A circuit consists of a wire, a lightbulb, a switch, and a battery. What would
happen if the battery were replaced with a section of wire?

Answer:

1.29 s

Explanation:

As we know that ,

\(\sf\longrightarrow Time_{descent}= \sqrt{\dfrac{2H}{g_{(moon)}}}\\\\\sf\longrightarrow t_d = \sqrt{\dfrac{ 2\times 1.4}{1.67}} \\\\\sf\longrightarrow t_d =\sqrt{1.67} s\\\\\sf\longrightarrow \boxed{\red{\sf Time_{descent}= 1.29 s }} \)

Answer:

How does the wavelength at which the maximum intensity occurs change when you increase the temperature? The wavelength decreases.

Explanation:

...

Answer:

27v

Explanation:

10 ohm resistor is the first in series. so it will have the entire current.

voltage across 10ohm resistor = 10*2.7= 27v

Answer:

the velocity of the car is 30 m/s.

Explanation:

Given;

Centripetal force on the car, F = 900 N

mass of the car, m = 10 kg

diameter of the circular path, d = 20 m

radius of the circular path, r = 10 m

The velocity of the car is calculated as follows;

\(F = \frac{mv^2}{r} \\\\mv^2 = Fr\\\\v^2 = \frac{Fr}{m} \\\\v = \sqrt{\frac{900 \times 10}{10} } \\\\v = 30 \ m/s\)

Therefore, the velocity of the car is 30 m/s.

Answer:

Dark matter?

Explanation:

Answer:

matter

Explanation:

Answer:

Explanation:

The acceleration of the ball would be due to the downward force of gravity, 9.8m/s^2. In order to find the displacement given that interval of time, you have to use the corresponding kinematic formula:

\(d=v_it+at^2/2\)

The initial velocity was given, the time was given, and the acceleration was given. Therefore:

\(d=(22m/s)(4s)+(9.8m/s^2)(4s)^2/2\)

\(d=166.4m\)

To find the required time given a desired final velocity, we can use:

\(v_f=v_i+at\)

\(60m/s=22m/s+(9.8m/s^2)(t)\)

\(38=9.8t\)

\(t=3.9s\)

The plumb bob hangs vertically downwards when the railroad car is at rest. However, when the car moves in a circular track of radius 340 m at a speed of 94 km/h, it experiences a centrifugal force that pulls the plumb bob away from the vertical.

To find the angle relative to the vertical at which the plumb bob hangs, we need to use the formula:

tan(theta) = (v^2) / (g * r)

where:
theta = angle relative to the vertical
v = speed of the railroad car = 94 km/h = 26.11 m/s
g = acceleration due to gravity = 9.81 m/s^2
r = radius of the circular track = 340 m

Substituting the given values, we get:

tan(theta) = (26.11^2) / (9.81 * 340)
tan(theta) = 2.146

Taking the inverse tangent of both sides, we get:

theta = tan^-1(2.146)
theta = 64.7 degrees

Therefore, the plumb bob hangs at an angle of 64.7 degrees relative to the vertical when the railroad car rounds a circular track of radius 340 m at a speed of 94 km/h.

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Answer:

redox reaction

Explanation:

Answer: Emotional

Answer to a.p.e.x

Answer:

\(\huge\boxed{\sf F= 350 \ N}\)

Explanation:

Considering pivot as the central point,

Key:

\(F_1r_1=F_2r_2\)

Here,

Substitute the givens in the above formula.

\(F(1.2)=600(0.7)\\\\F(1.2)=420\\\\Divide \ 1.2 \ to \ both \ sides\\\\F=420/1.2\\\\F= 350 \ N\\\\\rule[225]{225}{2}\)

By Using Euler's method with two steps, we can find the approximate value of Y(2) is 2.125. , where Y is the solution of the initial value problem dy/dx = x - y, and Y(1) = 3.

Euler's method is defined as a numerical technique which is  used to approximate solutions into ordinary differential equations. The method includes dividing the interval of interest into smaller steps and thereafter approximating the solution at each step by using the derivative of the function.

In this case, we are given the initial value problem dy/dx = x - y, with the initial condition Y(1) = 3. To approximate Y(2) using Euler's method with two steps, we will divide the interval [1, 2] into two equal steps.

Step 1:

We start with the initial condition Y(1) = 3. Using the differential equation dy/dx = x - y, we can approximate the value of Y at the midpoint of the interval [1, 2].

Using the step size h = (2 - 1) / 2 = 0.5, we can calculate Y(1.5) as follows:

Y(1.5) ≈ Y(1) + h × (x - y) = 3 + 0.5 × (1.5 - 3) = 3 + 0.5 × (-1.5) = 2.25

Step 2:

Now, using the value of Y(1.5) as the new approximation, we calculate Y(2) using the same process:

Y(2) ≈ Y(1.5) + h × (x - y) = 2.25 + 0.5 × (2 - 2.25) = 2.25 + 0.5 × (-0.25) = 2.125

Thus,  by using Euler's method with two steps, the approximate value of Y(2) is 2.125.

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The complete question is

Use Euler's Method With Two Steps To Approximate Y(2), Where Y Is The Solution Of The Initial Value Problem: Dy : X − Y, Y(1) = 3

Answer:

d ko alam eh ahahahahahhahahaa

Answer:

v = λ f      wavelength * frequency

v = λ / P

v = 4.5 n / .007 sec = 643 m/s

Answer:

power=400Watt

Explanation:

work done =12kJ=12×10³=12000j

time taken=30s

power=?

as we know that

power=work done/time taken

power=12000J/30s

power=400Watt

i hope this will help you :)

\(v{j} = 500\)

\(vpj = - 1500\)

\(vpj = vp - vj\)

\( - 1500 = vp - 500\)

\(vp = - 1000\)

= 1000 km/h

Speed of ejection of combustion products observed from ground is 1000km/h in direction opposite to the direction of motion of the jet airplane.

The initial horizontal velocity can also be determined by measuring the diameter d of the ball and dividing by the time t that it takes for the ball to move across the photogate. That is Vo = d/t.

Find the distance between the base of the hill and the point where the ball hits the ground?

Let’s review the 4 fundamental kinematic equations of motion for constant acceleration (suggest you commit these to memory):

s = ut + ½at^2 …. (1)

v^2 = u^2 + 2as …. (2)

v = u + at …. (3)

s = (u + v)t/2 …. (4)

where s is distance, u is initial velocity, v is final velocity, a is acceleration and t is time.

In this case, we want to find the time for the ball to drop vertically to the ground, and then use that time to find the horizontal distance traveled.

For the vertical drop, we know u = 0, a = g = 9.81m/s^2 and s = 5m, so from equation (1) we get

s = ut + ½at^2

5 = 0 +4.905t^2

t = √(5/4.905) = 1.01s

Knowing t, we can now find the horizontal distance

s = ut + ½at^2

s = 35(1.01) + 0 (no horizontal acceleration)

s = 35.35m

So, the ball travels 35.35m horizontally before hitting the ground.

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The initial horizontal velocity can also be determined by measuring the diameter d of the ball and dividing by the time t that it takes for the ball to move across the photogate. That is Vo = d/t.

Let’s review the 4 fundamental kinematic equations of motion for constant acceleration (suggest you commit these to memory):

s = ut + ½at^2 …. (1)

v^2 = u^2 + 2as …. (2)

v = u + at …. (3)

s = (u + v)t/2 …. (4)

where s is distance, u is initial velocity, v is final velocity, a is acceleration and t is time.

In this case, we want to find the time for the ball to drop vertically to the ground, and then use that time to find the horizontal distance traveled.

For the vertical drop, we know u = 0, a = g = 9.81m/s^2 and s = 5m, so from equation (1) we get

s = ut + ½at^2

5 = 0 +4.905t^2

t = √(5/4.905) = 1.01s

Knowing t, we can now find the horizontal distance

s = ut + ½at^2

s = 35(1.01) + 0 (no horizontal acceleration)

s = 35.35m

So, the ball travels 35.35m horizontally before hitting the ground.

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Answer: c. and a

Explanation:

Answer:

The law of conservation of mass is a fundamental principle of physics. According to this law, matter can be neither created nor destroyed. In other words, the mass of an object or collection of objects never changes, no matter how the parts are rearranged.

Hope it helps!!!

Answer:

their will be no change in this..

The law of conservation of mass is a fundamental principle of physics. According to this law, matter can be neither created nor destroyed. In other words, the mass of an object or collection of objects never changes, no matter how the parts are rearranged.

Answer: Velocity = v = 35 m/s

Explanation:

Kinetic energy of an object is defined as the energy possess by an object due to its motion. Kinetic energy K.E of an object is equal to the half of the mass of that object multiplied by square of the object's velocity.

Mathematically,

v = 35 m/s

Answer:

the car you are in the cars have the same time frame and one covers more ground so on a possition time graph the slope will be greater

One method of stabilizing slope to prevent mass wasting is to implement engineering measures such as installing retaining walls, rock bolts, or wire mesh to reinforce the slope and prevent soil or rock from sliding downhill.

Additionally, planting vegetation can also help stabilize slope as the roots can hold soil in place and reduce erosion. Proper drainage systems can also help prevent saturation of the slope and reduce the risk of mass wasting.

Mass wasting, or the downward flow of soil, rock, or debris due to gravity, can be stopped by stabilising slopes. There are several strategies that can be used to lessen this occurrence. Retaining walls are a frequent method for strengthening slopes because they offer structural support and prevent soil or rock from sliding. Slope grading and terracing is a different technique that entails reducing the slope's angle and enhancing stability by dividing it into a series of steps or benches.

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Thus, the total potential is then V_total = \(-1.2 * 10^9V\)

The potential at a point due to a charge is given by V = kQ/r, where k is Coulomb's constant (~\(9x10^9 Nm^2/C^2\)), Q is the charge, and r is the distance from the charge.

The total potential at the center of the square is the sum of the potentials due to each charge.

The distance of each charge to the center is half the diagonal of the square, which is \(\sqrt2 * side/2 = \sqrt2 * \sqrt4.5/2 = 1.5m.\)

The total potential is then V_total

= \(k * [(510^8/1.5) + (210^8/1.5) - (510^8/1.5) - (710^8/1.5)] = -2 * k * 10^8 / 1.5 \\= -1.2 x 10^9 V.\)

Thus, the total potential is then V_total = \(-1.2 * 10^9V\)

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“The electric flux through a closed surface is equal to the net charge inside the surface divided by the physical constant. This law is a fundamental principle in electrostatics and is expressed mathematically as E.ds = Q/ε0.

Gauss’s Law for electric fields is a fundamental principle in physics, specifically in the study of electrostatics. The law describes the relationship between the electric flux and the distribution of electric charges in a given space. Simply put, it states that the electric flux through a closed surface is proportional to the total amount of electric charges inside the surface. In mathematical terms, the statement of Gauss’s Law for electric fields is as follows: E.ds = Q/ε0Here, E.ds represents the electric flux through a closed surface, Q represents the total electric charge enclosed within the surface, and ε0 is the physical constant known as the permittivity of free space. This equation can be used to calculate the electric field created by a given charge distribution, provided that the electric flux through a closed surface around the distribution is known.

Gauss’s Law for electric fields states that the electric flux through a closed surface is proportional to the net electric charge enclosed within the surface. This law is a fundamental principle in electrostatics and is expressed mathematically as E.ds = Q/ε0.

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Based on the given information, we need to determine the proportion of strain gauges that meet the specification of having a resistance within the range of 100 ± 0.7 ohms.

To find the proportion of acceptable strain gauges, we need to calculate the area under the normal distribution curve within the specified range.

First, we standardize the range by subtracting the mean and dividing by the standard deviation: (0.7 - 100) / 0.3 = -0.333. This gives us a standardized value of -0.333.

Next, we consult a standard normal distribution table or use statistical software to find the proportion of the area under the curve to the left of -0.333. Looking up this value in the table, we find that it is approximately 0.3707.

Since the normal distribution is symmetric, we multiply this proportion by 2 to account for the area to the right of the range as well. Therefore, the proportion of gauges that meet the specification is approximately 0.7414 or 74.14%.

In conclusion, approximately 74.14% of the strain gauges will have a resistance within the specified range of 100 ± 0.7 ohms, based on the given mean and standard deviation of the resistance values.

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Answer:

Computer hard drives use magnetism to store the data on a rotating disk. More complex applications include: televisions, radios, microwave ovens, telephone systems, and computers. An industrial application of magnetic force is an electromagnetic crane that is used for lifting metal objects.

Answer:

Examples of magnetic force is a compass, a motor, the magnets that hold stuff on the refrigerator, train tracks, and new roller coasters. All moving charges give rise to a magnetic field and the charges that move through its regions, experience a force.

I Hope this will help you if not then sorry :)

The property of a transverse wave that stays the same even as the wave's energy and other properties change is the wavelength.

The correct option to the given question is option a.

The wavelength is the distance between two successive points of the wave that are in phase. As the wave's energy and amplitude change, the distance between two successive points of the wave that are in phase remains the same.

This is because wavelength is determined by the frequency of the wave and the speed of propagation. The frequency of the wave is the number of cycles of the wave that occur in one second, while the speed of propagation is the rate at which the wave travels through a medium.

If the frequency of the wave and the speed of propagation remain the same, then the wavelength will also remain the same even as the wave's energy and other properties change. This property is known as the characteristic of the wave.The amplitude is the maximum displacement of a point on the wave from its rest position. The frequency is the number of cycles of the wave that occur in one second. The rest position is the position of the medium when it is not disturbed.

Hence, wavelength of a transverse wave remains same even as the wave's energy and other properties change.

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The force responsible for the acceleration of the crate is the frictional force between the crate and the bed of the truck.

When the truck accelerates, the crate tends to remain at rest due to inertia. However, the frictional force between the crate and the bed of the truck acts in the forward direction, allowing the crate to accelerate along with the truck.

This frictional force is a result of the interaction between the surfaces of the crate and the truck bed. Without this frictional force, the crate would slide or move independently from the truck's acceleration.

The frictional force arises due to the microscopically rough surfaces of the crate and the truck bed. As the two surfaces are pressed against each other, intermolecular forces come into play, resulting in the generation of the frictional force

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In both situations, the two forces that form a Newton's third-law force pair with equal magnitudes are the buoyant force exerted by the liquid on the block and the weight of the block exerted on the liquid.

When a block is floating in a container of liquid, it experiences two forces: the weight of the block and the buoyant force exerted by the liquid. The weight of the block is given by the equation:

\(\[ F_{\text{{weight}}} = mg \]\)

where m is the mass of the block and g is the acceleration due to gravity. The buoyant force exerted by the liquid on the block is equal to the weight of the liquid displaced by the block. It can be calculated using Archimedes' principle:

\(\[ F_{\text{{buoyant}}} = \rho V_{\text{{submerged}}} g \]\)

where \(\( \rho \)\) is the density of the liquid and \(\( V_{\text{{submerged}}} \)\) is the volume of the block that is submerged in the liquid.

When the block is replaced with a block of mass 2m , the weight of the block doubles while the buoyant force remains the same. Therefore, the two forces that form a Newton's third-law force pair with equal magnitudes in both situations are the buoyant force exerted by the liquid on the block and the weight of the block exerted on the liquid.

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The net force acting on the two (2) kids is equal to 180 Newton.

Given the following data:

To determine the net force acting on the two (2) kids:

First of all, we would calculate the total mass of the two (2) kids:

\(Total\;mass = 50+40\)

Total mass = 90 kg.

In this exercise, you're required to calculate the magnitude of the net force that is acting on these two (2) kids running down the hall. Thus, we would apply Newton's Second Law of Motion.

Mathematically, Newton's Second Law of Motion is given by this formula;

\(Net\;force = mass \times acceleration\)

Substituting the given parameters into the formula, we have;

\(Net\;force = 90 \times 2\)

Net force = 180 Newton.

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Answer:

When you push your palms together and rub them back and forth, you are demonstrating one way of converting Kinetic energy into thermal energy.