A grocery store had 38 employees, but then they hired 4 more people. What is the percent change in their staff?

Answers

Answer 1

The percentage change in the staff strength of the grocery store is 10.53%.

How to find the percentage change?

We are given;

Number of employees in store = 38 employees

Number of additional people hired = 4 employees

Thus, percentage change in their staff is;

4/38 * 100% = 10.53%

Thus, the percentage change in the staff strength of the grocery store is 10.53%.

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Related Questions

Shelby made equal deposits at the beginning of every 3 months into an RRSP. At the end of 9 years, the fund had an accumulated value of $55,000. If the RRSP was earning 3.50\% compounded monthly, what was the size of the quarterly deposits? Round to the nearest cent

Answers

The size of the quarterly deposits in Shelby's RRSP account was approximately $147.40.

Let's denote the size of the quarterly deposits as \(D\). The total number of deposits made over 9 years is \(9 \times 4 = 36\) since there are 4 quarters in a year. The interest rate per period is \(r = \frac{3.50}{100 \times 12} = 0.0029167\) (3.50% annual rate compounded monthly).

Using the formula for the future value of an ordinary annuity, we can calculate the accumulated value of the RRSP fund:

\[55,000 = D \times \left(\frac{{(1 + r)^{36} - 1}}{r}\right)\]

Simplifying the equation and solving for \(D\), we find:

\[D = \frac{55,000 \times r}{(1 + r)^{36} - 1}\]

Substituting the values into the formula, we get:

\[D = \frac{55,000 \times 0.0029167}{(1 + 0.0029167)^{36} - 1} \approx 147.40\]

Therefore, the size of the quarterly deposits, rounded to the nearest cent, is approximately $147.40.

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Whole numbers are rational.

A. ALWAYS
B. SOMETIMES
C. NEVER

Answers

Answer:

A. Always

Step-by-step explanation:

:)

Answer:

Always

Natural Numbers and Whole Numbers are both always rational. The answer is rational.

Hope it helps!

A baker mixes 8\frac{3}{4}8
4
3

cups of white flour with 2\frac{1}{2}2
2
1

cups of rye flour for a bread recipe.



​How many cups of white flour does the baker mix for every 11 cup of rye flour?

Answers

Fractions are written as the ratio of two integers. 3 1/7 cups white flour will be needed for every 11 cup of rye flour

Ratio and proportion

Fractions are written as the ratio of two integers. If a baker mixes 8 3/4 cups of white flour with 2 1/2 cups of rye, the number of cups of rye needed for 1 cup ofwhile flour will be:

For 1 cup of flour = (2 1/2)/(8 3/4)

For 1 cup of flour = (5/2)/(35/4)

For 1 cup of flour = 5/2 * 4/35
For 1 cup of flour = 2/7 cups of rye

For 11 cups:

For  11 cup of rye flour = 11 * 2/7

11 cup of rye flour = 22/7=3 1/7 cups

Hence 3 1/7 cups white flour will be needed for every 11 cup of rye flour

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Mrs. Jackson spends $ 18 for 3 pound how many was it per pound

Answers

Answer: 6 dollars per pound

Step-by-step explanation:

You just divide 18/3 and you get your answer! Give me brainliest pleass!

Consider the following system of equations...
Part A: How many solutions does this system have? Justify your answer.


(25 Points to whoever answers this!)

Consider the following system of equations...Part A: How many solutions does this system have? Justify

Answers

We can use the concept of System of Equations to solve this question. The answer for part A is 0 and even for part B is 0.

How do you solve no.of solutions for a System of Equations?

A two-variable linear equation is one with the formula ax + by + c = 0, where a, b, c R, a, and b 0. By comparing the coefficients of the variables in the equations, we may determine how many solutions there are to a system of linear equations. Take into account the pair of linear equations involving x and y.

a1x + b1y + c1 = 0

a2x + b2y + c2 = 0

Here, the real numbers a2, b2, and c2 are all present.

Keep in mind that a12 + b12 0 and a22 + b22 0

1. There will be a singular solution if (a1/a2) (b1/b2).

2. There will be an endless number of solutions if (a1/a2) = (b1/b2) = (c1/c2).

3. There won't be a solution if (a1/a2) = (b1/b2) ≠(c1/c2).

Calculation

Part A:

       4x+6y=24

       2x+3y=8 are the given solutions are they are in the form of linear equations.

a1/a2 =2 b1/b2=2 and c1/c2=3

So according to the condition 3 , there will no solution if both the lines are parallel and a1/a2 =b1/b2 ≠c1/c2.

∴ So No.of solutions are Zero.

Part B:

   In the updated system,

             12x+18y=72

              2x+3y=8

a1/a2 =6 b1/b2 =6 and c1/c2=9.

So according to the condition 3 , there will no solution if both the lines are parallel and a1/a2 =b1/b2 ≠c1/c2.

So they have same no.of solutions as the original system.

We can use the concept of System of Equations to solve this question. The answer for part A is 0 and even for part B is 0.

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Latrell looks around at an assembly. He notices his younger sister to his right and his older brother 12 meters ahead of him. If Latrell's brother and sister are 20 meters apart, how far apart are Latrell and his younger sister?

Answers

Latrell and his younger sister are 16 meters apart.

From the given information, we can form a triangle with Latrell, his younger sister, and his older brother. Let's denote the distance between Latrell and his younger sister as "x" meters.

Using the Pythagorean theorem, we can set up the equation:

x^2 + 12^2 = 20^2

Simplifying the equation:

x^2 + 144 = 400

Subtracting 144 from both sides:

x^2 = 400 - 144

x^2 = 256

Taking the square root of both sides:

x = √256

x = 16

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Someone can help me !!!!

Someone can help me !!!!

Answers

Answer: the second to last answer

Step-by-step explanation:

i need someones help with this question

i need someones help with this question

Answers

V≈141.4 hope this helps

Which pair of triangles are similar?
A
Triangles 1 and 2 each have a 36° angle.
a
B
Triangles 3 and 4 each have a 42° angle.
с
Triangle 5 has a 70 angle and a 95° angle. Triangle 6 has a 30° and a 75º.
a
D
Triangle 7 has a 30 angle and a 90°. Triangle 6 has a 30° and a 60°.

Answers

Answer:

\( \sf \fbox{Option D have pair of triangles are similiar}\)

Step-by-step explanation:

To prove triangles are pair we will use AAA property.

ln option A the given triangles 1 & 2 have a 36° Angle, but the remaining two angles of both the traingle are not mentioned, as long as we don't know the measure of other two angle of both the traingle we can't say that pair of triangles are similar.

Similarly In option B triangles 3 & 4 can't be pair of similar triangle

In option C triangle 5 & 6 don't have any common angle, hence it does not follows AAA property and the given pair of traingles are not similar.

In option D Two angles of each triangle are given so we can easily find the third angle of both the triangle. let's solve for the third angles of triangle 7 and 8.

in triangle 7,

given angles are 30° and 90°let the third angle be X,now,30+90+X = 180(sum of all angles of triangle is 180)X= 180-90-30X= 60

All three angles of triangle 7 are 30, 60 & 90

Now in triangle 8,

given angles are 30° and 60°let the third angle be Y,now,30+60+Y = 180(sum of all angles of triangle is 180)Y= 180-90Y= 90

All three angles of triangle 8 are 30, 60 & 90

Hence, both the triangles have same measure of all three angles we can say that triangle 7 & 8 are similar triangle.

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In the given figure ABCD, prove that
angleBCD= angleBAD+ angle ABC+angle ADC.
[Hint: Join A and C then extended AC to the point E]​

In the given figure ABCD, prove thatangleBCD= angleBAD+ angle ABC+angle ADC.[Hint: Join A and C then

Answers

We have proved that Angle BCD is equal to angle BAD plus angle ABC plus angle ADC, as required.

To prove that angle BCD is equal to angle BAD plus angle ABC plus angle ADC, we can use the following steps:

Step 1: Join points A and C with a line segment. Let's label the point where AC intersects with line segment BD as point E.

Step 2: Since line segment AC is drawn, we can consider triangle ABC and triangle ADC separately.

Step 3: In triangle ABC, we have angle B + angle ABC + angle BCA = 180 degrees (due to the sum of angles in a triangle).

Step 4: In triangle ADC, we have angle D + angle ADC + angle CDA = 180 degrees.

Step 5: From steps 3 and 4, we can deduce that angle B + angle ABC + angle BCA + angle D + angle ADC + angle CDA = 360 degrees (by adding the equations from steps 3 and 4).

Step 6: Consider quadrilateral ABED. The sum of angles in a quadrilateral is 360 degrees.

Step 7: In quadrilateral ABED, we have angle BAD + angle ABC + angle BCD + angle CDA = 360 degrees.

Step 8: Comparing steps 5 and 7, we can conclude that angle B + angle BCD + angle D = angle BAD + angle ABC + angle ADC.

Step 9: Rearranging step 8, we get angle BCD = angle BAD + angle ABC + angle ADC.

Therefore, we have proved that angle BCD is equal to angle BAD plus angle ABC plus angle ADC, as required.

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Given: Quadrilateral \(\displaystyle\sf ABCD\)

To prove: \(\displaystyle\sf \angle BCD = \angle BAD + \angle ABC + \angle ADC\)

Proof:

1. Draw segment \(\displaystyle\sf AC\) and extend it to point \(\displaystyle\sf E\).

2. Consider triangle \(\displaystyle\sf ACD\) and triangle \(\displaystyle\sf BCE\).

3. In triangle \(\displaystyle\sf ACD\):

- \(\displaystyle\sf \angle ACD = \angle BAD + \angle ADC\) (Angles of a triangle add up to \(\displaystyle\sf 180^\circ\)).

4. In triangle \(\displaystyle\sf BCE\):

- \(\displaystyle\sf \angle BCE = \angle BAD + \angle ABC\) (Angles of a triangle add up to \(\displaystyle\sf 180^\circ\)).

5. Since \(\displaystyle\sf \angle BCE\) and \(\displaystyle\sf \angle BCD\) are corresponding angles formed by transversal \(\displaystyle\sf BE\):

- \(\displaystyle\sf \angle BCE = \angle BCD\).

6. Combining the equations from steps 3 and 4:

- \(\displaystyle\sf \angle BCD = \angle ACD = \angle BAD + \angle ADC\). - \(\displaystyle\sf \angle BCD = \angle BCE = \angle BAD + \angle ABC + \angle ADC\).

Therefore, we have proven that in quadrilateral \(\displaystyle\sf ABCD\), \(\displaystyle\sf \angle BCD = \angle BAD + \angle ABC + \angle ADC\).

\(\huge{\mathfrak{\colorbox{black}{\textcolor{lime}{I\:hope\:this\:helps\:!\:\:}}}}\)

♥️ \(\large{\underline{\textcolor{red}{\mathcal{SUMIT\:\:ROY\:\:(:\:\:}}}}\)

Is 3.1 terminating or repeating

Answers

Answer:

Depends if there is a line above the "1".

Step-by-step explanation:

If it were the attached image it would be repeating>>

If not and it's just 3.1, its terminal.

Is 3.1 terminating or repeating

What is the value of u?

What is the value of u?

Answers

Answer:

4\(\sqrt{2\)

Step-by-step explanation:

2 4/5 x = -1 1/4 help please

Answers

Answer: -25/56

Step-by-step explanation: To find x, we must divide both sides of the equation by 2 4/5. Start by turning both sides into improper fractions:

14/5 x = -5/4

Now we divide -5/4 by 14/5 which is equal to -5/4 * 5/14, giving us the answer of -25/56.

2 4/5x = -1 1/4
14x/5 = -5/4
56x = -25
X = -25/56

What is the equation of the line that passes through the points( (-6,-5) and(-5, 5)?​

Answers

Answer:

y=10x+55

Step-by-step explanation:

First, you need to find the slope.

y2-y1/x2-x1

-5-5/-6+5=-10/-1=10

Now, we substitute one of the points for the values in y=mx+b

y=10x+b

5=10(-5)+b

5=-50+b

55=b

The full equation is y=10x+55

Flying against the wind, a jet travels miles in hours. Flying with the wind, the same jet travels miles in hours. What is the rate of the jet in still air and what is the rate of the wind

Answers

Answer:

Velocity in still air: 760 mi/ hr

Velocity against the wind: 210 mi/ hr

Step-by-step explanation:

Given

See attachment for complete question

Required

The rate in still air

The rate of the wind

From the question, the velocity (v) against the wind is:

\(v =\frac{distance}{time}\)

\(v =\frac{3040}{4}\)

\(v_1 =760mi/hr\)

The velocity with the wind is:

\(v_2 = \frac{8260}{7}\)

\(v_2 = 1180mi/hr\)

Let:

\(x \to\) velocity in still air

\(y \to\) velocity of the wind

So, we have:

\(x - y = 760\)

\(x + y = 1180\)

Add both equations

\(x + x -y + y = 760 + 1180\)

\(2x = 1940\)

Divide by 2

\(x = 970\)

Substitute \(x = 970\) in \(x - y = 760\)

\(970 - y= 760\)

Make y the subject

\(y = 970 - 760\)

\(y = 210\)

find the probability

find the probability

Answers

Answer:

alright so you have to do math to do it

Step-by-step explanation:

20 POINT QUESTION!!!!
f(x)=12x^(2)+4x-5
find the zeroes of the function...

Answers

Answer:

x = - \(\frac{5}{6}\) , x = \(\frac{1}{2}\)

Step-by-step explanation:

To find the zeros let f(x) = 0 , that is

12x² + 4x - 5 = 0

Consider the factors of the product of the x² term and the constant term which sum to give the coefficient of the x- term.

product = 12 × - 5 = - 60 and sum = + 4

The factors are - 6 and + 10

Use these factors to split the x- term

12x² - 6x + 10x - 5 = 0 ( factor first/second and third/fourth terms )

6x(2x - 1) + 5(2x - 1) = 0 ← factor out (2x - 1) from each term

(2x - 1)(6x + 5) = 0

Equate each factor to zero and solve for x

6x + 5 = 0 ⇒ 6x = - 5 ⇒ x = - \(\frac{5}{6}\)

2x - 1 = 0 ⇒ 2x = 1 ⇒ x = \(\frac{1}{2}\)

Determine the number of different groups of 5 items that can be selected from 12 distinct items.

Answers

There are total 95040 number of different groups of 5 items can be selected from 12 distinct item.

According to the given question.

Total number of items, n = 12

Total numbers of items to be selected, r = 5

Since, we have to determine the number of different groups of 5 items that can be selected from 12 distinct items. So, we will find the number of different groups by permulation formula i.e.

\(^{n} P_{r} = \frac{n!}{(n-r)!}\)

Where,

\(^{n} P_{r}\) is the total number of permutations.

n is the total number of objects.

r is teh total number of objects to be selected.

Therefore,

The number of different groups or permutaions of 5 items that can be selected from 12 distinct group

\(^{12} P_{5}\)

\(= \frac{12!}{(12-5)!}\)

\(= \frac{12!}{7!}\)

\(= \frac{12\times11\times10\times9\times8\times7!}{7!}\)

= 12 × 11 × 10 × 9 × 8

= 95040

Hence, there are total 95040 number of different groups of 5 items can be selected from 12 distinct item.

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Find CD. Assume segments that appear to be tangent are tangent.​

Find CD. Assume segments that appear to be tangent are tangent.

Answers

Answer: 5

Step-by-step explanation:

Find CD. Assume segments that appear to be tangent are tangent.

D Find two solutions to the equation 5 y = 8 Complete the statements below.​

D Find two solutions to the equation 5 y = 8 Complete the statements below.

Answers

Step-by-step explanation:

(1,5/8), (2,5/4) those are the two solutions

Suppose a research team at UCLA wants to estimate the average depression level in the general population. To do so, they recruit a random sample of 300 participants from throughout the city. What is the population parameter for this scenario?The expected variability or standard deviation of the means from MANY different random samples is known as what quantity:a. Sampling variabilityb. Standard error (panel 51 from slides), it’s also said in the video c. Sampling distribution d. Paramete

Answers

The research team at UCLA wants to estimate the population parameter  using a random sample of 300 participants and understand the sampling variability by calculating the standard error.

Sampling variability refers to the expected variability or standard deviation of the means from many different random samples.

The population parameter in this scenario is the average depression level of the entire city's population.

This is because each sample is only a small representation of the entire population, and so the means from different samples may vary.

The standard error is a measure of the sampling variability and is represented by the Greek letter σ (sigma) divided by the square root of the sample size.

The standard error is an estimate of the standard deviation of the sampling distribution, which is the distribution of the means from many random samples.

In mathematical terms, the population parameter is represented as:

μ = mean of the entire population

The standard error can be calculated as:

σ/√n = standard error, where σ is the standard deviation of the population and n is the sample size.

Complete Question:

Suppose a research team at UCLA wants to estimate the average depression level in the general population. To do so, they recruit a random sample of 300 participants from throughout the city. What is the population parameter for this scenario?

The expected variability or standard deviation of the means from MANY different random samples is known as what quantity:

a. Sampling variability

b. The standard error (panel 51 from slides), it’s also said in video

c. Sampling distribution

d. Parameter

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PLEASE HELP I WOULDVE PUT MORE POINTS BUT I GOT BANNED ON MY OTHER ACC

10 • 10 • a • a • b

Answers

Answer:

100•a²•b

Step-by-step explanation:

10•10=100

a•a=a²

and then just b

which of the following is the solution to the equation 25(z-2 )= 125?

A. z= 5.5
B. z = 3.5
D. z = -2.5
E. z = -0.5

Answers

Answer:

The answer is z = 7.

Step-by-step explanation:

1) Divide both sides by 25.

\(z - 2 = \frac{125}{25} \)

2) Simplify 125/25 to 5.

\(z - 2 = 5\)

3) Add 2 to both sides.

\(z = 5 + 2\)

4) Simplify 5 + 2 to 7.

\(z = 7\)

Thus, the answer is z = 7.

Use the given graph to complete the table. Then write an equation representing the relationship.

Use the given graph to complete the table. Then write an equation representing the relationship.

Answers

The equation of the relation is y = 3/2x.

   x    |   y    

   0       0

   2       3

   4       6

How to Write the Equation that Represents a Proportional Relationship?

To write the equation for the proportional relationship between two variables, x and y, find the unit rate, k, which is k = y/x.

Substitute the value of k into y = kx to write the equation of the relationship.

Using a point on the line, (2, 3):

k = y/x = 3/2

Substitute k = 3/2 into y = kx:

y = 3/2x

Using the equation, substitute each of the values of x in the table to get the corresponding value of y:

For 0:

y = 3/2(0)

y = o

For 2:

y = 3/2(2)

y = 3

For 4:

y = 3/2(4)

y = 6

The table is:

   x    |   y    

   0       0

   2       3

   4       6

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show work needed with this question!

show work needed with this question!

Answers

Answer:

The final value is 8750

Step-by-step explanation:

First step is to find the increase

3500 * 150%

3500 * 1.5

5250

Now we need to add the increase to the starting value

3500 + 5250

8750

The final value is 8750

Use the given conditions to write an equation for the line in point-slope form and slope-intercept form Passing through (-2,4) and parallel to the line whose equation is x-3y = 7

Answers

Answer:

The equation for the line is:

3y - x = 14

Explanation:

Given the line:

x - 3y = 7

This line can be written as:

y = (1/3)x - 7/3

The slope is 1/3

The y-intercept is -7/3

A line parallel to this has the same slope but different y-intercept, written as:

y = (1/3)x + b

Using the given point (-2, 4), with x = -2 and y = 4, we can obtain the value of b

4 = (1/3)(-2) + b

b = 4 + 2/3

= 14/3

Therefore, the line is:

y = (1/3)x + (14/3)

or

3y - x = 14

0.18 rounded to the nearest tenth

Answers

Answer:

0.2

Step-by-step explanation:

8 is bigger than 5 so we will make 8 zero and will will add 1 to the next number

Answer:

0.2

Step-by-step explanation:

Hope this helps

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A right triangle has one angle that measure 27°. The adjacent leg measures 27.6 cm.

What is the length of the hypotenuse?


A.
60.8 cm


B.
54.2 cm


C.
31.0 cm


D.
24.6 cm

Answers

Answer:B

Step-by-step explanation:

If each shelf can hold at most 20 books, what is the least number of shelves needed to store the 175 books?

Answers

Answer- 9 shelves

In order to find out how many shelves are need we must divided 175 into 20. 175 divided by 20 is 8.75. But, because you cannot have have .75 of a shelf, you have to round this to a whole. This means that 9 shelves will be the least needed number of shelves need to store 175 books. To check this answer 20 books X 8 shelves is 160 books, which means eight shelves can only store 160 books, we will need and additional shelf to store the last 15 books.

HOPE THIS HELPS & GOOD LUCK!

A circular pond is 21 m in diameter. It is surrounded by 3.5 m wide path. Find the
cost of constructing the path at the rate of Rs. 25 per m2.

Answers

The cost of constructing the path at the rate of Rs. 25 per m2 would be Rs. 38,465.

To find the cost of constructing the path, we need to determine the area of the path and then multiply it by the cost per square meter.

The total diameter of the pond and the path is 21m + 3.5m + 3.5m = 28m.

So the radius of the pond is half of the diameter, which is 21m/2 = 10.5m.

The radius of the pond with the path is (21m+3.5m)/2 = 12.25m.

Area of the path = Area of the outer circle - Area of the pond

\(= π(12.25)^2 - π(10.5)^2\)

\(= π[(12.25)^2 - (10.5)^2]\)

= 3.14 x (24.5 + 10.5) x (24.5 - 10.5)

= 3.14 x 35 x 14

= 1538.6 m2 (rounded to one decimal place)

Therefore, the cost of constructing the path at the rate of Rs. 25 per m2 would be:

Cost = Area x Rate per m2

= 1538.6 x 25

= Rs. 38,465.

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