A force of 100 newtons was necessary to lift a tree. A total of 50 joules of work was done. How far was the tree lifted

Answer:

The naturally acidic rain will gradually wear the mountain of limestone away.

Hope it helps!

The rate constant of the second-order reaction is 0.111 M^-1 min^-1.

The given data represents a second-order reaction where the rate of the reaction is proportional to the square of the concentration of A.

The integrated form of the second-order reaction is:

1/[A]t = kt + 1/[A]0

where [A]t and [A]0 are the concentrations of reactant A at time t and time zero, respectively, k is the rate constant.

We can use the given information to calculate the rate constant (k) of the reaction for the given half-life (t1/2) of 3.15 minutes:

t1/2 = (1 / k[A]0)

Using the percentage decrease in concentration and the given initial concentration, we can calculate the concentration of A at time t:

[A]t = [A]0 - 0.30[A]0 = 0.57126 M

Substituting the given values, we get:

3.15 min = (1 / k)(0.0818 M) / (0.0818 M - 0.57126 M)

Simplifying the equation above, we can solve for k:

k = 0.111 M^-1 min^-1

Therefore, the rate constant of the second-order reaction is 0.111 M^-1 min^-1.

For such more questions on constant

https://brainly.com/question/3159758

#SPJ11

Answer:  **

H-N-H

   |

  H

Explanation:

Look at a periodic table to determine how many electrons you need to account for. Hydrogen (H) only has 1 electron, while Nitrogen (N) has 5. We have three Hydrogen atoms and one Nitrogen atom, so the total number of electrons will be 3 * 1 + 5 = 8 e-.

Now, place the center atom, which will be Nitrogen and place the three Hydrogens on three sides of it as above in the answer. You should use single bonds for this. Each single bond is a pair of electrons, so since we have three single bonds so far, we have accounted for 2 * 3 = 6 electrons. However, we need 2 more electrons for the total of 8. We put these electrons in as a lone pair above Nitrogen.

We check to see if everything follows the octet rule: Nitrogen has three single bonds, so that's 6 e-, as well as one lone pair, so that's another 2 e- for a total of 8 e-. Check. Now look at Hydrogen: H is the only element whose full orbital is 2 e-. Each H has a single bond with Nitrogen, so each does have 2 e-.

Thus, we know this is the correct diagram, and we are done.

Explanation:

A bond line structure of a compound has H N H in linear plane and a hydrogen is branching upward, and the compound is H N (H) H. The nitrogen has two dots at its bottom represents a lone pair of electrons. So ,the correct answer is option C.

The correct Lewis structure for ammonia (\(NH_3\)) is option C. It shows a bond line structure with three hydrogen atoms (H) bonded to a central nitrogen atom (N) in a linear plane.

One hydrogen atom branches upward from the plane. Additionally, the nitrogen atom in this structure has two dots at its bottom, indicating a lone pair of electrons. This arrangement follows the octet rule, as nitrogen has formed three covalent bonds with hydrogen, completing its valence shell. The lone pair on nitrogen gives ammonia its characteristic properties.

Thus, option C accurately represents the Lewis structure of ammonia, showing the bonding and lone pair arrangement of its atoms.

To know more about bond line structure:-

https://brainly.com/question/30639285

Answer: -354.78 kJ of energy would be released for a given amount.

Explanation:

The number of moles is defined as the ratio of the mass of a substance to its molar mass.

The equation used is:

\(\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}\)     ......(1)

For Zinc:

Mass of zinc = 50.0 g

Molar mass of zinc = 65.38 g/mol

Plugging values in equation 1:

\(\text{Moles of Zn}=\frac{50.0g}{65.38g/mol}=0.765mol\)

For oxygen gas:

Mass of oxygen gas = 30.0 g

Molar mass of oxygen gas = 32 g/mol

Plugging values in equation 1:

\(\text{Moles of }O_2=\frac{30.0g}{32g/mol}=0.9375mol\)

The chemical equation follows:

\(2ZnS(s)+3O_2(g)\rightarrow 2ZnO(s)+2SO_2(g);\Delta H=-927.54kJ\)

By the stoichiometry of the reaction:

If 2 moles of zinc reacts with 3 moles of oxygen gas

So, 0.765 moles of zinc will react with = \(\frac{3}{2}\times 0.765=0.51mol\) of oxygen gas

As the given amount of oxygen gas is more than the required amount. Thus, it is present in excess and is considered as an excess reagent.

Thus, Zn is considered a limiting reagent because it limits the formation of the product.

By the stoichiometry of the reaction:

If 2 moles of zinc are releasing 927.54 kJ of energy

So, 0.765 moles of zinc will react with = \(\frac{927.54}{2}\times 0.765=354.78kJ\) of energy

Hence, -354.78 kJ of energy would be released for a given amount.

Answer:

yep C is correct!!

Explanation:

Answer:

The true statement concerning visible light and electromagnetic radiation is considered to be - d. Visible light is a small portion of the electromagnetic spectrum.

The electromagnetic spectrum is the range of frequencies of electromagnetic waves or radiations. This spectrum also gives an idea about the wavelengths of electromagnetic radiations. The part of the spectrum on their higher to lower energy or frequency range from  Hz to  Hz are:

gamma rays

X-rays

ultraviolet radiation

visible light

infrared radiation

radio waves.

The visible light is the very small part of the electromagnetic spectrum that ranges from the to, Visible light is the light that the human eye can see.

Thus, the correct answer is- option d.

Learn more about visible light:

Explanation:

i did this

The partial pressure of F2 and a mixture of gases where the total pressure is one atm. The mole fraction of F2 is 0.394736.

The term mole fraction is defined as the number of molecules of a component in a mixture is divided by the total number of moles in the given mixture.

Total pressure = 1 atm

= 760 torr

Then,

The partial pressure of F2 = 300 torr

The mol fraction of F2 = PF2/PT

= 300/760

= 0.394736

Thus, The partial pressure of F2 and a mixture of gases where the total pressure is one atm. The mole fraction of F2 is 0.394736.

To learn more about the mole fraction, follow the link;

https://brainly.com/question/8076655

#SPJ1

Answer:

C. Scientists accepted the model at first but later rejected it.  

Explanation:

Scientists accepted the model at first because it explained the hydrogen emission spectrum.

However, with the development of quantum mechanics, scientists had to modify the model (not reject it).

Electrons still had specific energies, but they no longer travelled in fixed orbits.

Instead, electrons had a probability of being found in a given region of space.

Scientists accepted the model at first but later rejected it.

Niels Bohr change the atomic theory by realizing that the electrons did not crash into the nucleus as would be expected in classical physics. Classical physics says that opposites attract and like to repel, so the negative electrons should be attracted to the positive nucleus.

In 1913, Niels Bohr proposed a theory for the hydrogen atom, based on quantum theory that some physical quantities only take discrete values. Electrons move around a nucleus, but only in prescribed orbits, and If electrons jump to a lower-energy orbit, the difference is sent out as radiation.

Learn more about Niels Bohr here https://brainly.com/question/1402660

#SPJ2

The number of volume of the oxygen that would be consumed is 2.8 L.

Let us recall that what we have here is the process of the use of the stoichiometry of the reaction so as to be able to obtain the mass and the volume of the reactants that are taking place in the reaction as we are going to have in the case that is at hand.

What we now need to do so that we can be able to use the stoichiometry of the reaction would just be to write down the equation of the reaction and this is going to give us the reaction; \(2Mg(s) + O_{2} (g) ---- > 2MgO\).

In this case we know that;

Number of moles of the magnesium = 6g/24 g/mol

= 0.25 moles

Now we know that;

If 2 moles of the magnesium reacts with 1 mole of the oxygen then

0.25 moles of the magnesium would react with 0.25 * 1 /2

= 0.125 moles

Volume of oxygen that is consumed is; 0.125 moles * 22.4 L
=2.8 L

Learn more about moles:https://brainly.com/question/26416088

#SPJ1

Answer:

Concentrated solutions

Answer:

81%

Explanation:

Answer: D. Repeat the experiment to confirm the results

Answer:

D

Explanation:

Answer:

there is one atom of oxygen and two atoms of hydrogen

Explanation:

Answer:

See answer below

Explanation:

In this case, I will put the original photo of this exercise, because we are missing one data. The first picture is the original exercise.

Now, according to this, we need to make a serial dilution of CO(NO₃)₂. We don't know the volume of this solution, but we do know the total volume of the preparing solution (In the picture states that the total volume will be 10 mL).

So, we know the final volume of the solutions to be prepared, so, le'ts use the expression that will help us to solve this:

C₁V₁ = C₂V₂

Where:

C₁: Concentration of the given solution (stock)

V₁: volume required to prepare the dilluted solution

C₂; Concentration of the dilluted solution

V₂: Total volume of the dilluted solution.

Now that we know the expression to use and the meaning of each value, let's prepare the solutions:

To prepare 10 mL of 0.1 M using a 0.25 M, we will replace these values in the above expression; from there, we will solve for V₁, that value will tell us the required volume to prepare solution 2, and then, by difference we can calculate the volume of water:

Volume of water (Vw) =V₂ - V₁  

Now replacing the values:

0.25V₁ = 0.1 * 10

V₁ = 1/0.25 = 4 mL

This means that we need 4 mL of the stock to prepare the 0.1 M of dilluted solution, therefore, the volume of water required is:

Vw = 10 - 4

Using these same steps for the other two solutions we will get V1 and V2 for both of them. In this case, I will go straight to the procedure without further explanation because it's the same of this one.

For solution 2:

0.1V₁ = 0.05 * 10

V₁ = 0.5/0.1

Vw = 10 - 5

Finally for solution 3:

V₁ = 0.01 * 10 / 0.05

Vw = 10 - 2 mL

Hope this helps

Answer:

product

Explanation:

its the result of the reaction.

Answer:

The correct answer is - one carbon atom and two oxygen atoms.

Explanation:

Carbon dioxide is a gas that is present in the atmosphere of the earth. The chemical formula of carbon dioxide is CO₂. In this colorless gas, there is one molecule of carbon dioxide is made up of one atom of carbon covalently double bonded to the two atoms of the oxygens.

Thus, the make- up of a carbon dioxide molecule (CO2) includes one carbon atom and two oxygen atoms.

Answer:Favorable

Explanation:um I know That it is Favorable sorry!

Answer:

This question is incomplete. A fragment of the question is missing. The fragment is:

She finds that 4.87 g of oxygen gas is produced

0.152 moles

Explanation:

Using the formula: mole = mass / molar mass

According to the question, a chemist measures the amount of oxygen gas produced during an experiment. Oxygen gas has the chemical formula: O2. Hence, the molar mass will be:

O2 = 16(2) = 32g/mol

If the mass of the oxygen gas to be 4.87 g of oxygen gas.

Therefore,

moles = 4.87/32

moles = 0.152mol

Answer:

6.25 g

Explanation:

From the question given above, the following data were obtained:

Half-life (t½) = 68.8 years

Time (t) = 344 years

Original amount (N₀) = 200 g

Amount remaining (N) =?

Next, we shall determine the number of half-lives that has elapsed. This can be obtained as follow:

Half-life (t½) = 68.8 years

Time (t) = 344 years

Number of half-lives (n) =

n = t / t½

n = 344 / 68.8

n = 5

Thus, 5 half-lives has elapsed.

Finally, we shall determine the amount of the Uranium-232 that remains. This can be obtained as follow:

Original amount (N₀) = 200 g

Number of half-lives (n) = 5

Amount remaining (N) =?

N = 1/2ⁿ × N₀

N = 1/2⁵ × 200

N = 1/32 × 200

N = 200 / 32

N = 6.25 g

Thus, the amount of Uranium-232 that remains is 6.25 g

Answer: Thus the final temperature for both the mercury and the water is \(28.8^0C\)

Explanation:

The quantity of heat required to raise the temperature of a substance by one degree Celsius is called the specific heat capacity.

\(heat_{released}=heat_{absorbed}\)

\(Q=m\times c\times \Delta T=m\times c\times (T_{final}-T_{initial})\)

\(-[m_1\times c_1\times (T_{final}-T_1)]=[m_2\times c_2\times (T_{final}-T_2)]\)

Q = heat absorbed or released

\(m_1\) = mass of mercury= 452 g

\(m_2\)= mass of water = 145 g

\(T_{final}\)  = final temperature = ?

\(T_1\)   = temperature of mercury = \(85.0^0C\)

\(T_2\) = temperature of water = \(23.0^0C\)

\(c_1\)   = specific heat of mercury  = \(0.138J/g^0C\)

\(c_2\)   = specific heat of water= \(4.184J/g^0C\)

Now put all the given values in equation (1), we get

\(-[452\times 0.138\times (T_f-85.0)^0C]=145\times 4.184\times (T_f-23.0)^0C\)

\(T_f=28.8^0C\)

Thus the final temperature for both the mercury and the water is \(28.8^0C\)

Answer:

.063 moles Cl-

Explanation:

To find moles multiply molarity by volume.

1.4*.045=.063 moles Cl-

Answer:

The heat Q transferred to cause a temperature change depends on the magnitude of the temperature change, the mass of the system, and the substance and phase involved. (a) The amount of heat transferred is directly proportional to the temperature change.

Hope it helps, BE SAFE! :3

Answer:

Explanation:

Here, we want to calculate the molarity of the calcium hydroxide solution

We start by writing the equation of reaction:

Now, we proceed to write the standardization equation:

where:

Ca is the molarity of the acid which is 0.02 M

Va is the volume of the acid which is 24.6 mL

Cb is the molarity of the base which is what we want to calculate

Vb is the volume of the base which is 35.3 mL

na is the number of moles of the acid in the balanced equation which is 2

nb is the number of moles of the base in the balanced equation which is 1

Substituting the values, we have:

Answer:

10.5%

Explanation:

The equation used to calculate mass percent by volume is:

                                        Mass Solute (g)
Mass/Volume %  =  -----------------------------------  x  100%
                                   Volume Solution (mL)

In this case, the solute is the glucose. You can plug the given values into the equation and solve.

                                      34.1 g C₆H₁₂O₆
Mass/Volume %  =  -------------------------------  x  100%
                                        325 mL soln

Mass/Volume %   =  0.105 x 100%

Mass/Volume %  =  10.5%

Answer:

The concentration of the nitric acid (HNO3) solution is 72 M.

Explanation:

To determine the concentration of the nitric acid solution, we can use the concept of stoichiometry and the equation of the neutralization reaction between nitric acid (HNO3) and sodium hydroxide (NaOH):

HNO3 + NaOH → NaNO3 + H2O

The balanced equation shows that the molar ratio between HNO3 and NaOH is 1:1. This means that 1 mole of HNO3 reacts with 1 mole of NaOH.

Given:

Volume of HNO3 solution = 10.0 ml

Volume of NaOH solution = 3.6 ml

Molarity of NaOH solution = 0.2 M

To find the concentration of the HNO3 solution, we need to calculate the number of moles of NaOH used in the neutralization reaction:

moles of NaOH = volume of NaOH solution * molarity of NaOH solution

= 3.6 ml * 0.2 M

= 0.72 mmol (millimoles)

Since the molar ratio between HNO3 and NaOH is 1:1, the number of moles of HNO3 in the solution is also 0.72 mmol.

Now, we can calculate the concentration of the HNO3 solution using the formula:

concentration (in M) = moles of solute / volume of solution (in L)

concentration = 0.72 mmol / 0.010 L

= 72 mmol/L

= 72 M

Therefore, the concentration of the nitric acid (HNO3) solution is 72 M.

Answer:

17 reactions

Explanation:

Answer:

Explanation:

If a zero is found between significant digits, it is significant

Answer:

\(0.060molH_2O\)

Explanation:

Hello there!

In this case, since the chemical reaction between ethanol and oxygen to water and acetic acid is:

\(CH_3CH_2OH+O_2\rightarrow CH_3COOH+H_2O\)

Thus, since there is a 1:1 mole ratio between oxygen and water, the produced moles of water are calculated down below:

\(0.060molO_2*\frac{1molH_2O}{1molO_2}=0.060molH_2O\)

Best regards!