Answer:
L2 = 1.1994 m
the length of the pendulum rod when the temperature drops to 0.0°C is 1.1994 m
Explanation:
Given;
Initial length L1 = 1.2m
Initial temperature T1 = 27°C
Final temperature T2 = 0.0°C
Linear expansion coefficient of brass x = 1.9 × 10^-5 /°C
The change i length ∆L;
∆L = L2 - L1
L2 = L1 + ∆L ...........1
∆L = xL1(∆T)
∆L = xL1(T2 - T1) ......2
Substituting the given values into equation 2;
∆L = 1.9 × 10^-5 /°C × 1.2m × (0 - 27)
∆L = 1.9 × 10^-5 /°C × 1.2m × (- 27)
∆L = -6.156 × 10^-4 m
From equation 1;
L2 = L1 + ∆L
Substituting the values;
L2 = 1.2 m + (- 6.156 × 10^-4 m)
L2 = 1.2 m - 6.156 × 10^-4 m
L2 = 1.1993844 m
L2 = 1.1994 m
the length of the pendulum rod when the temperature drops to 0.0°C is 1.1994 m
An 8.0 Kg mass is placed at = 3 where should a 10 Kg mass be placed along the − so that the center of mass will be located ay = 4.5?
Answer:
Therefore, the 10 kg mass should be placed at x = 5.7 m along the x-axis to achieve a center of mass located at y = 4.5 m.
Explanation:
To find the position along the x-axis where a 10 kg mass should be placed such that the center of mass is located at y = 4.5, we can use the formula for the center of mass:
x_cm = (m1 * x1 + m2 * x2) / (m1 + m2)
Here, m1 and x1 represent the mass and position of the 8 kg mass, respectively. m2 is the mass of the 10 kg mass, and we need to find x2, its position.
Given:
m1 = 8 kg
x1 = 3 m
x_cm = unknown (to be found)
m2 = 10 kg
y_cm = 4.5 m
Since the center of mass is at y = 4.5, we only need to consider the y-coordinate when calculating the center of mass position along the x-axis.
To solve for x2, we can rearrange the formula as follows:
x2 = (x_cm * (m1 + m2) - m1 * x1) / m2
Substituting the given values:
x2 = (x_cm * (8 kg + 10 kg) - 8 kg * 3 m) / 10 kg
Simplifying:
x2 = (x_cm * 18 kg - 24 kg*m) / 10 kg
Now, we can set the y-coordinate of the center of mass equal to 4.5 m and solve for x_cm:
4.5 m = (8 kg * 3 m + 10 kg * x2) / (8 kg + 10 kg)
Simplifying:
4.5 m = (24 kg + 10 kg * x2) / 18 kg
Multiplying both sides by 18 kg:
81 kg*m = 24 kg + 10 kg * x2
Subtracting 24 kg from both sides:
10 kg * x2 = 81 kg*m - 24 kg
Dividing both sides by 10 kg:
x2 = (81 kg*m - 24 kg) / 10 kg
Simplifying:
x2 = 8.1 m - 2.4 m
x2 = 5.7 m
(brainlest?) ples:(
Answer:
the 10 kg mass should be placed at x = -2.4 m to achieve a center of mass at y = 4.5 m.
Explanation:
To find the position along the x-axis where the 10 kg mass should be placed so that the center of mass is located at y = 4.5, we can use the principle of the center of mass.
The center of mass of a system is given by the equation:
x_cm = (m1x1 + m2x2) / (m1 + m2),
where x_cm is the x-coordinate of the center of mass, m1 and m2 are the masses, and x1 and x2 are the positions along the x-axis.
Given:
m1 = 8 kg,
x1 = 3 m,
m2 = 10 kg,
y_cm = 4.5 m.
To solve for x2, we need to find the x-coordinate of the center of mass (x_cm) by using the y-coordinate:
y_cm = (m1y1 + m2y2) / (m1 + m2),
where y1 and y2 are the positions along the y-axis.
Rearranging the equation and substituting the given values:
4.5 = (83 + 10y2) / (8 + 10).
Simplifying the equation:
4.5 = (24 + 10*y2) / 18.
Multiplying both sides by 18:
81 = 24 + 10*y2.
Rearranging the equation:
10*y2 = 81 - 24,
10*y2 = 57.
Dividing both sides by 10:
y2 = 5.7.
Therefore, the y-coordinate of the 10 kg mass should be 5.7 m.
To find the x-coordinate of the 10 kg mass, we can use the equation for the center of mass:
x_cm = (m1x1 + m2x2) / (m1 + m2).
Substituting the given values:
x_cm = (83 + 10x2) / (8 + 10).
Since the center of mass is at x_cm = 0 (the origin), we can solve for x2:
0 = (83 + 10x2) / (8 + 10).
Rearranging the equation:
83 + 10x2 = 0.
24 + 10*x2 = 0.
10*x2 = -24.
Dividing both sides by 10:
x2 = -2.4.
A rocket has a mass of 156,789 kg and is traveling at 45.6 m/s. How much kinetic energy does the rocket
possess?
Explanation:
K.E =1/2 mv^2
=1/2(156789)(45.6)^2
=78,394.5 × 2,079.36
=163,010,387.52 kg m/s
This should be your answer.
What causes a compass needle to point to geographic north?
a. The force of Earth's rotation causes the needle of the compass to seek the north pole.
b. The pole of the compass is attracted to Earth's Geographic North Pole.
Selected:c. The compass needle aligns with Earth's magnetic field.
d. all of the answer choices are correct
A 2kg ball is rolled along the floor for 0.8 m at a constant speed of 6 m/s. What is the work done by gravity?
A, 0
B, 16 J
C, 72 J
D, 450 J
E, 90 J
=F×s×cosa=2×g×0,8×cos90°= 0
The work done by gravity on a ball of 2 kg which is moving with a constant speed of 6 meter per second is zero. Thus, the correct option is A.
What is Work?Work is the energy transfer to or from an object through the application of force along with the displacement. For a constant force aligned with the direction of motion, the work done is equal to the product of the force strength which is applied and the distance traveled by the object.
Work = Force × Displacement
Force = Mass × Acceleration
Acceleration of the ball is zero as it is moving with a constant speed. Therefore, the work done by the gravity is zero.
Therefore, the correct option is A.
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PLEASE ANSWER 50 points
A car manufacturer wants to change its car’s design to increase the car’s acceleration. Which changes should the engineers consider making to the design?
O increase the force that the engine provides
O decrease the force that the engine provides
O increase the mass of the car
O decrease the mass of the car
O increase the top velocity the car can travel
O decrease the top velocity the car can travel
A spherical balloon is made from a material whose mass is 4.30 kg. The thickness of the material is negligible compared to the 1.54-m radius of the balloon. The balloon is filled with helium (He) at a temperature of 289 K and just floats in air, neither rising nor falling. The density of the surrounding air is 1.19 kg/m3. Find the absolute pressure of the helium gas.
Answer:
P = 5.97 × 10^(5) Pa
Explanation:
We are given;
Mass of balloon;m_b = 4.3 kg
Radius;r = 1.54 m
Temperature;T = 289 K
Density;ρ = 1.19 kg/m³
We know that, density = mass/volume
So, mass = Volume x Density
We also know that Force = mg
Thus;
F = mg = Vρg
Where m = mass of balloon(m_b) + mass of helium (m_he)
So,
(m_b + m_he)g = Vρg
g will cancel out to give;
(m_b + m_he) = Vρ - - - eq1
Since a sphere shaped balloon, Volume(V) = (4/3)πr³
V = (4/3)π(1.54)³
V = 15.3 m³
Plugging relevant values into equation 1,we have;
(3 + m_he) = 15.3 × 1.19
m_he = 18.207 - 3
m_he = 15.207 kg = 15207 g
Molecular weight of helium gas is 4 g/mol
Thus, Number of moles of helium gas is ; no. of moles = 15207/4 ≈ 3802 moles
From ideal gas equation, we know that;
P = nRT/V
Where,
P is absolute pressure
n is number of moles
R is the gas constant and has a value lf 8.314 J/mol.k
T is temperature
V is volume
Plugging in the relevant values, we have;
P = (3802 × 8.314 × 289)/15.3
P = 597074.53 Pa
P = 5.97 × 10^(5) Pa
bus travels 6 km east and then 8 km south. What is the displacement?
Answer:
d = √(6² + 8²) = 10 km
Explanation:
displacement is a vector and subject to vector addition.
Question
1 point
An object of mass 8.0 kg is falling vertically through the air. The drag force acting on the object is 60N. What is the best estimate of the acceleration of
the object?
Answer:
here's the pdf for it
IB QuestionbankExplanation:
What is the equivalent temperature in kelvin if you have a metal at 50°F?
A.
50 K
B.
150 K
C.
283 K
D.
300 K
Answer:
The answer is C 283 kelvin
Answer: C.
283 K
Explanation: edmentum
Part B: Choose the best explanation from among the following: - Truck has more mass, and hence the force exerted on it it greater - The massive truck exerts a greater force on the lightweight car - Action-reaction forces always have equal magnitude
Solution
The answer would be "Equal to"
These forces from an action-reaction pair, and hence the force experienced by the car has the same magnitude as the force experienced by the truck.
For part B, the answer would be:
Action-reaction forces always have equal magnitude.
List the 6 questions you may apply to formulating a logical, reasonable perspective to any situation.
Steps to formulate a logical, reasonable perspective to any situation are: gather information, identify problem, analyze the situation, consider assumptions, generate solutions, evaluate options, consider your values, make decision and monitor and adjust
What are the 6 questions that may be applied to formulate logical, reasonable perspective to any situation?Here are the six questions that you can apply to formulating a logical, reasonable perspective to any situation:
What are the issues that should be addressed?
What are the relevant facts and data related to this problem or issue?
What assumptions am I making about the problem or issue?
What are the possible solutions or outcomes, and what are the pros and cons of each?
What are my values and priorities related to this problem or issue?
What additional information do I need to make an informed decision or come to a reasonable conclusion?
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1. Given the following vectors: A=(2i+6 j-4k|m, B=(4i-5j-3k)m and C=i+3j-2km. a) Find a unit vectors in the direction of i) A+B ii) A× B iii) 2 A+3C b) Find the magnitude of the following vectors: i) A+B ii) A× B iii) 3A-2C c) Find the angle between the following vectors: i) A× B and Bx A ii) A and C iii) B and C.
In this solution, the unit vectors in the directions of A + B, A × B, and 2A + 3C are √62,√1915, and √686. The magnitudes of A + B, A × B, and 3A - 2C are √62, √1915, and √164. The angles between A × B and B × A, A and C, and B and C are √30, cos-1(4/√35), and cos-1(-1/√14).
a) i) The unit vector in the direction of A + B is given by: A + B = (2i + 6j - 4k)m + (4i - 5j - 3k)m = 6i + j - 7k | 6² + 1² + (-7)²= 62|AB= √62We can now find the unit vector in the direction of A + B as follows:AB = (6/AB)i + (1/AB)j + (-7/AB)k= (6/√62)i + (1/√62)j + (-7/√62)kB)ii) The magnitude of the cross product A × B is given by: A × B = (-27i - 14j + 26k)m² | √(27² + 14² + 26²) = √1915|AB= √1915We can now find the unit vector in the direction of A × B as follows: AB = (-27/√1915)i + (-14/√1915)j + (26/√1915)kC) iii) The unit vector in the direction of 2A + 3C is given by: 2A + 3C = (2 x 2i + 2 x 6j - 2 x 4k)m + (3i + 9j - 6k)m= 7i + 21j - 14k | √(7² + 21² + (-14)²) = √686|AB= √686We can now find the unit vector in the direction of 2A + 3C as follows: AB = (7/√686)i + (21/√686)j + (-14/√686)kb) i) The magnitude of A + B is given by: A + B = (2i + 6j - 4k)m + (4i - 5j - 3k)m= 6i + j - 7k | AB= √62 | √(6² + 1² + (-7)²) = √62We can find the magnitude of A + B as follows: AB = √62ii) The magnitude of A × B is given by: A × B = (-27i - 14j + 26k)m² | AB= √1915We can find the magnitude of A × B as follows: AB = √1915iii) The magnitude of 3A - 2C is given by: 3A - 2C = (3 x 2i + 3 x 6j - 3 x 4k)m - (2i + 6j - 4k)m= 4i + 12j - 2k | AB= √164 | √(4² + 12² + (-2)²) = √164We can find the magnitude of 3A - 2C as follows:AB = √164c) i) The angle between A × B and B × A is 180°. ii) The angle between A and C is given by: A · C = (2i + 6j - 4k)m · (i + 3j - 2k)m= 2 + 18 + 8 = 28 |AB = √56 |AC = √30We can find the angle between A and C as follows:θ = cos-1((A · C)/(AB x AC))= cos-1(28/(√56 x √30))= cos-1(4/√35)iii) The angle between B and C is given by: B · C = (4i - 5j - 3k)m · (i + 3j - 2k)m= 4 - 15 + 6 = -5 |AB = √56 |BC = √30We can find the angle between B and C as follows:θ = cos-1((B · C)/(AB x BC))= cos-1(-5/(√56 x √30))= cos-1(-1/√14)The summary of the solution is that for the given vectors A, B, and C we have been able to find the unit vectors in the direction of A+B, A×B, and 2A+3C. The magnitudes of A+B, A×B, and 3A-2C have also been found. Finally, we have also been able to find the angles between A×B and B×A, A and C, and B and C.For more questions on unit vectors
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find the rms speed of a sample of oxygen at 30° C and having a molar mass of 16 g/mol.
At 30°C, the rms speed of a sample of oxygen with a molar mass of 16 g/mol is approximately 482.34 m/s.
The root mean square (rms) speed of a gas molecule is a measure of the average speed of the gas particles in a sample. It can be calculated using the formula:
vrms = √(3kT/m)
Where:
vrms is the rms speed
k is the Boltzmann constant (1.38 x 10^-23 J/K)
T is the temperature in Kelvin
m is the molar mass of the gas in kilograms
To calculate the rms speed of oxygen at 30°C (303 Kelvin) with a molar mass of 16 g/mol, we need to convert the molar mass to kilograms by dividing it by 1000:
m = 16 g/mol = 0.016 kg/mol
Substituting the values into the formula, we have:
vrms = √((3 * 1.38 x 10^-23 J/K * 303 K) / (0.016 kg/mol))
Calculating this expression yields the rms speed of the oxygen sample:
vrms ≈ 482.34 m/s
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A 0.0780 kg lemming runs off a
5.36 m high cliff at 4.84 m/s. What
is its potential energy (PE) when it
lands?
The potential energy of the lemming when it lands is 0.9108672 J.
To determine the potential energy (PE) of the lemming when it lands, we need to consider the conservation of energy. The potential energy of an object is given by the formula PE = mgh, where m is the mass of the object, g is the acceleration due to gravity, and h is the height.
Given:
Mass of the lemming (m) = 0.0780 kg
Height of the cliff (h) = 5.36 m
First, let's calculate the potential energy when the lemming is on the cliff. Using the given formula, we have:
PE = mgh
PE = 0.0780 kg * 9.8 m/s² * 5.36 m
PE = 0.413616 J
Next, we need to determine the final kinetic energy of the lemming just before it lands. We can use the equation for kinetic energy (KE) given by KE = (1/2)mv², where v is the velocity of the lemming.
Given:
Velocity of the lemming (v) = 4.84 m/s
Calculating the kinetic energy, we have:
KE = (1/2) * 0.0780 kg * (4.84 m/s)²
KE = 0.9108672 J
According to the conservation of energy, the potential energy at the top of the cliff is equal to the kinetic energy just before landing.
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In what ways does ecotourism help living things in ecosystems?
Ecotourism has the potential to eliminate the requirement to hunt wildlife for a living. Ecotourism generates revenue by maintaining the rainforest; deforestation is discouraged because it reduces tourist revenue.
What role does ecotourism play in biodiversity conservation?Ecotourism firms safeguard biodiversity by preserving animals in their natural habitats and preserving natural ecosystems in biosphere reserves, wildlife sanctuaries, and national parks.
Can tourism save the environment?Ecotourism contributes to the preservation of a destination's ecological and biological diversity. For example, since Costa Rica's jungle is so popular with visitors, inhabitants work hard to protect it instead of attempting deforest it for a short-term profit.
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What happens to the sunlight that does not reach Earth’s surface?
Two identical loudspeakers 2.30 m apart are emitting sound waves into a room where the speed of sound is 340 m/s. Abby is standing 3.00 m in front of one of the speakers, perpendicular to the line joining the speakers, and hears a maximum in the intensity of the sound. Part A What is the lowest possible frequency of sound for which this is possible
Answer:
1089.74 Hz
Explanation:
Using Pythagoras theorem, we can find the distance from the point to the second speaker.
Thus;
d2 = √(3² + 2.3²)
d2 = √(9 + 5.29)
d2 = √14.29
d2 = 3.78 m
Then, the path distance which is the extra distance travelled would be;
Δd = d2 - d1
Δd = 3.78 - 3
Δd = 0.78 m
Now, the destructive interference condition is given by the formula;
Δd = (m + ½)λ
λ is the wavelength
m is a non - negative integer.
In this case, m = 2
Thus;
0.78 = (2 + ½)λ
λ = 0.78/(2½)
λ = 0.312 m
Now the formula for frequency of a wave is given by;
f = v/λ
Where v is speed of sound.
Thus;
f = 340/0.312
f = 1089.74 Hz
50 POINTS ANSWEr CORRECT Explain how all the other elements heavier than iron are formed after the death of the star?
Answer:
Elements heavier than iron are formed by neutron capture processes during stellar death and supernovae.
Explanation:
Most of the elements heavier than iron are formed during the death of stars through neutron capture processes, specifically the R-Process and the S-Process. The R-Process is a rapid capture of neutrons, while the S-Process is a slow capture of neutrons. These processes either directly form elements or indirectly form them through decay processes [^1]. Elements heavier than iron are primarily made in environments with free-neutron densities in excess of a million particles per cubic centimeter [^2]. In the extreme energetic conditions of supernovae, atoms are bombarded by a very large number of neutrons, and rapid successive neutron capture, followed by beta decay, produces the heavier atoms [^5].
So, elements heavier than iron are formed by neutron capture processes during stellar death and supernovae.
[^1
Sound travels through air at a speed of 342m/s
342
m
/
s
at room temperature. What is the frequency of a sound wave with a wavelength of 1.8m
1.8
m
Answer:
Explanation:
The formula relating the speed of sound, frequency, and wavelength is:
speed = frequency x wavelength
Rearranging this formula to solve for frequency:
frequency = speed / wavelength
Substituting the given values:
frequency = 342 m/s / 1.8 m
frequency = 190 Hz
Therefore, the frequency of the sound wave is 190 Hz.
In the picture shown below A represents a characteristic of only geocentric model, B represents a characteristic common to both geocentric and heliocentric models, C represents a characteristic of only heliocentric model, and D represents a characteristic which the geocentric and heliocentric models do not have.
Under which label will the characteristic, "The sun and planets revolve around a central moon in the solar system" fall?
A
B
C
D
PLEASE HELP
How many days does it take Mars to orbit the Sun ? It is 1.52 au from the Sun. Saturn is 9.54 au from the sun and takes 29.5 years to orbit the Sun.
thank you!!!
Answer:
284 the mars of the earth goes to work
The distance and direction in which an object travels per unit of time. A. velocity B. magnitude C. speed
Answer:
Answer is C. Speed
a 2.75 kg box is pushed across the floor with a force of 15 N. it experiences a frictional force of 8 N. calculate the acceleration of the box
Answer:
Acceleration is 2.55m/s²
Explanation:
Force(F)=mass of object(m) ×acceleration(a)
in the scenario above,a force of 15N is used to push the box and because the floor is not having a smooth surface,frictional force(8N) will oppose the 15N used to push the box thereby decreasing the acceleration. so the actual force moving the box is 7N.
Force =Normal Force - Frictional Force
F= 15N - 8N
F= 7N
therefore the 7N is the actual force causing the box to move.
To find the acceleration,insert the mass of the box and the actual force into the formula (F=m×a)
F=m×a
7N =2.75kg × a
make a the subject by dividing both sides of the equation by 2.75kg.
7/2.75 = (2.75×a)/2.75
a= 7/2.75
therefore a= 2.55m/s²,where a is the Acceleration.
A stone whirled at the end of a rope 30cm long makes 5revs. Find the linear speed?
The stone moves at a linear speed of 9.42 m/s.
How is linear velocity determined?Where v stands for speed, d for distance, and t for time, the equation for linear velocity is v = d/t. The SI unit for linear velocity is the metre per second, abbreviated as m/s (ms-1).
The circumference of the circle the stone traces and the distance the stone travels in one revolution are equal.
C = 2πr
where r is the rope's length. If we substitute r = 30 cm, we obtain:
C = 2π(30 cm) ≈ 188.5 cm
As a result, one revolution of the stone moves it approximately 188.5 cm.
The stone moves a total of five times, covering the following distance:
d = 5(188.5 cm) = 942.5 cm
v = d/t
Let's say the stone makes 5 revolutions in t seconds. The linear speed is then:
v = d/t = 942.5 cm/t
To obtain the answer in milliseconds, we can convert the quantities to metres and seconds:
v = 9.425 m/t
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A transverse sinusoidal wave is traveling rightward along a string stretched along the X-direction. The wavelength is 70.0 cm and 8.00 wave peaks per second pass any fixed point on the string. The maximum speed of the string particles in the direction perpendicular to the string is 3.20 m/s. At time t 0, the element of string at x = 20.0 cm is 4.00 cm above its resting position. (a) Construct two distinct wave functions yfx,t) consistent with the given information. (If the only difference between two wavefunctions is that their phase constants differ by an integer multiple of 2n, then they are not distinct.) (b) Sketch both of these wavefunctions for time t 0 between x 0 and x A har 2 20 /s A= 0.0Ch 560 Ch a)yo) Acos CRxt wt +o) w- 2TF : 50 265 S A Vwa 3 20 5a.2655 =0.0656n 0.7854
Answer:
1111
1Explanation:
111111
1
De que esta hecho el sol? plisss ayuda.no necesito un texto de 100 reglones, puede ser resumido en solo 2 renglones
Ernie speed walks at the rate of 20m/s in 5 seconds. Calculate the distance he traveled
Answer:
4m
Explanation:
you divide 20m/s by 5 seconds
Three Small Identical Balls Have Charges -3 Times 10^-12 C, 8 Times 10^12 C And 4 Times 10^-12 C Respectively. They Are Brought In Contact And Then Separated. Calculate Charge On Each Ball.
Answer:
The charge in each ball will be 3 * 10^-12 C
Explanation:
(Assuming the correct charge of the second ball is 8 * 10^-12)
When the balls are brought in contact, all the charges are split evenly among then.
So first we need to find the total charge combined:
(-3 * 10^-12) + (8 * 10^-12) + (4 * 10^-12) = 9 * 10^-12 C
Then, when the balls are separated, each ball will have one third of the total charge, so in the end they will have the same charge:
(9 * 10^-12) / 3 = 3 * 10^-12 C
So the charge in each ball will be 3 * 10^-12 C
does the speed of a EM wave depend on its frequency
Answer:
The speed of a wave is independent of its frequency and wavelength. A change in the frequency value will not result in a change in the speed value. Rather, changing frequency will cause a change in the wavelength in such a manner that the speed value turns out the same.
Explanation:
Answer:
no
Explanation:
i NED HELP i’m so confused