A force of 6.0 N is applied horizontally to a 3.0 kg crate initially at rest on a horizontal frictionless surface. After the crate is pushed for 1.5 seconds, it has a velocity of 3.0 m/s. Does this support Newton's second law of motion, that force equals mass times acceleration? Explain. 

a. Yes, because the acceleration of the crate is 2.0 m/s².

b. No, because the acceleration of the crate is 2.0 m/s².

c. Yes, because the mass and the velocity of the crate are equal.

d. No, because the mass and the velocity of the crate are equal. ​

Answers

Answer 1

Answer:

a. Yes, because the acceleration of the crate is 2.0 m/s².

Explanation:

Given

\(Force = 6N\) --- f

\(Mass = 3kg\) --- m

\(Time = 1.5s\) --- t

\(Velocity = 3.0m/s\) --- v

Required

Does the system support \(F=ma\)

Yes, it does and this is shown below

The crate is initially at rest; so:

\(u = 0\)

Using the first equation of motion

\(v = u + at\)

Substitute values for v, u and t

\(3 = 0 + a*1.5\)

\(3 = 1.5a\)

Make a the subject

\(a = 3/1.5\)

\(a = 2\)

Using \(F = ma\)

Substitute values for F and m

\(6 = 3 * a\)

Divide both sides by 3

\(6/3 = 3/3 * a\)

\(2 = a\)

\(a = 2\)

In both cases:

\(a = 2\)

Hence, option (a) is correct.


Related Questions

OBSERVATION: A shiny red rock is sitting at the bottom of a swimming pool. You grab a long stick and poke it into the pool aiming for the rock, but the stick overshot the rock by a lot. ANSWER GUIDE: Use concepts from L3 and L4 to explain two aspects of this observation: (1) Why was the rock in a different position than you thought it was? (2) Why does the rock appear red? What happened to the other colors in the white sunlight?

Answers

(1) The rock came to be in a various position than you thought it was by way of the wonder of refraction. The rock's position seemed different due to light refraction as it travels at varying speeds through different mediums.

2. Rock looks red as it absorbs all colors of sunlight except red.

2b.  When white light enters water, it refracts and splits into various colors.

What is the concepts  about?

This causes the object to perform at a different position than it literally is. In this case, the light indications coming from the rock were bent when they entered the water, making the rock to appear at a more ignorant wisdom than it actually was.

Therefore, in response to question 2, rock appears red by way of the selective assimilation and reflection of light. The rock absorbs all of the banner of silvery light except for flaming, which is mirrored back to our eyes. This is because the microscopic structure of the rock absorbs all the banner except that red, that is reflected back.

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What happens if you cut a bar magnet in half between the north and south poles?
A. one half has a north pole and one half has a south pole
B. Each half is stronger magnet than the original magnet
C. Each half has both a north pole and a south pole
D. The two halves are no longer magnetic

Answers

c is the correct answer ......... if we cut a magnet i will divide into two halves and ecah half have a southpole and northpole.

Hope it helps

When a bar magnet is cut in half, each half has both a north pole and a south pole. Therefore, option C is correct.

This phenomenon is due to the rearrangement of magnetic domains within the material. The newly formed magnets will have a north pole on one end and a south pole on the other end. This process can be repeated, resulting in smaller and smaller magnets, but each piece will always exhibit both north and south poles.

The magnetic properties are retained even when the magnet is divided into smaller segments. Each half of the magnet becomes a new magnet with its own north and south pole.

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You are spinning two identical balls attached to strings in uniform circular motion, Ball 2 has a string that is twice as long as the string with ball 1, and the rotational speed (v) of ball 2 is three times the rotational speed of ball 1. What is the ratio of the centripetal force of ball 2 to that of ball 1?

Answers

The ratio of the centripetal force of ball 2 to that of ball 1 is 9:2.



To find the ratio of the centripetal force of ball 2 to that of ball 1, let's first look at the formula for centripetal force:
\(F_c = m * v^2 / r\)

where \(F_c\) is the centripetal force, m is the mass of the ball, v is the rotational speed, and r is the radius (or length of the string).

Given that ball 2 has a string that is twice as long as ball 1, we can represent the radii as:
\(r_1\) = r (for ball 1)
\(r_2\) = 2r (for ball 2)

Also, the rotational speed of ball 2 is three times the rotational speed of ball 1, so we have:
\(v_1\) = v (for ball 1)
\(v_2\) = 3v (for ball 2)

Now, we can substitute these values into the centripetal force formula for each ball:
\(F_{c1} = m * v^2 / r\\F_{c2} = m * (3v)^2 / (2r)\)

Now, we need to find the ratio of \(F_{c2}\) to \(F_{c1}\):
\(F_{c2} / F_{c1} = (m * (3v)^2 / (2r)) / (m * v^2 / r)\)

The mass (m) and the speed squared (v²) terms will cancel out:
\(F_{c2} / F_{c1} = ((3^2) / 2)\\F_{c2} / F_{c1} = (9 / 2)\)

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Resistors functioning as _____ are used in applications involving field-effect transistors (fets) and multirange voltmeter circuits.

Answers

Resistors functioning as voltage divider's are used in applications involving field-effect transistors (fets) and multirange voltmeter circuits.

What are voltage dividers?

The expression voltage dividers makes reference to electrical devices used to fractionate the difference of potential (i.e. voltage) of a particular class of electric/electronic instrument.

In conclusion, resistors functioning as voltage divider's are used in applications involving field-effect transistors (fets) and multirange voltmeter circuits.

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____________ occurs when heat is transferred into an object through motion or movement; an example would be boiling water. a conduction b convection c radiation d heat

Answers

Its a Conduction NO FOR REAL ITS A

Answer:

c, convection

Explanation:

edge 2020

How do objects react to forces?

Answers

Food is super good and the service was quick quick lol I was like I just got the food and I was

When one object applies a force to another, the second item responds by applying an equal and opposite force to the first.

What is force?

A force is an effect that can alter an object's motion according to physics. An object with mass can change its velocity, or accelerate, as a result of a force. An obvious way to describe force is as a push or a pull. A force is a vector quantity since it has both magnitude and direction.

An opposing force to an action force is referred to as a reaction force. The response force that results from surface engagement and adhesion while sliding is known as friction.

When one object applies a force to another, the second item responds by applying an equal and opposite force to the first.

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sleep and stress levels can be improved by what?

Answers

Answer:

A healthy diet, low in sugar, caffeine, and alcohol, can promote health and reduce stress.

Explanation:

A healthy diet, low in sugar, caffeine, and alcohol, can promote health and reduce stress. Get adequate sleep: A good night's sleep makes you able to tackle the day's stress more easily. When you are tired, you are less patient and more easily agitated, which can increase stress.

A roller coaster is traveling at 13 m/s when it approaches a hill that is 400 m long. Heading down the hill, it accelerates at 4.0 m/s2. What is the final velocity of the roller coaster? Round your answer to the nearest whole number.

m/s

Answers

Answer:

2as = v² - u²

v = √(2as + u²)

v = √(2 x 4 x 400 + 13²)

v = 58 m/s

Explanation:

Answer:

58

Explanation:

correct

Other than temperature, which property also has an effect on the rates of chemical reactions?
A.Color of reactants
B.Concentration of reactants
C.Solubility of reactants
D.Volume of reactants

Answers

Other than temperature, the property that also has an effect on the rates of chemical reactions is the concentration of the reactants. The correct answer is B

The rate of chemical reaction means how chemical react with respect to time or as a function of time. The rate of chemical reaction tells us the speed or how fast chemicals react.

There are many factors that can affect the rate of chemical reaction. Temperature is one of them. Increase in temperature will increase the rate at which chemical react.

The color of reactants, solubility of reactants and volume of reactants have nothing to do with the rate of chemical reaction.

Other than temperature, the property that also has an effect on the rates of chemical reactions is the concentration of the reactants.

Other factors affecting the rate of chemical reaction are:

the physical state of the reactants surface area temperature and the presence of a catalyst

Therefore, the correct answer is option B

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How to get the answer

How to get the answer

Answers

Fnet <F1+ F₂ because the net force will include the component of frictional force. Option C.

Forces are balanced when people on both sides of the rope are pulling the same amount in opposite directions. As a result, there is no motion. Balanced forces can cancel each other out. If the forces are balanced, the object will not move. When two forces act in the same direction, they add. Equal forces acting in opposite directions are called equilibrium forces.

Equilibrium forces acting on an object do not change the object's motion. Adding equal forces in opposite directions results in a net force of zero. Balanced forces acting on the same object, but in opposite directions. The net force due to these forces is zero. The sum of the magnitudes of the forces is also equal to the sum of the two forces acting in the same direction.

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________ occurs when the clutch does not fully disengage when the clutch pedal is depressed, causing a dragging of the clutch assembly. True or false?

Answers

The given statement, "Clutch dragging occurs when the clutch does not fully disengage when the clutch pedal is depressed, causing a dragging of the clutch assembly" is true.

This phenomenon is known as clutch dragging. Clutch dragging happens when the clutch disc doesn't fully release from the flywheel when the clutch pedal is depressed. In other words, the clutch's friction material remains in contact with the flywheel and pressure plate, causing friction, and making it difficult to shift gears, resulting in a dragging effect. Due to the drag, gears may grind during shifting, the clutch may slip or refuse to disengage, and the vehicle may lurch or stall when the engine is idling. If clutch dragging is not addressed quickly, it may result in harm to the transmission's gears. The most common cause of clutch dragging is a hydraulic or mechanical issue with the clutch linkage or hydraulic system, which prevents the clutch from disengaging entirely. A worn-out clutch plate or a distorted clutch disk may also cause dragging. Furthermore, clutch dragging may be caused by a malfunctioning flywheel, pressure plate, or clutch fork.

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The ball is about to hit the ground.

It has a kinetic energy store of 110 J.

Ignoring the effects of friction, what is the maximum elastic potential energy store of the ball when it is fully compressed after hitting the ground?​

Answers

The maximum elastic potential energy store of the ball when it is fully compressed after hitting the ground is 110 J

Since the effects of friction is ignored, there is no loss of energy as heat. So the entire elastic potential energy store of the ball is converted into kinetic energy store.

Elastic potential energy = Kinetic energy

Kinetic energy = 110 J

Elastic potential energy = 1 / 2 k x²

Kinetic energy = 1 / 2 m v²

k = Spring constant

x = Displacement

m = Mass

v = Velocity

If friction is ignored,

1 / 2 k x² = 1 / 2 m v²

v / x = √ ( k / m )

Therefore, the maximum elastic potential energy store of the ball is 110 J

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PROCEDURES/RESULTS: Task A. Decimal to BCD Encoder circuit (2.5 marks) 1. Connect the circuit of figure 1 using the 74147 IC (see IC pin configuration). +5V 11 16 2 12 9 401 16VCc 150 NC 13 512 613 14 D 1 B 704 130 3 Decimal inputs BCD outputs 85 120 2 7+147 2 Cis 1101 C 3 817 101 9 91 A 4 GND 8 5 9 10 붐 Figure 1: Decimal to BCD encoder circuit using 74147 IC and IC Pin Configurations (1.25marks) Table 1. Truth Table of Decimal to BCD encoder (1.25 marks) Active-Low Decimal Inputs 2 3 4 5 6 7 8 9 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 0 1 1 1 1 1 1 X 0 1 1 1 1 1 X X X 0 1 1 1 X X X X 0 1 1 X X X X X 0 1 1 X X X X X X 0 1 O X X X X X X X X 1 0 I Note: Numbers 1-9 are the inputs which are initially should be at 1 or HIGH (should be connected to +5VDC); 0 or LOW means input should be set into the OV or ground; X means don't care condition. The four outputs (A, B, C, and D) should be connected to the LED's. 1 1 0 X X X 1 0 X X X X X X 3 4 10 5 6 789 ? 1 1 1 1 A A 1 1 Active-Low BCD Outputs D C B A I 1 1 1 A 1 1 D 1 + ( 1 1 [0]. 0 0/0/0/0+ Glo 1 0-0 1 01 1 101-101
A 0 0 0 0 0 0 0 0 1 1 Task B. BCD to 7-Segment Decoder circuit (2.5 marks) +5VDC RI www R2 ww R3 A 16 13 www 12 B 11 R4 Common Anode 7447 or 7446 10 ww Common Cathode Ond RS 2 9 ww D 15 BEN 6 8 14 R7 ww 9 Figure 2: BCD to 7 segment decoder circait; decoder IC and 7 segment display pin configurations (1.25 marks) Table 2. Truth Table of BCD to 7 segment decoder (1.25 marks) BCD inputs Segments output D B C d a b С e 0 0 0 I T 1 ( 0 0 응 T C 0 0 1 1 1 1 0 0 ? H olc 0 1 1 0 0 1 1 0 0 0 1 0 1 0 1 0 O T 1 1 1 doo ( ( 1 1 b C O T GOO L O 1 D O 1 1 O 1 1 0 1 T 8.8. 1 lot G 1 ( 1 1 alali O DEO O 7 1 0 1 1 Numerical Output 1 3 4 S 61H0 7 8 9
2. The 74147 is an IC type where data inputs and outputs are active at a low logic this implied in the encoder circuit that you connected to that in Figure 17 (0.25 mark) L.. 14. -18~ we P 3. If all the inputs of 74147 IC are at logic "1", what is its equivalence in decimal numbers? In BCD numbers? (0.25 mark) Tim 4. What decoder IC is required for a common cathode and common anode seven segment display? (0.25 mark) 5. How will you connect a common anode and a common cathode seven segment display in the +5VDC power supply? (0.25 mark) 6. What is the purpose of the resistors at the output of the decoder IC before connecting it to the seven- segment display?

Answers

Resistors at the decoder IC's output limit current to protect the segments and IC from damage.

What is the purpose of the resistors at the output of the decoder IC before connecting it to the seven-segment display?

If all the inputs of the 74147 IC are at logic "1" (HIGH), its equivalence in decimal numbers is 9. In Binary-Coded Decimal (BCD) numbers, the binary representation of decimal 9 is 1001.

For a common cathode seven-segment display, you would require a BCD to 7-segment decoder IC such as the 7447. For a common anode seven-segment display, you would require a BCD to 7-segment decoder IC such as the 7446.

To connect a common anode seven-segment display to a +5VDC power supply, you would connect the common anode pin of the display to the +5VDC supply. The individual segment pins of the display would be connected to the outputs of the decoder IC.

To connect a common cathode seven-segment display to a +5VDC power supply, you would connect the common cathode pin of the display to ground (GND). The individual segment pins of the display would be connected to the outputs of the decoder IC.

The purpose of the resistors at the output of the decoder IC before connecting it to the seven-segment display is to limit the current flowing through the segments. The resistors help prevent excessive current that could damage the segments or the decoder IC.

The value of these resistors is typically chosen based on the specific requirements of the display and the decoder IC.

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two charges interact with 100 newtons attractive force initially. when their distance is increased by four times, what will be the force between them?

Answers

The force between the two charges will be 25k N m.

This can be determined by using Coulomb's Law, which is a formula relating the forces between two charges (q 1 and q 2 ) at a distance r apart. The formula states that their force is equal to kq1q2/r2, where k is a constant (9 × 109 N m2/C2). If we plug in the values of 100 newtons for each charge and 4 meters for their distance, we get:

F = 100k/(4 × 109) = 25k N m

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an air-filled capacitor consists of two parallel plates, each with an area of 7.60 cm2, separated by a distance of 1.70 mm. a 15.0-v potential difference is applied to these plates. (a) calculate the electric field between the plates.

Answers

The electric field between the plates of a capacitor can be calculated using the equation E = V/d, where E is the electric field, V is the potential difference, and d is the distance between the plates.

In this case, we are given the potential difference V = 15.0 V and the distance between the plates d = 1.70 mm = 0.0017 m. Plugging these values into the equation, we get:

E = V/d = (15.0 V)/(0.0017 m) = 8823.53 V/m

Therefore, the electric field between the plates of the capacitor is 8823.53 V/m.

To calculate the capacitance of the capacitor, we can use the equation C = ε₀A/d, where C is the capacitance, ε₀ is the permittivity of free space, A is the area of the plates, and d is the distance between the plates.

In this case, we are given the area of the plates A = 7.60 cm² = 7.60 x 10⁻⁴ m² and the distance between the plates d = 1.70 mm = 0.0017 m. The permittivity of free space ε₀ is a constant value of 8.85 x 10⁻¹² F/m. Plugging these values into the equation, we get:

C = ε₀A/d = (8.85 x 10⁻¹² F/m)(7.60 x 10⁻⁴ m²)/(0.0017 m) = 3.13 x 10⁻¹⁴ F

Therefore, the capacitance of the capacitor is 3.13 x 10⁻¹⁴ F.

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A helicopter of mass 3000KG rises vertically at a constant speed of 25m/s if the acceleration due to gravity is 10ms^-2, determine the resultant force working on the helicopter

Answers

Answer:

The resultant force working on the helicopter can be calculated using the formula:

Resultant force = mass x acceleration

We know that the mass of the helicopter is 3000 kg and the acceleration is the acceleration due to gravity, which is 10 m/s^2.

The force of lift that opposes the weight of the helicopter is equal to:

Resultant force = 3000 kg x (10 m/s^2 + 25 m/s^2)

Resultant force = 3000 kg x 35 m/s^2 = 105,000 N

So the resultant force working on the helicopter is 105,000 N, this is the force that the helicopter's engines need to exert to overcome the force of gravity and maintain its constant speed of 25m/s.

What happens to a circuit's resistance (R), voltage (V), and current (1) when
you change the thickness of the wire in the circuit?
A. V and I will also change, but R will remain constant.
B. R and I will also change, but V will remain constant.
O C. R, V, and I will all remain constant.
OD. R and V will also change, but I will remain constant.

Answers

When you change the thickness of the wire in a circuit, option B. the resistance (R) and current (I) will also change, but the voltage (V) will remain constant.

The resistance of a wire is directly proportional to its length and inversely proportional to its cross-sectional area (thickness). As the thickness of the wire changes, the cross-sectional area changes, which in turn affects the resistance. Thicker wires have a larger cross-sectional area, resulting in lower resistance, while thinner wires have a smaller cross-sectional area, resulting in higher resistance. Therefore, changing the thickness of the wire will cause a change in resistance.

According to Ohm's Law (V = IR), the voltage (V) in a circuit is equal to the product of the current (I) and the resistance (R). If the voltage is kept constant, and the resistance changes due to the thickness of the wire, the current will also change to maintain the relationship defined by Ohm's Law. When the resistance increases, the current decreases, and vice versa.

However, it's important to note that changing the thickness of the wire will not directly affect the voltage. The voltage in a circuit is determined by the power source or the potential difference applied across the circuit and is independent of the wire thickness. As long as the voltage source remains constant, the voltage across the circuit will remain constant regardless of the wire thickness. Therefore, the correct answer is option B.

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Specifications for a part for a 3-D printer state that the part should weigh between 24.7 and 25.7 ounces. The process that produces the parts has a mean of 25.2 ounces and a standard deviation of .20 ounce. The distribution of output is normal. Use Table-A.

a.What percentage of parts will not meet the weight specs? (Round your "z" value and final answer to 2 decimal places.)

b.Within what values will 99.74 percent of the sample means of this process fall if samples of n = 10 are taken and the process is in control (random)? (Round your answers to 2 decimal places.)

Answers

1.24% percentage of parts will not meet the weight specs amd the sample means will fall between 25.046 and 25.354 ounces.

a. To determine the percentage of parts that will not meet the weight specifications, we need to calculate the probability of a part weighing less than 24.7 ounces or more than 25.7 ounces. First, we need to calculate the z-scores for these values using the formula:

z = (x - μ) / σ

where x is the value, μ is the mean, and σ is the standard deviation. For 24.7 ounces:

z1 = (24.7 - 25.2) / 0.20 = -2.50

For 25.7 ounces:

z2 = (25.7 - 25.2) / 0.20 = 2.50

Using Table-A (Z-score table), we can find the area under the standard normal curve corresponding to these z-values. From the table, the area to the left of -2.50 is 0.0062, and the area to the right of 2.50 is also 0.0062. Therefore, the total probability of a part not meeting the weight specs is:

P(z < -2.50 or z > 2.50) = P(z < -2.50) + P(z > 2.50) = 0.0062 + 0.0062 = 0.0124

So, the percentage of parts that will not meet the weight specs is .

b. To determine the values within which 99.74% of the sample means will fall, we need to calculate the margin of error for a sample mean. The margin of error is given by the formula:

E = z * (σ / sqrt(n))

where E is the margin of error, z is the z-score corresponding to the desired level of confidence (in this case, 99.74% corresponds to a z-score of 2.75), σ is the standard deviation, and n is the sample size.

Plugging in the values:

E = 2.75 * (0.20 / sqrt(10)) ≈ 0.154

The range of sample means will be within ±E of the population mean. Therefore, the values within which 99.74% of the sample means will fall are:

25.2 ± 0.154 = (25.046, 25.354)

So, for samples of size 10, 99.74% of the sample means will fall between 25.046 and 25.354 ounces.

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A student is using a sound machine to produce the sound waves presented in the data table below. How could the student manipulate the sounds to make them match in pitch but make sound wave #1 louder than sound wave #2?

A student is using a sound machine to produce the sound waves presented in the data table below. How

Answers

Answer:  Make the frequency higher for number 1 and have the same amplitude.

Explanation: Wavelength and frequency are directly related so if you change one of those then you can't keep the other one the same. You would need to raise the frequency which would make 1 louder and keep amplitude the same for both so that 1 is louder.

To make the sounds match in pitch while making sound wave 1 louder than sound wave 2 : Increase the frequency for wave #1 while setting their amplitudes at the same value

The wavelength of a sound wave is inversely proportional to its frequency therefore when the frequency of wave 1 is increased its wavelength decreases with equal proportion.

Since the increase in frequency results to a decrease in wavelength. therefore to make wave 1 louder, both waves we will have to set the amplitude values of the waves at the same amplitude.

Hence we can conclude that to make the sounds match in pitch while making sound wave 1 louder than sound wave 2 ; Increase the frequency for wave #1 while setting their amplitudes at the same value.

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A student is using a sound machine to produce the sound waves presented in the data table below. How

a bus starts with a speed 15 metre per second then how much time does it take to complete 15 km

pls pls help ​

Answers

first, you can convert 15 km to metres, which would be 15000 metres

then, divide 15000 metres by 15 metres per second to find the time: 15000/15 = 1000 seconds

final answer: 1000 seconds

Answer:

1000 seconds

Explanation:

1km is equivalent to 1000meters

15km to 15000meters

Time=Distance/Speed

15000meter/15 meter per second =1000 seconds

18. A vertical spring has a length of 25cm when a 150g mass is hung from its end and its length is 30cm with 250g hanging from it. What is the spring constant? a) 19.6N/cm b) 19.6n/m c) 109.6N/m d) 19.6N/m e) 19.6N/km​

Answers

The spring constant of the spring is 19.6 N/m.

The correct answer is option D.

What is the spring constant of the spring?

The spring constant of the spring is calculated by applying the following equation as shown below.

Mathematically, the formula of Hooke's law is given as;

F = kx

where;

F is the applied forcek is the spring constantx is the extension of the spring

k = F / x

the extension of the spring when the 250 g mass was hung on it is calculated as;

x = 30 cm - 25 cm

x = 5 cm = 0.05 m

The spring constant of the spring is calculated as;

k = ( mg ) / x

where;

m is the additional mass = 250 g - 150 g = 100 g

k = ( 0.1 x 9.8 ) / ( 0.05 )

k = 19.6 N/m

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Complete the following sentence: How much you pay in taxes depends on _________________________.

Answers

Answer:

How much you pay in taxes depends on the amount of your taxable income

Explanation:

The total amount expected to be payed as taxes is a factor of the amount of taxable income earned within the given tax period.

The taxable income is found by subtracting the amount of deductions and exemption allowed in the tax year from the gross income. It is also specified as the adjusted gross income

The set marginal  tax rate indicates the percentage of the taxable income that is to be paid as taxes, such that there are three different ranges or tax brackets and taxes are paid according to the bracket to which a taxable income belongs.

1. What force is necessary to stretch an ideal spring with a spring constant of 125 N/m by
35 cm?

2. A spring with a spring constant of 650. N/m is used for a scale to weigh fish. What is the mass of a fish that would stretch the spring by 7.55 cm from its normal length?

3. A spring in a pogo-stick is compressed 16cm when a 43kg girl stands on it. What is the spring constant for the pogo-stick spring?

4. A spring is connected to a wall and a horizontal force of 80.0 N is applied. It stretches 28cm, what is its spring constant?

5. A spring stretches 8.0 cm when a 16 N force is applied. How far does it stretch when a 23 N is applied?

6. A 7.3 kg mass is placed on a spring with a spring constant of 36 N/cm. How much does this stretch the spring?

7. An elastic cord is 80cm long when it is supporting a mass of 15. kg hanging from it at rest. When an additional 5.0 kg is added, the cord is 82.5 cm long. What is the spring
constant?

8. What is the original length of the cord (with no mass) in question 7?

9. A spring with a spring constant of 50. N/m is hanging from a stand. A second spring with a spring constant of 100. N/m is hanging from the first spring. How far do they stretch if a 0.58 kg is hung from the bottom spring?

10. What is the spring constant of the system of springs in question 9?


please help , your help will be highly appreciated:)

Answers

A perfect spring with a spring constant of 125 N/m requires 437.5 N to extend it by 35 cm.

How much is the spring constant?

The force that insists on extending or compressing a spring, divided by the area where the spring lengthens or shortens, is the spring constant.

What, using an example, is spring force?

A metal spring is moved from its equilibrium position when it is stretched or compressed. As a result, it encounters a restoring Force that usually causes the spring to retract back to its initial position. The spring force is the name of the force. It is a force of contact that exists in elastic materials.

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A bowling ball has a mass of 7. 2 kg and a weight of 70. 6 N. It moves down the bowling alley at 1 m/s and strikes a pin with a force of 15. 0 N. What is the force that the pin exerts on the bowling ball? 7. 2 N 15. 0 N 70. 6 N 85. 6 N.

Answers

The correct answer is option B

If a bowling ball has a mass of 7. 2 kg and a weight of 70. 6 N. It moves down the bowling alley at 1 m/s and strikes a pin with a force of 15. 0 N. The force that the pin exerts on the bowling ball is 15.0 N.

This is because the force of the ball hitting the pin (15.0 N) is equal and opposite to the force of the pin hitting the ball. The mass and weight of the bowling ball are not relevant to this calculation.

The force that the pin exerts on the bowling ball can be determined using Newton's third law of motion, which states that every action has an equal and opposite reaction. Since the bowling ball strikes the pin with a force of 15.0 N, the pin exerts an equal and opposite force on the bowling ball.

Therefore, the force that the pin exerts on the bowling ball is also 15.0 N. The mass and weight of the bowling ball (7.2 kg and 70.6 N, respectively) are not directly related to the force exerted by the pin on the ball.

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At today's market value, how much gold is dissolved in the ocean?

Answers

Based on the current gold spot price of $42.51 USD per gram, that amount of gold would be worth approximately $771 trillion.

When we compare that to the 2016 US Gross Domestic Product (GDP) of 18.57 trillion and its 41 times. It can also be compare to global domestic product of $78.28 trillion in 2014, which is nearly 10 times the entire world's domestic product.

We can clearly see that world's oceans contain a lot of money in terms of the gold inside it. The enormous process of extracting the gold from enormous quantities of seawater, however is tedious. There would be about 13 billionths of a gram of gold in each liter of water.

There is currently no profitable way to extract the gold from seawater that is also cost-effective. Nevertheless, many enthusiastic investors and inventors, including dishonest ones, persisted. In a fever dream in the 1890s, preacher Ford Jernegan came up with the idea for a "Gold Accumulator." The idea was to use a procedure using mercury and electricity treatments to remove gold from the Long Island Sound.

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A cube is located with one corner at the origin of an x,y,z coordinate system. One of the cube's face lies in the x,y plane, another in the y,z plane, and another in the x,z plane/ In other words, the cube is in the first octant of the coordinate system. The edges of the cube are 0.20m long. A uniform electric field is parallel to the x,y plane and points in the direction of the +y axis. The magnitude of the field is 1500 N/C. Find the electric flux through each of the six faces of the cube. (b) Add the six values obtained in the part to show that the electric flux through the cubical surface is zero, as Gauss' law predicts, since there is no net charge within the cube.

Answers

a. The electric flux through each of the six faces of the cube is zero.

To answer this question, we must use Gauss' Law.

The electric flux is calculated as follows:

The electric flux through the face in the x,y plane is E*A = (1500 N/C)*(0.20m)2 = 600 Nm2/C.The electric flux through the face in the y,z plane is E*A = (1500 N/C)*(0.20m)2 = 600 Nm2/C.The electric flux through the face in the x,z plane is E*A = (1500 N/C)*(0.20m)2 = 600 Nm2/C.The electric flux through the face in the -y axis is E*A = (-1500 N/C)*(0.20m)2 = -600 Nm2/C.The electric flux through the face in the -x axis is E*A = (-1500 N/C)*(0.20m)2 = -600 Nm2/C.The electric flux through the face in the -z axis is E*A = (-1500 N/C)*(0.20m)2 = -600 Nm2/C.


Adding all of these values together, we see that the electric flux through the cubical surface is zero,

as Gauss' Law predicts, since there is no net charge within the cube.

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If at some point along the straight line directly between two charges the strength of the electric field at that point is found to be zero what can we say for sure about those two charges?.

Answers

Answer: The charges must be like charges (both positive or both negative).

Explanation:

what is the density rhoh of hot air inside the balloon? assume that this density is uniform throughout the balloon. express the density in terms of th , tc , and rhoc .

Answers

The density (ρh) of hot air inside the balloon, assuming it is uniform throughout, can be expressed in terms of Th, Tc  and ρc (density of surrounding air) using the ideal gas law as follows: ρh = (ρc * Tc) / Th

The ideal gas law states that for a given amount of gas, the product of its pressure (P) and volume (V) is proportional to the product of its temperature (T) and the number of moles (n). Mathematically, it can be expressed as:

PV = nRT

Where R is the ideal gas constant.

Since we are considering a balloon filled with hot air, the pressure and volume inside the balloon remain constant. Therefore, we can modify the ideal gas law to relate the densities of hot air (ρh) and surrounding air (ρc) to their respective temperatures:

(ρh * V) / Th = (ρc * V) / Tc

Here, V represents the volume of the balloon, which cancels out on both sides of the equation.

Simplifying the equation:

ρh / Th = ρc / Tc

Rearranging the equation to solve for ρh:

ρh = (ρc * Tc) / Th

The density (ρh) of hot air inside the balloon, assuming it is uniform throughout, can be calculated using the ideal gas law. The expression for ρh in terms of Th (temperature of hot air), Tc (temperature of surrounding air), and ρc (density of surrounding air) is given as: ρh = (ρc * Tc) / Th.

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Which country features the largest scale model of the solar system?.

Answers

The Sweden

___________

The Sweden Solar System is the world's largest permanent scale model of the Solar System. The Sun is represented by the Avicii Arena in Stockholm, the largest hemispherical building in the world.

when the syringe volume is cut in half, the presure changes by more than a factor of 2. why does it momentarily spike at a significantly higher pressure

Answers

When the volume of a syringe is cut in half, the pressure inside the syringe increases. This is because the same amount of gas or liquid is now compressed into a smaller space, resulting in a higher concentration of molecules. This increase in pressure is proportional to the decrease in volume and can be calculated using Boyle's law.

However, when the plunger of the syringe is rapidly pushed in, the pressure inside the syringe momentarily spikes at a significantly higher pressure than predicted by Boyle's law. This is due to the inertia of the fluid inside the syringe. As the plunger is rapidly pushed in, the fluid has a tendency to keep moving at the same speed, causing it to compress and generate a higher pressure than expected. This effect is temporary and quickly dissipates as the fluid comes to a stop.

In summary, when the volume of a syringe is cut in half, the pressure inside increases proportionally to the decrease in volume. When the plunger is rapidly pushed in, the pressure momentarily spikes due to the inertia of the fluid. Understanding these principles is important for accurate dosing and safe use of syringes in medical and laboratory settings.

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