a force of n acts on a kg body initially at rest compute the work done by the force in the first the second and the third seconds and the instantaneous power due to the force
Answers
Power in the first second:
P1 = dW1/dt,
= W2 - W1, (as the time interval is 1 second).
Power in the second second:
P2 = dW2/dt,
= W3 - W2, (as the time interval is 1 second).
Power in the third second:
P3 = dW3/dt,
= 0, (as we don't have data for the fourth second).
Let's assume the force acting on the body is constant throughout the time period.
Work done by a force (W) is given by the formula:
W = F * d * cos(theta),
where:
F is the magnitude of the force (in newtons, N),
d is the displacement of the body (in meters, m),
theta is the angle between the force and displacement vectors (if they are not in the same direction).
Since the body is initially at rest, we'll assume the displacement occurs in a straight line, so theta = 0 degrees and cos(theta) = 1.
To calculate the work done in the first second, we need to know the displacement during that time. Let's assume the body accelerates uniformly.
Using the equation of motion:
s = ut + (1/2)at^2,
where:
s is the displacement (unknown),
u is the initial velocity (0 m/s, as the body is at rest),
a is the acceleration (F/m, where m is the mass of the body in kg),
t is the time (1 s, for the first second).
Rearranging the equation, we get:
s = (1/2)at^2.
Since the initial velocity is zero, the equation simplifies to:
s = (1/2)(F/m)t^2.
Now, let's calculate the work done in the first second:
W1 = F * s1,
= F * [(1/2)(F/m)(1s)^2],
= F^2/(2m).
The work done in the second second can be calculated using the same approach but with a time of 2 seconds:
s2 = (1/2)(F/m)(2s)^2,
= 2^2(F^2/m),
= 4F^2/m.
W2 = F * s2,
= F * (4F^2/m),
= 4F^3/m.
For the third second:
s3 = (1/2)(F/m)(3s)^2,
= 9F^2/m.
W3 = F * s3,
= F * (9F^2/m),
= 9F^3/m.
Now, let's calculate the instantaneous power due to the force. Power (P) is defined as the rate at which work is done, given by the formula:
P = dW/dt,
where dW is the differential work done in a small time interval dt.
Since we know the work done in each second, we can calculate the instantaneous power as the rate of change of work with respect to time.
Power in the first second:
P1 = dW1/dt,
= W2 - W1, (as the time interval is 1 second).
Power in the second second:
P2 = dW2/dt,
= W3 - W2, (as the time interval is 1 second).
Power in the third second:
P3 = dW3/dt,
= 0, (as we don't have data for the fourth second).
Keep in mind that this calculation assumes the force remains constant throughout the time period and the body's mass doesn't change.
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Related Questions
An eccentric inventor attempts to levitate by first placing a large negative charge on himself and then putting a large positive charge on the ceiling of his workshop. Instead, while attempting to place a large negative charge on himself, his clothes fly off. Explain.
Answers
Answer:
shirt is little attached to the body, it can come off and fly away
Explanation:
In electrostatics, charges of different signs attract and charges of the same sign repel.
In this case, when a negative charge is placed on it, both the inventor and the shirt are charged, therefore there is a repulsive force, also there is an attraction between the positive charge of the roof attracts the negative charge, such as the shirt. of weak the two forces not greater than the resistance of the walk.
As the shirt is little attached to the body, it can come off and fly away
Ionic compounds ___________ electrons, so their compound can have a total of ____ valence electrons altogether
Answers
Ionic compounds give and receive electrons so that they have eight valence electrons in their outermost shell and form a stable electron configuration. They are usually formed between metals and non-metals and have high melting and boiling points due to strong electrostatic forces between oppositely charged ions.
Ionic compounds form a crystalline lattice structure. The ionic compound can have a total of 8 valence electrons in its outer shell to achieve a stable electron configuration. Ionic compounds usually exist as solids in their natural state and have high melting points. Sodium Chloride (NaCl) is an example of an ionic compound. They typically dissolve in polar solvents, and their properties are mainly determined by the ratio of the positively and negatively charged ions in the crystal structure. Most ionic compounds are soluble in water and can conduct electricity when melted or dissolved in a polar solvent. Hence, Ionic compounds give and receive electrons, so their compound can have a total of 8 valence electrons altogether.
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determine the tension developed in cables ab, ac and ad. determine the direction cosine angles of the force in cable ac
Answers
To determine the tension developed in cables AB, AC, and AD, we need additional information such as the forces acting on the cables or the dimensions of the system.
The direction cosine angles of the force in cable AC can be determined using trigonometry. The direction cosine angles represent the cosine values of the angles between the force and the coordinate axes.
Let's assume that the force in cable AC is represented by vector F_AC. The direction cosine angles can be calculated as follows:
1. Determine the magnitudes of the x, y, and z components of vector F_AC.
2. Calculate the magnitude of vector F_AC using the Pythagorean theorem: F_AC = √(F_ACx² + F_ACy² + F_ACz²).
3. Calculate the direction cosine angles θx, θy, and θz as follows:
- θx = F_ACx / F_AC
- θy = F_ACy / F_AC
- θz = F_ACz / F_AC
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how does earth protect us from higher energy waves such as x-rays and gamma rays
Answers
Answer:
The earth's atmosphere absorbs the majority of ultraviolet, X-, and gamma rays, which are all shorter wavelengths than visible light. High energy X- and gamma rays would damage organisms and cells of creatures if they were to reach the earth's surface directly. Fortunately, the atmosphere protects life on earth.
Explanation:
1.85 m tall person stands 8.50 m in front of a large, concave spherical mirror having a radius of curvature of 4.00 m. Determine the mirror's focal length, image distance, and magnification.
Answers
The mirror's magnification is -0.307, which indicates that the image is inverted, and its focal length is 2.0 m. The picture's separation from the mirror is 2.61 m.
Mirror radius: R = 4.0 meter's
Mirror's focal length is equal to
focal length = R/2,
focal length = 4.0/2 m, and f = 2.0 m.
The man is 1.85 meter's tall.
Do = 8.5 meter's separates the subject from the mirror.
The distance between the picture and the mirror is di
1/di = 1/2.0-1/8.51
di = 1/0.382
di = 2.61m.
The picture is produced on the same side of the mirror as the item because the image distance is positive, hence the image will be accurate.
The magnification is negative thus the picture created is inverted.
magnification = -di/do = - 2.61/8.5 = -0.307.
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According to the bohr model, the radius of the n = 1 orbit in the hydrogen is a0 = 0.053 nm. what is the radius of the n = 4 orbit?
Answers
The radius of the n = 4 orbit in a hydrogen atom is approximately 0.848 nm.
According to the Bohr model, the radius of the electron's orbit in a hydrogen atom is given by the formula:
r = (n² * a0) / Z
where:
r is the radius of the orbit
n is the principal quantum number (the energy level of the orbit)
a0 is the Bohr radius, which is approximately 0.053 nm for hydrogen
Z is the atomic number of the nucleus (which is 1 for hydrogen)
For the n = 4 orbit, we can substitute the values into the formula:
r = (4² * 0.053 nm) / 1
r = (16 * 0.053 nm) / 1
r = 0.848 nm
Therefore, the radius of the n = 4 orbit in a hydrogen atom is approximately 0.848 nm.
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3. Calculate the force of gravity that Saturn (mass = 5. 7 x 1026 kg) exerts
on a woman on Earth (mass = 61 kg) when Saturn is closest to Earth,
1. 2 x 10° km.
Answers
The force of gravity that Saturn (mass = 5. 7 x 1026 kg) exerts on a woman on Earth (mass = 61 kg) when Saturn is closest to Earth = 1. 2 x 10° km.
Explanation of the given answer:Formula used in step two. F = G m 1 m 2 r 2. Step 3: Determine the gravitational force.
Calculating the gravitational force is step three. F = 6.7 10 11 by changing the values in the formula above. 2 × 10 30 × 6 × 10 24 1 .5 × 10 11 2 F = 3 .
The formula for the gravitational constant of the universe is G = 6.674 x 10 - 11 m3/kg s2. Thus, this is the gravitational pull of the sun on the planet.
F = Gm1m2R2, where G is the gravitational constant of the universe. The gravitational force between two bodies of equal mass that are kept at an equal distance from one another constitutes the universal gravitational constant.
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The student notices that the electronic balance has a zero error, so it shows
mass readings that are all slightly too small.
This means that the density value is
A)incorrect and slightly too large
B)incorrect and slightly too small
C)correct because the student used three significant figures
D)correct because the mass of the block is more than zero
Answers
The student notices that the electronic balance has a zero error, so it shows mass readings that are all slightly too small. This means that the density value is incorrect and slightly too small. The correct option is B.
The density is the ratio of the mass and the volume of the object. It is denoted by ρ.
ρ = mass/Volume = m/V
The student notices that the electronic balance has a zero error, so it shows mass readings that are all slightly too small.
As mass is directly proportional to density. The density will also be slight small when mass reading are all slightly small.
Thus, the correct option is B.
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A) Find the tension in each of the two ropes supporting a hammock if one is at an angle of θ1 = 10 ∘ above the horizontal and the other is at an angle of θ2 = 33 ∘ above the horizontal. The person sleeping in the hammock (unconcerned about tensions and ropes) has a mass of 66 kg . Express your answer using two significant figures.
T1= ? N
B) Express your answer using two significant figures.
T2= ? N
Answers
(a) The tension in the rope at an angle of 10° above the horizontal is approximately 798.5.4 N.
(b) The tension in the rope at an angle of 33° above the horizontal is approximately937.7 N.
What is the tension in the rope?To find the tension in each rope, we can use the fact that the net force in the vertical direction must be zero since the person in the hammock is at rest. Let T1 and T2 be the tensions in the ropes, and let the x-axis point to the right and the y-axis point upward.
A) The forces acting on the person are their weight (mg) downward and the tensions T1 and T2 in the two ropes, which make angles θ1 and θ2 with the horizontal.
The vertical components of the tensions are T1sinθ1 and T2sinθ2, respectively, and the horizontal components are T1cosθ1 and T2cosθ2.
Therefore, we can write:
T1sinθ1 + T2sinθ2 = mg (vertical equilibrium)
T1cosθ1 = T2cosθ2 (horizontal equilibrium)
Solving for T1 and T2, we get:
T1 = (mgcosθ2) / (sinθ1cosθ2 + sinθ2cosθ1)
T1 = (66)(9.81 )(cos(33°)) / (sin(10°)cos(33°) + sin(33°)cos(10°))
T1 ≈ 798.5.4 N
B) Similarly, we can use the horizontal equilibrium equation to find T2:
T2 = T1cosθ1 / cosθ2 = (798.5 N)(cos(10°)) / cos(33°) ≈ 937.7 N
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What occurs to the particles in a substance at low temperature when energy is transferred to the substance as heat?
answer choices
a. The average kinetic energy of the particles varies unpredictably.
b. The average kinetic energy of the particles decreases.
c. The average kinetic energy of the particles remains constant.
d. The average kinetic energy of the particles increases.
Answers
When energy is transferred to a substance as heat, the average kinetic energy of the particles increases, leading to an increase in temperature.
Th correct answer is option d.
At low temperatures, when energy is transferred to a substance as heat, the average kinetic energy of the particles increases. This is because the heat energy is used to increase the energy of the particles and make them move more quickly.
As a result, the particles have greater kinetic energy, which is what is required for them to move faster and at a greater distance. In addition, when energy is added to the particles, they start to interact more with each other, increasing the overall energy of the substance.
The increase in kinetic energy of the particles is often referred to as temperature. The greater the temperature of a substance, the higher the kinetic energy of the particles. This increase in kinetic energy of the particles is what causes them to vibrate and move more quickly. As the temperature of a substance rises, the particles have more kinetic energy and are able to move further and faster.
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A 1380 kg car starts from rest at the top of a 28.0 m long hill inclined at 11.00 degrees. Ignoring friction, how fast is it going when it reaches the bottom of the hill?
Answers
Answer:
10.2 m/s
Explanation:
Using conservation of energy:
PE = KE
mgh = ½ mv²
v = √(2gh)
v = √(2 × 9.8 m/s² × 28.0 m × sin 11.0°)
v = 10.2 m/s
The velocity when car reaches the bottom of the hill is 10.2 m/s.
What is mechanical energy?The mechanical energy is the sum of kinetic energy and the potential energy of an object at any instant of time.
M.E = KE +PE
M.E = ½ mv² + mgh
where g is the acceleration due to gravity, v is the velocity, m is the mass and h is the height of the object.
Given is a 1380 kg car starts from rest at the top of a 28.0 m long hill inclined at 11.00 degrees.
Using conservation of energy principle, we have
PE = KE
mgh = ½ mv²
v = √(2gh)
Substitute the values, we get
v = √(2 × 9.8 m/s² × 28.0 m × sin 11.0°)
v = 10.2 m/s
Thus, the velocity when car reaches the bottom of the hill is 10.2 m/s.
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HELP PLS PLS PLS I WILL MARK U BRAINLIEST!!!
Answers
Answer:
glass is optically denser as it is a optical material having more index number above the list
Answer:
zicron
Explanation:
it has a large refractive index
explain how energy carried by a light and sound wave varies with amplitude and frequency properties brainly WILL GIVE 100 POINTS
Answers
Answer:
A sound is a form of energy, just like electricity, heat, or light. When you strike a bell, it makes a loud ringing noise. Now instead of just listening to the bell, put your finger on the bell after you have struck it. Can you feel it shaking? This movement or shaking, i.e. the to and fro motion of the body is termed as Vibration.
The sound moves through a medium by alternately contracting and expanding parts of the medium it is travelling through. This compression and expansion create a minute pressure difference that we perceive as sound. Let’s discuss the characteristics of sound waves like amplitude, frequency, wavelength, and timbre.
Explanation:
The amount of energy carried by them is proportional to their frequency and amplitude. The greater the frequency, the greater the energy, and the greater the amplitude, the greater the energy.
What is frequency?The frequency of a repeating event is the number of occurrences per unit of time. It is also known as temporal frequency to distinguish it from spatial frequency and ordinary frequency to distinguish it from angular frequency.
In physics, frequency is the number of waves that pass through a fixed point in one unit of time; it is also the number of cycles or vibrations that a body in periodic motion undergoes in one unit of time.
Their energy carrying capacity is proportional to their frequency and amplitude. The more frequency there is, the more energy there is, and the more amplitude there is, the more energy there is.
Thus, this way, energy carried by a light and sound wave varies with amplitude and frequency properties.
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Using F=mXa
1.
Maria's bicycle has a mass of 18.0 kg. What is the net force needed to attain the
acceleration of 1.62 m/s2?
Answers
Answer:
29.16 NExplanation:
The force acting on an object given it's mass and acceleration can be found by using the formula
force = mass × acceleration
From the question we have
force = 18 × 1.62
We have the final answer as
29.16 NHope this helps you
Which are the products in the equation CH3SH + 4O2 → CO2 + SO2 +2H2O? Check all that apply. CH3SH, O2 ,CO2, SO2, H2O
Answers
Answer:
C D E is the answer
Explanation:
The products of the reaction are; CO2, SO2, H2O.
What is a chemical reaction equation?A chemical reaction equation equation is composed of;
Reactants on the left hand sideProducts on the right hand sideThe interaction between the reactants give rise to the formation of the products. The products are the result of rearrangement of atoms in the reactants.
For the reaction; CH3SH + 4O2 → , the products of the reaction are; CO2, SO2, H2O.
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describe the motions of a baseball thrown from a height of 10 ft versus a ball that was just dropped from a height of 10 ft at the same time.
Answers
When comparing the motions of a baseball thrown from a height of 10 ft and a ball that is simply dropped from the same height, there are distinct differences.
The thrown baseball exhibits a combination of vertical and horizontal motion. It follows a curved path due to the initial throwing velocity and the force of gravity, resulting in a parabolic trajectory. In contrast, the dropped ball experiences only vertical motion, falling straight down toward the ground in a vertical line. While both objects are affected by gravity, the thrown baseball's additional horizontal velocity allows it to cover a longer distance and follow a more complex path compared to the vertically descending dropped the ball.
Therefore, the thrown baseball exhibits both vertical and horizontal motion, following a curved trajectory due to the combination of the initial throwing velocity and the force of gravity. The dropped ball, on the other hand, experiences only vertical motion, falling straight down toward the ground along a vertical line.
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a 1000 kg car is driving around a 100 m radius curve. the coefficient of static friction is 0.80 and the coefficient of kinetic friction is 0.60. determine the maximum speed that thee car can travel without slipping.
Answers
The maximum speed that the car can travel without slipping is 28 m/s.
What is the maximum speed of the car?For a car driving around a circular path not skid at maximum speed, then the centripetal force of the car must be equal to the static frictional force.
Fc = Fs
ma = μmg
a = μg
v²/r = μg
v² = rμg
v = √rμg
where;
v is the maximum speed of the carμ is the coefficient of static frictiong is acceleration due to gravityr is the radius of the circular pathv = √(100 x 0.8 x 9.8)
v = 28 m/s.
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A sample of helium behaves as an ideal gas as
it is heated at constant pressure from 283 K
to 393 K.
If 40 J of work is done by the gas during this process, what is the mass of the helium sample? The universal gas constant is
8.31451 J/mol · K.
Answer in units of g.
Answers
Answer: To calculate the mass of the helium sample, we can use the ideal gas law equation, which relates the pressure, volume, temperature, and amount of gas for an ideal gas:
PV = nRT
Where:
P = pressure of the gas
V = volume of the gas
n = amount of gas in moles
R = universal gas constant
T = temperature in Kelvin
Given information:
Pressure (P) = constant pressure during the process
Initial temperature (T1) = 283 K
Final temperature (T2) = 393 K
Work done by the gas (W) = 40 J
Universal gas constant (R) = 8.31451 J/mol · K
Since the pressure is constant, we can rearrange the ideal gas law equation to solve for the amount of gas (n) in moles:
n = (PV) / (RT)
Substituting the given values into the equation:
n = (constant pressure during the process * volume) / (universal gas constant * temperature)
Now we can calculate the amount of gas in moles.
Next, we can convert the amount of gas from moles to grams using the molar mass of helium (He), which is approximately 4 g/mol.
Finally, we can multiply the mass in grams by 1000 to convert it to grams.
Let's plug in the numbers and do the calculations:
P = constant pressure during the process
V = volume of the gas (not given in the question, need additional information)
R = universal gas constant = 8.31451 J/mol · K
T1 = initial temperature = 283 K
T2 = final temperature = 393 K
W = work done by the gas = 40 J
Molar mass of helium (He) = 4 g/mol
Please provide the value for the volume (V) of the helium gas in order to complete the calculation.
Un automovil de 900 kg toma una curva de radio de 40 m con una rapidez constante de 50 km/h. Cual es la fuerza neta necesaria para mantener al automovil moviendose en la curva circular
Answers
Answer:
Fc = 4340,93 Newton
Explanation:
Dados los siguientes datos;
Masa = 900 kg
Velocidad, V = 50 km/h a metros por segundo = (50 * 1000)/(60 * 60) = 50000/3600 = 13,89 m/s
Radio, r = 40 m
Para encontrar la fuerza centrípeta;
Fc = mv² / r
Fc = (900 * 13,89²)/40
Fc = (900 * 192,93)/40
Fc = 173637/40
Fc = 4340,93 Newton
In a physics lab, you apply a 34.5 N rightward
force to a 4.52 kg cart to accelerate it across a
horizontal surface at a rate of 1.28 m/s/s.
Determine the friction force acting upon the cart
and coefficient of friction.
Answers
Answer:
Explanation:
The frictional force is
=
28.71
N
Explanation:
Let
F
r
=
frictional force
and
F
=
the force applied
The net force acting on the object is
(
F
−
F
r
)
By Newton's second Law
(
F
−
F
r
)
=
m
a
where,
a
=
the acceleration
and
m
=
mass of the cart
So,
F
−
F
r
=
m
a
F
r
=
F
−
m
a
=
34.5
−
4.52
⋅
1.28
=
28.71
N
A man takes his dog for a walk. His motion is recorded on the coordinate plane below. On the plane, each block represents 1 km. a. The whole trip took 1.25 hours. What was the average velocity of the man? (2 points) 1.25 hr = 4500 sec. 28:125 m north 18:45 m east 28.125m south b. What was the average speed of the man?
Answers
a) The correct average velocity of the man is approximately 0.026928 km/h.
b) The correct average speed of the man is approximately 0.03726 km/h.
a) Average Velocity:
To calculate the average velocity, we need to determine the total displacement and divide it by the total time taken.
The north displacement is 28.125 m and the east displacement is 18.45 m. Since we are given that each block represents 1 km, we need to convert these distances to kilometers.
North displacement: 28.125 m ÷ 1000 = 0.028125 km
East displacement: 18.45 m ÷ 1000 = 0.01845 km
The total displacement can be calculated using the Pythagorean theorem:
Total displacement = √((0.028125 km)² + (0.01845 km)²) = √(0.000790039 km² + 0.0003409025 km²) ≈ √0.001130941 km² ≈ 0.03366 km
Since the total time taken is given as 1.25 hours, the average velocity is calculated by dividing the total displacement by the total time:
Average velocity = Total displacement ÷ Total time = 0.03366 km ÷ 1.25 hours ≈ 0.026928 km/h
Therefore, the correct average velocity of the man is approximately 0.026928 km/h.
b) Average Speed:
To calculate the average speed, we need to determine the total distance traveled and divide it by the total time taken.
The total distance traveled is obtained by summing up the north and east distances:
Total distance = 0.028125 km + 0.01845 km = 0.046575 km
Average speed = Total distance ÷ Total time = 0.046575 km ÷ 1.25 hours ≈ 0.03726 km/h
Therefore, the correct average speed of the man is approximately 0.03726 km/h.
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Melissa was putting on her makeup when she accidentally ran into a stopped car at a red light, 11. 01 m in front of her. Melissa's 1,219 kg car was moving at 8. 133 m/s and came to a complete stop in 0. 3994 seconds. What is the magnitude of the force that stopped Melissa's car?
a
2. 970E4 N
b
1. 535E4 N
c
1. 934E4 N
d
4. 550E4 N
e
4. 295E4 N
f
3. 400E4 N
g
3. 821E4 N
h
2. 482E4 N
Answers
The required magnitude of the force that stopped Melissa's car is 118608.7 N.
What are 1st 2nd and 3rd laws of motion?According to the first law, unless a force acts on an object, it will not alter its motion. According to the second law, an object's force is determined by multiplying its mass by its acceleration. According to the third law, when two objects interact, they exert equal-sized and opposite-direction forces upon one another.
According to question:An object at rest remains at rest, and an object in motion remains in motion at constant speed and in a straight line unless acted on by an unbalanced force.
Given,
speed=8.133 m/s
final velocity=0 (due to impact)
time=0.3994 seconds
distance=11.01m
Then,
S = ut + (at^2)/2
a = 2(s - ut)t^2
a = 97.3 m/s^2
So,
Force = ma
Force = 1219(97.3)
Force = 118608.7 N
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Suppose we have two oppositely charged sheet placed in y-z plane at x=0 and x=a and are parallel to each other what will be the total electric field intensity at x>a , x
Answers
If we have two oppositely charged sheet placed in y-z plane at x=0 and x=a and are parallel to each other, the total electric field intensity at x>a is zero.
To calculate the electric field at a point, we need to consider the contributions from both sheets. The electric field due to a charged sheet is given by:
E = σ / (2ε₀),
where σ is the surface charge density of the sheet and ε₀ is the permittivity of free space.
Let's assume that the surface charge density of both sheets is σ. Since the sheets are oppositely charged, the electric fields due to the two sheets will have opposite directions.
At a point with x > a, we will have the following situation:
- The electric field due to the sheet at x = 0 will be directed in the positive x-direction.
- The electric field due to the sheet at x = a will be directed in the negative x-direction.
Therefore, the total electric field at the point x > a will be the difference between the magnitudes of the electric fields due to the two sheets:
\(E_{total\) = |\(E_{sheet1\)| - |\(E_{sheet2\)|,
where |\(E_{sheet1\)| is the magnitude of the electric field due to the sheet at x = 0 and |\(E_{sheet2\)| is the magnitude of the electric field due to the sheet at x = a.
Substituting the formula for the electric field due to a charged sheet, we have:
\(E_{total\)= σ / (2ε₀) - σ / (2ε₀).
Simplifying:
\(E_{total\)= 0.
The total electric field at a point with x > a is zero. This means that the electric fields due to the two charged sheets cancel each other out, resulting in no net electric field at that point.
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An air standard diesel gele has a Compresion raho of ings 17 and cutoff raho of 1.6. Air is at 27C and lookpa at the beginning of the Comprestion process. Draw and label a P-v diagram (Wise the standard number Utes in the texbook with state 1 at the beginning of the compresim prices) and state 2 at the end of the compretsin process etc.). Determine the heat transev and work for each process in the cycle. (Assume constant Specific heats of [C p=1.005kJlkg,k and C v =0.718 kJ/kg⋅k and k=1.4 and R=0.2810kpam 3/kgk.] Fiva. 1. The heat transfer for process 1−2 in (kJ/kg) 2. Klork for proces 1−2( kJ/kJ) 3. The heat transfer for proces 2−3 (kJikg) 4. The work for process 2−3( kJ/kg) 5. The heat transfor fow procels 3−4(k→)k 0 ) 6. The work fir procell 3−4 (kJ/ky)
Answers
1. The heat transfer for process 1-2 is 0 kJ/kg.
2. The work for process 1-2 is 530.7 kJ/kg.
3. The heat transfer for process 2-3 is 0 kJ/kg.
4. The work for process 2-3 is 891.5 kJ/kg.
5. The heat transfer for process 3-4 is 0 kJ/kg.
6. The work for process 3-4 is -153.3 kJ/kg.
These values represent the heat transfer and work done in each process of the air-standard Diesel cycle, as calculated using the given specific heat values and the compression and cutoff ratios.
An air-standard Diesel cycle is considered with the following parameters:
Compression ratio (r) = 17
Cutoff ratio (rc) = 1.6
Initial conditions:
- Air temperature (T1) = 27°C
- Air pressure (P1) = 100 kPa
Process 1-2:
The state of air at state 1 is (P1, T1). During the compression process, the volume decreases from v1 to v2, and the temperature increases from T1 to T2. Since this is an air-standard cycle, there is no heat transfer in this process (Q12 = 0 kJ/kg).
The work for process 1-2 can be calculated using the specific heat at constant volume (Cv):
w12 = Cv * (T2 - T1) = 0.718 * (T2 - T1) kJ/kg
Process 2-3:
The air is compressed adiabatically from state 2 to state 3, resulting in an increase in temperature from T2 to T3. Again, since this is an air-standard cycle, there is no heat transfer in this process (Q23 = 0 kJ/kg).
The work for process 2-3 can be calculated using the specific heat at constant pressure (Cp):
w23 = Cp * (T3 - T2) = 1.005 * (T3 - T2) kJ/kg
Process 3-4:
The air expands isentropically from state 3 to state 4, resulting in a reduction in temperature from T3 to T4. Once again, there is no heat transfer in this process (Q34 = 0 kJ/kg).
The work for process 3-4 can be calculated using the specific heat at constant volume (Cv):
w34 = Cv * (T4 - T3) = 0.718 * (T4 - T3) kJ/kg
To determine the values of T2, T3, and T4, we can use the relations between temperature and pressure in the Diesel cycle, given by:
T2 = T1 * r^(k-1)
T3 = T2 * rc
T4 = T3 / r^(k-1)
Where k is the ratio of specific heats (k = Cp / Cv).
Based on given values of T1, P1, Cv, Cp, k, and r we are able to calculate the exact values of T2, T3, and T4, and subsequently, the work done in each process.
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The particles of a substance stay close together but slide past one another
as they move. When thermal energy is added to the substance, the particles
start to move independently of one another. What change in state has
occurred?
A. Solid to liquid
B. Solid to gas
C. Liquid to gas
D. Liquid to solid
Answers
Liquids slide past each other, and gases move individually
47) The moment of inertia of a 0.98-kg bicycle wheel rotating about its center is 0.13 kg · m2. What is the radius of this wheel, assuming the weight of the spokes can be ignored?
Answers
Answer:
0.36 m
Explanation:
The moment of inertial of a wheel can be calculated as
\(I=mr^2\)Where r is the radius of the wheel and m is its mass.
Solving the equation for r, we get
\(r=\sqrt[]{\frac{I}{m}}\)So, replacing I by 0.13 kg m2 and m by 0.98 kg, we get
\(r=\sqrt[]{\frac{0.13\operatorname{kg}\cdot m^2}{0.98\operatorname{kg}}}=0.36\text{ m}\)Therefore, the radius of the wheel is 0.36 m
a. When rock on Earth's surface is broken into
smaller pieces, forming loose material
Answers
When rock on Earth's surface is broken into smaller pieces, forming loose material is called Weathering.
Physical weathering and chemical weathering are the two basic types of weathering. On this page, we discuss mechanical weathering (and more).
Rocks naturally fracture at a number of different levels. The borders between mineral grains can be a source of weakness in the rock. Sedimentary rocks are frequently stratified, and the layers are occasionally not tightly bonded together. As larger, more massive rocks are exposed by erosion, joints (cracks with no relative motion across them, merely spreading) may form in the rocks. These rock fissures become wider due to physical deterioration. Of course, biological weathering refers to weathering caused by living creatures.
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A person takes a trip, driving with a constant speed of 97.5 km/h, except for a 28.0-min rest stop. the person's average speed is 68.0 km/h. (a) how much time is spent on the trip?
Answers
1.54 hours of time were spent on the trip.
What is Average Speed ?Average speed can be defined as the total distance travelled per total time taken.
Given that a person takes a trip, driving with a constant speed of 97.5 km/h, except for a 28.0-min rest stop. the person's average speed is 68.0 km/h.
With a constant speed, 97.5 = distance / ( t - 28/60 )
distance = 97.5 ( t - 0.467 )
distance = 97.5t - 45.5
With an average speed, 68 = distance / t
distance = 68t
Since the distance is the same, equate the two equation
68t = 97.5t - 45.5
68t - 97.5t = -45.5
-29.5t = -45.5
Make t the subject of formula
t = 45.5 / 29.5
t = 1.54 h
Therefore, 1.54 hours of time were spent on the trip.
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The making of the mind is a powerful place and what you feed it can affect you in a powerful way ^^
{NOT A QUESTION^^}
Answers
Answer:
yea that is very true ◠﹏◠✿
Explanation:
Formed at the boundary of two converging continental tectonic plates is called a Mountain formation
True
False
Answers
Answer:
True
Explanation:
At the boundary of two converging continental tectonic plates, a mountain is formed. This is because the collision results in the emergence of mountains.
The density of both plates are nearly similar and lesser than that of the mantle below. This makes the two plates grind together and bulge upward. The Himalaya mountain range is one of such example. In a continental - continental crust collision, mountains are formed.As the grinding continues, the builds upward more and more.