A grocery shopper tosses a(n) 8.5 kg bag of
rice into a stationary 17.4 kg grocery cart.
The bag hits the cart with a horizontal speed
of 5.5 m/s toward the front of the cart.
What is the final speed of the cart and bag?
Answer in units of m/s.

Answers

Answer 1

Answer:

3.1 m/sec

Explanation:

The contained in the flying bag of rice is applied to the stationary cart.  Lets calculate the kinetic energy of the flying bag of rice.  Kinetic energy (KE) is given by KE = (1/2)mv^2, where m is the mass and v is the velocity.

[Note:  a kg*m^2/s^2 is 1 Joule]

KE(rice bag) = (1/2)(8.5kg)(5.5m/s)^2

KE(bag) =  129 Joules

When the bag hits the shopping cart, some of the energy tis transferred to the cart.  We aill assume no energy in lost in the collision (conservation of energy).  The kinetic energy is now contained in a body  with a total mass of 25.9 kg (rice bag plus cart).  

Use the kinetic energy expression again, using the same KE from the rice bag, but with a new mass.

KE = (1/2)mv^2

129 Joules = (1/2)(26.9 kg)v^2

 129 kg*m^2/s^2 = (1/2)(26.9 kg)v^2

v^2 = (129 kg*m^2/s^2)/(12.95 kg)

 v^2 = 9.96 m^2/s^2

 v = 3.12 m/s (3.1 m/2 with 2 sig figs)

3.12 m/s will be the velocity of the grocery cart and rice bag.    [That's 6.7 miles/hr, for the non-metric inclined]

         


Related Questions

17. For how long should a force of 130 N be applied to an object of mass 50 kg to change its speed from 20 m/s to 60 m/s?
a. 0.031 s
b. 0.065 s
c. 15.4 s
d. 40 s

Answers

Answer:

c. 15.4 s

Explanation:

Given the following data;

Mass, m = 50kg

Force, F = 130N

Initial velocity, u = 20m/s

Final velocity, v = 60m/s

To find the time;

First of all, we would solve for acceleration using the formula below;

Force = mass * acceleration

130 = 50*acceleration

Acceleration = 130/50

Acceleration = 2.6m/s²

Now, we would use the first equation of motion to find the time.

V = U + at

60 = 20 + 2.6t

2.6t = 60 - 20

2.6t = 40

t = 40/2.6

Time, t = 15.39 ≈ 15.4 seconds.

The time taken will be 15.4 seconds approximately. The correct answer is option c

NEWTON SECOND LAW

Newton's second law state that, the rate of change of momentum is proportional to the force applied.

Given that  a force of 130 N be applied to an object of mass 50 kg to change its speed from 20 m/s to 60 m/s. The given parameters are;

Force F = 130 Nmass m = 50 kgInitial velocity u = 20 m/sFinal velocity V = 60 m/s

from Newton's second law,

Ft = m(v - u)

Substitute all the parameters into the formula

130t = 50 (60 - 20)

130t = 50 x 40

130t = 2000

t = 2000/130

t = 15.38 seconds

Therefore, the time taken will be 15.4 seconds approximately. The correct answer is option c

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What value of resistor R gives the circuit in the figure a time constant of 22 μs ?

Answers

The value of resistor R that gives the circuit in the figure a time constant of 22 μs is 220 Ω.

The circuit that is in the figure is shown below:Given that time constant (RC) = 22 μs. To find the value of resistor R, we need to use the formula for the time constant:

RC = τ, where R is the resistance and C is the capacitance of the circuit.

Rearranging the above formula, we get:R = τ / C

Where τ is the time constant and C is the capacitance of the circuit.

From the figure, the capacitance is given as 0.1 μF

.Substituting the values of τ and C in the above formula, we get:

R = (22 × 10⁻⁶ s) / (0.1 × 10⁻⁶ F)

R = 220 Ω

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The conductivity of water can be increased by adding .

Answers

Explanation:

The conductivity of water can be increased by adding any solute that increases the number of ions in solution.

Hope this helps you.. Good luck

The conductivity of water can be incrased by adding to it anything that disolves and ionizes in it.

Examples:

-- sugar

-- coffee

-- tea

-- artificial sweetener  

-- baking soda

-- orange juice

-- corn starch

-- salt

What is the volume of a cone with a height of 27cm and a radius of 13cm? And your answer to the nearest tenth

Answers

Answer:

the volume of the cone is \(4778.36 cm^3\)

Explanation:

The computation of the volume of the cone is shown below:

As we know that

The Volume of the cone is

r denotes the radius

And, h denotes the height

So,

\(= \frac{1}{3} \pi r^2 h \\\\= \frac{1}{3} \times 3.14 \times 13^2 \times 27\\\\= 4778.36 cm^3\)

Hence, the volume of the cone is \(4778.36 cm^3\)

Question 15 of 15
What is the product of mass and velocity of an object?
A. conservation
B. force
C. impulse
D. momentum
SUBMIT

Answers

Answer:

Momentum

Explanation:

-Conservation means that any quantity is kept constant.❌

-Force is product of mass and acceleration.❌

-Impulse is product of force and the period of action of the force.❌

-Momentum is the product of mass of a body and it's velocity.✔️

Module 3 Discussion!
After reading Ch.12 and 13 of the text (The essentials of Finance and Accounting for nonfinancial managers/ Third Edition) on Strategy and Financial Forecasting, watching the SWOT video based on Paley’s Products from the Ratio Analysis in Module 2 and the additional narrative information in Appendix C, Phase
Create a SWOT analysis that will reflect the TOWS analysis as described in Ch. 12 of the text. The purpose of the SWOT analysis is to lay out several issues and possibilities to be considered in Paley’s strategic planning. The strengths and weaknesses are internal issues, whereas the opportunities and threats are external.
The second part of the analysis is to create actions based on the SWOTs. This is sometimes called a TOWS analysis and is done by comparing the boxes, two at a time:
Offensive actions come from strengths that link to opportunities, so a specific strength can be applied to exploit an opportunity.
Adjusting actions come from addressing weaknesses, which then can be used to exploit opportunities that previously had not been possible.
Turnaround actions come from weaknesses that link to threats. These are high-risk issues where a priority needs to be given to addressing the weakness to minimize the vulnerability.
Defensive actions come from threats that link to strengths. These are latent issues because if the threat materializes, an already-existing strength is available to counter it.
Additional actions can be included to address other issues not directly identified in the SWOTs.
3. From the actions identified in part 2, pick 3-5 strategic actions that you feel Paley must achieve or at least start in the upcoming year and state your reasons for including them.
Attach your completed SWOT form and list of strategic actions with supporting logic and facts from the case as your answer for this discussion question. These actions are the foundation for the strategic plan

Answers

SWOT Analysis Strengths- Paley’s Products has a low overhead cost with the company operating at a high level of efficiency, resulting in competitive pricing.- They have a team of experienced employees who have worked in the industry for several years.- They have a variety of products in the portfolio that can satisfy customers from different sectors.- They are reputable and have a loyal customer base.Weaknesses- They have been slow to adopt new technology, and this may be a disadvantage to the company.- Limited marketing and sales promotion are affecting their sales revenue.-

They depend on a few key customers for the bulk of their sales revenue, leaving them vulnerable to market changes.Opportunities- Expansion of the product line to include unique products.- The establishment of strategic partnerships with other businesses in the industry.- Exploration of new markets, such as international markets.- Improvement of marketing techniques to increase brand awareness.Threats- Changes in consumer preferences towards environmentally friendly products.- Increase in competition from other businesses in the industry.- Fluctuating market prices for raw materials that may lead to price increases.

Strategic Actions to be taken by Paley Products1. Development of an E-commerce platform to allow online transactions with customers. The E-commerce platform will enable Paley to reach a wider customer base, expand its reach, and increase sales revenue.2. Investment in the research and development of new environmentally friendly products. Paley will remain competitive and cater to the needs of consumers who prefer green products.3. Establishment of strategic partnerships with other businesses in the industry to leverage the strength of other companies in the industry and to develop new products or increase market share.4. Improvement of marketing techniques to increase brand awareness and improve visibility. A marketing strategy that incorporates social media and other digital channels can help promote the brand to potential customers.5. Expansion into international markets. This will enable Paley to diversify its customer base and generate more revenue. Paley can start by targeting nearby countries, then expand globally as they gain more experience and financial stability.

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A certain 800-kg car has a motor whose power output is
30 kW. If the car is carrying two passengers whose total mass
is 150 kg, how long will it need to accelerate from 70 to 110
km/h?

Answers

Based on the relationship between power and time, the time required is 10.67 seconds

What is the time required for the car to accelerate from 70 to 110 km/h?

Force produced by the car = mass × acceleration

Force produced by the car engine = 30 kW = 3000 kW

mass of car = 800 Kg

acceleration of car = changein velocity / time

acceleration = 110 - 70/t = 40/t

3000 = 800 × 40/t

t = 32000/3000

time, t = 10.67 seconds

Therefore, the time required is 10.67 seconds

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If a sound wave travels through air at a speed of 345 m/s, what would be the frequency of a 0.80 m long wave?
276.0
343.2
345.8
431.3

Answers

Answer:

D

Explanation:431.3

A rocket is launched from the launch pad at a speed of 700 km/hr.
How far will the rocket have traveled after 1.5 hour?

Answers

Answer:

Explanation:

Vm = Δs/Δt

700km/h = Δs/1.5h

700 = Δs/1.5

\(\frac{700}{1} = \frac{S}{1.5}\)

S = 700 x 1.5

S = 1050 Km

*(S = Δs)

Answer: The rocket will have traveled 1050 Km

Hope this help ☺

After 1.5 hour the rocket will have traveled 1023.54 km.

What is speed?

In everyday use and in kinematics, the speed (commonly referred to as v) of an object is the magnitude of the change of its position over time or the magnitude of the change of its position per unit of time; it is thus a scalar quantity.  SI unit of speed is meter/second.

Initial speed of the rocket = 700 km/hr

= 700 (1000/3600) meter/second

= 194.44 meter/second

Acceleration due to gravity is = 9.8 m/s²

Time interval is = 1.5 hour = 1.5 × 60 × 60 second

hence, after 1.5 hour the rocket will have traveled = (194.44) (1.5 × 60 × 60) - 1/2×9.8×(1.5×60×60)² meter

= 1050000 meter - 26460 meter

= 1023540 meter

= 1023.54 km.

So,  the rocket will have traveled 1023.54 km after 1.5 hour .

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An enclosed chamber with sound absorbing walls has a 2.0 m × 1.0 m opening for an outsidewindow. A loudspeaker is located outdoors,, 78 m away and facing the window. The intensity level ofthe sound entering the window space from the loudspeaker is 79 dB. Assume the acoustic output of theloudspeaker is uniform in all directions and that the acoustic energy incident upon the ground iscompletely absorbed and therefore is not reflected into the window. The threshold of hearing is 1.0 × 10-12 W/m2. The acoustic power entering through the window space is closest to?A) 160 ?W.B) 79 ?W.C) 320 ?W.D) 790 ?W.E) 1600 ?W.

Answers

The window space has an acoustic power of 160 or less. The quantity of energy that is transported or transformed through time is referred to as power in physics

What exactly do the terms "force" and "power" mean?

Force is the principal result of an interaction between two things, whereas power is a measurement of energy consumed over time (energy), of which force is a component. Power and push can both be measured and expressed, but only a force is a true physical phenomenon.

what is Power definition and types?

The capacity to influence your surroundings is referred to as personal power. Reward power, coercive, legal power, formal authority, and referent power are the five categories of power that can be used to achieve this.

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what Are the Advantages of SI unit

Answers

Answer:

1)SI is coherent system of units

2) SI is rational system of units

what is the minimum internal cooking temperature and holding time for chopped sirloin

Answers

The recommended minimum internal cooking temperature for ground beef, including chopped sirloin, is 160°F (71°C). This temperature should be measured using a food thermometer inserted into the thickest part of the meat.

The minimum internal cooking temperature and holding time for chopped sirloin (ground beef) depend on food safety guidelines to ensure that harmful bacteria, such as E. coli, are sufficiently destroyed.

In terms of holding time, it is generally recommended to cook ground beef until it reaches the minimum internal temperature of 160°F (71°C) and then maintain that temperature for at least 15 seconds to ensure any potential pathogens are killed.

It's important to note that these guidelines are based on food safety recommendations, and following them helps reduce the risk of foodborne illnesses. Cooking ground beef, like chopped sirloin, to the proper internal temperature is crucial for food safety.

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A box moving on a horizontal surface with an initial velocity of 20 m/s slows to a stop over a time period of 5.0 seconds due solely to the effects of friction. What is the coefficient of kinetic friction between the box and the ground? 0.41 0.25 0.03 0.10

Answers

After considering the given data we conclude that the coefficient of kinetic friction between the box and the ground is approximately 0.41, which is Option A.

To solve the problem, we can use the following formula:
\(a = (vf - vi) / t\)
where a is the acceleration, vf is the final velocity (which is zero in this case), vi is the initial velocity (which is 20 m/s), and t is the time taken to stop (which is 5.0 seconds).
We can then use the following formula to calculate the coefficient of kinetic friction:
\(f_k = (ma) / (mg)\)
where \(f_k\) is the force of kinetic friction, m is the mass of the box, g is the acceleration due to gravity, and a is the acceleration calculated above.
Substituting the given values, we get:
\(a = (0 - 20 m/s) / 5.0 s = -4.0 m/s^2\)
\(f_k = (m * a) / (m * g) = a / g = -4.0 m/s^2 / 9.81 m/s^2 = -0.407\)
Since the coefficient of kinetic friction cannot be negative, we take the absolute value:
\(f_k = 0.407\)
Therefore, the coefficient of kinetic friction between the box and the ground is approximately 0.41, which is Option a.
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a 50.7-kg crate of tools rests on a horizontal floor. you exert a gradually increasing horizontal push on it and observe that the crate just begins to move when your force exceeds 301 n . after that you must reduce your push to 226 n to keep it moving at a steady 29.6 cm/s. what would its acceleration be if you maintained the push in part c?

Answers

a) The push required to give the crate an acceleration of 1.13 m/s^2 is 360.476 N.

b) If we maintain the push of 231 N, the crate would slow down with an acceleration of 1.734 m/s^2 in the opposite direction.

a) To give the crate an acceleration of 1.13 m/s^2, we need to find the net force required.

The force required to overcome static friction and just start the crate moving is given by

F_static = friction coefficient × N

where N is the normal force exerted by the floor on the crate. Since the crate is on a horizontal floor, the normal force is equal to its weight

N = m×g

where m is the mass of the crate and g is the acceleration due to gravity.

N = 45.2 kg × 9.81 m/s^2 = 443.812 N

The force required to overcome static friction is

F_static = friction coefficient × N

We know that the force required to just start the crate moving is 310 N, so the friction coefficient is

friction coefficient = F_static / N = 310 N / 443.812 N = 0.698

Once the crate is moving, the force required to keep it moving at a constant speed is equal to the force of kinetic friction

F_kinetic = friction coefficient × N = 0.698 × 443.812 N = 309.4 N

To give the crate an acceleration of 1.13 m/s^2, we need a net force of

F_net = m×a = 45.2 kg × 1.13 m/s^2 = 51.076 N

So, the force required to give the crate an acceleration of 1.13 m/s^2 is

F_push = F_net + F_kinetic = 51.076 N + 309.4 N = 360.476 N

b) If we maintain the push at 231 N, the net force on the crate would be

F_net = F_push - F_kinetic = 231 N - 309.4 N = -78.4 N

The negative sign indicates that the net force is in the opposite direction to the motion of the crate, so it would slow down with an acceleration of

a = F_net / m = -78.4 N / 45.2 kg = -1.734 m/s^2

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The given question is incomplete, the complete question is:

A crate of 45.2-kg tools rests on a horizontal floor. You exert a gradually increasing horizontal push on it and observe that the crate just begins to move when your force exceeds 310N . After that you must reduce your push to 231N to keep it moving at a steady 25.2cm/s .

a) What push must you exert to give it an acceleration of 1.13m/s^2 ? b) What would its acceleration be if you maintained the push?

17) Name two ways you could decrease the potential energy of a bucket full of water sitting on a bench.

Answers

Answer: Two ways you could decrease the potential energy of a bucket full of water sitting on a bench are: -(i) Lift it in such a way that you decrease its height as compared to the bench.(ii) Put it on a stool whose height is lower than the bench.

Explanation:

The potential energy of an object has the following formula

         Potential energy = mgh

      where m = mass of the object

                   g = acceleration due to gravity

                   h = height of the object

This means that the potential energy of an object depends upon its mass, acceleration due to gravity, and height.

In the given situation we have a bucket full of water. If the mass and acceleration due to gravity are not changed, the only way the potential energy can be decreased is by reducing the height of the bucket full of water.

This can be done by: -

         (i) Lifting the bucket full of water in such a way that you

             decrease its height as compared to the bench.

        (ii) Put the bucket full of water on a stool whose height is

            lower than the bench.

Answer:

1.By decreasing it's contents- this decreases the weight of the bucket thus decreasing the potential energy of the bucket.

2.By decreasing the height of the bench we have decreased the amount of potential energy stored in the bucket

the most abundant ingredient of the sun and jupiter is:

Answers

The most abundant ingredient in both the Sun and Jupiter is hydrogen. Hydrogen makes up about 73% of the mass of the Sun and approximately 90% of the mass of Jupiter.

The Sun and Jupiter are two vastly different celestial bodies with different compositions. The Sun is a star primarily composed of hydrogen (H) and helium (He), whereas Jupiter is a gas giant planet consisting mostly of hydrogen and helium as well, but with smaller amounts of other elements.

In the case of the Sun, hydrogen is the most abundant ingredient, making up about 74% of its mass. Helium is the next most abundant element, accounting for approximately 24% of the Sun's mass. Other elements like oxygen, carbon, neon, and iron make up less than 2% of the Sun'celestial bodiess mass combined.

In the case of Jupiter, hydrogen is the most abundant ingredient, constituting roughly 90% of its atmosphere. Helium is the second most abundant element in Jupiter, making up about 10% of its composition. Other trace elements such as methane, water vapor, ammonia, and various hydrocarbons make up less than 1% of Jupiter's composition.

It's worth noting that the exact compositions of celestial bodies like the Sun and Jupiter can vary slightly depending on factors like temperature, pressure, and depth within the body. However, hydrogen remains the dominant element in both cases.

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a dragster and a driver together have a mass of 907.6 kg. the dragster starting from rest, attains a speed of 29.2 m/s in .59 s. find the average acceleration of the dragster during this time interval.

Answers

The average acceleration of the dragster during this time interval is 49.49 m/s² when it attains a speed of 29.2 m/s.

Acceleration is the rate of change of an object's velocity.

It is the vector quantity that measures how quickly an object changes its speed and direction.

Acceleration is a measure of the rate of change of an object's velocity in physics.

The average acceleration of the dragster during this time interval can be calculated as follows:

Average acceleration = Change in velocity / Time interval

For the given problem, the change in velocity is:

Change in velocity = Final velocity - Initial velocity= 29.2 m/s - 0 m/s= 29.2 m/s

The time interval is: Time interval = 0.59 s

Now, the average acceleration can be calculated:

Average acceleration = Change in velocity / Time interval= 29.2 m/s / 0.59 s= 49.49 m/s²

Therefore, the average acceleration of the dragster during this time interval is 49.49 m/s².

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Every force applied to an object will cause the object to move.

Answers

Answer:

Yes your correct.

Explanation:

True you are right above that

(ab/bc, non-calculator) the position function 2 st t ( ) 4.9 396.9   , gives the height (in meters) of an object that has fallen from a height of 396.9 meters after t seconds. (a) explain why there must exist a time t , 1 2  t  , at which the height of the object must be 382 meters above the ground. (b) find the time at which the object hits the ground. (c) find the average rate of change in s over the intervalt 8,9. include units of measure. explain why this is a good estimate of the velocity at which the object hits the ground. how can this estimate be improved? (d) evaluate: 3 ( ) (3) limt 3 st s  t   . show the work that leads to your answer. include units.

Answers

Answer:

a)   y₁ = 392 m , y₂ = 377.3 m , t = 1.74 s ,   b)  v = 83.39.8 m/s , c) v = 88.2 m/s

Explanation:

Unfortunately some data of your statement is not clear, I will try to help you as much as possible.

The equation for free fall of a body is

        y = y₀ + v₀t -1/g  t²

As the body is released, its initial velocity is zero, the value of the acceleration of g = 9.8 m / s², the resulting equation is

       y = y₀ - 4.9 t²

a) From this equation we see that as time progresses the height decreases.

For t = 1s

        y = 396.9 -4.9 1²

        y₁ = 392 m

for t = 2 s

        y = 396.9 - 4.9 2²

        y₂ = 377.3 m

Let's find the time for the height of y = 382 m

         t = √ (y₀-y) 4.9

         t = √ [(396.9-382) / 4.9]

         t = 1.74 s

b) when the object hits the ground y = 0

       0 = y₀ - 4.9 t²

       t = √ y₀ / 4.9

       t = √ (396.9 / 4.9)

       t = 9 s

c) the rate of change of the position is the velocity,

 

t = 8 s

        y₈ = 396.9 - 4.9 8 2

        y₈ = 83.3 m

t = 9 s

        y₉= 396.9 -4.9 9 2

        y₉ = 0 m

the average exchange rate

        v = (x₈ -x₉) / Δt

       v = (83.8 -0) / 1

       v = 83.39.8 m / s

This is the average speed in the last interval so this average speed of this interval where it reaches the ground

c) The actual speed with which it reaches the ground

        v = dy / dt

        v = 2 (4.9) t

        v = 9.8 t

for t = 9s

        v = 9.8  9

        v = 88.2 m / s

How to improve these results using shorter time intervals


A train was moving along east at 25 m/s, but brakes for 3 seconds, reducing its velocity to 13 m/s east.
What was its displacement while braking?

Answers

Answer:

57 m

Explanation:

Given:

v₀ = 25 m/s

v = 13 m/s

t = 3 s

FInd: Δx

Δx = ½ (v + v₀) t

Δx = ½ (13 m/s + 25 m/s) (3 s)

Δx = 57 m

(20 points) What are wispy looking clouds, usually at high altitudes called?
stratus clouds
nimbus clouds
cirrus clouds
cumulus clouds

Answers

C , hope this helps

Answer:

the answer is c cirrus clouds

Explanation:

Block in Fig. P5.91 has a mass of 4.00 kg, and block has mass 12.0 kg. The coefficient of kinetic friction between block and the horizontal surface is 0.25. (a) What is the mass of block if block is moving to the right and speeding up with an acceleration of ? (b) What is the tension in each cord when block B has this acceleration?

Answers

(a) The mass of the block is 9.45 grams and

(b) the tension is 53.4 N

Given : mass = 4.00 kg and block mass = 12 kg

the coefficient of friction or μ = 0.25

the force can be calculated by ;

(b) F₋ = μmg

F₋ = (0.25)( 12 ) (9.8)

F₋ = 29.4 N

the total force on the block

Fₐ = ma

Fₐ = (12 )(2)

Fₐ = 24 N

F is the applied force

thus Fₐ= F - F₋

F = Fₐ + F₋

F = 24 + 29.4

F = 53.4 N

And now we can calculate the (a) part by ;

(a) F₋ - Fₐ = m₋g - 39.2

m₋g = 53.4 + 39.2

m- = 92.6/9.8

m - = 9.45 g

Thus the mass of the block is 9.45 gram

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so I'm 6'0 and I'm in high school and I'm really good at football and basketball but I only want to choose one what do yall think​

Answers

Answer:basketball

Explanation: football is a one way ticket to brain damage

A force of F= 45 N is used to drag a crate 3 m across a floor.

A force of F= 45 N is used to drag a crate 3 m across a floor.

Answers

ANSWER:

(a) 108 J

(b) 0 J

(c) 108 J

STEP-BY-STEP EXPLANATION:

(a)

Express the relation between horizontal component of work done and force on the crate:

\(W_h=F_h\cdot d\)

Here Wh is the horizontal component of the work done on the crate and Fh is the horizontal component of force and d is the distance of the crate across the floor.

Replacing:

\(\begin{gathered} W_h=36\cdot3 \\ W_h=108\text{ J} \end{gathered}\)

(b)

Express the relation between vertical component of work done and force on the crate:

\(W_v=F_v\cdot d\)

Here Wv is the vertical component of the work done on the crate and Fv is the vertical component of force and d is the distance of the crate across the floor.

Replacing:

\(\begin{gathered} W_h=27\cdot0 \\ W_h=0\text{ J} \end{gathered}\)

(c)

Express the relation for total work done by the 45 N force:

\(\begin{gathered} W_{\text{total}}=W_h+W_v \\ \text{ replacing} \\ W_{\text{total}}=108+0 \\ W_{\text{total}}=108\text{ J} \end{gathered}\)

What is a keystone species? give example

Answers

Answer:

a species on which other species in an ecosystem largely depend, such that if it were removed the ecosystem would change drastically. An example is a predator-prey relationship. If there was no more prey the predators may began to fall ill and die and if there was no more predators the prey would eventually over populate  

Explanation:

1. A runner drops her phone as she is running at a constant speed of 3 miles per hour from point A to point B in a park. Describe the motion of the phone as it is observed by someone sitting on a bench at the park.​

Answers

Answer:

Let's define the point A as our zero in the x-axis.

As the phone drops, it keeps the horizontal velocity that it had before, so the horizontal velocity is:

Vx = 3 mi/h.

Now, the only force acting on the phone is the gravitational force that acts in the vertical axis, then we have:

Ay = -g

where g = 9.8 m/s^2

It is dropped, so we do not have a vertical initial velocity, then for the vertical velocity we should integrate over time:

Vy = -g*t

And for the position again, we integrate over time, but now we have an initial position H, that is the height at which the phone is dropped.

Py = -(1/2)*g*t^2 + H

And the horizontal position can be found by integrating over time the horizontal velocity.

Px = (3mi/h)*t

This will be the two equations that describe the motion of the phone, and we can not solve it further because we do not know the initial height of the phone.

But in general, we have a linear equation in the horizontal axis and a quadratic equation with a negative leading coefficient in the vertical axis.

Position(t) = ( (3mi/h)*t,  -(1/2)*g*t^2 + H)

Answer:

yes he is running at 3 mph

Explanation:

because im the teacher

A soccer player strikes a soccer ball with a force of 550 N. If the player and the ball remain in contact for 0.03 s. What impulse was delivered to the ball by the player?

Answers

Easy my dude.
Impulse (J) is equal to the change in momentum of the ball. It is also equal to Force times Time:
J = Ft
J = (550 N)(0.03 s)
J = 16.5 Ns

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Shelley's cup of tea cooled down
1
2
of a degree in 10 minutes. At what rate is her tea cooling down

Answers

If Shelley's cup of tea cools 1/2 of a degree in 10 minutes, the rate of her tea cooling down is 0.05 degrees per minute.

10 minutes = 1 / 2 degrees

1 minute = 1 / 2 / 10 degrees

1 minute = 1 / 20 degrees

1 minute = 0.05 degrees

If a value is given for x amount of a factor, to calculate for unit amount of the factor, divide the value by the value of x. Similarly, if a value is given for unit amount of a factor, to calculate for x amount of factor, multiply the value by x.

Therefore, the rate of her tea cooling down is 0.05 degrees / minute.

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Latrice is helping build birdhouses in an effort to attract more purple martins to her area. Building purple martin birdhouses has been shown to increase the size of populations of this bird, which have declined in recent years. What limiting factor must her area have that decreases purple martin populations?

Answers

The availability of suitable nesting sites is one of the most important limiting factors for the purple martin bird population.  Building more birdhouses can help address this limiting factor and increase the size of the purple martin population in the area.

There are several limiting factors that can decrease purple martin populations, but one of the most important is the availability of suitable nesting sites. Purple martins are cavity-nesting birds, which means they require hollow spaces, such as tree cavities or specially designed birdhouses, to build their nests and raise their young. In areas where suitable nesting sites are scarce, the population of purple martins may be limited by the number of available nesting sites.

Therefore, by building more birdhouses, Latrice is addressing this limiting factor and helping to increase the size of the purple martin population in her area. Other limiting factors for purple martins may include the availability of food, the quality of habitat, and the presence of predators.

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as water begins to boil in the kettle the hotter water at the bottom of the kettle closest to the stove begins to rise and the cooler water a above sinks warms. why does the occur?

Answers

Answer:

condensation?

Explanation:

FULL IN DEPTH ANSWER

this occurs because the hotter water is atoms are expanding and becoming lighter or in other words less dense but the cold water is still the same and it’s not expending instead its atoms are closer together because it’s cold so it’s denser or heavier then the hot water so the denser cold water would sink and the lighter hot water should float on top of the cold water

SUMMARY

SO ITS MOSTLY BECAUSE OF THE DIFFERENCE IN DENSITY IN THE HOT AND COLD WATER WITH THE HOT WATER BEING LESS DENSE THEN THE COLD SO IT FLOATS
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