a gas cloud or a planet with a gaseous atmosphere passes between earth and a star. what can be used to determine the composition of the gas?

Answer:

The fundamental frequency is "190.52 Hz".

Explanation:

The given question is incomplete, please find attachment of the complete problem.

The given values are:

Frequency,

f = 146.8 Hz

Length of D-string,

L = 0.61

As we know,

⇒ \(f = \frac{v}{2L}\)

On putting the given values, we get

⇒ \(146.8 = \frac{v}{(2\times 0.61)}\)

⇒       \(v=146.8\times 1.22\)

⇒       \(v=179 \ m/s\)

So,

The new length will be:

⇒  \(f = \frac{179}{(2\times 0.47)}\)

⇒     \(=\frac{179}{0.94}\)

⇒     \(=190.52 \ Hz\)

The fundamental frequency, in hertz, of the new tone that is produced when the string is plucked is 168.84 Hz

Let assume that the oscillating length on the guitar is 0.62 m,

If the guitarist shortens the oscillating length of the properly tuned D-string by 0.15 m.

Then the new length of the oscillating string L' = (0.62 - 0.15 )m = 0.47 m

The fundamental frequency of the new tone can be computed by using the formula:

\(\mathbf{f = \dfrac{1}{2L'} \sqrt{\dfrac{T}{m/L}}}\)

where;

T  = 4× 0.62× 147 × 1.5× 10⁻³  (assuming old fundamental frequency = 147)

T  = 4× 0.62× 147 × 1.5× 10⁻³

T = 80.39 N

∴

\(\mathbf{f = \dfrac{1}{2 \times 0.47} \sqrt{\dfrac{80.39}{1.5 \times 10^{-3}/0.47}}}\)

f = 168.84 Hz

Therefore, the fundamental frequency, in hertz, of the new tone that is produced when the string is plucked is 168.84 Hz

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1.7 m/s is the horizontal velocity that is required to clear the rocks.

As the jumper runs off a 15 m high cliff.

And according to the question,  starts with 0 velocities in the start direction thus he covers 15 m.

Given,

x = 15 m

a = g = 9.8 m, which is the acceleration due to gravity.

iv is the initial velocity which is 0, vo = 0

vf is the final velocity,

Using 2nd equations of motion,

x = iv × t + (1 ÷ 2) a × t²

15 = 0 + ((1 ÷ 2) × ( 9.8) × t²)

t = 1.75

Thus, the time is 1.75 seconds.

Using the same equation, horizontal velocity will be:

x = iv × t + (1 ÷ 2) a × t²

3 = vf × (1.75) + 1 ÷ 2 × (0) × (1.75)

vf = 1.7

Therefore, The horizontal velocity required to cover the rocks is 1.7 m/s.

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Assuming that the box is not sliding off the bus, the forces exerted on it can be represented by the following diagram:

F

F: friction force

The friction force, represented by F in the diagram, acts in the opposite direction of the box's sliding motion. This force is caused by the friction between the box and the bus floor, and it is the only force present in the system. As the bus turns to the left, the box's sliding motion is directed to the right. The direction of the friction force then changes to the left, opposing the motion of the box and slowing it down until it stops.

the correct answer is: You must increase the track height by a factor of 4. The roller coaster's kinetic energy at the bottom of the track is provided by: \(K1 = (1/2) * m * v0^2\) where m is the roller coaster's mass and v0 is its velocity at the bottom.

The roller coaster's velocity would be v = 2v0 if we wanted it to go twice as fast at the bottom. At this increased velocity, the roller coaster's kinetic energy at the bottom would be\(: K2 = (1/2) * m * (2v0)^2 = 2 * K1\) To obtain this increased kinetic energy, we must raise the roller coaster's potential energy. The roller coaster's potential energy at the top of the track is given by: U1 = m * g *  where g denotes gravity's acceleration and h is the height of the track. To double the speed of the roller coaster, we need to double its kinetic energy, which means we need to double its potential energy.

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Answer:

d

Explanation:

d because the sun is in the center and everything else surrounds it

The air-to-fuel ratio (AFR) is an essential metric when discussing the combustion of hydrocarbon fuel in fired heaters. The ratio of air and fuel affects the combustion efficiency.

If a company were to completely combust n-Heptane (C7H16) in air for energy, meaning no side reactions occur, then the following reactions occur:

C7H16 + 11 O2 → 7 CO2 + 8 H2O.

The stoichiometric ratio is the ratio of moles of air required per mole of fuel burned entirely. Since the molar mass of C7H16 is 100, we need 11 moles of oxygen per mole of fuel. Therefore, the air-to-fuel ratio is:

11/1=11/1=11:1

For complete combustion of n-Heptane (C7H16), the heat of combustion can be calculated by Hess's Law. Hess's Law states that the enthalpy change of a reaction is constant if the initial and final conditions are the same. Combustion of n-Heptane (C7H16) can be expressed by the following equation:

C7H16 + 11 O2 → 7 CO2 + 8 H2O ΔH = -4813 kJ/mol

The standard heat of formation for CO2 and H2O can be found in tables to be -393.5 and -285.8 kJ/mol, respectively.ΔHf for C7H16 =

(7 × -393.5 kJ/mol) + (8 × -285.8 kJ/mol) − (-4813 kJ/mol) = -4536.9 kJ/molΔHf for C7H16 = -4536.9 kJ/mol

The stoichiometric air-to-fuel ratio for n-Heptane is 11:1. If there is 120% excess air in the reaction, the air-to-fuel ratio will be 13.2:1. To calculate the moles of air required for 1 mole of fuel, the following equation can be used.13.2 moles of air per 1 mole of n-Heptane can be calculated as follows:

1 mol C7H16 × 11 mol O2/mol C7H16 × 13.2 mol N2/mol O2 = 152.46 mol N2/mol C7H16

Thus, the air-to-fuel ratio with 120% excess air is 13.2:1. The standard heat of formation of CO2 and H2O can be found in tables to be -393.5 and -285.8 kJ/mol, respectively.ΔHf for C7H16 =

(7 × -393.5 kJ/mol) + (8 × -285.8 kJ/mol) − (-4813 kJ/mol) = -4536.9 kJ/mol

To calculate the heat of combustion for this reaction with 120% excess air, we will use the following equation:

C7H16 + 12.1 O2 + 55.3 N2 → 7 CO2 + 8 H2O + 55.3 N2 ΔH = -5435 kJ/mol

The air-to-fuel ratio for the complete combustion of n-Heptane (C7H16) in air is 11:1. The heat of combustion for the reaction is -4813 kJ/mol. The air-to-fuel ratio with 120% excess air is 13.2:1, and the heat of combustion for the reaction with 120% excess air is -5435 kJ/mol.

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Answer:

9.4666... (recurring)

Explanation:

To find the average of all trips, we have to find the velocity of each one first:

Now we have to add all the results and divide by 3 to find or average:

Hope this helps, have a lovely day! :)

Answer:

(1) t = 4.29 s

(2) h = 58.98 m

(3) v = 20.04 m/s (downward)

(4) h = 0.94 m

(5) v = 18.78 m/s

Explanation:

Assumption:

(1)

initial velocity of the baseball, u = 42.0 m/s

final velocity of the ball, v = 0

time of flight is given by;

v = u -gt

gt = u

t = u / g

t = 42 /9.8

t = 4.29 s

(2)

Given;

initial velocity of the golf, u = 0

final velocity of the golf, v = 34 m/s

the height of the cliff is given by;

v² = u² + 2gh

v² = 0 + 2gh

h = v²/2g

h = (34)²/(2x9.8)

h = 58.98 m

(3)

Given;

initial velocity of the rocket, u = 27 m/s

time of motion, t = 4.8s

final velocity, v = ?

v = u + gt

v = 27 + (-9.8 x 4.8)

v = 27 - 47.04

v = -20.04 m/s (the negative sign indicates downward motion of the rocket after 4.8 s)

(4)

Given;

initial velocity of the lizard, u = 4.3 m/s

final velocity of the lizard at maximum height, v = 0

the height rose by the lizard is given by;

v² = u² + 2(-g)h

0 = u² - 2gh

2gh = u²

h = u² / 2g

h = (4.3)²/(2 x 9.8)

h = 0.94 m

(5)

Given;

initial velocity of the person on the bridge, u = 0

height of the bridge, h = 18 m

final velocity of the person is the velocity at impact, v = ?

v² = u² + 2gh

v² = 0 + 2gh

v² = 2gh

v = √2gh

v = √(2 x 9.8 x 18)

v = 18.78 m/s

In terms of attitude change, the fundamental tenet of the cognitive theory would be that individuals are typically driven to lessen dissonance, which could be accomplished by altering their attitudes but also beliefs.

Cognitive theories concentrate on the premise that how exactly what people think causes the arousal of emotions, suggesting that some thoughts, as well as beliefs, as well as beliefs, contribute to healthy emotions as well as adaptive behavior while others lead to disturbing emotions and behaviors.

When people sense unease or guilt as a result of cognitive dissonance, they can actively lessen the dissonance by altering their attitude, beliefs, and even conduct in relation to it in order to attain consistency with both the contradictory cognitions.

In terms of attitude change, the fundamental tenet of the cognitive theory would be that individuals are typically driven to lessen dissonance, which could be accomplished by altering their attitudes but also beliefs.

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Bobby is more powerful because he runs up the stairs faster.

Power is known to be the speed at which work is done. P = gravimetric power The SI unit is Watt W, where 1 Watt equals 1 Joule/second (1W=1J/s). Since work is energy transfer, power is also the rate at which energy is consumed. For example, a 60 W light bulb consumes 60 J of energy per second.

W = F × s

Where, W = work done

F = Force

s = distance

Since both of them are of same weight and can exert equal force while running and are covering same distance, their work done will be equal.

Now according to, P = W/T

Where, P = Power

W = Work

T = Time

Hence, power is inversely proportional to time.

Lesser the time for a particular work higher will be the power.

Time taken by Bobby to reach the bleachers = 30s

Time taken by Michael to reach the bleachers = 40s

As Bobby took lesser time to reach the bleachers, implies his high rate of work.

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Answer:

imma have to come back to you on that one

Answer:

The Sun is at the center of the solar system and the planets move around it.

Explanation:pluto/edmentum

Answer:

i think the products have four hydrogen atoms and two oxygen atoms and the reactants have the same atoms in two molecules of h2o

The change of kinetic energy is -156.7 joules.

\(V1_{i}\) =15

\(V2_{i}\)= -13.5(as towards left)

V= common velocity during collision

On applying momentum conservation during the collision

\(m_{1}V1_{i} + m_{2}V2_{i} = V ( m_{1} + m_{2})\)

\(0.650 \ 15 + 0.950 \ (-13.5) = (0.625 + 0.950) \ V\)

    \(\frac{3.075}{1.6}\) =V

V= -1.92 m/s        

To kind change in kinetic energy we will subtract final and initial kinetic energy

ΔK=\(\frac{1\ (m_{1} + m_{2} ) \ V}{2} ^{2}\) - \(\frac{1\ (m_{1} ) \ V1_{i} }{2} ^{2}\)  -  \(\frac{1\ (m_{2} ) \ V2_{i} }{2} ^{2}\)

ΔK= \(\frac{1\ (0.625 + 0.950 ) \ (-13.5)}{2} ^{2}\) -  \(\frac{1\ (0.625 ) \ 15 }{2} ^{2}\)-  \(\frac{1\ (0.950 ) \ 13.5 }{2} ^{2}\)

ΔK=   = - 156.7 J

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The magnitude of the work done by the car's brakes to slow the car down is 235,537.5 Joules.

The work done:

W = ΔKE

The change observed in kinetic energy (ΔKE) can be find as:

ΔKE = (1/2) × m × (vf² - vi²)

Where m = mass of the car,

vf = final velocity, and

vi = initial velocity.

Let's replace the given values into the equation:

m = 1,500 kg

vf = 28.6 m/s

vi = 45.9 m/s

ΔKE = (1/2) × 1,500 kg  × ((28.6 m/s)² -  (45.9 m/s)²)

Now, determine the magnitude of the work done:

W = ΔKE

ΔKE = (1/2) ×  1,500 kg ×  ((28.6 m/s)² -  (45.9 m/s)²)

= (1/2) ×  1,500 kg ×  (-314.05 m²/s²)

= -235,537.5 J

The amount of work done by the car's brakes to slow it down is 235,537.5 Joules since the change in kinetic energy is negative (indicates a drop in kinetic energy).

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You cannot use the fully qualified name of an enum constant for this all of the given options. The correct answer is d) all of these.

Enum constants are declared with a name that is an identifier and they are implicitly static and final. While using enum constants, the fully qualified name of an enum constant is not allowed to be used in a switch expression, a case expression or an argument to a method.

This is because enum constants are implicitly static and final, so their fully qualified names are not needed to identify them. Instead, their unqualified names can be used to identify them.

For example, instead of using MyEnum.ONE in a switch statement, we can simply use ONE. This applies to all contexts where enum constants are used, including switch expressions, case expressions, and method arguments.

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Answer:

There are four types of orbitals that you should be familiar with s, p, d and f (sharp, principle, diffuse and fundamental). Within each shell of an atom there are some combinations of orbitals

Answer

It will stay the same!

Explanation:

If you so happen to move something from left to right, the size of it is not being shrunk or expanded in any type of way, shape, or form.

Answer:2 hours

Explanation:

Answer:

C. All cells have identical genetic information.

Answer:

A and C

Explanation:

a).  frequency = (speed) / (wavelength)

The speed of light is around 3 x 10⁸ m/s.

For 380 nm (violet light), frequency = (3 x 10⁸ m/s) / (380 x 10⁻⁹ m)

Frequency = 7.89 x 10¹⁴ Hz

For 760 nm (red light), frequency = (3 x 10⁸ m/s) / (760 x 10⁻⁹/s)

Frequency = 3.94 x 10¹⁴ Hz

The ratio is 2 .

That's 1 octave, or 0.3 of a decade.

b).  The ratio of highest/lowest sounds is (20,000 Hz/20 Hz) = 1,000

That's 3 decades, or about 10 octaves.

===> Speaking logarithmically ( ! ), ears are sensitive to a range of sound frequencies that's 10 times as wide as the range of light frequencies that eyes can detect.

IMA = inclined mechanical advantage = distance (L) : height (h)

the longer the track / distance the easier we lift it

C. carrying the piano up a long staircase with many steps spread apart

The velocity of a baseball thrown across a field is (V)= 10m/s

Velocity of a particle is its speed and the direction in which it is moving.

It can also be described as the instantaneous rate of change of the particle's distance traveled.

To calculate the velocity we are using the formula here,

V= S/t

Here we are given,

S= a distance of a baseball thrown= 40m

t= time to travel the distance = 4 seconds.

Now we put the values in the above equation, we get

V= S/t

Or, V = 40/4

Or, V= 10m/s

So, from the above calculation we can conclude that, the velocity of a baseball thrown across a field is (V)= 10m/s

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Answer:

PE=mgh = 35x9.8x2

=686J.

Answer: 25.1m

Explanation:

The expression of the initial potential energy when the ball is tossed upwards is given as followed

\(PE_{i}\)=mg\(PE_{i}= mgh_{0}\)

Here, m is the mass of the ball, g is the acceleration due to gravity and is the initial height.

The initial kinetic energy of the ball is:

\(KE_{i} =\frac{1}{2}mv^2\)

The final potential energy of the ball at the maximum height is given as:

\(PE_{f}=mgh_{max}\)

The final kinetic energy is at the maximum height is:

\(KE_{f} =0\)

Now you will use the conservation of energy princi\(h_{0}\)ple and substitute the equations into the expression below:

\(KE_{i}+PE_i=KE_f+PE_f\)

\(\frac{1}{2}mv^2+mgh_0=0+mgh_{max}\)

\(h_{max}=h_0+\frac{v^2}{2g}\)

Now substitute 9.81 m/\(s^{2}\) for g, 10m/s for v, and 20.0 m for \(h_{0}\) in the equation above.

h\(_{max}}=(20.0m)+\frac{(10m/s)^2}{2(9.81m/s^2}\)

which is equal to 25.1m

Answer:

The resistance of an ammeter should be low. This is because an ammeter is connected in series with the circuit for the measurement of electric current. In case, its resistance is high, then some amount of current may lost in heating it leading to the inaccurate reading. An ideal ammeter is one which has zero resistance.

Mechanical energy is indeed select one because the roller coaster selects one energy due to friction and air resistance as it travels down the track

When a ball is thrown onto the ground, it typically begins to roll with a certain velocity. However, due to Newton's first law, the ball would theoretically keep rolling without any force acting against it. In reality, the ball eventually stops after a certain distance, which implies that a force is being applied to it; this force is known as friction. Friction provides the necessary grip to allow us to walk without slipping and can be beneficial in many cases. On the other hand, friction can also be a major hindrance to motion, and around 20% of the power from a car engine is used to overcome friction in its moving parts.

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