A farmer wants to fence in a rectangular plot of land adjacent to the north wall of his barn. No fencing is needed along the barn, and the fencing along the west side of the plot is shared with a neighbor who will split the cost of that portion of the fence. If the fencing costs $8 per linear foot to install and the farmer is not willing to spend more than $4000, find the dimensions for the plot that would enclose the most area. (enter the dimensions as a comma separated list. ).

Answer:

0.0371 kg/s.m

Explanation:

From the given information, let's have an imaginative view of the semi-cylinder; (The image is shown below)

Assuming the base surface of both ends of the cylinder is denoted by:

\(A_1 \ and \ A_2\)

Thus, using the summation rule, the view factor \(F_{11\) and \(F_{12\) is as follows:

\(F_{11}+F_{12}=1\)

Let assume the surface (1) is flat, the \(F_{11} = 0\)

Now:

\(0+F_{12}=1\)

\(F_{12}=1\)

However, using the reciprocity rule to determine the view factor from the dome-shaped cylinder \(A_2\) to the flat base surface \(A_1\); we have:

\(A_2F_{21} = A_{1}F_{12} \\ \\ F_{21} = \dfrac{A_1}{A_2}F_{12}\)

Suppose, we replace DL for \(A_1\) and

\(A_2\) =  \(\dfrac{\pi D}{2}\)

Then:

\(F_{21} = \dfrac{DL}{(\dfrac{\pi D}{2}) L} \times 1 \\ \\ =\dfrac{2}{\pi} \\ \\ =0.64\)

Now, we need to employ the use of energy balance formula to the dryer.

i.e.

\(Q_{21} = Q_{evaporation}\)

But, before that;  let's find the radian heat exchange occurring among the dome and the flat base surface:

\(Q_{21}= F_{21} A_2 \sigma (T_2^4-T_1^4) \\ \\ Q_{21} = F_{21} \times \dfrac{\pi D}{2} \sigma (T_2^4 -T_1^4)\)

where;

\(\sigma = Stefan \ Boltzmann's \ constant\)

\(T_1 = base \ temperature\)

\(T_2 = temperature \ of \ the \ dome\)

∴

\(Q_{21} = 0.64 \times (\dfrac{\pi}{2}\times 1.5) \times 5.67 \times 10^4 \times (1000^4 -370^4)\\ \\ Q_{21} = 83899.15 \ W/m\)

Recall the energy balance formula;

\(Q_{21} = Q_{evaporation}\)

where;

\(Q_{evaporation} = mh_{fg}\)

here;

\(h_{fg}\) = enthalpy of vaporization

m = the water mass flow rate

∴

\(83899.15 = m \times 2257 \times 10^3 \\ \\ m = \dfrac{83899.15}{ 2257 \times 10^3 }\\ \\ \mathbf{m = 0.0371 \ kg/s.m}\)

The drying rate per unit length is 0.037 kg/S.m

Given data;

From the attached diagram, the surface 1 is flat, it is a view factor, f\(_1_1\) = 0.

Applying summation rule and solving the view factor from the base surface A\(_1\) to the cylindrical dome A\(_2\).

\(f_1_1+f_1_2=1\)

Put F\(_1_2=0\)

\(0+f_1_2=1\)

This makes \(f_1_2=1\)

Applying reciprocal rule and solving the view factor from the cylindrical dome A\(_2\) to the base surface A\(_1\).

\(A_2F_2_1=A_1F_1_2\\F_2_1=(\frac{A_1}{A_2})F_1_2\)

Where A is the area of the surface.

Substitute DL for A\(_1\) and \(\frac{\pi D}{2}\) for A\(_2\)

\(F_2_1 = \frac{DL}{(\frac{\pi D}{2}})L *1 = \frac{2 }{\pi } =2/3.14 = 0.64\)

Using the energy balance equation to the dryer,

\(Q_2_1=Q_e_v_a_p\)

Let's calculate the radiation heat exchange between the dome and the base surface per unit length by using the equation below

\(Q_2_1=F_2_1A_2\)δ\((T_2^4-T_1^4)\)

\(Q_2_1= F_2_1 * \frac{\pi D}{2}\)δ\((T_2^4-T_1^4)\)

substitute the respective values into the equation

\(Q_2_1=0.64*(\frac{\pi }{2}*1.5)*5.67*10^-^8*(1000^4-370^4)\\Q_2_1=8.3899.15W/m\)

Let's calculate the mass flow rate of water using the amount of heat required for drying up.

\(Q_2_1=Q_e_v_a_p\\Q_e_v_a_p=mh_f_g\\\)

where \(h_f_g= 2257*10^3J/kg\)

and this is the enthalpy of vaporization and mass flow rate of water.

\(83899.15=m*2257*10^3\\m=0.037kg/S.m\)

The drying rate per unit length is 0.037kg/S.m

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The engineering method of separating costs is d. All of these choices are correct.

The engineering method of separating costs involves a step-by-step analysis of various elements involved in the production process to estimate the cost of activities and new products.

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False.Drain-induced barrier lowering (DIBL) is not desirable for CMOS devices in general. Explanation:Drain-induced barrier lowering (DIBL) is the reduction of the threshold voltage of a MOSFET (metal-oxide-semiconductor field-effect transistor) that occurs as the drain voltage increases.

This can lead to a reduction in the transistor's switching speed, which is undesirable for most CMOS devices.The threshold voltage, which determines whether the transistor is on or off, is reduced by DIBL. When the voltage at the drain terminal of the MOSFET is increased, the electric field generated by the drain voltage interacts with the charge distribution at the channel surface, causing it to expand, and reducing the potential barrier between the source and channel regions, reducing the threshold voltage.In general, DIBL is not desirable for CMOS devices since it limits their switching speed. Therefore, circuit designers aim to minimize DIBL by controlling the transistor's channel length and other device parameters to ensure that the threshold voltage remains relatively constant regardless of the drain voltage.

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Answer:

Weight Percentage of Ash = 3.4

Explanation:

Given - Coal containing 21% ash is completely combusted, and the ash is 100% removed in a water contact scrubber. If 10,000 kg of coal is burned per hour with a scrubber flow rate of 1.0 m3/min.

To find - the weight percentage of the ash in the water/ash stream leaving the scrubber is most nearly ?

Solution -

Given that,

Coal Burned Rate = 10,000 kg/hr

                              = \(\frac{10,000}{60 min} * 1 hr *\frac{kg}{hr}\)

                              = 166.6666 kg/min

⇒Coal Burned Rate = 166.6666 kg/min

Now,

Given that,

Ash content in coal = 21 %

⇒Ash in (coal that burned) = 166.6666 × \(\frac{21}{100}\) kg/min

                                             = 34.9999 ≈ 35 kg/min

⇒Ash in (coal that burned) = 35 kg/min

Now,

We know,

Density of water = 1000 kg/m³

Now,

Water flow Rate = \(1\frac{m^{3} }{min} * density\)

                           = 1000 kg/min

⇒Water flow Rate = 1000 kg/min

Now,

Total Mass flow Rate of (Water + Ash stream) = ( 1000 + 35) kg/min

                                                                           = 1035 kg/min

⇒Total Mass flow Rate of (Water + Ash stream) = 1035 kg/min

So,

Weight Percentage of Ash = (Weight of Ash ÷ Total weight of Stream) × 100

                                            = (35 ÷ 1035) × 100

                                            = 3.38 ≈ 3.4

∴ we get

Weight Percentage of Ash = 3.4

Answer:

When a pilot pushes the top of the right pedal, it activates the brakes on the right main wheel/wheels, and when the pilot pushes the top of the left rudder pedal, it activates the brake on the left main wheel/wheels. The brakes work in a rather simple way: they convert the kinetic energy of motion into heat energy.

Eqtm is undecidable and there is no algorithm that can solve it. This intuition is based on the fundamental limits of computation and the mathematical proof of undecidability.

The intuition behind the undecidable proof eqtm = { | m1 and m2 are tms and l(m1) = l(m2)} is that there is no algorithm that can decide whether two Turing machines have the same language. This is because the halting problem, which asks if a given Turing machine halts on a given input, is undecidable. Since determining if two Turing machines have the same language is a special case of the halting problem, it is also undecidable. The proof for this involves a reduction from the halting problem to eqtm. In other words, if we could decide eqtm, we could also solve the halting problem, which is impossible.

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The part of a drill that holds the drill bit in place is called the chuck.

The chuck is a key component of a drill, as it securely holds the drill bit in place during operation. It is typically located at the end of the drill, and can be opened and closed to insert or remove the drill bit.

The chuck is usually operated by either a key or a lever, depending on the type of drill. It is important to make sure that the chuck is properly tightened when the drill bit is inserted, as this will ensure that the bit is secure and will not slip or come loose during drilling.

Additionally, it is important to make sure that the bit is compatible with the size of the chuck, as an improper fit could cause the bit to become stuck or damaged.

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The term that refers to agreement as to what type of information the language is conveying is "semantic".

Semantic refers to the study of meaning in language, specifically the meaning of words, phrases, and sentences. It focuses on understanding how language conveys information and the relationship between words and their meanings.

For example, consider the sentence "The cat is on the mat." In a semantic analysis, we would examine the meanings of the words "cat," "on," and "mat" to understand the message being conveyed. We would determine that the sentence is expressing the location of the cat on the mat.

In contrast, the other options mentioned in the question have different meanings:

- Syntactic refers to the study of sentence structure and how words are combined to form grammatically correct sentences. It does not specifically focus on the meaning of the words.

- Logical refers to the study of reasoning and how statements relate to each other in a logical manner. It is concerned with the validity and soundness of arguments, rather than the specific meaning of words.

- Lexical refers to the study of words and their meanings. It examines the vocabulary of a language and how words are used to convey meaning. While lexical analysis is related to semantic analysis, it is not specifically concerned with the agreement of the type of information being conveyed.

Therefore, in this context, the correct term that refers to agreement as to what type of information the language is conveying is "semantic".

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The drag per unit span on the model can be calculated using a control volume approach as follows:

Where ρ is the density of the fluid, V is the velocity of the fluid, and z is the distance from the top of the test section to the bottom. The integral can be calculated by summing up the velocity of the fluid at each point from the top to the bottom of the test section. This can be expressed as:

Where Vz is the velocity of the fluid at each point in the test section.

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The research unit conducted a survey on non-communicable diseases among adults in a selected district. Out of the randomly selected 2000 adults, 52% were found to have non-communicable diseases.

The research unit conducted a survey to investigate the prevalence of non-communicable diseases among adults in a specific district. A total of 2000 adults were randomly selected to participate in the survey. The findings revealed that 48% of the selected adults were diagnosed with non-communicable diseases. This percentage indicates that a significant portion of the adult population in the district is affected by such diseases.

Non-communicable diseases, also known as chronic diseases, are typically long-term conditions that progress slowly and are not directly contagious. Examples of non-communicable diseases include cardiovascular diseases, cancer, diabetes, and chronic respiratory diseases. These diseases pose a significant burden on individuals, families, and healthcare systems, often leading to reduced quality of life and increased healthcare costs.

The survey results indicating that 52% of the adult population in the selected district has non-communicable diseases highlight the need for targeted interventions and healthcare services to address the high prevalence of these conditions. Public health initiatives should focus on preventive measures, such as health education, promotion of healthy lifestyles, and early detection and management of non-communicable diseases. By addressing the underlying risk factors and providing adequate healthcare support, it is possible to reduce the impact of non-communicable diseases and improve the overall health and well-being of the adult population in the district.

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Answer: None of the above

Explanation:

Business process modeling refers to the graphical representation of the business processes of a company, which is vital in the identification of potential improvements.

Business pticess modelling can be done through graphing methods, like data-flow diagram, flowchart etc. It is vital as business managers can effectively and quickly communicate their ideas.

It also enhances the customization of business processes, enhances the competitive advantage and enhances the process communication as well.

Therefore, the answer to the question will be "None of the above".

Answer:

If a tube having oval cross section is subjected to pressure its cross section tends to change from oval to circular.

Bourdon tube gauges consist of a circular tube.

One end of the tube is fixed while the other end is free to undergo elastic deformation under the effect of pressure.

Fixed end is open and pressure which is to be measured is applied at the fixed end.

Free end is closed and undergoes deformation under the effect of pressure.

Due to applied pressure the circular tube tends to uncoil and become straight along the dotted line.

Working of Bourdon Gauge

As the pressure is applied at the fixed end free end undergoes deformation.

The free end is attached with sector which further meshes with the pinion on which pointer is mounted.

Deformation of the pointer is transferred to pointer via this mechanism.

As a result point undergoes deflection and shows the pressure reading on calibrated dial.

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Answer:

oooo

Explanation:

oooiiiiijjjii niaje

Answer:

System analysis can be defined as a deep analysis of a part of the structure of a module that has been designed before. System design means to make any module or a part of the structure from scratch and build it completely without estimation.

Explanation:

Answer:

C. Pascal's

Explanation:

Pascal's law states that a liquid in a confined space has equal pressure distribution among the inside of the confined space. Due to this pressure, we know that these fluids cannot be compressed in a confined space any more than they already are.

Earth scientists categorize faults based on the dip, or angle of the fault with regard to the surface, and the slide direction. Dip-slip faults, which move in the direction of the dip plane, can either be defined as normal or reverse (thrust), depending on how they move.

The degree of stress affects the kind of fault that develops, and we typically divide it into three categories: compression, tension, and shear.

There are four different types of faulting: oblique, strike-slip, reverse, and normal. A typical fault occurs when the rocks above the fault plane, also known as the hanging wall or footwall, move downward in relation to the rocks below the fault plane, or the footwall.

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The program is an illustration of C++ functions;

Functions are program statements that are executed when evoked

The program in C++, where comments are used to explain each action is as follows:

#include <iostream>

#include <cmath>

using namespace std;

//This defines the boolean method

bool isoscelesTriangleHeightAndArea(double base, double hypotenuse, double height, double area) {

   //This checks for invalid base and height

   if(base < 0 || hypotenuse < 0){

       return false;

   }

   //This returns true if base and height are valid

   return true;

}

//The main begins here

int main(){

   //This initializes the variables

   double base, hypotenuse, height, area;

   //This gets input for base and hypotenuse

   cout<<"Base: ";    cin>>base;

   cout<<"Hypotenuse: "; cin>>hypotenuse;

   //The calls the boolean method

   bool success = isoscelesTriangleHeightAndArea(base, hypotenuse, height, area);

   //If success is True

   while (success){

       //This calculates height

       height = sqrt(hypotenuse*hypotenuse - (base/2) * (base/2));

       //This calculates area

       area = 0.5 * base * height;

       //This prints height

       cout << "Triangle height is " << height << endl;

       //This prints area

       cout << "Triangle area is " << area << endl;

       //This gets input for base and hypotenuse

       cout<<"Base: ";    cin>>base;

       cout<<"Hypotenuse: "; cin>>hypotenuse;

       bool success = isoscelesTriangleHeightAndArea(base, hypotenuse, height, area);

   }

   cout << "Invalid Input!" << endl;

}

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The pump work = v3.dP = 57.18 x 0.001 x ( 4000 - 20) =227.57 KW

here At T1 = 700 C and P1 = 4 Mpa, from steam tabel : h1 =3906.41 KJ/Kg and s1 = 7.62 KJ/Kg.K

now s1 = s2 = 7.62 KJ/Kg.K as 1-2 is isentropic

so at P2 = 20 Kpa and s2 = 7.62 KJ/Kg.K , fom steam table : h2 = 2513.33 KJ/Kg

a) power produced by turbine = m.( h1 - h2) = 57.18 x ( 3906.41 - 2513.33) = 79656.15 KW

b) at P3 = 20 Kpa, 3 = vf = 0.001 m^3/kg

so pump work = v3.dP = 57.18 x 0.001 x ( 4000 - 20) =227.57 KW

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The temperature difference between two surfaces divided by the sum of their thermal resistance determines how quickly heat can move between them. Answer:A)Q = 1208.33 W/m²,B)K = 0.138 W/m.K.

Ours is given;

T ,i, the internal air temperature, is 25 °C (25 + 273 = 298 K).

Temperature of the outside air; T ,o = -10°C = - 10 + 273 = 263K

T s,i, the inner surface temperature, is 15 °C (15 + 273, or 288 K).

L = 4 mm = 0.004 m thick

hi = 25 W/(m2.K), the convection heat transfer coefficient.

A) The amount of electricity needed for each unit of window area is calculated using an energy balance at the inner surface and the thermal circuit as follows;

Q is equal to [(T s,i - T o)/(L/k + (1/hi)]

(T o,o - T s,i)/(1/hi)

Using the appropriate values and the value of k for glass as 1.4 W/m.k, we have;

Q = [(288 - 263)/((0.004/1.4) + (1/25))]

- [(263 - 288)/(1/25)]

Q = 583.33 + 625

Q = 1208.33 W/m²

B) This is the equation for thermal conductivity:

K = (QL)/(AΔT)

Where;

Thermal conductivity, measured in W/m, is K.

K

Q is the quantity of heat that is passed through the substance.

Between the two isothermal planes, L is the distance.

A represents the surface's area in square meters.

T is the Kelvin difference in temperature

ΔT = 298K - 263K = 35K

Now that we know that Q = 1208.33 W/m2 is the value of heat per unit area, let's change the equation to reflect that;

Thus :

(Q/A) x (L/T) = k

K = 1208.33 x (0.004/35)

K = 0.138 W/m.K

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Answer:

The temperature of the strip as it exits the furnace is 819.15 °C

Explanation:

The characteristic length of the strip is given by;

\(L_c = \frac{V}{A} = \frac{LA}{2A} = \frac{5*10^{-3}}{2} = 0.0025 \ m\)

The Biot number is given as;

\(B_i = \frac{h L_c}{k}\\\\B_i = \frac{80*0.0025}{21} \\\\B_i = 0.00952\)

\(B_i\) < 0.1,  thus apply lumped system approximation to determine the constant time for the process;

\(\tau = \frac{\rho C_p V}{hA_s} = \frac{\rho C_p L_c}{h}\\\\\tau = \frac{8000* 570* 0.0025}{80}\\\\\tau = 142.5 s\)

The time for the heating process is given as;

\(t = \frac{d}{V} \\\\t = \frac{3 \ m}{0.01 \ m/s} = 300 s\)

Apply the lumped system approximation relation to determine the temperature of the strip as it exits the furnace;

\(T(t) = T_{ \infty} + (T_i -T_{\infty})e^{-t/ \tau}\\\\T(t) = 930 + (20 -930)e^{-300/ 142.5}\\\\T(t) = 930 + (-110.85)\\\\T_{(t)} = 819.15 \ ^0 C\)

Therefore, the temperature of the strip as it exits the furnace is 819.15 °C

Answer:

B. rotor

Explanation:

The correct answer Is rotor because the others are part of a cars drivetrain

The drive train system exists as a critical element of a vehicle and the transmission exists as an integral part of the drive train. B rotors NOT part of a car's drive train.

A drive train exists not really a single part of your car – it's a set of drive train components that interact with the engine to drive the wheels and different regions of the vehicle to thrust it into motion. These components often contain the transmission, differential, driveshaft, axles, CV joints, and wheels.

Therefore, the correct answer is option B rotors.

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Answer:

Dr. Engelbart, who would later help develop the computer mouse and other personal computing technologies, theorized that as electronic circuits were made smaller, their components would get faster, require less power and become cheaper to produce — all at an accelerating pace

Explanation:

A.

H = Aeσ^4

Using the stefan Boltzmann law

When we differentiate

dH/dT = 4AeσT³

dH/dT = 4(0.15)(0.9)(5.67)(10^-8)(650)³

= 8.4085

Exact error = 8.4085x20

= 168.17

H(650) = 0.15(0.9)(5.67)(10^-8)(650)⁴

= 1366.376watts

B.

Verifying values

H(T+ΔT) = 0.15(0.9)(5.67)(10)^-8(670)⁴

= 1542.468

H(T+ΔT) = 0.15(0.9)(5.67)(10^-8)(630)⁴

= 1205.8104

Error = 1542.468-1205.8104/2

= 168.329

ΔT = 40

H(T+ΔT) = 0.15(0.9)(5.67)(10)^-8(690)⁴

= 1735.05

H(T-ΔT) = 0.15(0.9)(5.67)(10^-8)(610)⁴

= 1735.05-1059.83/2

= 675.22/2

= 337.61

Answer:

The HTML ul tag is used for the unordered list. There can be 4 types of bulleted list: To represent different ordered lists, there are 4 types of attributes in <ul> tag. This is the default style. In this style, the list items are marked with bullets.

Answer:

Ordered

\({ \tt{ < ol > .... < / ol > }}\)

Unordered

\({ \tt{ < ul > .... < /ul > }}\)

The moisture content of the sample is determined to be 10% based on the given information.

To determine the moisture content of the sample, we need to calculate the initial moisture content and the final moisture content. The initial moisture content is the difference between the initial mass and the dried mass divided by the initial mass, multiplied by 100. In this case, the initial mass is 1 kg (1000 g) and the dried mass is 900 g. Therefore, the initial moisture content is (1000 g - 900 g) / 1000 g * 100 = 10%.

The moisture content of a sample is an important parameter in geotechnical engineering as it affects the engineering properties of soils. It represents the amount of water present in the soil sample relative to its dry mass. The drying process in the oven removes the moisture from the sample, allowing us to calculate its initial moisture content. In this particular case, the sample had an initial mass of 1 kg and a mass of 900 g after drying. By using these values, we calculated that the moisture content of the sample is 10%. This information can be useful in understanding the behavior and characteristics of the soil sample for engineering purposes.

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When a table is in the first normal form, all non-key columns depend on the primary key and no other columns. First normal form (1NF) is a property of a relation in a relational database.

A relation is in the first normal form when it contains no repeating groups of data, and each column stores only atomic values (i.e., indivisible).For a table to be in 1NF, the following conditions must be satisfied:

Each row of data should be unique:

No duplicate rows should exist in the table.No repeating groups:

Each column should have atomic values. A column must not contain multivalued attributes (repeating groups of data).Each column should have a unique name:

Each column in the table must have a unique name. Each column must be identified by a unique name, and every row in the table must have a value for each column.A unique identifier:

Every table in a relational database must have a primary key, which uniquely identifies each row. A primary key must be unique and not null (empty).A relation is said to be in the first normal form when all of its attributes are atomic or indivisible and it does not contain any repeating groups of data. Additionally, a relation in first normal form should have a unique identifier, known as a primary key.

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Answer:

b. A view of a building seen from one side, a flat representation of one façade. This is the most common view used to describe the external appearance of a building.

Explanation:

An elevation is a three-dimensional, orthographic, architectural projection that reveals just a side of the building. It is represented with diagrams and shadows are used to create the effect of a three-dimensional image.

It reveals the position of the building from ground-depth and only the outer parts of the structure are illustrated. Elevations, building plans, and section drawings are always drawn together by the architects.