Which has a greater atomic radius Calcium or Iron?
Iron has a greater atomic radius than calcium.
This comes from the fact that Iron has more electrons, this in turns means that the it has more shells and then the distance between its nucleos to the outer shells is greater.
ROY G BIV is an acronym for what? What part of the EMR spectrum does it refer to?
Answer:
ROYGBIV or Roy G. Biv is an acronym for the sequence of hues commonly described as making up a rainbow: red, orange, yellow, green, blue, indigo and violet. The initialism is sometimes referred to in reverse order, as VIBGYOR.
1. Write two important precautions that you took during the connected in parallel?
Answer:
1)The connection should be tight.
2)The wire should be connected at the terminals not in between.
3)clean the ends of the wire by sandpaper.
4)Take the voltmeter and ammeter in proper range.
5)The rheostat should be used of low resistant(about 100).
The A has a mean lifetime of 26 10-10s and decays into p + e- + ve with a branching fraction of 83 10-4. The A+ (udc) has a mean lifetime of 2-1 10-13s. Estimate the branching fraction of the A into A+e+ +ve, comment on how your result compares with the measured value. [m()=2285GeV/c2BR(e+ve)=(2106)%]
The mean lifetime of A is given by τ(A) = 26 × 10⁻¹⁰ s. The A decays into p + e⁻ + ve with a branching fraction of BR(A → p + e⁻ + ve) = 83 × 10⁻⁴.The mean lifetime of A⁺ (udc) is given by τ(A⁺) = 2-1 × 10⁻¹³ s.
The branching fraction of A into A⁺ + e⁺ + ve is given as follows: First, we can calculate the decay constant for A.λ = (1/τ) = (1/26 × 10⁻¹⁰) s⁻¹.The half-life of A is given by t₁/₂ = ln(2) / λ = (ln2 × τ) = 2.667 × 10⁻¹⁰ s. The branching fraction of A → A⁺ + e⁺ + ve is given as follows: BR(A → A⁺ + e⁺ + ve) = 1 - BR(A → p + e⁻ + ve) = 1 - (83 × 10⁻⁴) = 0.99917.
The measured value of the branching fraction of A → A⁺ + e⁺ + ve is BR(e+ve) = 2106 %.This is greater than 100%. Therefore, the value must be a typographical error. The correct percentage is probably 21.06%.The estimated branching fraction of A → A⁺ + e⁺ + ve is 99.917%, which is very close to 100%. This implies that the A mainly decays into A⁺ + e⁺ + ve.
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Two waves travel at the same speed. the frequency of wave a is 1000 hz, and the frequency of wave b is 4000 hz. wavelength a is:________
the wavelength of wave a is equal to the speed of the wave divided by its frequency, or λ_wave a = v / 1000 Hz.
The speed of a wave is given by the equation:
v = f * λ
where v is the speed of the wave, f is the frequency of the wave, and λ is the wavelength of the wave.
Since the two waves are traveling at the same speed, their speed is constant, and we can set their speed equal to each other:
v_wave a = v_wave b
We know the frequencies of the waves, so we can use the above equation to find their wavelengths:
v = f * λ
λ_wave a = v_wave a / f_wave a
λ_wave a = v_wave b / f_wave b
Substituting the given values, we get:
λ_wave a = v / f_wave a
λ_wave a = v / 1000 Hz
The complete question is:
Two waves travel at the same speed. the frequency of wave a is 1000 hz, and the frequency of wave b is 4000 hz. wavelength a is:________
a v / 8000 Hz
b v / 2000 Hz
c v / 1000 Hz
d v / 9000 Hz
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A young girl jumps off the edge of a shopping trolley. The trolley is stationary at the moment the girl jumps. The girl jumps backwards. Describe and explain, using the idea of momentum, what happens when the girl jumps off the trolley.
Answer:
Momentum is a physical quantity equal to the product of mass of the object and its velocity. Since velocity is a vector (a quantity that has both magnitude and direction), momentum is a vector quantity as well. According to the law of conservation of momentum, the momentum is always conserved. This means that the initial momentum must be equal to the final momentum. Our initial momentum is zero since both, trolly and the girl on it are stationary. When the girl jumps, she has some velocity v. To compensate for that, the trolly will also move with some velocity v, but in the opposite direction so that the momentum stays conserved.
Explanation:
A 20 n object is placed on a surface and starts to slide. What is the most likely reason the object begins to move?.
An external force exceeding the maximum static friction between the object and the surface is the likely reason for the object to start moving. This force could be from various sources.
The most likely reason the object begins to move is that a force is acting on it, overcoming the static friction between the object and the surface.
Static friction is the force that keeps the object at rest, but once the force acting on the object exceeds the maximum static friction, the object starts to move.
The force could come from various sources, such as an external push or pull, the force of gravity if the surface is inclined, or the force of air resistance if the object is moving through the air.
The coefficient of static friction between the object and the surface is also an important factor in determining the maximum static friction that can be exerted before the object starts to move.
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A father fashions a swing for his children out of a long rope that he fastens to the limb of a tall tree. As one of the children swings from this rope that is 5.70 m long, his tangential speed at the bottom of the swing is 9.10 m/s.What is the centripetal acceleration, in m/s2, of the child at the bottom of the swing?
Given,
The length is r=5.70 m
The tangential speed is r=9.10 m/s
The centripetal acceleration is:
\(\begin{gathered} a=\frac{v^2}{r} \\ \Rightarrow a=\frac{9.10^2}{5.70} \\ \Rightarrow a=\frac{14.52m}{s^2} \end{gathered}\)The acceleration is:
\(a=14.52m/s^2\)The isotope 56
26Fe
decays into the isotope
56
27 Co.
By what process will this decay occur?
1. +
2. None of these
3. 4. ?
5.
The correct option is 4.
The process by which the isotope 56Fe decays into the isotope 56Co is beta decay.
The correct option is 4.What is beta decay? Beta decay is a type of radioactive decay in which a beta particle, a positron, or an electron is emitted by the nucleus of an atom. Beta decay is a decay process in which the atomic nucleus emits beta particles, which are high-energy, high-speed electrons or positrons.
In beta decay, a neutron in the nucleus transforms into a proton, causing the emission of an electron and a neutrino in the process. The isotope 56Fe decays into the isotope 56Co by the following beta decay process:56Fe26 → 56Co27 + β−where β- is a beta particle, and it is emitted from the nucleus, resulting in an increase in atomic number Z by one, while atomic mass number A remains unchanged. The daughter isotope is 56Co.
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What is the acceleration of a vehicle that changes its velocity from 100 km/h to a dead stop in 30 s ? Answer in units of m/s 2 .
Answer:
a = \(-\frac{25}{27}\) m/s²
Explanation:
Acceleration (a) = (final velocity - initial velocity) ÷ (final time - initial time) = \(\frac{v_{f} - v_{i} }{t_{f} - t_{i} }\)
Converting the speed from km/h to m/s;
100 km = 100000m
1hr = 3600s
∴ 100km/hr ⇄ \(\frac{100000 m}{3600 s}\) = \(\frac{250}{9} m/s\)
Acceleration = \(\frac{0 - 250/9}{30}\) = \(-\frac{250}{9 * 30} = -\frac{25}{27}\) m/s²
i.e deceleration = \(\frac{25}{27}\) m/s²
Which term does the phrase "an explanation of a natural phenomenon that is supported by facts gathered from many scientific investigations" best describe?
From what we know, we can confirm that the phrase in the question best describes the term "Theory".
Why does this describe the word "Theory"?We can say that this is the exact definition of a theory. In other words, a theory is an idea or hypothesis proposed as a possible solution to a known problem, which is backed up by facts and conclusions derived from many scientific experiments and investigations.
Therefore, we can confirm that the phrase in the question best describes the term "Theory".
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How can the efficiency of a simple machine be increased?
Answer:
Reduce friction
which wave has a wave length that is most likely seen as red light
Answer:
Explanation:
Red light has longer waves, with wavelengths around 620 to 750 nm.
A radio wave has a frequency of 5.5 × 104 hertz and travels at a speed of 3.0 × 108 meters/second. What is its wavelength?
Answer:5.45X10^3m
Explanation:So use the formula,v= fλ
3X10^8=5.5X10^4λ what Im saying is divide both and u should get 5454.54m but do sig figs to get answer
Answer:
5.45X10^3m
Explanation:
An Object with a mass o 5.13kg placed on top of a spring compresses it by 0.25m (a) what is the force constant of the spring (b) How high will this object go when the spring releases its energy?
The force constant of the spring is 200.696 N/m & The height the object achieves when the spring releases its energy is 2.5087 m
The spring constant is the force needed to stretch or compress a spring, divided by the compressive or expansive distance. It's used to determine stability or instability in the spring, and therefore the system it's intended for. we know,
F = kx
Therefore,
k = F/x
We also know that the force being exerted on the spring is equal to the mass of the object. Hence, F = mg = 5.13 * 9.8 N = 50.174 N and we know compression due to the mass is 0.25m. Therefore,
K = 50.174/0.25 N/m
K = 200.696 N/m
Therefore, The Spring Constant is 200.696 N/m
On release, the spring potential energy gets converted to kinetic energy. Hence, on release, the height attained by the object is given by:
h = \(1/2 kx^{2}\)
We know that k=200.696 N/m and x=0.25 m. Therefore the height is:
h = \(1/2 (200.696 N/m)(0.25 m)^{2}\)
h = 2.5087 m
Therefore, the force constant of the spring is 200.696 N/m & The height the object achieves when the spring releases its energy is 2.5087 m
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How much energy (in kWh) can you get from a 72 cell solar panel in one year?
George walks to a friend's house. He walks 750 meters North, then realizes he walked
too far. He turns around and walks 250 meters South. The entire walk takes him 13
seconds.
Answer:
I think you are looking for the velocity, so the answer is 38.5 m/s
Explanation:
Velocity is giving by displacement/time. North will be positive and South will be negative, George travels 750 meters then travels -250 meters his displacement is then 750 - 250 or 500 meters. Divide that by 13 seconds to get 38.5 m/s.
1. (T4 ) A basketball and a bowling ball are dropped at the same time from the same height. The bowling ball has three times the mass of the basketball. How will their falling times compare? Ignore air resistance. *
1 point
A. The basketball will reach the ground three times faster
B. The bowling ball will reach the ground three times faster
C. The bowling ball will reach the ground nine times faster
D. The two balls will hit the ground at the same time
Answer:
d
Explanation:
mass and weight do not effect how fast a object falls
When Apollo 15 astronaut David Scott did his famous freefall experiment on the Moon, he dropped a falcon feather from a height of about 1.6 meters. Assuming a gravitational acceleration of 1.6 m/s2 on the Moon, about how long did it take the feather to drop to the surface?
The time taken for the feather to drop to the surface, given that the gravitational acceleration is 1.6 m/s², is 1.4 s
How do I determine the time?From motion under gravity, we understood that height and time are related according to the follwing formula:
h = ½gt²
Where
h is the heightg is the acceleration due to gravityt is the timeUsing the above formula, we can obtain the time taken for the feather to drop to the surface. Details below:
Height (h) = 1.6 metersGravitational acceleration (g) = 1.6 m/s²Time taken (t) = ?h = ½gt²
1.6 = ½ × 1.6 × t²
1.6 = 0.8 × t²
Divide both side by 0.8
t² = 1.6 / 0.8
Take the square root of both side
t = √(1.6 / 0.8)
t = 1.4 s
Thus, the time take is 1.4 s
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A gymnast balancing on a beam will put her arms out. Why does this help?
By keeping their centre of gravity over the beam, a gymnast may balance himself. The gymnast increases their moment of inertia, or resistance to rotational motion, by spreading their arms out to the sides, making it harder to unintentionally tilt or spin. As a result, their body is more stable, aiding in balance maintenance. Moreover, the centre of mass can be slightly adjusted with the arm movements to make up for any minor deviations from the equilibrium position. The gymnast can also orient oneself in relation to the beam using the visual clues provided by the arms. Overall, while balancing on a beam, a gymnast can gain various advantages from extending their arms to the side, including increased stability and many more.
Please awnser as fast as you can, I will give 30 points.
Why is there wind on mars and how is there wind on mars?
Answer:
Because the atmosphere is so thin, high wind velocities are needed to move sand and dust.
What is the proper unit for gravitational potential energy?Question 16 options:gravitonsjoulesnewtonsmeters
Answer:
Joules
Explanation:
The unit for Energy is Joules, which is equal to kg m²/s².
The gravitational potential energy is calculated as:
\(Ep=\text{mgh}\)Where m is mass (kg), g is gravity (m/s²) and h is the height (m). So, the unit of the potential energy is:
\(kg\cdot\frac{m}{s^2}\cdot m=kg\cdot\frac{m^2}{s^2}=\text{Joules}\)Therefore, the answer is joules.
What is a wiggle in time called?
A spring of k=500 N/m that is initially compressed 2m is used to launch a 100N load of bricks up a 2 m tall
hill. Find the speed of the bricks at the top of the hill.
a. Qualitatively complete the energy flow diagram and the energy bar graphs.
c. Determine the speed
e. What would the speed at the top of the hill be with 2m of initial compression if 15% of the energy is
dissipated through friction?
d. What is the minimum compression of the spring necessary to get to the top of the hill? (v=0 at top, no
friction)
Speed of the bricks at the top of hill is 6.26 m/s. c.)speed of the bricks at the top of hill is 14.14 m/s. d)minimum compression of spring necessary to get to the top of hill is 6.26 m. e) speed of the bricks at the top of hill with 2 m of initial compression and 15% energy dissipation is 13.04 m/s.
What is energy?The capacity or power to do work, such as the capacity to move an object by application of force is called energy.
Initial potential energy of compressed spring is:
Ep = 1/2 kx^2 = 1/2 * 500 N/m * (2 m)^2 = 1000 J
k is spring constant, x is compression of the spring, and J is unit of energy in joules.
Final potential energy of the bricks is:
Ep = mgh = 100 N * 9.81 m/s^2 * 2 m = 1962 J
Ep = Ep
1/2 kx^2 = mgh
v = sqrt(2gh) = sqrt(2 * 9.81 m/s^2 * 2 m) = 6.26 m/s
Therefore, the speed of the bricks at the top of the hill is 6.26 m/s.
c. Initial potential energy of compressed spring is: 1000 J
Ek = Ep = 1000 J
Kinetic energy of the bricks is given by:
Ek = 1/2 mv^2
1000 J = 1/2 * 100 N * v^2
v = sqrt(200 / 1) = 14.14 m/s
Therefore, the speed of the bricks at the top of the hill is 14.14 m/s.
d. As, Ep = m g h
where m is mass of the bricks, g is acceleration due to gravity, and h is height of the hill.
Ep = 100 N * 9.81 m/s^2 * 2 m = 1962 J
Ep = 1/2 kx^2 = 1962 J
1/2 * 500 N/m * x^2 = 1962 J
x = sqrt(2 * 1962 J / 500 N/m) = 6.26 m
Therefore, the minimum compression of the spring necessary to get to the top of the hill is 6.26 m.
e. If 15% of the energy is dissipated through friction, final kinetic energy of the bricks at the top of the hill will be 85% of initial potential energy of the compressed spring. Therefore,
0.85 * 1000 J = 1/2 mv^2
v = sqrt(170 / 1) = 13.04 m/s
Therefore, the speed of the bricks at the top of the hill with 2 m of initial compression and 15% energy dissipation is 13.04 m/s.
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a block of mass 0.259 kg is placed on top of a light, vertical spring of force constant 4 975 n/m and pushed downward so that the spring is compressed by 0.099 m. after the block is released from rest, it travels upward and then leaves the spring. to what maximum height above the point of release does it rise? (round your answer to two decimal places.)
The block rises to a maximum height of 9.98 m above the point of release.
The maximum height above the point of release to which the block rises after it is released from rest can be calculated as follows:
Step 1: Determine the potential energy stored in the spring U = 1/2 kx² Where, U is the potential energy of the spring, k is the force constant, and x is the compression in meters U = 1/2 × 4975 N/m × (0.099 m)²U = 24.52 J
Step 2: The potential energy stored in the spring is converted into kinetic energy, which is then converted into gravitational potential energy.
Thus, U = K.E. = 1/2 mv²Where, K.E. is the kinetic energy of the block, m is the mass of the block, and v is the velocity of the block just after leaving the spring. Rearrange the above formula to calculate the velocity of the block as it leaves the spring: v = √(2U/m)v = √[2(24.52 J)/0.259 kg]v = 5.60 m/s
Step 3: At the maximum height above the point of release, the block has zero kinetic energy and a maximum potential energy. Thus, the gravitational potential energy of the block can be calculated as follows: mgh = U
Where, m is the mass of the block, g is the acceleration due to gravity, h is the maximum height above the point of release, and U is the potential energy stored in the spring. h = U/mg= U/(mg) = (24.52 J)/(0.259 kg × 9.81 m/s²)h = 9.98 m
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If the magnitude of the acceleration of a propeller blade's tip exceeds a certain value amax, the blade tip will fracture. If the propeller has radius r, is initially at rest, and has angular acceleration of magnitude α, at what angular speed ω will the blade tip fracture?
The angular speed at which the propeller blade's tip will fracture is given by ω = √(2(amax / r)s), where amax is the maximum acceleration, r is the radius, and s is the linear displacement of the blade tip.
To determine the angular speed at which the blade tip will fracture, we need to consider the relationship between angular acceleration, angular speed, and radius.
The angular acceleration of the propeller blade can be expressed as:
α = (ω^2 - ω₀^2) / (2θ)
where α is the angular acceleration, ω is the final angular speed, ω₀ is the initial angular speed (which is zero in this case since the propeller is initially at rest), and θ is the angle through which the blade rotates.
If the magnitude of the acceleration at the blade tip exceeds a certain value amax, then we can set α equal to amax:
amax = (ω^2 - 0) / (2θ)
Simplifying the equation, we get:
2θamax = ω^2
Now, we need to consider the relationship between the angular displacement θ and the radius r. The angular displacement can be expressed as:
θ = s / r
where s is the linear displacement of the blade tip.
Substituting θ in terms of s/r in the previous equation, we get:
2(amax / r)s = ω^2
Simplifying further:
ω = √(2(amax / r)s)
Therefore, the angular speed at which the blade tip will fracture is given by the equation:
ω = √(2(amax / r)s)
It's important to note that the exact value of s, the linear displacement of the blade tip, would depend on the specific conditions and characteristics of the propeller system.
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What is the mass of a dog if it accelerates at 15 m/s^2 and has a force of 50 N?
Answer:
3.33kg
Explanation:
Force=mass×acceleration
Force=50N
Acceleration=15m/s^2
50=m×15
50=15m
50/15=15m/15
3.33=m
Therefore the mass is 3.33kg
if an object orbits the sun at an average distance of 32 AU
(astronomical units), what would its orbital period be in Earth
years?
If an object orbits the Sun at an average distance of 32 astronomical units (AU), the question is asking for the orbital period of this object in Earth years.
The orbital period of a planet or any object orbiting the Sun can be determined using Kepler's Third Law of Planetary Motion. According to Kepler's Third Law, the square of the orbital period is directly proportional to the cube of the semi-major axis of the orbit.
In this case, the average distance of the object's orbit is given as 32 AU. The semi-major axis of an elliptical orbit is equal to the average distance, so we can consider the semi-major axis as 32 AU.
Using the relationship from Kepler's Third Law, we can set up the following equation:
(T₁ / T₂)² = (a₁ / a₂)³
Letting T₁ represent the orbital period in Earth years and a₁ represent the average distance in AU, we have:
(T₁ / 1 year)² = (32 AU / 1 AU)³
Simplifying the equation, we find:
(T₁ / 1)² = 32³
T₁² = 32³
Taking the square root of both sides, we get:
T₁ = √(32³)
Calculating the value, the orbital period in Earth years would be approximately 165.77 years.
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A certain circuit breaker trips when the rms current is 12.0 a. what is the corresponding peak current (in a)?
Required the corresponding peak current is 16.97 A.
The corresponding peak current can be calculated using the formula Ipeak = Irms * √2. Therefore, the peak current for a circuit breaker that trips at 12.0 A
RMS current would be Ipeak = 12.0 * √2 = 16.97 A (rounded to two decimal places). It's important to note that peak current represents the maximum instantaneous current that a circuit can handle, while RMS current represents the equivalent heating effect of a steady DC current. In other words, a circuit breaker is designed to protect against overloading caused by peak currents, which can be higher than the corresponding RMS current.
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The free-body diagram below represents a 12.0 kg wagon being pulled across a yard with a 2 N force that forms a 40.0° angle with the horizontal.
calculate the magnitude of the wagons horizontal acceleration.
→ The magnitude of the wagons horizontal acceleration is 8.5755 m/s².
First, apply the Second Law of Newton in the 'y' direction. Note: The P force has a component in the axis, it is Psin(40)! Therefore:
\(\Large \text {$N + Psin(40) = W$}\\\\\Large \text {$N + 2N \times sin(40) = m \times g$}\\\\\Large \text {$N(1+ \times 2sin(40)) = m \times g$}\\\\\Large \text {$ \sf N = \dfrac {12 \times 9.8}{1+2sin(40)} = 51.453 $ N}\)
So, in the X direction:
\(\Large \text {$m \times a = 2N \times cos(40)$}\\\\\Large \text {$ \sf a = \dfrac {2 \times 51.453}{12} = 8.5755 m/s^2$}\)
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