A circular loop of wire with a diameter of 21.475 cm is in the horizontal plane and carries a current of 3.917 A counterclockwise, as viewed from above. What is the magnetic field, in microTeslas, at the center of the loop?

1_The conventional current flows from the positive pole to the negative one. True

2_long thick hot wire has more resistance than short thin cold wire True

Current is a flow of charges. it is denoted by i and expressed in ampere A. Mathematically it is expressed as i = q/t, where q is the amount of charge and t is time. Current is nothing but amount of charges flown in the unit time in the electric wire. Charge is expressed in coulomb C and time in second s. hence coulomb per second (C/s) is ampere A. Charge on electron is 1.60217663 × 10⁻¹⁹ which is called as elementary charge.

There are two types of the current, Convectional current and non-conventional current. Convectional current is the current flows from positive to negative. Non convectional current flows from negative to positive. Note that flow of electrons is from negative to positive. Hence direction of flow of conventional current is from positive to negative. for low resistance, more current flows.

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Answer:

1 m/s^2

Explanation:

F=ma

2 Newtons=2 Kg * a

a=1 m/s^2

I DID A Science PROJECT ON THIS >:)))

basically light travels into the eye to the retina located on the back of the eye. the retina is covered withe millions of light sensitive cells called Rods and cones. when these cells detect light they send signals to the brain that help detect color.

the color of an object is determined by the wavelengths of light that it reflects. it's determined by the arrangement of electrons in the atoms of that substance that will absorb and re-emit photons of particular energies according to quantum laws.

To set an object in motion on a surface, it usually requires overcoming several factors. The primary requirement is to overcome the force of static friction between the object and the surface.

Static friction is the force that resists the motion of an object when it is at rest. The magnitude of static friction depends on the nature of the surfaces in contact and the normal force acting perpendicular to the surface. In order to overcome static friction and initiate motion, an external force must be applied to the object.

The minimum amount of force required to overcome static friction is known as the threshold force. This force must exceed the maximum static frictional force. Once the threshold force is applied, the object transitions from rest to motion, and the static friction changes to kinetic friction, which is typically lower than static friction.

The exact amount of force required to initiate motion varies depending on factors such as the weight of the object, the roughness of the surfaces, and any other external forces acting on the object. Smooth surfaces and lighter objects generally require less force to set them in motion compared to rough surfaces and heavier objects.

To overcome the force of static friction and set an object in motion, one can apply a force in the direction of desired motion, either by pushing, pulling, or applying a torque. Once the object is in motion, it continues to move with a constant velocity unless acted upon by external forces such as friction or gravity.

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Given,

The height from which the book was dropped, h=4.5 m

When the book is at the height h, at rest it possesses only the potential energy. As it falls, it loses its potential energy and gains kinetic energy. Just before the book hits the ground, the book loses all its potential energy and possesses only kinetic energy.

Thus the potential energy of the book when it was at the height h is equal to its kinetic energy just before it hits the ground.

That is,

Where v is the speed of the book just before it hits the ground and g is the acceleration due to gravity.

On substituting the known values,

Thus the speed of the book right before it hits the ground is 9.39 m/s.

Answer:

gravity

Explanation:

I don't know what the explanations would be

(1) The distance of the image formed by the lens is determined as 6 cm.

(2) The image formed is real.

The distance of the image formed by the lens is calculated by applying the following formula as follows;

1/f = 1/v + 1/u

where;

The distance of the image formed by the lens is calculated as;

1/v = 1/f - 1/u

1/v = 1/2 - 1/3

1/v = 1/6

v = 6 cm

Since the sign of the image of the image is positive, the image formed is real.

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Answer: transverse, ripples formed on the surface of water

Explanation:

It is transverse

Examples are ripples formed on the surface of water

Answer:

The one with the faster velocity is the one with a velocity of -10m/s

The weight of an object on Earth with a mass of 230 kg is 2256.3 newtons (n).

The weight of an object is the force acting on the object due to the acceleration of gravity. It is defined as the vertical force experienced by a mass as a result of gravitation.

Weight is obtained from the product of mass and acceleration due to gravity (g). The object gets accelerated due to gravity when the object is in free fall. The value of g is 9.8 m/s².

From the given,

mass of an object = 230 kg

weight of an objcet=?

weight (w) = m×a, where m is the mass of the object and the unit of mass is the kilogram, a is the acceleration due to gravity and its unit is m/s², and w is the weight of the object and the unit of weight is Newton.

w = m×a

  = 230×9.81

  = 2256.3 N

w = 2256.3 N

Thus the weight of an object is 2256.3 N.

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The electron number cannot be used instead because electrons can be removed from or added to an atom (option C)

The element of an atom is determined by its proton count, while the electron count can exhibit variability. Take, for instance, a sodium atom, which encompasses 11 protons and 11 electrons. However, it has the capacity to relinquish one electron, transforming into a sodium ion housing only 10 electrons.

This occurs due to the relatively loose binding of electrons to the nucleus, enabling their removal through the influence of an electric field or alternative mechanisms.

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Answer:

the sun is larger in mass and therefore gravitational pull.

Explanation:

Fun fact the moon has more gravitational force on the earth than the sun because its closer to the earth.

Answer:

Distance from sun to Neptune = 4.495E9 km

Time for light to travel = 4.495E9 / 3E5 sec = 14,980 sec

That is from sun to Neptune time fof light = 250 min

Time for light to travel from sun to earth is about 8 min

So the time from Neptune would be 242 to 258 min depending on position of Neptune - Note that Neptune is about 30X as far from the sun as earth and

250 min / 8 min is roughly 30

The uniform motion of kinematics allows us to find the time it takes for light to arrive from Neptune to Earth, which varies between:

          t₁ = 1.45 10⁴ s and t₂₂= 1.55 10⁴ s

depending on the relative distance of the two planets

given parameters

to find

They  velocit of an electromagnetic wave is constant, so we can use the uniform motion relationships

             v = d / t

             t = d / v

where v is the speed of light, d the distance and y time, in this case the speed of the wave is the speed of light (v = c)

We look in the tables for the distances and the rotation periods around the sun

                           distance ( m)         period (s)

Sun Neptunium     4.50 10¹²             5.2 10⁹

Sun - Earth             1.5    10¹¹              3.2 10⁷

With the data of the period it is observed that the rotation of Neptune is much greater than that of Eart rotation around the sun, for which we will assume that Neptunium is fixed in space and the Earth may be in its aphelion or perihelion, maximum approach o away distance from the sun, consequently we calculate the time for the two cases:

Maximum approach

positions relative distance from the dos Plantetas is

         Δd = \(x_{Neptuno - Sum} - x_{Earth - Sum}\)d  

         Δd = 4.50 10¹²  - 1.5 10¹¹

         Δd = 43.5 10¹¹ m

the time it takes for Neptune's light to reach Earth is

        Δt = \(\frac{ 43.5 \ 10^{11} }{3 \ 10^8}\)  

        Δt = 14.5 10³ s

        Δt = 1.45 10⁴ s

We reduce to hours

        Δt = 1.45 10⁴ s (1 h / 3600 s) = 4.03 h

Maximum away

         Δd = \(x_{Neptune - Sum} + x_{Neptune-Sum}\)  

         Δd = 4.50 10¹² + 1.5 10¹¹

         Δd = 46.5 10¹¹

The time is

         Δt = \(\frac{46.5 \ 10^{11}}{ 3 \ 10^8}\)  

         Δt = 15.5 10³

         Δt = 1.55 10⁴ s

We reduce to hours

         Δt = 1.55 10⁴ s (1 h / 3600 s) = 4.31 h

In conclusion, the time it takes for light to arrive from Neptune to Earth varies between:

          t₁ = 1.45 10⁴ s and t₂ = 1.55 10⁴ s

depending on the relative distance of the two plants

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Centripetal acceleration=  6.25m/s/s for a ball that is attached to 1 m string and swung around in a horizontal circle.

A change in velocity is called acceleration. Centripetal acceleration is the change in velocity due to circular motion . Centripetal acceleration is calculated by taking the square of linear velocity divided by the radius of the circle the object is travelling.

Centripetal acceleration can be calculated when length and speed are given. Centripetal acceleration is measured in meters per second per second (m/s/s) and  the equation can be written as a = v^2 / r.

Centripetal acceleration is greater at high speeds and in sharp curves as can be noticed while driving a car.

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Answer:As the temperature increases, the helium in the ballon expands.

Explanation:

I took the quiz already

The answer is C) As the temperature increases, the helium in the balloons expands.

Have a blessed day!

(a) The amplitude of the wave is 3 cm.

(b) The speed of the wave is 19.6 m/s

(c) The angular frequency is 653.72 rad/s.

(d) The period of the wave is 0.0096 s.

(e) The wavelength of the wave is 0.392 m.

The speed of the wave is calculated as follows;

\(v = \sqrt{\frac{T}{\mu} }\)

where;

\(v = \sqrt{\frac{50}{0.13} } \\\\v = 19.6 \ m/s\)

ω = v/r

ω = v/A

ω = 19.6/0.03

ω = 653.72 rad/s

\(T = \frac{2\pi }{\omega } \\\\T = \frac{2\pi }{653.72} \\\\T = 0.0096 \ s\)

v = fλ

λ = v/f

λ = 19.6/50

λ = 0.392 m

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Answer:

B) brittle

Explanation:

This describes most covalent compounds.

Answer:

B.)

Explanation:

The atoms can be of the same element or different elements. In each molecule, the bonds between the atoms are strong but the bonds between molecules are usually weak. This makes many solid materials with covalent bonds brittle.

Answer:

the bigger stars tend to be hotter and burn through their fuel more quickly than smaller stars they also tend to ether be turned into a black hole or a huge nebula with a neutron star the smaller stars have a tendency to go through their fuel slower and don't get as hot as big stars until the red giant stage.

Explanation:

Option C. The heat absorbed or lost by a substance while it's changing state  correctly describes latent heat

Latent heat is the heat absorbed or lost by a substance while it is changing state.

The latent heat is a type of heat that is transferred during phase change, i.e., while a substance undergoes a change of state.

For example, when ice melts into liquid water, or when liquid water evaporates into water vapor, heat is absorbed from the surroundings.

Latent heat is not associated with a temperature change; rather, it's associated with a change of state.

For instance, the temperature of water remains at 100°C while boiling.

When water is boiling, the latent heat of vaporization is absorbed and utilized to break the hydrogen bonds holding water molecules together to change water from the liquid phase to the gaseous phase.

When the water is boiling, adding more heat won't increase the water's temperature, instead, the extra heat will be absorbed to change the phase of water molecules.

Therefore, the correct answer to the given question is option C: The heat absorbed or lost by a substance while it is changing state.

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Questions Diagram is attached below

Answer:

\(T=2.08s\)

Explanation:

From the question we are told that:

Speed of Train \(V=3.0m.s\)

Angle \(\theta=12\textdegree\)

Height of window \(h_w=0.90m\)

Width of window \(w_w=2.0m\)

The Horizontal distance between B and A from Trigonometric Laws is mathematically given by

 \(b=\frac{0.9}{tan12}\)

 \(b=4.23\)

Therefore

Distance from A-A

 \(d_a=2.0+4.23\)

 \(d_a=6.23\)

Therefore

Time Required to travel trough d is mathematically given as

 \(T=\frac{d_a}{v}\)

 \(T=\frac{6.23}{3}\)

 \(T=2.08s\)

friction is the force that resists the sliding or rolling of an object over another.

Answer:

Refer to the step-by-step Explanation.

Step-by-step Explanation:

Simplify the equation with given substitutions,

Given Equation:

\(mgh+(1/2)mv^2+(1/2)I \omega^2=(1/2)mv_{_{0}}^2+(1/2)I \omega_{_{0}}^2\)

Given Substitutions:

\(\omega=v/R\\\\ \omega_{_{0}}=v_{_{0}}/R\\\\\ I=(2/5)mR^2\)\(\hrulefill\)

Start by substituting in the appropriate values: \(mgh+(1/2)mv^2+(1/2)I \omega^2=(1/2)mv_{_{0}}^2+(1/2)I \omega_{_{0}}^2 \\\\\\\\\Longrightarrow mgh+(1/2)mv^2+(1/2)\bold{[(2/5)mR^2]} \bold{[v/R]}^2=(1/2)mv_{_{0}}^2+(1/2)\bold{[(2/5)mR^2]}\bold{[v_{_{0}}/R]}^2\)

Adjusting the equation so it easier to work with.\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{2} \Big[\dfrac{2}{5} mR^2\Big]\Big[\dfrac{v}{R} \Big]^2=\dfrac12mv_{_{0}}^2+\dfrac12\Big[\dfrac25mR^2\Big]\Big[\dfrac{v_{_{0}}}{R}\Big]^2\)

\(\hrulefill\)

Simplifying the left-hand side of the equation:

\(mgh+\dfrac{1}{2} mv^2+\dfrac{1}{2} \Big[\dfrac{2}{5} mR^2\Big]\Big[\dfrac{v}{R} \Big]^2\)

Simplifying the third term.

\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{2} \Big[\dfrac{2}{5} mR^2\Big]\Big[\dfrac{v}{R} \Big]^2\\\\\\\\\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{2}\cdot \dfrac{2}{5} \Big[mR^2\Big]\Big[\dfrac{v}{R} \Big]^2\\\\\\\\\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2\Big]\Big[\dfrac{v}{R} \Big]^2\)

\(\\ \boxed{\left\begin{array}{ccc}\text{\Underline{Power of a Fraction Rule:}}\\\\\Big(\dfrac{a}{b}\Big)^2=\dfrac{a^2}{b^2} \end{array}\right }\)

\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2\Big]\Big[\dfrac{v^2}{R^2} \Big]\\\\\\\\\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2 \cdot\dfrac{v^2}{R^2} \Big]\)

"R²'s" cancel, we are left with:

\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2\Big]\Big[\dfrac{v^2}{R^2} \Big]\\\\\\\\\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5}mv^2\)

We have like terms, combine them.

\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2\Big]\Big[\dfrac{v^2}{R^2} \Big]\\\\\\\\\Longrightarrow mgh+\dfrac{7}{10} mv^2\)

Each term has an "m" in common, factor it out.

\(\Longrightarrow m(gh+\dfrac{7}{10}v^2)\)

Now we have the following equation:

\(\Longrightarrow m(gh+\dfrac{7}{10}v^2)=\dfrac12mv_{_{0}}^2+\dfrac12\Big[\dfrac25mR^2\Big]\Big[\dfrac{v_{_{0}}}{R}\Big]^2\)

\(\hrulefill\)

Simplifying the right-hand side of the equation:

\(\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac12\cdot\dfrac25\Big[mR^2\Big]\Big[\dfrac{v_{_{0}}}{R}\Big]^2\\\\\\\\\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac15\Big[mR^2\Big]\Big[\dfrac{v_{_{0}}}{R}\Big]^2\\\\\\\\\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac15\Big[mR^2\Big]\Big[\dfrac{v_{_{0}}^2}{R^2}\Big]\\\\\\\\\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac15\Big[mR^2\cdot\dfrac{v_{_{0}}^2}{R^2}\Big]\\\\\\\\\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac15mv_{_{0}}^2\Big\\\\\\\\\)

\(\Longrightarrow \dfrac{7}{10}mv_{_{0}}^2\)

Now we have the equation:

\(\Longrightarrow m(gh+\dfrac{7}{10}v^2)=\dfrac{7}{10}mv_{_{0}}^2\)

\(\hrulefill\)

Now solving the equation for the variable "v":

\(m(gh+\dfrac{7}{10}v^2)=\dfrac{7}{10}mv_{_{0}}^2\)

Dividing each side by "m," this will cancel the "m" variable on each side.

\(\Longrightarrow gh+\dfrac{7}{10}v^2=\dfrac{7}{10}v_{_{0}}^2\)

Subtract the term "gh" from either side of the equation.

\(\Longrightarrow \dfrac{7}{10}v^2=\dfrac{7}{10}v_{_{0}}^2-gh\)

Multiply each side of the equation by "10/7."

\(\Longrightarrow v^2=\dfrac{10}{7}\cdot\dfrac{7}{10}v_{_{0}}^2-\dfrac{10}{7}gh\\\\\\\\\Longrightarrow v^2=v_{_{0}}^2-\dfrac{10}{7}gh\)

Now squaring both sides.

\(\Longrightarrow \boxed{\boxed{v=\sqrt{v_{_{0}}^2-\dfrac{10}{7}gh}}}\)

Thus, the simplified equation above matches the simplified equation that was given.  

The acceleration of the system is 2.77 m/s² and the tension in the string is 127.4 N, given the provided values.

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Answer:

Sure, I can help you with that. Here are some of the properties of common salt and edible oil that can be compared using scientific learning:

Physical properties: Common salt is a solid at room temperature, while edible oil is a liquid. Common salt is also denser than edible oil.

Chemical properties: Common salt is a compound of sodium and chlorine, while edible oil is a mixture of triglycerides.

Biological properties: Common salt is essential for human health, while edible oil is a source of energy and essential fatty acids.

To compare the properties of common salt and edible oil, I would use the following scientific methods:

Observation: I would observe the physical properties of common salt and edible oil, such as their color, odor, and texture.

Measurement: I would measure the physical properties of common salt and edible oil, such as their melting point, boiling point, and density.

Chemical analysis: I would use chemical analysis to determine the chemical composition of common salt and edible oil.

Biological testing: I would use biological testing to determine the biological effects of common salt and edible oil on humans and animals.

By using these scientific methods, I would be able to compare the properties of common salt and edible oil in a comprehensive and informative way.

Explanation:

Common salt and edible oil can be compared using scientific learning by examining their physical and chemical properties. Through experiments and analysis, we can better understand the similarities and differences between them.

Common salt (sodium chloride) and edible oil are both food ingredients, but they have distinct properties and serve different purposes in cooking and nutrition. The properties of common salt and edible oil can be compared using scientific learning in various ways. One approach is to examine their physical properties such as melting point, boiling point, solubility, and density.

Another approach is to analyze their chemical properties, including their reactions with other substances and their ability to conduct electricity. By conducting experiments and analyzing the data, we can gain a better understanding of the similarities and differences between common salt and edible oil. Edible oils provide essential fats and calories, while salt is used sparingly due to its association with health concerns like hypertension.

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a. The minimum force required to start moving the block is 9.8 N

b.  The force required to continue moving the block at a constant velocity is 5.88 N.

c. If a force greater than 9.8 N is applied, the block will start moving and continue to move until the applied force is less than 5.88 N.

a. Force = μs * N

N = m * g = 2.0 kg * 9.8 m/s^2 = 19.6 N

Force = μs * N = 0.50 * 19.6 N = 9.8 N

b. Force = μk * N = 0.30 * 19.6= 5.88 N N

c. In conclusion, If a force greater than 5.88 N is applied, the block will accelerate. If a force less than 5.88 N is applied, the block will decelerate and eventually stop if the force becomes less than the force of static friction (9.8 N).

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Answer:

The strength of the electric field is determined by the amount of charge on the source charge (Q) and the separation distance (d) from the source charge.

Explanation:

The interaction of charged objects is a non-contact force that operates over a certain separation distance. Distance, distance, distance. Every electrical contact is accompanied by a force, emphasizing the significance of these three factors. Whether it's a plastic golf tube attracting paper bits, two like-charged balloons repelling, or a charged Styrofoam plate interacting with electrons in a piece of metal, the three crucial factors that impact the strength of the interaction are always two charges and a distance between them.  The electrical force, like all other forces, is usually measured in Newtons. The electrical interaction's intensity is a vector quantity with both magnitude and direction since it is a force. The electrical force's direction is determined by whether the charged objects are charged with similar or opposing charges, as well as their spatial orientation. With a little logic and knowledge of the two objects' charge types, the direction of the force on either of them may be determined. Objects A and B in the figure below have similar charges, hence they repel each other.

The structure that is on the ventral side of the heart, located more laterally within the axial region is axillary lymph nodes.

The axillary lymph nodes are lymph nodes located in the human armpit. They drain lymph vessels from the lateral quadrants of the breast, superficial lymph vessels from the thin walls of the chest and abdomen above the level of the navel, and upper limb vessels.

They are classified into several groups based on their location in the armpit. These lymph nodes are clinically significant in breast cancer, and metastasis from the breast to the axillary lymph nodes is taken into account in disease staging.

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Answer:

5.0 x 10^8

Explanation:

because u moved it 8 times to it places

Answer: B

G v = 60 cm/s λ = 15 cm E f = V / λ S f = 4 Hz U f = ? S f = (60 cm/s) / 15 cm 5.

Explanation: