a hippo's body is 4.0 m long with front and rear feet located as in (figure 1). the hippo carries 60% of its weight on its front feet. Figure <1 of 1 Part A How far from its tail is the hippo's center of gravity? Express your answer with the appropriate units. S → ? de Value Units Submit Request Answer Provide Feedback Beview 1 Constants

Answers

Answer 1

The hippo's center of gravity is d = 158m.

Calculation:

from the given figure-

weight of front = 0.60w

weight of back = 0.40 W

By Balancing the forces.

0.60 [1.8+ 0.5-d] -[0.4(α-0.5)]=0

= 1.08 +0.3 - 0.60d - 0.4d +0.2 = 0

d = 158m

A force is a push or pulls on an object caused by its interaction with another object. Whenever there is an interaction between two objects, there is a force acting on each object. When the interaction stops, there is no force on the two objects.

There are four fundamental forces gravity electromagnetic force weak nuclear force, and strong nuclear force. Of these four forces, the mighty nuclear force is the most powerful. From this, we can conclude that whenever the direction of force is in the direction of motion the velocity of the object increases, and when it is opposite to the direction of motion the velocity decreases.

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Related Questions

What is the density of a cube that has a mass of 3.75 g and a volume of 3 mL?

Answers

Answer:

\(\displaystyle \rho=1.25\ g/ml\)

Explanation:

Density

The density of a substance is the mass per unit volume. The density varies with temperature and pressure.

The formula to calculate the density of a substance of mass (m) and volume (V) is:

\(\displaystyle \rho=\frac{m}{V}\)

The cube has a mass of m=3.75 g and a volume of V=3 ml, thus the density is:

\(\displaystyle \rho=\frac{3.75\ g}{3\ ml}\)

\(\boxed{\displaystyle \rho=1.25\ g/ml}\)

Since 1 kg=1000 mg and 1 lt = 1000 ml, the density has the same value but with different units:

\(\displaystyle \rho=1.25\ kg/l\)

Which type of wall would make the best soundproofing for room?
A.
1.0 centimeter thick glass
OB.
two layers of 0.5 centimeter thick glass with 0.5 centimeters of air between them
C.
two layers of 0.5 centimeter thick glass with 0.3 centimeters of vacuum between them
OD.
1.0 centimeter thick steel

Answers

Among the options given, the choice that would make the best soundproofing for a room is option C: two layers of 0.5 centimeter thick glass with 0.3 centimeters of vacuum between them.

Soundproofing is achieved by reducing the transmission of sound waves from one side of the wall to the other. In this case, the combination of two layers of glass with a vacuum between them helps to reduce sound transmission effectively.

Glass is a denser material compared to air or vacuum, so it naturally provides some sound insulation. Adding an extra layer of glass creates a barrier that helps to further dampen sound vibrations. The vacuum between the glass layers acts as an additional sound barrier, as sound waves have difficulty propagating through a vacuum due to the absence of a medium for transmission.

On the other hand, a single layer of 1.0 centimeter thick glass (option A) or two layers of 0.5 centimeter thick glass with 0.5 centimeters of air between them (option B) would provide some sound reduction but not as effective as the combination of glass layers with a vacuum in option C.

1.0 centimeter thick steel (option D) would have high density and mass, which could help with sound insulation to some extent. However, steel can still transmit vibrations and might not be as effective as the combination of glass layers with a vacuum in option C for soundproofing a room.

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fun facts are,
Butterflies taste with their hind feet.
A group of crows is called murder.
Tomato sauce was sold in the 1800's as medicine.
A donkey will sink in quicksand, but a mule won't.
Lakes Can Explode. ...
Earth Used to Be Purple. ...
60 Tons of Cosmic Dust Fall to Earth Daily. ...
The Oceans Hold $771 Trillion Worth of Gold. ...
Earth Once Had Two Moons. ...
Earth Might Still Have Two Moons. ...
The Greatest Vertical Drop Is in Canada. ...
The Hottest Spot in the World Is in California.

Answers

Answer:

that is cool and i have one interesting fact

Explanation: North Korea and Cuba are the only places you can't buy Coca-Cola

this is sick :)

thanks for sharing , i mean i don’t really have a fun fact but did you know that every time you learn something new your brain wrinkles i think

An example of conservation of angular momentum is jumping on a Merry-Go-Round. Watch this video (it starts part way through but the only thing you miss is the people pushing the Merry-Go-Round) to see someone jumping on a Merry-Gr-Round in motion like this problem. You can model the Merry-Go-Round as a solid disk with a radius of 2.70 m and a mass of 77.0 kg. Initially the Merry-Go-Round has an angular velocity 7.40 radians / second. Then the person jumps on and change the Moment of Inertia of the system. The person lands on the outer edge of the Merry-Go-Round and has a mass of 58.0 kg. What is the final angular velocity of the system after the person jumps on

Answers

Answer:

ωf = 2.95 rad/sec

Explanation:

Assuming no external torques acting while the person jumps on, total angular momentum must be conserved.Angular momentum for a rotating rigid body can be expressed as follows:

       \(L = I * \omega (1)\)

where I = moment of inertia regarding the rotating axis, and ω= angular velocity.Since total angular momentum must be conserved, this means that the following equality must be satisfied:

       \(L_{o} = L_{f} (2)\)

The initial angular momentum, taking into account that the Merry-Go-Round can be modeled as solid disk, can be expressed as follows:

        \(L_{o} = I_{o} * \omega_{o} = \frac{1}{2}* M* R^{2}* \omega_{o} =\\ \frac{1}{2} * 77.0 kg* (2.70m)^{2}* 7.40 rad/sec = 2076.92 kg*m2*rad/sec (3)\)

The final angular momentum, is just the product of the new moment of inertia times the final angular velocity.The new moment of inertia, is just the sum of the original moment of inertia I₀ and the moment of inertia due to the person that jumps on.Assuming that we can treat him as a point mass, his moment of inertia is just the product of his mass times to the distance to the axis of rotation (the radius of the Merry-Go-Round) squared.So, we can write the new moment of inertia If as follows:

       \(I_{f} = I_{o} +( m_{p} * R^{2}) = (\frac{1}{2} * M* R^{2}) + ( m_{p} * R^{2}) =\\ (\frac{1}{2} * 77.0 kg* (2.70m)^{2}) +( 58.0 kg * (2.70m)^{2}) = \\ 280.67 kg*m2 + 422.82 kg*m2 = \\ 703.49 kg*m2 (4)\)

The final angular momentum can be written as follows:

        \(L_{f} = I_{f} * \omega_{f} (5)\)

Since (3) and (5) must be equal each other, replacing If by its value from (4) in (5), we can solve for ωf, as follows:

       \(\omega_{f} = \frac{L_{o} }{I_{f}} = \frac{2076.92kg*m2*rad/sec}{703.49kg*m2} = 2.95 rad/sec (6)\)

A 0.45kg football is thrown in the air and travels at a velocity of 26m/s. Calculate the momentum of the football.

Your Answer:

A 0.45kg football is thrown in the air and travels at a velocity of 26m/s. Calculate the momentum of

Answers

Answer:

11.7 I don't really know the unit for momentum, I think its p but I don't know

Explanation:

u have to multiply to get the momentum

Calculate the net torque about point O for the two forces applied as in the figure below. The rod and both forces are in the plane of the page. Let F1=7.80N and F2=11.0N. Take counterclockwise torques to be positive.
A horizontal rod. Point O is marked at its left end. The rod is subjected to two forces. Force F subscript 1 acts vertically downward on the right end of the rod. Force F subscript 2 acts on a point of the rod 2.00 meters from its left end and 3.00 meters from its right end. Force F subscript 2 points upward and to the left making an angle of 30.0 degrees with the rod.

Answers

The net torque about point O for the two forces applied as in the figure below is 17.4Nm

Find the diagram to the question attached

Given the following parameters

F1 = 7.80N

F2=11.0N

Taking the force along the vertical;

τ₂ = 7.80sin30(2.0)

τ₂ = 15.6Nm

For the other force along the vertical;

τ₁ = 11.0 * 3

τ₁ = 33Nm

Net torque is expressed as =  33Nm -  15.6Nm

Net torque = 17.4Nm

Hence the net torque about point O for the two forces applied as in the figure below is 17.4Nm

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Calculate the net torque about point O for the two forces applied as in the figure below. The rod and

consider the combination of two capacitor c1 and c2 with c2>c1,when connected in parallel,the equivalent capacitance is 8 times the equivalent capacitance of the same connected in series. calculate the ratio of capacitor c2/c1?​

consider the combination of two capacitor c1 and c2 with c2&gt;c1,when connected in parallel,the equivalent

Answers

Explanation:

Current flowing through the circuit, I = 2A Applying Kirchoff’s Ist law at junction P, I = I1 + I2 I2 = I – I1 …(1) Applying Kirchoff’s Ind law at junction PQSP 5 I1 + 10 Ig – 15 I2 = 0 5 I1 + 10 Ig -15(I – I1) = 0 20 I1 + 10 Ig = 15 I 20 I1 + 10 Ig = 15 x 2 ÷ by 10 21 I1 + Ig = 3 … (2) Applying Kirchoff’s II law at junction QRSQ 10(I1 – Ig ) – 20(I – I1 – Ig ) – 10 Ig = 0 10 I1 – 10g – 20(I – I1 – Ig ) – 10 Ig = 0 10 I1 – 10 – 20 I + 20 I1 -20Ig – 10 Ig = 0 30 I1 – 40 Ig = 20 I ÷ by 10 ⇒ 3 I1 – 4 Ig = 20 I 3 I1 – 4 Ig = 2 I 3 I1 – 4 Ig = 2 x 2

hope this helps :)

An Atwood's machine consists of blocks of masses m1=12.0kg and m2=19.0kg attached by a cord running over a pulley. The pulley is a solid cylinder with mass M=9.20kg and radius r=0.200m the block of mass m2 is allowed to drop, and the core turns the pulley without slipping. If the pulley axis is frictionless, find the linear acceleration of the system and the tension on each string.​

Answers

Answer:

2.60 m/s²

149 N and 137 N

Explanation:

Draw free body diagrams for the blocks and the pulley.

For the first block, there are two forces: m₁g pulling down and T₁ pulling up.

For the second block, there are two forces: m₂g pulling down and T₂ pulling up.

For the pulley, there are two torques: T₁r pulling counterclockwise and T₂r pulling clockwise.

m₁ moves up, so sum the forces in the +y direction:

∑F = ma

T₁ − m₁g = m₁a

m₂ moves down, so sum the forces in the -y direction:

∑F = ma

m₂g − T₂ = m₂a

The pulley rotates clockwise, so sum the torques in the clockwise direction:

∑τ = Iα

T₂r − T₁r = (½ Mr²) (a/r)

T₂ − T₁ = ½ Ma

If we add the first two equations together:

T₁ − m₁g + m₂g − T₂ = m₁a + m₂a

T₁ − T₂ + (m₂ − m₁) g = (m₁ + m₂) a

Substitute:

½ Ma + (m₂ − m₁) g = (m₁ + m₂) a

(m₂ − m₁) g = (m₁ + m₂ − ½ M) a

a = (m₂ − m₁) g / (m₁ + m₂ − ½ M)

Plug in values:

a = (19.0 kg − 12.0 kg) (9.8 m/s²) / (12.0 kg + 19.0 kg − ½ (9.20 kg))

a = 2.60 m/s²

Plug this into the first two equations to find the two tensions.

T₁ = m₁g + m₁a = 148.8 N

T₂ = m₂g − m₂a = 136.8 N

Rounded to three significant figures, the tensions are 149 N and 137 N.

The magnitude of tension force on each strings are 148.8 N and 136.8 N respectively.

Given data:

The mass of blocks are \(m_{1}=12.0 \;\rm kg\)  and  \(m_{2}=19.0 \;\rm kg\).

The mass of solid cylinder is, M = 9.20 kg.

The radius of solid cylinder is, r = 0.200 m.

In the given problem, there are two cases:

For the first block, there are two forces: m₁g pulling down and tension T₁ pulling up. For the second block, there are two forces: m₂g pulling down and tension T₂ pulling up.

For the pulley, there are two torques: T₁r pulling counterclockwise and T₂r pulling clockwise.

m₁ moves up, so sum the forces in the +y direction. Then apply the equilibrium of force condition as,

∑F = ma

T₁ − m₁g = m₁a

Since, m₂ moves down, so sum the forces in the -y direction:

∑F = ma

m₂g − T₂ = m₂a

The pulley rotates clockwise, so sum the torques in the clockwise direction:

∑τ = Iα

T₂r − T₁r = (½ Mr²) (a/r)

T₂ − T₁ = ½ Ma

If we add the first two equations together:

T₁ − m₁g + m₂g − T₂ = m₁a + m₂a

T₁ − T₂ + (m₂ − m₁) g = (m₁ + m₂) a

Substitute:

½ Ma + (m₂ − m₁) g = (m₁ + m₂) a

(m₂ − m₁) g = (m₁ + m₂ − ½ M) a

a = (m₂ − m₁) g / (m₁ + m₂ − ½ M)

Substitute the values:

a = (19.0 kg − 12.0 kg) (9.8 m/s²) / (12.0 kg + 19.0 kg − ½ (9.20 kg))

a = 2.60 m/s²

Plug this into the first two equations to find the two tensions.

T₁ = m₁g + m₁a = 148.8 N

T₂ = m₂g − m₂a = 136.8 N

 

Thus, we can conclude that the magnitude of tension force on each strings are 148.8 N and 136.8 N respectively.

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I need help with this practice I’m struggling to solve it

I need help with this practice Im struggling to solve it

Answers

The blades on the turbines transform the energy coming from the wind into rotational kinetic energy.

The blades convert wind energy into rotational energy.

Laasya is lifting a table and moving it to another room to expand the space in her room. What mode of
strength-training
is Laasya performing?

Answers

Laasya is performing resistance training by lifting a table and moving it to another room to expand the space in her room. The correct option to this question is D.

Strength training By putting your muscles up against resistance, resistance training builds muscle strength. Free weights, weight machines, resistance bands, and your own body weight are all used in various types of resistance training. To get the most out of their training, beginners should go two or three times per week.Resistance training is founded on the idea that, when called upon, the body's muscles will struggle to overcome a resisting force. Resistance exercise has both advantages and disadvantages.Resistance exercises include planks, sit-ups, squats, push-ups, leg raises, and leg extensions. You and a small amount of room are all that are needed for these strength training exercises.

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Complete question : Laasya is lifting a table and moving it to another room to expand the space in her room. What mode of strength-training is Laasya performing?

a. Endurance

b. Isometric

c. Isotonic

d. Resistance

What energy transfer happens in many musical instruments?
Sound to kinetic
Electrical to kinetic
Kinetic to sound​

Answers

Answer:

kinetic to sound

Explanation:

this is because energy is moving in the instrument and it produces sound.

A dentist uses a concave mirror to examine a tooth that is 1.00
cm in front of the mirror. The image of the tooth forms 10.0 cm
behind the mirror. What is the mirror's radius of curvature?

Answers

Answer:

-2.2cm

Explanation:

A dentist uses a concave mirror to examine a tooth that is 1.00 cm in front of the mirror. The image of the tooth forms 10.0 cm behind the mirror. What is the mirror's radius of curvature 0.909 m.

To determine the mirror's radius of curvature, we can use the mirror formula:

1/f = 1/v - 1/u

Where:

f is the focal length of the mirror

v is the image distance (distance of the image from the mirror)

u is the object distance (distance of the object from the mirror)

In this case, the object distance (u) is 1.00 cm and the image distance (v) is -10.0 cm (since the image is formed behind the mirror, the distance is negative).

1/f = 1/(-10.0) - 1/(1.00)

Simplifying the equation:

1/f = -0.1 - 1

1/f = -1.1

Now, we can find the reciprocal of both sides of the equation:

f/1 = -1/1.1

f ≈ -0.909 m

The negative sign indicates that the mirror is concave.

Therefore, the mirror's radius of curvature is approximately 0.909 m.

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5. A spring of k-500 N/m that is initially compressed 2m is used to launch a 100N load of bricks up a 2 m tall
hill. Find the speed of the bricks at the top of the hill.
a. Qualitatively complete the energy flow diagram and the energy bar graphs.

5. A spring of k-500 N/m that is initially compressed 2m is used to launch a 100N load of bricks up a

Answers

The kinetic energy of the brick equal the elastic potential energy at the top of the hill. Using this, the speed of the brick is 14 m/s.

What is elastic potential ?

The elastic potential of a spring is directly proportional to the squire of the displacement.

Then,

p = 1/2 k x²

Given that, spring constant k = 500 N/m

height of the hill x = 2 m

weight of the load = 100 N

then mass = 100N/9.8 m/s² =10.20 Kg.

At the top of the hill, kinetic energy of the hill is equal to the elastic potential.

then, 1/2 mv² =  1/2 k x²

speed v of the brick  = √kx²/m

v = √(500 N/m × 2 m²/10.20 kg)

  = 14 m/s.

Therefore, the speed of the brick at the top of the hill is 14 m/s.

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Describe and explain motion due to uniform velocity in one direction and uniform acceleration in a perpendicular direction

Answers

Answer: you have to divide and multiple fam

Explanation:

1. Question(s) related to how individuals are represented in the ads

2. Questions related to how groups and group behavior are represented in the ad

3. Questions related to how cultures and cultural identity are represented (or not represented) in the ad

4. How do the ads compare to each other?

5. What overall observations might a social scientist be interested in studying in relation to the themes present in these advertisements?

What larger questions about human interactions might they ask?

1. Question(s) related to how individuals are represented in the ads 2. Questions related to how groups

Answers

The ad shows an adult man and a child shopping for fruit at a grocery store. It is possible to notice that there are common physical similarities between them, and it is possible that they are father and son.

Groups and group behavior are identified in the advertisement through the process of socialization, that is, the cultural formation of the individual.

Socialization

It refers to a cultural identity, which are the habits, values ​​and behaviors learned through living in society. Primary socialization refers to the learning process in early childhood through the family, being a key agent in the process of formation of an individual's personality.

Culture is identified in the advertisement as coming from the child's socialization process. That is, it is possible to see him imitating his father's behavior when choosing a fruit at the grocery store, as if this were a habit learned at home.

A social scientist may be interested in studying the themes present in the advertisement by understanding how the socialization process is able to determine the culture, actions and behavior of individuals in society.

Therefore, through the socialization process it is possible to understand the interaction of individuals in society and ways to make it more developed and egalitarian.

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A certain satellite travels in an approximately circular orbit of radius 8.8 × 10^6 m with a period of 6 h 12 min. Calculate the mass of its planet from this information.

Answers

The mass of the planet is  5.98 × 10^24 kg.

To calculate the mass of the planet, we can use Kepler's Third Law of Planetary Motion. This law states that the square of the period of revolution of a planet around the sun is directly proportional to the cube of the semi-major axis of its orbit.

First, we need to convert the period of the satellite's orbit to seconds. We know that there are 60 minutes in an hour, so the period can be expressed as (6 × 60 + 12) minutes, which equals 372 minutes. Multiplying this by 60 seconds, we get a period of 22,320 seconds.

Next, we need to find the semi-major axis of the orbit. In a circular orbit, the semi-major axis is equal to the radius of the orbit. Therefore, the semi-major axis is 8.8 × 10^6 m.

Now, we can apply Kepler's Third Law to calculate the mass of the planet. The formula is T^2 = (4π^2/GM) × a^3, where T is the period of revolution, G is the gravitational constant, M is the mass of the planet, and a is the semi-major axis of the orbit.

Rearranging the formula, we can solve for the mass of the planet:
M = (4π^2/G) × a^3 / T^2

Plugging in the values, we get:
M = (4 × π^2 / 6.67430 × 10^-11) × (8.8 × 10^6)^3 / (22,320)^2

Evaluating this expression, we find that the mass of the planet is approximately 5.98 × 10^24 kg.

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In hiking, what fitness component is required of you

Answers

It’s strength, endurance and flexibility. Hope this helps

A roller coaster is at a peak of 20m and has a mass of 900kg. What is the potential energy of the roller coaster?
O 100000 J
10000 J
O 9.8 J
O 176400 J

Answers

The potential energy of the roller coaster is 176,400 J (joules).

The potential energy of an object is given by the formula PE = mgh, where PE is the potential energy, m is the mass of the object, g is the acceleration due to gravity, and h is the height or vertical position of the object.

In this case, the roller coaster is at a peak of 20m and has a mass of 900kg. The acceleration due to gravity, g, is approximately 9.8 \(m/s^2\).

Using the formula, we can calculate the potential energy:

PE = mgh

= (900 kg)(9.8 \(m/s^2\))(20 m)

= 176,400 J

Therefore, the potential energy of the roller coaster is 176,400 J (joules).

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A quartz sphere is 14.0 cm in diameter. What will be its change in volume if its temperature is increased by 305°F? The coefficient of volume expansion of quartz is 1.50×10^6/°C. Answer in cm^3 .

Answers

Answer:

  0.365 cm³

Explanation:

The change in volume is found by multiplying the coefficient of expansion by the volume and the temperature change. The temperature change is in °F, but the expansion coefficient is per °C, so we need to convert the temperature scale in the computation.

  ΔV = V·Ce·ΔT

  = (π/6·d³)(1.5×10⁻⁶/°C)((5 °C)/(9 °F))(305 °F)

  = (1436.76 cm³)(1.5×10⁻⁶/°C)(169.44 °C)

  = 0.365 cm³ . . . . increase in volume

Which describes the experiments of Becquerel and the Curies?

Answers

Becquerel showed that uranium gave off radioactivity, and the Curies discovered other radioactive elements.

An ultrasonic tape measure uses frequencies above 20 MHz todetermine dimensions of structures such as buildings. It does so byemitting a pulse of ultrasound into air and then measuring the timeinterval for an echo to return from a reflecting surface whosedistance away is to be measured. The distance is displayed as adigital read-out. A tape measure emits a pulse of ultrasound with afrequency of 25.0 MHz.
(a) What is the distance to an object fromwhich the echo pulse returns after 24ms when the air temperature is 26°C?
(b) What should be the duration of the emitted pulse if it is toinclude 10 cycles of the ultrasonic wave?
(c) What is the spatial length of such a pulse?

Answers

Answer:  

a) 1m

b) 2μs

c) 3mm

Explanation:

Given a rank for a particular flood event of 25 and a record of 24 years duration, what is
the recurrence interval for a flood of this size?

Answers

Answer:

The 25-year flood occurs on average once every 25 years and has an exceedance probability of 1 over 25, or 4 percent, in any given year

A cannon sits on top of a cliff that is 20 meters above an area of level ground. It fires a 5 kg cannonball horizontally (cannonball A) at 5 meters/second. At the same time, a second cannonball (cannonball B) is dropped from the same height. If air resistance is ignored, which cannonball will hit the ground first?
Note: The gravitational acceleration due to the Earth is 9.8 m/sec².
A. Cannonball A
B. Cannonball B
C. Both will hit the ground at the same time.
D. It can not be found from the given information.​

Answers

Answer:

d

Explanation:

Determine whether the center of mass of the system consisting of the earth and moon lies inside or outside the earth. Assume that the radius of the earth is 6.37 x 10^3 km, the mass of the earth is 5.98 x 10^24 kg, the mass of the moon is 7.35 x10^22 kg, and the distance between the centers of the earth and the moon is 3.84 x 10^5 km. When computing the center of mass, consider the earth and the moon as point masses.

Answers

Answer:

R_cm = 4.66 10⁶ m

Explanation:

The important concept of mass center defined by

         R_cm = 1 / M   ∑  x_i m_i

where M is the total mass, x_i and m_i are the position and masses of each body

Let's apply this expression to our case.

Let's set a reference frame where the axis points from the center of the Earth to the Moon,

       R_cm = 1 / M (m_earth 0 + m_moon d)

the total mass is

      M = m_earth + m_moon

     

the distance from the Earth is zero because all mass can be considered to be at its gravimetric center

let's calculate

      M = 5.98 10²⁴ + 7.35 10²²

      M = 6.0535 10₂⁴24 kg

we substitute

      R_cm = 1 / 6.0535 10²⁴ (0 + 7.35 10²² 3.84 )

      R_cm = 4.66 10⁶ m

Question 13 of 25
Which of the following best describes the function of an electric motor?
29
о A. Converts stored potential energy into mechanical energy
B. Converts mechanical energy into electrical energy
о C. Converts electric energy into mechanical energy
D. Converts the voltage of an alternating current source
SUB

Answers

An electric motor converts electric energy into mechanical energy. So, the right option is C.

In contrast to an electric generator, an electric motor transforms electrical energy into mechanical energy.

They function according to electromagnetism's principles, which demonstrate that a magnetic field's electric current exerts a force.

In the magnetic field, this force produces a torque that spins a loop of wire, causing the motor to function.

Fans, power tools, appliances, electric vehicles, and hybrid vehicles are just a few examples of the many uses for electric motors.

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A 15 kg box is pushed with a force of 35 N in the +x direction, and the box accelerates to the right. It does not accelerate up or down

Answers

The box accelerates to the right due to the applied force of 35 N in the +x direction.

Newton's second law states that the acceleration of an object is directly proportional to the net force applied to it and inversely proportional to its mass. In this case, the net force acting on the box is 35 N in the +x direction, and its mass is 15 kg. Therefore, we can calculate the acceleration using the formula:

acceleration = net force / mass

acceleration = 35 N / 15 kg = 2.33 m/s² (rounded to two decimal places)

Since the box is not accelerating up or down, we can conclude that the force applied is only causing the box to accelerate in the horizontal direction.

Other forces such as gravity and friction are not considered in this scenario. Thus, the 15 kg box will experience an acceleration of approximately 2.33 m/s² in the +x direction due to the applied force of 35 N.

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The centripetal force is proportional to the _____. mass velocity squared inverse of the radius All of the above

Answers

Answer:

Velocity squared.

Explanation:

We know that,

\(\text{F}_{\text{Centripetal}} = \dfrac{mv^2}{r}, \text{which implies} ~\text{F}_{\text{Centripetal}} \propto v^2\)

in a typical cop movie we see the hero pulling a gun firing that gun straight up into the air and shouting

Answers

It is not recommended to fire a gun straight up into the air.

When a bullet is fired into the air, it will eventually come down and can pose a danger to people and property below. The bullet can still be lethal when it reaches the ground, especially if it lands on a hard surface or hits someone directly.

Additionally, firing a gun in a residential area can be illegal and can result in legal consequences. In general, guns should only be fired in designated shooting ranges or in self-defense situations where there is an immediate threat to life. It is important to handle firearms responsibly and follow all safety guidelines to prevent accidents and injuries.

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Walking down a pebble beach becomes less painful as you enter the sea. Explain why.

Answers

Answer:Since pressure = force/area, the same force on a smaller area means more pressure. When you are walking on sand, the force being applied by your body is spread out over the entire surface of your foot. ... So, more pressure applied on a given area of your foot causes more pain.

Explanation:

Good Question

If a racecar traveling at 6 m/s accelerates at 0.75 m/s over 30 seconds, what is itsfinal velocity?

Answers

We are given the initial velocity and the acceleration of a moving object and we are asked to determine its final velocity after 30 seconds. To do that we will use the following equation of movement:

\(v_f=v_0+at\)

Where "vf" is the final velocity, "v0" is the initial velocity, "a" is the acceleration and "t" is time. Replacing the given values:

\(v_f=6\frac{m}{s}+0.75\frac{m}{s^2}\times30s\)

Solving the operations:

\(\begin{gathered} v_f=6\frac{m}{s}+22.5\frac{m}{s} \\ v_f=28.5\text{ m/s} \end{gathered}\)

Therefore, the final velocity is 28.5 meters per second.

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