A coin rests on a record 0.15 m from its center. The record turns on a turntable that rotates at variable speed. The coefficient of static friction between the coin and the record is 0.30.

Required:
What is the maximum coin speed at which it does not slip?

Answers

Answer 1

Answer:

0.66m/s

Explanation:

We are expected to solve for the velocity with no slip condition

we know that the expression that relate coefficient of friction and velocity is given as

μs = v^2/rg

Given

coefficient of friction μs = 0.3

radius r= 0.15

assume g=9.81m/s^2

substituting into the expression we have

0.3= v^2/0.15*9.81

v^2=0.3*0.15*9.81

v^2=0.44145

v=√0.44145

v=0.66

therefore the velocity is 0.66m/s


Related Questions

a runner runs 10 miles in 1 hour. how far could they run in 2 hours in m/s?
16000 m/hr
1500 km/s
8.88 m/s
4.44m/s

Answers

Answer:

4.47 m/s.

Explanation:

distance traveled, d = 10 miles

time, t = 1 hour

Speed of the runner, v = d / t

Speed of the runner = 10 miles / 1

Speed of the runner = 10 mph

1 mph ----------------------- 0.44704 m/s

10 mph -----------------------?

= 4.47 m/s

Thus, in 2 hours the distance traveled will change but the speed it still 10 mph or 4.47 m/s.

If a runner runs 10 miles in 1 hour, the runner will go 4.47m/s.

HOW TO CALCULATE DISTANCE?

The average speed of a moving body can be calculated using the following formula:

Average speed = distance/time

In 2 hours, the runner will run in 10 × 2 = 20 miles, which is equivalent to 10miles/hr

Next, we convert miles/hr to m/s as follows:

10miles/hr to 4.47m/s.

Therefore, runner runs 10 miles in 1 hour, the runner will go 4.47m/s.

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A farmer plants the same crop in a field year after year. Every year there are months during which the field is left without any plants. The farmer notices a decline in soil
quality during these months. What causes this decrease in soil quality?
Erosion
Drought
Desertification
Consumption of nutrients by the crops

A farmer plants the same crop in a field year after year. Every year there are months during which the

Answers

Answer:

Drought

Explanation:

Objects motion plus blank forces equal blank velocity

Answers

Answer:\

unbalances and slow direction is the answer

Explanation:

Answer:

no change in motion

Explanation:

In hiking, what fitness component is required of you

Answers

It’s strength, endurance and flexibility. Hope this helps

Consider two simple pendula. Pendulum 1 has a length of L and a bob mass of m. Pendulum 2 has a length of 4L and a bob mass of 4m. If the period of pendulum 1 is 4 seconds, then the period of pendulum 2 is...


2 s
16 s
1 s
8 s

Answers

Answer:

8s

Explanation:

period of pendulum = 2π*√(l/g)

l = length of pendulum

period for 1st pendulum = 4 sec

thats 2π*√(l/g) = 4

for 2nd pendulum

length = 4 l

substitute 4l in formula

2π*√4l/g = 2*4= 8s

Given the data from the question, the period of the pendulum 2 is 8 s

Data obtained from the questionLength of pendulum 1 (L₁ ) = LPeriod of pendulum 1 (T₁ ) = 4 sLength of pendulum 2 (L₂) = 4LPeriod of pendulum 2 (T₂) = ?

How to determine the period of pendulum 2

The period of pendulum 2 can be obtained as illustrated below:

T²₁ / L₁ = T²₂ / L₂

4² / L = T²₂ / 4L

Cancel out L

4² = T²₂ / 4

Cross multiply

T²₂ = 4² × 4

T²₂ = 64

Take the square root of both sides

T₂ = √64

T₂ = 8 s

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a quantum oscillator in the wall of a black body cabity has frequency of 5.0*10(14) Hz. calculate the energy of the first two quantum states.

Answers

The energy of the first two quantum states, given that the black body cabity has frequency of 5.0×10¹⁴ Hz is 3.313×10⁻¹⁹ J

How do I determine the energy?

Energy is defined as the capacity to do work. However, energy and frequency are related according to the formula given below:

E = hf

Where

E is the energyh is the Planck's constant f is the frequency

We can obtain the energy of the two quantum states as shown below:

Frequency (f) = 5.0×10¹⁴ HzPlanck's constant (h) = 6.626×10⁻³⁴ JsEnergy (E) =? 6.23×10⁻¹⁹ J

Energy (E) = Planck's constant (h) × frequency (f)

E = hf

E = 6.626×10⁻³⁴ × 5.0×10¹⁴

E = 3.313×10⁻¹⁹ J

Thus, we can conclude from the above calculation that the energy is 3.313×10⁻¹⁹ J

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What is MOST likely to be TRUE about asynchronous communication?
It is rarely used in businesses in today's society.
It offers many opportunities to ask clarifying questions in real time.
It is helpful when employees work across multiple time zones.
It only works when all employees work in the same time zone.

Answers

The most likely true statement about asynchronous communication is that it is helpful when employees work across multiple time zones.

Asynchronous communication refers to a mode of communication where participants do not need to be present or engaged simultaneously. Instead, they can send and receive messages at their convenience.In today's globalized society, businesses often have teams distributed across different geographical locations and time zones. Asynchronous communication becomes invaluable in such scenarios as it allows team members to collaborate effectively without the constraints of real-time interactions. By utilizing tools like email, project management platforms, or messaging apps, individuals can communicate and exchange information regardless of their location or the time differences.

Asynchronous communication also offers benefits such as flexibility and increased productivity. Team members have the freedom to work at their own pace and prioritize tasks accordingly. It provides opportunities for thoughtful and well-crafted responses, as individuals can take time to gather information or reflect on complex matters before replying.While asynchronous communication is advantageous for teams operating across multiple time zones, it does not rely on all employees working in the same time zone. In fact, it is designed to accommodate diverse schedules and allow individuals to collaborate efficiently despite their varying work hours.

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2. A tennis ball machine launches balls horizontally with an initial speed of 5.3 m/s, from a height of 1.2 m.
a) What will the time of flight be for a tennis ball launched by the ball machine? (3)
b) What will the range of the tennis ball be? (2)
c) What will be the final velocity of the ball with which it reaches the ground? (3)

Answers

(a) The time of flight be for a tennis ball launched by the ball machine is 0.19 s.

(b) The range of the tennis ball be is 1.01 m.

(c)  The final velocity of the ball with which it reaches the ground is 7.16 m/s.

Time of flight of tennis ball

The time of flight of the tennis ball is calculated as follows;

h = vt + ¹/₂gt²

1.2 = 5.3t + 0.5(9.8)t²

1.2 = 5.3t + 4.9t²

4.9t² + 5.3t - 1.2 = 0

a = 4.9, b = 5.3, c = 1.2

solve using quadratic formula

t = 0.19 s

Thus, the time of flight be for a tennis ball launched by the ball machine is 0.19 s.

Range of the tennis ball

The range of the tennis ball is calculated as follows;

R = vt

R = 5.3 x 0.19

R = 1.01 m

Final velocity of the ball

The final velocity of the ball with which it reaches the ground is calculated as follows;

vf = vo + gt

vf = 5.3 + 9.8(0.19)

vf = 7.16 m/s

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A thin half ring with a radius of R = 10 cm is uniformly charged with a linear density of = 1 Mikrokulon/m and located in a vacuum. Determine the force F of interaction between the half ring and a point charge q = 20 nC located at the center of curvature. (don't use chatgpt please)

Answers

Answer:

Explanation:

F = k * q * lambda * R * π * (1 - √2/2)

Substituting the given values of q, lambda, R, and k, we get:

F = (9 x 10^9 N*m^2/C^2) * (20 x 10^-9 C) * (1 x 10^-6 C/m) * (0.1 m) * π * (1 - √2/2)

F ≈ 8.58 x 10^-4 N

Therefore, the force of interaction between the half ring and the point charge is approximately 8.58 x 10^-4 N.

If a baseball travels a distance of 4 meters in 5 seconds, what is its average speed

Answers

Answer:

speed=d/t.

s=4/5=0.8m/s.

What does it mean for a chemical equation to be balanced?

Answers

Answer:

The number of each type of atom is the same for both the reactants and products.

I hope this helps

Pretty simple physics :) will give brainliest
pls dont just use me for points

Pretty simple physics :) will give brainliestpls dont just use me for points

Answers

Answer:

meter per second(m/s)

Explanation:

At what separation will two charges, each of magnitude 6.0 μC, exert a force of 0.70 N on

each other?

Answers

The given magnitude of the two charges are 6μc and they exert a force of 0.7N on each other. We need to find the distance of separation between the particles.

By Coloumb's Law :-

\(\sf\longrightarrow F =\dfrac{1}{4\pi\epsilon_0} \dfrac{q_1q_2}{r^2} \)

where

q1 and q2 are the two charges r is the distance of separation1/4πe0 = 9 * 10⁹

Substitute the respective values,

\(\sf\longrightarrow \) 0.7 = {(9*10⁹) (6*6) (10-⁶ *10-⁶) }/ r²

\(\sf\longrightarrow \) r² = (36*9 * 10-³)/0.7

\(\sf\longrightarrow \) r =√{ 36*9*10-³)/√7 m

\(\sf\longrightarrow \) r = 6* 3* 10-¹ /√70 m

\(\sf\longrightarrow \) r = 0.21 m

And we are done!

Two 22.7 kg ice sleds initially at rest, are placed a short distance apart, one directly behind the other, as shown in Fig. 1. A 3.63 kg cat, standing on the left sled, jumps across to the right one and immediately comes back to the first. Both jumps are made horizontally at a speed of 3.05 m/s relative to the ice. Ignore the friction between the sled and ice.
(a) Find the final speeds of the two sleds. [6 marks]
(b) Calculate the impulse on the cat as it lands on the right sled. [2 marks]
(c) Find the average force on the right sled applied by the cat while landing. Consider that the cat takes 12 ms to finish the landing.

Answers

Newton's third law of motion sates that force is directly proportional to the rate of change of momentum produced

(a) The final speeds of the ice sleds is approximately 0.49 m/s each

(b) The impulse on the cat is 11.0715 kg·m/s

(c) The average force on the right sled is 922.625 N

The reason for arriving at the above values is as follows:

The given parameters are;

The masses of the two ice sleds, m₁ = m₂ = 22.7 kg

The initial speed of the ice, v₁ = v₂ = 0

The mass of the cat, m₃ = 3.63 kg

The initial speed of the cat, v₃ = 0

The horizontal speed of the cat, v₃ = 3.05 m/s

(a) The required parameter:

The final speed of the two sleds

For the first jump to the right, we have;

By the law of conservation of momentum

Initial momentum = Final momentum

m₁ × v₁ + m₃ × v₃ = m₁ × v₁' + m₃ × v₃'

Where;

v₁' = The final velocity of the ice sled on the left

v₃' = The final velocity of the cat

Plugging in the values gives;

22.7 kg × 0 + 3.63 × 0 = 22.7 × v₁' + 3.63 × 3.05

∴  22.7 × v₁'  = -3.63 × 3.05

v₁' =  -3.63 × 3.05/22.7 ≈ -0.49

The final velocity of the ice sled on the left, v₁' ≈ -0.49 m/s (opposite to the direction to the motion of the cat)

The final speed ≈ 0.49 m/s

For the second jump to the left, we have;

By conservation of momentum law,  m₂ × v₂ + m₃ × v₃ = m₂ × v₂' + m₃ × v₃'

Where;

v₂' = The final velocity of the ice sled on the right

v₃' = The final velocity of the cat

Plugging in the values gives;

22.7 kg × 0 + 3.63 × 0 = 22.7 × v₂' + 3.63 × 3.05

∴  22.7 × v₂'  = -3.63 × 3.05

v₂' =  -3.63 × 3.05/22.7 ≈ -0.49

The final velocity of the ice sled on the right = -0.49 m/s (opposite to the direction to the motion of the cat)

The final speed ≈ 0.49 m/s

(b) The required parameter;

The impulse of the force

The impulse on the cat = Mass of the cat × Change in velocity

The change in velocity, Δv = Initial velocity - Final velocity

Where;

The initial velocity = The velocity of the cat before it lands = 3.05 m/s

The final velocity = The velocity of the cat after coming to rest =

Δv = 3.05 m/s - 0 = 3.05 m/s

The impulse on the cat = 3.63 kg × 3.05 m/s = 11.0715 kg·m/s

(c) The required information

The average velocity

Impulse = \(F_{average}\) × Δt

Where;

Δt = The time of collision = The time it takes the cat to finish landing = 12 ms

12 ms = 12/1000 s = 0.012 s

We get;

\(F_{average} = \mathbf{\dfrac{Impulse}{\Delta \ t}}\)

∴ \(F_{average} = \dfrac{11.0715 \ kg \cdot m/s}{0.012 \ s} = 922.625 \ kg\cdot m/s^2 = 922.625 \ N\)  

The average force on the right sled applied by the cat while landing, \(\mathbf{F_{average}}\) = 922.625 N

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2. Using Graph 2, calculate the net force experienced by the particle between 4 and 6 seconds. The
particle has a mass of 0.25 kg.

A +5.0 N
B. +0.5 N
C. -0.5 N
D. -2.0 N

2. Using Graph 2, calculate the net force experienced by the particle between 4 and 6 seconds. Theparticle

Answers

Using Newtons Second Law:

F = m×a

F = (0.25 kg)(-2 m/s²)

F = -0.5 N

The correct option is C

A smooth circular cylinder of radius 1.5m in a triangular grove, one side of which makes 15 °angle and the other 40° angle with the horizontal · Find the reaction. at the surface of contact, if there. is no fiction and the cylinder weigh 100N ​

Answers

Answer:

46.5 N

Explanation:

attached is explanation

PLEASE HELP PLEASEEEE

Answers

Answer:

How can I help you??? Plz insert some questions

Explain the advantages and disadvantages of having a racecar with a small mass in reference to Newton’s 1st law of motion. Use the term inertia in your answer.

Answers

Answer:

Newton's first law states that every object will remain at rest or in uniform motion in a straight line unless compelled to change its state by the action of an external force. This tendency to resist changes in a state of motion is inertia.

Explanation:

An airplane weighs 41,000 kg. How long will it take the airplane to travel 10,924 km to Rome, Italy if the plane flies at 988 km/hr?

Answers

It will take the airplane approximately 15,116 seconds, or about 4.2 hours, to travel 10,924 km to Rome, Italy.

What is the formula of time ?

To find the time it takes for the airplane to travel 10,924 km, we can use the formula:

time = distance / speed

where distance is 10,924 km and speed is 988 km/hr.

First, we need to convert the airplane's weight of 41,000 kg to Newtons, the unit of force used in physics:

force = mass x acceleration due to gravity

force = 41,000 kg x 9.8 m/s^2 = 401,800 N

Now, we can use Newton's second law of motion, which states that force equals mass times acceleration, to find the acceleration of the airplane:

force = mass x acceleration

401,800 N = 41,000 kg x acceleration

acceleration = 9.8 m/s^2

we can use the kinematic equation

distance = (1/2) x acceleration x time^2 + initial velocity x time

Since the airplane starts from rest, the initial velocity is 0, so we can simplify the equation to

distance = (1/2) x acceleration x time^2

Solving for time,

time = square root(2 x distance / acceleration)

Plugging in the values ,

time = square root(2 x 10,924,000 m / 9.8 m/s^2 x 1000) = 15,116 seconds

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Share an experience you've had with the bureaucracy. In thinking about that experience, how would you describe the bureaucracy? What characteristics of the bureaucracy did you observe in that experience? Please explain. (Refer to Weber's theory of bureaucracy in the module.)

Answers

Bureaucracy theory explains the basis of the systematic formation of any organization and ensures efficiency and economic effectiveness.

Bureaucracy is the theory proposed by Max Weber. It forms the ideal model for the management and administration of the organization and ensures its efficiency of organization into focus.

It includes six basic principles. They are Authority Hierarchy, Division of labor, impersonality, Career Orientation, Formal rules and regulations, and Selection process.

The characteristics of bureaucracy include: It can control and regulate the behavior of people in an organization. It is the organization that has the power to make decisions. The organizations have certain rules to follow by the people.

Bureaucracy is found in large organizations like governments and corporations. It has standardized methods, and procedures to practice. It doesn't allow any flexibility for the organization.

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The drawing shows a set of equipotential surfaces seen in cross-sections. Each is
labelled according to its electric potential. A 3.9 x 10-7 C point charge is placed at
position A. Find the work done on the point charge by the electric force when it is
moved (i) from A to B, and (ii) A to C.

Answers

(i) The work done on the point charge by the electric force when moved from A to B is 2.1 x 10⁻⁶ J.

(ii) The work done on the point charge by the electric force when moved from A to C is -5.5 x 10⁻⁶ J.

The work done by an electric force is equal to the negative of the change in potential energy, which is given by the product of the charge and the change in potential. The change in potential between two points is equal to the potential difference between those points.

For (i), the potential difference between A and B is 6 V, so the work done is (3.9 x 10⁻⁷ C) x (-6 V) = -2.1 x 10⁻⁶ J (negative because the charge moves from higher to lower potential).

For (ii), the potential difference between A and C is -15 V, so the work done is (3.9 x 10⁻⁷ C) x (-(-15 V)) = -5.5 x 10⁻⁶ J (negative because the charge moves from lower to higher potential).

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A rigid, insulated tank whose volume is 10 L is initially evacuated. A pinhole leak develops and air from the surroundings at 1 bar, 25 C enters the tank until the pressure in the tank becomes 1 bar (assume ideal gas model k=1.4 for the air). Find:
A) final temperature in tank.
B) amount of air that leaks into tank in grams.
C) amount of entropy produced in J/K.

Answers

Answer:

The answer is "\(143.74^{\circ} \ C , 8.36\ g, and \ 2.77\ \frac{K}{J}\)"

Explanation:

For point a:

Energy balance equation:

\(\frac{dU}{dt}= Q-Wm_ih_i-m_eh_e\\\\\)

\(W=0\\\\Q=0\\\\m_e=0\)

From the above equation:

\(\frac{dU}{dt}=0-0+m_ih_i-0\\\\\Delta U=\int^{2}_{1}m_ih_idt\\\\\)

because the rate of air entering the tank that is \(h_i\) constant.

\(\Delta U = h_i \int^{2}_{1} m_i dt \\\\= h_i(m_2 -m_1)\\\\m_2u_2-m_1u_2=h_i(M_2-m_1)\\\\\)

Since the tank was initially empty and the inlet is constant hence, \(m_2u-0=h_1(m_2-0)\\\\m_2u_2=h_1m_2\\\\u_2=h_1\\\\\)

Interpolate the enthalpy between \(T = 300 \ K \ and\ T=295\ K\). The surrounding air  

temperature:

\(T_1= 25^{\circ}\ C\ (298.15 \ K)\\\\\frac{h_{300 \ K}-h_{295\ K}}{300-295}= \frac{h_{300 \ K}-h_{1}}{300-295.15}\)

Substituting the value from ideal gas:

\(\frac{300.19-295.17}{300-295}=\frac{300.19-h_{i}}{300-298.15}\\\\h_i= 298.332 \ \frac{kJ}{kg}\\\\Now,\\\\h_i=u_2\\\\u_2=h_i=298.33\ \frac{kJ}{kg}\)

Follow the ideal gas table.

The \(u_2= 298.33\ \frac{kJ}{kg}\) and between temperature \(T =410 \ K \ and\ T=240\ K.\)

Interpolate

\(\frac{420-410}{u_{240\ k} -u_{410\ k}}=\frac{420-T_2}{u_{420 k}-u_2}\)

Substitute values from the table.

 \(\frac{420-410}{300.69-293.43}=\frac{420-T_2}{{u_{420 k}-u_2}}\\\\T_2=416.74\ K\\\\=143.74^{\circ} \ C\\\\\)

For point b:

Consider the ideal gas equation.  therefore, p is pressure, V is the volume, m is mass of gas. \(\bar{R} \ is\ \frac{R}{M}\) (M is the molar mass of the  gas that is \(28.97 \ \frac{kg}{mol}\) and R is gas constant), and T is the temperature.

\(n=\frac{pV}{TR}\\\\\)

\(=\frac{(1.01 \times 10^5 \ Pa) \times (10\ L) (\frac{10^{-3} \ m^3}{1\ L})}{(416.74 K) (\frac{8.314 \frac{J}{mol.k} }{2897\ \frac{kg}{mol})}}\\\\=8.36\ g\\\\\)

For point c:

 Entropy is given by the following formula:

\(\Delta S = mC_v \In \frac{T_2}{T_1}\\\\=0.00836 \ kg \times 1.005 \times 10^{3} \In (\frac{416.74\ K}{298.15\ K})\\\\=2.77 \ \frac{J}{K}\)

Can a convex mirror form a real image?​

Answers

Answer:

yes !

Explanation:

a mirror transforms and flips , but nonetheless produces a real image.

0.0884 moles of a diatomic gas
are in a piston. When the piston
is compressed, the temperature
drops by 18.8 K, and 83.7 J of
heat flow out. Find W.
(Be careful with + and - signs.
+W = expansion, +Q = added,
+AU = temp goes up)
(Unit = J)

Answers

Answer:

W = - 118.24 J (negative sign shows that work is done on piston)

Explanation:

First, we find the change in internal energy of the diatomic gas by using the following formula:

\(\Delta\ U = nC_{v}\Delta\ T\)

where,

ΔU = Change in internal energy of gas = ?

n = no. of moles of gas = 0.0884 mole

Cv = Molar Specific Heat at constant volume = 5R/2 (for diatomic gases)

Cv = 5(8.314 J/mol.K)/2 = 20.785 J/mol.K

ΔT = Rise in Temperature = 18.8 K

Therefore,

\(\Delta\ U = (0.0884\ moles)(20.785\ J/mol.K)(18.8\ K)\\\Delta\ U = 34.54\ J\)

Now, we can apply First Law of Thermodynamics as follows:

\(\Delta\ Q = \Delta\ U + W\)

where,

ΔQ = Heat flow = - 83.7 J (negative sign due to outflow)

W = Work done = ?

Therefore,

\(-83.7\ J = 34.54\ J + W\\W = -83.7\ J - 34.54\ J\\\)

W = - 118.24 J (negative sign shows that work is done on piston)

Answer:

-49.2

Explanation:

Trust me bro

A car moves with an average speed of 45 miles/hour. How long will it take the car to travel 90 miles?

Answers

It will take two hours for the car to travel 90 miles!!

45x2= 90

A car accelerates from rest at 3.00 m/second squared What is the velocity after 5 secs ? What is the displacement after 5 seconds?

Answers

Explanation:

after 5 seconds, the velocity is (5s)(3m/s²) = 15m/s

The displacement after 5s is

x=vo + (1/2)at²

x = 0 + (1/2)(3m/s²)(5s)(5s)

x= 37.5 m

A car accelerates from rest at 3.00 m/second then its velocity after 5 seconds would be 15 m/s and its covers a total displacement of  after 5 seconds  37.5 m  

What are the three equations of motion?

There are three equations of motion given by  Newton

The first equation is given as follows

v = u + at

the second equation is given as follows

S = ut + 1/2×a×t²

the third equation is given as follows

v² - u² = 2×a×s

As given in the problem a car accelerates from rest at 3.00 m/second squared

By using the first equation of motion

v= u + at

v = 0 + 3×5

v = 5 m/s

The velocity after 5 seconds would be 15 m/s

Now to calculate displacement after 5 seconds

S = ut + 1/2at²

u= 0 m/s , a= 3 m/s² and t = 5  seconds

S =  0.5*3*5²

S=37.5 m

The displacement after 5 seconds would be 37.5 m  

Thus, velocity after 5 seconds would be  15 m/s, and it covers a total displacement of  after 5 seconds 37.5 m  

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A certain object weight 300N at the earth's surface Determine the mass of the object in kg and it's weight in Newton when located on a planet with an acceleration of gravity equal to 4.0ft/s²

Answers

We are given:

Weight on Earth = 300 N

Value of g on the planet = 4 ft/s²

Converting to m/s:

4 ft/s² * (1 m / 3.3 ft) = 13.2 m/s²

Mass of the object:

We know that:

Weight = Mass * g

replacing the given values

300 = Mass * 9.8                                              [g = 9.8 m/s²]

Mass = 300/9.8

Mass = 30.6 kg (approx

Weight on the other Planet:

Weight = Mass * g(on that planet)

Weight = 30.6 kg * 13.2 m/s²

Weight = 403.92 N

in physics what is moment of couples?​

Answers

The moment of a couple is significant in various applications, such as analyzing the equilibrium and rotational motion of objects, understanding the behavior of rotating systems, and studying the effects of torques in mechanics and engineering.

In physics, the moment of a couple, also known as torque, refers to the rotational effect produced by two equal and opposite forces acting on an object but not along the same line of action.

A couple consists of two forces that have the same magnitude, act in parallel lines, and are opposite in direction. These forces create a rotational moment or torque around a particular point, known as the pivot or axis of rotation. The moment of a couple is a measure of the tendency of the couple to rotate an object.

The magnitude of the moment of a couple is given by the product of one of the forces and the perpendicular distance between the lines of action of the two forces. Mathematically, it can be expressed as:

Moment of couple = Force × Perpendicular distance

The SI unit of moment of a couple is the newton-meter (Nm). It is also important to note that the moment of a couple is a vector quantity and follows the right-hand rule for determining its direction.

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Unscramble heenagwirt

Answers

I believe the answer is weathering

Answer:

weathering

Explanation:

Which statement correctly describes the relationship between thermal energy and particle movement?(1 point)

As thermal energy increases, there is more particle movement.
As thermal energy increases, there is more particle movement.

As thermal energy increases, there is less particle movement.
As thermal energy increases, there is less particle movement.

As thermal energy increases, particle movement does not change.
As thermal energy increases, particle movement does not change.

As thermal energy increases, it is not possible to predict particle movement.
As thermal energy increases, it is not possible to predict particle movement.

Answers

Answer:

As thermal energy increases,there is more particle movement

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