a disk of mass m slides with negligible direction along a flat surface with a velocity v. the disc strikes a wall head-on and bounces back in the opposite direction with a kinetic energy one-fourth of its initial kinetic energy. what is the final velocity of the disc

The distance the car would have skidded, under identical conditions, if it had been traveling twice as fast is 4 times the initial stopping distance.

When a car travels at a high speed and then the driver applies the brake, the car will take some time to come to rest. The distance covered by the car while coming to rest is known as the stopping distance. The stopping distance is given by the formula:

d=1/2v²/a,

where d = stopping distance ,v = initial velocity ,a = acceleration. On applying brakes with a panic, the time taken to stop the car will be constant. This means that the stopping distance is directly proportional to the square of the initial velocity. Mathematically, we can write it as:

d₁/d₂ = v₁²/v₂²,

where d₁ = stopping distance for the initial velocity v₁, d₂ = stopping distance for the initial velocity v₂.

According to the work-energy theorem, the work done on the car is equal to the change in kinetic energy of the car. The kinetic energy of the car is given by the formula:

K.E. = 1/2mv²,

where m is the mass of the car.

Let us assume that the car has a mass of m kg. Initially, the car is traveling at a speed of v₁ m/s. After applying brakes, the car comes to rest. The work done on the car is given by:

W = ΔK.E.W = (1/2)mv₁² - 0W = (1/2)mv₁²

Now, let us assume that the initial speed of the car was v₂ = 2v₁. The work done on the car is given by:

W = ΔK.E.W = (1/2)mv₂² - 0W = (1/2)m(2v₁)²W = (1/2)m(4v₁²)W = 2mv₁²

Thus, the work done on the car when it was traveling at a speed of 2v₁ is four times greater than the work done on the car when it was traveling at a speed of v₁.

Therefore, the stopping distance will be four times greater. That is:

d₂ = 4d₁

Hence, the distance the car would have skidded, under identical conditions, if it had been traveling twice as fast is 4 times the initial stopping distance.

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Potential difference excites the electrons inside the material of the wire used throughout the circuit, due to this excitement the electrons start flowing to the higher potential (positive terminal) & due to their motion, current is directed in the opposite direction to the electron flow.

A ray of light impinges on a transparent material at some angle with the normal. If the material has a higher index of refraction, as it enters, the ray will B. bend to make a smaller angle with the normal

This phenomenon is known as refraction and occurs due to the change in the speed of light as it moves from one medium to another with different refractive indices. The bending of the light ray is governed by Snell's law, which states that the ratio of the sines of the angles of incidence and refraction is equal to the ratio of the refractive indices of the two media.

Therefore, when the ray enters the material with a higher refractive index, it will slow down and bend towards the normal. This behavior is what allows lenses to focus light and is essential in many optical devices, including eyeglasses, microscopes, and telescopes. So if a ray of light impinges on a transparent material at some angle with the normal and the material has a higher index of refraction, the ray will B. bend to make a smaller angle with the normal as it enters.

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Given

Time taken is t=8 s.

The initial speed is u=7 m/s

The final speed is v=9 m/s.

To find

The acceleration

Explanation

We know the acceleration is the ratio of the difference in the speed to the time taken.

Thus,

Conclusion

The acceleration is

The repeated flying into the air and landing on the same spot reinforces to the woodcock that this is the center of its territory.

The phrase "Woodcock sky dances" refers to the woodcock's breeding routine. It is a migratory bird that mates in the United States' Eastern and Central regions. Woodcock "sky dances" or courtship flights, which are a part of its breeding ritual, are familiar to ornithologists and bird lovers.The male woodcock prepares for the display by choosing a place and then creating a tiny opening in the trees or shrubs. It flies into the air at sunset or sunrise, calling out with a distinctive chirping sound. It then lands on the same spot, with each flight being more extensive than the last. The woodcock does this repeatedly, with each flight reaching a greater height than the previous one.

The woodcock's territory is at the center of its sky dancing. The repeated flying into the air and landing on the same spot reinforces to the woodcock that this is the center of its territory. During the breeding season, the woodcock's sky dancing activity is essential. It shows off the male's strength and agility to female woodcocks, which aids in their selection of mates.The woodcock's behavior is a result of natural selection. Through sky dancing, the woodcock's species has developed its breeding ritual over thousands of years. The ability to perform sky dances is an evolutionary benefit to the woodcock, as it aids in species reproduction and survival. Therefore, repeatedly flying into the air and landing on the same spot reinforces to the woodcock that this is the center of its territory.

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Answer:

The frequency of light beam is 4.74 x 10^(14) s^(-1)

Explanation:

In this problem we use the formula C=F x ( lamda )

here c= the speed of light

f =the frequency of light beam

lamda = wavelength

c=3 x 10^8 m/s ( universally same)

lamda = 633nm = 633 * 10^(-9) m

Therefore f = c/ ( lamda )

or; f = 3 x 10^8 /  633 * 10^(-9)

f= 4.74 x 10^(14) s^(-1) .

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Answer:

if there isn't a shorting mechanism, the whole sets will be blown out several lamps and then shortened, the overall resistance of the remaining operating lamps will be decreased resulting in an increased working current that is adequate to blast the fuse

Answer:

the correct one is 2

Explanation:

The emission and arcion spectra are similar, in the emission spectra a heated material emits photons for the internal transitions of the electrons, in the absorption spectrum the continuous emission of a lamp is absorbed at the energies that the material has transitions.

In our case the material is low early, so all the electrons are in their base states.

As the light beam has all wavelengths, those corresponding to the first emission of the material will be observed.

When reviewing the answers, the correct one is 2

Answer:

Your answer is F = 2280 N

Explanation:

The formula for force is \(F=ma\). Given this formula, \(1520\) × \(1.5\) \(= 2280\)

Explanation:

When Two Samples of Water are Mixed, what Final Temperature Results?

Go to Mixing Two Amounts of Water: Problems 1 - 10

Go to calculating the final temperature when mixing water and a piece of metal

Worksheet #2

Back to Thermochemistry Menu

Example #1: Determine the final temperature when 32.2 g of water at 14.9 °C mixes with 32.2 grams of water at 46.8 °C.

This is problem 8a from Worksheet #2.

First some discussion, then the solution. Forgive me if the points seem obvious:

1) The colder water will warm up (heat energy "flows" into it). The warmer water will cool down (heat energy "flows" out of it).

2) The whole mixture will wind up at the SAME temperature. This is very, very important.

3) The energy which "flowed" out (of the warmer water) equals the energy which "flowed" in (to the colder water)

This problem type becomes slightly harder if a phase change is involved. For this example, no phase change. What that means is that only the specific heat equation will be involved

Solution Key Number One: We start by calling the final, ending temperature 'x.' Keep in mind that BOTH water samples will wind up at the temperature we are calling 'x.' Also, make sure you understand that the 'x' we are using IS NOT the Δt, but the FINAL temperature. This is what we are solving for.

The warmer water goes down from to 46.8 to x, so this means its Δt equals 46.8 − x. The colder water goes up in temperature, so its Δt equals x − 14.9.

That last paragraph may be a bit confusing, so let's compare it to a number line:



To compute the absolute distance, it's the larger value minus the smaller value, so 46.8 to x is 46.8 − x and the distance from x to 14.9 is x − 14.9.

These two distances on the number line represent our two Δt values:

a) the Δt of the warmer water is 46.8 minus x

b) the Δt of the cooler water is x minus 14.9

Solution Key Number Two: the energy amount going out of the warm water is equal to the energy amount going into the cool water. This means:

qlost = qgain

However:

q = (mass) (Δt) (Cp)

So:

(mass) (Δt) (Cp) = (mass) (Δt) (Cp)

With qlost on the left side and qgain on the right side.

Substituting values into the above, we then have:

(32.2) (46.8 − x)(4.184) = (32.2) (x − 14.9) (4.184)

Solve for x

Answer:

1274 J

Explanation:

PE = m g h

    = 5 * 9.8 * 26 = 1274 J

In an upstream direction, the push/pull boundaries will be encountered in the reverse order as they appear in the supply chain, moving from the final customer back towards the initial supplier.

To answer your question regarding the correct relative order of push/pull boundary locations moving in an upstream direction:
1. Start at the downstream end of the supply chain.
2. Identify the push/pull boundary closest to the downstream end.
3. Move upstream to the next push/pull boundary in the supply chain.
4. Continue moving upstream, identifying push/pull boundaries in order.
The push/pull boundaries will be encountered travelling from the end client back towards the first supplier in an upward orientation, in the supply chain's reverse sequence.

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Change in length in meters is 0.21 m

volume is given by

 \(V_{f} = lwh\\\)

v = volume  \(V_{f}\) = Final  volume , \(V_{i}\) = initial volume

l = length

w = width

h = height

change in volume expansion,

\(V = \beta V_{i} T\)

where

t = change in temperature

\(\beta\) = coefficient of volume expansion

coefficient of volumetric expression defined as increasing volume per unit, original volume per Kelvin rising temperature.

\(\beta \\\) = 210×10⁻⁶ C⁻¹

\(V_{i} = lwh_{i}\)  

\(V_{f} - V_{i} = \beta V_{i}T\)

on solving we get,

\(h_{f} =\) 210×10⁻⁶ × 1 + 1000 = 1000.21m

Change in length=  \(h_{f} -h_{i}\)  = 0.21 m

Change in length in meters is 0.21 m

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Yes, if the output force is greater than the input force for a simple machine, the mechanical advantage is greater than one.

Mechanical advantage is a measure of how much a machine multiplies force or changes the direction of force. It is calculated by dividing the output force by the input force. If the output force is greater than the input force, the mechanical advantage will be greater than one.

If the output force is greater than the input force for a simple machine, it means that the machine is able to multiply the force applied to it. This is reflected in the mechanical advantage, which is a ratio of the output force to the input force. A mechanical advantage greater than one indicates that the machine is able to amplify the force.

For example, if the input force is 10 N and the output force is 30 N, the mechanical advantage would be 3 (30 N / 10 N), indicating that the machine is able to multiply the force by a factor of 3.

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Given:

distance of observer from the sound source, \(s=70~m\)

distance between the source of image information sender and the receiver, \(d=45~miles=72420.48~m\)

Assumptions:

speed of sound, \(v=343~m/s\)

speed of the image information being sent, \(c=3\times 10^8~m/s\) (we assume it to be nearly the speed of light in vacuum)

Solution:

Time taken by the sound to reach the observer:

\(time=\frac{distance}{speed}\)

\(time=70\div 343\)

\(time \approx 0.2~s\)

Time taken by the image to reach the destination:

\(time=\frac{72420.48}{3\times 10^8}\)

\(time=2.4\times 10^{-4}~s\)

Answer:

2n^2

Explanation:

depends on n

if first orboit n = 1

and so on

Answer:

1. The ice molecules are at a temperature of 0°C;

2. The ice molecules are absorbing latent heat which would result in their turning to liquid water. Therefore, melting or fusion is occurring.

Note: The question did not provide any options to choose from.

Explanation:

The process of change of state occurs when heat is added or removed from a substance. For example, solid may change to a liquid when heat is added to it whereas a liquid may change to liquid when heat is removed from it.

During the process of change of state, the temperature of the substance undergoing a change of state does not change throughout the time it is undergoing the change. The temperature will begin to increase or decrease when all the molecules of the substance has undergone a change of state. The heat supplied to or removed from a substance during a change of state is known as latent heat.

When a solid changes to liquid, it is known as fusion and the heat absorbed by the solid substance is known as latent heat heat of fusion. If a liquid changes to gas, it is known as vaporization and the heat absorbed by the liquid is known as latent heat of vaporization.

In the experiment by the students above, since the temperature of the ice remains constant at 0°C when heat is supplied from the Bunsen burner to it, the following processes could be occurring:

Answer: B, C, D

Explanation:

trust me

Answer:

Therefore, when a light ray traveling through air enters water or glass it slows down, refracts, and bends toward the normal line. ... For example, when light goes from glass or water to air, it speeds up. Refraction changes how objects look.

Explanation:

The light slows down when it passes from the less dense air into the denser glass or water. This slowing down of the ray of light also causes the ray of light to change direction. It is the change in the speed of the light that causes refraction.

The light slows down when it passes from the less dense air into the denser glass or water. This slowing down of the ray of light also causes the ray of light to change direction. It is the change in the speed of the light that causes refraction.

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The beetle's actual distance beneath the surface is 1.70 cm.

The given information states that the beetle appears to be 1.70 cm within the plastic. This means that the beetle is located at a distance of 1.70 cm from the outer surface of the cube of polystyrene plastic. However, the actual distance of the beetle beneath the surface is also 1.70 cm since it is embedded within the cube.

The phrase "appears to be" suggests that the observation of the beetle's position within the plastic is deceiving. The beetle is not deeper or closer to the surface than the given measurement. Therefore, the beetle's true depth beneath the surface is equivalent to the stated distance of 1.70 cm.

Distances and interpreting spatial relationships within objects like the embedded beetle.

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Answer:

Option C is correct.

The sum of Kinetic and Potential energy make up the object is mechanical energy.

Explanation:

The energy possessed to a body due to motion is called Kinetic energy.

\(K=\frac{1}{2}mv^{2}\)

The energy possessed to a body due to position is called Potential energy.

U=mgh

Hence, The sum of Kinetic and Potential energy make up the object is mechanical energy.

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Answer:

Approximately \(0.45\) (assuming that the surface is level, the mass is moving at constant velocity, and that \(g = 9.81\; {\rm m\cdot s^{-2}}\).)

Explanation:

With a power of \(P = 1.0\; {\rm kW} = 1.0\times 10^{3} \; {\rm W}\), the work that would be done over \(t = 10\; {\rm s}\) would be:

\(\begin{aligned}(\text{work}) &= (\text{power})\, (\text{time}) \\ &= (1.0\times 10^{3}\; {\rm W})\, (10\; {\rm s}) \\ &= 1.0 \times 10^{4}\; {\rm J}\end{aligned}\).

Divide work by distance to find the force that did the work:

\(\begin{aligned} (\text{force}) &= \frac{(\text{work})}{(\text{distance})} \\ &= \frac{1.0\times 10^{4}\; {\rm J}}{50\; {\rm m}} \\ &= 200\; {\rm N}\end{aligned}\).

If this mass is moving at a constant velocity, the magnitude of friction on this mass will be equal to that of the external force, \(200\; {\rm N}\).

If the surface is level, the magnitude of the normal force on this mass will be equal to that of weight:

\(\begin{aligned}(\text{weight}) &= (\text{mass})\, g \\ &= (45\; {\rm kg})\, (9.81\; {\rm N\cdot kg^{-2}}) \\ &\approx 4.41 \times 10^{3}\; {\rm N}\end{aligned}\).

Divide the magnitude of friction by normal force to find the coefficient of friction:

\(\begin{aligned}& (\text{coefficient of friction}) \\ =\; & \frac{(\text{friction})}{(\text{normal force})} \\ \approx\; & \frac{200\; {\rm N}}{(45\; {\rm kg})\, (9.81\; {\rm N\cdot kg^{-1}}))} \\ \approx \; & 0.45\end{aligned}\).

Following the image of the ball that have been shown;

1. Potential energy

2. Kinetic energy

3. Kinetic energy

4. Potential energy

5. Kinetic energy

6. Kinetic energy

7. Kinetic energy

Due to its position or elevation, an object has potential energy while it is at rest or is elevated above the ground. Depending on the circumstances, this potential energy may either be elastic or gravitational.

Kinetic energy, or the energy connected to motion, is present when an item is in motion. An object's kinetic energy is determined by its mass and velocity .

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Answer:

1: Potential and kinetic

2: Potential and kinetic

3: Potential and kinetic

4: potential

5: Potential and kinetic

6: Potential and kinetic

7: NEITHER

Explanation:

4 is potential because its the highest point

7 is neither because the question states "the image shows the path of a ball from the time it's thrown to the time it lands on the ground" so... 7 is when the ball has landed on the ground. therefore it has neither potential nor kinetic because it is resting.

Answer:

A ball is thrown straight up with a speed of 30

m/s. What is the maximum height reached by

the ball?

Explanation:

u=24

v=0

a=-0.29

s=

v^2=u^2+2as

s=(v^2-u^2)/2a

s=(0-576)/0.58

s=-575.42

By considering building a system of two positive charges: The work done by an external agent is negative.

Any attempt by an outside force to combine two positive charges would be harmful. This is done in order to overcome the electrical force that now opposes the movement of the two positive charges toward one another. Negative work is defined as an effort made to control a disagreeable factor. However, if the two positive charges are already close to one another and the external agent operates to separate them, the work done would be beneficial. This is due to how weak the electrical force that holds the two positive charges together becomes when they are separated, necessitating the aid of an outside force. When work done to separate charges, it is viewed favorably. It's important to keep in mind that the concept of work includes all kinds of forces, not only electrical ones. The sign of the work generated by an external source is determined by the force's direction and the charges' displacement. If both the force and the displacement are travelling in the same direction, the work is positive. If the force and displacement are moving in the opposite directions, the work is negative.

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Answer:

\(P_{h}\)=\(P_{0} e\)\(\frac{-mgh}{kT}\)

Explanation:

Answer:

False

Explanation:

Electromagnetic strength is inversely proportional to separation distance

Answer:

Inertia is directly proportional to mass of an object. Therefore, when the force of inertia increases the mass also increases, and when it decreases the mass also decreases.

Explanation:

Answer: Inertia is _ directly proportional_ to mass.

Explanation: