A example of a substance that has low pH is

A. Lemons, which have a pH of 2
B. Lemons, which have s pH of 12
C. Soap, which has a pH of 0
D. Lemons, which have a pH of 10

The potential energy of the roller coaster is 176,400 J (joules).

The potential energy of an object is given by the formula PE = mgh, where PE is the potential energy, m is the mass of the object, g is the acceleration due to gravity, and h is the height or vertical position of the object.

In this case, the roller coaster is at a peak of 20m and has a mass of 900kg. The acceleration due to gravity, g, is approximately 9.8 \(m/s^2\).

Using the formula, we can calculate the potential energy:

PE = mgh

= (900 kg)(9.8 \(m/s^2\))(20 m)

= 176,400 J

Therefore, the potential energy of the roller coaster is 176,400 J (joules).

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Answer:

a

 \(Q_e  =  -4.39 *10^{11}  \  C \)

b

\(Q_p  =  + 2.395*10^{-8} \  C \)

Explanation:

Generally the number of electron in the given mass is  mathematically evaluated as

        \(N_e =  \frac{2.5}{m_e }\)

Here  m_e is the mass of electron with value \(m_e =  9.11 * 10^{-31} \  kg\)

    =>  \(N_e =  \frac{2.5}{ 9.11 * 10^{-31} }\)

       =>  \(N_e =2.74 *10^{30} \  electrons \)

The total electric charge is mathematically represented as

       \(Q_e  =  N_e  *  e\)

Here e is the charge on a single electron with value  \(e  =  1.60 *10^{-19}  \  C\)

 So

          \(Q_e  =  -2.74 *10^{30}   *  1.60 *10^{-19} \)

          \(Q_e  =  -4.39 *10^{11}  \  C \)

The  negative sign is because we are considering electron

Generally the number of  protons in the given mass is  mathematically evaluated as

    \(N_p =  \frac{2.5}{m_p }\)

Here  m_p is the mass of electron with value \(m_e =  1.67 * 10^{-27} \  kg\)

    =>  \(N_p =  \frac{2.5}{ 1.67 * 10^{-27} }\)

       =>  \(N_p =1.497 *10^{27} \  protons \)

The total electric charge is mathematically represented as

       \(Q_p  = + N_p  *  e\)

Here p is the charge on a single proton with value  \(p  =  1.60 *10^{-19}  \  C\)

 So

          \(Q_p  =  +1.497 *10^{27}   *  1.60 *10^{-19} \)

          \(Q_p  =  + 2.395*10^{-8} \  C \)

Answer:

when air or water cools it sinks

the frictional force on the broom has magnitude μ * m * g * cos(theta)

The frictional force on the broom can be determined using the equation:

F_friction = μ * F_norm

Where F_friction is the frictional force, μ is the coefficient of friction, and F_norm is the normal force. The normal force is equal to the force exerted on the broom perpendicular to the surface of the floor. Since the broom is being pushed across a horizontal surface, the normal force is equal to the force of gravity, which is equal to the mass of the broom (m) multiplied by the acceleration due to gravity (g).

F_norm = m * g

The force being applied to the broom is 7N and it is at angle theta with the horizontal. The component of this force perpendicular to the surface of the floor is the force that acts on the normal force.

F_norm = 7 * cos(theta)

Therefore,

F_friction = μ * m * g * cos(theta)

So, the frictional force on the broom has magnitude μ * m * g * cos(theta)

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Answer:

Hello There!!

Explanation:

The answer is=> It is a common component of antacids.

hope this helps,have a great day!!

~Pinky~

Answer: A. Velocity

Explanation:

The fluid flow through a pipe has the constant flow rate, so:

Q1 = Q2

Then, A1 V1 = A2 V2

That means, if A1 increases, V1 will decrease in order to keep the flow rate constant. Mass stays the same since it has the same system, which is pipe. Flow rate stays the same, and density also stays the same since it consists of one type of fluid (i.e. water).

Velocity will decrease. The correct option is A.

The equation for flow \(Q\),

\(Q = A\times V\\\rm where,\\A = cross\ sectional\ area\\V = Velocity\ of\ the\ fluid\)

As the per the equation of continuity. for the same fluid in a pipe (properties of fluid are constant)  the flow at the inlet\((Q_1)\) and outlet\((Q_2)\) of the pipe will be constant. Therefore,

\(Q_1 = Q_2\\Q_1 =A_1 \times v_1\\Q_2 =A_2 \times v_2\\hence,\\A_1 \times v_1 = A_2 \times v_2\)

Hence, if the area is increased therefore to keep the flow constant, velocity will decrease.

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(a) The amount of gravitational potential energy possessed by the object at the given height is 147.

(b) The kinetic energy, KE the object have just before hitting the ground is 147 J.

The amount of gravitational potential energy possessed by the object at the given height is calculated as follows;

GPE = mgh

where;

GPE = 5 kg x 9.8 m/s² x 3 m

GPE = 147 J

Based on the law of conservation of energy, the amount of kinetic energy possessed by the object just before hitting the ground will the same as the gravitational potential energy at the initial height.

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Answer:

56.25 watts

Explanation:

P = F * d / t

P = Power (it's an unknown at this point).

F = 450 N

d = 25 steps each 10 cm = 25 steps 0.1 m/step = 2.5 m

t = 20 s

Solution

P = 450 * 2.5 / 20

P = 1125/20

P = 56.25

The mass of a cannon if a 5.0 kg cannonball is fired from a stationary cannon with a horizontal velocity of 550 m/s if the cannon recoil in the opposite direction with a speed of 1.3 m/s is 2115.4 kg.

When anything is moving, its velocity tells us how rapidly that something's location is changing from a certain vantage point and as measured by a particular unit of time.

If a point moves along a path and covers a certain distance in a predetermined amount of time, its average speed over that period of time is equal to the distance covered divided by the travel time. A train traveling 100 kilometers in two hours, for instance, is doing it at an average speed of 50 km/h.

Given:

The mass of the cannonball, m = 5 kg,

The velocity of the cannon, v = 550 m/s,

The recoil speed of the cannon, vₐ = 1.3 m / s,

Then by using momentum conservation calculate the mass of the cannon,

\(m \times v = m_{a} \times v_{a}\)

Here mₐ is the mass of the cannon,

Substitute the values,

5 × 550 = mₐ × 1.3

mₐ = 2115.4 kg

Therefore, the mass of a cannon if a 5.0 kg cannonball is fired from a stationary cannon with a horizontal velocity of 550 m/s if the cannon recoil in the opposite direction with a speed of 1.3 m/s is 2115.4 kg.

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The Momentum Calculator uses the formula p=mv, or momentum (p) is equal to mass (m) times velocity (v).

e xddd  snoAnswer:n

E

xplanation:s no

W = 25 J

Explanation:

Work done on an object is defined as

\(W = Fd = (10\:\text{N})(2.5\:\text{m}) = 25\:\text{J}\)

Answer:

37.33m

Explanation:

Using the equation of motion

S = ut + 1/2gt^2

Time t = 2.76secs

g = 9.8m/s^2

S = 0 + 1/2(9.8)(2.76)^2

S = 4.9*7.6176

S = 37.33

Hence the window is 37.33m above the ground

Answer:

1) A) Lens converging, B) lens 1 converging

2) A and B object is at a greater distance than its focal

3)

Explanation:

For this exercise we will give some more important characteristics of the lenses.

we use the equation of the constructor

         1 / f = 1 / p + 1 / q

where f is the focal length and p and qlas the distance to the object and image, respectively.

We must also use how the lenses are combined

       1 / = 1 / f₁ + 1 / f₂

where feq is the equivalent focal length and it is assumed that the two lenses are in contact.

By applying the equation of the constructor you get some characteristics of the image

Converging lens

* Object farther than focal length real and inverted image

* Oject after focal virtual image and right

Diverging lens

* for all virtual image distance and right

with this information let's analyze the different configurations

1) let's do an analysis for each scenario

A) since lens 1 and lens 2 create real image they must be converging lenses

B) Lens 1 must be convergent and lens 2 can be of both types

C) Lens 1 can be convergent with the object that is at a shorter distance than at focal point (p <f₁). The same analysis diverges for lens 2, the object that is the image of the other lens is shorter than its focal distance p₂ <f₂

D) the object is at a shorter distance than the focal length p₁ <f₁, the object for this lens is at a greater distance than its focal point p₂> f₂

2) let's analyze for each scenario

A) for each lens the object is at a greater distance than its focal length p₁> f₁ and p₂> f₂

B) for lens 1 p₁> f₁

for lens 2

if it is convergent p₂ <f₂

and if it is divergent any distance is possible

C) lens 1 p₁ <f₁ and for lens 2 p₂ <f₂

D) lens 1 p₁ <f₁ and for lens 2 p₂> f₂

3) see attached

The distance with subscript 1 is measured with respect to line1 and the distance with subscript 2 is measured with respect to the lens with subscript 2

Answer:

200j

Explanation:

The kinetic energy just as it reaches the ground is 200J.

Potential energy is defined as the energy stored within an object that exists as a result of the state, position or arrangement of the object. It is one of the two primary forms of energy while the other is kinetic energy. The stored energy is released when there is a change in the state, position or arrangement of the object.

This is the stored energy which depends upon the relative position of various parts of a system such as a spring has more potential energy when it is compressed or stretched.

Initially the potential energy of the body is 200 J but when it is released, its potential energy is converted into kinetic energy. When the body just touches the ground, the kinetic energy becomes equal to the potential energy.

Thus, the kinetic energy just as it reaches the ground is 200J.

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The box accelerates to the right due to the applied force of 35 N in the +x direction.

Newton's second law states that the acceleration of an object is directly proportional to the net force applied to it and inversely proportional to its mass. In this case, the net force acting on the box is 35 N in the +x direction, and its mass is 15 kg. Therefore, we can calculate the acceleration using the formula:

acceleration = net force / mass

acceleration = 35 N / 15 kg = 2.33 m/s² (rounded to two decimal places)

Since the box is not accelerating up or down, we can conclude that the force applied is only causing the box to accelerate in the horizontal direction.

Other forces such as gravity and friction are not considered in this scenario. Thus, the 15 kg box will experience an acceleration of approximately 2.33 m/s² in the +x direction due to the applied force of 35 N.

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Answer:

Energy transformation is when energy changes from one form to another – like in a hydroelectric dam that transforms the kinetic energy of water into electrical energy. While energy can be transferred or transformed, the total amount of energy does not change – this is called energy conservation.

Explanation:

Answer:

Explanation:

Answer:

The distance covered by the person is 8.5 metre and the displacement is 6.8 metre.

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The linear mass density of the rope in the given motion of the wave is 0.15 kg/m.

The linear mass density of the rope in the given motion of the wave is determined by dividing the mass of the rope with the length of the entire rope.

The linear mass density of the rope is calculated as follows;

μ = m/L

μ = 0.6 kg / 4 m

μ = 0.15 kg/m

Thus, the linear mass density of the rope in the given motion of the wave is 0.15 kg/m.

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Answer:

32mi

Explanation:

If 1lb contains 3,500 Cal

It means the number of hours required to burn 3500cal would be;

3500/331 = 10.57hours

But a brisk walk is 3.0 mi/h,

It means a distance of 3.0 × 10.57 mi would be covered = 31.71 miles

32miles{ approximated to the nearest whole}

Note Distance = speed × time

Answer:

.

Explanation:

Answer:

Photovoltaic detection is a technique that converts light into electrical energy. It is a process that involves the use of a photovoltaic cell, which is made up of semiconductor materials, to generate an electric current when exposed to light.

The photovoltaic cell absorbs the photons of light, which then knock electrons out of their orbits, creating a flow of electricity. The amount of electricity produced is proportional to the intensity of the light. The photovoltaic cell is commonly used in solar panels to generate electricity from sunlight. The efficiency of the photovoltaic cell is dependent on several factors, including the type of semiconductor material used, the purity of the material, and the thickness of the cell.

The photovoltaic cell has many applications, including in solar power generation, telecommunications, and remote sensing. The technique of photovoltaic detection is an important area of research, as it has the potential to provide a clean and renewable source of energy that can help mitigate climate change.

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Answer:

C = 2.9 10⁻⁵ F = 29 μF

Explanation:

In this exercise we must use that the voltage is

          V = i X

          i = V/X    

where X is the impedance of the system

in this case they ask us to treat the system as an RLC circuit in this case therefore the impedance is

          X = \(\sqrt{R^2 + ( wL - \frac{1}{wC})^2 }\)

tells us to take inductance L = 0.

The angular velocity is

         w = 2π f

the current is required to be half the current at high frequency.

Let's analyze the situation at high frequency (high angular velocity) the capacitive impedance is very small

         \(\frac{1}{wC}\) →0       when w → ∞

therefore in this frequency regime

         X₀ = \(\sqrt{R^2 + ( \frac{1}{2\pi 2 10^4 C} )^2 } = R \sqrt{ 1+ \frac{8 \ 10^{-10} }{RC} }\)

the very small fraction for which we can despise it

        X₀ = R

to halve the current at f = 200 H, from equation 1 we obtain

         X = 2X₀

let's write the two equations of inductance

          X₀ = R                                    w → ∞

          X= 2X₀ = \(\sqrt{R^2 +( \frac{1}{wC} )^2 }\)        w = 2π 200

we solve the system

         2R = \sqrt{R^2 +( \frac{1}{wC} )^2 }

         4 R² = R² + 1 / (wC) ²

         1 / (wC) ² = 3 R²

          w C = \(\frac{1}{\sqrt{3} } \ \frac{1}{R}\)

          C = \(\frac{1}{\sqrt{3} } \ \frac{1}{wR}\)

let's calculate

           C = \(\frac{1}{\sqrt{3} } \ \frac{1}{2\pi \ 200 \ 9}\)

           C = 2.9 10⁻⁵ F

           C = 29 μF

The mass of Car B is -6000 kg.

To solve this problem, we can apply the principle of conservation of momentum, which states that the total momentum before the collision is equal to the total momentum after the collision.

Therefore, we can write the equation for the conservation of momentum as:

(mass of Car A * velocity of Car A) + (mass of Car B * velocity of Car B) = (mass of Car A + mass of Car B) * velocity after collision

Let's substitute the given values into the equation:

(2000 kg * 10 m/s) + (mass of Car B * 0 m/s) = (2000 kg + mass of Car B) * (-5 m/s)

Simplifying the equation:

20000 kg*m/s = -5 m/s * (2000 kg + mass of Car B)

Dividing both sides by -5 m/s:

-4000 kg = 2000 kg + mass of Car B

Subtracting 2000 kg from both sides:

mass of Car B = -4000 kg - 2000 kg

mass of Car B = -6000 kg

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Explanation:

initial speed = 60

final speed = 20

time = 50

a = ??

v2 = v1 + at

20 = 60 + 50 a

- 40 = 50 a

a = -4/5

= - 0.8 m/s²

The answers are 1) The value of R2 is not relevant as it implies a downward force on the plank, 2) The reactions at C and D are 66.3 N and 90 N, respectively, and 3) The vertical force at B to lift the plank clear of D is 686.4 N. The reaction at C is zero, and the reaction at D is 61.4 kg.

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Answer:

602.27 kg

Explanation:

The computation of the largest mass of cargo the balloon can lift is shown below:-

Volume of helium inside the ballon= (4 ÷ 3) × π × r^3

= (4 ÷ 3) × 3.14 × 6.953

= 1406.19 m3

Mass the balloon can carry = volume × (density of air-density of helium)

= 1406.19 × (1.29-0.179)

= 1562.27 kg

Mass of cargo it can carry = Mass it can carry - Mass of structure

= 1562.27 - 960

= 602.27 kg