Answer:
\(0.066\)Explanation:
Here, we want to get the probability that at least 1 ace is drawn
There are 4 aces in a deck of cards
The total number of cards is 52
This means we have a total of 48 non-ace cards
The probability of picking at least an ace means that:
1 ace, 3 others
or 2 aces, 2 others
or
3 ace, 1 other
or
4 ace, no other
These are all the possible pickling combinations
The probability of picking an ace is the number of ace cards divided by the total number of cards which are 4/52 = 1/13
For non-ace cards, we have the probability as 48/52 = 12/13
We are going to add the combinations
We have that as follows:
\(\begin{gathered} (\frac{1}{13}\times\frac{12}{13}\times\frac{12}{13}\times\frac{12}{13})\text{ + (}\frac{1}{13}\times\frac{1}{13}\times\frac{12}{13}\times\frac{12}{13})\text{ + (}\frac{1}{13}\times\frac{1}{13}\times\frac{1}{13}\times\frac{12}{13}) \\ +\text{ (}\frac{1}{13}\times\frac{1}{13}\times\frac{1}{13}\times\frac{1}{13}) \end{gathered}\)Finally, we simply the above so as to get a single fraction
We have that as follows:
\(\frac{1728}{28561}+\frac{144}{28561}_{}+\frac{12}{28561}+\frac{1}{28561}=\text{ }\frac{1885}{28,561}\text{ = 0.066}\)una solución tiene un valor de pH=5 Cuál es la concentración molar de OH-?
Answer:
Podemos hacer la conversión entre [\text{H}^+][H
+
]open bracket, start text, H, end text, start superscript, plus, end superscript, close bracket y \text{pH}pHstart text, p, H, end text mediante las siguientes ecuaciones:
\begin{aligned}\text{pH}&=-\log[\text{H}^+]\\ \\ [\text H^+]&=10^{-\text{pH}}\end{aligned}
pH
[H
+
]
=−log[H
+
]
=10
−pH
Write a cubic function whose graph passes through the points.
4. (-1,0), (2,0), (3,0), (0,9)
Help ASAP
Answer:
(0,9) (-1,0), (2,0), (3,0),
Step-by-step explanation:
add me on discord LD BrxzyYT#8144 :)
Hotel rooms in Smalltown are $100/ room per day,
The tax revenue is $ 9000 and Deadweight loss is $500.
We have,
Hotel rooms in Smalltown go for $100, and 1,000 rooms are rented on a typical day.
So, The tax revenue is calculated by :
Tax revenue = Tax Imposed × Quantity sold
= 10 x 900
= $ 9000
Now, The deadweight loss is calculated as:
= 1/2 × Tax imposed × change in quantity sold
= 1/2 x 10 x (1000-900)
= $500
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NO LINKS!! URGENT HELP PLEASE!!!
11. Write the equation for the graph
This is the same as writing y = sqrt(4(x+5)) - 1
===============================================
Explanation:
The given graph appears to be a square root function.
The marked points on the curve are:
(-4,1)(-1,3)(4,5)Reflect those points over the line y = x. This will have us swap the x and y coordinates.
(-4,1) becomes (1,-4)(-1,3) becomes (3,-1)(4,5) becomes (5,4)Recall the process of reflecting over y = x means we're looking at the inverse. The inverse of a square root function is a quadratic.
----------
Let's find the quadratic curve that passes through (1,-4), (3,-1) and (5,4).
Plug the coordinates of each point into the template y = ax^2+bx+c.
For instance, plug in x = 1 and y = -4 to get...
y = ax^2+bx+c
-4 = a*1^2+b*1+c
-4 = a+b+c
Do the same for (3,-1) and you should get the equation -1 = 9a+3b+c
Repeat for (5,4) and you should get 4 = 25a+5b+c
We have this system of equations
-4 = a+b+c-1 = 9a+3b+c4 = 25a+5b+cUse substitution, elimination, or a matrix to solve that system. I'll skip steps, but you should get (a,b,c) = (1/4, 1/2, -19/4) as the solution to that system.
In other words
a = 1/4, b = 1/2, c = -19/4
We go from y = ax^2+bx+c to y = (1/4)x^2+(1/2)x-19/4
----------
Next we complete the square
y = (1/4)x^2+(1/2)x-19/4
y = (1/4)( x^2+2x )-19/4
y = (1/4)( x^2+2x+0 )-19/4
y = (1/4)( x^2+2x+1-1 )-19/4
y = (1/4)( (x^2+2x+1)-1 )-19/4
y = (1/4)( (x+1)^2-1 )-19/4
y = (1/4)(x+1)^2- 1/4 - 19/4
y = (1/4)(x+1)^2 + (-1-19)/4
y = (1/4)(x+1)^2 - 20/4
y = (1/4)(x+1)^2 - 5
The equation is in vertex form with (-1,-5) as the vertex. It's the lowest point on this parabola. Placing it into vertex form allows us to find the inverse fairly quickly.
----------
The last batch of steps is to find the inverse.
Swap x and y. Then solve for y.
y = (1/4)(x+1)^2 - 5
x = (1/4)(y+1)^2 - 5
x+5 = (1/4)(y+1)^2
(1/4)(y+1)^2 = x+5
(y+1)^2 = 4(x+5)
y+1 = sqrt(4(x+5))
y = sqrt(4(x+5)) - 1
I'll let the student check each point to confirm they are on the curve y = sqrt(4(x+5)) - 1.
You can also use a tool like GeoGebra to verify the answer.
e-Test Active
2
3
=+
4
Of(x) = -3x+4
Of(x) = -x +
Of(v)=-3y+4
5
6
7
8
10
TIME REI
Consider the function represented by 9x+3y=12 with x as the independent variable. How can this function be
written using function notation?
42-
The function notation of 9x + 3y = 12 is given as follows:
f(x) = 4 - 3x.
How to write the function notation?The function in the context of this problem is given as follows:
9x + 3y = 12.
The format for the function notation is given as follows:
Hence we must isolate the variable y, as follows:
3y = 12 - 9x
y = 4 - 3x (each term of the expression is divided by 3).
f(x) = 4 - 3x.
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Helppp me plsss :(:)
Answer:
5
Step-by-step explanation:
in a 45 45 90 triangle the 2 equal smaller sides (a) are the same and the hyp is a√2
[ASAP] Which table represents the graph of a logarithmic function in the form y=log _(b)x when b>1
Answer:
the first table
Step-by-step explanation:
We see that the first table represents the logarithmic function \(y = \log_2x\), so it's the first table.
The first table represents the graph of a logarithmic function in the form y=log _(b)x.
What is a logarithm?Exponentiation's inverse function is the logarithm. That is, the logarithm of a given number x is the exponent to which another fixed number, the base b, must be raised in order to obtain that number x.
The given table has data where y is a function of x;
y=F(x)
\(y=log _{b}x \\\\ -2 = log _{b}\frac{1}{4} \\\\ \frac{1}{4} = log _{b}{-2} \\\\ -1= log _{b}\frac{1}{2} \\\\ 0=log _{b}1 \\\\ 1=log _{b}2\)
Hence the first table represents the graph of a logarithmic function in the form y=log _(b)x.
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How do I do my calculations?
The area of the shaded region for the normal distribution is approximately 0.6985.
We have,
To find the area of the shaded region under the standard normal distribution curve between z = -0.87 and z = 1.24, we can use a standard normal distribution table or a calculator with a standard normal distribution function.
Using a standard normal distribution table, we look up the area to the left of z = -0.87 and the area to the left of z = 1.24 and then subtract the smaller area from the larger area to find the area between z = -0.87 and z = 1.24.
The table value for z = -0.87 is 0.1949, and the table value for z = 1.24 is 0.8934.
The area between z = -0.87 and z = 1.24 is:
= 0.8934 - 0.1949
= 0.6985
So the area of the shaded region is approximately 0.6985.
Thus,
The area of the shaded region for the normal distribution is approximately 0.6985.
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Recall that Rn denotes the right-endpoint approximation using n rectangles, Ln denotes the left-endpoint approximation using n rectangles, and Mn denotes the midpoint approximation using n rectangles. Calculate the approximation for each of the given function and interval below. (a) R5, f(x) = x2 + x on the interval [−1,1]. (b) L6, f(x) = √6x + 2 on the interval [1,3]. (c) M4, f(x) = 1 x2 + 1 on the interval [1,5].
The approximation for each of the given function and interval below is 1.12
The term function refers the special relationship where each input has a single output.
Here we have given that (a) R5, f(x) = x2 + x on the interval [−1,1]
And we need to find the the approximation for each of the given function and interval
Here we want to to calculate the right-endpoint approximation (the right Riemann sum) for the function:
=> f(x) = x² + x
For the interval [-1, 1] using five equal rectangles.
Let us find the width of each rectangle:
=> Δx = (1 - (-1))/5 = 2/5
Now, we have to list the x-coordinates starting with -1 and ending with 1 with increments of 2/5:
=> -1, -3/5, -1/5, 1/5, 3/5, 1.
Here we are find the right-hand approximation, we use the five coordinates on the right.
Then we have to evaluate the function for each value. This is shown in the table below.
And then each area of each rectangle is its area (the y-value) times its width, which is a constant 2/5.
Therefore, the approximation for the area under the curve of the function f(x) over the interval [-1, 1] using five equal rectangles is:
=> R₅ = 2/5 [-0.24 - 0.16 + 0.24 + 0.96 + 2] = 1.12
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1) Solve for r: 4= r/8
2) What symbol makes the statement true? 27×(36_6)=162
3) Solve for h: 19h=15
Answer:
1) r = 32
2) symbol is '÷'
3) h = 15/19
Step-by-step explanation:
Heeeelp please, Can be zero or not?
with all steps and explanay.
The value of integral is 3.
Let's evaluate the integral over the positive half of the interval:
∫[0 to π] (cos(x) / √(4 + 3sin(x))) dx
Let u = 4 + 3sin(x), then du = 3cos(x) dx.
Substituting these expressions into the integral, we have:
∫[0 to π] (cos(x) / sqrt(4 + 3sin(x))) dx = ∫[0 to π] (1 / (3√u)) du
Using the power rule of integration, the integral becomes:
∫[0 to π] (1 / (3√u)) du = (2/3) . 2√u ∣[0 to π]
Evaluating the definite integral at the limits of integration:
(2/3)2√u ∣[0 to π] = (2/3) 2(√(4 + 3sin(π)) - √(4 + 3sin(0)))
(2/3) x 2(√(4) - √(4)) = (2/3) x 2(2 - 2) = (2/3) x 2(0) = 0
So, the value of integral is
= 3-0
= 3
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Answer:
\(3-\displaystyle \int^{\pi}_{-\pi} \dfrac{\cos x}{\sqrt{4+3 \sin x}}\; \text{d}x\approx 0.806\; \sf (3\;d.p.)\)
Step-by-step explanation:
First, compute the indefinite integral:
\(\displaystyle \int \dfrac{\cos x}{\sqrt{4+3\sin x}}\; \text{d}x\)
To evaluate the indefinite integral, use the method of substitution.
\(\textsf{Let} \;\;u = 4 + 3 \sin x\)
Find du/dx and rewrite it so that dx is on its own:
\(\dfrac{\text{d}u}{\text{d}x}=3 \cos x \implies \text{d}x=\dfrac{1}{3 \cos x}\; \text{d}u\)
Rewrite the original integral in terms of u and du, and evaluate:
\(\begin{aligned}\displaystyle \int \dfrac{\cos x}{\sqrt{4+3\sin x}}\; \text{d}x&=\int \dfrac{\cos x}{\sqrt{u}}\cdot \dfrac{1}{3 \cos x}\; \text{d}u\\\\&=\int \dfrac{1}{3\sqrt{u}}\; \text{d}u\\\\&=\int\dfrac{1}{3}u^{-\frac{1}{2}}\; \text{d}u\\\\&=\dfrac{1}{-\frac{1}{2}+1} \cdot \dfrac{1}{3}u^{-\frac{1}{2}+1}+C\\\\&=\dfrac{2}{3}\sqrt{u}+C\end{aligned}\)
Substitute back u = 4 + 3 sin x:
\(= \dfrac{2}{3}\sqrt{4+3\sin x}+C\)
Therefore:
\(\displaystyle \int \dfrac{\cos x}{\sqrt{4+3\sin x}}\; \text{d}x= \dfrac{2}{3}\sqrt{4+3\sin x}+C\)
To evaluate the definite integral, we must first determine any intervals within the given interval -π ≤ x ≤ π where the curve lies below the x-axis. This is because when we integrate a function that lies below the x-axis, it will give a negative area value.
Find the x-intercepts by setting the function to zero and solving for x in the given interval -π ≤ x ≤ π.
\(\begin{aligned}\dfrac{\cos x}{\sqrt{4+3\sin x}}&=0\\\\\cos x&=0\\\\x&=\arccos0\\\\\implies x&=-\dfrac{\pi }{2}, \dfrac{\pi }{2}\end{aligned}\)
Therefore, the curve of the function is:
Below the x-axis between -π and -π/2.Above the x-axis between -π/2 and π/2.Below the x-axis between π/2 and π.So to calculate the total area, we need to calculate the positive and negative areas separately and then add them together, remembering that if you integrate a function to find an area that lies below the x-axis, it will give a negative value.
Integrate the function between -π and -π/2.
As the area is below the x-axis, we need to negate the integral so that the resulting area is positive:
\(\begin{aligned}A_1=-\displaystyle \int^{-\frac{\pi}{2}}_{-\pi} \dfrac{\cos x}{\sqrt{4+3\sin x}}\; \text{d}x&=- \left[\dfrac{2}{3}\sqrt{4+3\sin x}\right]^{-\frac{\pi}{2}}_{-\pi}\\\\&=-\dfrac{2}{3}\sqrt{4+3 \sin \left(-\frac{\pi}{2}\right)}+\dfrac{2}{3}\sqrt{4+3 \sin \left(-\pi\right)}\\\\&=-\dfrac{2}{3}\sqrt{4+3 (-1)}+\dfrac{2}{3}\sqrt{4+3 (0)}\\\\&=-\dfrac{2}{3}+\dfrac{4}{3}\\\\&=\dfrac{2}{3}\end{aligned}\)
Integrate the function between -π/2 and π/2:
\(\begin{aligned}A_2=\displaystyle \int^{\frac{\pi}{2}}_{-\frac{\pi}{2}} \dfrac{\cos x}{\sqrt{4+3\sin x}}\; \text{d}x&= \left[\dfrac{2}{3}\sqrt{4+3\sin x}\right]^{\frac{\pi}{2}}_{-\frac{\pi}{2}}\\\\&=\dfrac{2}{3}\sqrt{4+3 \sin \left(\frac{\pi}{2}\right)}-\dfrac{2}{3}\sqrt{4+3 \sin \left(-\frac{\pi}{2}\right)}\\\\&=\dfrac{2}{3}\sqrt{4+3 (1)}-\dfrac{2}{3}\sqrt{4+3 (-1)}\\\\&=\dfrac{2\sqrt{7}}{3}-\dfrac{2}{3}\\\\&=\dfrac{2\sqrt{7}-2}{3}\end{aligned}\)
Integrate the function between π/2 and π.
As the area is below the x-axis, we need to negate the integral so that the resulting area is positive:
\(\begin{aligned}A_3=-\displaystyle \int^{\pi}_{\frac{\pi}{2}} \dfrac{\cos x}{\sqrt{4+3\sin x}}\; \text{d}x&= -\left[\dfrac{2}{3}\sqrt{4+3\sin x}\right]^{\pi}_{\frac{\pi}{2}}\\\\&=-\dfrac{2}{3}\sqrt{4+3 \sin \left(\pi\right)}+\dfrac{2}{3}\sqrt{4+3 \sin \left(\frac{\pi}{2}\right)}\\\\&=-\dfrac{2}{3}\sqrt{4+3 (0)}+\dfrac{2}{3}\sqrt{4+3 (1)}\\\\&=-\dfrac{4}{3}+\dfrac{2\sqrt{7}}{3}\\\\&=\dfrac{2\sqrt{7}-4}{3}\end{aligned}\)
To evaluate the definite integral, sum A₁, A₂ and A₃:
\(\begin{aligned}\displaystyle \int^{\pi}_{-\pi} \dfrac{\cos x}{\sqrt{4+3\sin x}}\; \text{d}x&=\dfrac{2}{3}+\dfrac{2\sqrt{7}-2}{3}+\dfrac{2\sqrt{7}-4}{3}\\\\&=\dfrac{2+2\sqrt{7}-2+2\sqrt{7}-4}{3}\\\\&=\dfrac{4\sqrt{7}-4}{3}\\\\ &\approx2.194\; \sf (3\;d.p.)\end{aligned}\)
Now we have evaluated the definite integral, we can subtract it from 3 to evaluate the given expression:
\(\begin{aligned}3-\displaystyle \int^{\pi}_{-\pi} \dfrac{\cos x}{\sqrt{4+3 \sin x}}\; \text{d}x&=3-\dfrac{4\sqrt{7}-4}{3}\\\\&=\dfrac{9}{3}-\dfrac{4\sqrt{7}-4}{3}\\\\&=\dfrac{9-(4\sqrt{7}-4)}{3}\\\\&=\dfrac{13-4\sqrt{7}}{3}\\\\&\approx 0.806\; \sf (3\;d.p.)\end{aligned}\)
Therefore, the given expression cannot be zero.
The table shows three unique functions.
x f(x) g(x) h(x)
-2
4
6
-3
-1
1
2
1
4-
2
1
1
55 752
6
8
1
Hit
6:
Mark this and return
-25
Which statements can be used to compare the
characteristics of the functions? Select two options.
Of(x) has an all negative domain.
g(x) has the greatest maximum value.
All three functions share the same range.
Oh(x) has a range of all negative numbers.
All three functions share the same domain.
Answer:
The statements that can be used to compare the characteristics of the functions are:
1. g(x) has the greatest maximum value.
2. All three functions share the same domain.
Explanation:
- The table shows the values of three functions - f(x), g(x), and h(x) - evaluated at different values of x.
- We cannot determine the domain of f(x) or h(x) from the given table but we can see that g(x) has a domain of all real numbers.
- We can see that g(x) has the highest maximum value among the three functions, which is 8.
- We cannot determine the range of f(x) or g(x) from the given table but we can see that h(x) has a range of all negative numbers.
- We cannot say anything about the domain or range of f(x) based on the given table.
- Therefore, the two statements that can be used to compare the characteristics of the functions are: g(x) has the greatest maximum value and all three functions share the same domain.
If h = 12 and g = 4, which of the following has a value of 3?
1. g + 1
2. h - g
3. h ÷ 3
4. h/g
Answer:
Number 4 has a value of 3.
Step-by-step explanation:
1. 4 + 1 = 5
2. 12 - 4 = 8
3. 12 / 3 = 4
4. 12 / 4 = 3
Apiece of Wire 80cm long is cut into the two parts and bent each part to Form a square the tota area of the two squaresquare is 250 Find perimiter of each Square side length of each Square
The perimeter of the square with side of 5 cm is 20 cm.
The perimeter of the square with side length of 15 cm is 60 cm.
What is the area of each square?The area of each square is calculated as follows;
Let the dimension of first square = x
Let the dimension of second square = y
x² + y² = 250 ---- (1)
4(x + y) = 80 ----- (2)
x + y = 80/4
x + y = 20
x = 20 - y
Substitute x in equation (1)
(20 - y)² + y² = 250
400 - 40y + y² + y² = 250
2y² - 40y + 150 = 0
y² - 20y + 75 = 0
solve for y, using formula method;
y = 15 or 5
Solve for x;
x = 20 -15 = 5 or
x = 20 - 5 = 15
The perimeter of first = 4x = 4 x 5 = 20 cm
The perimeter of the second = 4y = 4 x 15 = 60 cm
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x2 + 3x - 4 = 6 any one know how to solve this
Answer:
-5,2
Step-by-step explanation:
make one side equal zero, x2 + 3x - 10
use guess and check to reverse foil and find (x+5)(x-2)
solve and get x = -5 , 2
Answer (it has two solutions):
x = -5x = 2I hope this helps!
Find the surface area of the solid given the net.
A. 1292 units²
B. 807.5 units
C. 646 units²
D. 935 units²
Answer:
Step-by-step explanation:
To find the surface area of the solid given the net, we need to identify all of the faces and add up their areas. Looking at the net, we can see that the solid consists of a rectangular prism and two triangular prisms attached to its sides.
To find the area of the rectangular prism, we need to multiply the length, width, and height. From the net, we can see that the length is 12 units, the width is 5 units, and the height is 8 units. So, the area of the rectangular prism is:
Area = length * width * height
Area = 12 units * 5 units * 8 units
Area = 480 units²
To find the area of the triangular prisms, we need to multiply the base, height, and half the width. From the net, we can see that the base of each triangular prism is 12 units and the height is 8 units. To find the width, we can use the Pythagorean theorem:
width² = height² + base²/4
width² = 8² + 12²/4
width² = 64 + 36
width² = 100
width = 10 units
So, the area of each triangular prism is:
Area = 1/2 * base * height * width
Area = 1/2 * 12 units * 8 units * 10 units
Area = 480 units²
Now, we can add up the areas of all three faces to find the total surface area:
Surface area = area of rectangular prism + area of two triangular prisms
Surface area = 480 units² + 480 units² + 480 units²
Surface area = 1440 units²
Therefore, the surface area of the solid given the net is 1440 units². None of the answer choices match exactly, but the closest one is A. 1292 units².
determine whether or not the distribution is a discrete probability distribution and select the reason why or why not. X = 0, 1, 9P( X = x ) | 0.41 | 0.6 | 0.06
Since the probabilities lie exclusively between 0 and 1 and the sum of probabilities is equal to 1 , therefore the yes , the distribution is discrete probability distribution.
As the probabilities range from 0 to 1, and the sum of probability equals 1.
Discrete probability distribution is a sort of probability distribution that provides all potential values of a discrete random variable along with the related probabilities. In other words, a discrete probability distribution describes the possibility of each potential value of a discrete random variable occurring.
Some common discrete probability distributions are geometric distributions, binomial distributions, and Bernoulli distributions. This page defines a discrete probability distribution, as well as its formulas, types, and numerous instances.
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In rectangle ABCD AE = 3x+3 and BD = 36 what is the value of x
Answer:
Step-by-step explanation:
Since AE is equal to 3x + 3 and BD is equal to 36, we can set up an equation to solve for x. If we let the width of the rectangle be x, then the length would be 3x + 3.
Area of the rectangle = width * length
36 * (3x + 3) = (3x + 3) * x
Expanding the right side, we get:
36 * (3x + 3) = 3x^2 + 3x + 3x + 9
36 * (3x + 3) = 3x^2 + 6x + 9
Dividing both sides by 3, we get:
12 * (3x + 3) = x^2 + 2x + 3
Expanding the left side, we get:
12 * (3x + 3) = x^2 + 2x + 3
36 * 3x + 36 * 3 = x^2 + 2x + 3
108x + 108 = x^2 + 2x + 3
Subtracting 3 from both sides, we get:
108x + 105 = x^2 + 2x
Expanding the left side, we get:
x^2 + 2x - 108x - 105 = 0
Combining like terms on the left side, we get:
x^2 - 106x - 105 = 0
Using the quadratic formula, we can solve for x:
x = (-b ± √(b^2 - 4ac)) / 2a
where a = 1, b = -106, and c = -105.
Plugging in the values, we get:
x = (-(-106) ± √((-106)^2 - 4 * 1 * -105)) / 2 * 1
x = (106 ± √(11,336 + 420)) / 2
x = (106 ± √11,756) / 2
x = (106 ± 34) / 2
Since x has to be positive, we take the positive square root:
x = (106 + 34) / 2
x = 70 / 2
x = 35.
So the width of the rectangle is 35 units.
in a class of c children there are 16 boys what fraction of the class are boys
Answer:
16/c of the class are boys
Step-by-step explanation:
If there are a total number of children, c, and 16 of them are boys, you are going to put the total number of children on the bottom of the fraction as the denominator and put the number that are boys on top of the fraction as the numerator.
(I hoped this helped)
Answer:
Step-by-step explanation:
if the number of the children is c and we have 16 boys
the fraction will be c/16
I need help with this question please with details
The dimensions of the rectangular box are given as follows:
All the dimensions.
A. 6 inches long, 3 inches wide, 3 inches tallB. 9 inches long, 2 inches wide, 3 inches tallC. 18 inches long, 3 inches wide, 1 inch tallD. 27 inches long, 2 inches wide, 1 inches tallHow to obtain the volume of a rectangular prism?The volume of a rectangular prism, with dimensions length, width and height, is given by the multiplication of these dimensions, according to the equation presented as follows:
Volume = length x width x height.
The box's volume is obtained as follows:
54 x 1³ = 128 x (3/4)³ = 54 cubic inches. (the volume of a cube is the side length cubed)
Hence all the options can be the dimensions of the box, as all the options have a multiplication resulting in 54.
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For a project in his Geometry class, Amadou uses a mirror on the ground to measure the height of his school building. He walks a distance of 11.15 meters from the building, then places a mirror flat on the ground, marked with an X at the center. He then walks 1.05 more meters past the mirror, so that when he turns around and looks down at the mirror, he can see the top of the school clearly marked in the X. His partner measures the distance from his eyes to the ground to be 1.25 meters. How tall is the school? Round your answer to the nearest hundredth of a meter
The height of the school is 13.27 m.
What is a triangle?It is a two-dimensional figure which has three sides and the sum of the three angles is equal to 180 degrees.
We have.
From the information given, we can draw the figure given below,
Now,
Triangle ABC and Triangle DCE are similar.
So,
x / 1.25 = 11.15 / 1.05
x = (11.15 x 1.25) / 1.05
x = 13.27 m
Thus,
The height of the school is 13.27 m.
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The sum of two numbers is -64. Their difference is -10. Find the numbers.
The smaller number is:
The larger number is:
Answer:
smaller: -37, larger: -27
Step-by-step explanation:
say one number is x the other one is y
x+y = -64
x-y = -10
subtract the two equations to get
2y = -54
y = -27
x = -37
-27 is larger, -37 is smaller
1,2,3,4,5,6,7,8,9,10,........
Answer:
What is this it's okay but thanks for points
Step-by-step explanation:
anyone can solve this?
\( \sqrt[4] {a}^{3 \:} to \: power\)
The value of the expression \(\sqrt[4]{a}^3\) when evaluated is \(a^\frac34\)
How to evaluate the expressionFrom the question, we have the following parameters that can be used in our computation:
\(\sqrt[4]{a}^3\)
Consider an expression expressed as xⁿ
The expression can be expanded as
xⁿ = x * x * x .... in n places
Using the above as a guide, we have the following:
\(\sqrt[4]{a}^3 = \sqrt[4]{a} * \sqrt[4]{a} * \sqrt[4]{a}\)
Apply the exponent rule of indices
\(\sqrt[4]{a}^3 = a^\frac14 * a^\frac14 * a^\frac14\)
Apply the power rule of indices
\(\sqrt[4]{a}^3 = a^\frac34\)
Hence, the expression \(\sqrt[4]{a}^3\) when evaluated is \(a^\frac34\)
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Please help me please
Answer:
486 square inches
Step-by-step explanation:
Which statement is correct?
Alex reads a newspaper and sees this headline:
they need to know which statement is correct according to Alex's headline in the newspaper
Asap needed please
thanks
Answer:
the football players salary is more that 71,000
Step-by-step explanation:
what ever way the open part of the arrow is facing means more than
for example
10>3
or
1<5
xyz for the given values of x=4/5, y=-15, z=7/8
Answer:
xyz = - \(\frac{21}{2}\)
Step-by-step explanation:
substitute the given values into the expression
xyz
= \(\frac{4}{5}\) × - 15 × \(\frac{7}{8}\)
= - 12 × \(\frac{7}{8}\)
= - 3 × \(\frac{7}{2}\)
= - \(\frac{21}{2}\)
Write a quadratic function in standard form that represents the table below: BUNCH OF POINTS IF YOU HELP!
Answer:
Step-by-step explanation:
ax² + bx + c = y
( 0 , 3 ) ⇒ c = 3
( 1 , - 3 )
a(1)² + b(1) + 3 = - 3 ⇒ a + b = - 6 ⇒ a = - b - 6 ........ (1)
( 2 , - 5 )
a(2)² + b(2) + 3 = - 5 ⇒ 4a + 2b + 3 = - 5 ......... (2)
(1) -----> (2)
4( - b - 6 ) + 2b = - 8 ⇒ b = - 8
a = 2
y = 2x² - 8x + 3
if a fuel efficient car can go 210 miles on 4gallons of fuel, how far can it go on 12
ABCD paralleogram, AE is perpendicular to EC, and DF is perpendicular to EC. Prove AEFD is a triangle
Answer:
ABCD paralleogram, AE is perpendicular to EC, and DF is perpendicular to EC. Prove AEFD is a triangle