A friend asks you to help them decide which crackers are healthier. Comparing approximately equal serving sizes of 1 cracker (approx. 4.5 g Breton serving size vs. 4.7 g Triscuit), which would be a better choice with regards to calories, fat and sodium content?

a. Breton
b. Triscsuit

Answer:

i would say the first one!

At pOH value  of 6.0 the pH value of the following solution is 8.0 and the concentration of [\(H^{+}\) ] ion is \(10^{-8}\)

In this question we will apply the formula

      pH +pOH = 14 . . . . . . . . . . . . .(1)

where pH = concentration of [\(H^{+}\) ] ion

pOH = concentration of [\(OH^{-}\) ] ion

As per the question

pOH =6.0

Putting the value of pOH in equation (1) we get the value of pH

              pH + 6.0 =14

             pH = 14 -6.0

             pH  = 8.0

 The value of pH if the pOH value is 6.0 is 8.0

To find the concentration of \(H^{+}\) ion we will use the following formula

This is calculated by the formula

                                 [\(H^{+}\)} = \(10^{-pH}\)

where we will write the values of pH

Hence the concentration of [\(H^{+}\)} ion is \(10^{-8}\)

Therefore at  pOH of 6.0 the pH value of the following solution is 8.0 and the concentration of [\(H^{+}\) ] ion is \(10^{-8}\)

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The complete question is -

What is the pH value and concentration of [\(H^{+}\) ] ion of the following if the pOH value of the solution is 6.0 ?

Answer:

0.119 moles

Explanation:

Given that,

Mass measured by Nurse Antonio is 7 grams of NaCl

To find,

The no of moles of NaCl

Solution,

The number of moles is given by

\(n=\dfrac{m}{M}\)

m is given mass

M is molar mass

For NaCl, molar mass is 23+35.5 = 58.5 grams

So,

\(n=\dfrac{7}{58.5}\\\\n=0.119\ \text{moles}\)

Therefore, there are 0.119 moles of NaCl.

Answer:

approximately 251.55 grams of AuCl3 would contain 5.0 x 10^23 molecules.

The mass of the object of density 5g/cm³ and volume 10 cm³ is 50kg.

Defining density How tightly a material is packed together is determined by its density. Its definition is "mass per unit volume". D or, the symbol for density

Density Formula: = m/V,

where is the density, m is the object's mass, and V is its volume.

The units used change depending on the calculation's use of mass and volume units. Density would be expressed in kg/cm³ if the mass is expressed in kg and the volume in cm³.

Density = mass / volume

Mass = density ×  volume

Mass =  5×10

Mass = 50 kg.

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Explanation:

hope the picture above make sense:)

Answer:

number. so the option is c

Answer:

atomic number

Explanation:

i just know it

Answer:

no they are an theropod

Explanation:

I'm not completely sure but i hope this helps you maybe! :)

.Answer: No Because of their slender bodies and long tails, salamanders look somewhat like lizards, and people often confuse the two. But lizards are reptiles, whereas salamanders are amphibians (as are frogs and toads)they look really cool to play wit but no not 4 me.

Explanation:

From the table as we can see it ;

A table is often used for the representation of information. We know that a table has to have columns. Each of the columns could be used to show  particular variable. Now we have the temperature, the color and the mass of different stars showed on the table as we can see it in the question.

We now have the assignment to find the color and mass of the start that corresponds to a temperature of about 4290 K hence we have to look intently at the table.

Color of the star - Orange

Average Mass of the star - 0.8

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Answer: What is most likely the color of Arcturus? ORANGE

What is most likely the mass of Arcturus? about 0.8 solar masses

Explanation: just did the assignment

The enthalpy change of the reaction C(diamond) → C(graphite) is -2.9 kJ.

The given information is ΔHrxn for the reaction C(diamond) → C(graphite) can be calculated with the given equations:Equations:  C(diamond) + O2(g) → CO2(g) ΔH = −395.4 kJ  2 CO2(g) → 2 CO(g) + O2(g) ΔH = 566.0 kJ  C(graphite) + O2(g) → CO2(g) ΔH = −393.5 kJ  2 CO(g) → C(graphite) + CO2(g) ΔH = −172.5 kJThe required reaction can be obtained by adding the equations (1) and (4), as follows:C(diamond) + O2(g) + 2CO(g) → C(graphite) + 3CO2(g)Addition of the two equations (1) and (4) results in a reaction whose products are C(graphite) and CO2.

To get the final equation that involves only the required reactants and products, the equation (2) should be added, which consumes CO2 and produces O2, as shown below:C(diamond) + O2(g) → CO2(g)  ΔH = −395.4 kJ [eq. (1)]  2 CO(g) → C(graphite) + CO2(g)  ΔH = −172.5 kJ [eq. (4)]  2 CO2(g) → 2 CO(g) + O2(g)  ΔH = 566.0 kJ [eq. (2)]  C(diamond) + O2(g) + 2CO(g) → C(graphite) + 3CO2(g)  ΔHrxn=ΣΔHf(products)−ΣΔHf(reactants)  ΔHrxn=[(3 mol CO2)(-393.5 kJ/mol) + (1 mol C(graphite))(0 kJ/mol)] − [(1 mol C(diamond))(0 kJ/mol) + (1 mol O2)(0 kJ/mol) + (2 mol CO(g))(−172.5 kJ/mol)] − [(2 mol CO2)(566.0 kJ/mol)]  ΔHrxn=−2.9 kJ.

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The concentration of the solution in molarity, given that 6.802×10²⁰ particles were dissolved in 0.38 L of water is 3.0×10⁻³ M (option B)

First, we shall determine the number of mole that contains 6.802×10²⁰ particles of Mn(NO₃)₃. Details below:

From Avogadro's hypothesis,

6.022×10²³ particles = 1 mole of Mn(NO₃)₃

Therefore, we can say that

6.802×10²⁰ particles = 6.802×10²⁰ / 6.022×10²³

6.802×10²⁰ particles = 0.001 mole of Mn(NO₃)₃

Finally, we shall obtain the molarity of the solution. Details below:

Molarity of solution = mole / volume

Molarity of solution = 0.001 / 0.38

Molarity of solution = 3.0×10⁻³ M (option B)

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The volume of N₂ at STP=56 L

Given

2.5 moles of N₂

Required

The volume of the gas

Solution

Conditions at T 0 ° C and P 1 atm are stated by STP (Standard Temperature and Pressure). At STP, the volume per mole of gas or the molar volume-Vm is 22.4 liters/mol.

So for 2.5 moles gas :

\(\tt 2.5\times 22.4=56~L\)

This representation suggests that the element is phosphorus (P) with a mass number of 30, which is incorrect. The correct mass number for phosphorus is approximately 30.97. The incorrect representation for a neutral atom is 36Li

To determine the correct representation for a neutral atom, we need to consider the atomic number (Z) and mass number (A) of the element. The atomic number represents the number of protons in the nucleus, while the mass number represents the sum of protons and neutrons.

Let's analyze the given representations:

36Li:

This representation suggests that the element is lithium (Li) with a mass number of 36, which is incorrect. The correct mass number for lithium is approximately 6.94.

613C:

This representation suggests that the element is carbon (C) with a mass number of 13, which is correct. Carbon has different isotopes, and 13C represents one of its stable isotopes.

3063Cu:

This representation suggests that the element is copper (Cu) with a mass number of 63, which is correct. Copper has different isotopes, and 63Cu represents one of its stable isotopes.

1530P:

This representation suggests that the element is phosphorus (P) with a mass number of 30, which is incorrect. The correct mass number for phosphorus is approximately 30.97.

Therefore, the incorrect representation for a neutral atom is 36Li, as it does not match the known properties of lithium.

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Answer: Well, the volume of the copper is (63.4 - 40.0) * mL = 23.4 * mL

Explanation:

Do you agree? The copper displaces the given volume of water.

Now  ρ Cu =  8.90  ⋅  g  ⋅  c m 3  OR  ρ Cu  =  8.90  ⋅  g  ⋅  m L − 1, i.e.  1 ⋅  m L  ≡  1  ⋅  c m 3

But by definition,  ρ  density  =  mass  volume

And thus  mass  =  ρ  ×  volume  =  8.90  ⋅  g  ⋅  m  L  −  1  ×  23.4  ⋅  m  L

= 208.3 * G

Answer:

1023 mole or just 1

2 elements

1 atom of carbon and 2 atoms of oxygen

2 I believe

and I think the 2 is a subscript

Layer 1 because it is closest to the surface

Answer: The pressure in the container is 1949.5 torr when the volume is 7.20 liters and the temperature is 71.0 °C

Explanation: To solve this problem, we can use the combined gas law, which relates the initial and final conditions of pressure (P), volume (V), and temperature (T) for an ideal gas:

(P1 × V1) / T1 = (P2 × V2) / T2

where P1, V1, and T1 are the initial pressure, volume, and temperature, and P2, V2, and T2 are the final pressure, volume, and temperature.

We can plug in the given values:

P1 = 740.5 torr

V1 = 10.8 L

T1 = 23.0 °C + 273.15 = 296.15 K

V2 = 7.20 L

T2 = 71.0 °C + 273.15 = 344.15 K

(P1 × V1) / T1 = (P2 × V2) / T2

(740.5 torr × 10.8 L) / 296.15 K = (P2 × 7.20 L) / 344.15 K

Solving for P2:

P2 = (740.5 torr × 10.8 L × 344.15 K) / (296.15 K × 7.20 L)

P2 = 1949.5 torr

Therefore, the pressure in the container is 1949.5 torr when the volume is 7.20 liters and the temperature is 71.0 °C.

The empirical mass of the compound, given that the molecular formula of the compound is N₂O₂, is 60 g/mol

First, we must understand here that empirical mass of a compound is simply the molar mass of the compound.

This means that if we obtain the molar mass of a compound, then we have equally obtain the empirical mass of the compound.

Now, we shall obtain the molar mass of the compound. Details below:

Molar mass of N₂O₂ = (14 × 2) + (16 × 2)

Molar mass of N₂O₂ = 28 + 32

Molar mass of N₂O₂ = 60 g/mol

From the above, the molar mass of the compound is 60 g/mol

Thus, we can conclude that the empirical mass of the compound is 60 g/mol

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Answer: The correct answer for the question would need to be 160 k

Explanation: I used the answer that was posted and it was inincorrect so I solved it myself to get the correct one

The mole fraction of the water solution is 0.77.

The mole fraction or molar fraction is defined as a unit of the quantity of a constituent, nᵢ, divided by the total quantity of all parts in a combination.

Moles of water = given mass/ molar mass

Moles of water = 84/18

Moles of water = 4.6

Moles of hexane =  given mass/ molar mass

Moles of hexane = 100/76

Moles of hexane = 1.3

Total moles = Moles of water + Moles of hexane

Total moles = 4.6 + 1.3 = 5.9

Mole fraction of water = Moles of water / Total moles

Mole fraction of water = 4.6/5.9

Mole fraction of water = 0.77

Hence, the Mole fraction of water is 0.77.

The mole fraction is the same as the mole percent however in a specific shape in chemistry. Inside the given combination, the range of moles of one constituent is divided by the total number of moles is referred to as the mole fraction. Multiplying the mole fraction of the thing by then we gain the mole percentage of the aspect.

Mole fraction is a unit of awareness, described to be equal to the range of moles of an aspect divided through the whole wide variety of moles of a solution. Because it's miles a ratio, the mole fraction is a unitless expression.

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In the case of a real gas when you're using Van Der Waals equation, the volume of a real gas is considered as (Vm - b), where b can be considered as the volume occupied by per mole.

Therefore, when the ideal gas law gets substituted with V = Vm  - b, it is given as : P(Vm  - b) = nRT

The presence of intermolecular attraction P was modified as follows.

\(\frac{P+a}{V^{2} } (Vm- b) = RT\\\frac{P+an^{2} }{V^{2} } (V - nb) = nRT\)

Where, Vm: molar volume of the gas

R: universal gas constant

T: temperature

P: pressure

V: volume

Thus, it is possible to reduce Van Der Waals equation to the ideal gas law as PVm = RT.

What is the significance of the Ideal gas Law?

The ideal gas law only functions as an approximation approach when high accuracy is not necessary because it describes the behaviour of ideal gasses, which there aren't any of. It is a solid introduction to the fundamental behaviour of gases and works well as a teaching tool, which is why it is taught to the majority of university students as part of any introduction to physics. In essence, the ideal gas law enables students to comprehend ideas such as the process of thermodynamic cycles, such as an engine, the reason an airbag expands, what transpires to a balloon at high altitude, and other related ideas.

Hence, Van Der Waals equation to the ideal gas law as PVm = RT.

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Answer:

So sorry if I was wrong but I think it's B. Because from the source states,

https://socratic.org/questions/which-group-on-the-periodic-table-is-the-least-reactive-why

"The least reactive elements are those who have a full outermost valence shell ie they have 8 electrons in the outer shell so elements such as helium, neon, radon or the transition elements."

hope it helped .r.a.t.e

Answer:

1,000.000

Explanation:

It is best to fill the pipet to a point just above the calibration line, then adjust the volume by slowly releasing liquid, which will help to be more successful when working with a pipet.

To use a pipet successfully, it is important to ensure that the tip of the pipet is kept submerged when filling, as this will help to prevent air from getting into the pipet. Once the pipet is filled, it is best to fill it to a point just above the calibration line, then adjust the volume by slowly releasing liquid. This will help to reduce the chances of overfilling or spilling the liquid.

It is also important to be gentle when placing the pipet bulb on the pipet, as aggressive movements can cause the bulb to come loose or even break, resulting in injury. Additionally, the blue bulbs used in the lab are not meant to be attached to the pipet, but rather simply rest on top of it.

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Answer:

The correct answer is option D, that is, magic numbers.

Explanation:

The magic number in nuclear physics refers to the number of nucleons, that is, either neutrons or protons, distinctly, such that their alignment results in the formation of complete shells within the nucleus of the atom. As a consequence, atomic nuclei comprising a magic number of neutrons or protons are much more stable in comparison to other nuclei.  

The seven most broadly known magic numbers are 2,8,20,28,50,85 and 126.