A circular rod of cross-sectional area 100 mm2 has a tensile force of 100 kN applied to it. The stress in the rod is:

The gas's internal energy that expands from I to F changes by 1015 J.

Since the gas is expanding and energy is added to it by heat, the change in internal energy of the gas can be calculated using the first law of thermodynamics, which states that:

ΔU = Q - W

where ΔU = change in internal energy,

Q = heat added to the system, 465 J and

W = work done by the system.

Assuming that the process is quasi-static use approximation known as the "staircase approximation."

By adding up the work done in each step, find that the total work done by the gas is approximately -550 J. The negative sign indicates that work is done on the gas.

Therefore, using the first law of thermodynamics, we can calculate the change in internal energy of the gas as:

ΔU = Q - W

ΔU = 465 J - (-550 J)

ΔU = 1015 J

Therefore, the change in internal energy of the gas is 1015 J.

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If the engine of a boat on a river is turned off while the boat is moving with a steady speed, several things would happen Loss of propulsion,Drifting,Loss of steering control and Potential hazards.

Loss of propulsion: Without the engine running, the boat would lose its power source for propulsion. The boat would gradually slow down and eventually come to a stop unless other external forces, such as currents or wind, continue to move it.

Drifting: Once the boat comes to a stop, it would start to drift with the current of the river or be affected by wind forces. The direction and speed of the drift would depend on the strength and direction of the current or wind.

Loss of steering control: When the engine is turned off, the boat's steering mechanism, such as a rudder, would also lose power. Without the ability to steer, the boat would follow the course determined by the river's current or the wind direction.

Potential hazards: Depending on the surroundings and the current conditions, there could be potential hazards for a boat that is no longer under power. These hazards might include other vessels, obstacles, shallow areas, or strong currents. The boat's crew would need to take appropriate actions to ensure the safety of the boat and its occupants.

It's important to note that the specific behavior of the boat after the engine is turned off can vary depending on factors such as the size and design of the boat, the strength and direction of the current, and the presence of wind or other external forces.
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Answer:

This is what gives the Ionosphere its name and it is the free electrons that cause the reflection and absorption of radio waves. ... The high frequency waves pass through the ionosphere and escape into space while the low frequency waves reflect off the ionosphere and essentially "skip" around the earth.

Explanation:

The near point of a human eye is about a distance of 25 cm.

The closest distance that an object may be viewed clearly without straining is known as the near point of the eye.

This distance (the shortest at which a distinct image may be seen) is 25 cm for a typical human eye.

The closest point within the accommodation range of the eye at which an object may be positioned while still forming a focused picture on the retina is also referred to as the near point.

In order to focus on an item at the average near point distance, a person with hyperopia must have a near point that is further away than the typical near point for someone of their age.

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Answer:The formula distance = (initial velocity * time) + (1/2 * acceleration * time^2) would help. Take the initial velocity as 0 m/s , time as 60 seconds ( convert minutes to SI units) and the acceleration as 1m/s^2. You should get 1.8 km.

Explanation:hope this helps

PV=nRT

Here

P=Pressure

V=Volume

n=Molarity

R=universal gas constant

T=Temperature.

LHS

\(\\ \tt\bull\leadsto PV\)

\(\\ \tt\bull\leadsto [ML^2T^{-2}][M^0L^3T^0]\)

\(\\ \tt\bull\leadsto [ML^5T^{-2}]\)

RHS

\(\\ \tt\bull\leadsto nRT\)

\(\\ \tt\bull\leadsto [M^0L^{3}T^0][M^1 L^2 T^{-2}K^{-1}][M^0L^0T^0K^1]\)

\(\\ \tt\bull\leadsto [ML^5T^{-2}]\)

LHS=RHS

hence verified

Answer:

b

Explanation:

when a ball falls from the sky, it falls down fast due to no friction.

9. The new tension in the string (T') is 8 times the initial tension (T).

10. The angular acceleration of the automobile when its instantaneous speed is 4 m/s is -0.77 rad/s².

9. Initially, the tension in the string (T) provides the necessary centripetal force, so we have:

T = m * ω₁² * r

After doubling the length and angular velocity, the new tension in the string (T') should provide the centripetal force, so we have:

T' = m * ω₂² * (2r)

Since the length and angular velocity are doubled, we can write:

ω₂ = 2 * ω₁

Substituting this into the equation for T', we get:

T' = m * (2 * ω₁)² * (2r)

= 4 * m * ω₁² * (2r)

= 8 * (m * ω₁² * r)

= 8 * T

Therefore, the new tension in the string (T') is 8 times the initial tension (T).

10. The linear acceleration of an object moving in a circle of radius r with an angular velocity ω can be found using the formula:

a = ω² * r

Differentiating this equation with respect to time gives:

dv/dt = d(ωr)/dt

= ω * dr/dt + r * dω/dt

= ω * v + r * α

Given that the speed of the automobile is increasing at a rate of 0.6 m/s², we can substitute the values into the equation:

0.6 = ω * 4 + 20 * α

Since the instantaneous speed is 4 m/s, we can set ω = 4, and solve for α:

0.6 = 4 * 4 + 20 * α

0.6 = 16 + 20 * α

0.6 - 16 = 20 * α

-15.4 = 20 * α

α = -15.4 / 20

α = -0.77 rad/s²

Therefore, the angular acceleration of the automobile when its instantaneous speed is 4 m/s is -0.77 rad/s².

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When an object lies on the ground, the ground applies a force which is perpendicular (or normal) to the surface of the ground and points away from it. Such force is called the Normal Force, and it balances the gravitational pull so the object does not sink infinitely towards the floor.

Therefore, the force that's shown in the diagram pointing up is the normal force. The answer is:

Answer:

Because as we climb higher the amount of oxygen in the air decreases and this makes the air thinner and dryer. And at higher altitudes the blood pressure inside of our body is more than the atmospheric pressure which forces the blood to come out from openings like the nose.

Explanation:

Answer:

Theres no given?

Explanation:

Well, whatever.

I observed the shift of their sunset time.

Examples like:

January to June = their sunset time increased while

July to December = their sunset time decreased

Acceleration is defined as the change in velocity per unit time. Its unit is m/s².

Distance is the amount of space, or the actual length of the path travelled.

Displacement is the difference between the initial and final positions of the object.

Speed is the rate at which an object covers a certain distance.

Velocity is defined as the speed with a direction.

An object is said to have a positive velocity, if it is moving in the positive direction. And an object moving in negative direction has a negative velocity.

Acceleration is the change in velocity per unit time.

For freely falling objects, gravity is the only thing acting on the object.

The acceleration due to gravity on the earth is 9.8 m/s².

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Answer:

A.) 17.04 N

B.) 10.76 m/s^2

Explanation:

Given that a 2kg block is acted on by two forces F1 and F2 as shown in the diagram. If the magnitude of F1 = 13N and F2 = 11N. If the coefficient of kinetic friction is .23,

A.) To find the normal force exerted on it by the floor, we need to first calculate the vertical forces of the ropes.

The vertical force on F1 = 13 sin 30

F1 = -6.5 N

The vertical force on F2 = 11 sin 21

F2 = 3.94

The resultant force = - 6.5 + 3.94

Resultant force = - 2.56

The normal force = mg - 2.56

The normal force = 2 × 9.8 - 2.56

The normal force = 19.6 - 2.56

The normal force = 17.04 N

(B) The acceleration on of the block will be achieved by first calculating the horizontal force.

For F1 = 13Cos 30

F1 = 11.26N

For F2 = 11 cos 21

F2 = 10.27

the resultant force = 11.26 + 10.27

Horizontal force = 21.53N

Force = mass × acceleration

21.53 = 2 × a

a = 21.53 / 2

Acceleration a = 10.76 m/s^2

Answer:

50km/h

Explanation:

average = (a + b) / 2

average = (60 + 40) / 2

average = 50

The electric field at x = 15 cm is approximately 671 N/C, which is closest to option (D) 670 N/C.

An electric dipole is a pair of equal and opposite charges separated by a distance. It is a simple but important concept in electromagnetism and is used to describe a variety of phenomena, such as the interaction between charges and the behavior of molecules in an electric field.

To calculate the electric field at a point along the x-axis due to an electric dipole, we can use the formula:

E = (1/4πε₀) [(2p cosθ)/r³]

where:

ε₀ is the electric constant (8.85 × 10⁻¹² N⁻¹ m⁻² C²)

p is the magnitude of the electric dipole moment (p = qd)

q is the charge on each end of the dipole

d is the separation between the charges

r is the distance between the point and the center of the dipole

θ is the angle between the dipole moment and the line connecting the point to the center of the dipole

In this problem, we are given:

q = ±2.5 µC = ±2.5 × 10⁻⁶ C

d = 1.0 × 10⁻⁴ m

x = 15 cm = 0.15 m

We can calculate the dipole moment as:

p = qd = (2.5 × 10⁻⁶ C)(1.0 × 10⁻⁴ m) = 2.5 × 10⁻¹⁰ Cm

The distance between the point and the center of the dipole is:

r = √(x² + d²/4) = √[(0.15 m)² + (1.0 × 10⁻⁴ m)²/4] = 0.15000125 m

The angle between the dipole moment and the line connecting the point to the center of the dipole is:

θ = 0° (since the dipole is oriented along the x-axis)

Plugging in the values, we get:

E = (1/4πε₀) [(2p cosθ)/r³] = (1/4πε₀) [(2)(2.5 × 10⁻⁰ Cm)(1)/ (0.15000125 m)³] = 671.2 N/C

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The average velocity of the object from t = 1 sec. to t = 2 is 8 feet / sec.

calculate  the average velocity of the object from t = 1 sec. to t = 2?

Average velocity is change in position over change in time.

To calculate this, we can see where the object is at t = 1 and where the object is at t = 2.

At t = 1:

d(t = 1) = 2.667 * (1)2 = 2.667 ft

At t = 2:

d(t = 2) = 2.667 * (2)2 = 10.667 ft

Our change in position is 10.667 - 2.667 = 8 feet

Our change in time is 2 sec - 1 sec = 1 second

Our average velocity between t = 1 and t = 2 is then 8 feet / sec.

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Answer:

I believe the correct answer would be A :)

Explanation:

According to Dr. paul Narguizian professor of Biology and Science Education at California State University, laws are generalizations about phenomena while theories are explanations of phenomena. Correct option is A.

Laws: Laws are generalizations or descriptions of consistent patterns observed in nature. They describe how something behaves under certain conditions without providing an explanation for why it behaves that way. Laws are often expressed as mathematical equations. For example, Newton's Law of Universal Gravitation states the mathematical relationship between the masses of two objects and the force of gravity between them. It tells us how objects attract each other but doesn't explain why gravity works in that manner.

Theories: Theories, on the other hand, are explanations or models that attempt to provide a comprehensive understanding of why certain phenomena occur. They are based on a body of evidence, observations, and experiments. Theories go beyond just describing patterns; they aim to explain the underlying mechanisms and reasons for those patterns. Theories can evolve over time as new evidence is discovered, and they can encompass multiple related laws. For example, the Theory of Evolution by Natural Selection explains the mechanism by which species change over time and adapt to their environments. It's a complex framework that integrates various observations and concepts.

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The phrase that most accurately describes its apparent motion in our sky against the background stars is west then Prograde - moving slower then Retrograde then Prograde - moving faster and at last east.

The apparent motion of a planet or other object as seen from Earth against a background of stars, moving from west to east (looking or viewing to the south - apparent right to left) which is called Prograde motion.

Retrograde motion is defined as "the apparent motion of a planet or other object as seen from Earth against the background of stars, moving from east to west (looking/viewing to the south - apparent left to right) motion."

When a superior planet (Mars, Jupiter, Saturn, Uranus, etc.) orbits the Sun at a distance greater than that of the Earth and is passed by the latter, which is moving with a higher relative velocity, the 'Superior' planet's normal direct motion appears to stop and then temporarily turn retrograde, giving it the appearance of undergoing a loop or zigzag in the sky.

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Plasma lacks a precise form or volume, much like gas. It completes the empty space. Even though it is in the gaseous form, there is a difference because some of the particles are plasma-ionized.

High-energy particles are free to move around and fill the area they inhabit in the state of matter known as gas.

Neutral atoms or molecules often make up gaseous substances like air.

The ionised gas known as plasma, on the other hand, contains both positively and negatively charged particles.

It develops when a gas is subjected to an intense electric field or heated to incredibly high temperatures.

Plasma is a substance that may be found in stars, lightning, and fluorescent lights. It is also an essential component of many modern technology, like plasma TVs and fusion reactors.

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We will have the following:

We are given the following:

So, we will have to proceed as follows:

First, we calculate the momentum of the pin:

Now, we calculate the final momentum of the ball:

Now, we will have that the original momentum of the ball would be:

Now, we find it's initial speed:

So, the initial speed of the ball was of 867/175 m/s, that is approximately 4.95 m/s.

The time taken for the ball to reach its maximum height is 1 second.

To calculate the time taken for the ball to reach its maximum height, we can use the kinematic equation for vertical motion. The equation is:

v = u + at

Where:

v = final velocity

u = initial velocity

a = acceleration

t = time

In this case, the ball is thrown vertically upwards, so the initial velocity (u) is 10 m/s (considering upwards as positive) and the acceleration (a) is -10 m/s² (negative because it opposes the motion).

The final velocity (v) at the maximum height will be zero because the ball momentarily comes to a stop before reversing its direction. Therefore, we can rewrite the equation as:

0 = 10 - 10t

Simplifying the equation, we get:

10t = 10

Dividing both sides by 10, we find:

t = 1 second

Therefore, the time taken for the ball to reach its maximum height is 1 second.

During this time, the ball covers the distance required to reach the maximum height, overcoming the gravitational acceleration. After reaching the maximum height, it will start to descend towards the ground due to the gravitational pull.

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Answer:

speeding up is the answer

Explanation:

from the graph it can be seen that as the time (horizontal axis) increases the speed of vehicle (vertical axis) increases

Resistivity is the resistance between opposite faces of a unit cube.

The electrical resistance of a conductor with a unit cross-sectional area and unit length is called resistivity. Resistivity is a distinctive attribute of any material that may be used to compare different materials based on how well they conduct electric currents. Low conductivity is indicated by high resistance.

The Greek letter rho is frequently used to represent resistance, which is numerically equivalent to the resistance R of a wire-like specimen, multiplied by its cross-sectional area A, and divided by its length l; RA/l. The ohm is the measurement of resistance. Units of ohm-centimeter can be used to represent resistance when lengths are measured in centimeters. The temperature of the material also affects the value of resistivity.

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Answer:

true b

Explanation:

They ask us to evaluate if the expressions are true

a) False. The concept of polarization refers to the direction of the oscillating electric field in a traveling wave, in this case the shocks cause the wave to disperse

b) True .. Yes, since no work is done inside the conductor, so all the load is on the surface

c) False. In electrostatic equilibrium the voltage must be the same everywhere

d) False. If the charges are positive point out

              If the charges are negative point inwards

e) False. If the charge is positive, the pattern is outward

               if negative largares points gavia inside.

The particular, as well as measurable scientific investigation, would be the depth of the well.

The following however is the explanation behind the aforementioned question:

The things were recovered by Jack as well as Jill:

The knowledge that you can obtain is what you find:

The equation related to the depth of the well will be:

→ \(h = \frac{1}{2} gt^2\)

Thus the above approach is right.

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Answer:

A)  4.95 m

B)  1.48225 m

Explanation:

Constant Acceleration Equations (SUVAT)

\(\boxed{\begin{array}{c}\begin{aligned}v&=u+at\\\\s&=ut+\dfrac{1}{2}at^2\\\\ s&=\left(\dfrac{u+v}{2}\right)t\\\\v^2&=u^2+2as\\\\s&=vt-\dfrac{1}{2}at^2\end{aligned}\end{array}} \quad \boxed{\begin{minipage}{4.6 cm}$s$ = displacement in m\\\\$u$ = initial velocity in ms$^{-1}$\\\\$v$ = final velocity in ms$^{-1}$\\\\$a$ = acceleration in ms$^{-2}$\\\\$t$ = time in s (seconds)\end{minipage}}\)  

When using SUVAT, assume the object is modeled as a particle and that acceleration is constant.

Consider the horizontal and vertical motion of the projectile separately.

The horizontal component of velocity is constant, as there is no acceleration horizontally.

Resolving horizontally, taking → as positive:

\(u=9.00\quad v=9.00 \quad a=0\quad t=0.550\)

\(\begin{aligned}\textsf{Using} \quad s & = \left(\dfrac{u+v}{2}\right)t:\\\\s&= \left(\dfrac{9+9}{2}\right)(0.550)\\s&= (9)(0.550)\\ \implies s&= 4.95\:\sf m\\\end{aligned}\)

As the projectile is fired horizontally, the vertical component of its initial velocity is zero.

Acceleration due to gravity = 9.8 ms⁻²

Resolving vertically, taking ↓ as positive:

\(u=0\quad a=9.8\quad t=0.550\)

\(\begin{aligned}\textsf{Using} \quad s & = ut+\dfrac{1}{2}at^2:\\\\s&= (0)(0.550)+\dfrac{1}{2}(9.8)(0.550)^2\\s&= 0+(4.9)(0.3025)\\\implies s&= 1.48225\:\sf m\\\end{aligned}\)

Answer:

B

Explanation:

Let T be the orbit period and a be the radius of orbit.

For T^2= k× a^3 (k is a constant)

there seems to be an indirect relationship between two variables.

Answer:

D) A magnesium atom donates two electrons to the fluorine atoms → Each fluorine atom accepts one of the electrons → The magnesium atom becomes a +2 ion → Each fluorine atom becomes a -1 ion

Explanation:

sorry if its a bit late

The correct steps in the formation of an ionic bond are A magnesium atom donates two electrons to the fluorine atoms → Each fluorine atom accepts one of the electrons → The magnesium atom becomes a +2 ion. The correct option is D.

The electrical attraction between two ions with opposing charges creates an ionic bond, also known as an electrovalent bond, in a chemical molecule.

Ionic compounds are created by ionic bonds, while covalent bonds create covalent compounds. Ionic bonds are created by a complete transfer of electrons, whereas covalent bonds are created by sharing electrons.

Covalent bonds are weaker than ionic ones. Ionic compounds have higher melting and boiling points.

Therefore, the correct option is D.

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Answer:

a cold front i think

Explanation: