A honeybee leaves the hive, flies in a straight line to a flower 6 km away in 15 min, and then takes 15 minutes to return (also in a straight line). a.) Please find the distance travelled and displacement for the entire trip: distance travelled: 1 12 km displacement: 2 0 km b.) Please find the average speed and average velocity for the entire trip: average speed: 3 0.4 km/min average velocity: 4 0.4 km/min c.) If the bee had not flown in a straight line-- but instead with an unknown motion-- to the flower and back, which could not be determined: the average speed or average velocity

The force required to rescue in the swimming pool with a mass of 60 kg is 588N and the pressure exerted in the area of 0.5 m² is 1.176×10³Pa.

Force is defined as the push or pull of an object. Force equals the product of the mass and acceleration of the object. Acceleration is defined as the rate of change of velocity per unit time. The force also equals the rate of change of momentum per unit of time. The unit of force is Newton (N).

Pressure is defined as the force applied perpendicular to the surface area. It equals the ratio of force per unit area and the unit of pressure is Pascal (Pa).

From the given,

mass of the swimmer's body (m) = 60 kg

Acceleration. due to gravity (g) = 9.8m/s²

area (A) = 0.5 m²

Force, F = m×a

F = 60×9.8

  = 588 N

The force to rescue the swimmer's body is 588N.

Pressure  = Force/Area

               = 588 / 0.5

               = 1176 Pa

               = 1.176×10³Pa

The pressure exerted on the body is 1.176×10³Pa.

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Answer:

2.5 seconds

Explanation:

Time is equal to distance over speed

300 divide by 120 u get 2.5 seconds

277.01 picometers is equivalent to 2.7701 × 10-⁸ centimetres in scientific notation. Details about how to convert picometers to centimetres can be found below.

Picometers is the SI unit of length that is equal to 10−¹² meters.

On the other hand, centimetres is another S.I unit of length that is equal to 10-² metres.

The conversion factor of picometers to centimetres is as follows:

1 picometre = 1 × 10-¹⁰ centimetres

277.01 picometers is equivalent to 2.7701 × 10-⁸ centimetres

Therefore, 277.01 picometers is equivalent to 2.7701 × 10-⁸ centimetres in scientific notation.

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The correct use of subordinate conjunction is  "As soon as the gun hit the floor, it discharged." The correct option is B.

A subordinate conjunction is a type of conjunction that connects two clauses in a sentence, making one clause dependent on the other. It establishes a relationship of dependence or subordination between the clauses.

Option A (The gun hit the floor, so it discharged) implies a cause-and-effect relationship, which may not be accurate in this case. The gun hitting the floor does not necessarily mean it will discharge.

Option C (The gun hit the floor, and it discharged) presents the two actions as separate events that happened sequentially but does not establish a clear cause-and-effect relationship between them.

Therefore, Option B (As soon as the gun hit the floor, it discharged) effectively connects the two events with a subordinate conjunction "as soon as," indicating that the discharge immediately followed the gun hitting the floor. This option provides a logical and temporal connection between the two actions.

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Answer:

i ≅ \(28^{0}\)

Explanation:

Let the angle of incidence be represented by i, angle of emergence be represented by e, and angle of refraction by r.

Snell's law states that;

n = \(\frac{sin i}{sin r}\) ................ 1

where n is the refractive index of the prism.

Given that emergence = \(90^{0}\)

But from a ray diagram for the given question, we have;

\(60^{0}\) + (\(90^{0}\) - r) + (\(90^{0}\) - \(r^{I}\)) = \(180^{0}\) (sum of angles in a triangle) .................. 2

(\(90^{0}\) - r ) + (\(90^{0}\) - \(r^{I}\) ) =  \(180^{0}\) - \(60^{0}\)

180° - (r + \(r^{I}\)) =  \(180^{0}\) - \(60^{0}\)

r + \(r^{I}\)  = \(60^{0}\)

⇒  r = \(60^{0}\) - \(r^{I}\)  ........................ 3

The refractive index of the equilateral prism = 1.5.

Applying Snell's law to the refracting surface,

 \(\frac{sinr^{I} }{sin e}\) = \(\frac{1}{n}\)

\(\frac{sinr^{I} }{sin 90^{0} }\) = \(\frac{1}{1.5}\)

⇒   \(r^{I}\)  = \(41.81^{0}\)

From equation 3,

r = \(60^{0}\) - \(r^{I}\)

r = \(60^{0}\) - \(41.81^{0}\)

r = \(18.19^{0}\)

So that ;

n = \(\frac{sin i}{sin r}\)

1.5 = \(\frac{sin i}{sin18.19^{0} }\)

sin i = 0.4683

i = \(27.92^{0}\) ≅ \(28^{0}\)

A state of character arises from the repetition of similar activities

Aristotle was a renowned scientist and philosopher. He has made significant contributions to society. He is renowned for his quotable sayings as well. Because of the correlation between the states of character and the distinctions between them, the behaviors we display must be of a specific type. States of character: The traits that "allow us to stand well or poorly in relation to the passions." Because: We are not commended and criticized only for having the ability to feel pleasure, grief, etc., virtues are not capacities.

Here in this quote, similar behaviors give birth to similar states of character

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The time required for half of the oil droplets to coalesce is 34.65 minutes.b) Calculation to find how long it takes for practically all of the oil droplets to coalesce:To find the time it would take for practically all of the oil droplets to coalesce, we need to use the following formula and solve for time when n is equal to 0.0 = e^(-0.02t)-infinity = -0.02tNo oil droplets remain after an infinite amount of time. Therefore, it takes an infinite amount of time for all the oil droplets to coalesce.Answer: It takes an infinite amount of time for all the oil droplets to coalesce.

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Since no work is done, the power exerted is zero. Therefore, the man exerts no power on the wall.

In physics, force is defined as any action that can change the motion of an object or cause an object to accelerate. Force is a vector quantity, meaning that it has both magnitude (size or strength) and direction. The unit of force in the International System of Units (SI) is the Newton (N), which is defined as the amount of force required to accelerate a mass of one kilogram at a rate of one meter per second squared (1 N = 1 kg × 1 m/s^2). Force can be measured using a variety of instruments, such as spring scales, strain gauges, or force plates. Some common types of forces include gravitational force, electromagnetic force, frictional force, and normal force. The study of forces and their effects on the motion of objects is known as mechanics and is a fundamental concept in physics.

Here,

a. The man does not do any work on the wall because the wall does not move. Work is only done when there is a displacement in the direction of the force applied.

b. Since no work is done, no energy is used or transferred.

c. The power exerted by the man can be calculated using the formula:

Power = Work / Time

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The  best description on  the weather conditions at location  A and B is  :It is warmer at position A than at position B.

Therefore Option (D) is correct

Weather condition is  described as  the regional weather during a defined time period from one up to several weeks describing typical weather phenomena, such as a series of thunderstorm in hot summer, foggy month in autumn or other weather conditions which are typical for a specific region and/or season.

From the given image, a warm front is being shown. Here, the region comprising letter A is the warm zone and the region above the front comprising the letter B indicates a cold zone. The position A forms a low-pressure zone, so it is comparatively warmer than the position B.

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#complete question:

Which of the following statements best describes the weather conditions at positions A and B shown below?

A. It is raining at position A and clear at position B.

B. It is cloudy at position A and clear at position B.

C. It is cooler at position A than at position B.

D. It is warmer at position A than at position B.

Answer:

mass and distance

Explanation:

mass, and distance. The force of gravity depends directly upon the masses of the two objects, and inversely on the square of the distance between them.

Answer:

\(thank \: you\)

Question:-

Convert 4cm to m

Solution:-

Lets do

First note down the below formula

\(\boxed{\sf 1m=10^{2}cm}\)

Then

\(\boxed{\sf 1cm=10^{-2}cm}\)

Now we are given 4cm

So convert

\(\\ \sf\longmapsto 4\times 10^{-2}m\)

If we simplify to decimal

\(\\ \sf\longmapsto 4cm=0.04m\)

Hence done .

Answer:

When the rock is dropped from a height of 9.0 m, its initial potential energy is given by

PE = mgh = (6.0 kg)(9.8 m/s^2)(9.0 m) = 534 J

We can solve for the height at which the kinetic energy of the rock is twice its potential energy by setting the kinetic energy equal to twice the potential energy and solving for h.

KE = 1/2 mv^2 = (1/2)(6.0 kg)(v^2)

2 * PE = 2 * (6.0 kg)(9.8 m/s^2)(h)

Substituting and solving for h yields

h = 15 m

Answer:

Explanation:

       Kirchhoff's Current Law, often shortened to KCL, states that “The algebraic sum of all currents entering and exiting a node must equal zero.

           #I AM ILLITERATE

The frequency at which the capacitive reactance is 375 ω and the Capacitance of 3.25 μF is 131 s⁻¹.

Capacitance is the ability or capacity of the substance to collect and store electrical energy and the unit of capacitance is Farad (F). Capacitive reactance is the term that measures the opposition to current flow in the AC circuits and the unit of capacitive reactance is the ohm(Ω).

From the given,

The capacitive reactance (Xc) = 375ω

capacitance (C) = 3.25μF

capacitive reactance Xc = 1/(2π×f×C)

Frequency (f) = 1/(2π×Xc×C)

                     = 1/(2×3.14×375×3.25×10⁻⁶)

                     = 131 s⁻¹.

Thus, the frequency of the capacitive reactance is 131 s⁻¹.

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Answer:

Soaps and detergents are made from long molecules that contain a head and tail the detergent molecules also help to make the washing process more effective by reducing the surface tension of the water. Surface tension is the force which helps a blob of water on a surface hold its shape and not spread out.

Answer:

Soaps and detergents are made from long molecules that contain a head and tail. ... The detergent molecules also help to make the washing process more effective by reducing the surface tension of the water. Surface tension is the force which helps a blob of water on a surface hold its shape and not spread out.

Explanation:

hello

The final velocity of the Maserati after accelerating at the rate of 85 m/s² for 5 seconds is 431m/s.

From the first equation of equation of motion, final velocity is the sum of the initial velocity and the product of acceleration and time.

It is expressed as;

v = u + at

Where v is final velocity, u is initial velocity, a is acceleration and t is time elapsed.

Given the data in the question;

Plug the given values into the first equation of motion and solve for v.

v = u + at

v = 6m/s + ( 85m/s² × 5s )

v = 6m/s + 425ms/s²

v = 6m/s + 425m/s

v = 431m/s

The final velocity of the Maserati after accelerating at the rate of 85 m/s² for 5 seconds is 431m/s.

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Answer:

Explanation:

His Kinetic energy = 1/2 m v^2

v = 5 m/s

m = 75 kg

Ke = 1/2 75 * 5^2

Ke = 937.5 Joules

This will be converted to PE when he reaches the maximum height he reaches. In other words KE = PE

PE = m * g * h

m = 75

g = 9.81

h = ?

PE = 937.5

937.5 = 75 * 9.81 * h

937.5 = 735.75 * h

937.5/735.75 = h

h= 1.27 meters

The dynamic viscosity of oxygen at 40°C and 160 kPa is 64.17 × 10⁻⁶ Pa.s.

The dynamic viscosity of a fluid is equal to its kinematic viscosity multiplied by its density.

Given:

Kinematic viscosity of oxygen at 40°C and 160 kPa = 0.104 stokes

Density of oxygen at 40°C and 160 kPa = (160000 Pa / 0.2598 kPa.m³) = 616.55 kg/m³ (using ideal gas law)

Using the formula:

Dynamic viscosity = Kinematic viscosity * Density

We get:

Dynamic viscosity of oxygen = 0.104 stokes * 616.55 kg/m³ = 64.17 × 10⁻⁶ Pa.s

Therefore, the dynamic viscosity of the oxygen at 40°C and 160 kPa is 64.17 × 10⁻⁶ Pa.s.

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Answer:

C6H12O6 is the final product of Calvin cycle light independent reactions

Explanation:

* steps in Calvin cycle

: carbon fixation

: reduction

: regeneration

for C6H12O6 it requires 2 molecules of PGAL or G3P

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Answer:

The acceleration at the moment the train speed reaches 52 kilometers per hour is approximately 1.826 meters per square second.

Explanation:

According to Rotational Physics, the total acceleration of the train rounding the horizontal turn is a combination of tangential (\(a_{t}\)) and radial accelerations (\(a_{r}\)), measured in meters per square second. The former one represents the change in the magnitude of the velocity, whereas the latter one represents the change in its direction. By definition of magnitude and Pythagorean Theorem we get that magnitude of total acceleration (\(a\)), measured in meters per square second, is:

\(a = \sqrt{a_{r}^{2}+a_{t}^{2}}\) (Eq. 1)

Magnitudes of tangential and radial accelerations are determined by using the following formulas:

\(a_{t} = \frac{v_{f}-v_{o}}{t}\) (Eq. 1)

\(a_{r} = \frac{v_{f}^{2}}{R}\) (Eq. 2)

Where:

\(v_{o}\), \(v_{f}\) - Initial and final speeds, measured in meters per second.

\(t\) - Time, measured in seconds.

\(R\) - Radius, measured in meters.

If we know that \(v_{o} = 24.444\,\frac{m}{s}\), \(v_{f} = 14.444\,\frac{m}{s}\), \(t = 18\,s\) and \(R = 120\,m\), then the magnitude of the total acceleration when the train speed reaches 52 kilometers per hour is:

\(a_{t} = \frac{14.444\,\frac{m}{s}-24.444\,\frac{m}{s} }{18\,s}\)

\(a_{t} = -0.556\,\frac{m}{s^{2}}\)

\(a_{r} = \frac{\left(14.444\,\frac{m}{s} \right)^{2}}{120\,m}\)

\(a_{r} = 1.739\,\frac{m}{s^{2}}\)

\(a = \sqrt{\left(-0.556\,\frac{m}{s^{2}} \right)^{2}+\left(1.739\,\frac{m}{s^{2}} \right)^{2}}\)

\(a \approx 1.826\,\frac{m}{s^{2}}\)

The acceleration at the moment the train speed reaches 52 kilometers per hour is approximately 1.826 meters per square second.

Answer:

ω = θ / t

1 rev = 2 pi rad

t = 60 sec / min * 60 min / hr = 3600 sec / hr

v = ω R         tangential speed

v = (2 pi m / hr) / (3600 sec / hr) = .00175 m/sec

As a check

s = 2 pi * 1 m = 6.28 meters around dial

It takes 3600 sec for 1 rotation of the minute hand

v = 6.28 / 3600 = .0017 m/s

The frictional force of an object is the product of the normal force and coefficient of kinetic friction. Here the frictional force acting on the object  is 16.4 N.

Frictional force is a kind of force acting on a body to resist it from motion. Thus, the direction of the force will be in negative with the magnitude. Frictional force is the product of coefficient of friction and the normal force.

The normal  force acting on the object of mass 4.2 Kg is N = mg

N = 4.2 Kg × 9.8 m/s² = 41.16 N

Frictional force = ц N

                         = 0.40 × 41.16 N

                         = 16.4 N.

Therefore, the frictional force acting between the surface of the object and the floor is 16.4 N

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Your question is incomplete. But your complete question probably was:

The coefficient of kinetic friction between an object and the surface upon which it is sliding is 0.40 the weight of the object is 4.2 kg. What is the frictional force of the object?

Answer:

Explanation:

The torque is given by the formula:

τ = F × r × sin(θ)

where τ is the torque, F is the force applied, r is the distance between the force and the pivot point, and θ is the angle between the force and the lever arm.

In this case, the person's weight is the force being applied, and it can be calculated as:

F = m × g

where m is the mass of the person and g is the acceleration due to gravity (9.81 m/s^2).

F = 65 kg × 9.81 m/s^2 = 637.65 N

The distance between the person and the pivot point is 1.5 m, so r = 1.5 m.

The angle between the person's weight and the lever arm is 90 degrees, so sin(θ) = 1.

Therefore, the torque the person is exerting on the board is:

τ = F × r × sin(θ) = 637.65 N × 1.5 m × 1 = 956.475 N·m

So the person is exerting a torque of 956.475 N·m on the diving board with respect to the pivot point.

Answer:

Explanation:

Use the equation

\(h(t)=-16t^2+v_0t+h_0\)

where h(t) is the height after a certain amount of time goes by, v0t is the initial upwards velocity, and h0 is the initial height of the projectile. For us:

h(t) = 10

v0t = 80

h0 = 3 and filling in:

\(10=-16t^2+80t+3\) and get everything on one side to factor:

\(0=-16t^2+80t-7\)

This factors to

t = .09 sec and 4.9 sec. Let's interpret this.

The time of .09 is when the ball reached 10 feet on the way up, and

the time of 4.9 is when the ball reached 10 feet on the way back down. That's the height we need, 4.9 seconds.

Answer:

8mph

Explanation:

speed=mph.

half an hourx2.

4 milesx2.

8 miles per hour.

That is the speed.

Hope this helps :D

Answer:

is this it?

Explanation:

λ = h/mv, where λ is wavelength, h is Planck's constant, m is the mass of a particle, moving at a velocity v. de Broglie suggested that particles can exhibit properties of waves.

Answer: the answer is D if its not i'm really sorry

The complete expression for the magnitude of the electric field generated by the minute plastic segment is: |dE| = 1/(4πε₀) * ρ * dr / \(r^2\)

The magnitude of the electric field generated by a point charge q at a distance r from the charge is given by Coulomb's law:

E = k*q/\(r^2\)

where k is the Coulomb constant.

For a small segment of charge dq, we can consider it as a point charge located at its center, which is at a distance r from the point where we want to calculate the electric field. The length of the segment is dr, and its charge density is ρ = dq/dr. Therefore, the charge q of the segment is given by:

q = ρ * dr

Substituting this expression for q into Coulomb's law, we get:

dE = k*(ρ*dr)/\(r^2\)

Simplifying this expression, we obtain the magnitude of the electric field generated by the minute plastic segment:

|dE| = kρdr/\(r^2\)

where |dE| denotes the magnitude of the electric field, ρ is the charge density of the segment, dr is the length of the segment, r is the distance from the segment to the point where we want to calculate the electric field, and k is the Coulomb constant:

k = 1/(4πε₀)

where ε₀ is the electric constant, also known as the permittivity of free space.  |dE| = 1/(4πε₀) * ρ * dr / \(r^2\)

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