A general contractor drives 5 miles to the hardware store in 10 minutes. He shops for needed tools for 30 minutes, then drives to his customer’s home at an average speed of 45 mph. He arrives 20 minutes later. Calculate the average speed from the time the contractor leaves his office to the time he arrives at his customer’s home.

Answer:

No Lo se :v esque estoy enferma del

The net force acting on the student in the vertical direction is -324 N, which means the force is directed downwards.

The seat applies a normal force of 1374 N to the student at the bottom of the loop.

b. The net force acting on the student in the vertical direction can be calculated using the following equation:

F_net = ma

where F_net is the net force, m is the mass of the student, and a is the acceleration of the student. At the bottom of the loop, the only forces acting on the student are the force of gravity and the normal force from the seat. The normal force is equal in magnitude and opposite in direction to the force of gravity, so the net force can be calculated as:

F_net = F_g - F_N

F_net = mg - N

where g is the acceleration due to gravity (9.8 m/s^2), and N is the magnitude of the normal force. Since the student is not accelerating in the horizontal direction, there is no net force in that direction.

At the bottom of the loop, the normal force is equal to the force of gravity plus the centripetal force needed to keep the student moving in a circular path. The centripetal force can be calculated as:

F_c = ma_c

where F_c is the centripetal force, m is the mass of the student, and a_c is the centripetal acceleration. The centripetal acceleration can be calculated using the following equation:

a_c = v^2 / r

where v is the speed of the roller coaster at the bottom of the loop, and r is the radius of the loop. Substituting the given values, we get:

a_c = (20 m/s)^2 / 30 m

a_c = 400/30 m/s^2

a_c = 13.3 m/s^2

The centripetal force can be calculated as:

F_c = ma_c

F_c = (60 kg)(13.3 m/s^2)

F_c = 798 N

Therefore, the normal force can be calculated as:

N = mg + F_c

N = (60 kg)(9.8 m/s^2) + 798 N

N = 1374 N

The net force can be calculated as:

F_net = mg - N

F_net = (60 kg)(9.8 m/s^2) - 1374 N

F_net = -324 N

Therefore, the net force acting on the student in the vertical direction is -324 N, which means the force is directed downwards.

c. The seat applies a normal force to the student, which is equal in magnitude and opposite in direction to the force of gravity. At the bottom of the loop, the normal force is equal to the force of gravity plus the centripetal force needed to keep the student moving in a circular path.

Therefore, the seat applies a normal force of 1374 N to the student at the bottom of the loop.

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Answer:

The amount of work done is 45 J.

Explanation:

We know that the force applied is 15N. The amount of displacement experienced by the box is 3 metres along the floor.

Thus, F= 15N

D= 3 metres

The formula for calculating work done is W= F×D

Thus, W=15×3

W=45J

Thus, the amount of work done is 45J.

The magnitude of their mutual gravitational force when they are separated by a distance of 18.3 cm is 0.000017 N.

When two particles weigh 1.07 N each, the magnitude of their mutual gravitational force when they are separated by a distance of 18.3 cm is 0.000017 N.

The gravitational force between two particles is determined by the masses of the particles and the distance between them.

The following equation is used to calculate the magnitude of the gravitational force: Fg = G(m1m2 / r^2)

where Fg is the magnitude of the gravitational force,

G is the gravitational constant (6.67 x 10^-11 Nm^2/kg^2),

m1 and m2 are the masses of the particles, and

r is the distance between the particles.

In this question, the masses of the two particles are given as 1.07 N each, and the distance between them is 18.3 cm, which is equal to 0.183 m. Plugging these values into the equation,

we get: Fg = (6.67 x 10^-11 Nm^2/kg^2) x (1.07 N) ^2 / (0.183 m) ^2Fg = 0.000017 N

Therefore, the magnitude of their mutual gravitational force when they are separated by a distance of 18.3 cm is 0.000017 N.

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Astronomers expected that the expansion of the universe might slow down due to Option a. the gravitational pull of all the matter in it.

Astronomers initially expected that the gravitational pull of all the matter in the universe would cause the expansion of the universe to slow down. This is because the gravitational force of matter pulls objects towards each other, and thus would be expected to slow down the expansion of the universe. However, later observations showed that the expansion of the universe was actually accelerating, rather than slowing down.

To account for this unexpected acceleration, astronomers introduced the concept of dark energy, which is a mysterious force that is thought to be causing the acceleration of the universe's expansion. Dark energy is believed to be a property of space itself, and it is thought to make up about 68% of the total energy density of the universe. The nature of dark energy is still not well understood, and it remains one of the biggest mysteries in modern physics.

In summary, while astronomers initially expected that the gravitational pull of matter in the universe would cause the expansion of the universe to slow down, later observations showed that the expansion is actually accelerating due to the mysterious force of dark energy. Therefore, Option A is Correct.

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Answer:

receptors

Explanation:

In this case, your skin and brain act as receptors in maintaining homeostasis. These receptors are monitors in different parts of an organism's body that are there to detect specific changes that occur and activate very specific responses in order to counteract these changes and maintain a very stable system. This is exactly, what your skin and brain are doing in this scenario, they detect the change in temperature and counteract its effects through sweat which ultimately causes the opposite effect and maintains equilibrium in your body.

The coefficient of friction for the surface is 0.9875 and the weight of the block is 5.2n

The coefficient of friction between the block and the surface is calculated by dividing the force required to move the block, 8 n, by the force required to move the block and the weight, 8.1 n. This gives us a coefficient of friction of 0.9875.

8/8.1= 0.9875

To calculate the weight w of the block, we subtract the force required to move the block alone, 2.9 n, from the force required to move the block and the weight, 8.1 n. This gives us a weight of 5.2 n.

8.1-2.9 = 5.2n

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The magnitude of the resultant displacement of the professor is 4.69km, and the direction of the resultant displacement is 19.7 degrees west of north.

The magnitude of the resultant displacement of the professor can be found using the Pythagorean theorem.

The north and south components will cancel each other out, leaving us with the east and west components to work with. The east component is 0, and the west component is 4.69km. Therefore, the resultant displacement is sqrt((0)^2 + (4.69)^2) = 4.69km.

The direction of the resultant displacement can be found using the arctan function. The arctan of the y-component divided by the x-component will give us the angle of the resultant displacement.

In this case, the y-component is 3.27km - 1.59km = 1.68km, and the x-component is 4.69km. Therefore, the direction of the resultant displacement is arctan(1.68/4.69) = 19.7 degrees west of north.

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Answer:

Plantae. Also called the Kingdom Metaphyta, the Kingdom Plantae consists of all multicellular, eukaryotic, and photosynthetic organisms on the planet. Being photosynthetic, these organisms are autotrophs and can make their food using the energy from the sun.

i dont know for real

A. The probe's Mach number is 92.593.

B. The angle of the shock wave relative to the direction of motion is approximately 0.678 degrees.

A. First, we need to convert the initial speed to meters per second:

15,000 km/h = 4,166.67 m/s

The Mach number is defined as the ratio of the object's speed to the speed of sound:

Mach number = object's speed / speed of sound

Mach number = 4166.67 m/s / 45 m/s = 92.593

B. The angle of the shock wave relative to the direction of motion can be calculated using the formula:

sin(θ) = 1 / Mach number

sin(θ) = 1 / 92.593

θ = sin^-1(1 / 92.593) = 0.678 degrees

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Explanation:

For example, a uniform electric field E is produced by placing a potential difference (or voltage) ΔV across two parallel metal plates, labeled A and B. ... The relationship between ΔV and E is revealed by calculating the work done by the force in moving a charge from point A to point B.

Answer:

The conversion efficiency of geothermal power developments is generally lower than that of conventional thermal power plants. ... The highest reported conversion efficiency is approximately 21% at the Darajat vapour-dominated system, with a worldwide efficiency average of around 12%.

Jane's rate along the summit was 25 mph.

Let's assume that Jane's rate along the summit is represented by the variable "x" in miles per hour. We know that she rode 72 miles uphill at a rate that was 5 mph slower than her rate along the summit. Therefore, her rate uphill would be (x - 5) mph.

To find her average rate for the entire journey, we can calculate the total time taken for each segment and divide it by the total distance covered.

Time taken to ride uphill = Distance / Rate

Time taken to ride uphill = 72 miles / (x - 5) mph

Time taken to ride along the summit = Distance / Rate

Time taken to ride along the summit = 21 miles / x mph

Since the total time taken for the entire journey is 3 hours, we can write the equation:

Time taken to ride uphill + Time taken to ride along the summit = Total time

72 / (x - 5) + 21 / x = 3

By solving this equation, we find that x = 25 mph. Therefore, Jane's rate along the summit was 25 mph.

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The intensity at a point on the screen 2.00 mm from the center of the central maximum is approximately 0.034 W/m². The intensity at a point on the screen 1.50 mm from the center of the central maximum is approximately 0.024 W/m².

I = Imax cos² (πd sin θ / λ),

where Imax is the intensity at the center of the interference pattern, d is the distance between the two slits, θ is the angle between the line connecting the point on the screen to the center of the interference pattern and the line perpendicular to the screen, and λ is the wavelength of the light.

To find the angle θ, we can use the small angle approximation:

sin θ ≈ θ ≈ y/L,

where y is the distance from the center of the interference pattern to the point on the screen, and L is the distance between the slits and the screen.

We are given d = 0.0720 mm, λ = unknown, L = 0.800 m, Imax = 0.0700 W/m², and the distance from the center of the central maximum to the first minimum y = 3.00 mm.

Using the given distance y, we can find the value of sin θ:

y/L = sin θ,

3.00 mm / 0.800 m = sin θ,

sin θ = 0.00375.

Now we can solve for the wavelength λ:

Imax cos² (πd sin θ / λ) = I,

0.0700 W/m² cos² (π(0.0720 × 10⁻³ m)(0.00375) / λ) = I,

cos² (π(0.0720 × 10⁻³ m)(0.00375) / λ) = I / 0.0700 W/m²,

π(0.0720 × 10⁻³ m)(0.00375) / λ = ± cos⁻¹ (√(I / 0.0700 W/m²)),

λ = π(0.0720 × 10⁻³ m)(0.00375) / cos⁻¹√(I / 0.0700 W/m²)),

λ = 5.70 × 10⁻⁷ m (for the positive root).

Now we can find the intensities at the given distances from the center of the central maximum.

For y = 2.00 mm:

sin θ = y/L = 2.00 mm / 0.800 m = 0.00250,

I = Imax cos² (πd sin θ / λ)

I = 0.0700 W/m² cos² (π(0.0720 × 10⁻³m)(0.00250) / (5.70 × 10⁻⁷ m))² ≈ 0.034 W/m².

So the intensity at a point on the screen 2.00 mm from the center of the central maximum would be approximately 0.034 W/m².

For y = 1.50 mm:

sin θ = y/L = 1.50 mm / 0.800 m = 0.001875,

I = Imax cos² (πd sin θ / λ)

I= 0.0700 W/m² cos² (π(0.0720 × 10⁻³m)(0.001875) / (5.70 × 10⁻⁷ m))² ≈ 0.034 W/m².

I ≈ 0.024 W/m².

So the intensity at a point on the screen 1.50 mm from the center of the central maximum would be approximately 0.024 W/m².

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Answer:

A) x4

Explanation:

Magnification is equal to image size divided by the actual size, or M = I/A.

The image size is the student's drawing, which is 28.8 cm, and the actual size is 7.2 cm. Divide them, and cancel out the units, and you should get:

28.8 cm/7.2 cm = 4

Energy change in motorcycle that uses gasoline (petrol) for movement is shown below.

chemical energy of gasoline  -> thermal energy -> electrical energy -> mechanical energy.

Energy is the ability to perform work in physics. It could exist in several different forms, such as potential, kinetic, thermal, electrical, chemical, nuclear, etc.

In motorcycle, when gasoline burns chemical energy of gasoline transforms into thermal energy . This thermal energy produces electric energy by the engine and the  motorcycle runs. Hence electrical energy transforms into mechanical energy. So it can be drawn as:

chemical energy of gasoline  -> thermal energy -> electrical energy -> mechanical energy.

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the options that are on the electromagnetic spectrum are invisible light (including UV radiation, X-rays, and gamma rays) and microwaves.

What is electromagnetic spectrum?

The electromagnetic spectrum includes all types of electromagnetic radiation, which are waves of energy that travel through space. Sound waves, on the other hand, are not on the electromagnetic spectrum because they are mechanical waves that require a medium to travel through, such as air or water.

Alpha rays, also known as alpha particles, are not on the electromagnetic spectrum either. They are actually particles that consist of two protons and two neutrons and are emitted by some radioactive materials.

Invisible light is a term that refers to electromagnetic radiation that is not visible to the human eye. This includes ultraviolet (UV) radiation, X-rays, and gamma rays, which have shorter wavelengths and higher energy than visible light.

Microwaves are on the electromagnetic spectrum and have longer wavelengths and lower energy than visible light. They are often used for communication and cooking food.

Otonal waves are not a known type of wave and are not on the electromagnetic spectrum.

In summary, the options that are on the electromagnetic spectrum are invisible light (including UV radiation, X-rays, and gamma rays) and microwaves.

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Note: If the question asked for work done by the car, then it will be equal to the kinetic energy of the body.

Answer:

A

Explanation:

The universe was created from a cosmic explosion.

Answer:

It looks like its moving north.

Explanation:

Answer:

The overall force pushing on the block is 26.63 N in the direction of N 34° E

Explanation:

Given;

force going north, F₁ = 15 N

force going east, F₂ = 22 N

The resultant of the two forces is the hypotenuse side of the right angled triangle formed by the two forces.

Let the magnitude of the resultant force = F

F² = F₁² + F₂²

F = √(F₁² + F₂²)

F = √(15² + 22²)

F = 26.63 N

The direction of the force is the angle between the resultant force and the horizontal force.

tan θ = 15 / 22

tan θ = 0.6818

θ = tan⁻¹ ( 0.6818)

θ = 34°

Therefore, the overall force pushing on the block is 26.63 N in the direction of N 34° E

Answer:

111dB

Explanation:

First, find the intensity of the sound using the formula I = Power / 4 x pi x radius ^2

So

60.0 / (4 x 3.14 (6.25)^2)

= 0.122

Then plug that into the equation to find sound level, which is 10log( I / Io)

Io being (1 x 10^-12)

So

10log(0.122 / 1 x 10^-12)

= 111dB

Hope this helps :)

Answer:

v = 3.89 m / s

Explanation:

For this exercise let's use the concept of conservation of mechanical energy

starting point. In the highest part of the mountain

         Em₀ = U = m g h

final point. In the lower part

         Em_f = K = ½ m v²

how energy is conserved

         Em₀ = Em_f

         mgh = ½ m v²

         v = \(\sqrt{ 2gh}\)

let's use trigonometry to find the height

         sin θ = h / L

          h = L sin θ

we substitute

          v = \(\sqrt{ 2g L \ sin tea}\)

let's calculate

          v = \(\sqrt{2 \ 9.8 \ 1.7 \ sin 27}\)

          v = 3.89 m / s

Answer:

the strength of the electric field

a)The lowest possible energy of the proton is 2.233 x 10^-18 J.

b)  The lowest possible energy of the electron is 1.856 x 10^-17 J, which is about 8 times greater than that of the proton in the same box.

a) The energy levels of a particle confined to a one-dimensional box are given by the formula:

E_n = (n^2 * h^2)/(8mL^2)

where n is the quantum number (n = 1, 2, 3, ...), h is the Planck constant, m is the mass of the particle, and L is the length of the box.

For a proton in a one-dimensional box of length L = 0.200 nm, with a mass of m = 1.6726219 x 10^-27 kg, the lowest possible energy level corresponds to n = 1:

E_1 = (1^2 * h^2)/(8mL^2)

= (1^2 * 6.626 x 10^-34 J s)^2 / (8 * 1.6726219 x 10^-27 kg * (0.200 x 10^-9 m)^2)

= 2.233 x 10^-18 J

Therefore, the lowest possible energy of the proton is 2.233 x 10^-18 J.

(b) For an electron in the same box, with a mass of m = 9.10938356 x 10^-31 kg, the lowest possible energy level also corresponds to n = 1:

E_1 = (1^2 * h^2)/(8mL^2)

= (1^2 * 6.626 x 10^-34 J s)^2 / (8 * 9.10938356 x 10^-31 kg * (0.200 x 10^-9 m)^2)

= 1.856 x 10^-17 J

Therefore, the lowest possible energy of the electron is 1.856 x 10^-17 J, which is about 8 times greater than the lowest possible energy of the proton in the same box. This is because the electron has a much smaller mass than the proton, and therefore its kinetic energy is much greater for the same energy level.

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Given four long straight wires form a square with an edge length of 25 cm. Each wire carries a current of 26 A. The net magnetic field at the center of the square will be zero.

To find the net magnetic field at the center of the square, we need to consider the contributions from each wire. The magnetic field produced by a long straight wire at a distance r from the wire is given by Ampere's law:

B = (μ₀ * I) / (2πr)

where μ₀ is the permeability of free space (4π x \((10)^{-7}\)Tm/A) and I is the current in the wire.

For wires 1 and 4, the magnetic fields at the center of the square due to their currents will cancel out since they have opposite directions.

For wires 2 and 3, the magnetic fields at the center of the square will also cancel out since they have equal magnitudes but opposite directions.

Therefore, the net magnetic field at the center of the square will be zero.

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The object believed to lie at the center of the Milky Way galaxy is a **supermassive black hole**.

Extensive observational evidence, including the motion of stars and gas clouds in the galactic center, indicates the presence of a massive and compact object. This object, known as Sagittarius A* (Sgr A*), has a mass of approximately four million times that of our Sun. It is located within a region called the Galactic Center, which is obscured by dust and gas, making direct observations challenging in visible light. However, observations using other wavelengths, such as radio and X-rays, have provided compelling evidence for the presence of a supermassive black hole. The behavior of stars in close proximity to Sgr A*, as well as the energetic processes observed in its vicinity, strongly suggest that it is a black hole with an incredibly strong gravitational pull at the center of our galaxy.

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Answer:

TRUE - A test booklet is sitting at rest on a desk. Compared to the force of the booklet on the desk, the force of the desk on the booklet is the same.

TRUE - The acceleration of an object is always in the direction of the net force acting on it.

Answer:

Distance, S = 13m

Explanation:

Given the following data;

Initial velocity, u = 4m/s

Final velocity, v = 9m/s

Time, t = 2 seconds

To find the distance, S;

First of all, we would determine the acceleration of the shark.

Acceleration = (v - u)/t

Acceleration = (9 - 4)/2

Acceleration = 5/2

Acceleration = 2.5m/s²

Now, to find the distance we would use the second equation of motion

S = ut + ½at²

Substituting into the equation, we have

S = 4(2) + ½*2.5*2²

S = 8 + 1.25*4

S = 8 + 5

Distance, S = 13m