A common liquid contains 11.19% hydrogen and 88.81% oxygen by mass.
a) Calculate the number of moles of hydro- gen atoms and oxygen atoms in 100.0 g of this liquid
b) Calculate the number of hydrogen and oxygen atoms in 100.0 g of this liquid.
(those aren't very important I already solved them)
c) Knowing that the molar mass of this liquid is 18.00 g.mol', calculate how many moles of hydrogen atoms, and how many moles of oxygen atoms are present in a mole of this substance.
d) What is the number of hydrogen and oxy- gen atoms present in one molecule of this substance. Deduce the molecular mass of this liquid and write its molecular formula.​

Answer:

The answer is A. an unbalanced force

Explanation:

This is because the force from the hammer on the nail causes a force that unbalanced  normal forces on the nail.

Answer:

1. Given that the wavelength of the photon required to promote an electron in the hydrogen atom from the n = 1 to the n = 3 level is lt the wavelength of the photon required to promote an electron in the hydrogen atom from the n = 1 to the n = 2 level.

2. Given that the energy of a photon with a wavelength of 463 nm is gt the energy of a photon whose wavelength is 722 nm.

3. Therefore, in order to promote an electron to go to a higher energy level, light with a wavelength that is lt 400 nm is required

Explanation:

The equation for electron transition in a hydrogen atom is given by the Rydberg equation as follows;

\(\dfrac{1}{\lambda} = R \times \left (\dfrac{1}{n^2_f} - \dfrac{1}{n^2_i} \right )\)

The energy required for electron transition is given by the formula;

\(E = \dfrac{h \cdot c}{\lambda}\)

\(E = R_E \times \left (\dfrac{1}{n^2_f} - \dfrac{1}{n^2_i} \right )\)

Where;

h = The Planck's constant

λ = The wavelength of light

c = The speed of light

n = Specific energy level

\(R_E\) = -2.178 × 10⁻¹⁸ J

Therefore, the energy required to move an electron from one energy level to a higher energy level is inversely proportional to the wavelength of light, λ.

Increase in λ, results in lower energy available to transition to a higher energy level while a decrease in λ results in more energy available to transition to a higher energy level.

Answer:

2.765amu is the contribution of the X-19 isotope to the weighted average

Explanation:

The average molar mass is defined as the sum of the molar mass of each isotope times its abundance. For the unknown element X that has 2 isotopes the weighted average is defined as:

X = Mass X-19 * Abundance X-19 + MassX-21 * Abundance X-21

The contribution of the X-19 isotope is its mass (19.00 amu) times its abundance (14.55% = 0.1455). That is:

19.00amu * 0.1455 =

2.765amu is the contribution of the X-19 isotope to the weighted average

Answer:

pH= 1.17

Explanation:

The neutralization reaction between HBr (acid) and KOH (base) is given by the following equation:

HBr(aq) + KOH(aq) → KBr(aq) + H₂O(l)

According to this equation, 1 mol of HBr reacts with 1 mol of KOH. Then, the moles can be expressed as the product between the molarity of the acid/base solution (M) and the volume in liters (V). So, we calculate the moles of acid and base:

Acid:

M(HBr) = 0.15 M = 0.15 mol/L

V(HBr) = 50.0 mL x 1 L/1000 mL = 0.05 L

moles of HBr = M(HBr) x V(HBr) = 0.15 mol/L x 0.05 L = 7.5 x 10⁻³ moles HBr

Base:

M(KOH) = 0.25 M = 0.25 mol/L

V(HBr) = 13.0 mL x 1 L/1000 mL = 0.013 L

moles of HBr = M(HBr) x V(HBr) = 0.25 mol/L x 0.013 L = 3.25 x 10⁻³ moles KOH

Now, we have: 7.5 x 10⁻³ moles HBr > 3.25 x 10⁻³ moles KOH

HBr is a strong acid and KOH is a strong base, so they are completely dissociated in water: the acid produces H⁺ ions and the base produces OH⁻ ions. So, the difference between the moles of HBr and the moles of KOH is equal to the moles of remaining H⁺ ions after neutralization:

moles of H⁺ = 7.5 x 10⁻³ moles HBr - 3.25 x 10⁻³ moles KOH = 4.25 x 10⁻³ moles H⁺

From the definition of pH:

pH = -log [H⁺]

The concentration of H⁺ ions is calculated from the moles of H⁺ divided into the total volume:

total volume = V(HBr) + V(KOH) = 0.05 L + 0.013 L = 0.063 L

[H⁺] = (moles of H⁺)/(total volume) = 4.25 x 10⁻³ moles/0.063 L = 0.067 M

Finally, we calculate the pH after neutralization:

pH = -log [H⁺] = -log (0.067) = 1.17

The correct answer is calcium sulfate. Calcium sulfate acts as a buffer in embalming fluids, helping to maintain the pH of the solution and prevent decomposition of the tissues. It also helps to reduce the amount of water loss by increasing the osmotic pressure of the solution.

Calcium sulfate acts as a buffer in embalming fluids, helping to maintain a constant pH level and prevent the decomposition of tissues.

It does this by releasing or absorbing protons (H+) into the solution as needed, thus preventing the pH from becoming too acidic or too basic. Additionally, calcium sulfate increases the osmotic pressure of the solution, which helps to reduce the amount of water lost from the tissues. This helps the embalmed tissues to remain intact for a longer period of time.

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Answer:

valence electrons

Explanation:

they are the electrons that are in the outermost shell

Answer:

Explanation:

balance

2 C2H6 + 7  O2  --> 4 CO2 + 6 H2O

given 360 g H20 (g)

required =586.67 g CO2

360 g H20 x (1mole/18 g H20) X (4 mole CO2/6 moles H20) X (44g CO2/1mole) =586.67 g CO2

The structure of the branched ether of chemical formula c4h10o, is \(CH_3 - CH_2 - CH_2 - O - CH_2 - CH_2 - CH_3.\)

\(C_4H_{10} O\) is a branched ether, also known as an alkoxyalkane or a glycol ether. It is an organic compound composed of four carbon atoms, ten hydrogen atoms, and one oxygen atom. Its molecular formula is \(C_4H_{10} O\)and its molecular weight is 86.13 g/mol.

Its structure is linear, with a carbon backbone and an oxygen atom attached to two of the carbons in the chain. The oxygen atom is then connected to two methyl (\(CH_3\)) groups, one on each side of the central carbon atom.

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White-tailed deer have eyes on the sides of their heads. This provides them with a broad range of view for identifying predators.

Adaptation has three meanings in biology. For starters, natural selection is a dynamic evolutionary process that adapts organisms towards their environment, increasing their evolutionary fitness.

Second, it is a condition attained by the population as a result of that process. The fawns depend on their behavioral and physical adaptations to survive their first few weeks. White-tailed deer are quick and nimble. White-tailed deer have eyes on the sides of their heads. This provides them with a broad range of view for identifying predators.

Therefore, white-tailed deer have eyes on the sides of their heads. This provides them with a broad range of view for identifying predators.

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a. The chemical equation for the electrolysis of water is:

2H2O(l) → 2H2(g) + O2(g)

b. The gas obtained at the anode during the electrolysis of water is oxygen (O2).

c. The volume of gas obtained at the anode is 0.002232 moles or approximately 0.05 L of oxygen gas.

a. The chemical equation for the electrolysis of water is:

2H2O(l) → 2H2(g) + O2(g)

b. The gas obtained at the anode during the electrolysis of water is oxygen (O2).

c. According to the balanced chemical equation, for every 2 moles of water (H2O) electrolyzed, 1 mole of oxygen gas (O2) is obtained. Since 1 mole of any gas occupies 22.4 L at standard temperature and pressure (STP), we can use the stoichiometry of the reaction to determine the volume of oxygen gas produced.

Given that 50 cm³ of gas is obtained at the anode, we need to convert this volume to liters:

50 cm³ = 50/1000 L = 0.05 L

Using the stoichiometric ratio of the balanced equation, we find that 2 moles of water produce 1 mole of oxygen gas. Therefore, 0.05 L of oxygen gas is equivalent to:

0.05 L × (1 mole/22.4 L) = 0.002232 moles

Thus, the volume of gas obtained at the anode is 0.002232 moles or approximately 0.05 L of oxygen gas.

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The correct order of the five steps of the scientific method is as follows:

State problem

Form hypothesis

Conduct experiment

Interpret data

Draw conclusion.

The scientific method is a systematic approach used by scientists to investigate and understand the natural world. The five steps of the scientific method, in their logical order, are as follows:

State problem: In this step, the scientist identifies and defines a specific question or problem to be investigated. The problem should be clear and well-defined to guide the rest of the scientific process.

Form hypothesis: A hypothesis is a proposed explanation or prediction for the problem stated in step one. It is an educated guess that can be tested through experiments and observations. The hypothesis should be based on prior knowledge and observations.

Conduct experiment: In this step, the scientist designs and performs experiments to test the hypothesis. The experiment is carefully planned and executed, and data is collected through observations and measurements.

Interpret data: Once the experiment is completed, the scientist analyzes the collected data. This involves organizing, graphing, and statistically analyzing the data to identify patterns and trends.

Draw conclusion: Based on the interpretation of the data, the scientist draws conclusions about whether the hypothesis is supported or not. The conclusions should be objective and supported by evidence obtained from the experiment.

It's important to note that while these steps are presented in a linear order, the scientific process is often iterative, with scientists revisiting and refining hypotheses, conducting further experiments, and building upon existing knowledge.

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Answer:

this question is badly formatted. CO2

Explanation:

the answer is CO2 because C and O are both anions/nonmetals. the other examples contain a cation/metal, so they're ionic compounds

Answer:

The solubility is  \(S = 0.00912 \ g/mL\)

Explanation:

From the question we are told that

     The original volume of sample is  \(V_o = 34.0 mL = 34 *10^{-3} \ L\)

      The temperature is  \(T = 22.0 ^oC\)

      The new volume of sample  is  \(V_n = 750.0 mL = 750 *10^{-3} \ L\)

       The weight of the crystal is  \(X = 0.31 \ g = 0.31 *10^{-3} \ kg\)

Now looking at the question we see that 34.0 mL of the sample is saturated with  0.31g of the crystal X

Generally the solubility of X in the water sample at  \(22.0 ^oC\) can be mathematically evaluate as

                \(S = \frac{0.31 }{34.0}\)

                \(S = 0.00912 \ g/mL\)

Answer:

D. The model can be observed from the classroom more easily

Explanation:

From the concept of using wire coil to model and the concept of using spring coil to measure, we can come to the conclusion that the correct answer is Option D.

Taking into account the reaction stoichiometry,  102 grams of Al₂O₃ are formed when 48 grams of O₂ react.

In first place, the balanced reaction is:

4 Al + 3 O₂  → 2 Al₂O₃

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

The molar mass of the compounds is:

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

The following rule of three can be applied: if by reaction stoichiometry 96 grams of O₂ form 204 grams of Al₂O₃, 48 grams of O₂ form how much mass of Al₂O₃?

\(mass of Al_{2} O_{3} =\frac{48 grams of O_{2} x204 grams of Al_{2} O_{3}}{96 grams of O_{2}}\)

mass of Al₂O₃= 102 grams

Finally, 102 grams of Al₂O₃ are formed when 48 grams of O₂ react.

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Answer:false you are welcome

Explanation:

Answer: False I hope this helpful please mark me brainlist

Explanation:

Kinetic friction is the friction acting upon a moving object. It would be the frictional force against you if you pulled a box across a table.Static friction is the frictional force needed to overcome to get an object at rest into motion.

Answer:

i don't understand

Explanation:

Object Action to Release Energy Energy Transformation

Flashlight Press the switch Electric Energy → Light Energy

Chocolate Consume or melt Chemical Energy → Thermal Energy

Gas Ignite or burn Chemical Energy → Thermal Energy

Dynamite Detonate Chemical Energy → Mechanical Energy + Thermal Energy + Sound Energy + Light Energy

Olympic diver Jump or dive Potential Energy (Gravitational) → Kinetic Energy (Mechanical)

on platform  

Match Strike against a rough surface Chemical Energy → Thermal Energy + Light Energy

Stretched elastic band Release one end Elastic Potential Energy → Kinetic Energy (Mechanical)

Flashlight: To release the stored energy in a flashlight, you need to press the switch. This action completes an electrical circuit, allowing the electric energy stored in the battery to flow through the bulb, transforming into light energy.

Chocolate: Consuming or melting chocolate releases its stored energy. When you eat chocolate, it undergoes a chemical reaction in your body, breaking down the complex molecules and converting the chemical energy stored in the chocolate into thermal energy, providing you with warmth.

Gas: The stored energy in gas can be released by igniting or burning it. When gas reacts with oxygen in the presence of heat or a flame, a chemical reaction occurs, converting the chemical energy stored in the gas into thermal energy and producing light and heat.

Dynamite: To release the stored energy in dynamite, it needs to be detonated. When detonated, the chemical energy stored in dynamite rapidly transforms into various forms of energy, including mechanical energy (shockwave and debris movement), thermal energy (from the explosion heat), sound energy (from the blast), and light energy (from the explosion flash).

Olympic diver on platform: The stored energy in an Olympic diver on a platform is gravitational potential energy. To release this energy, the diver needs to jump or dive off the platform, converting the potential energy into kinetic energy as they descend, eventually entering the water.

Match: To release the stored energy in a match, you need to strike it against a rough surface. This action causes a chemical reaction in the match head, converting the chemical energy stored in the match into thermal energy and light energy, resulting in a flame.

Stretched elastic band: Releasing one end of a stretched elastic band allows it to return to its original shape, converting the stored elastic potential energy into kinetic energy. As the elastic band snaps back, it moves and vibrates, exhibiting mechanical energy.

These examples demonstrate different energy transformations, including chemical energy being converted to thermal energy, electrical energy transformed into light energy, potential energy being converted to kinetic energy, and elastic potential energy being converted to mechanical energy.

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Answer:

the osmotic pressure increases

Explanation:

The osmotic pressure of a solution is directly proportional to the concentration, expressed in molarity, of the solute in solution. That is to say that osmotic pressure increases.

Answer:

To calculate the molarity of the solution, we need to first calculate the number of moles of iron (III) sulfate present:

Number of moles = mass / molar mass

molar mass of Fe2(SO4)3 = 2(55.845) + 3(32.066) + 12(15.999) = 399.88 g/mol

Number of moles = 16.7 g / 399.88 g/mol = 0.0418 mol

Next, we need to calculate the volume of the solution in liters:

Volume = 250 mL = 0.250 L

Finally, we can calculate the molarity of the solution:

Molarity = Number of moles / Volume

Molarity = 0.0418 mol / 0.250 L = 0.167 M

To calculate the concentration of the iron(III) cation, we need to know the stoichiometry of the compound. In this case, the formula of iron (III) sulfate is Fe2(SO4)3, which means that there are 2 iron (III) cations for every 1 sulfate anion. Therefore, the concentration of the iron(III) cation is:

Concentration of Fe3+ = 2 x Molarity

Concentration of Fe3+ = 2 x 0.167 M = 0.334 M

Similarly, the concentration of the sulfate anion is:

Concentration of SO42- = Molarity

Concentration of SO42- = 0.167 M

Explanation:

The energy of combustion for one mole of butane to be approximately 2888.81 kJ/mol.

To calculate the energy of combustion for one mole of butane (C4H10), we need to use the information provided and apply the principle of calorimetry.

First, we need to convert the mass of the butane sample from grams to moles. The molar mass of butane (C4H10) can be calculated as follows:

C: 12.01 g/mol

H: 1.01 g/mol

Molar mass of C4H10 = (12.01 * 4) + (1.01 * 10) = 58.12 g/mol

Next, we calculate the moles of butane in the sample:

moles of butane = mass of butane sample / molar mass of butane

moles of butane = 0.367 g / 58.12 g/mol ≈ 0.00631 mol

Now, we can calculate the heat released by the combustion of the butane sample using the equation:

q = C * ΔT

where q is the heat released, C is the heat capacity of the calorimeter, and ΔT is the change in temperature.

Given that the heat capacity of the bomb calorimeter is 2.36 kJ/°C and the change in temperature is 7.73 °C, we can substitute these values into the equation:

q = (2.36 kJ/°C) * 7.73 °C = 18.2078 kJ

Since the heat released by the combustion of the butane sample is equal to the heat absorbed by the calorimeter, we can equate this value to the energy of combustion for one mole of butane.

Energy of combustion for one mole of butane = q / moles of butane

Energy of combustion for one mole of butane = 18.2078 kJ / 0.00631 mol ≈ 2888.81 kJ/mol

Therefore, the energy of combustion for one mole of butane is approximately 2888.81 kJ/mol.

In conclusion, by applying the principles of calorimetry and using the given data, we have calculated the energy of combustion for one mole of butane to be approximately 2888.81 kJ/mol.

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Therefore, 86.1 grams of calcium sulfate can dissolve in 75.0 L of pure water at equilibrium.

Only a small amount of calcium sulphate is available. The equilibrium constant, also referred to as the solubility product, is written as Ks for this kind of dissolution process. Ks = 4.9  10  6 for this reaction. K s = 4.9  10  6.

The formula for calcium sulphate's solubility product constant is:

Ksp = [Ca2+][SO42-]

The solubility product constant, Ksp, is equivalent to the product of the molar concentrations of Ca2+ and SO42- at equilibrium:

[Ca2+][SO42-] = Ksp

The following calculation can be used to determine the molar solubility of calcium sulphate:

Ksp = [Ca2+][SO42-] = x²

where x is the molar solubility of calcium sulfate.

Therefore, x = √(Ksp) = √(7.10 x 10⁻⁵) = 8.43 x 10³M

m = n × M

n = V × C

Substituting the given values, we get:

n = 75.0 L × 8.43 x 10⁻³ mol/L = 0.632 mol

m = 0.632 mol × 136.1 g/mol = 86.1 g

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The rate law expression for the destruction of O3 based on the proposed two-step mechanism is: rate = k[O3][NO]

This expression is derived from the proposed mechanism by identifying the rate-determining step (the slow step) and using the concentrations of the reactants involved in that step.

In this case, the slow step is the reaction between O3 and NO to form NO2 and O2. Therefore, the rate law expression is based on the concentrations of O3 and NO, and the rate constant k.

It is important to note that the rate law expression does not include the concentrations of the other reactants or products involved in the mechanism, as they are not involved in the rate-determining step.

Overall, the rate law expression for the destruction of O3 in the upper atmosphere based on the proposed two-step mechanism is rate = k[O3][NO].

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The change in entropy for the crystallization of 1.25 moles of butane can be calculated using the formula ΔS = ΔH_fusion / T, where ΔS is the change in entropy, ΔH_fusion is the enthalpy of fusion, and T is the temperature in Kelvin.

In the given problem, the enthalpy of fusion of butane is 24.3 kJ/mol. To convert this to J/mol, we multiply it by 1000, resulting in 24,300 J/mol. The melting point of butane is -0.5°C, which is equivalent to 272.65 K.

Using the formula, we can calculate the change in entropy as follows:

ΔS = (24,300 J/mol) / 272.65 K

    ≈ 89.25 J/(mol·K)

Therefore, the change in entropy for the crystallization of 1.25 moles of butane is approximately 89.25 J/(mol·K).

The change in entropy (ΔS) for the crystallization of a substance can be determined using the equation ΔS = ΔH_fusion / T, where ΔH_fusion is the enthalpy of fusion and T is the temperature in Kelvin. In this case, the enthalpy of fusion of butane is given as 24.3 kJ/mol, which is converted to 24,300 J/mol. The melting point of butane is -0.5°C, which is equivalent to 272.65 K.

By substituting the values into the equation, we find that the change in entropy is approximately 89.25 J/(mol·K). This means that for the crystallization of 1.25 moles of butane, the entropy decreases by 89.25 J/(mol·K).

Entropy is a measure of the disorder or randomness of a system. In this case, the crystallization process involves the transition from a disordered liquid state to an ordered solid state, resulting in a decrease in entropy. The magnitude of the entropy change depends on the enthalpy of fusion and the temperature. A higher enthalpy of fusion or a lower temperature leads to a larger change in entropy.

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The amount, in kJ, of heat needed to completely vaporize 50.0g of water at 100°C is 118.8 kJ.

The heat needed to completely vaporize 50.0g of water at 100°C can be calculated using the following formula:

q = m x Hv

where:

First, we need to convert 50.0g to moles by dividing by the molar mass of water which is approximately 18.015 g/mol3:

moles of water = 50.0 g / 18.015 g/mol moles of water = 2.776 mol

Thus:

q = (2.776 mol) x (40.65 kJ/mol) q = 112.8 kJ

In other words, 112.8 kJ of heat is needed to completely vaporize 50.0g of water at 100°C.

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Answer:

The TRUE statement about strong acids is that they are 100% ionized in water.

Explanation:

The TRUE statement about strong acids is that they are 100% ionized in water. This means that all the acid molecules dissociate in water to produce a high concentration of hydronium ions (H3O+) and the corresponding anions. Examples of strong acids include hydrochloric acid (HCl), sulfuric acid (H2SO4), and nitric acid (HNO3).

The CO32- ion contains two C-O single bonds and one C=O double bond. Option D.

It includes a single carbon atom surrounded by using three oxygen atoms in a trigonal planar configuration with chemical symmetry D3h. A unmarried bond is a chemical bond between two atoms that carries two valence electrons.

The Lewis structure the atoms proportion the electron pairs that form the bond. therefore, a unmarried bond is a form of covalent bond. The distinction between single double and triple bonds is that a unmarried bond is a covalent bond between  atoms a double bond is a covalent bond among two atoms that proportion a pair of electrons and a triple bond is it's far a covalent bond among two atoms that percentage 3 pairs of electrons.

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