A crate of mass 2 kg is being pulled to the right across a rough horizontal surface by constant force F. The force F is applied at an angle of 20° to the horizontal, as shown in the diagram. how can l draw a labelled free body showing all force​

Answer:

1.02s

Explanation:

In this situation the following equation will be useful:



Where:

 is Marissa's car  final velocity

 is Marissa's car initial velocity

 is Marissa's car constant acceleration  (assuming this is the acceleration, since 1269 m/s^{2} does not make sense)

 is the time  it takes to accelerato from  to 

7)

The internal angles of a triangle must add up to 180.

The given answer is 64º and we can verify that:

Then, the answer is correct.

Notice that the measurement of 26.0º has three significant figures while the 90º angle is an exact value. Then, the answer must have 3 significant figures too: 64.0º.

8)

The tangent of an angle in a right triangle is the quotient between the side opposite to it and the side adjacent to it.

The tangent of 26º is 0.4877, and the quotient of the lengths of the sides according to the answer, is:

The length of 16.4cm has the correct number of significant figures and matches the value of the tangent. Then, the answer is correct.

9)

Using the Pythagorean Theorem, we should verify that:

To be precise, if the length of the hypotenuse is calculated, the result is 18.249...cm, so it should be rounded down to 18.2cm.

a) Equivalent hydraulic diameter for a circular cross-section:

  Deq = 4 * Ac / P

(b) Equivalent hydraulic diameter for a square cross-section: Deq = a

(c) Equivalent hydraulic diameter for a rectangular cross-section:

Deq = 2 * (a * b) / (a + b)

d) Equivalent hydraulic diameter for an annular cross-section: Deq = D - d

a) In a circular cross-section, the equivalent hydraulic diameter (Deq) is defined as four times the cross-sectional area (Ac) divided by the perimeter (P). It represents a hypothetical diameter of a circular pipe that would have the same flow characteristics as the given non-circular cross-section.

b) In a square cross-section, the equivalent hydraulic diameter (Deq) is equal to the side length of the square. This simplification is possible because the flow characteristics in a square channel are similar in all directions.

c) In a rectangular cross-section, the equivalent hydraulic diameter (Deq) is given by two times the product of the width (a) and height (b) divided by their sum (a + b). This formula takes into account the dimensions of the rectangular channel to determine the equivalent diameter.

d)  In an annular cross-section, the equivalent hydraulic diameter (Deq) is equal to the difference between the outer diameter (D) and the inner diameter (d) of the annulus. This simplification assumes that the flow occurs only through the annular region.

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The main problem with early attempts to listen for radio signals from space was the interference from terrestrial radio signals and insufficient technology to filter out the background noise. This made it difficult to distinguish potential signals from space and accurately identify any extraterrestrial sources.

The main problem with early attempts to listen for radio signals from space was that they were limited by the technology available at the time. The equipment used was not sensitive enough to detect faint signals from faraway sources, and there was a lot of interference from sources on Earth. Additionally, there was limited knowledge about the types of signals that might be emitted from space, which made it difficult to know where and how to search for them. Despite these challenges, scientists continued to develop new technologies and techniques, eventually leading to the discovery of many new and exciting sources of radio signals from space.

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In todays modern word modern scientists measure and calculate the speed at which the continents are moving using the Global Positioning System (GPS).

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Answer:

80.08 km/h

Explanation:

Given that Black Panther ran 567.6 km to the east in 23 hours

Velocity = distance covered/time

Substitute the distance covered and time into the formula

Velocity = 567.6/23

Velocity = 24.68 km/h

then turned around and ran 221.8 km to the west in 1.2 hours.

Velocity = 221.8/1.2

Velocity = 184.83 km/h

What was his average velocity during the trip in km/h ?

Average velocity = (V + U)/2

Since the two velocity are opposite to each other, the average velocity will be:

Average velocity = (-24.68 + 184.83)/2

Average velocity = 160.15/2

Average velocity = 80.08 km/h

Therefore, his average velocity during the trip is 80.08 km/h

Answer:

Explanation:

To calculate the height of the table in this scenario, we can use the equations of motion. Let's define the variables first:

Initial velocity (u) = 2.50 m/s (given)

Time taken to reach the floor (t) = 0.391 s (given)

Acceleration due to gravity (g) = 9.8 m/s² (assuming the ball falls freely near the surface of the Earth)

Now, we can use the kinematic equation:

h = u * t + (1/2) * g * t²

Plugging in the given values, we have:

h = (2.50 m/s) * (0.391 s) + (1/2) * (9.8 m/s²) * (0.391 s)²

Simplifying the equation:

h = 0.97875 m + 0.07511 m

h = 1.05386 m

Therefore, the height of the table is approximately 1.05386 meters.

Answer:

11900 meters

Explanation:

Use the Potential energy = mgh formula, substituting these in to get 11.1x10^6 = 95 x 9.81 x h.

Rearrange to make h the subject and the answer given is 11900 (3sig.fig.)

The maximum height to which he can climb will be 1.168 x 10⁴ meters.

The potential energy of a body is the energy of the body due it position. The potential energy always exist for two bodies which are in mutual interaction with each other for example by a force. For body a on earth, the potential energy of the body - earth system is -

E[P] = mgh

Given is a mountain climber that has a mass of 95 kg.

We can write -

Mass of climber = [M] = 95 kg

Energy gained by eating the chocolate = [E] = 11.1 MJ = 1.11 x 10⁷ joules

Assume that the height achieved achieve by the climber is [h] meters

Therefore, the potential energy gained at that height will be equal to 11 MJ

Therefore -

mgh = 1.11 x 10⁷

95 x 10 x h = 1.11 x 10⁷

95 x 10 x h = 1110 x 10⁴

h = (1110 x 10⁴)/950

h = 1.168 x 10⁴ meters

Therefore, the maximum height to which he can climb will be 1.168 x 10⁴ meters.

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Answer:

35.2941176 cm/s

Explanation:

round it if you need too

Distance divided by time.

Answer:42.41

Explanation:

Answer:

a) 102 meters

b) 14 meters

c) The direction is eastward.

Explanation:

Distance is said to be the length between two points. It is a scalar quantity.

a) The distance moved = 36 + 44 + 22

                                       = 102 meters

b) Displacement is the distance moved in a specified direction.

Representing the distance moved with specific direction as a directed number, 36 meters eastward = +36, 44 meters westward = -44, and 22 meters eastward = +22

/Displacement/ = +36 -44 +22

                         = +58-44

                         = 14

The magnitude of the displacement is 14 meters.

c) The direction is eastward.

So that the magnitude of displacement and his direction is 14 meters eastward.

Answer:

Sugar ofc.

Explanation:

Have you seen energy drinks such as gatorade? Electrolytes

Answer:

An electrolyte solution contains water, salt, potassium and sugar in the proper concentration. The salt and sugar also have an added benefit of helping the body absorb the water - it turns out we absorb water with a little salt and sugar much better than we do plain water.

Explanation:

A rocket ship has several engines and thrusters. While the solid rocket booster (srb) and main engines only work together during the first 2 minutes of flight, the main engines operate for a total of 8. 5 minutes after the launch. Once the srbs are released, the main engines alone accelerate the rocket from about 1341 m/s to 7600 m/s. During the first two minutes of flight, the SRB and main engine accelerate at a rate of 52.16 m/s2.

Acceleration is the rate at which a moving object's speed and direction change over time. When something moves faster or slower, it is considered to be accelerating. The engine's initial velocity (u), final velocity (v), and time of motion (t), which is equivalent to two minutes, are the parameters given (2 x 60 s).

The calculations for the main engine's and SRB's acceleration are listed below.

a= Δv / Δt

a=7600-1341 /2*60s

a=52.16 m/s²

As a result, during the first two minutes of flight, the main engine and SRB accelerate at a rate of 52.16 m/s2.

Your question is incomplete but most probably your full question is

A rocket ship has several engines and thrusters. While the Solid Rocket Booster (SRB) and main engines only work together during the first 2 minutes of flight, the main engines operate for a total of 8.5 minutes after the launch. Once the SRBS are released, the main engines alone accelerate the rocket from about 1341 m/s to 7600 m/s.

What is the height of the rocket when the rocket reaches the speed of 7600 m/s? Show your work.

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Answer:

the answer is A

Explanation:

The answer is A

The Choice in which the bond Strength ranks in the correct order is Choice A; S-S < K-K < K-S

According to the question;

The bond strength of a bond increases with increasing polarity of the bond.

Evidently, From the options above; In Choice A;

The polarity of S-S < K-K < K-S

As such, the bond strength which ranks in the correct order is Choice A: S-S < K-K < K-S

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By using the Kohler curves is 4×\(10^{-5} cm\). If Rh is not shown in the graph therefore the sensitivity is near 1.00 S Rh is 88%. That is 0.0055 means 0.55%.

Kohler curves, also known as Kohler plots, are a graphical representation of the magnetoresistance of a material as a function of the magnetic field strength. They were first introduced by Walter Kohler in 1934 to describe the behavior of ferromagnetic materials. Kohler curves are useful in the study of magnetic materials and have applications in the development of magnetic sensors and memory devices.

Kohler curves plot the ratio of the resistance of a material at a given magnetic field strength to its resistance in the absence of a magnetic field, versus the square of the magnetization of the material. The resulting curve can be used to determine the degree of spin polarization in the material, which is a measure of the alignment of electron spins in the material with the magnetic field.

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Complete Question:

Using the Kohler curves estimate the following: (a) the radius of the droplet that will form on a sodium chloride particle of mass 10^-18 kg in air that is 0. 1% supersaturated; (b) the relative humidity of the air adjacent to a droplet of radius 0. 4 microns that contains 10^-19 kg of dissolved ammonium sulfate; (c) the critical supersaturation required for an ammonium sulfate particle of mass 10^-19 kg to grow beyond the haze state

Answer:

a)It is NOT possible using this telescope, to see the two stars as separate stars

b)\(d_{min} =28.466m\)

Explanation:

From the question we are told that:  

Diameter of lens,\(d = 25 cm \approx 0.25 m\)

Distance from both star \(D_f= 2*10^{17} m\)

Distance between both stars \(D_b= 6*10^9 m\)

Wavelength of light \(\lambda =700 nm \approx 700*10^-9 m\)

Generally the equation for angle subtended by the two stars at the lens  is mathematically given by

 \(\theta=\frac{D_f}{D_b}\)

 \(\theta=\frac{6*10^9}{2*10^{17}}\)

 \(\theta=3.0*10^{-8} rad\)

Generally the equation for minimum angular separation of two object is mathematically given by

\(\theta_{min} = 1.22*\lambda/d\)  

\(\theta_{min}= \frac{1.22*700*10^-9}{0.25}\)  

\(\theta_{min}= 3.416*10^-^6 rad\)

Therefore

 \(\theta < \theta_{min}\)

\(3.0*10^{-8} rad< 3.416*10^-^6 rad\)

It is NOT possible using this telescope, to see the two stars as separate stars

b)

Generally the equation for minimum diameter of the lens is mathematically given by

  \(d_{min} =\frac{ 1.22*\lambda}{\theta}\)

  \(d_{min} =\frac{ 1.22*700*10^{-9}}{3*10^{-8}}\)

  \(d_{min} =28.466m\)

The resistance of the heater coil should be approximately 29.5 Ω. The power (P) dissipated by a resistor with resistance R and voltage V across it can be calculated using the formula P = V^2/R. Rearranging this formula, we can solve for R: R = V^2/P.

Substituting the given values, we get R = (125 V)^2 / 530 W = 29.5 Ω (rounded to one decimal place).

Therefore, the resistance of the heater coil should be approximately 29.5 Ω to provide 530 W of heat with a voltage of 125 V.

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We have that the gas will occupy at a pressure of 800 torr if temperature is held constant a Volume of

\(V_2=0.18L\)

From the Question we are told that

Initial Pressure \(P_1=720\)

final Volume  \(V_1=200mL\)

Initial Pressure \(P_2=800\)

final Volume  \(V_2=?\)

Generally the equation for Boyle's law  is mathematically given as

\(P_1V_1= P_2V_2\)

Therefore

\(V_2=\frac{ P_1V_1}{P_2}\\\\V_2=\frac{ 720*200}{800}\\\\V_2=180mL\)

\(V_2=0.18L\)

The gas will occupy at a pressure of 800 torr if temperature is held constant a Volume of

\(V_2=0.18L\)

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To find the maximum angle of incidence for which a light ray can emerge into the air above the water, we can apply Snell's law, which relates the angles and refractive indices of the two media involved.

Snell's law states:

n1 * sin(∅1) = n2 * sin(∅2)

where:

n1 is the refractive index of the first medium (in this case, glass),

∅1 is the angle of incidence,

n2 is the refractive index of the second medium (in this case, water),

∅2 is the angle of refraction.

In this problem, the light is incident from the glass into the water, so n1 is the refractive index of glass and n2 is the refractive index of water.

The critical angle (∅c) is the angle of incidence at which the refracted angle becomes 90°. When the angle of incidence exceeds the critical angle, the light is totally internally reflected and does not emerge into the air.

The critical angle can be calculated using the equation:

∅_c = arcsin(n2 / n1)

In this case, the refractive index of glass (n1) is approximately 1.5, and the refractive index of water (n2) is approximately 1.33.

∅_c = arcsin(1.33 / 1.5)

∅_c ≈ arcsin(0.8867)

∅_c ≈ 60.72 degrees

Therefore, the maximum angle of incidence for which a light ray can emerge into the air above the water is approximately 60.72 degrees.

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Alpha decay is a type of nuclear decay occurring by the emission of alpha particles. Thus the nuclei changes to a new nuclei with mass number decreased by 4 units and atomic number decreased by 2 units from the parent atom.

Nuclear decay is the process of radioactive decay of unstable isotopes to form its stable isotopes or new nuclei.  Unstable atoms undergo nuclear decay by the emission of alpha or beta particles or by  electron capture.

In alpha decay,  an alpha particle that is a helium nuclei is emitted with the new nuclei where the mass number reduces by 4 and atomic number reduces by 2.

For instance consider the alpha decay of carbon -14 produces stable beryllium -10 with an alpha particle.

\(\rm _{6}^{14}C \rightarrow _{10}^{4}Be + _{2}^{4}He\).

Similarly in beta decay, an electron is emitted where the atomic number increases by one and mass number does not change.

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Answer:

The molar mass of a compound tells you the mass of one mole of that substance. In other words, it tells you the number of grams per mole of a compound.

Answer:

potential energy

Explanation:

The magnitude of the velocity of point C (vC) when the piston has moved to the new position is approximately 6.001 in/s, in the opposite direction of the original motion.

Let's calculate the values to find the magnitude of the velocity of point C (vC) when the piston has moved to the new position.

Length of crank arm, r1 = 0.50 in

Length of connecting rod, r2 = 5.05 in

Angle between the crank arm and the connecting rod, θ = 30.0°

Angle of rotation of the crankshaft, α = 4.92°

Rotational speed of the crankshaft, ω = 220 rpm

Converting lengths to inches:

r1 = 0.50 in

r2 = 5.05 in

Converting angular velocity to rad/s:

ω = (2π * 220 rpm) / 60

ω ≈ 23.094 rad/s

Calculating angular displacement:

θ = α + 180°

θ = (4.92° + 180°)

θ ≈ 184.92°

Calculating the linear velocity of point B:

vB = ω * r1

vB = (23.094 rad/s) * (0.50 in)

vB ≈ 11.547 in/s

Calculating the velocity of C relative to B:

vC/B = ω * r2 * sin(θ)

vC/B = (23.094 rad/s) * (5.05 in) * sin(184.92°)

vC/B ≈ -17.548 in/s (negative sign indicates the direction)

Calculating the magnitude of the velocity of C:

vC = vB + vC/B

vC ≈ 11.547 in/s - 17.548 in/s

vC ≈ -6.001 in/s (negative sign indicates the direction)

Therefore, the magnitude of the velocity of point C (vC) when the piston has moved to the new position is approximately 6.001 in/s, in the opposite direction of the original motion.

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Answer:

With an increase in temperature, the electrical conductivity of a pure metal decreases. This implies that the thermal conductivity of the pure metal shows little variance with an increase in temperature. However, a sharp decrease is observed when temperatures approach 0K

Answer:

1080000

Explanation:

300 x 60s=18000m/minute

18000 x 60min=1080000m/h

Explanation:

Answer:

To foster trade between southern states and South American nations. Also to show the products and facilities to share in Europe & rest of nation.

0.265m/sec is the acceleration of the block when it is pulled with force of 5.3n having mass 2kg with friction 0.9N

F=ma, Where as F= force m= mass a= acceleration f = friction

F=5.3N  m=2kg a=? f=0.9N

The net force applied on the block is original force - friction force which is

(F-Ff)=ma

5.3- (5.3)(0.9)= 2x a

a= 0.265m/sec

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In atrial flutter, atrial contraction occurs at such a rapid rate that discrete P waves separated by a flat baseline cannot be seen.