Refer to the photo taken.
. A car starts to move from rest has an acceleration of 3m/s².what will be the velocity and distance travelled by the car after 50sec.
Sure! Here are the steps for calculating the velocity and distance traveled by the car after 50 seconds :
Step 1: Calculate the velocity using the equation:
\(v = u + at\)
where:
- \(v\) is the final velocity
- \(u\) is the initial velocity (0 m/s, as the car starts from rest)
- \(a\) is the acceleration (3 m/s²)
- \(t\) is the time (50 seconds)
Substituting the values into the equation:
\(v = 0 + (3 \, \text{m/s²}) \times (50 \, \text{s})\)
Step 2: Calculate the distance traveled using the equation:
\(s = ut + \frac{1}{2}at^2\)
where:
- \(s\) is the distance traveled
- \(u\) is the initial velocity (0 m/s)
- \(a\) is the acceleration (3 m/s²)
- \(t\) is the time (50 seconds)
Substituting the values into the equation:
\(s = 0 \times (50 \, \text{s}) + \frac{1}{2} \times (3 \, \text{m/s²}) \times (50 \, \text{s})^2\)
Now, let's simplify these equations:
\(v = 3 \times 50\)
\(s = \frac{1}{2} \times 3 \times 50^2\)
Calculating the results:
\(v = 150\) m/s
\(s = 3750\) meters
Therefore, after 50 seconds, the car will have a velocity of 150 m/s and would have traveled a distance of 3750 meters.
Explain how the motor takes advantages of electromagnetism to work?
Suppose a pendulum clock has been calibrated to be accurate in San Francisco, where g = 9.800 m/s2 . In Camrose, g = 9.811 m/s2 is slightly larger due to the effect of Earth’s rotation at a higher latitude. Explain why the clock will either run perfectly, run too quickly, or run too slowly in Camrose.
The clock would run too slowly in Camrose.
Since the period of the pendulum T = 2π√(L/g) where L = length of clock and g = acceleration due to gravity.
Now since g = 9.800 m/s² in San Francisco and g = 9.811 m/s² in Camrose, we see that g increases.
From the expression for the period T, since L is constant, we find that
T ∝ 1/√g
Since g increases, so, T would decrease.
Thus, the clock would run too slowly in Camrose.
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Calculate the answer to the correct
number of significant digits.
15.3 + 1.285
Which of the following lines of reasoning involves proving a event occurs, and assuming
something about the mechanisms leading to that conclusion?
O productive reasoning
O inductive reasoning
O deductive reasoning
O reductive reasoning
Correct option is C, deductive reasoning involves proving a event occurs, and assuming something about the mechanisms leading to that conclusion.
Deductive reasoning -In deductive reasoning, a conclusion is drawn from the agreement of multiple premises that are frequently assumed to be true. Deductive reasoning is also referred to as top-down reasoning. Deductive reasoning is built on making logical assumptions and drawing conclusions from them.
It is predicated on a broad assertion or hypothesis that is assumed to be true (sometimes referred to as a premise). In order to arrive at a clear, logical conclusion, the premise is used. The if/then statement is a typical illustration. Deductive reasoning informs us that A Equals C if A = B and B = C.
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how do hydrogen atoms become ionized within an h-ii region? question 19 options: as a result of emitting radiation within the visible light spectrum by absorbing ultraviolet radiation from a nearby star by absorbing radiation within the visible spectrum by capturing the free electrons within the cloud by absorbing thermal radiation from the nearby star
Within an H-II region, hydrogen atoms become ionized by absorbing ultraviolet radiation from a nearby star.
The high-energy photons from the star have enough energy to knock an electron off the hydrogen atom, leaving a positively charged hydrogen ion or proton.
This process is known as photoionization and is the main mechanism for ionizing hydrogen in H-II regions.
The ionized hydrogen then emits its own radiation, creating the characteristic red glow of H-II regions.
While hydrogen atoms can also become ionized by other means, such as absorbing thermal radiation or capturing free electrons, these processes are less common in H-II regions compared to photoionization by ultraviolet radiation from nearby stars.
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How many cubic inches are there in 3.25 yd3?Express the volume in cubic inches to three significant figures.
A student designs a gravity experiment. She will time how long it takes different objects to fall from her school's roof to the ground. She will use three
objects: a 2-foot-long board, a toy car, and a paper bag. What is wrong with her experiment's design? (1 point)
O The objects do not have the same size, shape, or mass, so any differences in drop times cannot be attributed to one variable
O The experiment does not test enough objects
O Gravity will not affect how long it takes for the objects to fall to the ground.
O The school roof is not tall enough to test the effect of gravity on different objects.
The problem with the student's experiment is that the objects do not have the same size, shape, or mass, so any differences in drop times cannot be attributed to one variable (option A).
What is an experiment?An experiment is a test under controlled conditions made to either demonstrate a known truth, examine the validity of a hypothesis, or determine the efficacy or likelihood of something previously untried.
According to this question, a student designs a gravity experiment to determine how long it takes different objects to fall from her school's roof to the ground.
She will use three objects as follows: a 2-foot-long board, a toy car, and a paper bag.
The flaw with this experiment is that different objects of different masses, sizes, shapes were used.
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Answer:
(Question) Which statement about mass is correct?
(Answer) Mass is the measure of the amount of matter in an object.
(Question) A student designs a gravity experiment. She will time how long it takes different objects to fall from her school’s roof to the ground. She will use three objects: a 2-foot-long board, a toy car, and a paper bag. What is wrong with her experiment’s design?
(Answer) The objects do not have the same size, shape, or mass, so any differences in drop times cannot be attributed to one variable.
(Question) Which statement about gravity is correct?
(Answer) Gravity is a force that attracts objects with mass toward each other.
(Question) A team of students performs an experiment to test the effect of gravity on different objects with the same mass. They measure how long it takes the objects to fall from the top of the school’s bleachers. How can they insure they get accurate data?
(Answer) by repeating the experiment several times
(Question) Students analyze their data from a gravity experiment. They find that objects fall at a greater speed from a greater height than from a lower height. What can they conclude?
(Answer) The longer an object falls, the more gravity increases its speed.
Explanation:
i just did the quick check UwU
Four views of a horseshoe magnet and a current-carrying wire are shown in the drawing. The wire is perpendicular to the screen, and the current is directed out of the screen toward you. In which one or more of these situations does the magnetic force on the current point due north?.
Four views of a horseshoe magnet and a current-carrying wire are shown in the drawing. The wire is perpendicular to the screen, and the current is directed out of the screen towards you.
The magnetic force acting on a current-carrying wire is influenced by the direction of the current flow and the direction of the magnetic field, which is decided by the magnetic pole it is near. The magnetic field lines created by a bar magnet, for example, run from the north to the south pole.In the given figure, the magnetic field lines are moving from north to south, as shown by the white arrow.
When the direction of the current is perpendicular to the direction of the magnetic field, a magnetic force is exerted on the current-carrying wire. According to the right-hand rule, the magnetic force on the wire will be perpendicular to both the current-carrying wire and the direction of the magnetic field.
According to the right-hand rule, magnetic force will be directed north in the first view (A), and magnetic force will be directed east in the third view (C).
Therefore, magnetic force on the current points due north in the first view (A).Hence, the answer is the first view (A).
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In golf, a club is swung to hit a small ball resting on the ground. Golfer A holds his club a short distance behind the golf ball, swings through a small distance, and hits the ball. The ball travels a small distance. Golfer B holds his club above his shoulder, swings through a large distance, and hits the ball. The ball travels a large distance. Explain why golfer B's golf ball travels a longer distance than golfer A's by using Newton's First Law.
Answer:
Golfer B hits his golf ball at a higher rate of speed and with more force. This means that golfer B's ball will travel for a longer period of time and a longer distance due to newtons first law, where it says an object in motion stays in motion, with the same speed and in the same direction.
Explanation:
An ice skater spins at 2.5 rev/s when his arms are extended. He draws his arms in and spins at 10.0 rev/s. By what factor does his moment of inertia change in the process?
Answer:
The moment of inertia decreased by a factor of 4
Explanation:
Given;
initial angular velocity of the ice skater, ω₁ = 2.5 rev/s
final angular velocity of the ice skater, ω₂ = 10.0 rev/s
During this process we assume that angular momentum is conserved;
I₁ω₁ = I₂ω₂
Where;
I₁ is the initial moment of inertia
I₂ is the final moment of inertia
\(I_2 = \frac{I_1 \omega_1}{\omega_2} = \frac{I_1*2.5}{10} \\\\I_2 = 0.25I_1 = \frac{1}{4}I_1\)
Therefore, the moment of inertia decreased by a factor of 4
Which series of steps describes how to demonstrate conservation of momentum in a system of two moving particles that collide? (1 point)
Determine the momentums of the two particles before the collision and add them together. Determine the momentums of the two
particles after the collision and add them together. Verify that both sums are the same.
Determine the momentums of one of the particles before and after the collision and add them together. Determine the momentums
of the other particle before and after the collision and add them together. Verify that both sums are the same.
Determine the momentums of the two particles before the collision and add them together. Determine the momentums of the two
particles after the collision and add them together. Verify that both sums are zero.
Determine the momentums of one of the particles before and after the collision and add them together. Determine the momentums
of the other particle before and after collision and add them together. Verify that both sums are zero.
The momentums of the two particles prior to the collision should be determined and added. After the collision, calculate the momentums of the two particles and combine them. Verify that both sums are the same option -2 is correct answer.
What are some examples of momentum conservation?In the collision, momentum remains constant. This idea of momentum conservation can be illustrated using a vector diagram, which makes use of an arrow to show the size and direction of the momentum vectors for each individual object prior to the collision as well as the combined momentum following it.
The principle of conservation of momentum ensures that the total momentum of an isolated system of two or more objects interacting with one another is always conserved. This indicates that when two objects interact, one of the objects transfers some of its momentum to the other object.
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Displacement
► If you walk 4 meters east then 3 meters
north, what displacement did you
travel?
Explanation:
The answer is mentioned above.
Hope it helps.
The average annual discharge at the outlet of a catchment is 0.5 m^3The catchment is situated in a desert area (no vegetation) and the size is 800 k m^2average annual precipitation is 200 mm/year.
a) Compute the average annual evaporation from the catchment in mm/year. BONUS!!! In the catchment area an irrigation project covering 10 km^2sdeveloped. After some years the average discharge at the outlet of the catchment appears to be 0.175 m^3/s.
b) Compute the evapotranspiration from the irrigated area in mm/year, assuming no change in the evaporation from the rest of the catchment.
a) The average annual evaporation from the catchment is approximately 180.29 mm/year.
b) The exact value of evapotranspiration from the irrigated area cannot be calculated due to missing information.
a) Average annual evaporation from the catchment in mm/year:
First, we calculate the total annual rainfall that is collected by the catchment area:
800,000,000 m² × 0.2 m = 160,000,000 m³/year
Since this is the only source of water for the catchment, the total amount of water available to the catchment area per year will be 160,000,000 m³/year.
We know that the average annual discharge at the outlet of a catchment is 0.5 m³/s, and since there are 31,536,000 seconds in a year, we can calculate the total volume of water that is discharged per year:
0.5 m³/s × 31,536,000 s = 15,768,000 m³/year
So, the total volume of water that is lost through evaporation per year will be:
160,000,000 m³/year - 15,768,000 m³/year = 144,232,000 m³/year
To convert this into millimeters, we need to divide this value by the area of the catchment in square meters, and then multiply by 1000 (since 1 m = 1000 mm):
144,232,000 m³/year ÷ 800,000,000 m² × 1000 mm/m = 180.29 mm/year
Therefore, the average annual evaporation from the catchment is approximately 180.29 mm/year.
b) Evapotranspiration from the irrigated area in mm/year:
Since we know that the size of the irrigated area is 10 km² = 10,000,000 m², we can calculate the total volume of water that is used for irrigation each year by multiplying this area by the amount of discharge that is lost as a result of the irrigation project:
10,000,000 m² × (0.5 m³/s - 0.175 m³/s) × 31,536,000 s/year = 4,422,480,000 m³/year
To calculate the amount of water that is lost through evapotranspiration from the irrigated area, we need to know the crop coefficient and the reference evapotranspiration (ET0) for the area. However, since this information is not provided in the question, we cannot calculate the exact value of evapotranspiration from the irrigated area.
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Find the rate of change of the volume of a cube with respect to the length of its side when =11
When s = 11, the rate of change of the volume of the cube with respect to the length of its side is 363 cubic units per unit change in side length.
To find the rate of change of the volume of a cube with respect to the length of its side, we need to differentiate the volume formula with respect to the side length.
Let's denote the side length of the cube as "s" and the volume as "V."
The volume of a cube is given by the formula V = s³.
To find the rate of change of V with respect to s, we differentiate V with respect to s:
dV/ds = 3s².
Now, if we substitute s = 11 into the expression, we can find the rate of change at that specific value:
dV/ds = 3(11)²
= 3(121)
= 363.
Therefore, when s = 11, the cube's volume changes at a rate of 363 cubic units for every unit increase or decrease in side length.
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which chemical equation obeys the law of conservation of mass
Answer:
C3H6OH + 5O3 = 5CO2 + 6H3O
Explanation:
State the basic assumptions of the kinetic theory.
a- All matter is composed of small particles;
b- The particles are in constant motion;
c- Molecules are smaller than atoms.
d- The energy lost in the collisions is negligible.
e- These particles are constantly colliding;
i need help so fast pls im in a exam !!!
Answer:
option a
Explanation:
a- All matter is composed of small particles.
Explanation:
The following are the basic assumptions of the Kinetic Molecular Theory: The volume occupied by the individual particles of a gas is negligible compared to the volume of the gas itself. ... Gas particles are in a constant state of random motion and move in straight lines until they collide with another body.
A cyclotron designed to accelerate protons has a magnetic field of magnitude 0.450 T over a region of radius 2.20 m.
(a) What is the cyclotron frequency?
(b) What is the maximum speed acquired by the protons?
A cyclotron that uses a magnetic field of 0.450 T within a 2.20 m radius to accelerate protons has:
(a) the cyclotron frequency is approximately 4.42 x 10^7 Hz.
(b) the maximum speed is approximately 3.29 x 10^7 m/s.
What is (a) the frequency and (b) maximum velocity of protons in a cyclotron with a 0.450 T magnetic field over a 2.20 m radius?(a) The cyclotron frequency is given by the equation:
f = qB/(2πm)
where f is the frequency, q is the charge of the particle, B is the magnetic field, and m is the mass of the particle.
For protons, q = 1.60 x 10^-19 C and m = 1.67 x 10^-27 kg. Substituting these values and the given magnetic field, we have:
f = (1.60 x 10^-19 C)(0.450 T)/(2π)(1.67 x 10^-27 kg) ≈ 4.42 x 10^7 Hz
Therefore, the cyclotron frequency is approximately 4.42 x 10^7 Hz.
(b) The maximum speed acquired by the protons can be found using the equation for the kinetic energy of a particle:
K = 1/2 mv^2
where K is the kinetic energy, m is the mass of the particle, and v is the speed.
In a cyclotron, the magnetic field is used to accelerate the particles in a circular path. The radius of this circular path is given by:
r = mv/(qB)
where r is the radius of the circular path, m is the mass of the particle, v is the speed, q is the charge of the particle, and B is the magnetic field.
Since the protons are accelerated in a circular path, the kinetic energy gained by the particles is converted into an increase in speed. At the maximum speed, the kinetic energy gained by the protons is equal to the potential energy gained in crossing the voltage gap between the dees of the cyclotron. This is given by:
K = qV
where V is the voltage gap between the dees.
Setting K = qV and substituting the equation for r, we have:
qV = 1/2 mv^2
qV = 1/2 m(v^2B^2)/(q^2B^2)
qV = 1/2 mv^2/(qB)
v = (2qV)/(mB^2)
Substituting the given values, we have:
v = (2)(1.60 x 10^-19 C)(10 kV)/(1.67 x 10^-27 kg)(0.450 T)^2 ≈ 3.29 x 10^7 m/s
Therefore, the maximum speed acquired by the protons is approximately 3.29 x 10^7 m/s.
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A cheetah has 5 joules of kinetic energy and runs up a 5 m hill. When it gets to the top of the hill, it stops. What is the gravitational potential energy of the cheetah?
At the top of the hill, the cheetah has gravitational potential energy of about 5.02 joules. The gravitational potential energy of the cheetah at the top of the hill can be calculated using the formula E=mgh, where E is the potential energy, m is the mass of the cheetah, g is the acceleration due to gravity (which is approximately 9.8 m/s^2), and h is the height of the hill.
Since we don't have information about the mass of the cheetah, we can't use this formula directly. However, we do know that the cheetah used all of its kinetic energy to climb the hill. So, we can use the fact that the work done by the cheetah to climb the hill (which is equal to its initial kinetic energy) is equal to the change in gravitational potential energy:
W = ΔE
where W is the work done and ΔE is the change in energy.
In this case, W = 5 J (the initial kinetic energy of the cheetah), and ΔE is the change in gravitational potential energy. Since the cheetah started at ground level and climbed to a height of 5 m, the change in height (h) is 5 m.
So, we can calculate the gravitational potential energy of the cheetah as:
ΔE = mgh
5 J = m(9.8 m/s^2)(5 m)
Solving for m, we get:
m = 0.102 kg
Now that we know the mass of the cheetah, we can use the formula E=mgh to calculate the gravitational potential energy:
E = (0.102 kg)(9.8 m/s^2)(5 m)
E = 5.02 J
Therefore, the gravitational potential energy of the cheetah at the top of the hill is approximately 5.02 joules.
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A bolt on a car engine must be tightened with a torque of 35 N.m. you use a 25 cm long wrench and
pull the end of the wrench at an angle of 60.0 degree to the handle of the wrench.
How long is the lever arm?
(Hint: L=r sine)
How much force must you
exert?
(Hint: T= F.r sine)
How much torque is needed
to be applied on the bolt to
keep it at equilibrium? in
which direction?
To tighten the bolt to 35 Nm, a force of 2.03 N must be exerted with a lever arm of 21.65 cm. The required torque is 44.03 Ncm in the clockwise direction.
Given that the torque required to tighten the bolt is 35 Nm, the length of the wrench is 25 cm and the angle between the handle and the wrench is 60 degrees. We need to find the lever arm, the force to be exerted, the torque needed to be applied, and its direction. We will use the following formulas to solve the problem.Lever Arm: L = r sin θwhere L is the lever arm, r is the length of the wrench and θ is the angle between the wrench and the handle.L = 25 sin 60° = 21.65 cmForce: F = T/r sin θ, where F is the force, T is the torque, and r and θ are defined as earlier. F = (35 Nm) / (25 cm sin 60°) = 2.03 N. Required Torque: T = F x L, where T is the required torque and F and L are defined as earlier.T = (2.03 N) (21.65 cm) = 44.03 N cmThe direction of the torque needed to be applied on the bolt to keep it in equilibrium is clockwise since the wrench is rotated in a clockwise direction. Therefore, to tighten the bolt to 35 Nm, a force of 2.03 N must be exerted on the wrench, which has a lever arm of 21.65 cm. A torque of 44.03 Ncm must be applied in the clockwise direction.For more questions on torque
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A student has been assigned to measure the density of an irregularly shaped piece of metal.which apparatus would be more appropriate to carry out this task
Complete Question:
A student has been assigned to measure the density of an irregularly shaped piece of metal.
Which apparatus would be most appropriate to carry out this task?
Group of answer choices
A. ruler, balance
B. beaker, crucible
C. flask, Bunsen burner
D. graduated cylinder, balance
Answer:
D. graduated cylinder, balance
Explanation:
In this scenario, A student has been assigned to measure the density of an irregularly shaped piece of metal.
The apparatus which would be most appropriate to carry out this task is a graduated cylinder and balance.
A graduated cylinder can be defined as a measuring cylinder used for the measurement of the volume of an irregularly shaped piece of metal or liquids. It is typically marked with horizontal lines on its side as units of measurement for volume. The balance is then used to weigh the metals mass.
Figure 5 shows a ray of light in an optical fibre.
Figure 5
Inside of optical fibre
What is the name given to the dotted line on Figure 5?
[1 mark]
The technology that sends information as light pulses via a glass or plastic fiber is known as fiber optics, or optical fiber. These glass fibers can range in quantity from a few to several hundred in a fiber optic cable. The glass fiber core is encircled by yet another glass layer known as cladding.
What fiber optics does and how it works?In fiber optics, data is sent as pulses of light, or photons, that travel over a fiber optic cable. Incoming light is bent at a specific angle due to the differing refractive indices of the glass fiber core and cladding.
Total internal reflection is the method by which light signals traveling through fiber optic cable bounce off the core and cladding in a series of zigzag motions. Due to the thick glass layers, the light signals move around 30% slower than the speed of light instead of at the speed of light.
Fiber optic transmission sometimes needs repeaters at a distance to renew, or amplify, the signal throughout its path. By converting the optical signal to an electrical signal, processing that electrical signal, and then retransmitting the optical signal, these repeaters regenerate the optical signal.
Up to 10 Gbps transmissions can currently be supported by fiber optic connections. A fiber optic cable often gets more expensive as its bandwidth capacity increases.
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A cart is travelling at 0.85 m/s for 1.5 seconds. How far does the cart travel?
Answer:
1.275 meters
rounded to 1 decimal place(s): 1.3 meters
rounded to 2 decimal place(s): 1.28 meters
Explanation:
Use the formula for distance
d = speed x time
0.85 x 1.5 = 1.275
1.275 m
Answer: 1.275 m
Explanation:
It is given that,
Velocity is 0.85 m/s
Time is 1.5 s
The equation for distance is d=vt, so:
d=vt
d=(0.85)(1.5)
d=1.275 m
Why is the searching of the houses done by the poorer whites of the community?
The searching of houses is often done by the poorer whites of the community due to various socio-economic factors and cultural norms.
In some instances, this practice might have evolved out of necessity, as lower-income individuals may have limited job opportunities and are therefore more likely to take up tasks like house searching to earn a living. Additionally, these searches could be driven by the concept of social capital, where poorer individuals may be more integrated into local networks and thus are more likely to possess detailed information about their community. This familiarity allows them to navigate the neighborhood effectively and locate specific houses with ease, making them well-suited for such tasks.
Furthermore, social hierarchies and historical context can also play a role in determining why poorer whites are involved in house searching. In certain areas, there may be a cultural expectation for individuals of lower socioeconomic status to perform such tasks as a form of service to the community, reflecting traditional power dynamics. In summary, the searching of houses by the poorer whites of the community can be attributed to factors such as limited job opportunities, social capital, and historical and cultural norms that reinforce the role of individuals from lower socioeconomic backgrounds in carrying out these tasks.
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a round asteroid has a surface gravity of 0.0288
If the mass of the asteroid is 1.10x10^18 kg, what is its radius??
Answer:
50473.45
Explanation:
(6.67×10^-11)(1.10×10^18)/(x)^2=0.0288.
answer: 5.047345 × 10^4 (50473.45)
give examples of bottom-up processing from your everyday life
bottom-up processing is a cognitive process that involves perceiving and understanding information based on individual sensory stimuli. examples of bottom-up processing in everyday life include recognizing objects based on their color, shape, and texture, identifying sounds based on their pitch, volume, and timbre, and perceiving tastes and textures based on individual flavors and tactile sensations.
bottom-up processing is a cognitive process that involves perceiving and understanding information based on the individual sensory stimuli. It refers to the way our brains make sense of the world by analyzing the basic features of stimuli and building up a complete perception.
In everyday life, we encounter numerous examples of bottom-up processing. For instance, when we see a new object, our brain processes its individual features such as color, shape, and texture, and then combines them to form a complete perception of the object. This allows us to recognize and understand the object without prior knowledge or expectations.
Similarly, when we hear a new sound, our brain analyzes its pitch, volume, and timbre to recognize and understand the sound. This enables us to differentiate between different sounds and identify their sources.
Bottom-up processing is also involved in other sensory experiences. When we taste a new food, our brain processes the individual flavors and textures to form a perception of the taste. Similarly, when we touch different textures, our brain analyzes the tactile sensations to understand the texture.
In summary, bottom-up processing plays a crucial role in our everyday lives by allowing us to perceive and understand the world around us based on the individual sensory stimuli we encounter.
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In consideration of the above diagram, a projectile is launched at 45 with an initial horizontal velocity (V0x) of 3 m/s. Calculate the Vox which is the actual launch velocity at 45 in m/s.
CFISD too huh? :D
also tryna get the answer
A ball of mass 0.12kg is hit by a tennis player. The velocity of the ball changes from 0m/ s to 5.0m/s in 0.60s. What is the average resultant force acting on the ball while it is being hit?
A 1.0N B 2.5N C 3.6N D 8.3N
(Please add explanation)
Answer:
A. 1.0NExplanation:
According to Newton's second law
F = ma
m is the mass = 0.12kg
a is the acceleration = v-u/t
a = 5-0/0.6
a = 5/0.6
a = 8.333m/s²
Get the force
F = 0.12 * 8.333
F = 1.0N
Hence the average resultant force acting on the ball while it is being hit is 1.0N
An athlete runs around a circular track of radius 50 m and finishes at the same point where he began his journey. His total displacement in metre(s) is evaluated to be
Answer:
Explanation:
His displacement is 0 because he ended up exactly where he started.
a motorboat is headed at a velocity of 25 kilometers/hour toward the north, while the velocity of the water current is 12 kilometers/hour to the west. what is the magnitude of the boats resultant velocity
The magnitude of the boat's resultant velocity will be 13 kilometers/hour.
What is velocity?The change of distance with respect to time is defined as speed. Speed is a scalar quantity. It is a time-based component. Its unit is kilometers/hour.
The magnitude of the boat's resultant velocity is found as;
\(\rm V_{resultant}=V_{north}-v_{west} \\\\ \rm V_{resultant}= 26 km/h - 12 km/h \\\\ V_{resultant}=13 \ km/h\)
Hence, the magnitude of the boat's resultant velocity will be 13 kilometers/hour.
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