid (H2SO4). It is a strong oxidizing agent that can convert aldehydes to carboxylic acids.
These are some commonly used reagents to convert aldehydes to carboxylic acids through oxidation. The choice of reagent may depend on factors such as reaction conditions, desired selectivity, and other functional groups present in the molecule.
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The carbon nucleus has atomic number A =13. calculate the radius, mass and volume of the nucleus?
The radius, mass and volume of the nucleus are Radius ≈ 2.72 fm Mass ≈ 2.17 x 10^(-26) kg Volume ≈ 108.4 cubic femtometers (fm^3)
The atomic number (A) represents the number of protons in the nucleus of an atom. However, carbon usually has an atomic number of 6, not 13. Nonetheless, I'll provide calculations based on the given A = 13.
To calculate the radius of the nucleus, we can use the empirical formula:
Radius = r0 * A^(1/3)
Where r0 is a constant equal to approximately 1.2 femtometers (1.2 fm).
Radius = 1.2 fm * 13^(1/3)
Radius ≈ 2.72 fm
To calculate the mass of the nucleus, we need to consider the mass of individual protons and neutrons. The atomic number (A) represents the total number of protons and neutrons in the nucleus.
Mass = A * mass of one nucleon
The mass of one nucleon (proton or neutron) is approximately 1.67 x 10^(-27) kilograms.
Mass = 13 * (1.67 x 10^(-27) kg)
Mass ≈ 2.17 x 10^(-26) kg
To calculate the volume of the nucleus, we can use the formula for the volume of a sphere:
Volume = (4/3) * π * Radius^3
Volume = (4/3) * π * (2.72 fm)^3
Volume ≈ 108.4 cubic femtometers (fm^3)
Please note that the given value for the atomic number (A = 13) is unusual for carbon. Normally, carbon has an atomic number of 6.
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make a list of nature friendly development activities in your community
Answer:
Nature friendly activities include:
AfforestationBan on deforestationConservation of waterRecyclingReduce & ReuseUsing renewable energy.Hope it helps!
Two beakers each contain 200 mL of water. Into one beaker, a student adds 5.0 g NaI. Into the other, she adds 5.0 g of KI. What is the expected effect on the boiling points of the solutions?A) the NaI solution will have a higher boiling point than the KI solutionB) the KI solution will have a higher boiling point than the NaI solutionC) the boiling points of both solutions will be elevated to the same temperature, above 100 degrees CelsiusD) the boiling points of both solutions will remain at 100 degrees Celsius
Answer:
A) the NaI solution will have a higher boiling point than the KI solution
Explanation:
We must have it behind our minds that the addition of a solute to water elevates the boiling point of water.
Boiling point elevation is a colligative property. It depends on the amount of solute present.
We know that;
ΔTb = Kb m i
Where;
ΔTb = boiling point elevation
Kb = boiling point constant
m = molality
i = Van't Hoff factor
Since KI and NaI has the same number of particles(two particles each), the boiling point elevation (ΔTb) depends on the molality of each solution. The molality also depends on the molar mass of each substance. The molality of NaI is greater than the molality of KI hence the boiling point NaI is greater than the boiling point of KI.
So;
200mL of water = 200g of water
Mass of solvent = 200g/1000 = 0.2 Kg
Molality of NaI = 5g/150 g/mol * 1/0.2 = 0.167 m
molality of KI = 5g/166 * 1/0.2 = 0.151 m
Kb for water = 0.512 oC m-1
Boiling point of water = 100 oC
Let the boiling point of NaI be A
A - 100 = 0.512 * 0.167 * 2
A = (0.512 * 0.167 * 2) + 100
A = 100.171 oC
Let the boiling point of KI be B
B - 100 = 0.512 * 0.151 * 2
B = (0.512 * 0.151 * 2) + 100
B = 100.154 oC
Hence;
Boiling point of NaI > Boiling point of KI
PLEASE HELP
See the following diagram of methane (CH4).
Catalytics
§ Portal
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Спин
H
What is the composition of the sigma bonds in methane i.e. what atomic orbits comprise the molecular orbit? Hint: they are all the same, so there is only one kind sigma bond here.
The composition of the sigma bonds in methane i.e. the atomic orbits comprise the molecular orbit is σsp³-sp³
Explain molecular structure of methane briefly.Methane is a one-carbon compound in which carbon is attached to four hydrogen atoms by single bonds. It is colorless, odorless, non-toxic, but a flammable gas (bp -161°C). It serves as a fossil fuel, a member of greenhouse gases, and a bacterial metabolite. In the methane molecule, a carbon atom forms covalent bonds with four different hydrogen atoms. There are no lone pairs of electrons in carbon atoms. So the 4 hydrogen atoms are at the 4 corners of the tetrahedron and the carbon is at the center of the tetrahedron. Hybridization in the methane molecule occurs by mixing one orbital with three p-orbitals. Each orbital consists of an unpaired electron. Carbon's s orbital and three p orbitals overlap with her 1s orbital of hydrogen to form a bond. Therefore, methane hybridizes to sp3 resulting in tetrahedral geometry. The methane molecule is non-polar. In particular, the dipole moment of methane is zero. A dipole moment of zero means that the "center of negative charge" in the molecule corresponds to the "center of positive charge".
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2. convert 4.22 cL to mL
Answer:
1 cl =10 ml
so
4.22cL= 4.22×10= 42.2 mL
What is the phase of water at 1.0 atm and 50°C?
Water
(liquid)
Pressure (atm)
1 -
0.5
0.25-
Ice
(solid)
Water vapor
(gas)
0
Oy
Temperature (*C)
O A. Liquid and gas
O B. Liquid
O C. Solid
O D. Gas
there is a change from vapour to liquid
What is an orbital ? I need this ASAP :)
what is the second most abundant gas in the atmosphere
if a 348 g sample of water (Cp= 2.06 J/g°C) at 127 °C is cooled to 103 "C, find the change in enthalpy of the system
The change in enthalpy of the system -1.67 x \(10^4\) J
Given the data contains,
The mass of the sample is 348g.
The initial temperature is 127 \(^oc\).
The final temperature is 103 \(^oc\).
The change in temperature is calculated as,
ΔT = T2 - T1
ΔT = 103 - 127 = -24\(^oc\)
The change in temperature is -24\(^oc\).
The heat content of the system is calculated as,
q = mc ΔTq = 348 x 2.010 x (-24)
q = -1.67 x \(10^4\) J
What is temperature ?Temperature, a measure of hotness or coldness, expressed on one of several arbitrary scales, indicating the direction in which thermal energy spontaneously flows—that is, from a hotter body. Temperature does not correspond to the energy of a thermodynamic system; e.g. a burning match is at a much higher temperature than an iceberg, but the total thermal energy of an iceberg is much greater than the energy contained in a volcano.
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If an atmosphere consisting of an ideal gas were indeed homogeneous (constant density) all the way to the top at z = H, find the temperature at that top. Could such an atmosphere actually exist, even in principle? Why or why not?
The temperature at the top of an atmosphere consisting of an ideal gas with constant density can be found using the ideal gas law, which states that PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature.
Assuming the density of the gas is constant throughout the atmosphere, we can express the pressure as P = ρgh, where ρ is the density, g is the acceleration due to gravity, and h is the height.
Since the atmosphere is homogeneous, the pressure at the top (P_top) is the same as the pressure at the bottom (P_bottom), so we have P_top = P_bottom = ρgh.
Using the ideal gas law, we can write ρghV = nRT, where V is the volume of the gas.
Assuming the volume of the gas is constant, we can cancel out V, and rearranging the equation, we get T_top = (nRT_bottom)/(nR) = T_bottom.
Therefore, the temperature at the top of the atmosphere would be the same as the temperature at the bottom.
In practice, however, it is not possible for an atmosphere to have constant density all the way to the top. As we go higher in the atmosphere, the density decreases due to decreasing pressure and temperature. This is because gravity becomes weaker at higher altitudes. Therefore, in reality, the temperature would decrease as we move higher in the atmosphere.
So, while a homogeneous atmosphere with constant density all the way to the top cannot exist in practice, it can be considered as an idealized scenario for understanding certain aspects of atmospheric behavior.
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Calculate the energy released when 100.0 g of steam at 110.0 °c are converted into ice at minus 30.0 °c
The energy released when 100.0 g of steam at 110.0 °C are converted into ice at minus 30.0 °C is 1.56 × 10^6 J.
To calculate the energy released, we need to determine the amount of heat energy required to cool the steam to 0 °C, then the amount of heat energy required to freeze the water, and finally the amount of heat energy to cool the ice to -30 °C.
First, we calculate the amount of heat energy required to cool the steam from 110.0 °C to 0 °C using the formula Q = mcΔT, where Q is the heat energy, m is the mass, c is the specific heat capacity of steam and ΔT is the change in temperature. The specific heat capacity of steam is 2.01 J/g °C.
Q1 = (100.0 g) × (2.01 J/g °C) × (110.0 °C – 0 °C) = 22,242 J
Next, we calculate the amount of heat energy required to freeze the water at 0 °C using the formula Q = mL, where Q is the heat energy, m is the mass and L is the latent heat of fusion of water. The latent heat of fusion of water is 334 J/g.
Q2 = (100.0 g) × (334 J/g) = 33,400 J
Finally, we calculate the amount of heat energy required to cool the ice from 0 °C to -30 °C using the formula Q = mcΔT, where Q is the heat energy, m is the mass, c is the specific heat capacity of ice and ΔT is the change in temperature. The specific heat capacity of ice is 2.06 J/g °C.
Q3 = (100.0 g) × (2.06 J/g °C) × (0 °C – (-30.0) °C) = 6,180 J
The total energy released is the sum of the three values calculated above:
Qtotal = Q1 + Q2 + Q3 = 22,242 J + 33,400 J + 6,180 J = 61,822 J = 1.56 × 10^6 J.
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Physical, Chemical, or Therapeutic Incompatibility?:
Penicillin is stable for 24 hours in aqueous solution having a pH of 6.5. However, at pH 3.5, it is degraded in less than an hour.
Penicillin is stable for 24 hours in aqueous solution having a pH of 6.5
in this case is chemical Incompatibility given
Penicillin is a drug that is known to be pH sensitive. In this scenario, the stability of penicillin in an aqueous solution is dependent on the pH level of the solution. Penicillin is stable for 24 hours in an aqueous solution with a pH of 6.5, but at a pH of 3.5, it quickly degrades in less than an hour. This means that the chemical makeup of the penicillin is altered at a pH of 3.5, resulting in its degradation
The incompatibility of penicillin is due to its chemical sensitivity to pH. It is important to note that any medication that is pH sensitive must be stored and administered in a manner that ensures the pH level is within the acceptable range to maintain its stability and effectiveness.
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How many electrons are present in an atom in which the first and second shells and the 3s subshell are filled?.
Explanation:
Any orbital can hold a maximum of 2 electrons with opposite spin. The first shell has one 1s orbital and holds 2 electrons. The second shell holds 8 electrons; 2 in a 2s orbital and 6 in three 2p orbitals. The third shell holds 18 electrons; 2 in a 3s orbital; 6 in three 3p orbitals; and 10 in five 3d orbitals.
In an atom which contains all the shells up to 3s filled, there will be 12 electrons.
According to the Aufbau principle, the s sub-shell can contain 2 electrons and the p sub-shell can contain 6 electrons.
The atom in which the shells up to 3s are filled, must have 1s, 2s, 2p and 3s orbitals filled.
Therefore, the total number of electrons present in the atom = number of electrons present in 1s + number of electrons in 2s + number of electrons in 2p + number of electrons in 3s.
Total number of electrons in the atom = 2 (electrons from 1s) + 2 (electrons from 2s) + 6 (electrons from 2p) + 2 (electrons from 3s).
Total number of electrons in the atom = 12
So, an atom which has all the shells up to 3s sub-shells filled contains 12 electrons.
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Styrene has the empirical formula CH with a molar mass of 104. 13 g/mol. Approximately how many hydrogen atoms are present in a 52 g sample of styrene?
The Styrene has the empirical formula CH with a molar mass of 104. 13 g/mol. The number of hydrogen atoms are present in a 52 g sample of the styrene is 4.63 × 10²² H atoms.
The Empirical formula of styrene CH
The molecular formula = n(empirical formula)
n = 8
The Molecular formula of styrene = C₈H₈
1 mol of styrene has the 8 moles of the C and the 8 moles of H and the 1 mol .
The molecular mass = 104.13 grams.
104.14 g (1 mol of C₈H₈) have the 8 moles of H
Moles of 52 g = (52 × 8) / 104.13
= 3.99 moles
1 mole of particles= 6.02×10²³ atoms
The number of hydrogen atoms= 3.99 mol . 6.02×10²³ atoms / 1 mol
= 4.63 × 10²² H atoms.
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What is the change in freezing
point, ATf, when the 0.195 m
aqueous solution of K2S dissolves
into 3 particles?
-1.09'C is the change in freezing point
“Freezing point depression” depends on the solvent and the molar concentration of the solute.
Sulfide is highly basic, consequently
K2S
completely and irreversibly hydrolyzes in water according to the following equation:
K2S+H2O→KOH+KSH
What is freezing?Freezing, also known as solidification, is a phase transition where a liquid turns into a solid when its temperature is lowered below its freezing point.
the temperature at which a liquid solidifies specifically : the temperature at which the liquid and solid states of the substance are in equilibrium at atmospheric pressure : melting point the freezing point of water is 0° Celsius or 32° Fahrenheit.
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Answer:1.0881
Explanation:
If you observed a beam of particles being bent towards a negatively
charged plate, what might you conclude?
Answer:
The particles did not have a positive charge.
The half-life of a certain chemical in the human body for a healthy adult is approximately 3hr. a) What is the exponential decay rate? b) How long will it take 97% of the chemical consumed to leave the body? a) The decay rate of the chemical is %. (Round to one decimal place as needed.)
a) The exponential decay rate of the chemical is approximately 0.2310 per hour. The exponential decay rate can be determined using the formula:
decay rate (k) = ln(2) / half-life
Given that the half-life is approximately 3 hours, we can calculate the decay rate:
decay rate (k) = ln(2) / 3
decay rate (k) ≈ 0.2310 (rounded to four decimal places)
Therefore, the exponential decay rate of the chemical is approximately 0.2310 per hour.
b) To determine how long it will take for 97% of the chemical to leave the body, we can use the exponential decay formula:
amount remaining = initial amount × \(e^(-kt)\)
We want to find the time when the amount remaining is 97% of the initial amount. Thus, we can rewrite the equation as:
0.97 = \(e^(-kt)\)
Taking the natural logarithm (ln) of both sides:
ln(0.97) = -kt
Solving for t: t = -ln(0.97) / k
Substituting the previously calculated decay rate:
t ≈ -ln(0.97) / 0.2310
Using a calculator, we find:
t ≈ 10.152 (rounded to three decimal places)
Therefore, it will take approximately 10.152 hours for 97% of the chemical consumed to leave the body.
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Why do atronomer think the univere began with an exploion (the "Big
Bang Theory?"
Answer:
Explanation: The best-supported theory of our universe's origin centers on an event known as the big bang. This theory was born of the observation that other galaxies are moving away from our own at great speed in all directions as if they had all been propelled by an ancient explosive force.
What is the 3D shape of H3o+
3D view of H3O+
The stronger line means that the Hydrogen is closer to us in a 3D view, meanwhile the line with traces, or you cal also see as a weaker line, it means that the Hydrogen is farther from us in a 3D view
Lewis Structure of H3O+
If you need to produce 66 grams of carbon dioxide, how many liters of water vapor would you produce as a by product?
The question requires us to calculate the amount of vapor water produced as a by-product when 66g of carbon dioxide are obtained from the combustion of propane.
Considering the combustion of propane (C3H8), we have the following reaction:
\(2C_3H_8+9O_2\to4CO_2+2CO_{}+8H_2O_{(v)}\)IFrom the reaction, we can see that the stoichiometric relationship between C3H8 and water (H2O) is as follows:
2 mol C3H8 ---------- 8 mol H2O
Then, to calculate the amount of water produced as a by-product, we'll need to determine the amount of reactant needed to produce 66g of CO2.
Since the molar mass of CO2 is 44g/mol and considering the reaction written above, we can write:
2 mol C3H8 ---------- 4 mol CO2
x ---------- (66g/44g) = 1.5 mol CO2
Solving for x, we have that 0.75 mol of C3H8 are required to produce 66g of CO2.
Now, we calculate the amount of water that should be obtained from 0.75 mol of C3H8:
2 mol C3H8 ---------- 8 mol H2O
0.75 mol C3H8 ----- y
Solving for y, we have that 3 moles of water will be obtained as a by-product.
At last, we convert the calculated amount of vapor water into its volume considering the Standard Temperature and Pressure conditions (STP), where 1 mol of a gas corresponds to 22.4 L of the same gas:
1 mol vapor H2O ---------- 22.4 L vapor H2O
3 mol vapor H2O --------- z
Solving for z, we have that 67.2 L of vapor water will be obtained as a by-product when 66g of CO2 are produced from the combustion of propane.
As the world is increasing in population, the sound from traffic is a significant issue. The U. S. Department of Transportation recognizes that noise from highways is a large issue, particularly for those who live close to the highway. Engineers have come up with several solutions to the problem. One solution is noise barriers which can be dirt mounds between a highway and homes or high vertical walls. A second solution is planting vegetation such as trees. Select one of the two options and answer the following: 1. Identify the wave interaction involved in your chosen solution. (i. E. Refraction, reflection, diffraction) 2. Explain how the interaction would reduce noise for the homeowners. 3. Identify how the interaction would affect noise for the highway
A motorist will be able to hear the sound the least through a soundproof wall, hear it the most across a big empty space, and hear it the least through trees because they take longer to dampen a sound.
Does noise from the road rise?Sounds bends vertically upward during the day because the earth is hotter than that of the air above it.
Why are interstates so loud?Roadway sound is the total sound energy produced by moving cars.Road surface, tyre, engine/transmission, aerodynamic, and brake components make up the majority of it.
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At what volume of added NaOH solution would you expect to see an end point Answer in units of mL (full question is in photo :) )
endpointVinegar is also called as acetic acid, and we can write it in the following way CH3COOH. When we talk about titration, it refers to the amount of base needed to neutralize the acid. So there is a chemical reaction involved. The reaction between vinegar and NaOH base is as follows:
\(CH_3CO_{}OH+Na_{}OH\rightarrow CH_3CO_{}O_{}Na+H_2O\)We have a 1 to 1 ratio, i.e. to neutralize x moles of vinegar we need the same moles of NaOH. Let's calculate how many moles of acid are believed to be in the solution. We will use the molarity = 0.78M = 0.78 mol/L.
\(\begin{gathered} \text{Moles of vinegar = Volume}\times Molarity \\ \text{Moles of vinegar = }0.02061L\times0.78\frac{mol}{L} \\ \text{Moles of vinegar = }0.016\text{mol} \end{gathered}\)Then we need 0.016 moles of NaOH, the volume required will be:
\(\begin{gathered} \text{Volume of NAOH=0.016 mol}\times\frac{1L}{0.933\text{mol}}\times\frac{1000mL}{1L} \\ \text{Volume of NAOH=}17.23mL \end{gathered}\)So, the volume that would be needed of NaOH to see an end point is 17.23 mL
Explain the difference between current electricity and magnetism.
Answer:
Electricity can be present in a static charge, while magnetism's presence is only felt when there are moving charges as a result of electricity. In simple words, electricity can exist without magnetism, but magnetism cannot exist without electricity.
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Explanation:
Check the rate of evaporation in a wide mouthed container and narrow mouthed container. Note your observation during the peak of summer & the start of monsoon.
Answer:
Because of the summer season
Explanation:
The water in the dish which is uncovered will evaporate faster as compared to the one which is
covered. This is because the air above the uncovered dish has less water vapour over it as
compared to the one which is covered. The covered dish has good amount of moisture over it as
the closed lid does not allow the moisture to come in direct contact with air.