a girl stand 5m away from a large plane mirror.How far must she walk ti be 2m away from her image?​

Abiotic variables are particularly essential since they have a direct impact on organisms' ability to live.

Answer:

6.7 m/s^2

Explanation:

The formula of acceleration is:

\(\displaystyle{\vec{a} = \dfrac{\Delta \vec{v}}{\Delta t} = \dfrac{v_2 - v_1}{t_2-t_1}}\)

where \(\displaystyle{\vec{a}}\) is acceleration, \(\displaystyle{\vec{v}}\) is velocity and \(\displaystyle{t}\) is time. \(\displaystyle{v_2}\) means final velocity. \(\displaystyle{v_1}\) means initial velocity, \(\displaystyle{t_2}\) means final time and \(\displaystyle{t_1}\) means initial time.

We are given that the Firebird travels at velocity of 0 to 60 mph in four seconds. Therefore:

Since it travels to the east then our vector will be positive. However, acceleration has to be in m/s^2 unit (Sl unit) so we'll have to convert from mph (miles per hours) to m/s (meters per second) first.

We know that:

Now we divide 1609.344 by 3600 to find a unit rate of m/s:

\(\displaystyle{\dfrac{1609.344}{3600} \ \, \sf{m/s}}\\\\\displaystyle{= 0.44704 \ \, \sf{m/s}}\)

Now multiply 0.44704 m/s by 0 and 60 to get velocity in m/s unit:

Time is already in second so no need for conversion. Substitute known information in the formula:

\(\displaystyle{\vec{a} = \dfrac{26.82-0}{4-0}}\\\\\displaystyle{\vec{a} = \dfrac{26.82}{4}}\\\\\displaystyle{\vec{a} = 6.7 \ \, \sf{m/s^2}}\)

Therefore, the Firebird will accelerate at the rate of 6.7 m/s^2.

Answer:

They help by knowing what you are using them for.

Explanation:

i.e: you know you're solving for length if the units are meters

you're solving for time if you are using seconds

etc..

When friction from Earth's upper atmosphere does -7.5×10^9 J of work on a satellite, it means the satellite has lost that amount of energy due to friction.

To find the new orbital speed, we first need to determine the change in the satellite's kinetic energy. Since work done equals the change in kinetic energy, we have:
ΔKE = -7.5×10^9 J

Next, we can use the formula for kinetic energy: KE = 0.5 × m × v^2, where m is the satellite's mass and v is its speed. To find the change in speed, we rearrange the formula:
Δv^2 = 2 × ΔKE / m
Now, we can calculate the new speed by taking the square root of the sum of the initial speed squared and the change in speed squared:
v_new = sqrt(v_initial^2 + Δv^2)
By plugging in the values and solving for v_new, you'll obtain the satellite's new orbital speed after friction has done work on it.

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Answer:

C. 199.9 s

Explanation:

3 minutes = 3×60 = 180 seconds.

the turtle moves in that time 180×10 = 1800 cm.

in other words the rabbit gave it that much head-start (it does not matter if that was at the begin of in the middle of the race).

the rabbit moves with 10×10cm/s = 100cm/s.

the rabbit needs therefore 1800/100 = 18 seconds for the

1800 cm.

at that time the turtle has added another 18×10 = 180 cm.

for which the rabbit needs 180/100 = 1.8 seconds.

during that time the turtle has added 1.8×10 = 18 cm.

and so on.

in formal mathematics this looks like this :

1800 + 10x = 100x

after x seconds of the rabbit running both will have run the same distance, and it is a tie.

1800 = 90x

x = 20 seconds

so, at that point, the rabbit was actively running for 20 seconds and raced 20×100 = 2000 cm

and the turtle was actively running for 180 + 20 = 200 seconds, and also covered 200×10 = 2000 cm.

but our question tells us that the turtle won by 10 cm.

so, the race was over a little bit before these 200 seconds (for a tie).

this means, the rabbit could not run the last 10 cm for the tie (because the race was over and the turtle had won).

the rabbit would have needed 10/100 seconds for these 10 cm.

as speed = distance/time

we need to divide distance by speed

distance/1 / distance/time

to get time.

so,

10cm/1 / 100cm/s = 10s/100 = 1/10 s

so, we need to deduct this 1/10 s from the 200 seconds of the turtle (and also from the 20 seconds for the rabbit).

the race lasted of course the whole time the turtle was running (while the rabbit was resting, officially still participating in the race with speed 0 for 3 minutes).

and so, the race was 199.9 s long.

The frequency of light when it reaches Earth is approximately 4.988 x 10^14 Hz.

Explanation:-

Given:

Emitted frequency of light, f = 5.000 x 10^14 Hz,

Speed of the galaxy receding from Earth, v_src = 4500 km/s.

We need to convert the speed of the galaxy from km/s to m/s:

v_src = 4500 km/s * (1000 m/km)

v_src = 4.5 x 10^6 m/s

Plugging the given values into the Doppler effect formula:

f' = (5.000 x 10^14 Hz) * (3.00 x 10^8 m/s + 0 m/s) / (3.00 x 10^8 m/s + 4.5 x 10^6 m/s)

Simplifying the expression:

f' = (5.000 x 10^14 Hz) * (3.00 x 10^8 m/s) / (3.00 x 10^8 m/s + 4.5 x 10^6 m/s)

f' ≈ 4.988 x 10^14 Hz

Therefore, the frequency of light when it reaches Earth is approximately 4.988 x 10^14 Hz.

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Answer: someone took down my answer I don’t know why when I took this test and got it right but the answer is C like the other person said.

Explanation:

The microwave radiation referred to in this context is radiation that was released as matter formed in the early universe. Therefore option A is correct.

Microwave radiation, also known as cosmic microwave background radiation (CMB), is a faint radiation that permeates throughout the universe.

It is considered to be the remnants of the thermal radiation released shortly after the Big Bang, during a phase called recombination. At this time, the universe transitioned from a hot, dense plasma to a state where neutral atoms could form, allowing photons to travel freely.

The cosmic microwave background radiation is isotropic, meaning it is uniformly distributed in all directions, and it has a characteristic temperature of approximately 2.7 Kelvin (-270.45 degrees Celsius).

It was first detected in 1965 by Arno Penzias and Robert Wilson, who were awarded the Nobel Prize in Physics for their discovery.

The presence of cosmic microwave background radiation provides strong evidence for the Big Bang theory and helps to support the understanding of the early universe's formation and evolution.

It serves as an important tool for studying cosmology and provides insights into the structure, age, and composition of the universe.

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The correct statement of Newton's Second Law is: An object's acceleration is inversely proportional to its mass and proportional to the net force acting on it.

Newton's Second Law of Motion states that the force acting on an object is directly proportional to the mass of the object and its acceleration. In other words, the greater the force applied to an object, the greater its acceleration, and the greater the object's mass, the less it will accelerate for a given force.

This law is often expressed mathematically as F = ma, where F is the force applied to an object, m is the object's mass, and a is its acceleration.

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The statement, "The Voyager 1 space probe can't change its own motion" is correct and true. The Voyager 1 space probe was launched by NASA in 1977, and since then it has traveled over 14 billion miles away from Earth. It's the most distant spacecraft from Earth.

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Since the resistors are in series, the equivalent resistance is the sum of the resistances:

Now, to find the current, let's divide the voltage by the total resistance:

The current through each resistor is the same because they are in series: 1.5 A.

To find the most powerful resistor, let's analyze the formula for the power in a resistor:

We can see that the greater the resistance, the greater the power, therefore the most powerful resistor is the 30 ohms resistor.

Answer:

B

Explanation:

Gravity, the attractive force between all masses, is what keeps the planets in orbit. Newton’s universal law of gravitation relates the gravitational force to mass and distance

The force of gravity is what gives us our sense of weight. Unlike mass, which is constant, weight can vary depending on the force of gravity (or acceleration) you feel. When Kepler’s laws are reexamined in the light of Newton’s gravitational law, it becomes clear that the masses of both objects are important for the third law, which becomes a3 = (M1+ M2) × P2. Mutual gravitational effects permit us to calculate the masses of astronomical objects, from comets to galaxies.

Answer:

The fringes are 4.7*10^-7 m apart, such that they are adjacent.

Explanation:

Using the formula for adjacent fringes given a single slit:

Δ\(x=\frac{(Wavelength)(Distance between slit and screen)}{Width}\)

Δ\(x=\frac{(590/10^{9})(1.90) }{(2.30)}\)

Δ\(x=0.000000487 m\)

Hope this helps!

The distance between the first-order and second-order dark fringes on the screen will be 4.874 × 10⁻⁵ cm.

Given:

wavelength, λ = 590 nm = 590 × 10⁻⁹ m

Distance between the slit and screen, D = 1.90 m

Width of slit, d = 2.30 m

Calculation:

We know that the distance between two slits is given as:

Δx = λD / d

where  λ is the wavelength of light

           D is the distance between the slit and screen

           d is the width of the slit

Applying values in the above equation we get:

Δx = (590 × 10⁻⁹ m)(1.90 m) / (2.30 m)

    = 4.874 × 10⁻⁷ m

    = 4.874 × 10⁻⁵ cm

Therefore, the distance between the first- and second-order dark fringes on the screen will be 4.874 × 10⁻⁵ cm.

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At the end of the acceleration, its speed is 81.77 m/s.

A description of an object's speed and direction of motion is comparable to the term "speed." Meter per second (m/s) is the metric measurement of speed. Centimeters per second (cm/s) can also be used to describe the velocity magnitude.

The rate at which something moves in a certain direction is referred to as its velocity. as quickly as a car traveling north on a highway or a rocket taking flight.

V = u + at

V = 5.47 + 1.65 × 9.06 s

V = 81.77m/s

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Answer:

v2^2 - v1^2 = 2 g s        fundamental formula

v2 = v1 + 2 g    = v1 + 19.8         increase in velocity in 2 sec

v1^2 + 39.6 v1 + 392 - v1^2 = 2 * 9.8 * 123.1 = 2412.76

v1 = (2412.76 - 392) / 39.6 = 51.03

v2 = 51.03 + 19.6 = 70.63

T = 70.63 / .8 = 7.207 sec     time to fall height of tower

S = 1/2 g T^2 = 4.9 * 7.207^2 = 254.5 m

(Note  v2^2 - v1^2 = 70.63^2 - 51.03^2 = 2385 m

2385 / (2 * 9.8) = 122 m (close to 123.1    as was given

the air pressure inside and outside is equal, and the pressure inside the eardrum remains constant. At 15 degrees Celsius and sea level, the density of air is approximately 1.225 kilograms per cubic meter (kg/m3).

At a temperature of 273 K and a pressure of 101.325 kPa, dry air has a density of 1.293 kg/m3. The composition of air is basically constant up to an altitude of at least 50 km, with the exception of the variability of water vapor. Finding the air density is a straightforward process. The air pressure must be split into two partial pressures: that of dry air and that of water vapor. These two values when combined result in the desired parameter.

= Density of air = 0.8 kg/m³

g = Acceleration due to gravity = 9.81 m/s²

h = Altitude

A = Area = 0.5 cm²

Pressure

\(p =pgh\\\\=p=0.8*9.81*(4301-1609)\\=p=21126.816Pa\\\\\)

Pressure

\(p= f/a \\=f = pa\\= F = 21126.816*0.5*10\)

The net force on your ear is 1.0563408 N

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Answer:

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Answer: ITS T

Explanation:

In a motor, electrical current enters through the brushes. TRUE.

Answer:

the combined speed of the two railroad cars after the collision is 4/3 m/s.

Explanation:

The combined speed of the two railroad cars after the collision can be calculated using the conservation of momentum principle.

Let's assume the combined speed of the cars after the collision is v'. Then, using the equation for momentum, p = m * v, where m is the mass of each car and v is the velocity of each car, the momentum of each car before and after the collision can be calculated as:

Before the collision:

m1 = 4000 kg, v1 = 2 m/s

p1 = m1 * v1 = 4000 kg * 2 m/s = 8000 kg m/s

After the collision:

m2 = 6000 kg, v2 = 0 m/s

p2 = m2 * v2 = 6000 kg * 0 m/s = 0 kg m/s

Since momentum is conserved, the momentum before the collision must equal the momentum after the collision:

p1 = p2

So,

8000 kg m/s = 6000 kg * v'

Solving for v', we find that:

v' = 8000 kg m/s / 6000 kg = 4/3 m/s

Therefore, the combined speed of the two railroad cars after the collision is 4/3 m/s.

Answer:

Your kinetic energy is 631800 J

Explanation:

Well i hope this helps

There are many factors that determine if an aircraft can operate from a given airport. Of course the availability of certain services, such as fuel, access to air stairs and maintenance are all necessary. But before considering anything else, one must determine if the plane can physically land at an airport, and equally as important, take off.

What is the minimum runway length that will serve?

Looking at aerial views of runways can lead some to the assumption that they are all uniform, big and appropriate for any plane to land. This couldn’t be further from the truth.

A given aircraft type has its own individual set of requirements in regards to these dimensions. The classic 150’ wide runway that can handle a wide-body plane for a large group charter flight isn’t a guarantee at every airport. Knowing the width of available runways is important for a variety of reasons including runway illusion and crosswind condition.

Runways also have different approach categories based on width, and have universal threshold markings that indicate the actual width.

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Answer:20 miles

Explanation:

An open-tube manometer is a device used to measure the pressure difference between two points in a fluid, such as in a pipe or a tank. It consists of a U-shaped tube partially filled with a liquid, typically water or mercury, and open to the atmosphere on one or both ends. Here's a simple diagram and explanation of how an open-tube manometer works:

Open-tube manometer diagram

In this diagram, the open-tube manometer is connected to a pipe carrying a fluid whose pressure difference we want to measure. The left side of the manometer is open to the atmosphere, while the right side is connected to the pipe.

To measure the pressure difference, we first fill the manometer with a liquid, such as water or mercury, until the liquid level is the same on both sides of the U-tube. Let's assume the liquid is water and the fluid in the pipe is at a higher pressure than the atmosphere. As the fluid flows into the right side of the manometer, it pushes the water down, creating a difference in liquid levels in the two arms of the manometer. The height difference, h, between the two liquid levels is proportional to the pressure difference between the fluid in the pipe and the atmosphere.

Using the equation for pressure in a fluid, we can relate the pressure difference, ΔP, to the height difference, h, and the density of the liquid, ρ, as follows:

ΔP = ρgh

where g is the acceleration due to gravity. So, by measuring the height difference, h, and knowing the density of the liquid, we can calculate the pressure difference, ΔP.

Note that the direction of the pressure difference depends on the direction of the flow. If the fluid in the pipe is at a lower pressure than the atmosphere, the water level in the left arm of the manometer will be higher than that in the right arm, and the height difference, h, will be negative.

Overall, an open-tube manometer is a simple and effective device for measuring pressure differences in fluids.

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The only other factor you need is the height of the object in real life (otherwise you could be photographing a model which is much closer to the camera).

The maths isn't actually that complex, the ratio of the size of the object on the sensor and the size of the object in real life is the same as the ratio between the focal length and distance to the object.

To work out the size of the object on the sensor, work out it's height in pixels, divide by the image height in pixels and multiply by the physical height of the sensor.

So the whole sum is:

Distance to object equation

Answer:

1. True 2.0

Explanation:

1. When balanced forces are acting on an object, they have a constant velocity, meaning that the velocity remains the same.

2. When an object begins at a starting point and returns back to that same starting point, its displacement would be 0.

I'm pretty confident in these answers, however, you must have studied this more than me, so let me know if you have any questions or concerns at all, I'll be glad to help. :)

Answer:

In Newton’s first law, an object at rest remains at rest until an external force isapplied. When I play soccer, the soccer ball will be at rest on the field (the initial condition) andremain in that spot on the field until I kick it (my muscles applying an external force to the ball).According to Newton’s second law, force = mass x acceleration (F=ma). When I kick the resting soccer ball, which has a given mass, it will accelerate in the direction that I kick it. From the equation, acceleration = force divided by mass. Therefore, since the mass of the soccer ball is fixed, the stronger my leg is and the more force I can apply to the ball, the faster it willaccelerate.According to Newton’s first law, an object in motion remains in motion until an external force isapplied. After I kick the soccer ball, it will continue in motion in the direction that I kicked it,but its acceleration will gradually slow down due to the external forces of friction from the airand the surface of the field. According to Newton’s third law, for every action there is an equal and opposite reaction.When I kick the soccer ball forward, if I also kick it in an upward direction, such as a thirty-degree angle from the field, it will come down at an angle when it strikes the field. When theball lands and strikes the field, there will be an equal and opposite reaction whereby instead oftraveling downward it will bounce of the surface of the field and will then be travelling upward.

A driver travels 135 km east in 1.5 h stops for 45mins for lunch and then resumes driving fir the next 2.0h through a displacement of 215 kn east.  the drivers average velocity is 82.3 km / hr.

given that :

distance travel d1 = 135 km

time taken t1 = 1.5 h

hault time t = 45 mins = 0.75 h

distance travelled d2 = 215 km

time t2 = 2.0 h

Average velocity  =  Total time taken / time

Average velocity = ( 135 km + 215 km ) / ( 1.5 h + 0.75 h + 2.0 h)

                            = 350 km / 4.25

                            = 82.3 km / hr

Thus, A driver travels 135 km east in 1.5 h stops for 45mins for lunch and then resumes driving fir the next 2.0h through a displacement of 215 kn east.  the drivers average velocity is 82.3 km / hr.

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Answer:

speed/time

Explanation:

Answer:

a= (Vf - Vi)

         t

To find acceleration (a) you need to subtract the finale velocity (Vf) minus the initial velocity (vi) divided by time (t) as shown in the equation above.

Answer:

D. By comparing traits

Explanation:

Because age isn't genetic, as well as names, as well as who discovered, but traits are genetic.  

Answer:

D

Explanation:

a) In the vapοr phase, the likely structure οf the dimer οf beryllium (Be) wοuld be Be².

b) The likely structure οf BeCl² in diethyl ether wοuld be a mοnοmer, with beryllium chlοride mοlecules existing as separate entities.

(a) Each beryllium atοm wοuld be bοnded tο anοther beryllium atοm thrοugh a cοvalent bοnd. The hybridizatiοn scheme apprοpriate fοr the Be centers in this dimer wοuld be sp hybridizatiοn. Each Be atοm wοuld have twο electrοn pairs in the hybrid οrbitals and twο unhybridized p οrbitals, resulting in a linear geοmetry fοr the dimer.

(b) When dissοlving in diethyl ether, beryllium chlοride (BeCl²) fοrms mοnοmeric species. The bοnding in BeCl² can be described as fοllοws:

Beryllium (Be) has twο valence electrοns, and chlοrine (Cl) has seven valence electrοns. BeCl² undergοes electrοn-pair sharing, where beryllium shares οne electrοn frοm each chlοrine atοm, fοrming twο cοvalent bοnds.

Each chlοrine atοm cοntributes οne electrοn tο fοrm a bοnding pair with beryllium, resulting in a linear geοmetry arοund the beryllium atοm. The bοnding can be cοnsidered as a cοmbinatiοn οf sigma (σ) bοnds fοrmed by the οverlap οf atοmic οrbitals.

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