a frictionless tracm contains a circular section of radius r as shown

Answer:

Let the initial charges be q1 and q2 respectively.

After they come in contact, the charges are rearranged such that they acquire same charge.

let us say that charge on each of them is Q.

They are again brought apart at a distance of 0.9 m. Hence, the force between them will be given as

F = kQ2 / r2

0.025 = (9×109 x Q2) / 0.92

Q2 = 0.025 x 0.92 / 9×109

Q = 1.5 x 10-6 C

Explanation:

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The circuit shown has the drawback that it can only operate with alternating current.

The correct answer is D

A type of electrical current known as alternating current (AC) alternates the flow of electrons periodically or in cycles between two directions. Alternating current (AC) is the kind of current that circulates through electrical outlets used in everyday homes and power lines.

Both alternating current (AC) and direct current (DC) are types of electric current (DC). The way that electrons move determines how AC and DC are different from one another. While the flow of electrons in AC is constantly changing, moving first ahead and then backward, as opposed to DC's steady movement in one direction

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Answer:

After a nucleus with 85 protons undergoes alpha decay, it has  83 protons.

Explanation:

In an alpha particle there are two protons

In the given substance's nucleus, there are total of 85 protons

After the decay, the proton number reduce

The current proton number after decay is

85 -2 = 83

After a nucleus with 85 protons undergoes alpha decay, it has  83 protons.

The number of protons in this nucleus after it undergoes an alpha decay is 83 protons.

Given the following data:

To determine the number of protons in this nucleus after it undergoes an alpha decay:

The chemical symbol for an alpha particle is:

\(^{4}_{2} \alpha\)

Therefore, we can deduce the following points about an alpha particle:

After an alpha decay:

Protons = \(85-2\)

Protons = 83

Therefore, the number of protons in this nucleus after it undergoes an alpha decay is 83 protons.

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We only have two observations, n = 2, and the formula can be simplified as: E[(θ1 - θ1)^2] = (1/2) * [(t_1 - θ1)^2 + (t_2 - θ1)^2]

Based on the given information, we can calculate the mean squared error (MSE) for the special case of two observations (n=2). The formula for MSE can be expressed as:

E[(θ1 - θ1)^2] = (1/n) * Σ(θ1 - θ1)^2

Since we only have two observations, n = 2, and the formula can be simplified as:

E[(θ1 - θ1)^2] = (1/2) * [(t_1 - θ1)^2 + (t_2 - θ1)^2]

This is the formula for the mean squared error as a function of t1 and t2.

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Answer:

earlier when there is no pandemic ( corona virus ) then rarely people give time to fitness/ excercise routine. But now, because of pandemic many people give more enthusiasm in fitness . In India we are motivated to do yoga. In this case, our culture has been back u can say. Lot of people startted doing yoga . Because of fitness in this pandemic no one will feel isolated with this u will be healthy .

Explanation:

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The number of oxygen atoms in a 120.0g sample of iron(III) oxide (Fe2O3) is approximately 2.241 × 10^23 oxygen atoms.

To calculate the number of oxygen atoms in a sample of iron(III) oxide (Fe2O3), we need to use the concept of moles and Avogadro's number.

First, we need to determine the number of moles of iron(III) oxide. To do this, we divide the given mass of iron(III) oxide by its molar mass. The molar mass of Fe2O3 can be calculated by summing the atomic masses of its constituent elements: 2 atoms of iron (Fe) and 3 atoms of oxygen (O).

The atomic mass of iron (Fe) is 55.845 g/mol, and the atomic mass of oxygen (O) is 16.00 g/mol. Therefore, the molar mass of Fe2O3 is:

(2 × 55.845 g/mol) + (3 × 16.00 g/mol) = 159.69 g/mol

Next, we calculate the number of moles of Fe2O3 by dividing the given mass (120.0g) by its molar mass (159.69 g/mol):

Number of moles = 120.0g / 159.69 g/mol ≈ 0.7511 mol

Since there are three oxygen atoms in one molecule of Fe2O3, the number of moles of oxygen atoms is three times the number of moles of Fe2O3:

Number of moles of oxygen atoms = 3 × 0.7511 mol ≈ 2.2533 mol

Finally, we use Avogadro's number, which states that there are 6.022 × 10^23 entities (atoms, molecules, etc.) in one mole, to convert the number of moles of oxygen atoms to the number of oxygen atoms:

Number of oxygen atoms = (2.2533 mol) × (6.022 × 10^23 atoms/mol) ≈ 1.358 × 10^24 atoms

Rounded to four significant digits, the number of oxygen atoms in the given sample is approximately 2.241 × 10^23 oxygen atoms.

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Answer:

0.303 seconds

Explanation:

We need to find the time that the cell phone takes to reach the sink. So, we will use the following equation

Where

yi is the initial position, so yi = 0.45 m

vi is the initial velocity. Since it is freefall, vi = 0 m/s

a is the acceleration due to gravity, so a = -9.8 m/s²

y is the final position, so y = 0 m

t is the variable that we need to find.

So, replacing the values, we get:

Now, we can solve for t

Therefore, you have 0.303 seconds before your cell phone is ruined.

Answer:

The formula is the form -

m λ = d sin Θ

As the wavelength λ is decreased sin Θ will also decrease.

One can see from the derivation that as the wavelength, being considered,

is decreased the dispersion will also decrease.

The coefficient of kinetic friction between the block and the tabletop is 0.41.

The given parameters;

mass of the block, m = 0.5 kg

extension of the spring, x = 0.2 m

spring constant, K = 100 N/m

The coefficient of kinetic friction between the block and the tabletop by applying the principle of conservation of energy as shown below.

Fd = Uₓ

μmgd = ¹/₂kx²

where;

μ is the coefficient of kinetic friction

The coefficient of kinetic friction between the block and the tabletop;

Thus, the coefficient of kinetic friction between the block and the tabletop is 0.41.

Answer:

It would lift the object to the same height than before you move it 3 centimeters to the left. You see, the height doesn't change if you move the inclined plane horizontally, because height is a vertical variable.

Therefore, if the inclined plane has a height of 1 meters, then the object will be lifted 1 meters up, no matter if you move the inclined plane 50 meters horizontally, it won't change its height.

a) The rate of heat transfer (W) by conduction through the wall is 14.40 W.

b) The total heat (J) transferred through the wall in 45 minutes is 32,400 J.


Given, Length (l) = 3.0 m, Breadth (b) = 2.0 m, Thickness of brick (d) = 8.0 cm = 0.08 m, Thermal conductivity of brick (k) = 0.15 W/m-K, Temperature inside the room (T1) = 15 degC, Temperature outside the room (T2) = -9.5 degC, Time (t) = 45 minutes = 2700 seconds

(a) Rate of heat transfer (Q/t) by conduction through the wall is given by:

Q/t = kA (T1-T2)/d, where A = lb = 3.0 × 2.0 = 6.0 m2

Substituting the values, we get:

Q/t = 0.15 × 6.0 × (15 - (-9.5))/0.08 = 14.40 W

Therefore, the rate of heat transfer (W) by conduction through the wall is 14.40 W.

(b) The total heat (Q) transferred through the wall in 45 minutes is given by: Q = (Q/t) × t

Substituting the values, we get: Q = 14.40 × 2700 = 32,400 J

Therefore, the total heat (J) transferred through the wall in 45 minutes is 32,400 J.

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Answer:

The golf ball has a greater mass than the foam ball

Explanation:

Zero work is done when the force and the displacement are perpendicular to each other. In other words, if the angle between the force vector and the displacement vector is 90 degrees, then the work done is zero.

Work in physics is defined as the product of the force applied on an object and the displacement of the object in the direction of the force. Mathematically, work (W) is given by the equation.

W = F * d * cos(theta)

where F is the magnitude of the force applied, d is the magnitude of the displacement, and theta is the angle between the force vector and the displacement vector.

When the angle theta between the force and the displacement is 90 degrees (perpendicular), the cosine of 90 degrees is zero. Therefore, the term cos(theta) becomes zero, and as a result, the work done is zero.

In this scenario, even though forces are being exerted or a body is moving, the forces are not contributing to the displacement of the object in the direction of the force. The force and the displacement are acting in different directions, and their vector components perpendicular to each other cancel each other out.

For example, when you push a book horizontally along a tabletop with a constant force, the displacement of the book is in the horizontal direction, while the force you exert is perpendicular to the displacement (vertical). As a result, no work is done on the book by your pushing force.

Therefore, zero work is done when the force and the displacement are perpendicular to each other.

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The phrase "like dissolves like" can be described as the compounds which have similar nature dissolve in each other that is polar dissolves polar and non-polar dissolves non-polar molecules.

Polarity is the separation of electric charge which is leading to a molecule or the chemical groups which are having an electric dipole moment, with a negatively charged end and a positively charged end as well. Polar molecules are the molecules which must contain one or more polar bonds which occur due to a difference in the electronegativities between the bonded atoms of the molecule.

A simple way to predict the compounds which will dissolve in other compounds is the phrase of the compound such as "like dissolves like". This means that the polar compounds dissolve in polar compounds, and the nonpolar compounds dissolve in nonpolar compounds, however, the polar and nonpolar molecules do not dissolve in each other.

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The Patagonia region of Chile and Argentina features a large, elongated glacier approximately 90 km (56 mi) wide and 360 km (224 mi) long. this is an example of a(n): Ice field

The Patagonia region of Chile and Argentina is characterized by the largest ice fields in South America.

An ice field is a large mass of ice that covers part of the land.

The Patagonia is an area located in South America which is shared by Chile and Argentina.

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acceleration of the car a=9.7 m/\(s^{2}\) and force must the track exert on the tires 5900 N

v= d/t

v= 2\(\pi\)r/T

v=2\(\pi\)(50)/14.3

v=22 m/s

a=\(v^{2} /r\)

a=\(22^{2}\)/50

a=9.7 m/\(s^{2}\)

F= ma =615*9.7 =5900 N

Force and acceleration are directly correlated, as demonstrated by Newton's second law. An item will accelerate more quickly the more force is supplied to it, regardless of its mass. The object's acceleration, for instance, doubles when the force acting on it is doubled.

According to Newton's second law, when a large body is subjected to a constant force, it will accelerate—that is, alter its velocity—constantly.

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By using the Forward Euler method and incorporating a quadratic air resistance model, we can numerically solve the problem of free falling until terminal velocity is reached.

To solve the problem of free falling with quadratic air resistance using the Forward Euler method, we start with the given variables: initial velocity (v(0)) is 0 m/s, acceleration due to gravity (g) is 9.81 m/s^2, mass (m) is 68.1 kg, drag coefficient (c) is 0.25 kg/m, and k = C/m, where C is the coefficient of quadratic air resistance.

In the Forward Euler method, we approximate the change in velocity over a small time step (At) using the equation:

Δv = At * (g - (k/m) * v^2)

Here, v represents the velocity at each iteration. We repeat the calculations until the velocity reaches the terminal velocity, which is the point where the velocity remains constant between iterations.

To determine the appropriate time step (At), we need to ensure that the terminal velocity is reached. If the time step is too large, the numerical approximation may not accurately capture the behavior of the system. By experimenting with different time steps, we can find a value that allows us to converge to the terminal velocity.

During each iteration, we update the velocity using the Forward Euler method and check if the velocity remains constant. If the velocity is not constant, we continue iterating. Once the velocity no longer changes, we have reached the terminal velocity.

To summarize, by implementing the Forward Euler method and accounting for quadratic air resistance, we can iteratively solve the problem of free falling until the terminal velocity is achieved. The appropriate time step is crucial to accurately capture the behavior of the system.

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Answer:

The answer is below

Explanation:

Acceleration is the rate of change of velocity with respect to time. The S.I unit of acceleration is m/s².

We say that there is acceleration if there is a change of distance or change in velocity (increase or decrease) or both.

The statement above is an example of acceleration because there is a change in velocity. The velocity when the motor was at rest was 0, but an increase in acceleration caused the train to move a distance of 10 meters.

The shrinking of integrated circuit device dimensions over six decades led to faster computing, advanced circuit functions, improved power efficiency, and widespread advanced electronic devices.

Increased Computing Speed: As device dimensions have shrunk, the distance between transistors on a chip has decreased, enabling faster electrical signal propagation. This has led to increased clock speeds and faster processing capabilities, allowing for more complex computations and faster data processing.

Enhanced Circuit Functionality: With smaller device dimensions, more transistors can be integrated into a single chip. This has enabled the development of highly sophisticated and complex circuits, such as microprocessors, capable of performing intricate tasks.

The increased number of transistors has also facilitated the integration of various functionalities, such as memory, graphics processing, and communication capabilities, onto a single chip, leading to more versatile and powerful computing devices.

Improved Power Efficiency: Smaller device dimensions have reduced the distance that electrical signals need to travel within a chip. This has minimized the power losses associated with signal propagation, resulting in improved power efficiency. Additionally, the miniaturization of components has allowed for the development of low-power transistors, enabling energy-efficient operation and longer battery life in portable electronic devices.

Proliferation of Advanced Electronic Devices: The million-fold reduction in device dimensions has made it possible to produce smaller, lighter, and more compact electronic devices. This has led to the widespread adoption of smartphones, tablets, wearables, and other portable devices that offer advanced computing, communication, and multimedia capabilities. The miniaturization of integrated circuits has also enabled the development of Internet of Things (IoT) devices, smart sensors, and embedded systems, which have revolutionized various industries and aspects of everyday life.

Increased Integration and System Complexity: Shrinking device dimensions have allowed for greater integration of components and systems on a single chip. This has led to the development of system-on-chip (SoC) solutions, where multiple functions, such as processing, memory, and communication, are combined on a single integrated circuit. The increased integration and system complexity have contributed to the advancement of technologies like artificial intelligence, machine learning, and autonomous systems.

Cost Reduction: The continual shrinking of device dimensions has resulted in increased transistor density on a chip. This has led to higher production yields per wafer, driving down the manufacturing cost per transistor. The cost reduction has made advanced computing and communication technologies more affordable and accessible to a wider range of users, fostering their widespread adoption.

Overall, the million times shrinking of device dimensions in integrated circuits over the past six decades has had a profound impact on computing and communications, revolutionizing the speed, functionality, power efficiency, and size of electronic devices while enabling the development of new technologies and driving economic growth in the digital era.

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Answer:

B)18750

Explanation:

it because

\(1250 \times 15 = 18750\)

Answer: The impulse of the car is B.) 18750 kg m/s

hope this helps.

Explanation:

To find the inductance of the inductor, we can use the formula:Vpeak = L × ω × Ipeak the peak current at 86 MHz with a constant voltage of 3.7 V is 66.6 µA.

Voltage, also known as electric potential difference, is the measure of the difference in electric potential energy between two points in an electric circuit. It is the driving force that pushes electric charge through a circuit. Voltage is measured in volts (V) and is typically represented by the symbol "V".

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The impedance of this circuit is 778.46 Ω.

Given parameters:

The series RLC circuit consists of a 231 Ω resistor, a 14. 3 mh inductor, a 9. 71 μf capacitor.

AC voltage applied on it = 39 Volt.

So, resonance frequency: f₀ = 1/√LC = 1/√(14.3 × 10⁻³ × 9.71 × 10⁻⁶) Hz = 8486 Hz.

Hence, applied frequency: f = 6f₀ = 6×8486 Hz = 50918 Hz.

So, impedance of the circuit at this frequency: Z= √( R² + (f²L²-1/f²C²)

After putting the values of R,L,C and f we get,

Z = 778.46 Ω.

Hence, the impedance of this circuit is 778.46 Ω.

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Answer:

The answer is "Option D"

Explanation:

Please find the graph file in the attached file.

Using formula:

\(\to v= \rho \lambda \\\\\ \to \lambda= 130 \cm \\\\ \to v= 335 \frac{cm}{s}\\\\ \to \rho= \frac{v}{\lambda} \\\\\)

      \(=\frac{335}{130} \\\\ = 2.57 \approx 2.50 \ Hz\)

Answer:

Pressure of .2 m^3 of bricks:

Pb = ρ g H = 1.8 ρw * 9.80 m/s^2 * .20 m = 1800  * 9.8 * .2 = 3530 Pascals

ρb = 1.8 ρw = 1.8    since the density of bricks is 1.8 that of water

Pw = 1 * 9.8 * 1000 * .2 = 1960 Pascals

W = P * A   pressure * Area = Force

Pnet = 1570 Pascals - pressure due to bricks under water

F = 1570 N/m^2 * .2m^2 = 63 N     force on pile of bricks

The speed of the rolling ball having a kinetic energy of 98J and a mass of 4kg is 7m/s.

Kinetic energy is simply the energy a body possesses due to its motion;

It is expressed as;

K.E = 1/2 × m × v²

Where m is mass and v is the velocity of the body.

Given the data in the question;

Plug the given values into the Kinetic energy formular and solve for v.

K.E = 1/2 × m × v²

98kgm²/s²  = 1/2 × 4kg × v²

98kgm²/s²  = 2kg × v²

v² = 98kgm²/s² / 2kg

v² = 49kgm²/s²

v = √( 49kgm²/s² )

v = 7m/s

Therefore, the speed of the ball is 7 meters per second.

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The maximum height attained by the bob is (7 + 3 * sqrt(2)) times the height it would attain if the bullet passed through it without being embedded in it.

Let h be the maximum height attained by the bob.

By conservation of momentum, the initial momentum of the bullet is equal to the momentum of the bullet-bob system after the collision:

m_bullet * v = (m_bullet + m_bob) * v'

where v' is the velocity of the bullet-bob system immediately after the collision.

By conservation of energy, the kinetic energy of the bullet before the collision is equal to the sum of the kinetic energy of the bullet-bob system immediately after the collision and the potential energy of the bob at its maximum height:

(1/2) * m_bullet * v^2 = (1/2) * (m_bullet + m_bob) * (v'/3)^2 + (m_bullet + m_bob) * g * h

Solving these two equations for v' and h, we get:

v' = v/4

h = (m_bullet * v^2)/(2 * (m_bullet + m_bob)^2 * g) * (7 + 3 * sqrt(2))

So the maximum height attained by the bob is (7 + 3 * sqrt(2)) times the height it would attain if the bullet passed through it without being embedded in it.

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Answer:

Kinetic Energy

Explanation:

Ang prinsipyo ay nagsasaad na ang enerhiya ay hindi maaaring malikha o masira, ngunit maaari lamang ma-convert mula sa isang anyo patungo sa isa pa. Ang tubig sa tuktok ng napakataas na talon ay nagtataglay ng gravitational potential energy. Habang bumabagsak ang tubig, ang enerhiya na ito ay na-convert sa kinetic energy, na nagreresulta sa isang daloy sa isang mataas na bilis.

Answer:

A. When half the parent nuclei in a sample have become daughter nuclei

Explanation:

The point at which the half-life is reached is when half of the parent nuclei in a sample have become daughter nuclei.

Every radioactive atom starts with the parent. When they disintegrate they given the daughter nuclides.

The half - life is the time taken for half of the radioactive nuclei to disintegrate.

The shorter the half - life, the faster the decay process.

Answer:

A. When half the parent nuclei in a sample have become daughter nuclei

Explanation:

Ap3x

Answer:

yea its D  .

Explanation: