A criterion is required for selecting a material with the lowest cost in a strength-limited design for a cylindrical tie rod. Write the objective statement. Derive the criterion and identify the material index. The length of the tie rod, L, is fixed.

Answer:

The greatest mass, that the weight C can have such that block A does not move is approximately 23.259 kg

Explanation:

The given parameters are;

The mass of the block A= 58 kg

The coefficient of static friction between the block and the surface, \(\mu _s\) = 0.300

The coefficient of static friction between the rope and the fixed peg, B \(\mu _B\) = 0.310

Let T represent the tension in the rope

Therefore, when the rope is static, T = The normal reaction at the peg, B, \(N_B\)

The angle of inclination of the rope holding the block A = arctan(3/4) ≈ 36.87°

The length of the rope = √(0.4² + 0.3²) = 0.5

∴ sin(θ) = 3/5 = 0.6

cos(θ) = 4/5 = 0.8

The vertical component of the tension in the rope = T × sin(θ) = 0.6·T

The horizontal component of the tension in the rope = T × cos(θ) = 0.8·T

The friction force = μ×(W - 0.6·T) = 0.300×(58×9.8 - 0.6·T) = 170.52 - 0.18·T

The block will start to move when we have;

The horizontal component of the tension in the rope = The friction force

∴ 0.8·T = 170.52 - 0.18·T

0.8·T + 0.18·T = 170.52

0.98·T = 170.52

T = 170.52/0.98 = 174

Therefore, the tension in the rope = T = 174 N = The normal reaction at the peg, B \(N_B\)

The frictional force at the peg, \(F_B\) = \(\mu _B\) × \(N_B\) = 0.310 × 174 N = 53.94 N

The weight of the mass, \(m_c\), \(W_c\) = The frictional force at the peg, \(F_B\)  + The tension in the rope

∴ The weight of the mass, \(m_c\), \(W_c\) = 53.94 N + 174 N = 227.94 N

Weight, W = Mass, m × The acceleration due to gravity, g, from which we have;

m = W/g

Where;

g = 9.8 m/s²

∴ \(m_c\) = \(W_c\)/g = 227.94 N/(9.8 m/s²) ≈ 23.259 kg.

The greatest mass, that the weight C can have such that block A does not move = \(m_c\) ≈ 23.259 kg.

Answer:

False.

Explanation:

Employees working with dangerous machines and hazardous energy are required to know and follow LOTO procedures in order to ensure the safety of themselves and fellow employees. Employers are also required to train employees in LOTO procedures to ensure they know, understand, and are able to follow the applicable provisions of LOTO procedures.

The use of the 'what-if' function in MS Excel makes a decision a type of forecast and scenario model.

In MS Excel, the 'what-if' function allows changing the values in cells to check to see how those changes affect the outcome of formulas on the worksheet. When the 'what-if' function of Excel is used to check different outcomes of decisions based on different values on input, it is considered a type of forecast and scenario model.  The forecast and scenario model depicts a strategic method for businesses that is used to plan various potential futures. These scenarios are forecasted on the basis of visible risks and assumed uncertainties existing in a set of plausible situations. In short, it can be said that it helps to model multiple 'what-if' scenarios to be prepared for the future.

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Answer:

It made information easily accessible and ensured individuals became more vast in subject topics of interest.

Explanation:

Information revolution is different and unique and it came with the advent of computers and the internet. A lot of information is stored there which is too large and complex for the human brain.This helped people to access information without much stress as informations about almost every subject is on the Internet.

Individuals can check the informations up and become more vast in interested topics.

Answer:

1) The three possible assumptions are

a) All processes are reversible internally

b) Air, which is the working fluid circulates continuously in a closed loop

cycle

c) The process of combustion is depicted as a heat addition process

2) The diagrams are attached

5) The net work per cycle is 845.88 kJ/kg

The power developed in horsepower ≈ 45374 hP

Explanation:

1) The three possible assumptions are

a) All processes are reversible internally

b) Air, which is the working fluid circulates continuously in a closed loop

cycle

c) The process of combustion is depicted as a heat addition process

2) The diagrams are attached

5) The dimension of the cylinder bore diameter = 3.7 in. = 0.09398 m

Stroke length = 3.4 in. = 0.08636 m.

The volume of the cylinder v₁= 0.08636 ×(0.09398²)/4 = 5.99×10⁻⁴ m³

The clearance volume = 16% of cylinder volume = 0.16×5.99×10⁻⁴ m³

The clearance volume, v₂  = 9.59 × 10⁻⁵ m³

p₁ = 14.5 lbf/in.² = 99973.981 Pa

T₁ = 60 F = 288.706 K

\(\dfrac{T_{2}}{T_{1}} = \left (\dfrac{v_{1}}{v_{2}} \right )^{K-1}\)

Otto cycle T-S diagram

T₂ = 288.706*\(6.25^{0.393}\) = 592.984 K

The maximum temperature = T₃ = 5200 R = 2888.89 K

\(\dfrac{T_{3}}{T_{4}} = \left (\dfrac{v_{4}}{v_{3}} \right )^{K-1}\)

T₄ = 2888.89 / \(6.25^{0.393}\) = 1406.5 K

Work done, W = \(c_v\)×(T₃ - T₂) - \(c_v\)×(T₄ - T₁)

0.718×(2888.89  - 592.984) - 0.718×(1406.5 - 288.706) = 845.88 kJ/kg

The power developed in an Otto cycle = W×Cycle per second

= 845.88 × 2400 / 60  = 33,835.377 kW = 45373.99 ≈ 45374 hP.

The MATLAB code for the greatest value of n that satisfies the given equation is as follows:

Here is an example MATLAB code that finds the maximum value of n:

sum = 0;

n = 0;

while sum < 998

   n = n + 1;

   sum = sum + n^3;

end

% Subtract 1 from n since the last iteration will make the sum exceed 998

n = n - 1;

% Print the value of n

disp(['The greatest value of n is: ', num2str(n)]);

In MATLAB, you may use a loop to iterate over the variables and accumulate the sum to calculate the sum 14 + 24 + 3¹ + ... + 200¹. Here is an illustration of MATLAB code that computes the total:

sum = 0;

for n = 1:200

   sum = sum + n;

end

% Print the sum

disp(['The sum is: ', num2str(sum)]);

Thus, these codes can be executed in MATLAB to obtain the desired results.

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To find the maximum electric force that each proton will exert on the other, we can use Coulomb's law.

which states that the electric force between two charged particles is proportional to the product of their charges and inversely proportional to the square of the distance between them.
First, we need to determine the charge of a proton, which is equal to the elementary charge, e = 1.602 x 10^-19 coulombs.
Next, we can calculate the distance between the two protons when they are closest to each other, which is when they are at the midpoint of their path. This distance can be found using the equation d = vt, where v is the speed of the protons and t is the time it takes for them to reach the midpoint. Since the protons start several meters apart, we can assume that they are initially at a distance of at least 10 meters from each other.
Using the equation d = vt, we can find that it takes approximately 0.033 seconds for the protons to reach the midpoint of their path. Therefore, the distance between the protons at this point is: d = (3 x 10^8 m/s) x (0.033 s) = 9.9 x 10^6 meters.Now we can use Coulomb's law to calculate the maximum electric force that each proton will exert on the other. Since the protons have the same charge, the force will be repulsive.
F = k(q1q2)/d^2
where k is the Coulomb constant, q1 and q2 are the charges of the protons, and d is the distance between them.
Plugging in the values, we get:
F = (9 x 10^9 Nm^2/C^2) x [(1.602 x 10^-19 C)^2]/(9.9 x 10^6 m)^2
F = 3.6 x 10^-10 N
Therefore, the maximum electric force that each proton will exert on the other is approximately 3.6 x 10^-10 Newtons.

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Answer: B. thermocouple measures temperatures at the tip and the thermistor at the dimple.

Explanation:

A thermistor is a temperature-sensitive resistor, whilst a thermocouple generates a voltage proportional to the temperature. Thermocouples can work at much higher temperatures than thermistors. They are commonly used for temperature control in heating systems.

Answer:

Following are the solution to this question:

Explanation:

In point a:

This takes me six weeks for both the took ideas that I was searching for but it continued for 3 years (12 weeks) as it's an intern.  

In point b:

Finding job:

\(\to f = \frac{1}{6} = 0.166\) jobs weekly  

Separation of jobs:

\(\to \frac{ 1}{12}=0.083\) employment per week.  

In point c:

Its natural rate of unemployment is:  \(\frac{U}{L} = s+(s \times f)\).  

The normal level of employment for that community I represent, once we add up from that preceding section, is as follows:

\(\to \frac{U}{L} = 0.083+ (0.083\times 0.166) = 0.096\)

If on average, it requires six weeks to find another job or the work lasted 12 weeks, the group's unemployment level is \(0.096 \ \%\).

The generator matrix for this code is G = 100001111011ii) The parity-check matrix for this code is H = 1 1 1 0 1 0 0 0 1 1 0 1ii) 10101010 is not a valid codeword.

Given the parity-check equations are as follows:p1 = mi + m2 + m4p2 = mi + m3 + m4p3 = mi + m2 + m3And, 24 = m2 + m3 + m4i) The generator matrix for this code is obtained by applying the Gaussian elimination method to the following matrix.

G = [Im|P], where,

For the given parity-check equations matrix P is : P = 1 1 0 1 1 0 1 0 1On applying Gaussian elimination to [Im|P], the generator matrix is obtained as G = [1 0 0 0|0 1 1 1|0 1 1 0|1 1 0 1]

Thus, the generator matrix isG = 100001111011ii) The parity-check matrix is obtained by using the generator matrix as follows: (H)T = [-G(n−k) | In−k]

Hence, from the above generator matrix, we get n-k=4Hence, I4 = 1000 0100 0010 0001⇒ [G(n−k) | In−k]T = 1001 0111 0110 1011 1111 1000 1101 0011

Thus, the parity-check matrix H for the given systematic code isH = 1 1 1 0 1 0 0 0 1 1 0 1iii) 10101010 is a valid codeword if and only if it satisfies the parity-check equations i.e., H10101010T = 0.

So, we haveH = 1 1 1 0 1 0 0 0 1 1 0 110101010T = 1010 1010Hence,H10101010T = 1 1 1 0 1 0 0 0 1 1 0 1 * 1 0 1 0 1 0 1 0T= 0Therefore, 10101010 is not a valid codeword.

The generator matrix for this code is G = 100001111011ii) The parity-check matrix for this code is H = 1 1 1 0 1 0 0 0 1 1 0 1ii) 10101010 is not a valid codeword.

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Answer:

Inductive reactance is denoted by \(X_L\) where

\(X_L=2\pi fL\)

from looking at the equation, you can see that as frequency increases, so does the inductive reactance.

Answer:

(The diagram of the question is given in Attachment 1)

The largest load which can be applied is:

P=67.62 kN

Explanation:

All the forces are shown in the diagram in Attachment 2.

∑ F(y)= 0 (Upwards is positive)

\(F_{BC}sin\theta-P=0\\\frac{4}{5}F_{BC} - P=0\\F_{BC}=\frac{5}{4}P\\\\F_{BC}=1.25P\)

∑ F(x)= 0 (Towards Right is positive)

\(N_{a-a} - F_{BC}cos\theta=0\\N_{a-a}-1.25P(\frac{3}{5})=0\\N_{a-a}=0.75P\)

∑ F(y)= 0 (Upwards is positive)

\(F_{BC}sin\theta- V_{a-a}= 0\\(\frac{4}{5})1.25P-V_{a-a}=0\\V_{a-a}=P\)

The cross sectional area of a-a:

\(A_{a-a}= \frac{(0.026)(0.026)}{3/5}\\A_{a-a}= 1.127\cdot10^{-3}\)

σ = N(a-a)/A(a-a)

Substitute values:

\(160\cdot10^6=\frac{0.75P}{1.127\cdot10^{-3}}\\P=240.42\cdot10^3 N\\P=240.42 kN\)

Т= V(a-a)/A(a-a)

Substitute values:

\(60\cdot10^6=\frac{P}{1.127\cdot10^{-3}}\\P=67.62\cdot10^{3}N\\P=67.62kN\)

To satisfy both the condition, we have to choose the lower value of P.

P=67.62 kN

1) Initialize a 2D vector of integers: { { 1,1,3,1,5 },{ 1,1,3,1,5 },{ 1,1,3,1,5 },{ 1,1,3,1,5 },{ 1,1,3,1,5 } } Name this 2D Vector Data1.

An integer is a whole number, meaning it is not a fraction, and can be positive, negative, or zero. Integers are commonly used in mathematics and computer programming. They are used to represent whole numbers such as 1, 2, 3, 4, 5, and so on.

2) Initialize a 2D vector of integers: vector<vector<int>> Data2 = { { 1,2,3,4,5,6,7,8,9,10 },{ -2,-1,2,1},{ },{ 2,2,2 } };

3) The vector returned will only contain the value -1: vector<pair<int,int>> result = SearchEven(Data1);

4) Name this function: Display Locations:
void Display_Locations(vector<pair<int,int>> result) {

if (result.size() == 0) {

   cout << "Data1 did not contain any even numbers." << endl;

} else {

   cout << "Data1 contained at least 1 even number:" << endl;

   for (auto p : result) {

       cout << "Row: " << p.first << ", Column: " << p.second << endl;

   }

}

}

5) Pass Data2 as an argument to the SearchEven function: vector<pair<int,int>> result = SearchEven(Data2);

6) If Data2 did not contain any even numbers: Display_Locations(result);

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It is to be noted that all UHRS platforms are optimized for the popular kinds of internet browser applications.

The Universal Human Relevance System (UHRS) is a crowdsourcing platform that allows for data labeling for a variety of AI application situations.

Vendor partners link people referred to as "judges" to offer data labeling at scale for us. All UHRS judges are bound by an NDA, ensuring that data is kept protected.

A browser is a software tool that allows you to see and interact with all of the knowledgeon the World Wide Web. Web sites, movies, and photos are all examples of this.

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In Iowa courts, the testimony of a licensed engineer or land surveyor, when presented as an expert witness, can be challenged by the opposing attorney.

The opposing attorney has the right to cross-examine the expert witness and challenge their testimony through questioning and presenting counterarguments or conflicting evidence. This is a fundamental aspect of the legal process that allows for the exploration of different perspectives and the evaluation of the credibility and accuracy of expert testimony. By challenging the testimony, the opposing attorney aims to test the expert's qualifications, methods, reasoning, and conclusions to present a comprehensive and well-rounded view to the court. It is through the adversarial process that the court can weigh the evidence and make an informed decision. Therefore, in Iowa courts, the testimony of a licensed engineer or land surveyor, like any other expert witness, can be subject to challenge by the opposing attorney.

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huhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhh

Answer:

?

Explanation:

what do you mean

The observation that will be noticed in transferring heat by changing the intermediate cross sectional area is that;

An increase in the intermediate cross sectional area would lead to an increase in the rate of heat transfer and vice versa.

dQ/dt = kA(dT/dx)

Where;

dQ/dt is rate of heat transfer

k is thermal conductivity of the medium

A is cross sectional area

dT/dx is the rate  of change of the temperature per unit length

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Therefore, the relative speed at the time of collision is 17.8816 mps

We will use the equation of motion:

v^2 = u^2 + 2as

s = (v^2 - u^2) / 2a

s = (0 - (25)^2) / (2a)

s = 312.5 / a

The distance the Car B travels during the 1.30 seconds when its driver is distracted and does not apply the brakes is gotten as

S = ut + (1/2)at^2

s = (17.8816 mps)(1.30 sec) + (1/2)(-5.4864 m/sec^2)(1.30 sec)^2

s = 11.645 m

The relative speed at the time of collision is:

(40 mph - 0 mph) * 1.60934 kmph * 1000 m/km / 3600 sec/hour = 17.8816 mps

Car B will only travels at 11.645 m   before hitting Car A which is clear indication that Car B will not be able to stop in time and a collision will occur.

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A multispeed capacitor-run motor changes speed by adding impedance to the run winding and increasing the slip, not by changing the number of poles.

A capacitor-run motor is a type of single-phase induction motor that uses a capacitor to create a phase shift between the run winding and the start winding. This phase shift causes the motor to start rotating in the desired direction.

The run winding is the main winding of the motor. It is responsible for providing the torque that keeps the motor running. The impedance of the run winding can be increased by adding a resistor or inductor in series with it. This increases the slip, which is the difference between the synchronous speed of the motor and the actual speed of the motor.

The slip is a measure of how much the rotor is lagging behind the rotating magnetic field. As the slip increases, the torque of the motor decreases. This allows the motor to run at different speeds.

The number of poles in a motor determines its synchronous speed. The synchronous speed is the speed at which the rotating magnetic field rotates. The number of poles can be changed by changing the physical configuration of the motor. However, this is not typically done in multispeed capacitor-run motors.

Additional Information

Multispeed capacitor-run motors are typically used in appliances such as fans and air conditioners. They are a good choice for these applications because they are relatively inexpensive and easy to maintain.

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As the temperature of the material increases, the potential energy of the molecules increases. Thermal expansion occurs due to changes in temperature, and interatomic distances increase as potential energy increases.

Thermal expansion is used in a variety of applications such as rail buckling, engine coolant, mercury thermometers, joint expansion, and others.

It is to be noted that an application of the concept of liquid expansion in everyday life concerns liquid thermometers. As the heat rises, the mercury or alcohol in the thermometer tube moves in only one direction. As the heat decreases, the liquid moves back smoothly.

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Answer:

There are six conditions

1. Poles should contain some residual flux.

2. Field and armature winding must be correctly connected so that initial mmm adds residual flux.

3. Resistance of field winding must be less than critical resistance.

4. Speed of prime mover of generator must be above critical speed.

5. Generator must be on load.

6. Brushes must have proper contact with commutators.

Explanation:

Nowadays, you can link practically all of your home's appliances to a single device and operate it from anywhere. A better use of time is made possible through productivity apps.

The most pressing climatic concerns facing the globe can be addressed with the use of ICTs, which can also help with the transition to a circular economy that is much needed.

Access to biometric gadgets, food management software, and exercise routines easily leads to improved health. Communication with friends and family is simpler and less expensive.

Therefore,  Additionally, they can be employed to keep track of, lesson, and adjust to climate change.

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Answer:

\(250\ \text{lbm/min}\)

\(625\ \text{ft/min}\)

Explanation:

\(A_1\) = Area of section 1 = \(10\ \text{ft}^2\)

\(V_1\) = Velocity of water at section 1 = 100 ft/min

\(v_1\) = Specific volume at section 1 = \(4\ \text{ft}^3/\text{lbm}\)

\(\rho\) = Density of fluid = \(0.2\ \text{lb/ft}^3\)

\(A_2\) = Area of section 2 = \(2\ \text{ft}^2\)

Mass flow rate is given by

\(m=\rho A_1V_1=\dfrac{A_1V_1}{v_1}\\\Rightarrow m=\dfrac{10\times 100}{4}\\\Rightarrow m=250\ \text{lbm/min}\)

The mass flow rate through the pipe is \(250\ \text{lbm/min}\)

As the mass flowing through the pipe is conserved we know that the mass flow rate at section 2 will be the same as section 1

\(m=\rho A_2V_2\\\Rightarrow V_2=\dfrac{m}{\rho A_2}\\\Rightarrow V_2=\dfrac{250}{0.2\times 2}\\\Rightarrow V_2=625\ \text{ft/min}\)

The speed at section 2 is \(625\ \text{ft/min}\).

(a) The mass flow rate will be "250 lbm/min".

(b) At section 2, the speed will be "625 ft/min".

According to the question,

Section 1 area, A₁ = 10 ft²

Section 2 area, A₂ = 2 ft²

Water's velocity, V₁ = 100 ft/min

Volume at section 1, v₁ = 4 ft³/lbm

(a) We know the formula,

Mass flow rate, m = ρA₁V₁

                              = \(\frac{A_1 V_1}{v_1}\)

By substituting the values,

                              = \(\frac{10\times 100}{4}\)

                              = \(\frac{1000}{4}\)

                              = 250 lbm/min

(2) The speed will be:

→ m = ρA₂V₂

or,

  V₂ = \(\frac{m}{\rho A_2}\)

By substituting the values,

       = \(\frac{250}{0.2\times 2}\)

       = \(\frac{200}{0.4}\)

       = 625 ft/min

Thus the responses above are correct.  

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In radiology, the distance of the illuminator light bulb from the center of the mirror can be found by measuring the distance between the bulb and the center of the mirror using a measuring tape or ruler.

In radiology, the illuminator is a device that provides light for viewing X-ray films. The illuminator consists of a light bulb and a mirror that reflects the light towards the film. To ensure that the light is properly directed onto the film, it is important to know the distance between the light bulb and the center of the mirror.

This distance can be measured using a measuring tape or ruler, by measuring the distance from the bulb to the mirror and subtracting the radius of the mirror. This measurement helps to ensure that the light is properly focused on the film for accurate and clear image viewing.

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When judging the authority of a website, an element which is not a judgment criterion include the following: C. layout of content.

In Computer technology, a website can be defined as a collective name which connotes a series of webpages that are interconnected and linked together with the same domain name, in order to provide certain information to end users.

Generally speaking, the judgment criteria that should be used in judging the authority of a website include the following:

In conclusion, the layout of content is not a judgment criterion for judging the authority of a website.

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The statement, "Space temperature is the only temperature that is important in modern systems." is False.

Modern systems are more complex than older ones. These systems may manage different environments with various requirements and situations. It is critical that you know the varying temperatures that the building and its components need. Temperature sensors have become an essential component of modern climate control systems.

Space temperature is the temperature of the room. It is not the only temperature that is important in modern systems. The following are some of the critical temperature measurements that modern systems monitor:

1. The temperature of outdoor air

2. The temperature of the return air

3. Supply air temperature

4. Temperature of water

5. Temperature of the air being delivered by the rooftop unit

6. Refrigerant temperatures

7. The temperature of the discharge

8. Temperature of the inlet.

A temperature sensor is used to keep track of the temperature in various areas of a building. A building management system (BMS) may use these sensors to help control heating, cooling, and ventilation. These sensors might help to avoid overheating or overcooling areas of the building thus monitoring temperature.

Therefore, while space temperature is significant in certain systems, it is not the only temperature that is important in modern systems. So the given statement "Space temperature is the only temperature that is important in modern systems." is False.

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Lens shades 4 to 6 are ideal for gas welding or oxyfuel torch welding/ oxyfuel gas cutting because In AWS Z49.1, the numbers for welding lens shades range from 4 to 14. Lens shades 4 to 8 are useful for low light intensity welding and cutting tasks such as gas cutting, brazing, or soldering, among others.

Selecting the right lens shade for welding:

The first and most important point to remember is to never look at welding without wearing black safety glasses or a suitable helmet. Next, what is the appropriate glass shade for various welding processes?

Looking directly at the welding arc without eye protection, or failing to follow this rule, can result in varying degrees of eye burn.

These burns do not usually result in permanent damage, but they can be excruciatingly painful for several days after exposure.

A helmet-style head shield, as shown in the figure below, is standard equipment for shielding the welder's face and eyes from the arc's direct rays.

To reduce reflection, these shields are typically made of a non-flammable insulating material and are black or gray in color. They are designed to shield the face, neck, and ears from the arc's direct radiant energy.

Glass lens shade for Gas welding and Gas cutting:

Lens shades 4 to 6 are ideal for gas welding or oxyfuel torch welding. The gas lens for oxyfuel gas cutting is determined by the material thickness to be cut, and the same is true for OFW welding, where the thickness to be welded determines the lens shade.

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Answer:

the range of length scales is ( 0.0602 -  0.1094 )

Explanation:  

  Given the data in the question;

\(P_{absolute\) = 1300 kPa

V\(_{prototype\) = 406 km/h

speed of model nit more than 29%

we know that Reynolds number Re = pVl/μ = constant

p\(_m\)V\(_m\)l\(_m\)/μ\(_m\) = pVl/μ  

such that;

l\(_m\)/l = ( p/p\(_m\) )( V/V\(_m\) )( μ\(_m\)/μ )  ----- let this be equation 1

Now, for an idea gas; P = pRT { with constant temperature }

p / p = constant; p/p\(_m\) = p/p\(_m\)  

assuming μ\(_m\) = μ\(_m\)  

Therefore, the relation becomes;

l\(_m\)/l = ( p/p\(_m\) )( V/V\(_m\) )

from the given data;

l\(_m\)/l = ( 101/1300 )( V/V\(_m\) )

where our V\(_m\) = ( 1 ± 29% )V

so

l\(_m\)/l = ( 101/1300 )( V / ( 1 ± 29% )V )

l\(_m\)/l = ( 101/1300 )( 1 / ( 1 ± 0.29  ) )

Now, The minimum limit will be;

l\(_m\)/l = ( 101/1300 )( 1 / ( 1 + 0.29  ) )

= ( 101/1300 ) × ( 1 / 1.29 )

= 0.0602

The maximum limit will be;

l\(_m\)/l = ( 101/1300 )( 1 / ( 1 - 0.29  ) )

= ( 101/1300 ) × ( 1 / 0.71 )

= 0.1094

Therefore, the range of length scales is ( 0.0602 -  0.1094 )