a coin with a diameter of 2.1 cm with an initial angular speed of 19 rad/sec and rolls in a straight line. The rotation slows at an angular acceleration of magnitude 1.9 rad/s^2. What is the magnitude of the linear acceleration?

Answer:

Blank 1 (asteroids)

Blank 2 (Ceres)

Explanation:

Rocky metallic objects found between the orbits of Mars and Jupiter are asteroids The largest known of these is ceres.

Asteroids are stony elements that circle the Sun. Although asteroids circle the Sun in the same way as planets, they are considerably smaller.]

A dwarf planet located between Mars and Jupiter in the asteroid belt. Ceres was the first asteroid discovered, it was originally classed as a planet,

Rocky metallic objects found between the orbits of Mars and Jupiter are asteroids The largest known of these is ceres.

The correct option from the drop-down menu is asteroids and ceres.

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More energy to escape gravitational pull of the Earth than to escape the pull of Moon is calculated as : D) 5

Escape velocity is the minimum speed needed for free, non-propelled object to escape from gravitational influence of primary body.

Energy required to escape the gravitational pull of a planet or a moon is:

\(\mathrm{E = (1/2)mv^2}\)

E is the energy required, m is mass of the object being launched, and v is escape velocity.

E(Earth) = (1/2)(1 kg)\(\mathrm{(11,000 m/s)^2}\) = \(\mathrm{6.05 \times 10^7 J}\)

E(Moon) = (1/2)(1 kg)\(\mathrm{(2,400 m/s)^2}\) = \(\mathrm{2.88 \times 10^6 \ J}\)

E(Earth) - E(Moon) = \(\mathrm{6.05 \times 10^7 J}\) - (\(\mathrm{2.88 \times 10^6 \ J}\)) = \(\mathrm{5.76 \times 10^7 \ J}\)

Answer D) is correct.

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Answer:

If we are upset, often our mind cannot think straight. we need to take deep breaths, and focus on reality. When we are upset we do things out of anger.

Explanation:

Hope this helps!

A prototype is the best example or representation of a concept, which is used as a design to shape a device.

A prototype can be defined as a given design in its experimental stage which is very useful to shape the framework or idea to carry out.

Therefore, with this data, we can see that a prototype can be very useful to shape an idea or concept about a given device in particular.

Complete question:

Fill in the blank. A _____ is the best example or representation of a concept.

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The question is incomplete. Here is the complete question.

Suppose the mass of a loaded elevator is 1600 kg.

(a) What force, in Newtons, must be supplied by the elveator's cable to produce an acceleration of 0.745 m/s² upwards against a 185N frictional force?

(b) How much work, in joules, is done by the cable in lifting the elevator 21m?

(c) What is the final speed, in meters per second, of the elevator if it starts from rest?

(d) How much work, in kilojoules, went into thermal energy produced by friction?

Answer: (a) F = 1377 N

              (b) W = 28917 J

              (c) v = 5.6 m/s

              (d) W = 3.885 kJ

Explanation:

(a) According to Newton's Second Law: \(F_{net}=m.a\), in which, \(F_{net}\) is the vetorial sum of all the forces in a system and its unit is [F] = kg.m/s² or newton (N).

In the elevator's case, and assuming going upwards is positive:

\(F-F_{f}=m.a\)

F - 185 = 1600(0.745)

F = 1377 N

For an elevator to produce an acceleration of 0.745m/s² upwards, the cables have to supply a force of 1377 newtons.

(b) Work is the energy transferred to an object while is being moved. It is calculated as: W = F.s. Its unit is [W] = N.m or Joule (J)

In the elevator's cable:

W = 1377.21

W = 28917 J

The work done by the elevator's cable is W = 28917 joules.

(c) Acceleration is variation in velocity along time. Since we know the displacement of the elevator:

\(v^{2}=v_{0}^{2}+2a\Delta x\)

where:

v₀ is initial velocity, which is this case v₀=0 because it starts from rest;

a is acceleration;

Δx is the displacement

Replacing values:

\(v^{2}=2(0.745)(21)\)

\(v=\sqrt{31.29}\)

v = 5.6 m/s

Final speed of the elevator is 5.6 m/s.

(d) \(W=F_{f}.s\)

W = 185(21)

W = 3885 J

Work transferred into thermal energy because of friction is W = 3.885 kJ.

If a current of 1 ampere enters a parallel circuit at Point A. This 1 ampere of current will divide between Resistors R1 and R2 and then recombine at Point B

A  parallel circuit is a circuit with separate branches with a common endpoint. In a parallel circuit, the voltage across each branch is the same but the currents vary. The total current is the sum of the currents flowing through each component.

If a current of 1 ampere enters a parallel circuit at Point A. This 1 ampere of current will divide between Resistors R1 and R2 and then recombine at Point B.

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Louis de Broglie's principle of electrons states that (b) They behave as a wave and a particle.

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S = displacement

V = final velocity

U = initial velocity

Answer:As the temperature increases, the helium in the ballon expands.

Explanation:

I took the quiz already

The answer is C) As the temperature increases, the helium in the balloons expands.

Have a blessed day!

Answer: False

Explanation:

Took the test.

Hide question 9 feedback

Rationale:

Ideal mechanical advantage is the ratio of input to output distance moved.

Use the work-energy theorem to find the velocity of the block when it's released by the spring. The work done by the spring on the block as it's restored to equilibrium is

W = 1/2 kx ²

where k is the spring constant and x is the compression of the spring. So

W = 1/2 (1400 N/m) (0.170 m)² = 20.23 J

This is equal to the block's change in kinetic energy ∆K,

W = ∆K

and since it starts from rest, the initial K is zero, leaving us with

W = 1/2 mv ²

where m is the mass of the block and v is its speed, so that

20.23 J = 1/2 (0.200 kg) v ²

==>   v ≈ 14.2 m/s

The block slides at this speed across the frictionless surface until it hits the incline which introduces friction.

First, you need to find the length of the incline. It forms a 45° angle, and the underlying 45°-45°-90° triangle has a hypotenuse of length √2 (2.0 m) ≈ 2.83 m.

Next, you need to find the total work done on the block as it slides up the incline. Use Newton's second law to examine the forces acting on the block during this phase:

• the net force acting on the block in the direction perpendicular to the incline is

∑ F = n - mg cos(45°) = 0

where n = mg cos(45°) ≈ 1.39 N is the magnitude of the normal force and mg cos(45°) ≈ 1.39 N is the perpendicular component of the block's weight;

• the net force acting on the block parallel to the surface is

∑ F = -f - mg sin(45°) = ma

where f = µn = 0.210n ≈ 0.291 N is the magnitude of kinetic friction, mg sin(45°) ≈ 1.39 N is the parallel component of the weight, and a is the acceleration of the block.

Only the parallel forces do work on the block, and this work is negative because friction and weight oppose the block's sliding up the incline. The total work done on the block is then

W = (-0.291 N - 1.39 N) (2.83 m) ≈ -4.74 J

Use the work-energy theorem again to find the block's new speed v at the top of the incline:

W = ∆K

==>   -4.74 J = 1/2 (0.200 kg) v ² - 1/2 (0.200 kg) (14.2 m/s)²

==>   v ≈ 12.4 m/s

And now this becomes a projectile problem. The block travels a horizontal distance x after being launched at an angle of 45° with initial speed 12.4 m/s after time t according to

x = (12.4 m/s) cos(45°) t

Its height y from the 2.0 m-high surface at time t is given by

y = (12.4 m/s) sin(45°) t - 1/2 gt ²

The block lands on the surface when y = 0, which occurs after t ≈ 1.79 s, at which point the block has covered a distance d ≈ 15.7 m.

The block sail through the air at the distance of "15.8 m"

Given:

Spring constant,

Mass,

Block's coefficient,

By using Work energy theorem, we get

→ \(W_{spring}+W_g+W_f = KE_f-KE_i\)

By substituting the values, we get

→ \(\frac{1}{2}\times 1400\times (0.17)^2- (0.2\times 9.8\times 2)-(0.21\times 0.2\times \frac{9.8}{\sqrt{2} }\times \sqrt{2}\times 2 )= \frac{1}{2}\times 0.2\times V_f^2\)

here,

\(V_f = 12.44 \ m/s\)

→ \(d = \frac{V_f^2 Sin 2 \Theta}{g}\)

     \(= \frac{(12.44)^2 Sin 90^{\circ}}{9.8}\)

     \(= 15.8 \ m\)

Thus the answer above is right.  

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If a frictionless plane is 10.0 m long and inclined at 36.0°.

We can use conservation of energy to find the distance that the first sled travels up the incline. The potential energy of the sled at the bottom of the incline is zero, and its kinetic energy is:

KE = (1/2)mv^2

where m is the mass of the sled and v is its speed. At the point where the sled stops, all of its kinetic energy has been converted into potential energy, so we can write:

mgh = (1/2)mv^2

where h is the height that the sled has traveled up the incline. Solving for h, we get:

h = (v^2)/(2g)

where g is the acceleration due to gravity. Using the given values, we have:

h = (6.00 m/s)^2 / (2 * 9.81 m/s^2) = 1.83 m

So the first sled travels a distance of 10.0 m - 1.83 m = 8.17 m up the incline.

b. To find the initial speed of the second sled, we can use conservation of energy again. At the top of the incline, the sled has potential energy:

PE = mgh

where h is the height of the incline. As the sled slides down the incline, its potential energy is converted into kinetic energy:

KE = (1/2)mv^2

where v is the speed of the sled at the bottom of the incline. We can equate these two expressions and solve for v:

mgh = (1/2)mv^2

v = sqrt(2gh)

Using the given values, we have:

v = sqrt(2 * 9.81 m/s^2 * 10.0 m * sin(36.0°)) = 12.2 m/s

So the second sled must be released from the top of the incline with an initial speed of 12.2 m/s.

The position of the sled as a function of time is given by:

y = -0.5gt^2 + Vi*t + h

where y is the vertical position of the sled, t is the time, Vi is the initial speed of the sled, and h is the height of the incline. At the bottom of the incline, y = 0, so we can solve for the time it takes for the second sled to reach the bottom:

0 = -0.5gt^2 + Vi*t + h

t = (Vi ± sqrt(Vi^2 - 2gh)) / g

Since we want both sleds to reach the bottom at the same time, we set the time for the first sled to slide down the incline equal to this expression for t and solve for Vi:

t = sqrt(2h/g) = sqrt(2 * 1.83 m / 9.81 m/s^2) = 0.619 s

0 = -0.5gt^2 + Vi*t + h

Vi = (h - 0.5gt^2) / t

Vi = (1.83 m - 0.5 * 9.81 m/s^2 * (0.619 s)^2) / 0.619 s

Vi = 5.68 m/s

So the initial speed of the second sled is about  5.68 m/s

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The magnitude of the initial acceleration of the object is 4.2 m/s².

The tension in the string once the object starts moving is 13.65 N.

The magnitude of the initial acceleration of the object is calculated by applying Newton's second law of motion as follows;

F(net) = ma

m₂g - μm₁g cosθ = a(m₁ + m₂)

where;

(4.75 x 9.8) - (0.535 x 3.25 x 9.8 x cos40) = a(3.25 + 4.75)

33.5 = 8a

a = 33.5/8

a = 4.2 m/s²

The tension in the string once the object starts moving is calculated as;

T = m₁a

T = 3.25 x 4.2

T = 13.65 N

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Answer:

50 m/s^2

Explanation:

F=ma

25 N= 0.5 kg • a

divide both sides by 0.5 kg

a=50 m/s^2

When a ball is dropped from the same height and at the same time as the ball that was shot horizontally, both balls will hit the ground at the same time. This is because both balls experience the same acceleration due to gravity, which is a constant 9.81 m/s² near the surface of the Earth.

The horizontal velocity of the second ball has no effect on its vertical motion. This is because the two motions (horizontal and vertical) are independent of each other, and do not interfere with each other.
The vertical motion of the second ball is determined solely by the force of gravity acting on it, which causes it to accelerate downwards at a constant rate. The time it takes for the ball to hit the ground is determined by its initial height and the acceleration due to gravity.

The first ball that is dropped vertically, travels only vertically. It doesn't have any horizontal velocity. Hence it comes down straight, whereas the other ball comes down in a parabolic path. However, both the balls will hit the ground at the same time as the horizontal motion doesn't affect the vertical motion.

Therefore, it can be concluded that if a ball is dropped from the same height and at the same time as the ball that was shot horizontally, both balls will hit the ground at the same time. This is because the time taken by both balls is the same as their motion is independent of each other.

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Here you go...

The speakers provide an enforcement role in the community and the people automatically obey them.

In the community, everyone’s every move is watched all of the time.  Community rules are reinforced by constant video surveillance.  When a person is seen breaking a rule, the voice over the speaker will remind...

Answer:

Explanation:

Sure, I'd be happy to help you with the question!

Let's denote the input as x. According to the function machine, the input is multiplied by 6 and then 80 is subtracted from the result to obtain the output.

So, the function can be written as:

Output = (6 * x) - 80

Now, the problem states that the input is the same as the output. Therefore, we can set up the equation:

x = (6 * x) - 80

Let's solve this equation to find the value of x:

x = 6x - 80

Subtracting 6x from both sides, we get:

x - 6x = -80

Combining like terms, we have:

-5x = -80

Dividing both sides by -5, we find:

x = (-80) / (-5)

Simplifying the expression, we have:

x = 16

Therefore, the input (x) that results in the input being the same as the output is 16.

To work out these types of questions, it's important to carefully read the instructions and understand the operations being performed in the function machine. Then, you can set up an equation with the input and output, and solve for the unknown value. Always double-check your solution to ensure it satisfies the given conditions of the problem.

Answer:

16

Explanation:

(x*6) - 80 = x

Multiply the parentheses

6x - 80 = x
Add 80 to each side to get
6x = x + 80
Subtract x from both sides to get
5x = 80
Divide both sides by 5
x = 16

Answer: i use this in ss class

Explanation:

Answer: the answer is 23voltage

Explanation: because the voltage and time put together is 23

Answer:

Explanation:

MEMORANDUM

To: Bennie

From: Finance Consultant

Subject: Recommendation to Move the Company to Mexico

I am writing to recommend that we move our company to Mexico. The move will reduce our expenses, make us more competitive, and provide several other benefits. In this memo, I will discuss the three biggest expenses and how the move will help reduce them.

Firstly, labor is one of the biggest expenses for our company. The minimum wage in Mexico is only $7.00 per day, which is significantly lower than the $60.00 per day in the US. Furthermore, Mexican workers may work 48 hours in a week before overtime must be paid, whereas US workers must be paid overtime for more than 40 hours in a week. This means that we can save a lot of money on labor costs by relocating to Mexico.

Secondly, transportation is another major expense for our company. Mexico is closer to many of our suppliers, which means that we can reduce transportation costs by sourcing our materials locally. This will also help us to reduce our carbon footprint by decreasing the amount of fuel we use for transportation.

Thirdly, the cost of doing business in Mexico is generally lower than in the US. Mexico has lower taxes and fewer regulations, which means that we can save money on compliance and other administrative costs. Additionally, the North American Fair Trade Agreement (NAFTA) allows companies from the member countries to import and export agricultural products without tariffs, which will help us to reduce our costs further.

The re-location will make us more competitive by allowing us to offer lower prices to our customers. Lower labor and transportation costs will enable us to produce our products at a lower cost, which means that we can sell them at a lower price. This will help us to increase our market share and attract more customers.

I anticipate that Bennie may have concerns about operating a business abroad. However, the benefits of the move far outweigh the potential problems. By off-shoring to Mexico, we can take advantage of the incentives provided by the Mexican government and create a better supply chain for our manufacturing processes. We can also maintain the quality of our products and ensure that they meet the demand and quantity required by our consumers.

In conclusion, I strongly recommend that we move our company to Mexico. The move will reduce our expenses, make us more competitive, and provide several other benefits. Thank you for your consideration, and please do not hesitate to contact me if you have any questions.

Sincerely,

[Your Name]

The magnitude of the force and the impulse applied to the car are  85714 N and  30000 N-s respectively.

The definition of force in physics is: The push or pull on a massed object changes its velocity. An external force is an agent that has the power to alter the resting or moving condition of a body. It has a direction and a magnitude.

The magnitude of the force applied to the car = change in momentum/time interval

= (1200 kg × 25 m/s - 1200 kg×0)/0.35 second

= 85714 N.

The impulse applied to the car = change in momentum

= (1200 kg × 25 m/s - 1200 kg×0)

= 30000 N-s.

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The image only shows the path of the ball and its different positions at different times during the flight.

To determine the speed of the ball at each position, additional information such as the time elapsed between each position and the distance traveled would be needed. Only with this information would it be possible to calculate the speed at each position and determine where the ball is traveling the fastest.

Speed is the measure of the distance traveled by an object over a specified period. It is a scalar quantity and is typically expressed in units of distance per unit of time, such as miles per hour, kilometers per hour, or meters per second. Speed can be calculated as the ratio of the distance covered by an object to the time taken to cover that distance. It is an important concept in physics and plays a critical role in determining the motion of objects, particularly in the field of mechanics.

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Answer:

D. Wavelength

Explanation:

An infrared (IR) and ultraviolet (UV) wave propagating through a vacuum must have the same wavelength.

The form of energy that is released into the atmosphere by the Earth’s surface is thermal radiation.

The statements that accurately describe the greenhouse effect are:

It is caused by gases in Earth’s atmosphere.

It warms up Earth’s surface and the lower atmosphere.

It maintains Earth’s normal range of temperatures.

The greenhouse effect is a natural process in which greenhouse gases (such as carbon dioxide, methane, and water vapor) in the Earth's atmosphere capture heat from the sun that is radiated by the Earth's surface.

This trapped heat warms the Earth's surface and lower atmosphere, assisting in the maintenance of a temperature range appropriate for life.

The greenhouse effect is responsible for maintaining the average temperature of the Earth at around 59°F (15°C).

The Earth's temperature would be too cold for most forms of life to live if the greenhouse effect did not exist.

Human actions such as the use of fossil fuels and deforestation have increased the concentration of greenhouse gases in the atmosphere, resulting in a more pronounced greenhouse effect known as global warming. This is causing global temperatures to rise, climate patterns to shift, sea levels to increase, and other environmental consequences.

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Answer:

\(3.6\times10^{23} N\)

Explanation:

\(F=\frac{GmM}{r^2}=4\times10^{22} N\)

\(F'=\frac{GmM}{(r/3)^2}=9\frac{GmM}{r^2}=9\times4\times10^{22}=3.6\times10^{23} N\)

if the planet were 3 times closer to the star, the magnitude of the force on the star due to the planet would be \(\( 3.6 \times 10^{23} \, \text{N} \).\)

The gravitational force between two objects is given by Newton's law of universal gravitation:

\(\[ F = \frac{G \cdot m_1 \cdot m_2}{r^2} \]\)

where:

F is the gravitational force between the two objects,

G is the gravitational constant \((\( G \approx 6.67430 \times 10^{-11} \, \text{m}^3/\text{kg}\cdot\text{s}^2 \)),\)

\(\( m_1 \)\) and \(\( m_2 \)\) are the masses of the two objects, and

r is the distance between the centers of the two objects.

Let's assume the planet is \(\( m_1 \)\) and the star is \(\( m_2 \).\)

Given that the original force is \(\( 4 \times 10^{22} \, \text{N} \)\), we have:

\(\[ F_{\text{original}} = 4 \times 10^{22} \, \text{N} \]\)

Let's denote the original distance between the planet and the star as \(\( r_{\text{original}} \).\)

Now, when the planet is 3 times closer to the star, the new distance \((\( r_{\text{new}} \))\) will be \(\( \frac{1}{3} \)\) of the original distance:

\(\[ r_{\text{new}} = \frac{1}{3} \cdot r_{\text{original}} \]\)

To find the new magnitude of the force \((\( F_{\text{new}} \))\) on the star due to the planet, we use the same formula with the new distance:

\(\[ F_{\text{new}} = \frac{G \cdot m_1 \cdot m_2}{r_{\text{new}}^2} \]\)

Substitute \(\( r_{\text{new}} \)\) with \(\( \frac{1}{3} \cdot r_{\text{original}} \):\)

\(\[ F_{\text{new}} = \frac{G \cdot m_1 \cdot m_2}{\left( \frac{1}{3} \cdot r_{\text{original}} \right)^2} \]\)

Simplify the expression:

\(\[ F_{\text{new}} = \frac{G \cdot m_1 \cdot m_2}{\frac{1}{9} \cdot r_{\text{original}}^2} \]\)

Multiply both the numerator and denominator by 9 to get rid of the fraction:

\(\[ F_{\text{new}} = \frac{9 \cdot G \cdot m_1 \cdot m_2}{r_{\text{original}}^2} \]\)

Now, we can see that \(\( F_{\text{new}} \)\) is simply 9 times the original force \(\( F_{\text{original}} \):\)

\(\[ F_{\text{new}} = 9 \times F_{\text{original}} \]\)

Substitute the value of \(\( F_{\text{original}} \):\)

\(\[ F_{\text{new}} = 9 \times 4 \times 10^{22} \, \text{N} \]\[ F_{\text{new}} = 36 \times 10^{22} \, \text{N} \]\[ F_{\text{new}} = 3.6 \times 10^{23} \, \text{N} \]\)

So, if the planet were 3 times closer to the star, the magnitude of the force on the star due to the planet would be \(\( 3.6 \times 10^{23} \, \text{N} \).\)

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Answer:

The value is  \(KE = 9 J\)

Explanation:

From the question we are told that

      The mass is  \(m = 0.5 \ kg\)

     The velocity is  \(v = 6 \ m/s\)

Generally the kinetic energy is mathematically represented as

        \(KE = \frac{ 1}{2} * m*v^2\)

=>     \(KE = \frac{ 1}{2} * 0.5*6^2\)

=>     \(KE = 9 J\)

Answer:

1➡️ this is the method of decomposition

2➡️ H2 and O2

3➡️ b

sorry if I am wrong