A force vector is positioned in the 6th octant.

The projection angle is 37 degrees. The planar angle referenced from the negative x-axis is 53 degrees.

The x,y, and z components will be

+,-,-

-,+,+

-,-,-

-,+,-

-The magnitude of the vector is 10 N. The z component is

6 N

- 6 N

8 N

- 8 N

Answer:

ANS DOWN BELOW! PLS MARKN AS BAINLIEST

Explanation:

hardness of a mineral is determined by observing whether its surface is scratched by a substance of known or defined hardness.

Answer:

Resistance of copper = 1.54 * 10^18 Ohms

Explanation:

Given the following data;

Length of copper, L = 3 kilometers to meters = 3 * 1000 = 3000 m

Resistivity, P = 1.7 * 10^8 Ωm

Diameter = 0.65 millimeters to meters = 0.65/1000 = 0.00065 m

\( Radius, r = \frac {diameter}{2} \)

\( Radius = \frac {0.00065}{2} \)

Radius = 0.000325 m

To find the resistance;

Mathematically, resistance is given by the formula;

\( Resistance = P \frac {L}{A} \)

Where;

First of all, we would find the cross-sectional area of copper.

Area of circle = πr²

Substituting into the equation, we have;

Area  = 3.142 * (0.000325)²

Area = 3.142 * 1.05625 × 10^-7

Area = 3.32 × 10^-7 m²

Now, to find the resistance of copper;

\( Resistance = 1.7 * 10^{8} \frac {3000}{3.32 * 10^{-7}} \)

\( Resistance = 1.7 * 10^{8} * 903614.46 \)

Resistance = 1.54 * 10^18 Ohms

The minimum pressure at which the water-supplying pump must operate is approximately 2.45 x 10⁶ Pa or 2450 bar.

To calculate the minimum pressure at which the water-supplying pump must operate, we need to use the formula for the volumetric flow rate of a fluid:

Q = A * v

where,

Q =the flow rate

A = the cross-sectional area of the hole

v = the velocity of the fluid.

We can use this formula to determine the velocity of the water, and then use the Bernoulli equation to determine the minimum pressure.

From the question:

ṁ=0.05 kg/s

ρ= 996 kg/m

d= 0.02 cm

Calculating the area of the hole:

A = (π/4) * (d²)

where,

d is the diameter of the hole, and pi is approximately 3.14.

d = 0.02 cm = 0.0002 m

A = (3.14/4) * (0.0002 m)² = 1.57 x 10⁻⁷ m²

Using the mass flow rate to calculate the velocity of water:

Q = ṁ / ρ

where,

Q = the volumetric flow rate

ṁ = the mass flow rate

ρ = the density of water.

Q = (0.05 kg/s) / (996 kg/m³)

Q = 5 x 10⁻⁵ m³/s

Using the area of the hole to find the velocity of water

v = Q / A

v = (5 x 10⁻⁵ m³/s) / (1.57 x 10⁻⁷m²)

v = 318.8 m/s

Using the Bernoulli equation to find the pressure:

P = Patm + (1/2) * ρ * v²

where,

P = the pressure

Patm = the atmospheric pressure

ρ =the density of water

v = the velocity of the water.

P = Patm + (1/2) * (996 kg/m³) * (318.8 m/s)²

Hence, the minimum pressure at which the water-supplying pump must operate is approximately 2.45 x 10⁶ Pa or 2450 bar.

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Answer:

Using 1's complement

a)

Therefore the difference is -10001

b)

Therefore the difference is 00001

c)

Therefore the difference is 01001

d)  

Therefore the difference is 10100

e)

Therefore the difference is 00111

Explanation:

Using 1's complement

a) The 1's complement of the subtrahend 11010 = 00101.

Therefore 01001-11010 = 01001 + 00101 = 01110

Since no overflow, we take the 1's complement of the result and it is negative.

Therefore the difference is -10001

b) The 1's complement of the subtrahend 11001 = 00110.

Therefore 11010-11001 = 11010 + 00110 =1 00000

Since there is an overflow, we add the overflow to the result

Therefore the difference is 00001

c) The 1's complement of the subtrahend 01101 = 10010

Therefore 10110-01101 = 10110 + 10010 =  1 01000

Since there is an overflow, we add the overflow to the result

Therefore the difference is 01001

d)  The 1's complement of the subtrahend 00111 = 11000

Therefore 11011-00111= 11011 + 11000 =  1 10011

Since there is an overflow, we add the overflow to the result

Therefore the difference is 10100

e) The 1's complement of the subtrahend 10101 = 01010

Therefore 11100-10101= 11100 + 01010 = 1 00110

Since there is an overflow, we add the overflow to the result

Therefore the difference is 00111

Using 2's complement

a) The 2's complement of the subtrahend 11010 = 00110.

Therefore 01001-11010 = 01001 + 00110 = 01111

Since no overflow, we take the 2's complement of the result and it is negative.

Therefore the difference is -10001

b) The 2's complement of the subtrahend 11001 = 00111.

Therefore 11010-11001 = 11010 + 00111 =1 00001

Since there is an overflow, we drop the overflow

Therefore the difference is 00001

c) The 1's complement of the subtrahend 01101 = 10011

Therefore 10110-01101 = 10110 + 10011 =  1 01001

Since there is an overflow, we drop the overflow

Therefore the difference is 01001

d)  The 1's complement of the subtrahend 00111 = 11001

Therefore 11011-00111= 11011 + 11001 =  1 10100

Since there is an overflow, we drop the overflow

Therefore the difference is 10100

e) The 1's complement of the subtrahend 10101 = 01011

Therefore 11100-10101= 11100 + 01011 = 1 00111

Since there is an overflow, we drop the overflow

Therefore the difference is 00111

Answer:

T = 3460 K

Explanation:

See attachment for calculation.

Since the temperature we have is above the melting point of the metal, then we can conclude that it is too high for the diffusion process to be possible.

It is important to wait until the model has fully set before removing it from the impression. This usually takes around 30 minutes to an hour, depending on the type of material used.

It is recommended to follow the manufacturer's instructions for specific setting times. Removing the model too early can cause distortion or damage to the impression, while waiting too long can make it difficult to remove the model without damaging it. It is important to also handle the model with care when removing it from the impression to avoid any accidental damage. By waiting for the recommended time, the model can be safely and easily removed from the impression, allowing for accurate and precise results.

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Answer:

The Dependent Variable is the Effect, Its value depends on changes from the Independent Variable

Hope this Helps

Answer:

mobile

Explanation:

.

Answer:

Mobile crane

Explanation:

The two types of cranes are overhead and mobile.

Answer:

thanks for the poiunts

Explanation:

Sorting by Cardinality The total number of 1s a number contains in its binary representation is known as its binary cardinality.

What is Python?

Python is an interpreted, object-oriented, high-level, dynamically semantic programming language. It is very attractive for Rapid Application Development as well as for use as a scripting or glue language to connect existing components together due to its high-level built-in data structures, dynamic typing, and dynamic binding. Python's straightforward syntax emphasizes readability and makes it simple to learn, which lowers the cost of program maintenance. Python's support for modules and packages promotes the modularity and reuse of code in programs. For all popular platforms, the Python interpreter and the comprehensive standard library are freely distributable and available in source or binary form.

Code:

def solution(array):    

   array.sort(key=lambda array:

   (bin(array).count("1"), array))    

   return array

num = [31,15,7,3,2]

print(solution(num))

Output:

[2, 3, 7, 15, 31]

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Answer:

make sure its safe make sure it works as inteded

Explanation:

yes

Answer:

Las declaraciones falsas incluyen

- El KOH es el agente reductor.

- La suma de electrones transferidos más el coeficiente mínimo de agua suman 16.

Todas las otras declaraciones son ciertas.

The false statements include

- The KOH is the reducing agent.

- The sum of transferred electrons plus the minimum coefficient of water add up to 16.

All the other statements are true.

Explanation:

Es evidente que esta es una reacción redox en presencia de medio básico. Entonces, equilibraremos esta reacción redox en pasos. I₂ + KOH → KIO₃ + KI + H₂O

Paso 1 Eliminar los iones espectadores; Estos son los iones que aparecen en ambos lados de la reacción. Es evidente que solo el ion de potasio (K⁺) es el ion espectador de esta reacción.

I₂ + OH⁻ → IO₃⁻ + I⁻ + H₂O

Paso 2

Separamos la reacción en las medias reacciones de oxidación y reductina. La oxidación es la pérdida de electrones que conduce a un aumento del número de oxidación del ion, mientras que la reducción es la ganancia de elecrones que conduce a una disminución en el número de oxidación del ion. También es evidente que es el gas de yodo el que se reduce y oxida para esta reacción.

El gas de yodo se reduce a I⁻ (el número de oxidación se reduce de 0 a -1) y el gas de yodo se oxida a IO₃⁻ (el número de oxidación de yodo aumenta de 0 en gas de yodo a +5 en IO₃⁻)

Reducción media reacción

I₂ → I⁻

Media reacción de oxidación

I₂ + OH⁻ → IO₃⁻ + H₂O

Paso 3

Equilibramos las medias reacciones y agregamos los respectivos electrones transferidos

Reducción media reacción

I₂ → 2I⁻

I₂ + 2e⁻ → 2I⁻

Media reacción de oxidación

I₂ + 12OH⁻ → 2IO₃⁻ + 6H₂O

I₂ + 12OH⁻ → 2IO₃⁻ + 6H₂O + 10e⁻

Paso 4

Balancee el número de electrones en las dos medias reacciones

[I₂ + 2e⁻ → 2I⁻] × 5

[I₂ + 12OH⁻ → 2IO₃⁻ + 6H₂O + 10e⁻] × 1

5I₂ + 10e⁻ → 10I⁻

I₂ + 12OH⁻ → 2IO₃⁻ + 6H₂O + 10e⁻

Paso 5

Agregue las dos medias reacciones y elimine cualquier especie que aparezca en ambos lados

5I₂ + 10e⁻ + I₂ + 12OH⁻ → 10I⁻ + 2IO₃⁻ + 6H₂O + 10e⁻

Entonces, eliminamos los 10 electrones que fueron transferidos en la reacción balanceada

6I₂ + 12OH⁻ → 10I⁻ + 2IO₃⁻ + 6H₂O

Paso 6

Reintroducimos la especie eliminada desde el principio (el ion potasio)

6I₂ + 12KOH → 10KI + 2KIO₃ + 6H₂O

Los coeficientes mínimos son entonces

3I₂ + 6KOH → 5KI + KIO₃ + 3H₂O

Luego verificamos cada una de las declaraciones proporcionadas para elegir las falsas.

- La suma de los coeficientes mínimos del agua y el agente reductor es 6.

El gas yodo es el agente reductor y oxidante. Coeficiente mínimo de agua y gas de yodo = 3 + 3 = 6 Esta afirmación es cierta.

- El KI es la forma reductora KI resulta de la semirreacción de reducción.

Por lo tanto, es la forma reducida del gas de yodo. Esta afirmación es cierta. - El KOH es el agente reductor. KOH no es el agente reductor. Esta afirmación es falsa.

- La suma de los electrones transferidos más el coeficiente mínimo de agua suman 16.

Electrones transferidos = 10

Coeficiente mínimo de agua = 3

Suma = 13 y no 16.

Esta afirmación es falsa.

- La proporción del agente oxidante y el agente reductor es 1.

Dado que el gas yodo es el agente reductor y oxidante, la proporción de estos dos es verdaderamente 1. Esta afirmación es cierta.

¡¡¡Espero que esto ayude!!!

Answer:

The program is written in Python:

num = int(input("User Input: "))

mylist = []

while(num !=0):

    mylist.append(num)

    num = int(input("User Input: "))

mylist.reverse()

for i in mylist:

    print(i,end = ' ')

Explanation:

This question is answered using Python and it uses 0 as a sentinel value; i.e. the program stops prompting user for input when user enters 0

This line prompts user for input

num = int(input("User Input: "))

This line declares an empty list

mylist = []

This loop is repeated as long as user enters input other than 0

while(num !=0):

This appends user input to the list

    mylist.append(num)

This prompts user for another input

    num = int(input("User Input: "))

This reverses the list

mylist.reverse()

The following iteration the list in reverse order

for i in mylist:

    print(i,end = ' ')

The reliability of the system is 1.5732986.

Given,The computer has three main modules that have individual reliabilities of 0.75, 0.93, and 0.83.It is given that, each module has a backup with a reliability equal to its own and a backup switch with a reliability of 1.00.Reliability of module 1 = 0.75Reliability of module 2 = 0.93Reliability of module 3 = 0.83Let, S be the reliability of the system.The system will work if: (original module 1 is working and its backup is not required) OR (original module 1 fails but its backup works) OR (original module 1 and its backup both fail but the backup switch is working and the backup of module 1 on another machine is working)Similarly, the system will work if: (original module 2 is working and its backup is not required) OR (original module 2 fails but its backup works) OR (original module 2 and its backup both fail but the backup switch is working and the backup of module 2 on another machine is working)Similarly, the system will work if: (original module 3 is working and its backup is not required) OR (original module 3 fails but its backup works) OR (original module 3 and its backup both fail but the backup switch is working and the backup of module 3 on another machine is working)Probability of original module i working = reliability of module i = RiProbability of original module i failing = 1 - RiProbability of the backup module of i failing = 1 - RiProbability of both original and backup of module i failing = (1 - Ri)^2Probability of the backup switch failing = 1 - 1.00 = 0.00Probability of the backup computer failing = 1 - reliability of backup computer = 1 - RiS = Probability of (original module 1 working and its backup is not required) OR (original module 1 fails but its backup works) OR (original module 1 and its backup both fail but the backup switch is working and the backup of module 1 on another machine is working) OR (original module 2 is working and its backup is not required) OR (original module 2 fails but its backup works) OR (original module 2 and its backup both fail but the backup switch is working and the backup of module 2 on another machine is working) OR (original module 3 is working and its backup is not required) OR (original module 3 fails but its backup works) OR (original module 3 and its backup both fail but the backup switch is working and the backup of module 3 on another machine is working)Probability of each module i being required = probability of original module i failing and its backup working + probability of both original and backup of module i failing but backup switch and backup of module i on another machine working= (1 - Ri) * Ri + (1 - Ri)^2 * Ri * (1 - 0.75) * (1 - 0.93) * (1 - 0.83) * (1 - 0.00) * (1 - R)S = Probability of module 1 being required + Probability of module 2 being required + Probability of module 3 being requiredS = [(1 - 0.75) * 0.75 + (1 - 0.75)^2 * 0.75 * (1 - 0.93) * (1 - 0.83) * (1 - 1.00) * (1 - 0.75)] + [(1 - 0.93) * 0.93 + (1 - 0.93)^2 * 0.93 * (1 - 0.75) * (1 - 0.83) * (1 - 1.00) * (1 - 0.93)] + [(1 - 0.83) * 0.83 + (1 - 0.83)^2 * 0.83 * (1 - 0.75) * (1 - 0.93) * (1 - 1.00) * (1 - 0.83)]S = 0.75 + 0.1374165 + 0.6858815 = 1.5732986

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Tech b says that many oxygen sensors have a built-in heater to warm them up more quickly - correct

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The maximum value of load F is approximately 18310 lb (rounded to 4 significant figures).

Given the diameter of the steel axle is 2.3 inches.

The steel axle is used as a cantilever of length 2 feet.

The load applied is F and the yield strength and ultimate strength of the material of the axle are given as

Sy = 48 ksi and

Su = 65 ksi respectively.

We need to find the maximum value of load F, considering a combined shock and fatigue factor of 1.5.

The bending stress induced in the axle is given by the relation:

bending stress = (M × y)/I

Where M is the maximum moment induced in the axle,

y is the distance of the point from the neutral axis of the axle and

I is the moment of inertia of the axle.

The maximum moment occurs at the free end of the cantilever and its value is

M = F × L,

where L is the length of the cantilever.

The neutral axis of the axle is at its center.

The moment of inertia of the axle is

I = πd⁴/64,

where d is the diameter of the axle.

The maximum bending stress can be given as:

(M × y)/I = (FL/2) / (πd⁴/64)

            = 32FL/(πd⁴)

The factor of safety is given by the relation:

FOS = (Sy / bending stress)

The endurance limit of the steel material of the axle is given by the relation:

Se = 0.5Su

The modified endurance limit considering a combined shock and fatigue factor of 1.5 is given by the relation:

S′e = Se / 1.5

The fatigue strength of the steel material of the axle is given by the relation:

Sf = S′e × FOS

We can calculate the maximum value of load F using the above relation and substituting the given values:

Sf = S′e × FOSS′e

= Se / 1.5 = (0.5Su) / 1.5

= (0.5 × 65) / 1.5

= 21.6667 ksi

Bending stress = 32FL/(πd⁴)

= S′e / FOS

= (21.6667 ksi) / (1.5 × 48 ksi)

= 0.3020833

F = bending stress × (πd⁴) / 32L

= (0.3020833 × (π × (2.3 in)⁴) / 32 × (2 ft) ) / lb

= 18311.6 lb

≈ 18310 lb

Thus, the maximum value of load F is approximately 18310 lb (rounded to 4 significant figures).

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In order to construct a recursive algorithm for finding the square root of a nonnegative real number, we can use the following steps: Suppose x is a non-negative real number, a is the approximate square root of x, and epsilon is the tolerance.

Start with a = x. If |a² - x| ≤ epsilon, then a is the square root of x within the tolerance; otherwise: Replace a with (a² + x) / and repeat Step a, in which |a² - x| denotes the absolute value of a² - x. The recursion stops when the base case is reached, i.e., when the absolute value of the difference between the approximate square root and the actual square root of x is less than or equal to the tolerance.

To implement this algorithm in C++, we can write a recursive function as follows: which is the nonnegative real number whose square root we want to find; a, which is the initial approximation of the square root; and epsilon, which is the tolerance value. The function returns the approximate square root of x within the given tolerance.

The main() function prompts the user to enter the values of x, a, and epsilon, calls the sqrtRecursive() function to find the square root of x, and prints the result.

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The Rule That Packets Not Originating From Inside Your LAN Should Not Be Forwarded Relates to routers

In order to transfer data between two or more packet-switched computer networks, a router—either real or virtual—is used.. The Internet Protocol address (IP address) of the destination is examined by a router, which then determines the optimal path for the data packet to take to get there.

According to the various application categories, there are five different types of routers available. They include VPN routers, core routers, edge routers, wireless routers, and wired routers. The aforementioned fundamental details can be used to aid in making the best router selection possible.

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The shaded area's polar radius of gyration around its centroid C. Assume t = 130 mm, a = 465 mm, b = 565 mm ko = 253 mm.

The difference between the area of the complete polygon and the area of the unshaded portion inside the polygon is the area of the shaded region. There are two methods for the area of the shaded component to appear in polygons. The darkened area can be found either in the polygon's centre or on one of its sides. You might occasionally be necessary to determine the size of shaded areas. The area of the shaded zone is often calculated by deducting the area of a smaller inner form from the area of a larger outer shape. "Sector" of a circle is represented by the darkened area. A sector is the area of a circle that is bounded by two radii and an arc.

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Traffic fatalities are higher at night compared to daytime.

During nighttime, visibility is reduced, and it becomes more challenging for drivers to see clearly, judge distances accurately, and react to unexpected situations. The lack of adequate lighting on roads also contributes to increased risks. Additionally, factors such as fatigue, impaired driving due to alcohol or drugs, and increased prevalence of reckless driving behaviors during nighttime can further contribute to the higher rate of traffic fatalities.

Therefore, the statement implies that the number of traffic fatalities is greater during nighttime compared to daytime. This is supported by statistical data and studies that consistently show an increased risk of accidents and fatalities during nighttime hours.

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Answer:

It does not take into consideration what the responsible party knew about the law or regulation they violated. Environmental criminal liability is triggered through some level of intent.

In regards to whether an employee can be held legally liable for environmental violations, this statement is False.

This means that if an employee notices that a company is responsible for environmental violations, and does nothing about it, they could be held legally responsible for the violation as well.

In conclusion, this is true.

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Answer:

car a is moving faster than the car b

Answer:

B: Car A and car B are moving in opposite directions.

C: Car A is moving faster than car B.

E: Car A and car B are moving toward each other until they cross over.

Explanation:

I just did the assignment on EDGE2020 and it's 200% correct!  

Also, heart and rate if you found this answer helpful!! :) (P.S It makes me feel good to know I helped someone today!!)  :)  

The received power if the effective aperture area of the receiving antenna is 20 m2 is 177.77 m2.

In physics, power is referred to as the rate of energy conversion or transfer over time. The unit of power in the SI system, often known as the International System of Units, is the Watt (W). A single joule per second is one watt.

Power was formerly referred to as activity in some research. A scalar quantity is power. As power is always a function of labor done, it follows that if a person's output varies during the day depending on the time of day, so will his power.

A measure of the pace at which energy is transferred, power is a physical quantity. As a result, it can be described as the pace of job completion relative to time.

Therefore, The received power if the effective aperture area of the receiving antenna is 20 m2 is 177.77 m2.

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The angle of attack of a wing directly controls the C) distribution of pressures acting on the wing.

When the angle of attack of a wing is increased, the air moving over the curved upper surface of the wing must travel a greater distance and faster than the air moving beneath the wing's flat lower surface. This creates an area of lower air pressure above the wing and an area of higher air pressure beneath the wing, resulting in lift. The greater the angle of attack, the greater the lift produced.

However, if the angle of attack is too great, the airflow over the wing may separate, causing a loss of lift and potentially leading to a stall. Therefore, proper control of the angle of attack is crucial for safe and efficient flight.

Option C is answer.

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Answer:

The values shown in the table below are valid only for the conditions under which they were determined (usually room temperature and atmospheric pressure using a 2 inch tube with spark ignition). The flammability range of most materials expands as temperature, pressure and container diameter increase. All concentrations in percent by volume.

GasLELUELAcetone2.613Acetylene2.5100Acrylonitrile317Allene1.511.5Ammonia1528Benzene1.37.91.3 Butadiene212Butane1.88.4n Butanol1.7121 Butene1.610Cis 2 Butene1.79.7Trans 2 Butene1.79.7Butyl Acetate1.48Carbon Monoxide12.574Carbonyl Sulfide1229Chlorotrifluoro ethylene8.438.7Cumene0.96.5Cyanogen6.632Cyclohexane1.37.8Cyclopropane2.410.4Deuterium4.975Diborane0.888Dichlorosilane4.198.8Diethylbenzene0.8 1.1 Difluoro 1 Chloroethane914.81.1 Difluoroethane5.117.11.1 Difluoro ethylene5.521.3Dimethylamine2.814.4Dimethyl Ether3.4272.2 Dimethyl propane1.47.5Ethane312.4Ethanol3.319Ethyl Acetate2.211Ethyl Benzene16.7Ethyl Chloride3.815.4Ethylene2.736Ethylene Oxide3.6100Gasoline1.27.1Heptane1.16.7Hexane1.27.4Hydrogen475Hydrogen Cyanide5.640Hydrogen Sulfide444Isobutane1.88.4Isobutylene1.89.6Isopropanol2.2 Methane517Methanol6.736Methylac etylene1.711.7Methyl Bromide10153 Methyl 1 Butene1.59.1Methyl Cellosolve2.520Methyl Chloride717.4Methyl Ethyl Ketone1.910Methyl Mercaptan3.921.8Methyl Vinyl Ether2.639Monoethy lamine3.514Monomethy lamine4.920.7Nickel Carbonyl2 Pentane1.47.8Picoline1.4 Propane2.19.5Propylene2.411Propylene Oxide2.837Styrene1.1 Tetrafluoro ethylene443Tetrahydrofuran2 Toluene1.27.1Trichloro ethylene1240Trimethylamine212Turpentine0.7 Vinyl Acetate2.6 Vinyl Bromide914Vinyl Chloride422Vinyl Fluoride2.621.7Xylene1.16.6

Answer:

I TOLD YOU I DID NOT UNDERSTAND PLEASE,

Explanation:

Answer:

true

Explanation:

Answer:

18 gauge

Explanation:

Standard automotive primary wire is 18 gauge. (internet search) Hope this helps