A commercial building, 60Hz, three phase system, 230V, with total highest single phase ampere load of 1,235 amperes, plus the three phase load of 122 amperes;including the highest rated of a three phase motor of 15Hp, 230V, 3Phase, 42 amperes full load current. Determine the following through showing your calculation.
1. The size of Thhn copper conductor, conductor in EMT conduit.
2. The Instantenous Trip Power Circuit Breaker size.
3. The Transformer size
4. Generator size

Growling and Chattering are signs of worn clutch components; in certain cases, changing the limited slip lubrication oil resolves the issue.

Low oil levels starve component surfaces of lubricant, resulting in fast wear and eventual machine failure. Metal-on-metal friction can cause shaft, housing, and other machine damage, making this failure one of the most expensive ones.

In contrast to automatics, which only have two, manuals feature three pedals. The farthest pedal to the left is the clutch pedal. When changing from one gear to the next, including neutral, you utilize it to shift up or down.

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Answer:

Email etiquette is important

Explanation:

It is important to understand how to use correct email etiquette because it helps you communicate more clearly. It also makes you seem a bit more professional too. For example depending in who you're emailing like say you're emailing your teacher for help then here's how it'd go:

Dear(teacher name, capitalize, never use first name unless they allow it)

Hello (teacher name), my name is (first and last name) from your (number class) and I was wondering if you could please help me out with (situation, be clear on what you need help with otherwise it won't get through to them)? If you could that would be greatly appreciated!

Sincerely,

(your name first and last)

Tech b says that many oxygen sensors have a built-in heater to warm them up more quickly - correct

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Answer:

Emails and phone calls are both common forms of communication that are used in professional and personal settings. There are several similarities between email and phone calls:

1. Both are asynchronous forms of communication: Unlike instant messaging or face-to-face conversations, both emails and phone calls allow the sender or recipient to respond at their convenience. They don't require immediate attention or an instant response.

2. Both are written forms of communication: While phone calls rely on spoken words, emails are written. As a result, both can be used to convey detailed information and allow the sender to carefully consider their words before sending.

3. Both are forms of direct communication: Emails and phone calls both allow for direct communication between two parties. This can be beneficial for discussing sensitive information or resolving issues quickly.

4. Both can be used for formal and informal communication: Emails and phone calls can be used in both personal and professional contexts. They are both flexible forms of communication that can be adapted to fit different situations.

5. Both require attention to tone and etiquette: Just like with phone calls, emails require attention to tone and proper etiquette. Both forms of communication should be approached professionally and respectfully to ensure effective communication.

In conclusion, while there are differences between emails and phone calls, there are also similarities that make them useful communication tools. Both allow for direct, asynchronous communication and can be adapted to fit different situations.

Explanation:

Answer: Ethanol

Explanation:

Answer:

D. 90 degrees.

Explanation:

Torque is a rotational force which moves an object in other direction. There should be 90 degrees out of phase to start, run winding currents with each other. Torque is produced by the rotational motion of an object. The angle of the object must be 90 degrees set in order to create torque.

Answer:c. Operational Risk Management

Explanation:

The phrase "Fly-Crash-Fix-Fly" is often used to describe the concept of Operational Risk Management. It emphasizes the continuous cycle of identifying potential risks and hazards (Fly), analyzing and learning from past incidents and accidents (Crash), implementing corrective actions and preventive measures (Fix), and resuming normal operations with improved safety (Fly). This approach aims to proactively manage risks and enhance safety performance within an organization.

The program to convert MegaBytes to either Bytes, KiloBytes, GigaBytes, or TeraBytes is found in the attached image.

The program defines five helper functions to help the program do its work. The functions are:

Within the Main Program, a while loop is used to make sure the menu continues to be presented to the user until the user selects the option to quit.

The inner while loop makes sure the user enters an option within the menu.

Once the user enters an option to convert, the program requests the value to be be converted, in MegaBytes. then an if statement selects the correct conversion function.

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Answer:

Explanation:

The null hypothesis is that the mean fill volume is 16 oz, and the alternative hypothesis is that the mean fill volume is different from 16 oz. The level of significance is 5%, and the sample size is 15. The test statistic is t=0.0367t=0.0367. The p-value is 0.9738.

Since the p-value is greater than the level of significance, we fail to reject the null hypothesis. Therefore, there is not enough evidence to conclude that the mean fill volume is different from 16 oz. The engineer should not reset the machine.

```

The test statistic is calculated as follows:

t = (x - μ) / s / sqrt(n)

= (16.0367 - 16) / 0.0551 / sqrt(15)

= 0.0367

The p-value is calculated using the t-distribution with 14 degrees of freedom.

p-value = 2 * t.cdf(-0.0367, 14)

= 0.9738

```

Answer:

Engine oil level.

Brake fluid.

Power steering fluid.

To associate a keyboard event and an event-handling method with a widget, you can follow these steps:

1. Identify the widget you want to associate the keyboard event with. This can be any widget such as a button, text field, or a custom widget.

2. Register a keyboard event listener for the widget. In most programming frameworks or libraries, there are methods or functions available to register event listeners for specific events. Look for a method or function that allows you to register a keyboard event listener specifically.

3. Create an event-handling method or function that will be executed when the keyboard event occurs. This method should contain the logic you want to execute in response to the keyboard event.

4. Associate the event-handling method with the keyboard event listener for the widget. Use the appropriate method or function to bind or associate the event-handling method with the keyboard event listener. This step may involve passing the method reference or function name as an argument to the event listener registration method.

By completing these steps, the keyboard event will be associated with the widget, and when the specified keyboard event occurs (e.g., key press, key release), the associated event-handling method will be executed. This allows you to define custom behaviors or actions based on keyboard input for your widget.

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The 2x2 impedance matrix for the phase conductors is:

Z_phases = [0.4410+j0.1559 -j0.0562; -j0.0562

To find the impedance matrix, we first need to calculate the self-impedance and mutual impedance of the conductors. We can use the following formulas:

Self-impedance of a conductor:

Z_self = R + jX

where R is the resistance and X is the inductive reactance given by:

X = 2πfGMR

Mutual impedance between two conductors:

Z_mutual = jX_mutual

where X_mutual is given by:

X_mutual = 2πfGMD

where f is the frequency (assumed to be 60 Hz), GMR is the geometric mean radius, and GMD is the geometric mean distance between the conductors.

Given that the phase and neutral conductors are identical, we can calculate the self-impedance and mutual impedance for one conductor and multiply by 2 for the phase conductors and by 1 for the neutral conductor. Therefore, we have:

Self-impedance of one conductor:

Z_self = 0.1837 Ω/1000 ft + j(2π60 Hz0.0111 ft) = 0.1837 + j0.0418 Ω

Mutual impedance between phase conductors:

Z_mutual = j(2π60 Hz0.1418 ft) = j0.0531 Ω

Mutual impedance between phase and neutral conductors:

Z_mutual = j(2π60 Hz0.1777 ft) = j0.0669 Ω

Now, we can assemble the impedance matrix:

Z11 = Z22 = 2*Z_self + Z_mutual = 0.4637 + j0.1369 Ω

Z12 = Z21 = -Z_mutual = -j0.0531 Ω

Z13 = Z31 = -Z_mutual/2 = -j0.0335 Ω

Z23 = Z32 = -Z_mutual/2 = -j0.0335 Ω

Z33 = Z_self = 0.1837 + j0.0418 Ω

To remove the neutral conductor using Kron's reduction, we need to calculate the equivalent impedance seen by the phase conductors when the neutral is removed. We can do this by short-circuiting the neutral conductor and calculating the impedance between the phase conductors at the far end of the cable. The equivalent impedance is then given by:

Z_eq = Z_far - Z_3f/Z_33*Z_f3

where Z_far is the impedance matrix of the cable without the neutral conductor (i.e., the 2x2 matrix for the phase conductors), Z_3f and Z_f3 are the mutual impedances between the neutral conductor and each phase conductor, respectively.

Using the values above, we have:

Z_3f = Z_f3* = -j0.0669 Ω

Z_far = [Z11 Z12; Z21 Z22] = [0.4637+j0.1369 -j0.0531; -j0.0531 0.4637+j0.1369]

Z_33 = Z_self = 0.1837+j0.0418 Ω

Substituting these values, we get:

Z_eq = [0.4410+j0.1559 -j0.0562; -j0.0562 0.4410+j0.1559]

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The excludable interest is just $1,000 because Arthur's modified adjusted gross income exceeds the applicable dollar limit by $5,000.

Tax can be defined as the sum that is received by an individual or an organization on its profits or other income, and it is then received by the government.

Interest on education savings bonds is tax-free up to a maximum of $6,000 per bond.

$5,000 is the excess of the modified adjusted gross income.

Arthur should not exceed the phase-out limits in terms of adjusted gross income.

As a result, since Arthur's modified adjusted gross income is $5,000 more than the applicable dollar limit, the excludable interest is $1,000.

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Answer:

Explanation:

To find the discharge carried by the river, we need to use the cross-sectional area of the river and the velocity of the water. The cross-sectional area can be found by integrating the width of the river across the depth.If the side slope of the river is 1:1, that means that for every 1 meter of horizontal distance from the centerline, the depth of the water decreases by 1 meter. Using this information, we can set up the following integral to find the cross-sectional area:A = ∫[0,b] (b - x) dxWhere b is the width of the river at the base, and x is the distance from the centerline.Solving this integral, we find that the cross-sectional area is:A = (b^2)/2Now that we have the cross-sectional area, we can use the equation for discharge:Q = VAWhere Q is the discharge, V is the velocity of the water, and A is the cross-sectional area. If S is equal to 210^-4 for all sections, that means that the slope of the river is 210^-4. The velocity of the water can be found using the equation:V = √(SgD)Where S is the slope of the river, g is the acceleration due to gravity (9.81 m/s^2), and D is the depth of the water.If we plug in the values for S, g, and D, we can find the velocity of the water and then use the equation for discharge to find the total discharge carried by the river.For example, if the width of the river at the base is 10 meters and the depth of the water is 5 meters, the cross-sectional area would be:A = (10^2)/2 = 50 m^2The velocity of the water would be:V = √(2*10^-4 * 9.81 * 5) = 1.99 m/sAnd the discharge would be:Q = VA = 50 m^2 * 1.99 m/s = 99.5 m^3/sThis is the total discharge carried by the river.

Answer:

D). Eesha  pays more than the minimum payment each month.

Explanation:

Eesha would be considered most creditworthy among the given persons as she not only pays on time but also repays more than the minimum amount assigned to pay each month. In order to test the creditworthiness of an individual, his ontime debt paying capability is tested at first followed by the past credit repayment history and the credit score. Except Eesha, all the given candidates have failed to make timely repayment of their debts and hence, they cannot be considered creditworthy.

n, √n, 2/n, 2n/2, 37, 2n < n1.5 < n2 < nlogn < n log2 n < n log(n2) < n log log n < n2 log n < n3

Functions that grow at the same rate: n, √n, 2/n, 2n/2, and 37

What is function
In programming, a function is a block of code that performs a specific task. It is often used to perform a task based on given parameters, and can be reused multiple times. Functions are essential components of programming, and can be found in many different programming languages.

When a function is not functioning properly, it may not be producing the desired output or might be producing incorrect results. This could be due to a number of factors, such as incorrect syntax, a logical error in the code, or a bug in the code. In order to fix the issue, it is important to identify what is causing the malfunction and make any necessary changes to the code.

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Answer:

A

Explanation:

Primary radial system

Answer:

use it as a decimal and to. especially it by the time and divide by the speed k think

The model of a certain mass-spring-damper system is given as follows:10x¨+cẋ+20x=f(t)where f(t) is the input force applied to the mass m and x(t) is the displacement of the mass from its equilibrium position at time t.

The resonant frequency of the mass-spring-damper system can be found using the following formula:ωr=ωn√(1-2ζ^2)where,ωn=√(k/m) = natural frequency of the systemζ = damping ratio of the system, and c = 2ζωn m, where m = mass of the system.r = ωn√(1-2ζ^2)Given that ζ=0.1, we can find the resonant frequency as follows:r = ωn√(1-2ζ^2)Let's find the natural frequency of the system first.k = 20, m = 10, andωn=√(k/m)=√(20/10)=√2Thus,ωn=√2c = 2ζωn m = 2(0.1)(√2)(10) = 4√2Thus,c=4√2Substituting the values of ωn and ζ, we get:r = ωn√(1-2ζ^2)r = (√2)√(1-2(0.1)^2)r = 1.38 rad/sThus, the resonant frequency of the mass-spring-damper system is 1.38 rad/s.The peak magnitude M of the mass-spring-damper system can be found using the following formula:M = f0/2ζωnwhere f0 is the amplitude of the input force applied to the mass m.When the system is subjected to an input force of f0 = 1, we can find the peak magnitude of the system as follows:M = f0/2ζωn=1/2(0.1)(√2)(10)=1.78Thus, the peak magnitude of the mass-spring-damper system is 1.78.

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The elastic properties of the brass specimen enables it to return to its

original length when stressed below the yield strength.

The correct responses are;

4. a. The final length is 90.0 m.

b. The final length is 97.2 mm.

Reasons:  

a. Diameter of the brass alloy = 7.5 mm

Length of the specimen = 90.0 mm

Force applied = 6000 N

The equation for the applied stress, σ, is presented as follows;

\(\sigma = \dfrac{Force \ applied}{Area \ of \ specimen} = \dfrac{6000 \, N}{\pi \cdot \left(\dfrac{7.5 \times 10^{-3}}{2} \, m} \right)^2 } \approx 135.81 \ \mathrm{MPA}\)

Depending on the cold working condition, 135.81 MPa is below the yield

strength, and the brass will return to its original condition when the force is

removed. The final length is remains as 90.0 m.

b. When the applied force is F = 16,500 N, we have;

\(\sigma = \dfrac{16,500\, N}{\pi \cdot \left(\dfrac{7.5 \times 10^{-3}}{2} \, m} \right)^2 } \approx 373.48\ \mathrm{MPA}\)

The stress found for the force of 16,500 N is above the yield stress of

brass, and it is therefore, in the plastic region.

From the stress strain curve, the strain can be estimated by drawing a line

from the point of the 373.48 MP on the stress strain curve, parallel to the

elastic region to intersect the strain axis, which gives a value of strain

approximately, ε = 0.08.

The length of the specimen is given by the formula; \(l_i = l_0 \cdot (1 + \epsilon)\)

Therefore;

\(l_i\) = 90 × (1 + 0.08) = 97.2

The final length of the specimen, \(l_i\) = 97.2 mm

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It may not be advisable to directly compare the growth of organisms on each plate to each other for several reasons:

Variability in conditions: Each plate may have different conditions that affect organism growth, such as variations in temperature, pH, nutrient availability, or exposure to antibiotics. These differences can lead to growth rate variations, making direct comparisons unreliable.

Different organisms, different growth requirements: Organisms have diverse growth requirements, and comparing their growth directly may not provide meaningful insights. Some organisms may require specific nutrients or environmental conditions not present in all plates. Comparing growth between organisms with distinct growth requirements can lead to inaccurate conclusions.

Interference and competition: Some organisms interact with each other on the plate, through cooperation or competition. This can impact their growth rates and make direct comparisons challenging. For example, one organism may inhibit another's growth, resulting in apparent differences in growth rates that are not reflective of their individual capacities.

Statistical considerations: To draw reliable conclusions, consider data analyses when comparing growth. Simply observing growth visually may not provide a comprehensive understanding of the data. Statistical tests can help determine if observed differences are significant or simply due to random chance.

Instead of comparing growth directly between plates, it is often more advisable to analyze growth patterns within each plate individually. This allows for a better understanding of the specific conditions and interactions on each plate. This can provide valuable insights into individual organism growth characteristics.

Critical load Fcr or buckling load is the value of load that causes the phenomenon of change from stable to unstable equilibrium state.

With that beign said, first it is neessary to calculate the moment of inercia about the x-axis:

\(Ix= \frac{db^3}{12}\\ Ix = \frac{2.(4)^3}{12} = 10.667in\)

Then it is necessary to calculate the moment of inercia about the y-axis:

\(Iy = \frac{db^3}{12}\\ Iy = \frac{4.(2)^3}{12} = 2.662in\)

Comparing both moments of inercia it is possible to assume that the minimun moment of inercia is the y-axis, so the minimun moment of inercia is 2662in.

And so, it is possible to calculate the critical load:

\(Pc\gamma = \frac{2046\pi ^2E.I}{L^2} \\Pc\gamma= \frac{2046.\pi ^2.(1,6.10^3.10^3).2662}{(10.12)^2} \\Pc\gamma= 5983,9db\)

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Time-series data and cross-sectional data are two distinct types of data used in statistical analysis. Here's an explanation of each type and an example of how they can be used:

Time-series data:

Time-series data refers to a sequence of observations collected over regular intervals of time. In time-series data, the variable(s) of interest are measured and recorded at different points in time. This type of data allows for the analysis of trends, patterns, and relationships that evolve over time.

Example: Let's say you have collected daily temperature readings for a particular city over the past year. Each observation includes the date and the corresponding temperature. You can use this time-series data to analyze seasonal patterns, identify temperature trends, or forecast future temperatures.

Cross-sectional data:

Cross-sectional data, also known as snapshot data, represents observations taken at a particular point in time. In cross-sectional data, the variable(s) of interest are measured for multiple individuals, entities, or objects simultaneously. This type of data allows for comparisons and analysis across different groups or categories.

Example: Suppose you want to study the average income levels across various professions in a particular city. You collect data by surveying individuals from different professions within the city. Each observation includes the profession and the corresponding income. By analyzing this cross-sectional data, you can compare the income levels between different professions and identify any disparities.

In summary, time-series data focuses on changes over time, while cross-sectional data focuses on comparisons across different groups or categories at a specific point in time. Both types of data provide valuable insights into different aspects of statistical analysis and can be used to answer various research questions.

Answer:

The major financial flop that led to the end of the Sega Dreamcast and ultimately caused Sega to stop making game consoles altogether is:

3: A game called Shenmue, that cost more than $70 million to make, meant that everyone who owned a Dreamcast needed to buy two copies of the game just for Sega to make back the money they had spent to develop it-which didn't happen.

Explanation:

Shenmue, released on December 29, 1999, was created for Dreamcast by Suzuki.  It was widely described as the most expensive video game ever produced.  It had an estimated production and marketing cost of between US$47 and $70 million, according to the latest available data.

Answer:

L = Henry

C = Farad

Explanation:

The electrical parameter represented as L is the inductance whose unit is Henry(H).

The electrical parameter represented as C is the inductance whose unit is Farad

Resonance frequency occurs when the applied period force is equal to the natural frequency of the system upon which the force acts :

To obtain :

At resonance, Inductive reactance = capacitive reactance

Equate the inductive and capacitive reactance

Inductive reactance(Xl) = 2πFL

Capacitive Reactance(Xc) = 1/2πFC

Inductive reactance(Xl) = Capacitive Reactance(Xc)

2πFL = 1/2πFC

Multiplying both sides by F

F * 2πFL = F * 1/2πFC

2πF²L = 1/2πC

Isolating F²

F² = 1/2πC2πL

F² = 1/4π²LC

Take the square root of both sides to make F the subject

F = √1 / √4π²LC

F = 1 /2π√LC

Hence, the proof.