Answer:
The range of the projectile is 60 m
Explanation:
Horizontal Motion
When an object is thrown horizontally with a speed vo from a height h, it describes a curved path ruled exclusively by gravity until it eventually hits the ground.
The horizontal component of the velocity is always constant because no acceleration acts in that direction, thus:
\(v_x=v_o\)
The vertical component of the velocity changes in time because gravity makes the object fall at increasing speed given by:
\(v_y=g.t\)
The horizontal distance is calculated as a constant speed motion:
\(x = v_x.t\)
Knowing the crossbow is fired horizontally at vo=vx=15 m/s and it takes t=4 s to hit the ground, thus the range of the projectile is:
x = 15*4 = 60
The range of the projectile is 60 m
A sphere of mass 15 kg possess kinetic energy of 1200 J. Calculate its
velocity
Answer:
12.65 Meters / Second (m/s)
Explanation:
the problem is really easy to solve, we begin by stating the kinetic energy formula which is:
KE = (1/2)(mass)(velocity)^2
We equate 1200 J to the formula, substitute the mass, and solve for velocity either using a CAS, app, or by hand
1200J = (0.5)(15kg)v^2
v = 12.65 m/s
estimate the work you do to mow a lawn 10m by 20m with a 50 cm wide mower. Assume you push with a force of about 15 N.
Answer:
W = 6000 Joule
Explanation:
Work is defined as force times distance
W = F * d
We know that F = 15N, we just need the distance (d)
Imagine you have a square lawn with length of 10 m and width of 20m. So, we want to know the the distance you have to travel to cover every square meter of the lawn.
The width of the mower is only 50 cm = 0.5 m.
This means that you have to go back and forth 40 times to cover 20m (lawn width), with a distance of 10 m (lawn length). So,
d = 10 (meter) * 40 (times) = 400 meter
Therefore:
W = (15) * (400) = 6000 J
Mrs Turner has a scale drawing of her apartment.IN the scale drawing the lenght of her apartment is 6.25 inches and the width is 2.75 onches. If Mrs. Turner used the scale factor 1 inc/18ft, what would the area of the apartment be?
The area of Mrs. Turner's apartment is approximately 0.05304 square feet.
To find the area of Mrs. Turner's apartment, we need to convert the measurements from the scale drawing to the actual measurements in feet, using the given scale factor of 1 inch/18 feet.
Length of apartment in feet = 6.25 inches × (1 foot/18 inches) = 0.34722 feet
Width of apartment in feet = 2.75 inches × (1 foot/18 inches) = 0.15278 feet
Now, we can calculate the area of the apartment in square feet by multiplying the length and width:
Area of apartment in square feet = Length × Width = 0.34722 feet × 0.15278 feet = 0.05304 square feet
Therefore, the area of Mrs. Turner's apartment is approximately 0.05304 square feet.
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At this point, you have learned that heat is the ________ of ________ energythat is possessed by an object due to the motion of its particles. When this happens, an object’s ____________ changesfrom cool to warmer.There are ways of heat transfer: (a) ____________, where heat is transferred between materials that are in direct contact with each other. While (b) ____________, occurs when heat is transferred by electromagnetic waves (through space). And lastly, (c) ____________is transfer of heat in fluids which makesthe hot fluids to rise and cold fluidstosink
To practice Problem-Solving Strategy 11.1 Equilibrium of a Rigid Body. A horizontal uniform bar of mass 2.7 kg and length 3.0 m is hung horizontally on two vertical strings. String 1 is attached to the end of the bar, and string 2 is attached a distance 0.6 m from the other end. A monkey of mass 1.35 kg walks from one end of the bar to the other. Find the tension T1 in string 1 at the moment that the monkey is halfway between the ends of the bar.
Answer:
\(T_{1}\) = 14.88 N
Explanation:
Let's begin by listing out the given variables:
M = 2.7 kg, L = 3 m, m = 1.35 kg, d = 0.6 m,
g = 9.8 m/s²
At equilibrium, the sum of all external torque acting on an object equals zero
τ(net) = 0
Taking moment about \(T_{1}\) we have:
(M + m) g * 0.5L - \(T_{2}\)(L - d) = 0
⇒ \(T_{2}\) = [(M + m) g * 0.5L] ÷ (L - d)
\(T_{2}\) = [(2.7 + 1.35) * 9.8 * 0.5(3)] ÷ (3 - 0.6)
\(T_{2}\)= 59.535 ÷ 2.4
\(T_{2}\) = 24.80625 N ≈ 24.81 N
Weight of bar(W) = M * g = 2.7 * 9.8 = 26.46 N
Weight of monkey(w) = m * g = 1.35 * 9.8 = 13.23 N
Using sum of equilibrium in the vertical direction, we have:
\(T_{1}\) + \(T_{2}\) = W + w ------- Eqn 1
Substituting T2, W & w into the Eqn 1
\(T_{1}\) + 24.81 = 26.46 + 13.23
\(T_{1}\) = 14.88 N
In the figure; two point sources S1 and S2, Which are in phase and emit identical sound waves of wavelength 2.0 m: The length L1 = 21 m. A listener stands at point P: Assume the amplitude of individual sound reaching at point P does not change, the sound that the listener hears willl be least intense if the L2 is
The length L₂ for destructive interference is L₂ = 22 m
What is a sound wave?A sound wave is a mechanical wave which carries sound energy from one point to another.
How to find the point L2?Since two point sources S₁ and S₂, Which are in phase and emit identical sound waves of wavelength 2.0 m: The length L₁ = 21 m. A listener stands at point P: Assume the amplitude of individual sound reaching at point P does not change, to find L₂, we need to know the path difference for destructive interference.
What is path difference for destructive interference?The path difference for destructive interference is given by ΔL = (n + 1)λ/2
where
ΔL = path difference = L₂ - L₁, λ = wavelength and n is an integer.Since we require the least intensity, we have the minimum interference. So, n = 0.
So, ΔL = (n + 1)λ/2
ΔL = (0 + 1)λ/2
L₂ - L₁ = λ/2
So, making L₂ subject of the formula, we have
L₂ = L₁ + λ/2
Given that
L₁ = 21 mλ = 2.0 mSubstituting the values of the variables into the equation, we have that
L₂ = L₁ + λ/2
L₂ = 21 m + 2.0 m/2
L₂ = 21 m + 1 m
L₂ = 22 m
So, the length L₂ = 22 m
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a pick up truck weighing 1200 kg is pulling a boat weighing 1500 kg by applying a force of 2000 N in the north direction. What is the force that the boat
The force that the boat exerted back on the truck is 2000 N in south direction.
What is Newton's third law of motion?
Newton's third law of motion states that, for every action, there is an equal and opposite reaction.
Mathematically, Newton's third law of motion can be expressed as follows;
Fa = -Fb
where;
Fa is the force applied by object A on object BFb is the reaction of object B due to the force exerted by object AThe magnitude of both forces are equal but the direction is different.
The given parameters;
mass of the truck, m1 = 1200 kgmass of the boat, m2 = 1500 kgforce exerted by the truck, f1 = 2000 N northforce exerted by the boat, f2 = ?If the force exerted on the boat by the truck = 2000 N north, the reaction of the boat will 2000 N south direction.
Thus, the force that the boat exerted back on the truck is 2000 N in south direction.
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The complete question is below:
a pick up truck weighing 1200 kg is pulling a boat weighing 1500 kg by applying a force of 2000 N in the north direction. What is the force that the boat exerted on the truck?
A 3.0-kilogram object initially at rest explodes and splits into three fragments. One fragment has a mass of 0.50 kg and flies off along the negative x axis at a speed of 2.8 m/s, and another has a mass of 1.3 kg and flies off along the negative y axis at a speed of 1.5 m/s.
Required:
What are the speed and direction of the third fragment?
Answer:
The speed and direction of the third fragment are 2 meters per second and 54.316º, respectively.
Explanation:
The object is not under the influence of any external force, meaning that Principle of Momentum Conservation to calculation of the velocity of the third fragment:
\((m_{1}+m_{2}+m_{3})\cdot \vec {v}_{o} = m_{1}\cdot \vec v_{1} + m_{2}\cdot \vec v_{2} + m_{3}\cdot \vec v_{3}\) (1)
Where:
\(m_{1}\), \(m_{2}\), \(m_{3}\) - Masses of the first, second and third fragments, in kilograms.
\(\vec v_{o}\) - Initial velocity of the object, in meters per second.
\(\vec v_{1}\), \(\vec v_{2}\), \(\vec v_{3}\) - Velocities of the first, second and third fragments, in meters per second.
If we know that \(m_{1} = 0.5\,kg\), \(m_{2} = 1.3\,kg\), \(m_{3} = 1.2\,kg\), \(\vec v_{o} = (0,0)\,\left[\frac{m}{s} \right]\), \(\vec v_{1} = \left(-2.8, 0\right)\,\left[\frac{m}{s} \right]\) and \(\vec v_{2} = \left(0,-1.5\right)\,\left[\frac{m}{s} \right]\), the velocity of the third fragment is:
\((-1.4,0) + (0,-1.95) + 1.2\cdot \vec v_{3} = (0,0)\)
\(1.2\cdot \vec v_{3} = (1.4,1.95)\)
\(\vec v_{3} = (1.167, 1.625)\,\left[\frac{m}{s} \right]\)
The speed of the third fragment is the magnitude of the result found above:
\(v_{3} = 2\,\frac{m}{s}\)
And the direction of the third fragment is:
\(\theta_{3} = \tan^{-1} \left(\frac{1.625}{1.167}\right)\)
\(\theta_{3} \approx 54.316^{\circ}\)
The speed and direction of the third fragment are 2 meters per second and 54.316º, respectively.
2.) Assume you decided to build a cabin off the electrical grid in a remote region of the United States, and your cabin would require 720 kWh per month to easily meet your needs. You decide to produce your electricity using photovoltaic cells and store it using a battery system so that it is available when you wish to use it. If every photovoltaic cell has the potential to produce 0.25 kilowatts (250 watts), and they produced electricity for 24 hours a day, how many photovoltaic cells would you need to meet your electricity needs for a month
Answer:
4 photovoltaic cells are required to meet monthly energy consumption of the cabin.
Explanation:
Let suppose that PV generation system produces energy at constant energy, the number of photovoltaic system to meet energy consumption of the cabin is:
\(n = \frac{E}{\dot E \cdot t}\) (1)
Where:
\(E\) - Energy consumption of the PV system, in kilowatt-hours.
\(\dot E\) - Power generation of the PV cell, in kilowatts.
\(t\) - Working times, in hours.
If we know that \(E = 720\,kWh\), \(\dot E = 0.25\,kW\) and \(t = 720\,h\), then the number of photovoltai cells is:
\(n = \frac{E}{\dot E \cdot t}\)
\(n = 4\)
4 photovoltaic cells are required to meet monthly energy consumption of the cabin.
What is the impact of the imagery used in paragraph six on the meaning of "On a Mountain Trail"?
The impact of the imagery used in paragraph six on the meaning of "On a Mountain Trail" emphasizes the fear and uncertainty of the narrator as the pack surrounds the sleigh on the trail.
The imagery in paragraph 6 paints a vivid and powerful picture of a pack of wolves surrounding the sled. Because of the narrator's inability to count the number of wolves present, this description adds to the feeling of anxiety and uncertainty. The scene reinforces the emotional impact of the scene and helps convey the protagonist's sense of vulnerability and danger.
Therefore, the correct option is C.
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Fig above shows a wave traveling through a medium. Use the fig to answer the questions below.
A.)What is the amplitude of the wave ? Include correct units.
B.)Use the graph to determine the time of one wave. Use it to find the frequency.
C.)If the speed of the wave is 25 m/s, what is the wavelength of the wave ? Show data listing, equation , substitution leading to the answer for full credit.
(a) The amplitude of the wave is 0.2 m.
(b) The period of the wave is 4 s.
(c) The wavelength of the wave is 100 m.
What is the amplitude of the wave?(a) The amplitude of the wave is the maximum displacement of the wave.
amplitude of the wave = 0.2 m
(b) The period of the wave is the time taken for the wave to make one complete cycle.
period of the wave = 5.5 s - 1.5 s = 4 s
(c) The wavelength of the wave is calculated as follows;
λ = v / f
where;
v is the speed of the wavef is the frequency of the wavef = 1/t = 1 / 4s = 0.25 Hz
λ = ( 25 m/s ) / 0.25 Hz
λ = 100 m
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The molecules of a gas are in constant random motion. This means that they have energy in what type of energy store?
Answer:
Heat causes the molecules to move faster, (heat energy is converted to kinetic energy ) which means that the volume of a gas increases more than the volume of a solid or liquid.
Explanation:
What is the economic term for the act of sacrificing one good or service to purchase or produce another?
Answer:
Trade-off. sacrificing one good or service to purchase or produce another.What are 2 sources of proteins?
What would happen if one of the four-stroke combustion cycle parts never worked?
Answer:
An internal-combustion engine goes through four strokes: intake, compression, combustion (power), and exhaust. As the piston moves during each stroke, it turns the crankshaft.
Answer:
The engine will not work causing no movement in the wheels .
Explanation:
Remember the four stroke combustion cycle powers the wheels and if one of these parts do not work, then the car will not move .
a car in stop-and-go traffic starts at rest, moves forward 25 m m in 8.0 s s , then comes to rest again. the velocity-versus-time plot for this car is given in the figure
A velocity-time graph's area under the curve represents the distance traveled. In the first 4.8 meters of its velocity, it travels a distance of 4 seconds.
What are velocity and speed?In contrast to velocity, which describes the speed and direction of an object's movement, speed is the rate of movement along a path. Instead, velocity is a vector while speed is a scalar quantity.
Is speed always equal to velocity?Individuals may mistakenly believe that average speed and average velocity are merely two different names for the same quantity, but in reality, average speed depends on distance and average velocity depends on displacement. if something is moving in a different direction.
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Which observation is evidence that electromagnetic radiation (EMR) has particle-like
properties? (1 point)
O EMR refracts as it moves into a different medium.
O
A diffraction pattern is observed when EMR passes through a narrow slit.
O Some EMR is blocked when it passes through a polarized lens.
O EMR with energy above a certain value can eject electrons out of a metal.
The observation that electromagnetic radiation with energy above a certain value can eject electrons out of a metal is a piece of evidence that they have particle-like properties.
Electromagnetic radiations as particlesThe observation that electromagnetic radiation with energy above a certain value can eject electrons out of a metal is a piece of evidence that they have particle-like properties.
This observation that electromagnetic radiation behaves like particles is known as the photoelectric effect.
It provides evidence that electromagnetic radiation exhibits particle-like properties. When EMR with sufficient energy (above a certain threshold) interacts with a metal surface, it can cause the ejection of electrons from the metal.
This behavior indicates that EMR behaves as discrete packets of energy called photons, which transfer their energy to the electrons and cause their release. The photoelectric effect supports the particle nature of EMR and is a fundamental concept in the field of quantum mechanics.
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Why is DNA a useful evolutionary clock?
A boy slides a book across the floor, using a force of 5 N over a distance of 2
m. What is the kinetic energy of the book after he slides it? Assume there is
no friction.
A. 5 J
B. 10 J
C. 20 J
D. 2.5 J
SUBMIT
The kinetic energy of the book after it is slids a distance of 2 meters will be 10 Joules.
How to determine the kinetic energy of an object?The work-energy theorem states that "the work done on an object is the change in its kinetic energy".
Hence;
Kinetic energy = work done
Note that: work-done is expressed as:
Work done = f × d
Where f is force applied and d is distance traveled.
Given that:
Force applied f = 5 newton
Distance d = 2 meters
Work done = ?
Plug these values into the above formula and solve for the workdone.
Work done = f × d
Work done = 5N × 2m
Work done = 10Nm
Work done = 10 Joules
Therefore, the kinetic energy is 10 Joules.
Option B) 10 J is the correct answer.
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During a medieval siege of a castle, the attacking army uses a trebuchet to hurl heavy stones at the castle walls. If the trebuchet launches the stones with a velocity of +30.0m/s at an angle of 50.0°, how long does it take the stone to hit the ground? What is the maximum distance that the trebuchet can be from the castle wall to be in range? How high will the stones go? Show all your work.
(a) The time of motion of the stone is 4.69 seconds.
(b) The maximum distance the trebuchet can be from the castle wall to be in range is 90.44 m.
(c) The maximum height reached by the stone is 26.95 m.
What is the time of motion of the stone?
The time of motion of the stone is calculated as follows;
t = 2u sinθ / g
where;
u is the initial velocity of the stoneθ is the angle of projection of the stoneg is acceleration due to gravityt = (2 x 30 x sin50) / (9.8)
t = 4.69 seconds
The maximum distance the trebuchet can be from the castle wall to be in range is calculated as;
R = u²sin(2θ) / g
R = (30² sin(2 x 50))/(9.8)
R = 90.44 m
The maximum height reached by the stone is calculated as follows;
H = u² sin²θ / 2g
H = (30² x (sin 50)²) / (2 x 9.8)
H = 26.95 m
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A cube, whose edges are aligned with the , and axes, has a side length . The field is immersed in an electric field aligned with the axis. On the left and right faces, the field has a strength and , respectively. The field along the front and back faces has strengths and . The field at the bottom and top faces has strengths and , respectively. What is the total charge enclosed by the cube
Complete Question
Complete Question is attached below
Answer:
\(q=1.558*10^{-9}c\)
Explanation:
From the question we are told that:
Side length s=1.13m
Left field strength \(E_l=784.75N/m\)
Right field strength \(E_r=776.38 N/m\)
Front field strength \(E_f=725.5 N/m\)
Back field strength \(E_b=749.54 N/m\)
Top field strength \(E_t=944.95 N/m\)
Bottom field strength \(E_{bo}=1082.58 N/m\)
Generally, the equation for Charge flux is mathematically given by
\(\phi=EAcos\theta\)
Where
Theta for Right,Left,Front and Back are at an angle 90
\(cos 90=0\)
Therefore
\(\phi =0\) with respect to Right,Left,Front and Back
Generally, the equation for Charge Flux is mathematically also given by
\(\phi=\frac{q}{e_o}\)
Where
\(Area =L*B\\\\A=1.13*1.13\\\\A=1.2769m^2\)
Therefore
\(Q_{net}=E_{bo}Acos\theta_{bo} +E_tAcos\theta_t\)
\(Q_{net}=1082.85*1.2769*cos0=944.95*1.2769cos (180)\)
\(Q_{net}=176N/C m^2\)
Giving
\(q=\phi*e_0\)
\(q=176N/C m^2*1.558*10^{-12}c\)
\(q=1.558*10^{-9}c\)
Describe the motion of an object experiencing blueshift
A source travelling in the direction of the observer causes Doppler blueshift.
When an object is moving towards us, the light from the object is known as blueshift.
The phrase refers to any relative motion, that causes a decrease in the wavelength and rise in frequency, including those that take place outside of the visible spectrum.
During the motion of the object towards us, blueshift will happen, thus shifting light to shorter wavelengths on the blue side of the spectrum.
This causes the color to shift from the red to the blue end of the spectrum in visible light.
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A self-driving car traveling along a straight section of road starts from rest, accelerating at 2.00 m/s2 until it reaches a speed of 25.0 m/s. Then the vehicle travels for 39.0 s at constant speed until the brakes are applied, stopping the vehicle in a uniform manner in an additional 5.00 s.
(a) How long is the self-driving car in motion (in s)?
(b) What is the average velocity of the self-driving car for the motion described? (Enter the magnitude in m/s.) m/s
Answer:
\(56.5\ \text{s}\)
\(21.13\ \text{m/s}\)
Explanation:
v = Final velocity
u = Initial velocity
a = Acceleration
t = Time
s = Displacement
Here the kinematic equations of motion are used
\(v=u+at\\\Rightarrow t=\dfrac{v-u}{a}\\\Rightarrow t=\dfrac{25-0}{2}\\\Rightarrow t=12.5\ \text{s}\)
Time the car is at constant velocity is 39 s
Time the car is decelerating is 5 s
Total time the car is in motion is \(12.5+39+5=56.5\ \text{s}\)
Distance traveled
\(v^2-u^2=2as\\\Rightarrow s=\dfrac{v^2-u^2}{2a}\\\Rightarrow s=\dfrac{25^2-0}{2\times 2}\\\Rightarrow s=156.25\ \text{m}\)
\(s=vt\\\Rightarrow s=25\times 39\\\Rightarrow s=975\ \text{m}\)
\(v=u+at\\\Rightarrow a=\dfrac{v-u}{t}\\\Rightarrow a=\dfrac{0-25}{5}\\\Rightarrow a=-5\ \text{m/s}^2\)
\(s=\dfrac{v^2-u^2}{2a}\\\Rightarrow s=\dfrac{0-25^2}{2\times -5}\\\Rightarrow s=62.5\ \text{m}\)
The total displacement of the car is \(156.25+975+62.5=1193.75\ \text{m}\)
Average velocity is given by
\(\dfrac{\text{Total displacement}}{\text{Total time}}=\dfrac{1193.75}{56.5}=21.13\ \text{m/s}\)
The average velocity of the car is \(21.13\ \text{m/s}\).
Which is a force that attracts any two pieces of matter in the universe?
O weak
O static
O electromagnetic
O gravitational
Answer:
Gravitational
Explanation:
A Motorcycle Jump. You are planning to make a jump with your motorcycle by driving over a ramp that will launch you at an angle of 30.0° with respect to the horizontal. The front edge of the ramp on which you are supposed to land, however, is 25.0 ft lower than the edge of the launch ramp (i.e., your launch height).
(a) Assuming a launch speed of 55.0 mph, at what horizontal distance from your launch point should the landing ramp be placed?
(b) In order to land smoothly, the angle of the landing ramp should match the direction of your velocity vector when you touch down. What should be the angle of the landing ramp?
a. the landing ramp should be placed at 276.298 ft horizontally from the launch point.
(b) the angle of the landing ramp is 30°.
How do we calculate?(a)
Launch speed = 55.0 mph * (1.467 ft/s)
= 80.685 ft/s
Horizontal distance = Launch speed * Time of flight
Vertical velocity = Launch speed * sin(30.0°)
Time to reach maximum height = Vertical velocity / g
Vertical distance = (1/2) *g * t²
and Time = √(2 * Vertical distance / g)
Total time of flight = 2 * Time to reach maximum height + Time for descent
Horizontal distance = Launch speed * Total time of flight
The Vertical velocity = 80.685 ft/s * sin(30.0°)
= 40.3425 ft/s
Time to reach maximum height = 40.3425 ft/s / 32.2 ft/s²
Time to reach maximum height = 1.253 s
Time of descent = √(2 * 25.0 ft / 32.2 ft/s²)
Time of descent = 0.913 s
Total time of flight = 2 * 1.253 s + 0.913 s
Total time of flight = 3.419 s
In conclusion, the horizontal distance = 80.685 ft/s * 3.419 s
horizontal distance = 276.298 ft
b.
the angle of the landing ramp is 30.0 be the same as the launch angle.
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HELPPPPPPPPP please
Current can flow uphill in a:
light bulb
battery
flowing water conduit
resistor
Current cannot flow uphill in any of the listed options: a light bulb, a battery, a flowing water conduit, or a resistor. Hence option E) is the correct answer.
Current cannot flow uphill in any of the listed options: a light bulb, a battery, a flowing water conduit, or a resistor. In an electrical circuit, current is the flow of electric charge carried by electrons. Current flows in a closed loop, typically from the positive terminal of a power source (such as a battery) through the circuit components and back to the negative terminal. A light bulb, battery, flowing water conduit, and resistor all have specific roles within a circuit, but none of them allow current to flow uphill. In a circuit, current always flows from a higher electric potential to a lower electric potential. This is known as the direction of conventional current flow. In the case of flowing water, water flows downhill due to gravity, following the path of least resistance. Similarly, in an electrical circuit, current flows along the path of least resistance, from higher voltage (electric potential) to lower voltage. Therefore, option E) is the correct answer current does not flow uphill in any of the mentioned options.
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Note Complete Question
Current can flow uphill in a:
A)light bulb
B)battery
C)flowing water conduit
D)resistor
E) none of the above
Identical particles are placed at the 50-cm and 80-cm marks on a meter stick of negligible mass. This rigid body is then mounted so as to rotate freely about a pivot at the 0-cm mark on the meter stick. If this body is released from rest in a horizontal position, what is the angular speed of the meter stick as it swings through its lowest position
Answer:
5.35 rad/s
Explanation:
From the question, we are toldthat an Identical particles are placed at the 50-cm and 80-cm marks on a meter stick of negligible mass. This rigid body is then mounted so as to rotate freely about a pivot at the 0-cm mark on the meter stick.
Solving this question, the potential energy of the particles must equal to the Kinectic energy i.e
P.E=K.E
Mgh= m½Iω²-------------eqn(*)
Where M= mass of the particles
g= acceleration due to gravity= 9.81m/s^2
ω= angular speed =?
h= height of the particles in the stick on the metre stick= ( 50cm + 80cm)= (0.5m + 0.8m)= 130cm=1.3m
If we substitute the values into eqn(*) we have
m×9.81× (1.3m)= 1/2× m×[ (0.5m)² + [(0.8m)²]× ω²
m(12.74m²/s²)= 1/2× m× (0.25+0.64)× ω
m(12.74m²/s²)= 1/2× m× 0.89× ω²
We can cancel out "m"
12.74= 1/2×0.89 × ω²
12.74×2= 0.89ω²
25.48= 0.89ω²
ω²= 28.629
ω= √28.629
ω=5.35 rad/s
Hence, the angular speed of the meter stick as it swings through its lowest position is 5.35 rad/s
what is the physics behind why electric parallel plates move from positive to negative
The physics behind the movement of electric charges between parallel plates is based on the principles of electrostatics. Electric charges are either positive or negative, and they are affected by electric fields.
Electric fields are created by a difference in electric potential, which is measured in volts. When a voltage is applied to a set of parallel plates, the charges within the plates will be affected by the electric field, and will move in response to it.
What are electric parallel plates?When a voltage is applied to a set of parallel plates, the positive charges in the plate connected to the positive voltage will be attracted to the negative voltage, while the negative charges in the plate connected to the negative voltage will be attracted to the positive voltage.
The movement of charges between the plates is also affected by the presence of any obstacles or resistances in the electric field, such as resistance in the wire. This can slow down the movement of charges and result in a decrease in the current flowing through the circuit.
In all, the movement of charges between electric parallel plates is the result of the electric field created by a difference in electric potential, and the movement of charges is called drift velocity. The movement is also affected by the presence of resistance.
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Answer:
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Explanation:
A car can go from 0 m/s to 27 m/s in 4.5 seconds. If a net force of 6600 N acted on the car, what is its mass? (Hint: You must first calculate the acceleration then plug into Newton’s second law.)
Answer:
1100 kg
Explanation:
acceleration:
\(a=(27-0)/4.5\)
\(a=6ms^{-2}\)
Newton's second law:
\(F=ma\)
\(6600=6m\\m=1100 kg\)