a force f is applied to a cylindrical steel cable of diameter 3.5 mm and length 10.0 m. determine the value of f if the change in length of the cable is 7.8 mm. ysteel

Answer:

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The two network management tools are Datadog and Zabbix.

Datadog

The application topology and interdependencies are well visualized, and Datadog assists in automatically monitoring and analyzing network traffic between the application's component parts. It is simple to access the metrics' past. It is easy to manage the downtime for different resources.

Zabbix

Zabbix can keep an eye on servers, networks, databases, and websites. The zabbix interface is absolutely fantastic. The team can monitor only the things that are important to them using the customized dashboards. aids in the production of reports on the network assets' performance. Monitoring connection availability is beneficial.

What are disadvantages of Datadog and Zabbix?

Datadog

A faster method of removing the resources from datadog would be preferable. Training is more expensive. There is a lack of documentation in some setup-related areas. Customization is valued over simplicity.

Zabbix

Reports that are already created can also be updated. Being open source does not imply that something is free. Overall, the UI is functional, not necessarily attractive. Increase the number of triggers that can be configured The user interface is now slightly more tidy. The process is a little bit lighter as a result.

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It is motor oil, as oil is used to reduce friction

The ratio of shear strength of the clay in vertical direction to that in horizontal direction is 1.41.

The force that can cause an object to rotate along an axis is measured as torque. Similar to how force accelerates an item in linear kinematics, torque accelerates an object in an angular direction.

The apparent shear stress of the soil can be calculated using the following formula:

τ = T/(2πLW)

Where τ is the apparent shear stress, T is the torque at failure, L is the length of the vane, and W is the width of the vane.

For the first test with the vane of length 150mm and diameter 60mm:

τ1 = 46/(2π × 0.15 × 0.06) = 666.67 kPa

For the second test with the vane of length 200mm and diameter 90mm:

τ2 = 138/(2π × 0.2 × 0.09) = 402.23 kPa

To calculate the ratio of shear strength of the clay in vertical direction to that in horizontal direction, we can use the formula:

tan φ = (τv - σ)/τh

Where φ is the angle of internal friction, τv is the shear strength in the vertical direction, τh is the shear strength in the horizontal direction, and σ is the normal stress.

Assuming that the normal stress is the same in both directions, we can rearrange the formula to get:

τv/τh = tan φ + 1

To find the angle of internal friction, we can use the average of the two apparent shear stresses:

φ = (1/2) × arctan((τ1/2 + τ2/2)/σ) = (1/2) × arctan((534.45 + 333.33)/σ)

Assuming a normal stress of 100 kPa, we get:

φ = (1/2) × arctan(867.78/100) = 21.16°

Substituting this value into the formula for the ratio of shear strength, we get:

τv/τh = tan(21.16°) + 1 = 1.41

Therefore, 1.41 the ratio of shear strength of the clay in vertical direction to that in horizontal direction.

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Answer:

a) C1 = 3C2

b) C1 = 1 , C2 = -3  

c) \(w = \frac{-x^2}{2} + \frac{y^2}{2} + 3xy + C\)

d) (v.v)T = 0

Explanation:

u = 3x + C1y

v = x + C2y

A) determining all  stagnation points

At The stagnation points : u = 0, v = 0

for all  values of C1 and C2 , C1 = 3C2

B) The coefficients of C1 and C2 so that the flow is potential

C1 = 1 , C2 = -3  

C) Determine the expression of the stream function

\(w = \frac{-x^2}{2} +\frac{y^2}{2} +3xy+ C\)

D) The value of (v.v)T at the point (x,y) = (1,2)

(v.v)T = 0

Attached is the detailed solution

Label the steps involved in producing energy in this illustration of a coal-fired power plant in a clockwise direction.

1). Firstly, the furnace burns coal.

2). Heat from burning causes water to boil.

3). Steam drives the turbine.

4). In order to produce current, magnets are moved past copper coils.

5). Condensed steam is cooled.

6). Filters are used to remove air contaminants.

7). Toxic ash is transported to a disposal facility for hazardous waste.

Energy is the ability to conduct work in physics. It may exist in potential, kinetic, thermal, electrical, chemical, nuclear, or other forms. Additionally, there is heat and work, which is energy moving from one body to another. Energy is always identified in accordance with its nature once it has been transferred. Therefore, the heat transported may manifest as thermal energy while work performed may result in mechanical energy.

Motion is a property of all energies. Anybody in motion, for instance, possesses kinetic energy. Even while at rest, a tensioned object like a spring or bow has the capacity to move; this is because of the way it is built.

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Answer:

The flux (volume of water per unit time) through the hoop will also double.

Explanation:

The flux = volume of water per unit time = flow rate of water through the hoop.

The Flow rate of water through the hoop is proportional to the area of the hoop, and the velocity of the water through the hoop.

This means that

Flow rate = AV

where A is the area of the hoop

V is the velocity of the water through the hoop

This flow rate = volume of water per unit time = Δv/Δt =Q

From all the above statements, we can say

Q = AV

From the equation, if we double the area, and the velocity of the stream of water through the hoop does not change, then, the volume of water per unit time will also double or we can say increases by a factor of 2

Answer:

Tack coat is a sprayed application of an asphalt binder upon an existing asphalt or Portland cement concrete pavement prior to an overlay, or between layers of new asphalt concrete.

Explanation:

Answer:

Option B, qualification-based selection

Explanation:

Whenever bidding is done for seeking professional services, selection of contractor should be done using qualifications-based selection.

While seeking professional service, focus is on selecting the best quality and value matter, hence the contracting agency with best experience and skill for the job is selected.

Answer:

Explanation:

Considering the flow of mercury in a tube:

When it comes to laminar flow of mercury, the thermal entry length is quite smaller than the hydrodynamic entry length.

Also, the hydrodynamic and thermal entry lengths which is given as DLhRe05.0= for the case of laminar flow. It should be noted however, that Pr << 1 for liquid metals, and thus making the thermal entry length is smaller than the hydrodynamic entry length in laminar flow, like I'd stated in the previous paragraph

Answer:

1.2 Newtons upwards

Explanation:

because the friction is opposite of the magnitude.

Complete Question

Complete Question is attached below.

Answer:

\(V'=5m/s\)

Explanation:

From the question we are told that:

Diameter \(d=0.10m\)

Power \(P=4.0kW\)

Head loss \(\mu=10m\)

 \(\frac{P_1}{\rho g}+\frac{V_1^2}{2g}+Z_1+H_m=\frac{P_2}{\rho g}+\frac{V_2^2}{2g}+Z_2+\mu\)

 \(\frac{300*10^3}{\rho g}+35+Hm=\frac{500*10^3}{\rho g}+15+10\)

 \(H_m=(\frac{200*10^3}{1000*9.8}-10)\)

 \(H_m=10.39m\)

Generally the equation for Power is mathematically given by

 \(P=\rho gQH_m\)

Therefore

 \(Q=\frac{P}{\rho g H_m}\)

 \(Q=\frac{4*10^4}{1000*9.81*10.9}\)

 \(Q=0.03935m^3/sec\)

Since

 \(Q=AV'\)

Where

 \(A=\pi r^2\\A=3.142 (0.05)^2\)

 \(A=7.85*10^{-3}\)

Therefore

 \(V'=\frac{0.03935m^3/sec}{7.85*10^{-3}}\)

 \(V'=5m/s\)

Answer

TL/TH- TL

Because we know that power coefficient is. = QL/QH-QL

=so using this for performance we have

=>Perf= TL/(TH-TL)

Answer:

A = 1.41 m²

Explanation:

The ara can be found out by using Stefan Boltzman Law:

\(P = \sigma AT^4\)

where,

A = Area = ?

P = Radiation Power = 1200 W

σ = Stefan Boltzman Constant = 5.6703 x 10⁻⁸ W/m².k⁴

T = surface temperature = 350 k

Therefore:

\(1200\ W = (5.6703\ x\ 10^{-8}W/m^2.k^4)(A)(350\ k)^4\\\\A = \frac{1200\ W}{850.9\ W/m^2}\)

A = 1.41 m²

Answer:

I hope it helps :)

Explanation:

It is useful to measure Height and Arm Span in tennis players. Body fat can be measured using the skinfold method. If this is not available, monitoring body weight changes would give an indication of body fat changes, assuming no

The convective heat flux is 80 W/m², demonstrating heat exchange due to convection, whereas the radiative heat flux is around -0.111 W/m², showing heat misfortune through radiation.

To decide the convective and radiative heat fluxes to the divider at x = 0, able to utilize the following equations:

Convective heat flux (qconv) = h * (Ts - Ta)

Radiative heat flux (qrad) = ε * σ * (Ts^4 - Tsurr^4)

Given the values given:

Surrounding temperature (Ta) = 20°C

Encompassing temperature (Tsurr) = 40°C

Convection warm exchange coefficient (h) = 20 W/m²K

Absorptivity of the uncovered surface (a) = 0.78

Surface temperature (Ts) = 24°C

Stefan-Boltzmann steady (σ) = 5.67 × 10^-8 W/m²K^4

Substituting these values into the equations, we will calculate the convective and radiative heat fluxes:

qconv = 20 * (24 - 20) = 80 W/m²

qrad = 0.78 * 5.67 × 10^-8 * (24^4 - 40^4) = -0.78 * 5.67 × 10^-8 * 3973056 = -0.111 W/m² (accepting positive internal flux)

In this manner, the convective heat flux to the divider at x = is 80 W/m², and the radiative heat flux is around -0.111 W/m². Note that the negative sign demonstrates heat misfortune through radiation.

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Answer:

I believe it would be to lower the troop seats.

Explanation:

Answer:

In series:

\( \frac{1}{r} = \frac{1}{r_{1} } + \frac{1}{r _{2} } + \frac{1}{r_{3} } \)

\( \frac{1}{r} = \frac{1}{4} + \frac{1}{6} + \frac{1}{8} \\ \\ \frac{1}{r} = \frac{13}{24} \\ \\ r = \frac{24}{13} \\ { \underline{r = 1.85 \: Ω}}\)

In parallel:

\(r = r _{1} + r _{2} + r _{3} \\ r = 4 + 6 + 8 \\ r = 18Ω\)

A closed system is heated from a temperature T1 to T2, followed two different process paths: Process A (Change from state 1 to 2a) and Process B (Change from state 1 to 2b) - None of the above. Therefore the correct option is option D.

A closed system is a system in which no matter can enter or leave, but energy can. The energy can be exchanged in the form of work or heat between the closed system and its surroundings. For a closed system, the amount of mass inside the boundary is constant, which means that the total mass is conserved.

An ideal gas is a gas that obeys the ideal gas law. The ideal gas law is a mathematical equation that relates the pressure, volume, temperature, and number of molecules of an ideal gas together.

Isobaric: It is a thermodynamic process that takes place at a constant pressure, which means that the pressure of the system is kept constant during the entire process. It is written as: ∆E = q - P∆V.

Isometric: It is a thermodynamic process that takes place at a constant volume, which means that the volume of the system is kept constant during the entire process. It is written as: ∆E = q. Therefore the correct option is option D.

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A closed system is heated from a temperature T1 to T2, followed two diffferent process paths: Process A (Change from state 1 to 2a) and Process B (Change from state 1 to 2b). Which of the followings can be concluded from these two processes?

Answer:

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Answer:

a method of connecting polyphrase circuits in which one end of each phase line is connected to a common neutral point that may be connected to the earth as protection against lightning or to a wire to which all the other neutral points of the system are connected

Explanation:

The question asks for the lowest possible elevation of the bottom of the overpass to ensure sufficient stopping sight distance at 60 mi/hr. Stopping sight distance is the distance required for a driver to bring their vehicle to a complete stop in an emergency.
To determine the stopping sight distance, we can use the following formula:

Stopping Sight Distance = Perception Distance + Reaction Distance + Braking Distance

Perception distance can be calculated as follows:

Perception Distance = 1.47 (t + 1.5V)

where t is the perception-reaction time (1.5 seconds) and V is the design speed (60 mi/hr).

Perception Distance = 1.47 (1.5 + 1.5 x 60) = 220.5 ft

Reaction distance can be calculated as follows:

Reaction Distance = V x t

Reaction Distance = 60 x 1.5 = 90 ft

Braking distance can be calculated as follows:

Braking Distance = (V² / 30f) + (V/2g)(a + f)

where f is the coefficient of friction between the tires and the road surface, g is the acceleration due to gravity (32.2 ft/s²), and a is the grade.

Since the initial grade is -3.0%, we can assume that the entire vertical curve has a grade of -3.0%. Therefore, a = -3.0%.

The coefficient of friction depends on several factors such as the condition of the road surface, the weather conditions, and the type of tires. A typical value for the coefficient of friction for dry pavement is 0.7.

Braking Distance = (60² / (30 x 0.7)) + (60/2 x 32.2)(-0.03 + 0.7)

Braking Distance = 410.96 + 180.18 = 591.14 ft

Therefore, the stopping sight distance is:

Stopping Sight Distance = Perception Distance + Reaction Distance + Braking Distance

Stopping Sight Distance = 220.5 + 90 + 591.14 = 901.64 ft

To ensure sufficient stopping sight distance, the driver must be able to see at least 901.64 ft ahead of their vehicle. This means that the lowest possible elevation of the bottom of the overpass should be such that the vertical distance from the driver's eye height (5 ft) to the overpass is greater than or equal to 901.64 ft.

Let h be the height of the overpass above the PVI. Then the vertical distance from the driver's eye height to the overpass is h - 5 ft.

h - 5 ft ≥ 901.64 ft

h ≥ 906.64 ft

Therefore, the lowest possible elevation of the bottom of the overpass should be 906.64 ft above the PVI.

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Look at the Picture.
Frequency deviation = (830 MW - 830 MW) / (2π60*5 s)

Answer:

minimum current level required =  8975.95 amperes

Explanation:

Given data:

diameter = 5.5 mm

length = 5.0 mm

T = 0.3

unit melting energy = 9.5 j/mm^3

electrical resistance = 140 micro ohms

thickness of each of the two sheets = 3.5mm

Determine the minimum current level required

first we calculate the volume of the weld nugget

v = \(\frac{\pi }{4} * D^2 * l\) = \(\frac{\pi }{4} * 5.5^2 * 5\) = 118.73 mm^3

next calculate the required melting energy

= volume of weld nugget * unit melting energy

= 118.73 * 9.5 = 1127.94 joules

next find the actual required electric energy

= required melting energy / efficiency

= 1127 .94 / ( 1/3 )  = 3383.84 J

TO DETERMINE THE CURRENT LEVEL REQUIRED  use the relation below

electrical energy =  I^2 * R * T

3383.84 / R*T = I^2

3383.84 / (( 140 * 10^-6 ) * 0.3 ) = I^2

therefore  8975.95 = I ( current )

Answer:

6.27 × 10⁻⁴

Explanation:

Relative roughness, k = ε/D where ε = absolute roughness = 0.0025 mm and D = internal pipe diameter = 0.157 in = 0.157 × 25.4 mm = 3.9878 mm

So, k = ε/D

= 0.0025 mm/3.9878 mm

= 6.27 × 10⁻⁴

The relative pipe roughness for a plastic pipe will be:

"6.27 × 10⁻⁴".

According to the question,

Absolute roughness, ε = 0.0025 mm

Internal pipe diameter, D = 0.157 in or,

                                          = 0.157 × 25.4 mm

                                          = 3.9878 mm

We know that,

The relative roughness be:

→ k = \(\frac{Absolute \ roughness}{Diameter}\)

or,

   k = \(\frac{\varepsilon }{D}\)

By substituting the above values,

      = \(\frac{0.0025}{3.9878}\)

      = 6.27 × 10⁻⁴

Thus the above approach is correct.

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Answer:

You first get a new job, and make a new company and then by amazon to traumatize Jeff Bezos after his divorce

Explanation:

The stress at elastic limit is 1.27 N/mm^2, the Young's modulus is 254 N/mm^2, the percentage elongation is 57.5%, the percentage reduction in area is 97.44%, and the ultimate tensile stress is 696.67 N/mm^2.

Stress = Force / Area

Young's modulus = Stress / Strain

Percentage elongation = (extension / gauge length) x 100%

Percentage reduction in area = [(original area - area at neck) / original area] x 100%

Ultimate tensile stress = Maximum load / Area

Diameter of specimen = 100 mm

Gauge length = 100 mm

Extension at 70 KN load = 0.50 mm

Load at elastic limit = 10 KN

Maximum load = 140 KN

Total extension at fracture = 58 mm

Diameter at neck = 16 mm

We can calculate the area of the specimen as follows:

Area = π/4 x d^2

Area = π/4 x (100 mm)^2

Area = 7853.98 mm^2

The stress at elastic limit can be calculated as:

Stress = Load / Area

Stress = 10 KN / 7853.98 mm^2

Stress = 1.27 N/mm^2

The Young's modulus can be calculated as:

Strain = Extension / Gauge length

Strain = 0.50 mm / 100 mm

Strain = 0.005

Stress = Load / Area

Load = Stress x Area

Load = 1.27 N/mm^2 x 7853.98 mm^2

Load = 9982.16 N

Young's modulus = Stress / Strain

Young's modulus = 1.27 N/mm^2 / 0.005

Young's modulus = 254 N/mm^2

The percentage elongation can be calculated as:

Percentage elongation = (extension / gauge length) x 100%

Percentage elongation = (58 mm - 0.50 mm) / 100 mm x 100%

Percentage elongation = 57.5%

The percentage reduction in area can be calculated as:

Original area = π/4 x (100 mm)^2 = 7853.98 mm^2

Area at neck = π/4 x (16 mm)^2 = 201.06 mm^2

Percentage reduction in area = [(original area - area at neck) / original area] x 100%

Percentage reduction in area = [(7853.98 mm^2 - 201.06 mm^2) / 7853.98 mm^2] x 100%

Percentage reduction in area = 97.44%

The ultimate tensile stress can be calculated as:

Area at neck = π/4 x (16 mm)^2 = 201.06 mm^2

Ultimate tensile stress = Maximum load / Area

Ultimate tensile stress = 140 KN / 201.06 mm^2

Ultimate tensile stress = 696.67 N/mm^2

Therefore, the stress at elastic limit is 1.27 N/mm^2, the Young's modulus is 254 N/mm^2, the percentage elongation is 57.5%, the percentage reduction in area is 97.44%, and the ultimate tensile stress is 696.67 N/mm^2.

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