A fox locates its prey, usually a mouse, under the snow by the slight sounds that it makes. the fox then leaps straight into the air and burrows its nose into the snow when it lands, to catch its next meal. which of the three pairs of velocity versus time

Correct option is B, satellite that has the greatest speed has Mass Radius m ½R.

Because the satellite orbits the earth, the gravitational pull of the planet on the satellite supplies the necessary centrifugal force. In a circular orbit, the gravitational force is constant, hence the satellite's velocity is also constant.

Kepler's third law informs us that

V² = GM/R

Therefore, v = (GM/R)

Where;

V is the speed

G stands for gravity constant.

Mass is M.

R is radius

Let's begin by examining the first choice, which is Option B.

Here, mass equals m and radius equals (1/2)R.

Consequently, v = (Gm/(R/2)) = (2Gm/R)

After carefully examining each choice, it is evident that option B will have the highest velocity because its numerator is the largest, which will result in a higher velocity.

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Answer:

t = 0 1.697 seconds

Explanation:

Comment

This is a standard question where the time is the same for both the vertical distance the ball has to drop and the time it takes to go horizontally.

Formulas

dv = vi*t + 1/2 a t^2

dv is the vertical distance that the ball has to travel in a downward direction

dh = vh * t

Givens

a = 9.81

dv = 1.44

vi = 0

t = ?

dh = 2 m

t = same as above (but not given)

Solution

dv = 1/2 a * t^2

1.44 = 1/2 * 9.81 *t^2                 Multiply by 2

2*1.44 = 1/2 * 2 * t^2

2.88 = t^2

t = 1.697 seconds

Note that you do not have to use the horizontal information to get the time. You only have to realize that the ball has no vertical velocity to begin with.

Answer:

Home run

Explanation:

i play

To check the temperature leads of an electronic thermometer for low temperature, they should be stirred in a container of crushed ice and pure water.

Electronic thermometers use thermoresistive devices, in which the electrical resistance alters in reaction to temperature changes, to detect temperature changes (Fig. 22-3). The tip of a probe contains this device, which could be a thermocouple or a thermistor.

The fastest and most accurate way to take a temperature is with a digital thermometer. Most medicine stores and supermarket pharmacies stock digital thermometers.

Heat sensors are used by digital thermometers to measure body temperature. You can use them to measure the temperature in your mouth, rectus, or armpit. Remember that armpit (axillary) temperature is often 12 to 1°F (0.6°C) colder than mouth readings when evaluating digital thermometer results.

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The rider is moving at a speed of approximately 3.74 m/s when experiencing 10 g's in the centrifuge.

Length of centrifuge arm (r) = 14.0 m

Centrifugal force (F) experienced by the rider = 10 g's

First, let's calculate the mass of the rider using the formula:

w = mg

w = weight of the rider

g is the acceleration experienced by objects due to the force of gravity, and its approximate value on Earth is 9.81 meters per second squared (m/s²).

m = mass of the rider

w = F * g

= 10 * 9.81

= 98.1 N

m = w / g

= 98.1 / 9.81

= 10 kg

Now, we can use the formula for speed:

v = √(Fr/m)

v = √((F * r) / m)

= √((10 * 14.0) / 10)

= √(140 / 10)

= √14

≈ 3.74 m/s

Therefore, the rider is moving at a speed of approximately 3.74 m/s when experiencing 10 g's in the centrifuge.

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Star b will have better fusion rate as compared to star a.

What is nuclear fusion reaction?

It is the reaction which powers the sun and other stars. In this reaction, two small nuclei fuse together to form one single heavier nucleus. During this process, large amount of heat is being liberated out.

The rate of fusion reaction increases rapidly with temperature until it reaches a point where it maximizes and then falls. Hence, it depends upon the numeric value of temperature taken. The star with temperature 3t will have a good fusion rate as compared to the star a with t temperature. There are many other things as well, which has to be kept in mind and it comes later on in the reaction.

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Approximately 3.23 × 10^(12) photons emitted each second, we can use the formula: Number of photons = Power / Energy of each photon

First, we need to convert the power from microwatts to watts:

Power = 1 microwatt = 1 × 10^(-6) watts

Next, we need to calculate the energy of each photon using the equation:

Energy of each photon = Planck's constant × speed of light / wavelength

Given:

Wavelength (λ) = 640 nm = 640 × 10^(-9) meters

Planck's constant (h) = 6.626 × 10^(-34) J·s

Speed of light (c) = 3.00 × 10^(8) m/s

Plugging in the values, we can calculate the energy of each photon:

Energy of each photon = (6.626 × 10^(-34) J·s × 3.00 × 10^(8) m/s) / (640 × 10^(-9) m)

= 3.10 × 10^(-19) J

Now we can calculate the number of photons emitted each second:

Number of photons = Power / Energy of each photon

= (1 × 10^(-6) watts) / (3.10 × 10^(-19) J)

≈ 3.23 × 10^(12) photons

Therefore, approximately 3.23 × 10^(12) photons are emitted each second.

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When standing on Earth or on the Moon, the following values remain the same: One's mass, The acceleration due to gravity, The value of G etc. Correct answers are option B, D and E

One's mass: Mass is a measure of the amount of matter an object contains and is independent of the gravitational field. Thus, an individual's mass remains the same whether they are on Earth or the Moon. Mass is typically measured in kilograms (kg).

The acceleration due to gravity: The acceleration due to gravity is the rate at which an object falls towards the centre of a celestial body under the influence of gravity. On Earth, the acceleration due to gravity is approximately 9.8 metres per second squared (m/s²), and on the Moon, it is about 1.6 m/s².

The value of G: The value of G represents the gravitational constant, which is a fundamental constant of nature. It determines the strength of the gravitational force between two objects. The value of G is approximately 6.67430 cubic metres per kilogram per second squared (m³/kg/s²).

It is a constant value that does not change based on the location within the universe. Therefore, the value of G remains the same whether one is on Earth or the Moon. Correct answers are option B, D and E

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The values that are the same standing on Earth or on the Moon are:  one's mass, the acceleration due to gravity, the value of G (the gravitational constant). The correct option is A, D and E.

What is gravity?

Gravity is a fundamental force of nature that governs the interactions and attraction between objects with mass. It is responsible for the phenomenon of gravity, which is the force that pulls objects toward each other.

Gravity is described by Albert Einstein's theory of general relativity, which states that mass and energy warp the fabric of spacetime, creating a gravitational field. In this theory, objects with mass curve the surrounding spacetime, and other objects moving through that curved spacetime experience the force of gravity.

A person's mass (A) remains the same regardless of their location because mass is an intrinsic property of an object and is independent of the gravitational field.

The acceleration due to gravity (D) is the same on Earth and the Moon, although its value may differ slightly. On Earth, the acceleration due to gravity is approximately 9.8 m/s², while on the Moon, it is approximately 1.6 m/s². However, both values represent the acceleration experienced by objects near the surface of the respective celestial bodies.

The value of G (E), the gravitational constant, is a fundamental constant of nature and is the same throughout the universe. It is approximately equal to 6.674 × 10^(-11) N(m/kg)² and governs the strength of the gravitational force between two objects.

One's weight (B) and weight-to-mass ratio (C) vary depending on the gravitational field. Weight is the force exerted on an object due to gravity and is given by the formula weight = mass × acceleration due to gravity.

Therefore, weight changes when the acceleration due to gravity changes, as is the case when comparing Earth and the Moon. The weight-to-mass ratio also varies accordingly. The correct option is A, D and E.

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Answer:

She would travel 175.5 m in the same amount of time

Explanation:

Here is the complete question:

Seven bicyclist are racing. Each bicyclist rides for 9s. If a bicyclist, with initial velocity of zero, steadily gained speed until reaching a final velocity of 39m/s, how far would she travel during the race in the same amount of time)?

Explanation:

To determine how far she would travel in the same amount of time, that is the distance she would cover in the same amount of time

From the question,

The bicyclist has an initial velocity of zero

That is, u = 0 m/s

and a final velocity of 39 m/s

That is, v = 39 m/s

Each bicyclist rides for 9s,

She also traveled for the same amount of time

that is, t = 9s

To determine the distance,

From one of the equations of motion for linear motion

s = \(\frac{1}{2}\) t(u + v)

Then

s = \(\frac{1}{2}\) (9)(0+39)

s = 4.5 (39)

s = 175.5 m

Hence, she would travel 175.5 m in the same amount of time

The voltage drop across the 18 kΩ resistor is 90 volts. This means that when a current of 5 mA flows through an 18 kΩ resistor, there is a potential difference of 90 volts across the resistor.

To calculate the voltage drop across a resistor, Ohm's Law can be applied. Ohm's Law states that the voltage (V) across a resistor is equal to the product of the current (I) flowing through it and the resistance (R) of the resistor. The formula for Ohm's Law is V = I * R.

Given:

Current (I) = 5 mA = 5 * 10^(-3) A

Resistance (R) = 18 kΩ = 18 * 10^(3) Ω

Using Ohm's Law, we can calculate the voltage drop (V):

V = I * R

= (5 * 10^(-3) A) * (18 * 10^(3) Ω)

= 90 V

Therefore, the voltage drop across the 18 kΩ resistor is 90 volts. This means that when a current of 5 mA flows through an 18 kΩ resistor, there is a potential difference of 90 volts across the resistor.

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Answer:

by raising them in an environment in wich it is common and giving false information about other races to install bad stereo types and distrust in the child who will grow up to not know any better do to the dumb ignorant parent raised the same way

Explanation:

?????? thats all i got im not a politician BLM

The telescope created the data gathered by Kepler and his team.

What is a star?

A star is a large luminous astronomical body which produces light and heat energy as well as radiation.

There are billions of stars in the universe organized into galaxies.

The Sun is the star of our solar system.

The Kepler project produced a wide range of data products and documentation to assist the community in using data from the mission to help study both exoplanets and other astrophysical areas.

In the video, a mysterious star was observed which is 50 percent bigger and 1,000 degrees hotter than the Sun.

By mean of telescopes, it was observed that the dimming seen in the diet was dues to dust particles.

These data produced ranges from engineering data on the detectors to lists of planet candidates and includes many of the intermediate data products in the data processing path.

The Kepler first mission came to an end after four years when two of the four reaction wheels, used to point the spacecraft malfunctioned.

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Answer:

You have the answer in your comments. I will be copying it so your question doesn't get deleted.

The answers is $0.58

$11.48

the video tape

the new shirt

The distance between the image and the mirror can be expressed as di = -2f. The negative sign indicates that the image is formed on the same side as the object, which confirms that it is a real image.

When an object is placed at a distance in front of a mirror that is twice the focal length (do = 2f), the image formed is a real and inverted image. According to the mirror formula, 1/do + 1/di = 1/f, where do is the object distance, di is the image distance, and f is the focal length of the mirror. By substituting the given values, we get 1/2f + 1/di = 1/f. Solving this equation, we find di = -2f. The negative sign indicates that the image is formed on the same side as the object, which confirms that it is a real image.

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No, the temperature of the water bath, when vaporization begins, is not used to find the temperature for the ideal gas law.

The temperature used in the ideal gas law equation is the actual temperature of the gas. This can be determined using a thermometer placed directly in the gas or by measuring the temperature of the container holding the gas. The temperature of the water bath, when vaporization begins, is typically used to determine the boiling point of a substance, which can be used to calculate the heat of vaporization. However, this temperature is not used in the ideal gas law equation.

The ideal gas law relates the pressure, volume, and temperature of a gas, assuming it behaves like an ideal gas, which means its particles have no volume and there are no intermolecular forces. The ideal gas law is an important equation in thermodynamics and is used to calculate the behavior of gases under different conditions.

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In the field of physics, total internal reflection refers to the entire reflection of a beam of light that is traveling through a medium such as water or glass back into the medium itself from the surfaces that surround the medium.

When the angle of incidence is larger than a specific limiting angle, which is referred to as the critical angle, the phenomena will take place. When a ray of light traveling through a medium with a higher index of refraction approaches another medium with an angle of incidence that is greater than the critical angle, a phenomenon known as total internal reflection occurs. In general, this phenomenon takes place at the boundary between two transparent media.

True statements are;

1. A smaller critical angle means the total internal reflection is more likely to occur.

2. Fiber optic cables are practical applications of total internal reflections.

False statements are;

1. When light hits a boundary at a less than the critical angle, it will undergo total internal reflection.

2. Single reflection of light of a silvered mirror is more efficient than total internal reflection so mirrors are often used instead of prisms in optical instruments to minimize light loss.

The complete question is attached as an image.

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In general, the statement that validation is not needed for single-use systems in a bioreactor is not accurate. Validation is an essential process in bioprocessing that ensures the reliability, consistency, and safety of the manufacturing process. Single-use systems, which are increasingly used in bioreactors, can introduce unique challenges and considerations.

Validation of single-use systems involves assessing their performance, integrity, and compatibility with the process requirements. Factors such as material integrity, sterile connections, and proper functioning of sensors and control systems should be evaluated to ensure the system's suitability for use.

While single-use systems offer advantages in terms of cost, flexibility, and minimizing cross-contamination risks, they still require validation to demonstrate their reliability and performance. It is essential to follow industry standards, regulatory guidelines, and good manufacturing practices to ensure the quality and safety of bioprocessing operations, regardless of the system being used.

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Answer:

1 micron = 1.00E-6  m   is one way

1.00^-6 m    is another but is not usually considered scientific notation, but                      

                   often convenient to use.

Scientists use the micron as a unit of length for very small objects. A micron is one-millionth of a meter or 0.000001 m, then the number of meters in a micron in scientific notation would be 1×10⁻⁶ meters.

In positional notation, significant figures refer to the digits in a number that is trustworthy and required to denote the amount of something, also known as the significant digits, precision, or resolution.

If a number expressing the result of a measurement includes more digits than the number of digits allowed by the measurement resolution, only the digits allowed by the measurement resolution can be significant figures.

As given in the problem Scientists use the micron as a unit of length for very small objects. A micron is one-millionth of a meter or 0.000001 m.

1 micron = 0.000001 m

              =1×10⁻⁶ meters

Thus, the number of meters in a micron in scientific notation would be 1×10⁻⁶ meters.

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The sound would have a wavelength of about  9.8 * 10^-3 m.

The wavelength is a characteristic of a wave that describes the distance between two successive points in the wave that are in phase, or the distance over which the wave's shape repeats. It is typically denoted by the Greek letter lambda (λ) and is measured in meters (m) or other units of length.

Given that the speed of sound in air is 343 m/s

v= λf

λ = v/f

λ =  343 m/s/3.5x10^4 Hz

λ =  9.8 * 10^-3 m

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Answer:

\(5,480\:\text{N}\)

Explanation:

The formula for work is given by \(W=F\Delta x\), where \(F\) is the force applied over a distance of \(\Delta x\).

Plugging in given values, we get:

\(16,700=F\cdot 3.05,\\F=\frac{16,700}{3.05},\\F\approx \boxed{5,480\:\text{N}}\)(three significant figures).

Answer:

\(\theta=\tan^{-1}\dfrac{a}{g}\)

Explanation:

Here we are assuming that the car is moving in a straight line and is traveling on a smooth surface. When the car is moving with acceleration \(a\) the bob moves in the opposite direction with the same acceleration. Gravity is acting on the bob so it is experiencing an acceleration of \(g\) downwards.

The angle between the acceleration \(a\) and the acceleration due to gravity \(g\) is

\(\theta=\tan^{-1}\dfrac{a}{g}\).

Therefore, your speed(v) is 0 m/s when you reach the deer's position.

a) Where would you come to a stop if the deer were not in your way?

Using the equation, v^2 = u^2 + 2as, where v is the final velocity, u is the initial velocity(u), a is the acceleration(a), and s is the displacement(s). Substituting the known values, we have:v = 0m/su = 30m/sa = -10m/ss = ?v^2 = u^2 + 2as0 = 30^2 + 2(-10)s0 = 900 - 20s900 = 20s40.5 = s. Therefore, you will stop after 40.5 meters if the deer was not in your way. b) How fast are you going when you reach the deer’s position?

Using the equation, v = u + at, where v is the final velocity, u is the initial velocity, a is the acceleration, and t is the time. Substituting the known values, we have: v = ?u = 30m/sa = -10m/st = ?s = 40mv = u + atv = 0m/su = 30m/sa = -10m/st = ?s = 40m0 = 30 + (-10)t10t = 30t = 3 seconds. Therefore, the time it takes you to reach the deer's position is 3 seconds. The equation to find the final velocity is:v = u + atv = 30 + (-10)(3)v = 0m/s.

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Answer:

BASETBALL

Explanation:

Answer:

  C

Explanation:

Most discussions of refraction will have a diagram similar to that of C.

The angle of incidence is measured from the normal to the boundary, as is the angle of refraction. The product of the sine of the angle and the index of refraction is the same for the media on either side of the boundary.

  n₁·sin(θ₁) = n₂·sin(θ₂)

For media, such as optical fiber, that has an index of refraction greater than 1, the angle of refraction will be smaller in that media than the angle of incidence coming from air.

Figure C applies.

Answer:

40,000 m/s²

Explanation:

The formula is given as Force = mass × acceleration, so then acceleration = Force / mass.

Therefore...

5800 N ÷ 0.145 kg = 40,000 m/s²

Answer:

yes

Explanation:

A group of atoms having all like poles pointing in the same direction is called a magnetic domain.

A magnetic domain is defined as a group of atoms with their poles aligned in the same direction. To produce a net magnetic force, the magnetic domains in permanent magnets are aligned with each other.

When cooled below the Curie temperature, the magnetization of a piece of ferromagnetic material divides spontaneously into many small regions that are called magnetic domains. A magnetic domain form in a material that has magnetic ordering, which means its dipoles spontaneously align because of the exchange interaction. These include ferromagnetic, ferrimagnetic, and antiferromagnetic materials.

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