A coal barge with a mass of 2.36 × 10^4 kg drifts along a river. When it passes under a coal hopper, it is loaded with 9.4 × 10^3 kg of coal. What is the speed of the unloaded barge if the barge after loading has a speed of 2.7 m/s?
Answers
Known :
m = 2.36 × 10⁴ kg
M = 9.4 × 10³ kg
V = 2.7 m/s
Solution :
Using the principle of momentum
m • v = (m + M) • V
(2.36 × 10⁴) • v = (2.36 × 10⁴ + 9.4 × 10³)(2.7)
v = 3.77 m/s
Related Questions
if we cannot see the ocean floor from an airplane, we cannot see it from space either. so, how does a satellite measure the depth of ocean water to determine the topography of the ocean floor?
Answers
Although the ocean floor cannot be seen from an airplane, it can be viewed from space by a satellite. The satellite can determine the topography of the ocean floor by measuring the depth of ocean water. Bathymetry is the science of measuring water depth in oceans and other bodies of water.
Bathymetry is the study of underwater depth, shape, and topography of the ocean floor. With the help of satellite altimetry, bathymetry data is collected to construct maps of ocean topography. Sea surface height measurements can be made by a satellite altimeter. The accurate measurements of the sea surface height are taken relative to a reference surface like a geoid. The ocean’s topography can be determined by combining the precise measurements of sea surface height with satellite radar altimeter information.
The radar altimeter sends out short radio pulses which bounce off the ocean surface and return to the satellite. The length of time it takes for the pulse to return to the satellite is measured and converted into a distance. This gives us a precise measurement of the sea surface height above the geoid. By subtracting the measured sea surface height from the geoid, we can obtain the ocean’s topography.
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A spherical shell has inner radius Rin and outer radius Rout. The shell contains total charge Q, uniformly distributed. The interior of the shell is empty of charge and matter.
Part A
Find the electric field strength outside the shell, r≥Rout.
Express your answer in terms of some or all of the variables r, Rin, Rout, Q, ϵ0, and the constant of π.
Part B
Find the electric field strength in the interior of the shell, r≤Rin.
Express your answer in terms of some or all of the variables r, Rin, Rout, Q, ϵ0, and the constant of π.
Part C
Find the electric field strength within the shell, Rin≤r≤Rout.
Express your answer in terms of some or all of the variables r, Rin, Rout, Q, ϵ0, and the constant of π.
Answers
Part A: Thus, the electric field strength outside the shell is given by:
E = kQ/r² (for r≥Rout)
The electric field strength outside the shell, r≥Rout, can be found using Coulomb's law. The charge Q is uniformly distributed over the surface area of the sphere, which is 4πRout². Therefore, the charge density σ = Q/4πRout². The electric field strength at a distance r from the center of the sphere is given by E = kQ/r², where k = 1/4πϵ0. Since the electric field is radially outward, we can write E = kQ/r² for r≥Rout.
Thus, the electric field strength outside the shell is given by:
E = kQ/r² (for r≥Rout)
Part B:
The electric field strength inside the shell, r≤Rin, is zero because the interior of the shell is empty of charge and matter. Hence, E = 0 for r≤Rin.
Part C:
The electric field strength within the shell, Rin≤r≤Rout, can be found by using Gauss's law. The electric field inside the shell is spherically symmetric, and its magnitude depends only on the distance from the center of the sphere. Therefore, we can consider a Gaussian surface in the form of a sphere of radius r, centered at the center of the spherical shell. The total charge enclosed by this Gaussian surface is zero because the interior of the shell is empty of charge and matter. Hence, by Gauss's law, the electric flux through this surface is zero.
The electric flux through the Gaussian surface is given by Φ = E*4πr², where E is the electric field strength at a distance r from the center of the shell. Since the electric flux is zero, we can write:
Φ = E*4πr² = 0
Therefore, E = 0 for Rin≤r≤Rout.
In summary:
- The electric field strength outside the shell, r≥Rout, is E = kQ/r².
- The electric field strength inside the shell, r≤Rin, is zero (E=0).
- The electric field strength within the shell, Rin≤r≤Rout, is zero (E=0).
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How many watts is 1 amp?
Answers
Answer: 1 amp is equal to 120 watts at 120v voltage.
Explanation:
In a head-on car crash, the passenger flies forward into the seat belt, steering wheel, or windshield.
This is an example of what principle of motion?
Answers
A nuclear power plant produces an average of 3200 MW of power during a year of operation. Find the corresponding change in mass of reactor fuel over the entire year.
Answers
Over the entire year of operation, the corresponding change in mass of reactor fuel would be approximately 7.6 tons.
A nuclear power plant operates by generating heat through nuclear reactions, which is then used to produce electricity. In this case, the power plant produces an average of 3200 MW of power during a year of operation.
The corresponding change in mass of reactor fuel over the entire year can be calculated using the concept of mass-energy equivalence, as described by Einstein's famous equation E=mc². This equation relates the amount of energy released in a nuclear reaction to the mass of the reactants, by the factor of the speed of light squared.
To find the corresponding change in mass of reactor fuel, we can use the formula Δm = ΔE/c², where Δm is the change in mass, ΔE is the change in energy, and c is the speed of light. Assuming an efficiency of 33%, the reactor will consume about 9.7 million pounds of uranium fuel per year. This corresponds to a decrease in mass of approximately 0.24 grams per second, or 7.6 tons over the course of a year.
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Jared lifts a 35.0 kg of box from the floor to a table that is 1.75 meters above the floor. How much gravitational potential energy does the box gain?
Answers
Given,
The mass of the box, m=35.0 kg
The height to which the box was lifted, h=1.75 m
Potential energy is the energy possessed by an object due to its position.
The gravitational potential energy gained by the box is,
\(E=\text{mgh}\)Where g is the acceleration due to gravity.
On substituting the known values,
\(\begin{gathered} E=35.0\times9.8\times1.75 \\ =600.25\text{ J} \end{gathered}\)Thus the gravitational potential energy gained by the box is 600.25 J
help me pleaseeeeeeddd
Answers
Answer:
Explanation:
a )
According to graph the object moves with constant velocity of 10 m /s during first 8 s and then its velocity changes to - 5 m /s from 8 th second upto 12 th second .
Initial displacement = 8 m
displacement during 8 s = velocity x time
= 8 x 10 = 80 m
total displacement = 88 m
b )
displacement during period from 8 th to 12 th s
= - 5 x 4 = - 20 m
total displacement after 12 s
= 88 - 20 = 68 m
c ) average speed = total distance covered during 12 s / total time
= (80 + 20) / 12
= 8.33 m /s
average velocity = total displacement during 12 s / total time
= 80 - 20 / 12
= 60 / 12
= 5 m /s .
An object is moving with constant speed in a circular path. The object's centripetal acceleration remains constant in.
Answers
For an object moving in circular path with constant speed is having an acceleration which remains constant in magnitude.
What is acceleration?Acceleration of an object is its rate of change in velocity. Both are vector quantities thus, having a magnitude and direction. The change in acceleration can be either due to the change in magnitude of velocity or due to its direction.
Centripetal acceleration is the acceleration associated with an object moving through a circular path. If the object is moving in constant speed but there may occur a change in direction but make the object having an acceleration.
The acceleration of the body moving with the constant speed is constant in magnitude but changes in direction.
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Given that the electric field for a long line of charge with charge density λ=2.5μC/m is E= 2πε 0
r
λ
, pointing radially outward from the line of charge, showing your work, a) determine the electric potential as a function of the distance, r from the line of charge, assuming the potential V(r=10 m)=1000 volts at a distance of 10 meters from the line. b) What is the electric potential at a distance of r=2 meters from the line?
Answers
The electric potential, V, as a function of the distance, r, from the line of charge is given by V = 2πε₀λ ln(r/r₀), where r₀ is a reference distance. To determine the specific equation, we need to solve for r₀ using the given information that V(r=10 m) = 1000 volts at a distance of 10 meters from the line.
To find the electric potential at a distance of r = 2 meters from the line, we can substitute the obtained value of r₀ into the equation V = 2πε₀λ ln(r/r₀) and evaluate it.
How is the electric potential equation derived, and how do we determine the value of r₀?
To derive the electric potential equation, we start with the expression for the electric field (E) in terms of the charge density (λ) and radial distance (r). Then we integrate E with respect to r to obtain the potential (V). By applying the appropriate constant of integration and using the given condition, we can determine the value of r₀.To find the electric potential at r = 2 meters, we substitute the known values (such as λ and r₀) into the derived equation for V and perform the calculation.
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What wavelength photon would have the same energy as a 145-gram baseball moving 30.2 m/s ?
Answers
Answer:
Approximately \(3.01 \times 10^{-27}\; {\rm m}\) (when measured in a vacuum.)
Explanation:
Apply unit conversion and ensure that the mass of the baseball is in standard units (kilograms):
\(m = 145\; {\rm g} = 0.145\; {\rm kg}\).
The kinetic energy of the baseball will be:
\(\displaystyle E = \frac{1}{2}\, m\, v^{2}\),
Where \(v = 30.2\; {\rm m\cdot s^{-1}}\) is the speed of the baseball.
\(\begin{aligned}E &= \frac{1}{2}\, m\, v^{2} \\ &= \frac{1}{2}\, (0.145)\, (30.2)^{2}\; {\rm J} \\ &= 66.12290\; {\rm J}\end{aligned}\).
The energy of a photon of frequency \(f\) is:
\(E = h\, f\),
Where \(h \approx 6.62607 \times 10^{-34}\; {\rm m^{2}\cdot kg \cdot s^{-1}}\) is Planck's constant.
When measured in a vacuum where speed of light is \(c \approx 3.00 \times 10^{8}\; {\rm m\cdot s^{-1}}\), the wavelength \(\lambda\) of this photon will be:
\(\displaystyle \lambda = \frac{c}{f}\).
\(\displaystyle f = \frac{c}{\lambda}\).
Hence, the expression for the energy of this photon can be rewritten as:
\(\displaystyle E = h\, f = \frac{h\, c}{\lambda}\).
Rearrange this equation to find \(\lambda\):
\(\displaystyle \lambda &= \frac{h\, c}{E}\).
Assuming that the energy of this photon to be equal to the kinetic energy of that baseball, \(66.12290\; {\rm J}\):
\(\begin{aligned}\lambda &= \frac{h\, c}{E} \\ &\approx \frac{(6.62607\times 10^{-34})\, (3.00 \times 10^{8})}{(66.12290)}\; {\rm m} \\ &\approx 3.01 \times 10^{-27}\; {\rm m}\end{aligned}\).
seawater velocity = 1478 m/s water depth = 509 m sandstone velocity = 2793 m/s thickness=1003 m mudstone velocity= 2240 m/s thickness = 373 m Air Gun Energy Source Note: Illustration is not to scale. Hydrophone Receivers seafloor sand/mud 2. In the marine seismic acquisition example shown, you are interested in two events observed in the seismic trace that is recorded at the first hydrophone. One is a first-order multiple (double bounce) off the seafloor. The other is a primary reflection from the sand/mud interface for which the energy ray-path has a takeoff angle of 9 degrees from vertical as shown. Assume horizontal rock layers and isotropic velocities. Which of the two events arrives at the hydrophone first-the primary or the multiple? Clearly show your calculations and include a simple drawing of the two- event seismic trace. 3. How long does it take for energy to travel directly from the air gun to the first hydrophone (no bounces)? 4. What is the maximum takeoff angle at which seismic energy can reflect from the sand/mud interface? Explain what happens to the energy for larger angles. 5. Explain the relative direction of travel for energy that is transmitted into the mudstone.
Answers
2. The primary reflection from the sand/mud interface will arrive first at the hydrophone. To determine which event arrives first, we need to calculate the two-way travel times (TWTT) for each event. The TWTT for the primary reflection from the sand/mud interface is:
TWTT = (2 × depth × sin (angle of incidence)) / velocity
TWTT = (2 × 509 × sin (9)) / 1478TWTT = 0.317 s
The TWTT for the double bounce off the seafloor is:TWTT = (2 × depth) / velocityTWTT = (2 × 509) / 1478TWTT = 0.689 s
Therefore, the primary reflection arrives first at the hydrophone. Here is a simple drawing of the two-event seismic trace:
3. To calculate the time it takes for energy to travel directly from the air gun to the first hydrophone, we need to determine the distance between them and divide it by the velocity of sound in seawater. Using the given values, we have:
Distance = depth + (thickness of sand/mud) + (thickness of mudstone)
Distance = 509 + 1003 + 373
Distance = 1885 m
Velocity of sound in seawater = 1478 m/s
Time = Distance / VelocityTime = 1885 / 1478Time = 1.276 s
Therefore, it takes 1.276 seconds for energy to travel directly from the air gun to the first hydrophone.
4. The maximum takeoff angle at which seismic energy can reflect from the sand/mud interface is called the critical angle. This angle can be calculated using Snell's law:
n1 × sin (angle of incidence) = n2 × sin (angle of refraction)
where n1 and n2 are the velocities of the two materials and the angle of refraction is 90 degrees (since seismic energy travels along a horizontal path once it reaches the interface).
For the sand/mud interface, the critical angle is:
n1 × sin (critical angle) = n2 × sin (90)n1 / n2 = cos (critical angle)critical angle = cos^-1 (n1 / n2)
Using the given values:
n1 = 2793 m/s (sandstone velocity)n2 = 2240 m/s (mudstone velocity)critical angle = cos^-1 (2793 / 2240)
critical angle = 35.9 degrees
Seismic energy cannot reflect from the sand/mud interface at angles greater than the critical angle. For larger angles, the energy will be transmitted into the mudstone.
5. When seismic energy is transmitted into the mudstone, it travels in all directions away from the source. However, the energy will be attenuated (reduced in amplitude) as it travels through the mudstone due to its relatively low velocity compared to the sandstone and seawater.
As a result, the mudstone acts as a barrier that blocks or reduces the energy that would otherwise be transmitted deeper into the subsurface.
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A car has a maximum acceleration of 3.0 m/s2. what would its maximum acceleration be while towing a second car twice its mass?
Answers
A car has a maximum acceleration of 3.0 m/s2. Its maximum acceleration, while towing a second car which is twice its mass is 0.11\(ms^{2}\)
According to Newton's second law of motion,
F = ma, i.e Force on a body is equal to the product of the mass of the body multiple by its acceleration
Let us assume the mass of the car be "m"
Force applied by the engine of the car = \(\frac{m}{3}\)
Now, as the car is towing another car, twice its mass which means that the total mass the engine has to pull is m+2m = 3m
As the force applied by the engine is Equal to \(\frac{m}{3}\)
=> F = ma
=> Acceleration = \(\frac{Force}{Total mass}\)
=> Acceleration = \(\frac{\frac{m}{3} }{3m}\) = \(\frac{1}{9} ms^{2}\)
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The efficiency of a petrol car engine is 40%. The speed of the car is 9.0 m s−1 when the power developed by the
engine is 20 kW. Calculate how many kilometres the car can go with one litre of petrol when driven at this speed.
Answers
The car will travel 6.12 km one litre of petrol when driven at this speed
Given the energy provided by one liter of gasoline e = 34 * 10⁶ Joules
efficiency of the car = 40%
The speed of the car is 9.0 ms⁻¹
Power of the car = P = 20 kW
The useful energy produced by the car is equal to
= P * e
Therefore the useful energy is
= 34 * 10⁶ * 40/100
= 1.36 * 10⁷ Joules
Now, we can say that car consumes 20 ± 10³ J/s to travel at the speed of 9 m/s
The time for which the car will keep moving at this speed using the energy provided by 1 liter of fuel is
\(t=\frac{1.36*10^{7} }{20*10^{3} }\) = 680 sec
The distance travelled by car during this time is
d = 9 * 680
d= 6.12 km
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Please help! Will give brainliest!
A cyclist changes its speed going down hill from 22 m/s to 37 m/s in 2 seconds. Calculate the acceleration of the cyclist.
Answers
Answer:
7 1/2m/s/s
Explanation:
37-22=15
15/2=7 1/2
Which scientist suggested that the earth was at the center of the solar system?.
Answers
The scientist who suggested that the earth was at the center of the solar system is Ptolemy. His theory is known as the Ptolemaic system.
The Ptolemaic system was a geocentric model of the universe that was developed by the ancient Greek astronomer Ptolemy. According to this theory, the Earth is at the center of the universe, and the Sun, Moon, planets, and stars all revolve around it. Ptolemy's model was widely accepted and was considered to be the most accurate description of the universe until the Copernican system was proposed in the 16th century.
The Copernican system was a heliocentric model of the universe that suggested that the Sun was at the center of the universe, and the Earth and other planets revolved around it. Despite being proven incorrect, Ptolemy's theory had a significant impact on the history of science and astronomy. It laid the groundwork for future observations and discoveries, and it paved the way for the development of more accurate models of the universe.
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What does Newton's first law of motion imply about an object in motion?A. It will tend to slow down until it comes to rest.B. It will tend to remain at a constant velocity unless acted upon by aforce.C. It will tend to exert a friction force on the air around it.D. It will tend to accelerate until it reaches the speed of light unlessacted upon by a force.
Answers
Newton's first law of motion:
Newton's first law of motion states that a body in motion tends to remain in motion at a constant velocity unless acted on by a net external force.
Hence, the correct option is (B)
Integrated Concepts:_______.
(a) Calculate the ratio of the highest to lowest frequencies of electromagnetic waves the eye can see, given the wavelength range of visible light is from 380 to 760 nm.
(b) Compare this with the ratio of highest (20,000 Hz) to lowest (20 Hz) frequencies the ear can hear.
Answers
a). frequency = (speed) / (wavelength)
The speed of light is around 3 x 10⁸ m/s.
For 380 nm (violet light), frequency = (3 x 10⁸ m/s) / (380 x 10⁻⁹ m)
Frequency = 7.89 x 10¹⁴ Hz
For 760 nm (red light), frequency = (3 x 10⁸ m/s) / (760 x 10⁻⁹/s)
Frequency = 3.94 x 10¹⁴ Hz
The ratio is 2 .
That's 1 octave, or 0.3 of a decade.
b). The ratio of highest/lowest sounds is (20,000 Hz/20 Hz) = 1,000
That's 3 decades, or about 10 octaves.
===> Speaking logarithmically ( ! ), ears are sensitive to a range of sound frequencies that's 10 times as wide as the range of light frequencies that eyes can detect.
Ideas for uniform circular motion?This is for a physics lab if u can help please do
Answers
The time of motion of the satellite is 1.65 hours. The speed of the satellite from the centre of the Earth is 26,945.35 km/h.
What is the time of motion of the satellite?This is the motion of an object in which the object travels in a straight line and its velocity remains constant along that line as it covers equal distances in equal intervals of time, regardless of time duration.
The time of motion of the satellite in hours is calculated as follows;
t = ( 99 min / 1 ) x ( 1 hour / 60 min )
t = 1.65 hours
The speed of the satellite from the centre of the Earth in km/h is calculated as follows;
v = ( 2πr ) / ( t )
where;
r is the distance of the satellite from the centre of the Earth
The position of the satellite above the surface of the Earth = 705 km
The radius of Earth = 6,371 km
The total distance of the satellite from the centre of the Earth = 705 km + 6,371 km = 7,076 km
v = ( 2π x 7076 ) / ( 1.65 )
v = 26,945.35 km/h
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The complete question is attached with the answer below.
if we wwere at the center of the milky way galaxy, and the globular clusters were distributed randomly throughout our milky way, what would the distribution of globular clusters look like on your star map?
Answers
The distribution of globular clusters in the Milky Way would appear as a roughly spherical distribution of stars, with clusters densely concentrated towards the center of the galaxy and becoming more sparsely spread out towards the outer reaches.
This is due to the fact that the Milky Way is a barred spiral galaxy, so the globular clusters are most likely to be located along the spiral arms and in the central bulge due to their high gravitational potential. Additionally, the number of globular clusters would drop off as the distance from the core of the Milky Way increases, as the amount of interstellar gas and dust available for star formation decreases.
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escribe the differences between the terrestrial and jovian planets and classify each of the 8 planets to the proper type
Answers
Answer:
*******
Explanation:
is obviously the correct answer they are both so different yet so alike
wrong question someone just comment the right answer ;-;
Conversion of electromagnetic (EM) energy from the sun into other forms of energy occurs for (select all that apply) a. Biofuels (EM to chemical bonds during photosynthesis)
b. Hydroelectric power (EM to evaporation and precipitation of water)
c. Solar thermal power (EM to motion of exchange fluid)
d. Photovoltaic power (EM to electricity, the movement of particles)
e. Wind power (EM to air movements)
Answers
Conversion of electromagnetic (EM) energy from the sun into other forms of energy occurs for the following options:
a. Biofuels
c. Solar thermal power
e. Wind power (EM to air movements)
A- Biofuels: During photosynthesis, plants capture electromagnetic energy from the sun and convert it into chemical energy, stored in the bonds of organic molecules, such as glucose. This process allows for the conversion of EM energy to chemical energy in the form of biofuels.
c. Solar thermal power: Solar thermal power plants use mirrors or lenses to concentrate sunlight, which is then converted into heat energy. This thermal energy can be used to generate steam, which drives a turbine and produces mechanical energy.
e. Wind power: Wind turbines harness the kinetic energy of moving air, which is ultimately driven by the sun's uneven heating of the Earth's surface. The sun's energy heats the atmosphere, creating temperature and pressure gradients that result in wind currents.
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A 2.50 × 105 w motor is used for 26.4 s to pull a boat straight toward shore. how far does the boat move toward shore if a force of 4.20 × 104 n is applied by the motor? 157 m 1,590 m 1.11 × 106 m 6.60 × 106 m
Answers
The distance travelled by the boat towards shore if a force of 4.20x10⁴N is applied is 157.14 m.
Power is a unit of measurement for the amount of work completed in a particular period of time; it may be computed using both work and time. Divide the amount of work by the length of time it takes to do the work to find power. The unit of work is the joule. The unit of power measurement is known as joules of work per second.
The power of the motor = 2.50x10⁵ W
= 2.50x10⁵ N m/s
The time it takes to pull the boat = 26.4 s
The force applied = 4.20x10⁴ N
Using the formula;
\(d = \frac{Pt}{F}\)
where,
P = Power
t = Time taken
F = Force applied
d = Distance travelled
The distance traveled by the boat = 2.50x10⁵ N m /s (26.4 s) /(4.20x10⁴ N)
=157.14 m
Therefore, the distance travelled by the boat if a force of 4.20x10⁴N is applied is 157.14 m.
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A Balloon is filled with water inside, when it is hanged over a burning fire the balloon filled with water doesn't brust why??
Answers
Answer:
The water filled balloon does not burst because the rubber obviously does not reach a temperature sufficient for it to melt or burn. The rubber is stretched thin so that heat is quickly transferred into the balloon. With air inside the balloon, this heat is not readily dissipated away from the spot touching the flame.
The mass is 2.0 kg. If the net force is 20.0 N, what is the acceleration?
Answers
Answer:
The answer is 10 m/s²Explanation:
The acceleration of an object given it's mass and the force acting on it can be found by using the formula
\(a = \frac{f}{m} \\ \)
where
f is the force
m is the mass
We have
\(a = \frac{20}{2} \\ \)
We have the final answer as
10 m/s²Hope this helps you
Answer: BUTT
Explanation: Because its a Cheek;)
63. The magnetic force acting on a moving charge is given by the product of three quantities,
namely
చలనంలో ఉన్న ఆవేశంపై పనిచేయు అయస్కాంత బలం మూడు రాశుల లబ్దానికి సమానం అని
(1) charge, speed, electromotive force
ఆవేశం, వడి, విద్యుతచ్చాలక బలం
archarge, magnetic flux, magnetic flux density
ఆవేశం, అయస్కాంత అభివాహం, అయస్కాంత అభివాహ సాంద్రత
(3) charge, speed, magnetic flux density
ఆవేశం, వడి, అయస్కాంత అభివాహ సాంద్రత
(4) charge, speed, current
ఆవేశం, వడి, విద్యుత్ ప్రవాహం
Answers
Answer:
the correct one is 3
Explanation:
The magnetic force is described by the expression
F = q v x B
The bold indicate vectors, q is the charge, v the velocity and B the magnetic induction
This expression can be written in scalar form
F = q v B sin θ
where θ is the angle between velocity and induction.
The direction of the force is perpendicular to the vectors.
When revising this expression the force depends on the electric charge, the speed of the particle and the induction of the magnetic field
therefore, checking the possible answers, the correct one is 3
It was once recorded that a Jaguar left skid marks that were 290 m in length. Assuming that the Jaguar had a constant acceleration of -3.9 m/s/s, determine the speed of the Jaguar before it began to skid to a stop.
Answers
Answer: 47.6 m/s
Explanation: Please see attached for the calculation and formula.
Titanium reacts less with oxygen than most metals do. This is a___.
Answers
Explanation:
this is a physical property
This is a "chemical property" in that Titanium interacts with oxygen less than most metals.
What is the chemical property?A chemical property is a characteristic of a substance that can only be observed or measured by changing the identity of the substance through a chemical reaction.
In this case, the fact that titanium reacts less with oxygen than most metals is a chemical property because it describes how titanium behaves in the presence of oxygen, and it is a result of the chemical properties of titanium's atomic structure and the bonds it forms with oxygen atoms.
In contrast, physical property is a characteristic of a substance that can be observed or measured without changing its identity.
Titanium reacts less with oxygen than most metals do. This is a "chemical property".
Thus, the correct answer would be option (B) chemical property.
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A plane has a take off speed of 1 point
300 km/h. What is the
acceleration in m/s2 of the
plane if the plane started from
rest and took 45 seconds to
take off? *
Answers
Answer:
Acceleration = 1.85m/s²
Explanation:
Given the following data;
Final velocity = 300km/h to m/s = 300*1000/3600 = 83.33m/s
Time = 45 seconds
Since the plane started from rest, initial velocity is equal to 0m/s.
To find the acceleration;
In physics, acceleration can be defined as the rate of change of the velocity of an object with respect to time.
This simply means that, acceleration is given by the subtraction of initial velocity from the final velocity all over time.
Mathematically, acceleration is given by the equation;
\(Acceleration (a) = \frac{final \; velocity - initial \; velocity}{time}\)
Where,
a is acceleration measured in \(ms^{-2}\)
v and u is final and initial velocity respectively, measured in \(ms^{-1}\)
t is time measured in seconds.
Substituting into the equation, we have;
Acceleration = (83.33 - 0)/45
Acceleration = 83.33/45
Acceleration = 1.85m/s²
Therefore, the acceleration of the plane is 1.85m/s².
A photovoltaic cell produces electricity when the sun shines. What energy conversion is going here?
Answers
Answer:
light potential energy is converted into electrical potential energy.
Explanation:
A solar heat absorbs the light that creates pairs of electron - holes, these free charges when moving create a current, the light energy stored in the radiation is converted into electrical energy within the n-p junctions.
In summary, light potential energy is converted into electrical potential energy.
Pressure exerted by liquid at the bottom of the container depends on the _______ of its column.
Answers
The pressure exerted by a liquid at the bottom of a container depends on the height of its column.
The pressure exerted by a liquid is directly proportional to the height of the column of the liquid. This relationship is known as Pascal's law, which states that pressure applied to a fluid is transmitted uniformly in all directions.
When a liquid is in a container, the weight of the liquid column above exerts a force on the bottom of the container. This force is spread evenly across the entire bottom surface, resulting in a pressure.
The pressure exerted by a liquid can be calculated using the equation P = ρgh, where P is the pressure, ρ is the density of the liquid, g is the acceleration due to gravity, and h is the height of the liquid column.
As the height of the liquid column increases, the weight of the liquid above increases, resulting in a higher pressure at the bottom of the container. Conversely, if the height of the liquid column decreases, the pressure exerted at the bottom of the container will be lower.
Therefore, the pressure exerted by a liquid at the bottom of a container depends on the height of its column, following the principles of Pascal's law.
Learn more about Pascal's law here:
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