Answers
Answer:
\(v_B=3.78\times 10^5\ m/s\)
Explanation:
It is given that,
Charge on helium nucleus is 2e and its mass is \(6.63\times 10^{-27}\ kg\)
Speed of nucleus at A is \(v_A=6.2\times 10^5\ m/s\)
Potential at point A, \(V_A=1.5\times 10^3\ V\)
Potential at point B, \(V_B=4\times 10^3\ V\)
We need to find the speed at point B on the circle. It is based on the concept of conservation of energy such that :
increase in kinetic energy = increase in potential×charge
\(\dfrac{1}{2}m(v_A^2-v_B^2)=(V_B-V_A)q\\\\\dfrac{1}{2}m(v_A^2-v_B^2)={(4\times 10^3-1.5\times 10^3)}\times 2\times 1.6\times 10^{-19}=8\times 10^{-16}\\\\v_A^2-v_B^2=\dfrac{2\times 8\times 10^{-16}}{6.63\times 10^{-27}}\\\\v_A^2-v_B^2=2.41\times 10^{11}\\\\v_B^2=(6.2\times 10^5)^2-2.41\times 10^{11}\\\\v_B=3.78\times 10^5\ m/s\)
So, the speed at point B is \(3.78\times 10^5\ m/s\).
Related Questions
A bullet is fired horizontally at a height of 2 meters at a velocity of 930 m/s. Assume no air resistance. How far did the bullet travel horizontally when it hit the ground?
595.2 m
478.4 m
364.0 m
247.2 m
Answers
Answer:
im pretty sure its a
Explanation:
Question 16 of 17
Figure (a) shows a wire that forms a rectangle (W = 23.0cm, H = 31.0cm) and has a resistance of 4.00 mOhm. Its interior is split into three equal areas, with magnetic fields B₁, B₂, and B. The fields are uniform within each region and directly out of or into the page as indicated. Figure (b) gives the change in the z components B, of the three fields with time t; the vertical axis scale is set by B, = 3.00 μT
and B-2.50B, What are the
(a) the magnitude and
(b) direction of the current induced in the wire?
Answers
For the magnetic fields:
(a) 53.8 A(b) The induced current will flow counterclockwise.How to determine magnitude and direction?From Faraday's law of electromagnetic induction, the emf induced in the wire is given by:
emf = -dΦ/dt
where Φ is the magnetic flux through the wire. The negative sign indicates that the induced emf opposes the change in magnetic flux.
The magnetic flux through each of the three regions can be calculated as follows:
Φ₁ = B₁WH/3
Φ₂ = B₂WH/3
Φ₃ = BWH/3
The total magnetic flux through the wire is:
Φ = Φ₁ + Φ₂ + Φ₃ = (B₁ + B₂ + B)WH/3
Taking the time derivative of the magnetic flux:
dΦ/dt = (B₁ + B₂ + B)(WH/3)(dB/dt)
Substituting the given values:
dΦ/dt = (3.00 μT + 2.50(3.00 μT))(0.23 m)(0.31 m)(1.00 m)/(3)(0.010 s) = 0.215 V
The induced emf is equal to the product of the current and the resistance of the wire:
emf = IR
Solving for I:
I = emf/R = 0.215 V / 4.00 mΩ = 53.8 A
The direction of the induced current can be determined using Lenz's law, which states that the direction of the induced current is such that it opposes the change in magnetic flux that produced it. In this case, the induced current will produce a magnetic field that opposes the change in the magnetic field through the wire.
As the magnetic field increases in the downward direction, the induced current will produce a magnetic field in the upward direction to oppose the increase. As the magnetic field decreases in the downward direction, the induced current will produce a magnetic field in the downward direction to oppose the decrease.
Therefore, the direction of the induced current will be counterclockwise.
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Think of a person standing still at the end of a diving board, getting ready to make a dive into a pool. When the diver is ready, the diver will make 3 small jumps on the diving board, and then dive into the water. Where is the amount of potential energy increasing? Where is the amount of potential energy decreasing and the amount of kinetic energy increasing? Where are the points of maximum kinetic energy? Where are the points of maximum potential energy?
Answers
Answer:
The amount of potential energy is increasing when they jump on the board. The amount of potential energy is decreasing and the amount of kinetic energy is increasing when they are falling towards the water. The point of maximum kinetic energy is right before they splash into the water. The point of maximum potential energy is when they jump the highest into the air.
Explanation:
The points of maximum potential energy when they jump highest into the air, their potential energy is at its highest.
What is potential energy?Potential energy develops in systems where the configuration, or relative position of the pieces, determines the amount of the forces they exert on one another. Potential energy directly proportional to height of object higher the object higher the potential energy with respect to same reference point.
When they jump onto the board, potential energy is building. When they are descending toward the sea, their potential energy is dwindling and their kinetic energy is rising. Just before they splash into the water is when they have the most kinetic energy. When they jump highest into the air, their potential energy is at its highest.
Potential energy is highest at its highest point of jump.
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What is the correct definition of a resistor?
A) the difference in electric charge between two points
B) a substance capable of transmitting and creating an electric charge
C) a component that resists the flow of electricity
D) a device that allows electrical energy to flow through a complete path
Answers
A cube has a mass of 100 grams and its density is determined to be 1 g/cm3. The volume of the cube must be _____. 0.1 cm3 1 cm3 10 cm3 100 cm3
Answers
Answer: The volume of the block will be \(100cm^3\)
Explanation:
Density is defined as the mass contained per unit volume.
\(Density=\frac{mass}{volume}\)
Given : Mass of cube = 100 grams
Density of cube = \(1g/cm^3\)
Putting in the values we get:
\(Volume=\frac{mass}{density}\)
\(Volume=\frac{100g}{1g/cm^3}=100cm^3\)
Thus volume of the block will be \(100cm^3\)
A 17-kg
piece of metal displaces 2.8 L
of water when submerged. what is its density?
Answers
Answer: Density = 6071.428571 kg/m³
Explanation: Given that mass m=17 kg
volume displaced v=2.8L
We know that
density = mass/volume
Here density=17kg/2.8L
Also 1L=1000m³ Hence
density=17kg/2.8×10⁻³m³
=6071.428571 kg/m³
Hello anyone have the answer for Newton's Third Law of Motion
Answers
Newton's Third Law of Motion states that for every reaction, there is always an equal but an opposite reaction.
Newton's law is proposed by Sir Isaac Newton. He is an English physicist and he proposed three laws of motion.
The first law of motionThe second law of motionThe third law of motionNewton's Third Law of Motion states that for every reaction, there is always an equal but an opposite reaction.
Examples of Newton's Third Law of Motion are:
Rowing a boatAttraction of paper clip to a magnetRecoil of a gunLearn more about Newton's law here:
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A 2000 kg car moves at a speed of 30 m/s. To reach this speed, it was necessary to burn 0.1 l of gas. Burning gas provides 30 MJ/l of source energy. Determine the energy efficiency (in %) of this car.
Answers
The energy efficiency of the car is approximately 16.7%.
The energy efficiency of a car is the ratio of the useful work output (in this case, the kinetic energy of the car) to the total energy input (in this case, the energy released by burning the gasoline). The equation for energy efficiency is:
Efficiency = Useful work output / Total energy inputThe useful work output can be calculated as the kinetic energy of the car using the equation:
KE = 0.5mv²where m is the mass of the car and v is its velocity.
Substituting the given values:
KE = 0.5 x 2000 kg x (30 m/s)² = 900,000 JThe total energy input is the energy released by burning 0.1 L of gasoline, which is:
Total energy input = 0.1 L x 30 MJ/L = 3 MJ = 3,000,000 JSubstituting these values into the equation for efficiency:
Efficiency = (900,000 J / 3,000,000 J) x 100% = 0.3 x 100% = 16.7%Therefore, the energy efficiency of the car is approximately 16.7%.
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what type of image is formed by a lens if m = -4.6? A. One that is larger than the object and virtual, B. One that is smaller than the object and virtual, C. One that is larger then the object and real, D. One that is smaller than the object and real
Answers
Answer:
One that is larger than the object and real
Explanation:
A student has two balloons attached to strings and rubs each balloon on one of two different materials. The student wants to know whether or not the balloons have the same sign charge. Which of the following procedures will provide enough information while ensuring the net charge on the balloons is not affected? Select two answers. А. Touching the balloons to each other and observing whether they stick together B. Suspending the balloons near each other and observing which way they deflect C. Suspending each balloon near the material it was not rubbed on and seeing which way it deflects D. Touching each balloon to the material it was not rubbed on and observing whether they stick together
Answers
Suspending the balloons near each other and observing which way they deflect
Suspending each balloon near the material it was not rubbed on and seeing which way it deflects
Can an object be charged by friction?An object can be charged by friction. When two objects are rubbed against each other, electrons can be transferred from one object to the other, resulting in one object becoming positively charged and the other becoming negatively charged. This is known as the triboelectric effect.
We know that if the objects do have the same charge then they will deflect away from each other but towards each other if they have opposite charges.
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A 0.21 kg apple falls from a tree to the ground 4.0m below. Ignoring air resistance, determine the apple's kinetic energy, the gravitational potential energy, and the total mechanical energy of the system when the apple’s height above the ground is 3.0m.
Answers
Given :
Mass of the apple (m): 0.21 kgHeight of the apple above the ground at the start (initial height) (h1): 4.0 mHeight of the apple above the ground at the end (final height) (h2): 3.0 mAcceleration due to gravity (g): 9.81 m/s^2To Find :
The falling apple's kinetic energy, gravitational potential energy, and total mechanical energy.
Solution :
We can use the conservation of energy principle to find the apple's kinetic energy, gravitational potential energy, and total mechanical energy at the height of 3.0m above the ground.
First, we need to find the gravitational potential energy (GPE) of the apple when it is at the height of 4.0m above the ground:
GPE = mgh
where m is the mass of the apple, g is the acceleration due to gravity (9.81 m/s^2), and h is the height above the ground.
So, GPE = (0.21 kg) x (9.81 m/s^2) x (4.0 m) = 8.2266 J
Next, we find the apple's kinetic energy (KE) just before it hits the ground. We can use the conservation of energy principle, "which states that a system's total mechanical energy is conserved (i.e., it remains constant) if no external forces are acting on it." In this case, gravity is the only force acting on the apple, an internal force within the system (i.e., the apple and the Earth).
So, at the height of 3.0m above the ground, the total mechanical energy (TME) of the system is:
TME = GPE + KE
Since the apple is falling freely, we can assume that all of its potential energy at the height of 4.0m has been converted into kinetic energy just before it hits the ground. Therefore, at the height of 3.0m above the ground, the GPE is:
GPE = (0.21 kg) x (9.81 m/s^2) x (3.0 m) = 6.1359 J
Using the conservation of energy principle, we can find the kinetic energy just before the apple hits the ground:
TME = GPE + KE
KE = TME - GPE = (0.21 kg) x (9.81 m/s^2) x (4.0 m) - 6.1359 J = 2.0907 J
Therefore, the kinetic energy of the apple just before it hits the ground is 2.0907 J.
To summarize:
Gravitational potential energy (GPE) of the apple at a height of 4.0m above the ground: 8.2266 J
Gravitational potential energy (GPE) of the apple at a height of 3.0m above the ground: 6.1359 J
Kinetic energy (KE) of the apple just before it hits the ground: 2.0907 J
The system's total mechanical energy (TME) is conserved throughout the fall.
a spring has a constant of 80 N/m. How much energy is stored in the spring when it is compressed 0.2 m past its natural length?
Answers
The amount of energy stored in the spring, given it has a spring constant of 80 N/m is 1.6 Joules
How to determine the energy stored in the springFirst, we shall list out the given parameters from the question. This is shown below:
Spring constant (K) = 80 N/mCompression (e) = 0.2 mEnergy stored (E) = ?The energy stored in the spring, given the above data can be obtained as follow:
E = ½Ke²
E = ½ × 80 × 0.2²
E = 40 × 0.04
E = 1.6 Joules
Thus, from the above calculation, we can conclude that the energy stored is 1.6 Joules
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A mass that has a force of the 10N to the right, 7N up, 3N down, and 4N to the left. What is the net external force on that mass? If the mass is 2kg find the acceleration.
Answers
acceleration = 7.2 / 2 = 3.6 m/s^2
At the moment when a shot putter releases a 5.00kg shot, the shot is 3.00m above the ground and traveling at 15.0m/s. It reaches a maximum height of 14.5m above the ground and then falls to the ground. If air resistance is negligible, what was the potential energy of the shot as it left the hand relative to the ground?
Answers
The potential energy of the shot as it left the hand relative to the ground would be -524 J.
Potential energy calculationAt the moment the shot putter releases the shot, the total energy of the system is:
E = KE + PE
where KE is the kinetic energy of the shot and PE is its potential energy relative to the ground. We can assume that the kinetic energy is entirely due to the motion of the shot in the horizontal direction, so we can write:
KE = (1/2)mv^2
where m is the mass of the shot, and v is its horizontal velocity. Substituting the known values, we get:
KE = (1/2)(5.00 kg)(15.0 m/s)^2 = 1125 J
At the maximum height of 14.5 m, the shot has zero kinetic energy, so all its energy is potential energy:
PE = mgh
where g is the acceleration due to gravity and h is the height above the ground. Substituting the known values, we get:
PE = (5.00 kg)(9.81 m/s^2)(14.5 m - 3.00 m) = 601 J
Therefore, the potential energy of the shot as it left the hand relative to the ground was:
PE = E - KE = 601 J - 1125 J = -524 J
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The resistance RT of a platinum varies with temperature T(°C), as measured on the constant-volume gas thermometer according to the equation RT = Ro(1+AT+BT^2). Where A = 3.8×10^-3°C^-1 and B = -5.6×10^-7°C^-2. Calculate the temperature that would be on indicated on a platinum thermometer, when the gas scale reads 200°C.
Answers
The resistance indicated by the platinum thermometer at 200°C is 1.648 times the reference resistance Ro at 0°C.
The given equation is RT = Ro(1+AT+BT²), where A = 3.8×10⁻³°C⁻¹ and B = -5.6×10⁻⁷°C⁻². To determine the temperature that would be indicated on a platinum thermometer when the gas scale reads 200°C, we will have to use the given formula. RT = Ro(1+AT+BT²) .....(i)We know that the gas scale reads 200°C. Therefore, we can substitute T = 200°C in equation (i).RT = Ro (1 + A × 200 + B × 200²) = Ro (1 + 0.76 - 0.112) = Ro (1.648)Thus, the resistance that the platinum thermometer would indicate is 1.648 times the reference resistance Ro at 0°C. This is the solution to the problem.In summary, The given equation is RT = Ro(1+AT+BT²), where A = 3.8×10⁻³°C⁻¹ and B = -5.6×10⁻⁷°C⁻². To determine the temperature that would be indicated on a platinum thermometer when the gas scale reads 200°C, we substituted T = 200°C in equation (i) to get RT = Ro (1 + A × 200 + B × 200²) = Ro (1 + 0.76 - 0.112) = Ro (1.648).For more questions on thermometer
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What three statements are true about the wave shown?
Answers
Calculating percentage using Bernoulli's equation on an aeroplane wing
Answers
Bernoulli's equation can be used to calculate the pressure difference and hence the lift generated by an aeroplane wing.
How is Bernoulli's equation used?The equation is: P + 1/2 × ρ × v² + ρ × g × h = constant
Where P is the pressure, ρ is the density of the fluid (air), v is the velocity of the fluid, g is the acceleration due to gravity, and h is the height.
To calculate the lift generated by an aeroplane wing, we can use the Bernoulli's equation to find the pressure difference between the top and bottom of the wing. The pressure difference creates an upward force, which is the lift.
To find the percentage of the lift generated by an aeroplane wing, use the total weight of the aeroplane and divide the lift by the weight, and then multiply by 100 to get the percentage.
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The complete question is:
Calculating percentage using Bernoulli's equation on an aeroplane wing. Explain!
HELP ASAP!
on the screenshot.
Answers
7-B
8-A
Hope this helps
Suppose a 3000 cm3 container holds 7.0 g of nitrogen gas at a pressure of 200 kPa. The gas can be heated at constant pressure if a piston moves outward to let the gas expand as it's heated. Alternatively, the gas can be heated at constant volume if the piston is locked in place to prevent expansion.
We know starting temperature is 290 K
1, Returning to the starting conditions, the gas is heated but the piston is allowed to move in a way that keeps the pressure constant. What is the final temperature if the gas is heated until the volume doubles?
Answers
1) The temperature at the beginning is 288 K
b)After we doubled the pressure we have, the temperature at 576 K
What is the temperature?The ideal gas equation is the key that is going to help with the temperature of the gas as we can see the parameters in the question clearly shown as follows;
Pressure = 200 kPa or 1.97 atm
Volume = 3000 cm3 or 3 L
Temperature = ?
Moles of the gas = mass/molar mass = 7 g/28 g/mol = 0.25 moles
Thus;
PV = nRT
T = PV/nR
T = 1.97 * 3/0.25 * 0.082
T = 5.91/0.0205
T = 288 K
After the pressure is doubled;
P1/T1 = P2/T2
P1T2 = P2T1
T2 = 2(1.97) * 288/1.97
T2 = 576 K
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Highway safety engineers want to design roadside barriers that will crumple
in the event that a car drives off the road and collides with them, slowing
down the car more gradually. The average person has a mass of 68 kg and
travels on a highway at a velocity of 27 m/s. If the engineers know that the
maximum force that a person can safely withstand is 1650 N, approximately
how much time is required to crumple the barrier to safely slow the person
with this force?
A 1.5s
B. 0.7 s
C. 1.1 s
D. 2.1 s
Answers
The time required to crumple the barrier and safely slow down the person with a force of 1650 N is approximately C, 1.1 seconds.
How to find time?To determine the time required to crumple the barrier and safely slow down the person with a maximum force of 1650 N, use the equation of motion:
F = m × a
where:
F = force
m = mass
a = acceleration
Given:
m = 68 kg
F = 1650 N
Find the acceleration (a) first. Rearranging the equation:
a = F / m
Substituting the values:
a = 1650 N / 68 kg
a ≈ 24.26 m/s²
Now, use the equation of motion to find the time (t):
v = u + at
where:
v = final velocity (0 m/s as the person comes to a stop)
u = initial velocity (27 m/s)
a = acceleration (24.26 m/s²)
t = time
Rearranging the equation:
t = (v - u) / a
Substituting the values:
t = (0 m/s - 27 m/s) / 24.26 m/s²
t ≈ -27 m/s / 24.26 m/s²
t ≈ -1.11 s
The negative sign indicates that the time is in the opposite direction to the initial velocity. Taking the absolute value, the time required to crumple the barrier and safely slow down the person with a force of 1650 N is approximately 1.11 seconds.
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To better understand crash dynamics we have to look at "__________."
A. the law of gravity
B. Bernoulli's principle
C. the laws of motion
D. Archimedes' principle
Answers
To better understand crash dynamics we have to look at "the laws of motion."
The laws of motion
The laws of motion were introduced by Sir Isaac Newton in 1687 in his book Philosophiæ Naturalis Principia Mathematica ("Mathematical Principles of Natural Philosophy"), which defined the laws of motion, or three fundamental laws that govern the movement of bodies. The laws of motion, according to Newton, govern the motion of an object or a system of objects that interact.
It defines the concepts of force and mass, and the fundamental dynamics of motion.The following are the laws of motion:Every object will remain at rest or in uniform motion in a straight line unless compelled to change its state by the action of an external force. The velocity of an object changes proportional to the force applied to it, and the acceleration of an object is proportional to both its force and its mass. For every action, there is an equal and opposite reaction.
Therefore, these laws are necessary to fully grasp crash dynamics because they explain how objects respond to outside forces that cause them to accelerate or decelerate.
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Keyana and Sam are testing the law of conservation of energy. They use the same ball and release it from the same vertical height. Keyana is using a frictionless track, while Sam's track has friction. They discover Keyana's ball had more kinetic energy than Sam's when it reached the bottom. Which statement best explains why this happened if energy is conserved? Sam's ball lost mass as it traveled along the track. Sam's ball interacting with the track converted energy into heat. Keyana's ball was able to gain momentum. Keyana's ball had more potential energy.
Answers
The true statement is "Sam's ball interacting with the track converted energy into heat." The correct option is B.
The law of conservation of energy states that energy cannot be created or destroyed, only transferred or converted from one form to another. This means that the total amount of energy in a closed system remains constant.
The friction between Sam's ball and the track caused some of the energy to be lost as heat, while Keyana's ball experienced no such loss due to the absence of friction in her experiment. Therefore, Keyana's ball retained more of its initial potential energy as kinetic energy, resulting in a greater velocity and hence more kinetic energy at the bottom.
Option A (Sam's ball lost mass as it traveled along the track) is not true because it is not possible for the ball to lose mass during the experiment. The mass of the ball is a constant value and is not affected by the experiment.
Option C (Keyana's ball was able to gain momentum) is not the best explanation because momentum is not conserved in this scenario since external forces like friction are acting on the ball. The ball is only gaining kinetic energy.
Option D (Keyana's ball had more potential energy) is not true because both Keyana and Sam released the ball from the same vertical height. Therefore, both balls had the same initial potential energy. The difference in their kinetic energies at the bottom can be explained by the difference in their conservation of energy due to friction.
Therefore, The correct statement that best explains why Keyana's ball had more kinetic energy than Sam's when it reached the bottom, even though energy is conserved, is: Sam's ball interacting with the track converted energy into heat.
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what is the velocity of a 1.3 kg puppy with a forward momentum of 6 kg m/s
Answers
Answer:
by using p = mv equation we can find v,
6 = 1.3 v
4.615 = v
Object 1 with mass 1=3.25 kg
is held in place on an inclined plane that makes an angle
of 40.0∘
with the horizontal. The coefficient of kinetic friction between the plane and the object is 0.535.
Object 2 with mass 2=4.75 kg
is connected to object 1 with a massless string over a massless, frictionless pulley. The objects are then released.
Calculate the magnitude
of the initial acceleration.
Calculate the magnitude
of the tension in the string once the objects are released.
Answers
The magnitude of the initial acceleration of the object is 4.2 m/s².
The tension in the string once the object starts moving is 13.65 N.
What is the magnitude of the initial acceleration?The magnitude of the initial acceleration of the object is calculated by applying Newton's second law of motion as follows;
F(net) = ma
m₂g - μm₁g cosθ = a(m₁ + m₂)
where;
m₁ and m₂ are the masses of the blocksg is acceleration due to gravityμ is coefficient of frictionθ is the angle of inclinationa is the acceleration(4.75 x 9.8) - (0.535 x 3.25 x 9.8 x cos40) = a(3.25 + 4.75)
33.5 = 8a
a = 33.5/8
a = 4.2 m/s²
The tension in the string once the object starts moving is calculated as;
T = m₁a
T = 3.25 x 4.2
T = 13.65 N
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A periodic wave has a wavelength of 0,50 m and a speed of 20 m/s, What is the wave frequency?
Answers
Answer:
u=speed, w=wavelenght, f=frequency
It's known that u=w*f => f=u/w
u=20m/s ==> f=20/0,5 => f=40 Hz
w=0,50m
Explanation:
A sculpture is suspended in equilibrium by two cables, one from a wall and the other
from the ceiling of a museum gallery. Cable 1 applies a horizontal force to the right of
the sculpture and has a tension, Fn. Catble 2 applies a force upward and to the left at an
angle of 37.0° to the negative x-axis and has a tension, Fn. The gravitational force on
the sculpture is 5.00 '10`N. What is Fn?
Answers
Answer:
\(T_1=6655.295917 \approx 6655.3N\)
Explanation:
From the question we are told that
Angle of cable 2 \(\theta=37.0\textdegree\)
Weight of sculpture \(W=5000 N\)
Generally the Tension from cable 2 \(T_2\) is mathematically given by
\(T_2sin37\textdegree=5000N\)
\(T_2=5000N/sin37\textdegree\)
\(T_2=8308.2N\)
Generally the Tension from Cable 1 \(T_1\) is mathematically given by
\(T_1=T_2 cos37\textdegree\)
\(T_1=8308.2* cos 37\textdegree\)
\(T_1=6655.295917 \approx 6655.3N\)
What is the main incentive for using a traditional economy? A. profit B. stability C. progress D. economic equality Please select the best answer from the choices provided A B C D
Answers
Answer:
the answer is B, stability
Explanation:
A traditional economy is a system that is based on honorable customs, history, and beliefs. Tradition guides economic decisions, such as production and distribution. Traditional economies depend on agriculture, fishing, hunting, gathering or some combination above. They use exchange instead of money. Most traditional economies operate in emerging markets and developing countries. They are often in Africa, Asia, Latin America and the Middle East. But you can find scholarships from traditional economies scattered all over the world. Economists and anthropologists believe that all other economies started out as traditional economies. Thus, they expect the remaining traditional economies to evolve into market, command or mixed economies over time.
Answer:
d
Explanation:
what is the unit of time not based on a heavenly body
Answers
12- Calculate the power when a force of 60N moves an object over a distance of 0.6 km in 20
minutes
A. 100watts
B. 6,000 watts
C. 0.25watts
D. 30 watts
Answers
Hi there!
To solve, we must begin by calculating the total WORK done on the object.
W = F · d (Force · displacement)
Plug in the given values. Remember to convert km to m:
1 km = 1000 m
0.6 km = 600 m
W = 60 · 600 = 36000 J
Now, we can solve for power:
P = W/t
Convert minutes to seconds:
1 min = 60 sec
20 min = 1200 sec
P = 36000/1200 = 30 W ⇒ Choice D.
What is density????????????
Answers
Density is a measure of mass per volume.
The average density of an object equals its total mass divided by its total volume.
An object made from a comparatively dense material (such as iron) will have less volume than an object of equal mass made from some less dense substance (such as water).
Perhaps the highest density known is reached in neutron star matter.
The singularity at the centre of a black hole, according to general relativity, does not have any volume, so its density is undefined.