A helium-filled balloon has a volume of 4.50 L when the temperature is 22.5 degrees C and the barometric pressure is 747.3 mmHg. The balloon’s volume is neither increasing nor decreasing, so what is the pressure of the helium inside the balloon?

I feel like there's either not enough information here to solve or the answer is simply 747.3 mmHg, but I'm not sure at all. Any help would be much appreciated.

Answer:

The correct answer is chemical change because both a color change and a solid formation were observed, which provide strong evidence of a new substance.

A physical change is a change in the state of a substance, such as a change from a solid to a liquid or a change from a liquid to a gas. A chemical change is a change in the composition of a substance, such as the formation of a new substance.

When potassium iodide and lead nitrate are mixed, a yellow precipitate forms. This precipitate is a new substance that was not present before the two substances were mixed. Therefore, the change that occurs when potassium iodide and lead nitrate are mixed is a chemical change.

The other answers are incorrect.

* Answer 1 is incorrect because the observation of a solid forming is not evidence of a state change. A state change is a change in the physical state of a substance, such as a change from a solid to a liquid or a change from a liquid to a gas. The formation of a precipitate is not a state change, but rather a chemical change.

* Answer 2 is incorrect because the color change of the mixture is evidence of a chemical change. When two substances are mixed and a new substance is formed, the new substance may have a different color than the original substances.

* Answer 3 is incorrect because the statement "two substances were mixed, which always results in the formation of a new substance" is not always true. For example, if you mix two different types of liquids, you may not get a new substance. Instead, you may just get a mixture of the two liquids.

The reaction between potassium iodide and lead nitrate results in a chemical change because a color change and solid formation, indicative of a new substance, are observed.

When potassium iodide and lead nitrate are mixed, there is a chemical change that takes place. This is because both a color change and a solid formation were observed, which provide strong evidence of a new substance. In this reaction, two new compounds are formed - lead iodide and potassium nitrate - which is a clear indication of a chemical change. This process is not easily reversible, further supporting it being a chemical change.

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Cu + O2 --->  CuO2 -The first reaction is a combustion reaction

2 HCl + Mg → H2 + MgCl2- The second reaction is a Single replacement reaction

A combustion reaction is a type of chemical reaction that occurs between a fuel and an oxidizer in the presence of heat or light, resulting in the release of energy in the form of heat and light.

In other words, it is a reaction in which a substance reacts with oxygen to produce heat and light.

Combustion reactions are important in many aspects of daily life, including the burning of fossil fuels for energy production, the combustion of wood or other materials for heating or cooking, and the combustion of fuels in internal combustion engines.

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Answer:

24.31 g/mol.

Explanation:

moles =mass/molar mass

n=w/m

The buffer solution has a pH of 5.36.

To find the pH of this buffer solution, use the Henderson-Hasselbalch equation:

pH = pKa + log([A⁻]/[HA])

where pKa = dissociation constant of acetic acid, [A⁻] = concentration of acetate ions, and [HA] = concentration of acetic acid.

Calculate the concentrations of acetate ions and acetic acid in the solution.

The initial moles of acetic acid are:

moles of acetic acid = volume of acetic acid x concentration of acetic acid

moles of acetic acid = 0.020 L x 0.10 mol/L

moles of acetic acid = 0.002 mol

After mixing with sodium acetate, the total volume of the solution is 50 mL, so the concentration of acetic acid and acetate ions are:

[HA] = moles of acetic acid / total volume of solution

[HA] = 0.002 mol / 0.050 L

[HA] = 0.040 M

[A⁻] = concentration of sodium acetate

[A⁻] = 0.10 M

The dissociation constant of acetic acid is pKa = 4.76.

Now, substitute these values into the Henderson-Hasselbalch equation:

pH = pKa + log([A⁻]/[HA])

pH = 4.76 + log(0.10/0.040)

pH = 4.76 + 0.60

pH = 5.36

Therefore, the pH of the buffer solution is 5.36.

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By removing the need to build additional transmission lines and equipment, energy storage may reduce costs for utilities and their customers.

By removing the need to build additional transmission lines and equipment, energy storage may reduce costs for utilities and their customers. Energy storage's inherent ability to offer backup power in the event of grid failure is a feature that both residential consumers and commercial owners find highly desirable.

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Answer:

im not sure

Explanation:

i went on here looking nobody answered yet

Answer:

\( \huge{ \boxed{111.30 \: \: \text{moles}}}\)

Explanation:

To find the number of moles in a substance given it's number of entities we use the formula

\( \bold{n = \frac{N}{L} \\ }\)

where

n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities.

From the question.

N = 6.7 × 10²⁵ \( \: H_2SO_4 \: \) molecules

\(n = \frac{6.7 \times {10}^{25} }{6.02 \times {10}^{23} } \\ = 111.2956...\)

We have the final answer as.

It is not necessary to test the reactivity of the elemental metals with solutions of the same metal ion because it won't react with itself.

This is referred to as the relative capacity or how readily a substance undergoes a chemical reaction.

Reactivity of elements are dependent on various types of parameters such as the number of valence electrons, shells etc and can be tested with other substances. However, it can't be tested with the solutions of the same metal ion because no reaction will occur thereby making it the most correct reason in this scenario.

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The pressure of the H2 gas is 739.1 torr.

What is Pressure?

The SI unit of pressure is Pascal (Pa), which is defined as one Newton per square meter (N/m^2). Other common units of pressure include atmospheres (atm), millimeters of mercury (mmHg), torr, and pounds per square inch (psi). Pressure is a fundamental concept in physics, chemistry, and engineering, and it plays a crucial role in various natural and man-made processes, such as fluid mechanics, thermodynamics, and weather patterns.

To find the pressure of the H2 gas, we need to subtract the vapor pressure of water from the total pressure inside the eudiometer.

Given:

Pressure of eudiometer (total pressure) = 760.0 torr

Vapor pressure of water = 20.9 torr

Pressure of H2 gas = Pressure of eudiometer - Vapor pressure of water

Pressure of H2 gas = 760.0 torr - 20.9 torr

Pressure of H2 gas = 739.1 torr

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A rainbow is produced through a proces that includes refraction, reflection, and dispersion of  sunlight.

A rainbow is formed when sulinght is refracted and reflected by rain drops in the atmospher.

The sunlight is split into its component colors, which is why rainbows appear as having an array of colors. This is due to each color being bent by a different amount during refraction.

The colors of a rainbow are always in the same order, with red on the outside and violet on the inside.

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We can determine the following based on the provided information:

Metal nitrate A is a compound that, when heated, transforms into colourless gas, brown gas B, and a metal oxide with a yellowish brown hue. B. C: Colourless petrol C. B: Brown petrol C. D: Compound D, a yellow precipitate produced by the reaction of potassium iodide with an aqueous solution of compound A.

We may deduce that A is probably lead nitrate (Pb(NO3)2) because lead is frequently used in soldering alloys and the metal contained in A is utilised in an alloy for soldering purposes.

Identifications:

Lead nitrate, or Pb(NO3)2,

N2O: Nitrogen dioxide

B: Carbon (CO)

D: PbI2, or lead iodide.

Thus, this can be concluded regarding the given scenario.

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Your question seems incomplete, the probable complete question is:

A metal nitrate A on heating gives a yellowish brown coloured metal oxide along with brown gas B and a colourless gas C. An aqueous solution of A on reaction with potassium iodide forms a yellow precipitate of compound D. Identify A, B, C and D. Also, identify the types of reactions taking place. Metal present in A is used in an alloy which is used for soldering purposes.

The total energy released per gram of methane in the experiment is 119941.33 J/g

Change in temperature (ΔT) = T₂ – T₁

Change in temperature (ΔT) = 68 – 25

Change in temperature (ΔT) = 43 °C

The absorbed by the water can be obtained as illustrated below:

Q = MCΔT

Q = 500 × 4.184 × 43

Q = 89956 J

Heat absorbed by water = 30% of heat released by methane

89956 = 30% × heat released by methane

89956 = 0.3 × heat released by methane

Divide both sides by 0.3

Heat released by methane = 89956 / 0.3

Heat released by methane = 299853.33 J

Q = m × ΔH

Divide both sides by m

ΔH = Q / m

ΔH = 299853.33 / 2.5

ΔH =119941.33 J/g

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After the reaction is complete, no nitrogen and no hydrogen molecules remain, and 8.00 x 1014 molecules of NH3 are produced.

In the equation, nitrogen and hydrogen react at a high temperature, in the presence of a catalyst, to produce ammonia, according to the balanced chemical equation:N2(g)+3H2(g)⟶2NH3(g)The coefficients of each molecule suggest that one molecule of nitrogen reacts with three molecules of hydrogen to create two molecules of ammonia.

So, to determine how many molecules of ammonia are produced when four nitrogen and nine hydrogen molecules are present, we must first determine which of the two reactants is the limiting reactant.

To find the limiting reactant, the number of moles of each reactant present in the equation must be determined.

Calculations:
Nitrogen (N2) molecules = 4Hence, the number of moles of N2 = 4/6.02 x 1023 mol-1 = 6.64 x 10-24 mol
Hydrogen (H2) molecules = 9Hence, the number of moles of H2 = 9/6.02 x 1023 mol-1 = 1.50 x 10-23 mol

Now we have to calculate the number of moles of NH3 produced when the number of moles of nitrogen and hydrogen are known, i.e., mole ratio of N2 and H2 is 1:3.

The mole ratio of N2 to NH3 is 1:2; thus, for every 1 mole of N2 consumed, 2 moles of NH3 are produced.
The mole ratio of H2 to NH3 is 3:2; thus, for every 3 moles of H2 consumed, 2 moles of NH3 are produced.
From these mole ratios, it can be observed that the limiting reactant is nitrogen.

Calculation for NH3 production:
Nitrogen (N2) moles = 6.64 x 10-24 moles
The mole ratio of N2 to NH3 is 1:2; therefore, moles of NH3 produced is 2 × 6.64 × 10−24 = 1.33 × 10−23 moles.

Now, to determine how many molecules of NH3 are produced, we need to convert moles to molecules.
1 mole = 6.02 x 1023 molecules
Thus, 1.33 x 10-23 moles of NH3 = 8.00 x 1014 molecules of NH3 produced.

To find the amount of each reactant remaining after the reaction is complete, we must first determine how many moles of nitrogen are consumed, then how many moles of hydrogen are consumed, and then subtract these from the initial number of moles of each reactant.

The moles of nitrogen consumed = 4 moles × 1 mole/1 mole N2 × 2 mole NH3/1 mole N2 = 8 moles NH3
The moles of hydrogen consumed = 9 moles × 2 mole NH3/3 mole H2 × 2 mole NH3/1 mole N2 = 4 moles NH3
Thus, the moles of nitrogen remaining = 6.64 × 10−24 mol – 8 × 2/3 × 6.02 × 10^23 mol-1 = 5.06 × 10−24 mol
The moles of hydrogen remaining = 1.50 × 10−23 mol – 4 × 2/3 × 6.02 × 10^23 mol-1 = 8.77 × 10−24 mol

Finally, the number of molecules of each reactant remaining can be calculated as follows:
Number of N2 molecules remaining = 5.06 × 10−24 mol × 6.02 × 10^23 molecules/mol = 3.05 × 10−1 molecules ≈ 0 molecules
Number of H2 molecules remaining = 8.77 × 10−24 mol × 6.02 × 10^23 molecules/mol = 5.28 × 10−1 molecules ≈ 0 molecules.

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Answer:change in energy of the electron=3.052x 10^-19J

which energy level does it move= level 2 , n=2

Explanation:

Using the formulae

1/λ = R (1/n1²- 1/n2²)

Where λ= 656.27 nm

1 nm = 1 x 10^-9 m

656.27 nm = 656.27 x 1 x 10^-9 =6.5726 x 10^-7

R =Rydberg constant = 1.0967 x 10^7m-1

1/λ = R (1/n1²- 1/n2²)

1/6.5726 x 10^-7=1.0967 x 10^7(1/n1²- 1/3²)

1/n1²=(1/6.5726 x 10^-7 x   1/1.0967 x 10^7) + 1/9

1/n1²=1,521,467.9 x 9.118x10^-8 + 0.1111

1/n1² =0.2498

n1²= 1/0.2498 =4

n1= \(\sqrt{4}\) = 2

it moves to energy level 2

b) Change in energy =ΔE = Rhc (1/n1²- 1/n2²)

Where R==Rydberg constant = 1.0967 x 10^7m-1

h = Planck constant = 6.626x 10^-34js

c = speed of light = 3.0 x 10^8 x m/s

ΔE = Rhc (1/n1²- 1/n2²)

=1.0967 x 10^7m-1 x6.626x 10^-34js X 3.0 x 10^8 x m/s (1/2² - 1/3²)

=2.18 x 10-18 x ( 1 /4 - 1/9)

=3.052x 10^-19J

Answer:

See figure 1

Explanation:

On this case we have a base (methylamine) and an acid (2-methyl propanoic acid). When we have an acid and a base an acid-base reaction will take place, on this specific case we will produce an ammonium carboxylate salt.

Now the question is: ¿These compounds can react by a nucleophile acyl substitution reaction? in other words ¿These compounds can produce an amide?

Due to the nature of the compounds (base and acid), the nucleophile (methylamine) doesn't have the ability to attack the carbon of the carbonyl group due to his basicity. The methylamine will react with the acid-producing a positive charge on the nitrogen and with this charge, the methylamine loses all his nucleophilicity.

I hope it helps!

Answer:

aluminum Zicam iron

Explanation:

Which metals dont react with anything?

Metals like aluminium, iron and zinc do not react either with cold or hot water. But they react with steam to form the metal oxide and

Mass of Sample = 59.993 - 57.880 = 2.113 g

Mass of Sample after 1st Heating = 59.710 - 57.880 = 1.83 g

Mass of Water Removed = 2.113 - 1.83 = 0.283 g

Mass of Sample after 2nd Heating = 59.7 - 57.88 = 1.82 g

Mass of Water Removed = 1.83 - 1.82 = 0.01 g

Total Mass of Water lost = 0.293 g

Moles of Water lost = 0.293 / 18 = 0.01628

Mass of Anhydrate = 1.82 g

Now check the molar mass of each hydrate:

CuSO4.5H2O = 159.61 g/mol

ZnSO4.7H2O = 287.58 g/mol

BaCl2.2H2O = 244.26 g/mol

MgSO4.7H2O = 246.47 g/mol

Now, Check the mole ratio of Anhydrous Salt : Water to get the required stoichiometric coefficient of H2O.

For BaCl2.2H2O,

Answer: BaCl2.2H2O

What is anhydrous salt?

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A) Equilibrium constant is usually written as:

We will firstly determine the concentrations of the gases:

B) By substituting what we know in the first equation to find out our unknown we have:

To determine the number of moles of CH3OH, we multiply the molar concentration by 10L

At equilibrium we have 0.55mol of CH3OH

C) If you want the equilibrium to to be shifted to the right in the direction of the product you can remove the CO from the ballon. According to Le Chateliers principle, the foward reaction is favored if the concentration of the the product is deecreased so that more product can be formed.

The solubility of AgCl is 18 × \(10^-^1^0\) in a 0.1M solution of CuCl₂.

The amount of a substance that can dissolve completely in a solvent at a specific temperature is known as its solubility. A saturated solution is one such example.

The maximum number of moles per liter of solution can be dissolved before the solution becomes saturated.

The equilibrium in the saturated solution will be as :

\(AgCl\) ⇄ \(Ag ^+ + Cl ^-\)

 \(a\)           \(a\)         \(a\)

\(CuCl_2\) ⇄ \(Cu^2^+ + Cl^-\)

  \(0.1\)        \(0.1\)          \(0.1\)

Ksp = \(1.8\) × \(10^ -^1^0\)

The solubility product constant: Ksp is the equilibrium constant for the dissolving of an ionic compound in water. Ksp is a function of temperature.

\(ksp AgCl = [ Ag ^+ ] [ Cl^-]\\\)

             \(= a\)×\([ a + 0.1]\)

             \(= a^2 + 0.1a\)

\(a^2\) is very small, so it is neglected.

ksp AgCl = 0.1a

\(1.8\) × \(10^ -^1^0\) = 0.1a

a = 18 × \(10^-^1^0\)

Therefore, the solubility of AgCl is 18 × \(10^-^1^0\).

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The reaction order and specific reaction rate constant can be determined by performing the kinetics experiment on irreversible polymerization A. Kinetic experiments can be used to investigate the rate and mechanism of chemical reactions. Chemical kinetics is the study of chemical reactions' speed and pathway.

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i When sodium carbonate (Na2CO3) is mixed with an aqueous solution of copper(II) sulfate (CuSO4), the student can expect to see several evidence of a chemical reaction:

Formation of a solid precipitate: When these two solutions are mixed, a solid precipitate of copper(II) carbonate (CuCO3) will form. This is a sign that a chemical reaction has occurred.

Change in color: The reaction between sodium carbonate and copper(II) sulfate will also result in a change in color. The solution may turn a blue or green color, indicating the presence of copper(II) ions.

Release of gases: The reaction between sodium carbonate and copper(II) sulfate may also produce gases, such as carbon dioxide (CO2).

ii The balanced chemical equation for the reaction between sodium carbonate and copper(II) sulfate is:

2Na2CO3(aq) + CuSO4(aq) → 2Na2SO4(aq) + CuCO3(s)

iii This is a double displacement reaction, also known as a metathesis reaction. In this type of reaction, the cations (positively charged ions) and anions (negatively charged ions) of the reactant compounds exchange places to form the products. In this case, the sodium ions (Na+) and the copper ions (Cu2+) exchange places to form sodium sulfate (Na2SO4) and copper carbonate (CuCO3).

Answer:

To determine the number of molecules in 5.67 moles, we can use Avogadro's number, which is the number of particles (atoms, molecules, etc.) in one mole of a substance. Avogadro's number is approximately 6.022 x 10^23 particles per mole.

Answer:

There are approximately 3.41 × 10²⁴ molecules in 5.67 moles, to three significant figures.

Explanation:

To calculate the number of molecules in moles, we can use Avogadro's constant.

Avogadro's constant is a fundamental constant that represents the number of particles in one mole of a substance. It is named after the Italian scientist Amedeo Avogadro, who first proposed the concept in 1811.

The exact value of Avogadro's constant, also known as Avogadro's number, is defined as 6.02214076 x 10²³ particles per mole.

To calculate the number of molecules in 5.67 moles we can use the equation:

\(\boxed{\textsf{Number of molecules = number of moles $\times$ Avogadro's constant}}\)

Substitute the values:

\(\begin{aligned}\implies \textsf{Number of molecules}&=5.67 \times 6.02214076 \times 10^{23}\\&= 34.1455381092 \times 10^{23}\\&=3.41455381092 \times 10^{24}\\ &\approx 3.41 \times 10^{24}\;\; \sf (3 \; s.f.)\end{aligned}\)

Therefore, there are approximately 3.41 × 10²⁴ molecules in 5.67 moles, to three significant figures.

Adding a catalyst will not cause the equilibrium of the reaction to shift towards the products.

A catalyst is a substance that speeds up the rate of a chemical reaction without being consumed in the reaction. It does not affect the position of the equilibrium or the relative amounts of reactants and products at equilibrium.

In the given reaction, Si(s) + 2Cl₂(g) + heat ↔ SiCl₄(g), the forward reaction is exothermic, which means it releases heat. According to Le Chatelier's principle, an increase in temperature will shift the equilibrium towards the reactants side in order to counteract the increase in heat. Therefore, increasing the temperature will shift the equilibrium towards the left, reducing the yield of silicon tetrachloride.

Increasing the pressure of the system will also shift the equilibrium towards the side with fewer gas molecules, which is the products side. In this case, increasing the pressure will shift the equilibrium towards the products, increasing the yield of silicon tetrachloride.

Increasing the mass of both reactants and products by 20% will not affect the position of the equilibrium either, as it does not change the ratio of the concentrations of the reactants and products.

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Consumers are organisms which depend on the producers or autotrophs for their food and nutrition.

Consumers are also known as heterotrophs, and they feed on the producers (autotrophs or self-feeders or plants) and herbivores (animals that eat plants) for food and energy. They don't produce their own food.

There are four types of consumers:

1) Primary – Herbivores are known as primary consumers and their source of food is plants or the first trophic level of the food chain. Example, Rabbits, Butterflies, Zooplanktons, etc.

2) Secondary – these consumers eat both plants and herbivores and are therefore also known as omnivores. Example, Ants, Crabs, Rats, Humans, etc.

3) Tertiary – these consumers eat primary and secondary consumers. Thus, they can be omnivores as well as carnivores. Example, Hawks, Snakes, Lions, etc.

4) Quaternary – these consumers prey on the tertiary consumers. Example, Polar bear, Alligator, etc.

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Answer:

The smallest whole-number coefficient for OH⁻ is 2

Explanation:

Step 1: The equation redox reaction is divided into two half equations

Reduction half equation: MnO₄⁻  ----> MnO₂

Oxidation half-equation: I⁻  ---> IO₃⁻

Step 2: Next the atoms are balanced by adding OH⁻ ions and H₂O molecules to the appropriate side of each half equation;

MnO₄⁻ +  2H₂O ----> MnO₂ + 4OH⁻

I⁻ + 6OH⁻ ---> IO₃⁻ + 3H₂O

Step 3 : The charges are then balanced by adding electrons to the appropriate sides of each half equation

MnO₄⁻ +  2H₂O + 3e⁻ ----> MnO₂ + 4OH⁻

I⁻ + 6OH⁻ ---> IO₃⁻ + 3H₂O + 6e⁻

Step 4: Oxidation half equation is multiplied by 2 while reduction half equation is multiplied by 1 to balance the number of electrons gained and lost for the reaction

2MnO₄⁻ +  4H₂O + 6e⁻ ----> 2MnO₂ + 8OH⁻

I⁻ + 6OH⁻ ---> IO₃⁻ + 3H₂O + 6e⁻

Step 5 : addition of the two half equations to yield a net ionic equation

2MnO₄⁻  + I⁻ + H₂O ----> 2MnO₂ + IO₃⁻ + 2OH⁻

The smallest whole number coefficient for OH⁻ is 2

A redox reaction is divided into two half equations which are shown below:

Reduction half equation: MnO₄⁻  ----> MnO₂

Oxidation half-equation: I⁻  ---> IO₃⁻

Atoms are balanced by adding OH⁻ ions and H₂O molecules to the appropriate side of each half equation to make the equation complete ;

MnO₄⁻ +  2H₂O ----> MnO₂ + 4OH⁻

I⁻ + 6OH⁻ ---> IO₃⁻ + 3H₂O

The charges needs to be balanced and this is done by adding electrons to the appropriate sides of each half equation

MnO₄⁻ +  2H₂O + 3e⁻ ----> MnO₂ + 4OH⁻

I⁻ + 6OH⁻ ---> IO₃⁻ + 3H₂O + 6e⁻

The equation needs to be balanced by multiplying the oxidation half equation by 2 while reduction half equation is multiplied by 1 to balance the number of electrons on both sides of the equations.

2MnO₄⁻ +  4H₂O + 6e⁻ ----> 2MnO₂ + 8OH⁻

I⁻ + 6OH⁻ ---> IO₃⁻ + 3H₂O + 6e⁻

The two half equations are then added and written together to form a net ionic equation

2MnO₄⁻  + I⁻ + H₂O ----> 2MnO₂ + IO₃⁻ + 2OH⁻

The smallest whole-number coefficient for OH⁻ is therefore 2.

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Answer:

The speed of molecules in a gas is directly proportional to the square root of the temperature and inversely proportional to the square root of the molar mass.

Since both gases are at the same temperature, we only need to compare their molar masses.

The molar mass of carbon dioxide (CO2) is 44 g/mol and the molar mass of hydrogen (H2) is 2 g/mol.

Therefore, the square root of the molar mass of hydrogen is smaller than the square root of the molar mass of carbon dioxide.

This means that the speed of hydrogen molecules is greater than the speed of carbon dioxide molecules at the same temperature.

The statement "All organic compounds contain the element carbon, but not all compounds containing the element 'carbon' are organic" can be justified based on the definition and characteristics of organic compounds.

Organic compounds are compounds primarily composed of carbon and hydrogen atoms, often with other elements like oxygen, nitrogen, sulfur, and phosphorus. These compounds are typically associated with living organisms and are known for their unique properties and behavior, including the ability to form complex structures, exhibit covalent bonding, and undergo organic reactions.

On the other hand, there are compounds that contain carbon but are not classified as organic. One notable example is carbon dioxide (\(CO_{2}\)), which is a simple inorganic compound composed of carbon and oxygen. Carbon dioxide does not possess the characteristic properties of organic compounds, such as the ability to form long chains or undergo organic reactions.

Additionally, there are inorganic compounds like carbonates (such as calcium carbonate) and carbides (such as calcium carbide) that contain carbon but are not considered organic. These compounds have distinct chemical and physical properties different from those of organic compounds.

In summary, while all organic compounds contain carbon, not all compounds containing carbon are organic. The classification of a compound as organic or inorganic depends on its overall molecular structure, bonding, and characteristic properties.

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