The cost of the paint needed to give the entire wall a good coverage of paint is $22
Firstly, we need to calculate the equivalent areas
Mathematically, we know that 1 ft is 12 inches
So to calculate the area of the wall in square inches, we have;
\(8\times22\times12\times\text{ 12 = 25,344 sq. inches}\)Now let us calculate the area of the test;
We have this as;
\(14\times\text{ 18 = 252 sq.inches}\)Now, we know that1 ounce is okay for the test, the number of ounces okay for the main wall would be;
\(\frac{25,344}{252}\text{ }\times\text{ 1 ounce =100.60 ounces}\)So, 100.60 ounces of paint would be enough to cover the wall
Finally, we proceed to get the cost of this as follows;
Mathematically, 1 ounce is 0.0078125 gallons
So, the number of ounces would be;
\(100.60\times0.0078125\text{ = 0.786 gallons}\)From the question, the cost per gallon is $28
So, the cost in 0.786 gallons would be;
\(0.786\times28\text{ = \$22}\)PLEASE HELP ON QUESTION ASAP! 30PTS!
I WILL ALSO GIVE YOU A THANKS RATE YOU FIVE STARS AND MAYBE EVEN BRAINLIEST any silly answeres will be reported / deleted
Hiba needs 40g sugar to make 15 biscuits. she also needs three times as much flour as sugar . Hiba is going to make 60 biscuits . work out the amount of flour she needs .
Need help will give brainliest
The equation formed after the transformations is given as follows:
\(g(x) = \frac{1}{6}\sqrt{x + 3}\)
How to obtain the function?The parent function in this problem is defined as follows:
\(f(x) = \sqrt{x}\)
For the vertical shrink by a factor of 1/6, the function is multiplied by 1/6, hence it is given as follows:
\(g(x) = \frac{1}{6}\sqrt{x}\)
For the translation left 3 units, we have that x -> x + 3, hence:
\(g(x) = \frac{1}{6}\sqrt{x + 3}\)
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Malcolm has $50 gift card to a local car wash and order is the ultimate car wash each visit is $8.95
The amount cheaper is the car washes Malcolm orders than the car washes Martha's order is $13.
The correct answer choice is option B.
How much cheaper is the car washes Malcolm orders than the car washes Martha's order?Malcolm's gift card = $50.
Cost Malcolm's car wash per visit = $7
Martha's gift card = $180
Cost Martha's car wash per visit = Difference between gift card balance of first and second visit
= $180 - $160
= $20
How cheap is the car washes Malcolm orders than the car washes Martha's order = $20 - $7
= $13
Therefore, Malcolm's car wash is cheaper than Martha's car wash by $13
The complete question is attached in the diagram.
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Factor.
x^2−8x+16
(x−4)2
(x+8)^2
(x−8)^2
(x+4)^2
Answer:
A
Step-by-step explanation:
two poles are 80 meters and 60 meters tall. Their bases are located at a distance of 90 meters. A grounding wire needs to connect the top of the poles with each other and the ground. At what point should we connect the wire with the ground if we wanted to use the least amount of wire?
It needs to do that route I guess. But I don't understand the last question well.
Please help me with this. (Geometry)
Step-by-step explanation:
Pythagoras's rule: \(a^2 + b^2 = c^2\) becomes \(x^2 + 10^2 = y^2\)
If we say b = 10: \(b = 10 = \sqrt{c^2 - a^2} = \sqrt{y^2 - x^2}\)
You only need to look at the left triangle
Which of the options follows Pythagoras's rule?
Let's try the options until we get the right one (in no particular order)
If we try: 3) x = 4 y = \(29\sqrt{2}\)...
\(\sqrt{(29\sqrt{2})^2 - 4^4} = 7\sqrt{34} \neq 10\)
If we try: 4) x = 16 y = 116...
\(\sqrt{116^2 - 16^2} = 20\sqrt{3} \neq 10\)
If we try: 2) x = 16 y = 29...
\(\sqrt{29^2 - 16^2} = 3\sqrt{65} \neq 10\)
If we try: 1) x = 4 y = \(2\sqrt{29}\)...
\(\sqrt{(2\sqrt{29})^2 - 4^2} = 10\)
The multiple instruments on the spacecraft-Cassini observed a giant storm erupted in December 2010 on Saturn. Which one of the following descriptions is NOT correct for the giant storm?
A. The storm developed in the northern hemisphere.
B. Lightning was not detected in the giant storm.
C. The storm generated very bright clouds on Saturn.
D. The storm affected the radiant energy budget of Saturn
The correct answer is option B.
The observation of a giant storm on Saturn from spacecraft Cassini indicates that lightning was not detected in the giant storm.
Usually Mega storms on Saturn happen on every 20 to 30 years.
Through the Cassini spacecraft, scientists could see a massive storm in December 2010. They saw that the storm waves were spreading from the planet's centre and that it was seen as a ringed globe.
The storm waves covered the whole surface of Saturn and had a diameter of around 190,000 miles or 300,000 kilometres.
Simply said, this enormous storm is also known as the Great Northern Storm or the Great White Spot.
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The graph compares the weights in pounds of 100 dogs and cats that are brought in
to a veterinarian's office. Using the medians, how much more does a typical dog weigh than a typical cat?
Answer:20
Step-by-step explanation:this is wrong
Answer:
40
Step-by-step explanation:
subtract median of dogs and median of cats
A two-child family is selected at random. Let B denote the event that at least one child is a boy, and let D denote the event that
the genders of the two children differ. Find the union of B and D. (1 point)
The union is (bb, gg); the first letter denotes the gender of the firstborn child, and the second letter denotes the gender of the
second child.
The union is (bg. gb); the first letter denotes the gender of the firstborn child, and the second letter denotes the gender of the
second child.
The union is {bb, bg, gb, gg); the first letter denotes the gender of the firstborn child, and the second letter denotes the gender of
the second child.
The union is (bb, bg. gb); the first letter denotes the gender of the firstborn child, and the second letter denotes the gender of the
second child.
With the help of probability we can say that, DUM={GG,BB,GB,BG).
What is Probability?Probability is the concept that describes the likelihood of an event occurring.
In real life, we frequently have to make predictions about how things will turn out.
We may be aware of the result of an occurrence or not.
When this occurs, we state that there is a possibility that the event will occur.
In general, probability has many excellent applications in games, commerce, and this newly growing area of artificial intelligence
The chance of an event can be calculated using the probability formula by only dividing the favourable number of possibilities by the total number of potential outcomes.
hence, DUM={GG,BB,GB,BG)
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Find the value of x.
Round to the nearest tenth.
18
A
28°
x = [? ]
X
Law of Sines: sin A
a
=
sin B
b
=
83°
C
sin C
C
X
B
Answer: It looks like you are trying to use the Law of Sines to find the value of x. The Law of Sines states that, in any triangle, the ratio of the sine of an angle to the length of the side opposite that angle is the same for all three angles and all three sides. In other words, if A, B, and C are the angles of a triangle and a, b, and c are the lengths of the sides opposite those angles, then:
sin A / a = sin B / b = sin C / c
To find the value of x, you need to plug in the values of the angles and the side lengths that you know, and then solve for x. Based on the information you provided, it looks like you know the values of A, B, and c. Therefore, you can use the Law of Sines to write the following equation:
sin A / x = sin B / b = sin C / c
You can then solve for x by cross-multiplying and rearranging the terms:
x = (b * sin A) / sin B
Plugging in the values you know, you get:
x = (b * sin 28°) / sin 83°
You can then use a calculator to find the value of x. When you do this, you will get a value of approximately 5.2. Rounded to the nearest tenth, the value of x is 5.2. The other options you gave are not equal to 5.2.
The value of x using sine rule is 8.5 (nearest tenth)
What is sine rule?The sine rule states that if a, b and c are the lengths of the sides of a triangle, and A, B and C are the angles in the triangle; with A opposite a, etc., then a/sinA=b/sinB=c/sinC.
Sine rule is used to find unknown side and unknown angle when the other side and corresponding angle is given.
The corresponding angle to 18 is 83°
The corresponding angle to x is 28°
Therefore;
x/sin28 = 18/sin83
18sin28 = xsin83
8.45 = 0.992x
divide both sides by 0.992
x = 8.45/0.992
x = 8.5 (nearest tenth)
Therefore the value of x to the nearest tenth is 8.5
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The area of a parallelogram is 40 square inches. The base of the parallelogram is 5 inches. What is the height of the parallelogram? Explain how you can use the formula for the area of a parallelogram to solve the problem.
The height of the parallelogram is 8 inches. By using the formula for the area of a parallelogram, we were able to find the missing value (height) by rearranging the formula and plugging in the given values.
To find the height of the parallelogram, we can use the formula for the area of a parallelogram, which is Area = Base × Height (A = b × h). In this problem, the area (A) is given as 40 square inches, and the base (b) is 5 inches. We need to find the height (h).
Using the formula, A = b × h, we can plug in the given values:
40 = 5 × h
To solve for h, we can divide both sides of the equation by 5:
40 ÷ 5 = 5 × h ÷ 5
8 = h
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Compare the values of the following numbers, using the symbols > (greater than), < (less than), and = (equal to).
0.5 _____0.500
Answer:
0.5 = 0.500
Step-by-step explanation:
Both numbers are five-tenths. The zeros to the right of the 5 are not place holders and do not change the value of the number.
0.5 = 0.500
You spend $40 on $5 pounds of concrete.what is the unit rate in dollars per pound
Answer:
$8/pound
Step-by-step explanation:
$40 ÷ 5 lbs = 8$ per pound
Which of the following expressions are equivalent to -9/j?
A: 9/-j
B: - -9/j
C: none of the above
Answer:
A
Step-by-step explanation:
-9/j is the same as 9/-j
If a firm has a production quota of 400=5x1^2+8x1x2+15x2^2, what combination of good x1 and x2 should the firm produce to minimize cost of C=x1^2+x2^2
The firm should produce good x₁ = 4 and x₂ = 8 to minimize cost of C = x₁² + x₂² .
What is Lagrange multipliers ?
Lagrange multipliers is a method used in optimization problems to find the maximum or minimum value of a function subject to one or more constraints. The method involves introducing a Lagrange multiplier, which is a scalar variable, to the objective function and the constraint(s). This forms the Lagrangian function, which is then optimized with respect to the original variables and the Lagrange multiplier.
To minimize the cost C = x₁² + x₂²
We can use the method of Lagrange multipliers to solve this problem. Let's define the Lagrangian function L as:
L(x₁, x₂, λ) = x₁²+ x₂² + λ(400 - 5x₁²- 8x₁x₂ - 15x₂²)
Taking partial derivatives of L with respect to x₁, x₂, and λ, we get:
∂L/∂x₁ = 2x₁ - 10λx₁ - 8λx₂ = 0
∂L/∂x₂ = 2x₂ - 30λx₂ - 8λx₁ = 0
∂L/∂λ = 400 - 5x₁² - 8x₁x₂ - 15x₂² = 0
Solving these equations simultaneously, we get:
x₁ = 4
x₂ = 8
λ = 1/20
Hence, the firm should produce a combination of x₁ = 4 and x₂ = 8 to minimize the cost of C = x₁² + x₂² while satisfying the production quota of 400.
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Can anyone help with this?
Answer:
AD = 15
Step-by-step explanation:
Based on the Pythagoras Theorem, the longest side of a right-angled triangle is: \(\sqrt{a^{2}+b^{2}}\) where a and b are the legs of the triangle.
In triangle BDC, we can put in the formula to find BD.
85 = \(\sqrt{77^{2}+BD^{2}}\)
85² = 77² + BD²
7225 = 5929 + BD²
BD² = 7225 - 5929
= 1296
BD = \(\sqrt{1296}\)
BD = 36
In triangle ABD, we can put in the formula to find AD.
39 = \(\sqrt{36^{2}+AD^{2}}\)
39² = 36² + AD²
1521 = 1296 + AD²
AD² = 1521 - 1296
= 225
AD = \(\sqrt{225}\)
AD = 15
Set up and solve an equation for the value of x. Use the value of x and a relevant angle relationship in the diagram.
(please also show an step by step process of getting EAF!)
Answer:
x = 27 , ∠ EAF = 27°
Step-by-step explanation:
∠ GAF = 90° , then
∠ GAC + ∠ CAF = ∠ GAF , that is
x + 63 = 90 ( subtract 63 from both sides )
x = 27
∠ DAE = 90°
since CD is a straight angle of 180° , then
∠ CAE = 90° , so
∠ CAF + ∠ EAF = ∠ CAE , that is
63° + ∠ EAF = 90° ( subtract 63° from both sides )
∠ EAF = 27°
Statistical data of breakdowns of computer XXX show that the duration for trouble-free operation of the machine can be described as a gamma distribution with a mean of 40 days and a standard deviation of 10 days. The computer is occasionally taken out for maintenance in order to insure operational condition at any time with a 95% probability.
1. How often should the computer be scheduled for maintenance? Should it be shorter or longer than the mean of 40 days?
2. Three XXX computers were acquired at the same time by an engineering consulting firm. The computers are operating under the same environment, workload, and regular maintenance schedule. The breakdown times between the computers, however, may be assumed to be statistically independent. What is the probability that at least one of the three machines will break down within the first scheduled maintenance time?
1. In this case, we want the reliability to be 95%, so the probability of not breaking down is 0.95.
2. Probability of no breakdowns = (reliability of a single machine)^3. Probability of at least one breakdown = 1 - Probability of no breakdowns
1. To determine how often the computer should be scheduled for maintenance, we need to consider the reliability and the desired level of operational condition. Since the duration for trouble-free operation follows a gamma distribution with a mean of 40 days, this means that, on average, the computer can operate for 40 days before a breakdown occurs.
To ensure operational condition with a 95% probability, we can calculate the maintenance interval using the concept of reliability. The reliability represents the probability that the machine will not break down within a certain time period. In this case, we want the reliability to be 95%, so the probability of not breaking down is 0.95.
Using the gamma distribution parameters, we can find the corresponding reliability for a specific time duration. By setting the reliability equation equal to 0.95 and solving for time, we can find the maintenance interval:
reliability = 0.95
time = maintenance interval
Using reliability and the gamma distribution parameters, we can calculate the maintenance interval.
2. To calculate the probability that at least one of the three machines will break down within the first scheduled maintenance time, we can use the complementary probability approach.
The probability that none of the machines will break down within the first scheduled maintenance time is given by the reliability of a single machine raised to the power of the number of machines:
Probability of no breakdowns = (reliability of a single machine)^3
Since the breakdown times between the machines are statistically independent, we can assume that the reliability of each machine is the same. Therefore, we can use the reliability calculated in the first part and substitute it into the formula:
Probability of at least one breakdown = 1 - Probability of no breakdowns
By calculating this expression, we can determine the probability that at least one of the three machines will break down within the first scheduled maintenance time.
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what is the intial value of the function represented by this graph (7,6) (0,3)
Answer: 7
i took the test
by examining birth records, it has been determined that 12% of people are born in the winter (w), 28% are born in the spring (sp), 42% are born in the summer (su), and 18% are born in the fall (f). suppose we select a person at random. find each probability. p(w and f)
The probability of selecting a person at random is p(w and f) is 0.0216 or 2.16%.
The probability of an event occurring and another event occurring is found by using the multiplication rule of probability, which states that the probability of two events occurring together is equal to the product of the probabilities of each event occurring independently.
In this case, we are looking for the probability of a person being born in the winter (p(w)) and the probability of a person being born in the fall (p(f)), so we would calculate:
p(w and f) = p(w) * p(f)
Using the information provided, we know that:
p(w) = 12% = 0.12
p(f) = 18% = 0.18
So, to find p(w and f), we would multiply:
p(w and f) = 0.12 * 0.18 = 0.0216 or 2.16%
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Answer:
0
0.30
0.82
0.70
Step-by-step explanation:
A sequence can be generated by using an= 3an-1, where a1 = 10 and n is a whole number greater than 1.
What are the first 3 terms in the sequence?
A. 3, 13, 23
B. 10, 30, 90
C. 10, 13, 16
D. 3, 30, 300
Answer:
B
Step-by-step explanation:
using the recursive rule \(a_{n}\) = 3\(a_{n-1}\) and a₁ = 10, then
a₁ = 10
a₂ = 3a₁ = 3 × 10 = 30
a₃ = 3a₂ = 3 × 30 = 90
the first 3 terms are 10 , 30 , 90
Dennis says that 1 1/2,1 2/4, and 1 3/6 are all equivalent. Is he
correct?
Answer: Yes
Step-by-step explanation:
Most fractions can be simplified into smaller fractions, while some are in it's simplest form. When putting a bit in its simplest form it is much easier to compare to other fractions
What I did first tried to simplify all the factions, starting with 1 1/2.
After looking at 1 1/2, I can see that it is in its simplest form.
Then looking at 1 2/4 I can see that it can be simplified into 1 1/2.
Lastly looking at 1 3/6 I can see that it can be simplified into 1 1/2.
Merone Company allocates materials handling cost to the company's two products using the below data:
Modular Homes Prefab Barns
Total expected units produced 5,900 8,900
Total expected material moves 590 190
Expected direct labor-hours per unit 790 290
The total materials handling cost for the year is expected to be $325,890.
If the materials handling cost is allocated on the basis of material moves, the total materials handling cost allocated to the modular homes is closest to: (Round your intermediate calculations to 2 decimal places.)
Multiple Choice
$246,507.90
$160,629.00
$213,514.00
$238,382.50
Merone Company allocates materials handling cost to the company's two products using the below data:
Modular Homes Prefab Barns
Total expected units produced 6,000 9,000
Total expected material moves 600 200
Expected direct labor-hours per unit 800 300
The total materials handling cost for the year is expected to be $300,000.
If the materials handling cost is allocated on the basis of direct labor-hours, the total materials handling cost allocated to the prefab barns is closest to: (Round your intermediate calculations to 2 decimal places.)
Multiple Choice
$105,000.00
200,000.00
$150,204.00
$108,000.00
Spates, Incorporated, manufactures and sells two products: Product H2 and Product E0. Data concerning the expected production of each product and the expected total direct labor-hours (DLHs) required to produce that output appear below:
Expected Production Direct Labor-Hours Per Unit Total Direct Labor-Hours
Product H2 190 6.9 1,311
Product E0 190 5.9 1,121
Total direct labor-hours 2,432
The company’s expected total manufacturing overhead is $270,968.
If the company allocates all of its overhead based on direct labor-hours, the overhead assigned to each unit of Product H2 would be closest to: (Round your intermediate calculations to 2 decimal places.)
Multiple Choice
$222.84 per unit
$126.48 per unit
$768.80 per unit
$96.36 per unit
Doles Corporation uses the following activity rates from its activity-based costing to assign overhead costs to products.
Activity Cost Pools Activity Rate
Setting up batches $ 70.72 per batch
Processing customer orders $ 27.78 per customer order
Assembling products $ 12.81 per assembly hour
Data concerning two products appear below:
Product K52W Product X94T
Number of batches 66 53
Number of customer orders 46 31
Number of assembly hours 419 162
Required:
How much overhead cost would be assigned to each of the two products using the company's activity-based costing system? (Round your intermediate calculations and final answers to 2 decimal places.)
The total materials handling cost allocated to the modular homes is $246,372.84.
The total materials handling cost allocated to the Prefab Barns is closest to $108,000.
What is the total materials handling cost allocated?To allocate materials handling cost based on material moves, we must determine proportion of material moves for each product and then apply that proportion to the total materials handling cost.
Proportion of material moves for Modular Homes:
= (Total expected material moves for Modular Homes) / (Total expected material moves for both products)
= 590 / (590 + 190)
= 0.756
Total materials handling cost allocated to Modular Homes:
= Proportion of material moves for Modular Homes * Total materials handling cost
= 0.756 * $325,890
= 246 372.84
= $246,372.84.
To allocate the materials handling cost based on direct labor-hours, we need to determine proportion of direct labor-hours for each product.
For Modular Homes:
Total direct labor-hours for Modular Homes:
= 6,000 units * 800 hours/unit
= 4,800,000 hours
For Prefab Barns:
Total direct labor-hours for Prefab Barns:
= 9,000 units * 300 hours/unit
= 2,700,000 hours
Total direct labor-hours for both products:
= 4,800,000 hours + 2,700,000 hours
= 7,500,000 hours
Proportion of direct labor-hours for Prefab Barns:
= 2,700,000 hours / 7,500,000 hours
= 0.36
Allocated materials handling cost for Prefab Barns:
= Proportion of direct labor-hours for Prefab Barns * Total materials handling cost
= 0.36 * $300,000
= $108,000.
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Group the terms with variables on one side of the equal sign, and simplify.
5z + 3 = 36z
Answer:
z = 3/31
Step-by-step explanation:
5z + 3 = 36z
subtract 5z on both sides
3 = 31z
divide by 31 on both sides
z = 3/31
find the y intercept and the slope of thr line y=-7-3x
By definition, the Slope-Intercept form of the equation of a line is:
\(y=mx+b\)Where "m" is the slope of the line and "b" is the y-intercept.
In this case, you have the following equation of the line given in the exercise:
\(y=-7-3x\)You can rewrite it as following:
\(y=-3x-7\)Therefore, knowing the explained before, you can identify that:
\(\begin{gathered} m=-3 \\ b=-7 \end{gathered}\)The answer is:
• Slope:
\(m=-3\)• y-intercept:
\(b=-7\)suppose that prices of a gallon of milk at various stores in one town have a mean of $3.55 with a standard deviation of $0.14 . using chebyshev's theorem, state the range in which at least 75% of the data will reside. please do not round your answers.
At least 75% of the data might very well fall between $3.25 and $3.81. According to Chebyshev's theorem, at least 75% of the value systems in a distribution are well within 2 the mean standard deviation.
A delivery has at least 89% of its values inside of three of the mean's standard deviation.
We have the following in this problem:
Mean = $3.53
$0.14 is the standard deviation.
Using Chebyshev's Theorem, determine the range that contains least 75% of the information will live.
2 standard deviations from the mean.
So 3.53 - 2*0.14 = $3.25 becomes 3.53 + 2*0.14 = $3.81.
At least 75% of the data might very well fall between $3.25 and $3.81.
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PLEASSSSSSSSSSSSEEE HELPPP
69=-3(-3-4p)
Answer:
p = 5
Step-by-step explanation:
-3(-3-4p) = 69
-3×(-3) + -3× (-4p) = 69
9 + 12p = 69
12p + 9 - 9 = 69 - 9
12p = 60
p = 5
Hope this helps!!!
What are the slope and y-intercept of the line?
slope = -170. y-intercept = 1020
Step-by-step explanation:
Let \(P_1(0, 1020)\) and \(P_2(6, 0).\) The slope can be calculated as
\(m = \dfrac{0 - 1020}{6 - 0} = -170\:\text{m/hr}\)
So the equation can be written as
\(y = -170x + b\)
To solve for b, let's use the values for P2:
\(0 = -170(6) + b \Rightarrow b = 1020\)
Therefore,
\(y = -170x + 1020\)
To find the y-intercept, let x = 0. then the y-intercept is
\(y = -170(0) + 1020\)
or
\((0, 1020).\)
Joe drove 464 miles in 8 hours.
At the same rate, how long would it take him to drive 754 miles?
hours
Х
$
?
Answer:
13 hours
Step-by-step explanation:
Set up a proportion.
464 miles / 8 hours = 754 miles / x hours
Cross multiply
464x = 6032
Divide by 464 on both sides
x = 13
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A random sample of adult female reaction times has a sample mean of x¯=394.3 milliseconds and sample standard deviation of s=84.6 milliseconds. Use the Empirical Rule to determine the approximate percentage of adult female reaction times that lie between 140.5 and 648.1 milliseconds.
Answer:
The percentage of adult female reaction times that lie between 140.5 and 648.1 milliseconds is 99.7%.
Step-by-step explanation:
The Empirical Rule states that, for a normally distributed random variable:
68% of the measures are within 1 standard deviation of the mean.
95% of the measures are within 2 standard deviation of the mean.
99.7% of the measures are within 3 standard deviations of the mean.
In this problem, we have that:
Mean = 394.3 ms
Standard deviation = 84.6 ms
Use the Empirical Rule to determine the approximate percentage of adult female reaction times that lie between 140.5 and 648.1 milliseconds.
140.5 = 394.3 - 3*84.6
So 140.5 is 3 standard deviations below the mean.
648.1 = 394.3 + 3*84.6
So 648.1 is 3 standard deviations above the mean.
By the Empirical Rule,
The percentage of adult female reaction times that lie between 140.5 and 648.1 milliseconds is 99.7%.