A given wire of resistance 10ohms has a length of 5m and a cross sectional area of four multiple by ten raise to power minus three meter square.Calculate the conductivity of the wire (ssce June 1995)

An object dropped from rest, its velocity be 294 m/s in downward direction after 30 s .

Kinematics is the study of the motion of mechanical points, bodies and systems without consideration of their associated physical properties and the forces acting on them.

initial velocity = u =  0

time = t = 30sec

g = acceleration due to gravity = 9.8 \(m/s^{2}\)

using equation of kinematics

v = u - g*t

v = 0 - 9.8 * 30

v = - 294 m/s

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Answer:

a) Volt

Explanation:

The standard metric unit on electric potential difference is the volt.

answer

all of the above

explanation

as we know that the si unit of potential difference is volt

which is equal to j/c and j/c is equal to j/a.s so the correct answer is all of the above

Let's calculate the equivalent resistances on both circuits.

On Diagram A we have a series connection of the resistors. The equivalent resistance will be the sum of all resistances:

\(R_{eq}=1+1+1\\\\\boxed{R_{eq}=3\Omega}\)

On diagram B we have a parallel connection of the resistors. The reciprocal of the equivalent resistance will be the sum of the reciprocals of all the resistances:

\(\frac{1}{R_{eq}} = \frac{1}{1} +\frac{1}{1} +\frac{1}{1} \\\frac{1}{R_{eq}}=3\\\\\boxed{R_{eq}=\frac{1}{3}}\)

Therefore, the larger resistance occurs on diagram A.

For the current, recall

\(V=IR\)

Where \(I\) stands for current \(R\) is the resistance and \(V\) is the voltage. Rearranging the equation we have

\(I = \frac{V}{R}\)

We can see that the larger the resistance, the smaller the current gets. So the larger current must happen in the diagram with smaller resistance. Therefore, the larger current occurs on diagram B.

Glad to help, wish you great studies ;)

Mark brainliest if you deem the answer worthy

Answer:

Explanation: The density of gas differentiates all the varieties of gas present in the atmosphere.

HYDROGEN- it is a lighter gas having a lesser density.

For example, a hydrogen balloon displaces the air around it thus making it rise.

CARBON DIOXIDE: It is a denser gas as it makes the balloon heavier than the air pressure around it thus making it sink.

I hope the explanation was helpful. :)

Answer:

B. 24.2 m/s

Explanation:

Given;

mass of the roller coaster, m = 450 kg

height of the roller coaster, h = 30 m

The maximum potential energy of the roller coaster  due to its height is given by;

\(P.E_{max} = mgh\\\\PE_{max} = 450 *9.8*30\\\\PE_{max} = 132,300 \ J\)

\(P.E_{max} = K.E_{max} \ (law \ of \ conservation\ of \ energy)\)

\(K.E_{max} = \frac{1}{2}mv_{max}^2\\\\ v_{max}^2 = \frac{2K.E_{max}}{m}\\\\ v_{max}^2 = \frac{2*132300}{450}\\\\ v_{max}^2 =588\\\\v_{max} = \sqrt{588}\\\\ v_{max} = 24.2 \ m/s\)

Therefore, the maximum speed of the roller coaster is 24.2 m/s.

Answer:

1. 24.2 m/s

2. 20.4 m

3. 22.5 m/s

4. 109,375 J

5. It is easy to calculate new scenarios.

Explanation:

5/5 on the Maximum Energy Quick Check

a) For n=5, it takes 9 moves to turn all the lights off.

b) For any n, the number of moves required to turn off all initial value s is n + \(2^(n-1) - 2\). The recurrence relation is: \(f(n) = f(n-1) + 2^(n-1)\) with initial value f(1) = 1.

a) For n = 5, we can represent the lights as follows:

1 - on

2 - on

3 - on

4 - on

5 - on

To turn off the fifth light, we need to turn off lights 2, 3, 4, and 5, in that order. This takes 4 moves.

1 - on

2 - off

3 - off

4 - off

5 - off

Now, to turn off the fourth light, we need to turn off lights 2 and 4, in that order. This takes 2 more moves.

1 - on

2 - off

3 - off

4 - off

5 - off

Next, we turn off the third light, requiring only one move:

1 - on

2 - off

3 - off

4 - off

5 - off

Then we turn off the second light, again requiring only one move:

1 - on

2 - off

3 - off

4 - off

5 - off

Finally, we turn off the first light, which can be done in one move:

1 - off

2 - off

3 - off

4 - off

5 - off

Thus, it takes a total of 4 + 2 + 1 + 1 + 1 = 9 moves to turn off all 5 lights.

b) Let M(n) be the number of moves required to turn off n lights. To turn off the last light, we need to turn off all the preceding lights, so we first need to turn off the (n-1)th light. This requires M(n-1) moves.

Then, we need to turn off the (n-2)nd light, which requires M(n-2) moves, and so on, until we turn off the first light, which requires 1 move. Therefore, we can write the recurrence relation:

M(n) = M(n-1) + M(n-2) + ... + M(2) + M(1) + 1

with the initial condition M(1) = 1.

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The equator of jupiter rotates slower than the great red spot. This statement is false.

The equator of Jupiter rotates faster than the Great Red Spot. Jupiter is a gas giant with a rapid rotation rate, completing a full rotation on its axis in about 10 hours. This fast rotation creates strong winds and atmospheric dynamics on the planet. The Great Red Spot is a persistent high-pressure storm on Jupiter that has been observed for centuries. While the exact rotation period of the Great Red Spot can vary, it generally takes about 6 days to complete one rotation. Therefore, the equator of Jupiter rotates faster than the Great Red Spot.

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Answer:

T=502.5N

Ax=171.8N

Explanation:

The computation of the tension T in the rope and the forces exerted by the pin at A is shown below:

vertical forces sum = Ay + Tsin20 + T - 245 - 883 = 0

Now  

horizontal forces sum = Ax - Tcos70

Now Moment about B

-Ay × 4.8 + 245 × 2.4 + 883 × 1.8=0

Ay=453.6N

Now substitute in sum of vertical forces T=502.5N

Ax=171.8N

a. The tension (T) in the rope is equal to 502.51 Newton.

b. The forces exerted by the pin at A is equal to 171.86 Newton.

Given the following data:

To calculate the tension (T) in the rope and the forces exerted by the pin at A:

First of all, we would determine the vertical force by taking moment about point B as shown in the diagram.

\(-A_y \times 4.8 + 883 \times 1.8 + 245 \times 2.4 =0\\\\-4.8A_y + 1589.4 + 588 =0\\\\4.8A_y= 3237\\\\A_y=\frac{2177.4}{4.8} \\\\A_y= 453.63 \;Netwon\)

The tension (T) in the rope would be calculated by the sum of the vertical component of forces, which is given by:

\(\sum F_x = A_y + Tsin20 + T - 245 - 883 = 0\\\\453.63 + 0.3420T + T -1128=0\\\\1.3420T = 1128-453.63\\\\1.3420T =674.37\\\\T =\frac{674.37}{1.3420}\)

Tension, T = 502.51 Newton.

To find the forces exerted by the pin at A, we sum the vertical component of forces, which is given by:

\(\sum F_y = A_x - Tcos70 =0\\\\A_x =Tcos70\\\\A_x = 502.51 \times cos70\\\\A_x = 502.51 \times 0.3420\\\\A_x = 171.86\;Newton\)

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The answers are physically and mathematically reasonable, since both have the same order of magnitude of the external forces shown in the figure.

Let be a system at equilibrium, which mathematically is represented by the following formulas:

\(\Sigma F = 0\) (1)

\(\Sigma M = 0\) (2)

We construct equations around points A and B by Newton's Laws and D'Alembert Principle:

\(\Sigma M = F_{B}\cdot (1\,m)-(3000\,kgf)\cdot (2\,m)-(10000\,kgf)\cdot (6\,m) = 0\) (3)

\(\Sigma M = -F_{A,x}\cdot (1\,m) - (3000\,kgf)\cdot (2\,m)-(10000\,kgf)\cdot (6\,m) = 0\) (4)

\(\Sigma F_{x} = F_{A,x} + F_{B} = 0\) (5)

\(\Sigma F_{y} = F_{A,y} -3000\,kgf-10000\,kgf = 0\) (6)

The solution of the entire system is: \(F_{A,x} = -66000\,kgf\), \(F_{B} = 66000\,kgf\) and \(F_{A,y} = 13000\,kgf\).

The magnitude of the force acting on the crane at point A is determined by the Pythagorean theorem:

\(F_{A} = \sqrt{(-66000\,kgf)^{2}+(13000\,kgf)^{2}}\)

\(F_{A} \approx 67268.120\,kgf\)

The force acting on the crane at point A has a magnitude of approximately 67268.128 kilograms-force. \(\blacksquare\)

The force acting on the crane at point B has a magnitude of approximately 66000 kilograms-force. \(\blacksquare\)

The answers of parts (a) and (b) have an order of magnitude of \(10^{3}\), the same order of magnitude of the external forces shown in the figure. Hence, those answers are physically and mathematically reasonable.

Figure is missing. The statement is incomplete. Complete statement is presented below:

A 3000 kilograms-force is supporting a 10000 kilograms-force crate. The crane pivots about point A and is at rest pressed against a support at B.

(a) FInd the force acting on the crane at point A.

(b) Find the force acting on the crane at point B.

(c) Use order of magnitude sense-making to determine the reasonableness of your answers to parts (a) and (b). Hint: consider how the lever arm to the crate  is much different than that to other points.

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The net force on the middle charge due to the four other charges is zero.

The given parameters:

The magnitude of the force on the middle charge due to the four other charges is calculated as follows;

\(F_0{net} = F_{01} + F_{02} + F_{03} + F_{04}\\\\F_0{net} = \frac{k\times q_0(-q_1)}{r^2} + \frac{k\times q_0(q_2)}{r^2} + \frac{k\times q_0(q_3)}{r^2} + \frac{k\times q_0(-q_4)}{r^2}\\\\F_0{net} = - \frac{k\times q_0q_1}{r^2} + \frac{k\times q_0q_2}{r^2} + \frac{k\times q_0q_3}{r^2} - \frac{k\times q_0q_4}{r^2}\\\\F_0{net} = \frac{kq_0}{r^2} (-q_1 + q_2 + q_3 - q_4)\\\\recall, \ |q_1| = q_2 = |q_3| = |q_4| = 2 \ nC\\\\F_0{net} = \frac{kq_0}{r^2} (-2 + 2+ 2-2)\\\\F_0{net} = \frac{kq_0}{r^2}(0)\\\\\)

\(F_0{net} = 0\)

Thus, the net force on the middle charge due to the four other charges is zero.

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Answer:

The difference in tension,  between adjacent sections of the pull cable at the given conditions is 17.701 kN

Explanation:

We take the cars as moving upwards such that the resultant pulling force on the car, F, along the cable is given by the relation

\(F_{car}\) = Upward tension force,  \(Tension_{(upwards)}\) - Downward tension force, \(Tension_{(downwards)}\) - Component of the weight of the car along the taut cable

The parameters given are;

Mass of car, m = 2750 kg

Angle of inclination of taut cables, θ = 35°

The upward acceleration of the car, a = 0.81 m/s²

Given that the weight is acting vertically downwards, we have;

Component of the weight of the car along the taut cable = m × g × sin(θ)

∴ Component of the weight of the car along the taut cable = 2750 × 9.81 × sin (35°) = 15473.66 N

We therefore have;

\(F_{car}\) =  \(Tension_{(upwards)}\) - \(Tension_{(downwards)}\) - 15473.66 N

\(F_{car}\)  = m × a = 2750 × 0.81 =  \(T_{upwards}\) - \(T_{downwards}\) - 15473.66

∴  \(Tension_{(upwards)}\) - \(Tension_{(downwards)}\) = 2750 × 0.81 + 15473.66 = 17701.16 N

Hence the difference in tension,  \(Tension_{(upwards)}\) - \(Tension_{(downwards)}\) between adjacent sections of the pull cable if the cars are at the maximum permissible mass and are being accelerated up the incline = 17701.16 N or 17.701 kN.

Given that the balloon is negatively charged and it is touching a wooden wall, the ballon will perform all the actions given in the answer choices.

A negatively charged balloon will pull positive charge on the wall surface towards it, since opposite charges attract each other.

Also, the negatively charged balloon touching a wooden wall will push any negative charge in the wall away from it. This is because like charges repel each other.

The negatively charged balloon also polarizes the molecules on the wall. This is because in molecules, atoms are bonded together since protons in one atom attract the electrons in the cloud of another atom.

Therefore, the correct choice is All of the above

ANSWER:

All of the above

Answer:

25.5m/s

Explanation:

0+9.8(2.60)=25.48=25.5m/s

The type of light that best illustrates the photoelectric effect is (c) ultraviolet light. Hence, the correct answer is option c).

Photoelectric effect refers to the emission of electrons from a metallic surface when a light of suitable frequency shines on the surface of the metal. The phenomenon, first noticed by Heinrich Hertz in 1887, was explained in 1905 by Albert Einstein when he used Planck's hypothesis to illustrate that light energy is carried in discrete quantized packets to describe the photoelectric effect.

In relation to photoelectric effect, the type of light that best illustrates it is ultraviolet light. This is because ultraviolet light has a high enough frequency to remove electrons from the metal surface. As a result, electrons that absorb photons with enough energy from the ultraviolet region of the electromagnetic spectrum will be ejected from the metal, causing the photoelectric effect, and producing an electric current.

When light is shone on a metallic surface, an electric current is produced, which is called the photoelectric effect. The photoelectric effect is caused by the emission of electrons from a metal surface that is exposed to a light of suitable frequency. The energy of the electrons depends on the frequency of the light, and the intensity of the light determines the number of electrons ejected from the surface.

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the force between the two wires if they are separated by 2.50 cm is 0.525 N.

Given that force F between two parallel wires carrying electric currents is inversely proportional to the distance d between the wires and that a force of 0.750 N exists between wires that are 1.75 cm apart and that we are supposed to find the force between them if they are separated by 2.50 cm.

Let the initial force be F₁ and the initial distance be d₁.

Therefore, we can write the relationship between force and distance as;

F₁d₁ = F₂d₂

Where

;F₁ = 0.750 N (initial force)

d₁ = 1.75 cm (initial distance)

F₂ = ? (force at new distance)

d₂ = 2.50 cm (new distance)

Let us find F₂;F₁d₁ = F₂d₂F₂ = F₁d₁/d₂

Now substitute the values we know;

F₂ = (0.750 N x 1.75 cm) / 2.50 cmF₂ = 0.525 N

Therefore, the force between the two wires if they are separated by 2.50 cm is 0.525 N.

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Answer:

a, 4

b, 3

c, 6

d, 3

e, 3

f, 3

g, ambiguous

h,

A beam of light of the pure color red is made up of photons of the lowest energy.

A beam of light made up of photons with the lowest energy corresponds to the pure color red. Red light has the longest wavelength and lowest frequency, resulting in the least amount of energy among the visible light spectrum.

The pure colour red corresponds to a beam of light made composed of photons with the lowest energy. The visible light spectrum's least energetic colour is red since it has the longest wavelength and lowest frequency.

A stream of photons travelling in a wave-like pattern, each carrying energy, and travelling at the speed of light can be compared to electromagnetic radiation. It was noted in that part that the energy of the photons is the only distinction between radio waves, visible light, and gamma rays. The lowest energy photons are found in radio waves. Radio waves lack the energy that microwaves do. There are even more in infrared, which is followed by visible, ultraviolet, X, and gamma rays.

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The force due to gravity that acts on a block of ice that slides down an icy ramp remains equal to C. mg at all angles, where m is the mass of the block and g is the acceleration due to gravity.

This is because the force due to gravity is always acting vertically downwards on the block of ice, and it is proportional to the mass of the block. The angle of the ramp only affects the component of the force due to gravity that is acting parallel to the surface of the ramp, which contributes to the acceleration of the block down the ramp.

As the angle of the ramp increases, the component of the force due to gravity acting parallel to the ramp increases, while the component acting perpendicular to the ramp decreases. However, the magnitude of the force due to gravity itself remains constant, and is always equal to mg.

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Answer:

The speed of light in air is c = 3 × 108 m/s.

Thus, the speed of light in glass will be given as.

v = c/n = 3 × 108/ 1.5 = 2 × 108 m/s.

The speed, wavelength and frequency are related as.

c = νλ

Thus, wavelength in air is given as.

λa = c/ν = 3 × 108/ 6 × 1014 = 5 × 10-7 m.

In general, the shorter the wavelength, the greater the danger to living things. Although longer wavelengths also have their hazards, very short wavelengths, such as X-rays and gamma rays, can easily damage living tissue

UV radiation is more damaging when its wavelength is shorter. Shorter wavelength UV light, however, has a lower ability to enter skin. Three bands make up the UV area, which has a wavelength range of 100 to 400 nm. UVA (315-400 nm) (315-400 nm)

A waveform signal's wavelength is defined as the separation between two identical points (adjacent crests) in adjacent cycles as the signal travels through space or along a wire. Its length in wireless systems is typically expressed in metres (m), centimetres (cm), or millimetres (mm) (mm).

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Answer:

24° north of east

Explanation:

tan(x)=90/200 ie x=arctan(90/200)=24°

So the plane took off 24° east.

Answer:

24° north of east

Explanation:

Hope this will help

Effects of Population Growth on The Economy Population growth may have a positive effect on the economy.

Human population growth bounces the Earth's system in a variety of ways, involving Increasing the extraction of resources from the environment. Rapid population growth built it more difficult for low-income and lower-middle-income countries to supply the increase in public expenditures. Population growth, along with increasing use, of the economy tends to increase emissions of climate-changing greenhouse gases.

On a facile level, the relationship between growth in population and growth in per capita income is clear. After all, per capita income equals total income divided by population. The growth rate of per capita income forcefully equals the difference joining the growth rate of income and the growth rate of population.

So we can conclude that  Population size, growth, age structure, and geographic issues influence economies.

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A man applies a force of 330 N at an angle 60 degrees relative to a door. The wedge must exert a force of 214.5 N to prevent the applied force from opening the door.

To determine the force required from the wedge to prevent the door from opening, we need to analyze the torque acting on the door. Torque is the rotational force that causes an object to rotate.

The torque exerted by the applied force can be calculated using the equation:

Torque = Force * Distance * sin(θ)

where:

Force is the magnitude of the applied force (330 N),

Distance is the distance from the point of rotation to the point of force application (1.5 m),

θ is the angle between the applied force and the lever arm (60 degrees).

Calculating the torque exerted by the applied force:

Torque = 330 N * 1.5 m * sin(60 degrees)

= 330 N * 1.5 m * √3/2

= 330 N * 1.5 m * √3/2

= 214.5 Nm

To prevent the door from opening, an equal and opposite torque must be exerted by the wedge. The distance from the point of rotation to the point of wedge application is half the width of the door, so it is 1 meter.

Therefore, the force required from the wedge to counteract the applied force is:

Force = Torque / Distance

= 214.5 Nm / 1 m

= 214.5 N

Hence, the wedge must exert a force of 214.5 N to prevent the applied force from opening the door.

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Answer:

you could hurt yourself

Explanation:

Answer

You should never do an exercise such as the bench press without a spotter because you could hurt yourself or push your self too much.

Explanation:

Answer:

a species on which other species in an ecosystem largely depend, such that if it were removed the ecosystem would change drastically. An example is a predator-prey relationship. If there was no more prey the predators may began to fall ill and die and if there was no more predators the prey would eventually over populate  

Explanation:

Answer:

E = 149.92 N/C

Explanation:

Given that,

The power emitted by a sinusoidal light is 60 W

Intensity is equal to the power per unit area. It can be given by :

\(I=\dfrac{P}{4\pi r^2}\\\\I=\dfrac{60}{4\pi \times (0.4)^2}\\\\I=29.84\ W/m^2\)

The relation between the amplitude of the electric field and the intensity is given by :

\(I=\dfrac{E_o^2c \epsilon_o}{2}\)

Here, \(E_o\) is the amplitude of the electric field

\(E_o=\sqrt{\dfrac{2I}{c\epsilon_o}} \\\\E_o=\sqrt{\dfrac{2\times 29.84}{3\times 10^8\times 8.85\times 10^{-12}}}\\E_o=149.92\ N/C\)

So, the amplitude of the electric field is 149.92 N/C.

Answer:

The answer to this question would be 3.6 m/s