A homogenous rod of length 5 m and a mass of 60 kg is kept in lever. Calculate the effort required to balance lever.
​

The total side to side distance at the top of the building, covered during such an oscillation is 8.4 cm.

Solution:

The height of building is, h = 152 m.

The frequency on windy days is, f = 0.17 Hz.

The acceleration on the top of building is, a = 2/100g (Here g is gravitational acceleration).

\(a = A \times \omega ^{2}\)

\(a = A \times (2\pi f) ^{2}\)

\(\frac{2}{100} \times g = A \times (2\pi \times 0.17) ^ 2\)

A = 0.042m

hence the total distance is twice the distance

that is 0.084m

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Question:

The New England Merchants Bank Building in Boston is 152 m high. On windy days it sways with a frequency of 0.17 Hz, and the acceleration of the top of the building can reach 2.0% of the free-fall acceleration, enough to cause discomfort for occupants. What is the total distance, side to side, that the top of the building moves during such an oscillation?

Answer:

How many ampere in 1 milliampere? The answer is 0.001.

We assume you are converting between ampere and milliampere.

You can view more details on each measurement unit:

ampere or milliampere

The SI base unit for electric current is the ampere.

1 ampere is equal to 1 ampere, or 1000 milliampere.

Note that rounding errors may occur, so always check the results.

Use this page to learn how to convert between amperes and milliamperes.

Type in your own numbers in the form to convert the units

Explanation:

Hope this helped :)

Answer: I believe it’s location D. Or whichever is the location of slow crystallization.

Explanation: Slow crystallization of magma forms granite. Hope this helps. :)

Answer:

D

Explanation:

The correct answer is option B. It travels up and down. Transverse waves are characterized by the fact that they cause particles in the medium to move perpendicular to the direction of wave propagation.

Transverse waves are a type of wave that causes the particles of the medium to move up and down or side to side as the wave passes through them.

The other options are not right because:

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Area must the plates have is 1.26 x 10^-16 m^2

Given:

The capacitance of the parallel plate capacitor:

= 0.40F

The separation between the plates = 2.8-mm

To Find:

area of plates

Solution:

The capacitance of the parallel plate capacitor can be expressed as:

C = ε0*A/d

A = Cd/ε0

A = 0.40 x 0.0028/8.85*10^-12

A = 1.26 x 10^-16 m^2

Hence, area must the plates have is 1.26 x 10^-16 m^2

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Answer

A) Time to reach zenith

t

=

2.2

2

=

1.1

s

v

=

u

+

a

t

∴

0

=

u

−

9.8

×

1.1

u

=

10.78

m/s

Explanation:

It would take 6416.8 kJ of heat to vaporize 1.22 kg of helium at its boiling point.

Helium is a chemical element with the symbol He and atomic number 2.

The amount of heat needed to vaporize a substance can be calculated using the formula:

Q = m * ΔHv

Where

For helium, the heat of vaporization is 21.1 kJ/mol at its boiling point of -268.9°C. The molar mass of helium is 4.003 g/mol.

To calculate the amount of heat needed to vaporize 1.22 kg of helium, we first need to convert the mass to moles:

1.22 kg He * (1000 g / 1 kg) * (1 mol / 4.003 g) = 304.4 mol He

Then, we can use the formula to calculate the amount of heat needed:

Q = m * ΔHv = 304.4 mol * 21.1 kJ/mol = 6416.8 kJ

Therefore, it would take 6416.8 kJ of heat to vaporize 1.22 kg of helium at its boiling point.

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The abstract for a science project regarding the frequency of guitar strings is given below

This science project  is one that seeks to explores the relationship between the length of a guitar string and the wavelength of the elemental tone it produces when culled.

The recurrence of a guitar string is seen as part on its length, pressure, and mass. This extend tells that shorter strings will create a on a very basic level higher tone.

Hence An electronic tuner was said to be utilized to record the recurrence of each note played. The comes about appeared that the elemental tone delivered by each string was higher when the string got to be shorter and more slender.

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The question is incomplete, the complete question is;

A car can go from 0 to 60 mph in 7.0 s. Assuming that it could maintain the same acceleration at higher speeds, how long would it take the car to go from 0 to 120 mph? A. 10 s B. 14 s C. 21 s D. 28 s

Answer:

B

Explanation:

We have;

vo = 0 m/s

v1 = 60 mph or 26.8 m/s

v2 = 120 mph or 53.6 m/s

t1 = 7s

To obtain a

v1 = vo + at1

but vo = 0 m/s

a = v1/t1 = 26.8 m/s/7s = 3.8 ms-2

To obtain t2 for the car;

v2 = vo + at2

but vo = 0 m/s

t2= v2/a = 53.6m/s/3.8ms-2

t2 = 14.1 s

Answer:

Hey dear

U are a Nice photographer

The pic I awesome.

wow that looks really cool! 9/10

The correct option is A. The source of information could be biased.

The scientist's conclusion is most likely unreliable because the sample used for the investigation is not representative or diverse enough to draw a generalized conclusion about the beliefs of the entire population.

Interviewing only 50 people who work in the local oil mine introduces a potential bias, as those individuals may have a vested interest in downplaying the impact of the mine on bird population decline.

Additionally, the sample size is relatively small, which reduces the statistical reliability of the conclusion.

To obtain a more accurate and reliable conclusion, a larger and more diverse sample should be used, including individuals from various backgrounds and perspectives, along with other data collection methods such as field surveys or scientific studies.

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Answer:

Explanation:

Given:

m₁

m₂

R₁

F₁ = 16 units

m₁' = 2·m₁

m₂' = 2·m₂

R₂ = 2·R₁

_________

F₂ - ?

The force of gravity:

F₁ = G·m₁·m₂ / (R₁)²

F₂ = G·m₁'·m₂' / (R₂)² = G·(2·m₁)·(2·m₂) / (2·R₁)² =

= 4·m₁·m₂ / (4·R₁²) = m₁·m₂ / (R₁)² = F₁

F₂ = F₁ = 16 units

The sound wave moved at a speed of about 170.59 m/s.

Echoes. An echo is a sound that is reproduced when sound waves are reflected back. Sound waves can also reflect off smooth, hard surfaces, much to way a rubber ball does. The echo sounds the same as the original sound, despite the fact that the sound's direction changes.

Time for sound to reach the mountain and bounce back = 2 x 1.7 s = 3.4 s

The distance traveled by the sound wave is twice the distance between the hiker and the mountain, so:

Distance = (580 m x 2 x 290 m)

Using the formula:

Speed = Distance / Time

we get:

Speed = 580 m / 3.4 s = 170.59 m/s

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Answer:

58.24 Km/h.

Explanation:

From the question given above, the following data were obtained:

Distance (d) = 495 Km

Time (t) = 8 h 30 mins

Speed (S) =?

Next, we shall express 8 hours 30 mins to hours.

We'll begin by convert 30 mins to hour.

60 mins = 1 h

Therefore,

30 mins = 30 mins × 1 h/ 60 mins

30 mins = 0.5 hour.

Thus,

8 h 30 min = 8 + 0.5 = 8.5 hours

Speed is define as the distance travelled per unit time. Mathematically, it is expressed as:

Speed = Distance /time

With the above formula, we can obtain the speed as shown below:

Distance (d) = 495 Km

Time (t) = 8.5 hour

Speed (S) =?

Speed = Distance /time

Speed = 495 Km / 8.5 hour

Speed = 58.24 Km/h

Thus, the speed is 58.24 Km/h.

Answer:

The answer is temperature

a. To arrive at the same point after driving 7.5 km in a direction east of north, you would need to drive approximately 6.11 km straight east and approximately 3.75 km straight north.

b. Reversing the order of the east and north legs will still bring you to the same point.

a. To find the distances you would have to drive straight east and then straight north to arrive at the same point, you can use trigonometry. Let's assume the angle between the direction east and the line connecting the starting point and the destination point is θ.

Using trigonometric ratios, we can determine the distances:

The distance traveled in the east direction (dₑ) can be found using the cosine function:

cos(θ) = dₑ / 7.5 km

Solving for dₑ, we have:

dₑ = 7.5 km * cos(θ)

Similarly, the distance traveled in the north direction (dₙ) can be found using the sine function:

sin(θ) = dₙ / 7.5 km

Solving for dₙ, we have:

dₙ = 7.5 km * sin(θ)

These equations give us the distances you would have to drive straight east and straight north to arrive at the same point.

b. To show that reversing the order of the east and north legs still brings you to the same point, we can consider the vector addition of the displacements.

When driving east first and then north, the total displacement is the vector sum of the east displacement (dₑ) and the north displacement (dₙ). Let's denote the total displacement as D₁.

D₁ = dₑ + dₙ

On the other hand, when driving north first and then east, the total displacement is the vector sum of the north displacement (dₙ) and the east displacement (dₑ). Let's denote this total displacement as D₂.

D₂ = dₙ + dₑ

Since vector addition is commutative, meaning the order of adding vectors does not affect the result, we have:

D₁ = D₂

Therefore, reversing the order of the east and north legs still brings you to the same point.

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Answer:

highest at top

f=b

e=a=d

c

Explanation:

The charge on the bead is approximately 2.16 x 10^(-7) coulombs.

To determine the charge on the bead, we can use the equation that relates the force experienced by a charged particle in an electric field to its mass and acceleration.

The force experienced by the bead can be calculated using Newton's second law of motion, which states that the force (F) acting on an object is equal to its mass (m) multiplied by its acceleration (a):

F = m × a

In this case, the mass of the bead is given as 3.6 g, which is equivalent to 0.0036 kg, and the acceleration is 12 m/s². Therefore, the force acting on the bead is:

F = 0.0036 kg × 12 m/s²

F = 0.0432 N

The force acting on a charged particle in an electric field can be expressed using the equation:

F = q × E

Where q represents the charge on the particle and E is the electric field strength. In this case, the electric field E⃗ = (200,000 N/C, up).

Since the electric field is directed upward, and the force experienced by the bead is also upward, we can conclude that the charge on the bead must be positive. Let's assume the charge is q coulombs.

Using the equation for force in terms of charge and electric field, we can rearrange it to solve for the charge q:

q = F / E

Substituting the values:

q = 0.0432 N / 200,000 N/C

q = 2.16 x 10^(-7) C

Therefore, the charge on the bead is approximately 2.16 x 10^(-7) coulombs.

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By applying Newton's second law of motion, the reading on this bathroom scale is equal to 2,058 Newton.

Mathematically, Newton's Second Law of Motion is given by this expression;

F = ma = mg

Where:

In this scenario, the downward force that is being experienced by this astronaut is equal to his or her weight:

Weight = mg = 70g Newton.

Note: The upward force that is being exerted by the bathroom scale on this astronaut is the net force (F) and acceleration due to gravity is equal to 9.8 m/s².

By applying Newton's second law of motion, the reading on this bathroom scale is given by:

Net force, F = 70g

Net force, F = 70(3g)

Net force, F = 70 × 3 × 9.8

Net force, F = 2,058 Newton.

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Answer: 25 m/s

Explanation:

1. rearrange equation p = mv to find v

2. v = p/m - then convert 800 g into kg (= 0.8 kg)

3. plug in p and m - v = 20 / 0.8 = 25 m/s

Answer:

V= 25m/s

Explanation:

Mass=800g

Momentum=20kgm/s

V= ?

Convert 800g to kg

800/1000 = 0.8kg

Momentum=mass× Velocity

Momentum/Mass = Velocity

20/0.8 =25m/s

Answer:

40

Explanation:

because his increasing speed

The distance on the screen from the unscattered slit image to the first-order violet line is 0.00514 cm.

What is Transmission?

In physics, transmission refers to the passage of waves, particles, or energy through a medium or barrier, without any change in the shape or form of the wave. This can occur in various contexts, such as the transmission of electromagnetic waves (such as light) through a material, the transmission of sound waves through the air, or the transmission of particles (such as electrons or ions) through a solid-state material.

The distance d between the central bright fringe and the first-order bright fringe for a transmission diffraction grating is given by:

dλ = mD

where λ is the wavelength of light, m is the order of the bright fringe, D is the distance between the grating and the screen, and d is the distance between adjacent slits on the grating.

For a hydrogen spectrum, the wavelengths of the first three visible (first-order) lines are:

λ_1 = 656.3 nm (red line)

λ_2 = 486.1 nm (blue-green line)

λ_3 = 434.0 nm (violet line)

The distance between adjacent slits on the grating is:

d = 1/325 mm = 0.00308 cm

The distance between the grating and the screen is D = 2.6 m = 260 cm.

For the first-order red line (m = 1, λ = 656.3 nm), we have:

dλ = mD

0.00308 cm * 656.3 nm = 1 * 260 cm * x

Solving for x, we get:

x = (0.00308 cm * 656.3 nm) / 260 cm = 0.00776 cm

So, the distance on the screen from the unscattered slit image to the first-order red line is 0.00776 cm.

For the first-order blue-green line (m = 1, λ = 486.1 nm), we have:

dλ = mD

0.00308 cm * 486.1 nm = 1 * 260 cm * x

Solving for x, we get:

x = (0.00308 cm * 486.1 nm) / 260 cm = 0.00579 cm

So, the distance on the screen from the unscattered slit image to the first-order blue-green line is 0.00579 cm.

For the first-order violet line (m = 1, λ = 434.0 nm), we have:

dλ = mD

0.00308 cm * 434.0 nm = 1 * 260 cm * x

Solving for x, we get:

x = (0.00308 cm * 434.0 nm) / 260 cm = 0.00514 cm

So, the distance on the screen from the unscattered slit image to the first-order violet line is 0.00514 cm.

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Answer:

A) the initial point all energy is elastic potential and the final point all energy is kinetic

B) a bar graph the two bars have the same height and the sum of their height is the initial energy

C) two bars, one for the  kinetic energy and the other for the gravitational potential energy.

Explanation:

A) For this exercise we must use the energy conservation relations

starting point. When the spring is compressed

        Em₀ = K_e = ½ k x²

end point, at the bottom of the loop

        Em_f = K = ½ m v²

energy is conserved

        Em₀ = Em_f

         ½ k x² = ½ m v²

         v = \(\sqrt{ \frac{k}{m} }\)   x

In a bar graph the initial point all energy is elastic potential and the final point all energy is kinetic

B) intermediate point in a quarter of the radius

In this case we use the lower part of the loop as the starting point and the quarter part of the bow as the end point.

        Em₀ = K

         Em_f = K + U = ½ m v² + m g R

in a bar graph the two bars have the same height and the sum of their height is the initial energy

C) End point highest part of the loop

   starting point, bottom of loop

         Emo = K = ½ m v₀²

from part A of the exercise we saw that it is equal to the elastic energy of the spring

    final point. Highest part of the loop

         Emf = K + U

         Em_f = ½ m \(v_{f}^2\) + mg (2R)

where R is the radius of the loop

         Em₀ = Em_f

        1/2 m v₀² = 1/2 m v_{f}^2+ mg 2R

        v₀² = v_f^2 + 4gR

In a bar graph there are two bars, one for the  kinetic energy and the other for the gravitational potential energy. The sum of the heights of these bars is the initial energy, so the energy is transformed but not created or destroyed in the process.

The spring compresses if it is an elevator accelerating upwards at 3g is Option A. a)16x

Acceleration is the rate of change of the velocity of an item with appreciation to time. Accelerations are vector portions. The orientation of an item's acceleration is given by the orientation of the net pressure appearing on that object.

Calculation:-

Gravitational acceleration = g

Spring constant of the spring = k

Mass of the first block = m1

Compression of the spring due to the first block = X1

m1g = kX1

Mass of the second block = 4m1

Upward acceleration of the elevator = 3g

The force from the spring on the second block = F

Compression of the spring due to the second block in the elevator = X2

From the free-body diagram of the 4m1 block,

(4m1)(3g) = F - 4m1g

F = 16m1g

kX2 = 16m1g

kX2 = 16(kX1)

X2 = 16X1

Compression of the spring due to a 4m1 block placed on it in an elevator accelerating upwards at 3g = 16X1.

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Answer:

Circuit

Series Circuit

Parallel Circuit

Short Circuit

Explanation:

I think this is right haha,,

Answer:

a = 5

Explanation:

F = M × A

15 = 3 × a

a = 15 / 3

a = 5

This is only if the toy can is pushing the book or smth coz the question looks incomplete...?

Answer:

5 m/s^2

Explanation:

Realize that Newton's Second Law explains that the net force is equal to the mass mulitplied by the acceleration, or in simple terms, F=ma. In the problem, the force is 15 newtons, and the mass is 3 kg. Substiting and dividing, we get 5 m/s^2 (5 meters per second squared).

Answer: 10

Explanation: