A galvanic cell at a temperature of 25.0°C is powered by the following redox reaction:

2MnO4^-(aq)+16H+(aq)+5Pb(s)-->2Mn^2+(aq)+8H2O(l)+5Pb^2+(aq)

Suppose the cell is prepared with 1.87 M MnO−4 and 1.37 M H+ in one half-cell and 3.23 M Mn+2 and 6.62 M Pb+2 in the other. Calculate the cell voltage under these conditions. Round your answer to 3 significant digits.

Answer:

B and C

Explanation:

B=calcium (Ca)

C=Barium{Ba)

Answer:

3) option c

4) option b

5) option a

pls mark brainliest

In both plants and animals, the process of cellular respiration may be broken down into the following steps: Oxygen + carbon dioxide.

When plant cells undergo cellular respiration, oxygen is taken in through the plant's leaves from the surrounding atmosphere, and carbon dioxide is exhaled back into the atmosphere as a byproduct of the process. In contrast, when animal cells undergo cellular respiration, oxygen is taken in through the lungs, and carbon dioxide is exhaled through the lungs.

Therefore, a quick review, throughout the process of cellular respiration, plants and animals trade oxygen and carbon dioxide with one another.

Therefore, we may draw the following conclusion: Oxygen + carbon dioxide is a shorthand for the process of cellular respiration in plants and animals.

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Answer:

0.001968 M min-1

Explanation:

NH2NO2(aq) --> N2O(g) + H2O(l)

[NH2NO2],M       0.978 0.476 0.232    0.113

time, min              0          255     510      765

The average rate of disappearance over the time period form t = 0 min to t = 255 min is given as;

Average rate = Change in concentration / time taken

Change in concentration = Final Concentration - Initial concentration

Change = 0.476 - 0.978 = 0.502

time taken = 255min - 0min = 255 min

Average rate = 0.502 / 255 = 0.001968 M min-1

Answer:

It is a becaues i am a doctor and i know about that

Explanation:Just here to help

Answer:

i wish i could help but t know either so i wish you luck for an answer once again truly sorry don'

Explanation:

i am sorry but i do not know :(

There is no limiting reactant because both reactants produce the same amount of products indicating that neither reactant is in excess and both are fully consumed in the reaction.

The limiting reagent is described as  the reactant that is completely used up in a reaction, and thus determines when the reaction stops.

calculating the number of moles of each reactant of the equation:

C2H4 + 3 O2 -> 2 CO2 + 2 H2O.

Moles of C2H4: not given, assume 1 mole

Moles of O2: 3 moles (given in the equation)

Moles of CO2 produced by 1 mole of C2H4: 2 moles (from the balanced equation)

Moles of H2O produced by 1 mole of C2H4: 2 moles (from the balanced equation)

Moles of CO2 produced by 3 moles of O2: 2 x 3/3 = 2 moles (from the balanced equation)

Moles of H2O produced by 3 moles of O2: 2 x 3/3 = 2 moles (from the balanced equation)

In conclusion, both reactants produce the same amount of products (2 moles of CO2 and 2 moles of H2O).

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Answer:

They increase from left to right and top to bottom.

Answer:

They increase from left to right and top to bottom.

A reaction has an enthalpy change of +14 kJ mol-¹ entropy change of +37 J K-¹ mol-¹. the temperature is 378105.2284°C.

Generally, To determine the temperature at which an endothermic reaction becomes spontaneous, you need to use the entropy change of the reaction and the enthalpy change of the reaction. This can be done using the equation:

ΔG = ΔH - TΔS

Where

If the ΔG for a reaction is negative, then the reaction is spontaneous. If the ΔG for a reaction is positive, then the reaction is not spontaneous.

In this case, we are given that the enthalpy change for the reaction is +14 kJ/mol and the entropy change for the reaction is +37 J/K*mol.

We can use this information to solve for the temperature at which the reaction becomes spontaneous

ΔG = ΔH - TΔS

0 = +14 kJ/mol - T(+37 J/Kmol)

T = 14000 J/mol / (37 J/Kmol*1/1000)

T = 378378.3784 K

Thus, the temperature at which this endothermic reaction becomes spontaneous is approximately 378378.3784 K, which is approximately 378105.2284°C.

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The mass of Fluorine in grams in the second sample is 2066 g. The concept law of definite proportions is used here to obtain the mass of Fluorine in the second sample.

This law was stated by a French chemist, Louis Proust. It states that 'a chemical compound always contains the same elements combined together in the same proportion by mass'.

The mass of Mg in sample 1 is 1.66 kg and that of F is 2.56 kg. The mass of Mg in sample 2 is 1.34 kg and we have to find out the mass of F in second sample.

The mass of Fluorine in sample 2 can be obtained by using the mass ratio of the elements in sample 1.

In sample 1:

Mass of magnesium ÷ Mass of Fluorine = 1.66 kg ÷ 2.56 kg

In sample 2:

By using dimensional analysis,

Mass of Fluorine = 2.56 kg Fluorine ÷ 1.66 kg Magnesium × 1.34 kg Magnesium

Therefore the mass of Fluorine = 2.066 kg

The mass in kilogram can be converted into grams as:

Mass of Fluorine = 2.066 kg × 1000 g ÷ 1 kg = 2066 g

Thus the mass of Fluorine in the second sample is 2066 g.

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Answer:

The density of water is 1g/mL

It is an amine, and it has less polar nitrogen-hydrogen and oxygen-hydrogen bonds.

A compound's boiling point is a physical characteristic. These intramolecular linkages between the molecules that make up a chemical affect these physical characteristics.

Alcohols and amino acids have the same kind of intermolecular linkages. The hydrogen bond is the name of this kind of bond.

The electrical attraction between a hydrogen atom from one molecule and an electronegative atom from a nearby molecule is known as a hydrogen bond.

The strength of the bond is in the following order: H.....F > H.....O > H......N

The H....N hydrogen bonds exist in amines, whereas the H....O hydrogen bonds exist in alcohols.

Consequently, the alcohol's hydrogen bonds are stronger and it will impart a higher boiling point on the compound.

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Answer:uses world like

Explanation:

When two objects descend towards one another, the potential energy related to the gravitational field is released (transformed into kinetic energy).

The potential energy that a huge item has in relation to a different massive object due to gravity is known as gravitational energy and gravitational potential energy. When two objects descend towards one another, the potential energy related to the gravitational field is released (transformed into kinetic energy). Bringing two things farther apart increases the gravitational potential energy.

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Option B, where [OH-] is 1.0 x 10-13 mol dm-³3, is the only one that can be considered basic. Therefore, Option B is the correct answer.

To determine whether a solution is basic or acidic at 25 °C, we can compare the concentration of hydroxide ions ([OH-]) with the concentration of hydronium ions ([\(H_3O\)+]). In a neutral solution, the concentrations of [\(H_3O\)+] and [OH-] are equal, resulting in a pH of 7.

Option A states that the concentration of [\(H_3O\)+] is 1.0 x 10-3 mol dm-3. Since [\(H_3O\)+] represents the concentration of hydronium ions, this solution would be acidic because the concentration of [\(H_3O\)+] is higher than [OH-], indicating an excess of hydronium ions.

Option B states that the concentration of [OH-] is 1.0 x 10-13 mol dm-³3. In this case, [OH-] is higher than [\(H_3O\)+], indicating an excess of hydroxide ions. Therefore, this solution would be considered basic.

Option C states that the solution has a pH of 4.00. A pH of 4.00 is below the neutral pH of 7, indicating an excess of hydronium ions and an acidic solution. Therefore, this option does not represent a basic solution.

Option D states that the concentration of [\(H_3O\)+] is 1.0 x 10-13 mol dm-3. Similar to Option A, this concentration of [\(H_3O\)+] indicates an acidic solution, not a basic one.

Option B

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Answer:

D is the correct answer

Explanation:

In order for a solution to be basic at 25 C, the H+ concentration has to be less than the OH- concentration, and given that H+ times OH- is 10^-14, we deduce that H+ must be less than 10^-7 for the solution to be acidic. Thus, A can be eliminated, and so can C. With B, we calculate an H+ concentration of 0.1M, which also fails to be less than 10^-7
Thus, D is the correct answer and we can verify that as H+ is less than 10^-7.



Note: I do not know why my previous answer was deleted for "being incorrect", and i'm not sure how the incorrect answer was "expert verified", but I am as certain that D is the correct answer as i am sure of 3*(4+5-1) being equal to 24.

Answer:

b) 3x10³m³

Explanation:

The volume of each astronaut breathing in m³ is:

500cm³ * (1x10⁻⁶m³ / 1cm³) = 5x10⁻⁴m³

In 1 minute, the volume is:

5x10⁻⁴m³ * 15 = 7.5x10⁻³m³

In 1 hour:

7.5x10⁻³m³ /min  * (60min / 1 hour) = 0.45m³/h

In 1 day:

0.45m³/h * (24h / 1 day) = 10.8m³/day

In 1 year:

10.8m³/day * (365 days / 1 year) = 3942m³ = 3.9x10³m³

That is approximately:

12 tablets maximum number of Percocet tablets a patient can take daily

Percocet is a prescription medicine used to treat the symptoms of acute pain and moderate-to-severe pain percocet may be used alone or with other medications percocet belongs to a class of drugs called Analgesics, Opioid Combos every strength also contains 325  this is the weakest dose of Percocet and is what most doctors will start with to help avoid side effects like respiratory depression this dosage is also used to gradually reduce Percocet dosage after dependence has developed, and to limit withdrawal symptoms percocet is a pain reliever for moderate to severe symptom over dose of percocet show side effect on body thats why 12 tablets maximum number of Percocet tablets a patient can take daily.

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Based on the given half-life, the amount of time it takes for 3/4 of a radioactive sample of an isotope of bromine to decay is 33 hours.

The time needed for a quantity to decrease to half of its initial value is known as the half-life. In nuclear physics, the phrase is frequently used to indicate how rapidly unstable atoms decay radioactively or how long stable atoms last.

Any substance that contains unstable atoms that release ionizing radiation during their natural decay is considered radioactive material.

Given the half-life of the radioactive sample of an isotope of bromine to be 16.5 hours. The amount of time it takes for 3/4 of a radioactive sample of an isotope of bromine to decay is calculated as follows:

After one half-life, half of the sample remains, and half decays

After two half-lives, 1/4 of the sample remains, and 3/4 decays

The time for two half-lives = 16.5 hours * 2

The time for two half-lives = 33 hours.

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Explanation:

As you know, the conjugate base of an acid is determined by looking at the compound that's left behind after the acid donates one of its acidic hydrogen atoms.

The compound to which the acid donates a proton acts as a base. The conjugate base of the acid will be the compound that reforms the acid by accepting a proton.

In this case, sulfurous acid has two protons to donate. However, the conjugate base of sulfurous acid will be the compound left behind after the first hydrogen ion is donated.

Answer:

7 sublimation

8 freezing

9 melting

10 condensation

11 evaporation

Explanation:

The order of increasing ionic property is;

WO3 < ZrS2 < MnS2< ZnS < MnS

Ionic compounds are compounds that contain an ion pair. Typically, ionic compounds are formed between metals and nonmetals.

The degree of ionic character depends on the type of metal involved and the magnitude of charge it carries.

Typically, first row transition metals form ionic compounds. The degree of ionic character depends on the row in which the metal is found and the magnitude of charge it carries.

Hence, the order of ionic character of the compounds from most ionic to least Ionic is; WO3 < ZrS2 < MnS2< ZnS < MnS.

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2.96 × 10²³ molecules is required if Alex drips hydrochloric acid onto a 5.9 g piece of magnesium in a single displacement reaction

According to this question, hydrochloric acid (HCl) reacts with magnesium metal (Mg) to produce magnesium chloride and hydrogen has as follows:

2HCl(aq) + Mg(s) → MgCl2(aq) + H2(g)

Where; Mg = 24g/mol

mole = 5.9/24

mole = 0.246mol of Mg

To convert mole to number of molecules, we multiply number of moles by 6.02 × 10²³ (Avogadro's no.)

Hence, number of molecules of HCl required is 0.492mol × 6.02 × 10²³

= 2.96 × 10²³ molecules of HClHCl

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Answer:

I cannot see what you are trying to show.

Explanation:

Answer: 21.90 grams HCl  ; 22 g HCl if need correct sig figs

Explanation:

moles = M X L  = 1.5 x .40 =0.60 moles HCl

convert to grams

0.60 X 36.5 = 21.90

The half reaction with a more positive standard reduction potential will proceed spontaneously in a redox reaction

The half reaction with a more positive standard reduction potential will undergo reduction when compared to the half reaction with a more negative standard reduction potential.

Oxidation-reduction reactions, often known as redox reactions, are a set of chemical reactions that involve electron transfer between reactants. In a redox reaction, one reactant is oxidized, losing electrons, while the other reactant is reduced, gaining electrons.

The oxidation half-reaction is the process of losing electrons and increasing the oxidation number, whereas the reduction half-reaction is the process of gaining electrons and decreasing the oxidation number. The total reaction is referred to as the redox reaction.

Half-reaction:Half-reaction refers to the two parts of an oxidation-reduction reaction that happen separately. A half-reaction must always be either an oxidation reaction or a reduction reaction. It also describes the movement of electrons and hydrogen ions in an equation.

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So, we're going to find the electron configuration for the ion:

This is, the same Mn electron configuration, with 4 less electrons:

As you can see, the number of electrons of the given ion is 21, so that's its electron configuration. :)

Answer: 4.76 * 10^2

476.

you bring the ending decimal to the first number and it takes you two hops to get the first number so that's what you put in the box after the 10

Answer:

1

Explanation:

To determine the value of K (equilibrium constant) at 25 °C, we can use the Nernst equation, which relates the cell potential (E) to the equilibrium constant (K) and the standard cell potential (EºCell). The Nernst equation is given by:

E = EºCell - (RT / nF) * ln(K)

Where:

E = cell potential

EºCell = standard cell potential

R = gas constant (8.314 J/(mol·K))

T = temperature in Kelvin (25 °C = 298 K)

n = number of electrons transferred in the balanced redox equation

F = Faraday's constant (96,485 C/mol)

ln = natural logarithm

In this case, the given standard cell potential (EºCell) is -0.37 V.

The balanced redox equation for the cell reaction is:

Pt + Cr²+ -> Pt + Cr³+

Since there is no change in the oxidation state of Pt, no electrons are transferred in the reaction (n = 0).

Substituting the known values into the Nernst equation, we have:

E = -0.37 V - (8.314 J/(mol·K) * 298 K / (0 * 96,485 C/mol)) * ln(K)

E = -0.37 V

Since n = 0, the term (RT / nF) * ln(K) becomes 0, and we are left with:

-0.37 V = -0.37 V - 0

This implies that the value of K is 1, since any number raised to the power of 0 is equal to 1.

Therefore, the value of K at 25 °C for the given cell is 1.