a compound with a molecular formula c9h10o2 has the following 1h nmr spectrum. which of the following structures is consistent with this spectrum?

Answer:

A green liquid becoming a red liquid.

Explanation:

If the color change is unexpected it is a chemical change.

(If 2 clear liquids make a black, red, green, ect color it is a chemical change)

no normal color mix makes green turn red.

Balanced chemical equation - A chemical equation in which the number of each type of atom is equal on the two sides of the equation. Subscripts - Part of the chemical formulas of the reactants and products that indicate the number of atoms of the preceding element.

Examples of Balancing Chemical Equations

WE CAN SEE ATOMS!?!?! I swear I'm getting dumber everyday

but I think is like a.... a penny?

Answer:

E = 8085 kJ

Explanation:

Given that,

The mass of a truck, m = 1500 kg

Height, h = 550 m

We need to find the gravitational potential energy of the truck. It can be calculated as follows :

\(E=mgh\)

Put all the values,

\(E=1500\times 9.8\times 550\\\\E=8085000\ J\\\\or\\\\E=8085\ kJ\)

So, the gravitational potential energy is 8085 kJ.

Answer:

lungs

Explanation:

The energy of the photon of light can be obtained as 6.27 * 10^-20 J.

We know that a photon has to to do with a particular unit of light. We know that light can be said to be composed of very tiny corpuscles and these corpuscles of light is what we call the photon of the light.

We can be able to us the equation that is derived by Max Plank to be able to get the value of the energy of the photon of light. Now we know that a photon of light can have an energy that is able to be obtained by;

E = hf

h = Plank's constant

f = Frequency

Then;

E = 6.6 * 10^-34 Js * 9.5 * 10^13 Hz

= 6.27 * 10^-20 J

Thus as we can see from the parameters in the question, the energy of the photon is 6.27 * 10^-20 J.

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We know that in gas the particles are loosely packed, that is it can move freely compared to solid and liquid. Two bottles of the same gas are connected. One bottle has 15 particles at first and one has 2 particles. Diffusion will occur. The particles will move until the volume in both the bottles will be equalized.            

For gas there are three laws which are applied. Boyles law, Charles law and Avogadro's law.

Boyles law here it is the relationship between the pressure and the volume. when the volume of the gas at constant temperature varies with pressure applied on it inversely. Formula

                                                     P₁V₁=P₂V₂

Charles law is explained in the terms of temperature and volume. it states that the volume of the gas in a fixed amount is directly proportional to  its temperature if and only the pressure remains constant. formula

                                                     V₁/T₁=V₂/T₂

Avogadro's law is related with the amount and the volume. it says that under the same condition the pressure and the temperature, the equal volume of different gases contains equal number of molecules.

                                                  V₁/n₁=V₂/n₂

Diffusion will occur and the particles will be same in both.

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Answer:

\(\boxed {\boxed {\sf molarity \approx 3 \ M \ KCl}}\)

Explanation:

Molarity is a measure of concentration in moles per liter. The formula is:

\(molarity= \frac{moles \ of \ solute}{liters \ of \ solution}\)

We are given grams of solute and liters of solution, so we must convert both before calculating molarity.

We convert grams to moles using the molar mass. This value is found on the Periodic Table. It is the same as the atomic mass, but the units are grams per mole (g/mol) instead of atomic mass units (amu).

We have the compound KCl, so we look up the molar masses of the individual elements.

The compound does not contain subscripts, so we can add the molar masses together to find the molar mass of the compound.

Use the molar mass as a ratio.

\(\frac {74.548 \ g\ KCl}{1 \ mol \ KCl}\)

Multiply by 140 grams of KCl.

\(140 \ g\ KCl*\frac {74.548 \ g\ KCl}{1 \ mol \ KCl}\)

Flip the ratio so the units of grams of KCl cancel.

\(140 \ g\ KCl*\frac{1 \ mol \ KCl} {74.548 \ g\ KCl}\)

\(140 *\frac{1 \ mol \ KCl} {74.548 }\)

\(1.877984654 \ mol \ KCl\)

1 liter contains 1000 milliliters. Create another ratio.

\(\frac{ 1 \ L}{1000 \ mL}\)

Multiply by 600 milliliters (the value we are converting).

\(600 \ mL *\frac{ 1 \ L}{1000 \ mL}\)

The units of milliliters cancel.

\(600 \ *\frac{ 1 \ L}{1000 }\)

\(0.6 \ L\)

Now we know the moles of solute and the liters of solution.

Substitute the values into the molarity formula.

\(molarity= \frac {1.877984654 \ mol \ KCl}{0.6 \ L}\)

\(molarity= 3.129974424 \ mol \ KCl/L\)

The original measurements of grams and milliliters have 2 and 1 significant figures. We must round our answer to the least number of sig figs: 1.

For the number we found, that is the ones place. The 1 in the tenths place tells us to leave the 3 in the ones place.

\(molarity \approx 3 \ mol \ KCl/L\)

1 mole per liter is equal to 1 molar or M. Convert the units.

\(molarity \approx 3 \ M \ KCl\)

The molarity is approximately 3 M KCl.

The chemical of hydrogen has 0.0426 moles per y.

A compound combines with an oxidising element, such as oxygen, in a complete combustion reaction, and the products are compounds of each element in the fuel and the oxidising element. This reaction is exothermic. For instance, Carbon dioxide(g) + 2water(g) + heat + light = Methane(g) + 2Oxygen(g).

Molar mass of water (Water) = 2(1.008 g/mol) + 1(15.999 g/mol) = 18.015 g/mol

moles of water = mass of water collected / molar mass of water

moles of water = 0.384 g / 18.015 g/mol

moles of water = 0.0213 mol

Therefore, 0.0213 mol of water were produced from the combustion of the compound.

To determine the moles of hydrogen in the compound, we need to use the balanced chemical equation for the combustion of hydrocarbons:

(x + y/4 - z/2)Oxygen → xCarbon dioxide + y/2water

From the equation, we can see that each mole of water produced in the combustion reaction corresponds to y/2 moles of hydrogen in the original compound.

Since we now know that 0.0213 mol of water were produced, we can calculate the moles of hydrogen in the compound:

moles of hydrogen = (2 mol of water / y mol of hydrogen) x 0.0213 mol of water

moles of hydrogen = 0.0426 mol / y

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There are approximately 1.62 x 10^25 water molecules in the 499.8 mL bottle of water.

To determine the number of water molecules in the given volume of water, we need to use the relationship between mass, volume, and molar mass of water.

First, we need to find the mass of water in the bottle:

Mass = Density * Volume

Mass = 0.967 g/mL * 499.8 mL = 483.9 g

Next, we need to convert the mass of water to moles using the molar mass of water. The molar mass of water (H2O) is approximately 18.015 g/mol.

Moles = Mass / Molar mass

Moles = 483.9 g / 18.015 g/mol = 26.88 mol

Finally, we can calculate the number of water molecules using Avogadro's number, which is approximately 6.022 x 10^23 molecules/mol.

Number of molecules = Moles * Avogadro's number

Number of molecules = 26.88 mol * (6.022 x 10^23 molecules/mol) = 1.62 x 10^25 molecules

Therefore, there are approximately 1.62 x 10^25 water molecules in the 499.8 mL bottle of water.

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The value of the solubility product constant (Ksp) for the salt AB at 25°C is 2.60 x 10⁻³.

The solubility product constant (Ksp) is the equilibrium constant for the dissolution of a sparingly soluble salt in water. It is given by the expression Ksp = [A⁺][B⁻] where [A⁺] and [B⁻] are the molar concentrations of the cations and anions in solution, respectively.

In this case, the balanced equation for the dissolution of the salt AB is: AB(s) ⇌ A⁺(aq) + B⁻(aq) We know that at 25°C, only 0.0510 mol of the salt AB is soluble in 1.00 L of water. This corresponds to a molar solubility of

s = 0.0510 mol / 1.00 L = 0.0510 M

At equilibrium, the molar concentration of A⁺ and B⁻ will also be 0.0510 M. Therefore, the value of Ksp for the salt AB at 25°C can be calculated as: Ksp = [A⁺][B⁻] = (0.0510 M) * (0.0510 M) = 2.60 x 10⁻³.

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Answer:

D

Explanation:

hope this helps

The correct answer is that thermal energy is moving from your feet to your socks. The battery-heated socks work by using the heat generated by your body to warm your feet in cold weather.

The body produces heat, which is converted into thermal energy, and moves from your feet to the socks.

In order to warm your feet and make them more comfortable in cold weather, the socks use thermal energy. The thermal energy is only transferred in one direction, from your feet to the socks.

No more energy is produced because the battery-heated socks utilise your body's thermal energy to keep your feet warm.

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The volume of the balloon after it cools is 0.68 L.

Charles law states that the volume of a gas is directly proportional to its temperature at constant pressure.

It is given by:

V ∝ T

V/T = constant

Therefore:

\(\frac{V_1}{T_1}=\frac{V_2}{T_2} \\\\V_1=2.6\ L,T_1=293\ K,T_2=77\ K:\\\\\frac{2.6}{293}=\frac{V_2}{77} \\\\V_2=\frac{2.6}{293}*77\\\\V_2=0.68\ L\)

Hence the volume of the balloon after it cools is 0.68 L.

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We can write down the electron configuration of bromine using the periodic table's building pieces.

The amount of electrons in each sublevel and energy level of the ground-state atom is displayed in the electron configuration of an atom. Start at the nucleus and add electrons one at a time until the total number of electrons equals the total number of protons in the nucleus to establish the electron configuration of a specific atom.

The lowest energy sublevel is awarded to each additional electron. The 1s sublevel will be the first to be filled, followed by the 2s and 2p sublevels, the 3s and 3p, the 4s and 3d, and so on. It may be crucial to understand how the electrons in an atom's partially filled sublevel are allocated throughout the orbitals.

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Answer:

1.37x10²⁵atoms of carbon

2.74x10²⁵ atoms of oxygen.

33.7g of KNO₃

Explanation:

To answer this question you must use molar mass of carbon dioxide (44g/mol) and 1 mole are 6.022x10²³atoms.

1.00kg are 1000g of CO₂. Moles are:

1000g CO₂ * (1mol / 44g) = 22.73 moles of CO₂ = 22.73 moles of carbon.

In atoms:

22.73 moles C * (6.022x10²³atoms / 1mole) = 1.37x10²⁵atoms of carbon

There are 22.73 moles of CO₂ * 2 = 45.45 moles of oxygen are present in the carbon dioxide. In atoms:

45.45 moles Oxygen * (6.022x10²³atoms / 1mole) = 2.74x10²⁵ atoms of oxygen.

1 mole of Potassium nitrate, KNO₃, contains 3 moles of oxygen. 1 mol of oxygen are:

1.00 mol O * (1mol KNO₃ / 3 moles O) = 0.33 moles of KNO₃

As molar mass of KNO₃ is 101.1g/mol:

0.33 moles of KNO₃ * (101.1g / mol) = 33.7g of KNO₃

Answer:

1. 1.37 * 10^25 atoms of carbon

2. 2.74 * 10^25 atoms of oxygen

3. 33.67g of Potassium Nitrate

Explanation:

2. Firstly, we want to know the number of atoms of oxygen in 1 kg of carbon dioxide.

Firstly, we will need to know the number of moles of carbon iv oxide in 1kg of carbon iv oxide

Mathematically;

number of moles = mass/molar mass

molar mass of carbon iv oxide is 44 g/mol

mass here is 1000g (1kg is 1000g)

So the number of moles of CO2 in 1kg of CO2 will be; 1000/44 = 22.73 moles

Now 1 mole of CO2 contains 2 atoms of oxygen, thus 1 mole of CO2 contains 2 moles of oxygen

So the number of moles of oxygen in 1kg CO2 will be 2 * 22.73 = 45.46 moles

Mathematically, 1 mole contains 6.02 * 10^23 atoms

So 45.46 moles will contain =

6.02 * 10^23 * 45.46 = 2.74 * 10^25 atoms of oxygen

1. 1 mole of co2 contains 1 atom of carbon , thus, 1 mole of CO2 will

contain 1 mole of carbon

From above, 1kg of carbon iv oxide contains 22.73 moles , thus 1kg of carbon iv oxide will contain 22.73 moles of carbon too

So the number of atoms will be 22.73 * 6.02 * 10^23 = 1.37 * 10^25 atoms

3. Mass of KNO3 that contains 1 mole of oxygen atom

From the formula of the compound, we can see that 1 mole of KNO3 contains 3 atoms of oxygen which translates to 3 moles of oxygen

So 1 mole of oxygen will translate to 1/3 mole of KNO3

Mathematically;

mass = number of moles * molar mass

Molar mass of KNO3 = 39 + 14 + 3(16) = 39 + 14 + 48 = 101 g/mol

So the mass will be = 1/3 * 101 = 33.67g

C₂H₄O₂ + NaHCO₃ —> NaC₂H₃O₂ + H₂O + CO₂ the amount of Carbon dioxide produced is 5.28 mg.

Water, CO₂ , and C₂H₃NaO₂ were produced when acetic acid and NaHCO₃ were combined. The chemistry is as follows: The reaction between vinegar and baking soda was endothermic.

Acetic acid:  2(12.01 g/mol) + 4(1.01 g/mol) + 2(16.00 g/mol)

                                              = 60.05 g/mol

NaHCO₃ 22.99 g/mol + 1.01 g/mol + 3(16.00 g/mol)

                                             = 84.01 g/mol

100 mg of Acetic acid is equal to 0.1 g, and 10 mg of NaHCO₃ is equal to 0.01 g.

Number of moles of Acetic acid = 0.1 g / 60.05 g/mol

                                             = 0.00167 mol

Number of moles of NaHCO₃  = 0.01 g / 84.01 g/mol

                                               = 0.00012 mol

Since NaHCO₃ has fewer moles, it is the limiting reactant.

Therefore, 0.00012 mol of NaHCO₃  will produce 0.00012 mol of CO₂

The mass of CO₂ produced can be calculated as follows:

Mass of CO₂ = Number of moles of CO₂  x Molar mass of CO₂

Mass of CO₂ = 0.00012 mol x 44.01 g/mol

                             = 0.00528 g or 5.28 mg

Therefore, the amount of CO₂ produced is 5.28 mg.

The theoretical yield of CO₂ is 0.00012 mol x 44.01 g/mol

                               = 0.00528 g or 5.28 mg.

This is equal to the actual yield of CO₂ produced.

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Xeriscaping is a landscaping approach that focuses on conserving water by using drought-tolerant plants and efficient irrigation techniques. The goal is to create a visually appealing and sustainable garden while minimizing water usage.

Successful xeriscaping projects involve several key elements. Firstly, careful plant selection is crucial, opting for species that can thrive in arid conditions without excessive watering. Mulching is used to reduce evaporation and retain soil moisture.

Proper soil preparation, such as improving drainage and adding organic matter, promotes healthier plant growth. Efficient irrigation systems, like drip irrigation or soaker hoses, deliver water directly to plant roots, minimizing wastage.

Additionally, controlling erosion through the use of retaining walls or terracing is important. Lastly, regular maintenance, including appropriate pruning and weed control, ensures the longevity and vitality of the xeriscape garden. Overall, a successful xeriscaping project harmonizes sustainable practices with a beautiful outdoor environment.

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The actual result of the calculation is 101.920. Therefore, none of the options provided in the question matches the correct answer.

To calculate the given expression: (43 × 2.310) + (7 × 0.370), we perform the multiplication first and then add the results.

Multiplying the counted numbers:

43 × 2.310 = 99.330

Multiplying the measured numbers:

7 × 0.370 = 2.590

Now, we add the results:

99.330 + 2.590 = 101.920

The correct answer is not provided in the given options: a) 38.35, b) 38.4, c) 38, or d) 40.

The actual result of the calculation is 101.920. Therefore, none of the options provided in the question matches the correct answer.

It's important to note that when performing calculations, it is crucial to accurately follow the order of operations (multiplication before addition) and ensure precision when dealing with decimal numbers.

In this case, the correct answer is not among the options provided, and the accurate result is 101.920.

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\(\qquad \qquad\huge \underline{\boxed{\sf Answer}}\)

Here's the solution ~

\(\qquad \sf  FeCl_3 + 3 \: NaOH \dashrightarrow Fe(OH)_3 + 3 \: NaCl\)

Answer:

I'm not really sure how but here's the formula?

To calculate theoretical yield first check chemical equations are balanced.  Calculate the mole ratios of the reactants and products, Find the theoretical yield of the reaction.

Percent Yield = Mass of Actual Yield / Mass of Theoretical Yield x 100 percent.

The theoretical yield is the quantity of product that stoichiometry predicts will be produced, whereas the actual yield is the amount that is actually produced.

The yield of a reaction is used to represent how much of a product is produced from that reaction.

Thus, Divide the ratio by the limiting reactant's molecular weight. The answer is the theoretical yield of the desired product in moles.

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Synthetic materials are made from natural resources and can be used for many purposes.

Synthetic materials are made by chemically changing the starting substances to create a material with different characteristics. Some examples of synthetic materials are plastics, medicines, and new fuels.

A synthetic substance may be chemically identical to a naturally-occurring substance or may be different.

Item is made from a synthetic material :

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Answer:

Photosynthesis

Explanation:

The molecular weight of \((NH_4)_2SO_4\) would be 132 g/mol.

The molecular weight, otherwise known as the molar mass of substances is the sum of the molar weights of individual atoms that make up the substance.

\((NH_4)_2SO_4\) is made up of 2 atoms of N, 8 atoms of H, 1 atom of S, and 4 atoms of O.

Thus, the molecular weight of \((NH_4)_2SO_4\) = (14x2) + (1x8) + 32 + (16x4)

                                                                     = 132 g/mol

In other words, the molecular weight of \((NH_4)_2SO_4\) is 132 g/mol.

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Answer:

a. Serine is converted to pyruvate. It is glucogenic.

b. Aspartate is converted citric acid cycle intermediates. It is glucogenic.

c. Leucine is converted to AcetylCoA. It is ketogenic.

Explanation:

The degradation of amino acids usually account for a significant amount of energy production by the human body. The carbon skeletons of amino acids after deamination are either channelled to gluconeogenesis, ketogenesis or are completely oxidized to carbon dioxide and water.

The amino acids that are channelled to gluconeogenesis are said to be glucogenic. The glucogenic amino acids are those that are either degraded to ∝-ketoglutarate, succinylCoA, fumarate or oxaloacetate which are citric acid cycle intermediates that can be converted to glucose and glycogen. Also, amino acids that are degraded to pyruvate are glucogenic as pyruvate can be converted to glucose via oxaloacetate. Examples of these amino acids are serine which is converted to pyruvate and aspartate which is converted to the citric acid cycle intermediate, oxaloacetate.

On the other hand, amino acids that are channelled to ketogenesis are said to be ketogenic. The ketogenic amino acids are degraded to either acetylCoA or acetoacetylCoA. AcetylCoA and acetoacetylCoA are used in the formation of key one bodies. An example of a ketogenic amino acid is leucine which is converted both to AcetylCoA and acetoacetylCoA.

Answer:

d

Explanation:

yes