a desert tray has three slices of cake, three key lime pies, and four ice cream sundaes. What is the probability of the next two customers both select key lime pie?

Answer: C

Step-by-step explanation: A P E X

Answer:

\(\frac{30meters}{second}\)

600meters

Step-by-step explanation:

Use conversion factors that represent 1.  You can cross cancel wods just like numbers.

\(\frac{108km}{1hour}\) · \(\frac{1hour}{60 minutes}\) · \(\frac{1minute}{60seconds}\) ·\(\frac{1000meters}{1 km}\)

\(\frac{108000meters}{3600seconds}\)

\(\frac{30meters}{second}\)

\(\frac{30meters}{second}\) ·\(\frac{20seconds}{1}\)

600 meters

Helping in the name of Jesus.

Answer:

-1.9f-18

Step-by-step explanation:

Evaluate like terms. (0.4f-2.3f) & (-13-5)

-2.3f+0.4f-13-5 = -1.9f-18

Answer:

Step-by-step explanation:

Find 15 percent of 81.95 and add it to that.

The answer is 94.24 rounded.

Answer:

200

Step-by-step explanation:

\(\frac{2}{5}\) = \(\frac{80}{x}\)

2 x 40 = 80, so

5 x 40 = 200

Answer:

200 houses

Step-by-step explanation:

Flat: 2 parts = 80 flats
1 part => 80 : 2 = 40 flats
Houses: 5 parts = 40 x 5 = 200 houses

The term "isometric" has the Greek roots "isos," which means "same," and "metron," which means "measure." The definition of an isometric transformation is one in which the original figure and its transformed equivalent have the same shape, size, and orientation.

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The estimate for when the population will exceed 6371 is t > 20.33. This means that at a time greater than 20.33 units

To estimate when the population will exceed 6371, we can set up the inequality:

p(t) > 6371

where p(t) is the population at time t, as given by the equation \(p(t) = 1950e^{0.16t}\)

Substituting the expression for p(t) into the inequality, we get:

\(1950e^{0.16t} > 6371\)

Next, we can divide both sides of the inequality by 1950 to isolate the exponential term:

\(e^{0.16t} > 6371 / 1950\)

To solve for t, we can take the natural logarithm (ln) of both sides, which will eliminate the exponential term:

\(ln(e^{0.16t} > ln(6371 / 1950)\)

Using the property of logarithms that ln(e^x) = x, we get:

\(0.16t > ln(6371 / 1950)\)

Now, we can divide both sides of the inequality by 0.16 to solve for t:

\(0.16t / 0.16 > ln(6371 / 1950) / 0.16\)

Simplifying, we get:

\(t > ln(6371 / 1950) / 0.16\)

Using a calculator, we can find the approximate value of \(ln(6371 / 1950) / 0.16\), which is approximately 20.33 (rounded to two decimal places).

So, the estimate for when the population will exceed 6371 is t > 20.33. This means that at a time greater than 20.33 units

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True, The given equation for the asymptotes for a hyperbola with horizontal transverse axis is y = k ± (b/a) (x - h).

Define Hyperbola

The collection of all points along a hyperbola such that the difference in distance between any point along the hyperbola and two fixed locations is constant is known as the hyperbola. The foci of the hyperbola are the two fixed points.

The standard equation for a hyperbola with a horizontal transverse axis is

(x - h)² / a² -  (y - k)² / b² = 1

The distance between the vertices is 2a.

Every hyperbola has two asymptotes

A hyperbola with a horizontal transverse axis and center at (h, k) has one asymptote with equation

y = k + (b/a)  (x - h)

and the other with equation

y = k - (b/a) (x - h)

Therefore, the answer is True.

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The answer will be 0. 10 >  0. 01 . Option B

Given the values as;

Turn the values into proper fractions

a. 0. 10 = 10/ 100

Reduce to simpler terms

= 10/ 100

= 1/ 10

b. 0. 01 = 1/ 100

a = 1/ 100

b = 1/ 100

This means that both decimals are not of  equal proportion and thus a is greater than (>) b

Thus, the answer will be 0. 10 >  0. 01 . Option B

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At a price of $3, the total revenue will be the greatest, and the company will sell 3 units at that price.

To find the total revenue at each price, we can multiply the price by the corresponding quantity.

Price        Quantity          Total Revenue

$6                0                      $0

$5                 1                       $5

$4                 2                       $8

$3                 3                        $9

$2                 4                         $8

$1                  5                          $5

To find the price at which total revenue is the greatest, we look for the highest value in the Total Revenue column.

In this case, the highest total revenue is $9, which occurs when the price is $3.

At a price of $3, the company will sell 3 units (as indicated in the Quantity column).

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Answer:

x = -6

y = 4

Step-by-step explanation:

Rewriting the equations :

Now, solving the two equations using substitution method, we get :

x = -6

y = 4

Answer:

y = 4

x = -6

Step-by-step explanation:

1/2 x + 1/4 y= -2        first equation

-2/3 x + 1/2 y = 6      second equation

solution:

from the first equation:

8(1/2 x + 1/4 y) = -2*8

8x*1/2 + 8y*1/4 = -16

8x/2 + 8y/4 = -16

4x + 2y = -16        third equation

from the second equation

6(-2/3 x + 1/2 y) = 6*6

6x*-2/3 + 6y*1/2 = 36

-12x/3 + 6y/2 = 36

-4x + 3y = 36        fourth equation

from the third & fourth equation:

 4x + 2y  = -16

-4x + 3y  = 36

   0  + 5y = 20

5y = 20

y = 20/5

y = 4

from the fourth equation:

-4x + 3y = 36

-4x + 3*4 = 36

-4x + 12 = 36

-4x = 36 - 12

-4x = 24

x = 24/-4

x = -6

Check:

from the first equation:

1/2 x + 1/4 y = -2

1/2 *-6 + 1/4 * 4 = -2

-3 + 1 0 -2

from the second equation:

-2/3 x + 1/2 y = 6

-2/3 * -6  +  1/2 * 4 = 6

4 + 2 = 6

Answer:

0.3756

Step-by-step explanation:

I believe this is a combinatorics probability problem.

We first figure out in how many ways we can choose 3 cats out of 14 cats

Then we figure out how many ways we can choose 2 dogs out of 7 dogs

The total number of ways to select 3 cats and 2 dogs will be the product of these two

We then figure out in how many ways we can select 5 animals out of a total of 21 animals

The product we computed divided by the above number will give the probability

The number of ways we can choose k items out of n items is given by nCk i.e n Choose k

The formula is rather complicated but almost all calculators should be able to compute this given n and k

Let's deal with the selection of 3 cats from the population of 14 cats

This is given by 14C₃ which works out to 364

Number of ways for selecting 2 dogs from 7 dogs = 7C₂ = 21

Number of ways of selecting 5 animals from 21 = 21C₅ = 20349

The probability of selecting 3 cats and 2 dogs is therefore:

\(\dfrac{364 \times 21}{20349} = 0.3756\)

That, I believe is the answer. Please let me know if it is correct and if you need more info.

Answer: a) x = .555...

              => 10x = 5.55...

              => 10x - x = 5.55... - .555...

              => 9x = 5

              => x = 5/9

b) x = .2525...

   => 100x = 25.25...

   => 100x - x = 25.25... - .2525...

   => 99x = 25

   => x = 25/99

Answer:

(a) Probability that a family of a returning college student spend less than $150 on back-to-college electronics is 0.0537.

(b) Probability that a family of a returning college student spend more than $390 on back-to-college electronics is 0.0023.

(c) Probability that a family of a returning college student spend between $120 and $175 on back-to-college electronics is 0.1101.

Step-by-step explanation:

We are given that according to an NRF survey conducted by BIG research, the average family spends about $237 on electronics in back-to-college spending per student.

Suppose back-to-college family spending on electronics is normally distributed with a standard deviation of $54.

Let X = back-to-college family spending on electronics

SO, X ~ Normal(\(\mu=237,\sigma^{2} =54^{2}\))

The z score probability distribution for normal distribution is given by;

                                 Z  =  \(\frac{X-\mu}{\sigma}\)  ~ N(0,1)

where, \(\mu\) = population mean family spending = $237

           \(\sigma\) = standard deviation = $54

(a) Probability that a family of a returning college student spend less than $150 on back-to-college electronics is = P(X < $150)

        P(X < $150) = P( \(\frac{X-\mu}{\sigma}\) < \(\frac{150-237}{54}\) ) = P(Z < -1.61) = 1 - P(Z \(\leq\) 1.61)

                                                             = 1 - 0.9463 = 0.0537

The above probability is calculated by looking at the value of x = 1.61 in the z table which has an area of 0.9463.

(b) Probability that a family of a returning college student spend more than $390 on back-to-college electronics is = P(X > $390)

        P(X > $390) = P( \(\frac{X-\mu}{\sigma}\) > \(\frac{390-237}{54}\) ) = P(Z > 2.83) = 1 - P(Z \(\leq\) 2.83)

                                                             = 1 - 0.9977 = 0.0023

The above probability is calculated by looking at the value of x = 2.83 in the z table which has an area of 0.9977.

(c) Probability that a family of a returning college student spend between $120 and $175 on back-to-college electronics is given by = P($120 < X < $175)

     P($120 < X < $175) = P(X < $175) - P(X \(\leq\) $120)

     P(X < $175) = P( \(\frac{X-\mu}{\sigma}\) < \(\frac{175-237}{54}\) ) = P(Z < -1.15) = 1 - P(Z \(\leq\) 1.15)

                                                         = 1 - 0.8749 = 0.1251

     P(X < $120) = P( \(\frac{X-\mu}{\sigma}\) < \(\frac{120-237}{54}\) ) = P(Z < -2.17) = 1 - P(Z \(\leq\) 2.17)

                                                         = 1 - 0.9850 = 0.015

The above probability is calculated by looking at the value of x = 1.15 and x = 2.17 in the z table which has an area of 0.8749 and 0.9850 respectively.

Therefore, P($120 < X < $175) = 0.1251 - 0.015 = 0.1101

Step-by-step explanation:

\( {(x - 3)}^{ - 1} \\ = - (x - 3) \times (1) \\ = - (x - 3)\)

An Annual is not an example of an agreement.

Answer:

-------------------------

Since angle α is between 0° and 90°, it is in the first quadrant and therefore all sin α, cos α and tan α are positive numbers.

Use the following identities:

Given tan α = 2.4. Using identities, find cosine as follows:

Find sine:

Answer:

168 = 18 * x + 12 * 2x

Step-by-step explanation:

It's the only one that makes sense. You can mark out the 2nd and last one. We don't add 2x + x; for the 3rd, they need to subtract 18 - 2x, so that's not right either.

Set A has a peak at 5. It is also skewed to the right. The center is 5.

Set B also has a peak at 5. Is relatively symmetrical. The center is also 5.

(Sorry about those circle in the back of my picture)

Answer:

\(3\sqrt{22}\)

Step-by-step explanation:

The product of roots with the same index is equal to the root of the product \(3\sqrt{11*2}\)

Multiply

The stars in order from the closest one to the farthest one are:

0.883, 0.886, 0.89, 1.25

so, the answer is A.

What is a sequence?

A sequence is an enumerated collection of objects in which repetitions are allowed. Like a set, it contains members (also called elements, or terms).

To put the given distances in order from the closest one to the farthest one, we need to arrange them in ascending order.

That means we need to start with the smallest value and move toward the largest value.

Looking at the given distances, we see that the smallest value is 0.883, followed by 0.886, then 0.89, and finally 1.25, which is the largest value.

Putting the given distances in ascending order, we get:

0.883, 0.886, 0.89, 1.25

Therefore, the stars in order from the closest one to the farthest one are:

0.883, 0.886, 0.89, 1.25

so, the answer is A.

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Answer:

.........................

Step-by-step explanation:

Answer:

2

-2

-1.5/7,-1)

-2

2

Step-by-step explanation:

Also your first answer is correct ma'am or sir! thank me later

The perimeter of the rectangle is 62 square units.

The perimeter of a rectangle can be calculated using the formula:

P = 2(L + W)

Where:

L is the length of the rectangle

W is the width of the rectangle

We have:

L = 20 units

W = 11 units

Substituting into the formula:

P = 2(20 + 11)

P = 2(31)

P = 62 square units

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Question in English

What is the perimeter of a rectangle if it is 20 long and 11 wide?

Step-by-step explanation:

a 75% rebound ratio means that the rebounding back reaches 75% of the height of the previous drop.

75% = 3/4

a geometric series means that every term is created by multiplying the previous term by a certain factor. this factor is this mentioned 3/4.

each term (except s0, the start value) stands for the hight of the bounce.

s0 = k

s1 = s0 × 3/4 = k × 3/4

s2 = s1 × 3/4 = k × 3/4 × 3/4 = k × (3/4)²

sn = sn-1 × 3/4 = k × (3/4)^n

for k = 235ft

the 6th bounce is

s6 = 235 × (3/4)⁶ = 41.82495117... ft

the total distance by the ball is

2× the sum of the terms until s11 (the last bounce before the ball strikes the ground a 12th time) - s0.

why ? for s1 to s11 the ball has to go up and down, so the height of the bounce is traveled twice. but s0 happens only once (the first drop). so, when we multiply the whole sum by 2, we need to deduct s0 one time again.

the sum of all bounces s0 to s11 (n = 11) is

s = s0 × (1 - r^(n+1))/(1 - r)

where r is the multiplication factor (here 3/4).

s = 235 × (1 - (3/4)¹²)/(1 - 3/4) =

= 235 × (1 - (3/4)¹²)/(1/4) = 235 × (1 -(3/4)¹²) × 4 =

= 910.2242291... ft

2×s - s0 = 1,585.448458... ft

The distance between points P and Q is √73

First, remember that the distance between two points whose coordinates are (a, b) and (c, d) is given by:

distance = √( (a - c)² + (b - d)²)

Here we can see that the coordinates of the two shown points are:

P = (-3, 2)

Q = (5, -1)

Replacing that in the distance formula we will get:

distance = √( (-3 - 5)² + (2 + 1)²)

distance = √( (-8)² + (3)²)

distance = √73

So the correct option is the third one.

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Answer: 27.509, 27.56, 27.599, 27.5998

Step-by-step explanation: