a child throws a rock with a velocity of 25 m/s at angle of 65 degrees above the horizontal. the rock hits the side of the building at a height of 12 meters. (a) How far above the release point does the ball hit the wall? What are the (b) horizontal and (c) vertical components of its velocity as it hits the wall? (d) When it hits, has it passed the highest point on its trajectory?

Answers

Answer 1

(a) The ball hits the wall 5.3 meters above the release point.

(b) The horizontal component of its velocity is 17.5 m/s. (c) The vertical component of its velocity is 17.1 m/s.

(d) Yes, it has passed the highest point on its trajectory.

(a) Using the equation for range, we can solve for time:

R = V*t*cosθ =>25*t*cos65 = 12 t = 0.75 s

We can then solve for the height using the equation for vertical displacement:

h = V*t*sinθ - 0.5*g*t^2

h = 25*0.75*sin65 - 0.5*9.8*0.75^2 h

= 5.3 m

(b) We can solve for the horizontal component of the velocity using the equation for range:

R = V*t*cosθ 17.5

    = 25*t*cos65 t

   = 0.7 s V = 17.5 m/s

(c) We can solve for the vertical component of the velocity using the equation for vertical displacement:

h = V*t*sinθ - 0.5*g*t^2 17.1

= 25*0.75*sin65 - 0.5*9.8*0.75^2 V = 17.1 m/s

(d) Yes, the ball has passed the highest point on its trajectory because the ball is traveling downwards when it hits the wall.

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Related Questions

The net force on a 13 kg cart is 4.6 N backward.
Ignoring friction, what is the acceleration of the
cart?
a. 0.27 m/s2 backward
b. 3.8 m/s2 backward
c. 35 m/s2 backward
d. 38 m/s2 backward

Answers

Divide the net force by the mass:

a = (4.6 N) / (13 kg) ≈ 0.35 m/s²

also pointing backward, which looks like option B, but hard to say for sure since it's missing a decimal point.

is this kinetic energy ---> elastic potential energy OR elastic potential energy ---> kinetic energy ??​

is this kinetic energy ---> elastic potential energy OR elastic potential energy ---> kinetic energy

Answers

Answer:

it is potential energy ---- kinetic energy

Under a pressure of 862 Pa, a gas has a volume of 752 L. The pressure is increased, without changing the temperature, until the volume is 624 L. What is the new pressure?

Answers

Claims that if temperature is kept constant, the end result of both volume and pressure is constant. The new level is 1036 Pa, which is how this can be expressed.

How does pressure work?

So either a strong force or a strong force applied over a short area can cause a lot of pressure. When we stand up compared to when we are walking, more of our feet are in proximity to the earth. Pressure would be lower if there was more surface area in contact.

Describe a force?

An external force is an agent that has the power to alter the resting or moving condition of a body. It has a direction and a magnitude. There are both living things and non-living objects in the concept of a force.

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There are two space ships traveling next to each other. The first one is 500
Kg and the second one is 498 Kg. Since they are 35 meters apart, what is
the force of gravity between the two space ships?

Answers

This question involves the concept of  Newton's law of gravitation.

The force of gravity between the two spaceships is "1355.78 N".

Newton's Law Of Gravitation

According to Newton's Law of Gravitation:

\(F=\frac{Gm_1m_2}{r^2}\)

where,

F = force of gravity between ships = ?G = Universal Gravitational Constant = 6.67 x 10⁻¹¹ N.m²/kg²m₁ = mass of first ship = 500 kgm₂ = mass of second ship = 498 kgr = distance between ships = 35 m

Therefore,

\(F=\frac{(6.67\ x\ 10^{-11}\ N.m^2/kg^2)(500\ kg)(498\ kg)}{(35\ m)^2}\\\\\)

F = 1355.78 N = 1.356 KN

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Two space ships traveling next to each other. The first one is 500 kg and the second one is 498 kg. They are 35 meters apart, the Force of gravity between the two spaceships is 1355.78 N.

It is given that the First spaceship's weight (\(m_{1}\)) is 500 kg,

The second spaceship's weight (\(\rm m_{2}\)) is 498 kg.

The distance between spaceships (r) is 35 meters.

It is required to find the Force of gravity between these spaceships.

What is Gravitational force?

It is defined as the force which attracts any two masses in the universe.

By Newton's law of Gravitation:

\(\rm F= \frac{Gm_1m_2}{r^2}\)  , Where

\(\rm F = The\ force \ of \ gravity \ between \ the \ spaceships\\\rm G= Universal\ Gravitational \ Constant = 6.67 \times 10^{-11} N.m^2/kg^2\)

Putting values in the above formula:

\(\rm F = \frac{(6.67\times 10^{-11} N.m^2/kg^2)(500kg)(498kg)}{(35m)^2}\)

F = 1355.78 N = 1.356  KN

Thus, Two spaceships travel next to each other. The first one is 500 kg and the second one is 498 kg. They are 35 meters apart, the Force of gravity between the two spaceships is 1355.78 N.

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A cognitive bias is a kind of logical fallacy.
True or false?

Answers

Answer:

True

Explanation:

It definetly is because, if we are biased it sets us up to fail on some things.

Two identical 0.25 kg balls are involved in a head-on collision. Ball A is initially travelling at 3.5 m/s, and ball B is initally at rest. Determine the velocity of each ball after the collision.

Answers

Answer:

a) mv(final):<0,0,0> minus mv(initial):<25,0,0> = <-25,0,0>

b) mv(final):<25,0,0> minus mv(initial):<0,0,0> = <25,0,0>

c) conservation of momentum makes it <0,0,0>

for a-b-c, momentum_system + momentum_surroundings = 0

Explanation:

Hope this helps

The velocity of each ball after the collision is 1.75 m/s

Law of conservation of momentum states that:

Total momentum before collision = Total momentum after collision

m₁u₁ + m₂u₂ = (m₁ + m₂)v

Where m₁, m₂ is the mass of object, u₁, u₂ is the initial velocity before collision and v is the final velocity after collision

Given that: m₁ = m₂ = 0.25 kg, u₁ = 3.5 m/s, u₂ = 0, hence:

0.25(3.5) + 0.25(0) = (0.25 + 0.25)v

v = 1.75 m/s

The velocity of each ball after the collision is 1.75 m/s

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If a person is putting in 500 J of work in a 25 second period, how much power are they producing?​

Answers

P= work/time. the work here is 500J and the time is 25s. simply plug in the given info into the equation. 500J/25s. remember that the unit of power is watts. your answer is 20 watts. hope this helps !

Part A) What is the magnitude of the force on the 1.0 nC charge in (Figure 1)?

Part B) What is the direction of the force on the 1.0 nC charge?

Part A) What is the magnitude of the force on the 1.0 nC charge in (Figure 1)?Part B) What is the direction

Answers

The magnitude of the force on the 1.0 nC charge is 3.8 N. The direction of the force on the 1.0 nC charge is towards the 2.0 nC charge, at an angle of 60°.

What is magnitude ?

Magnitude is a measure of the size or strength of something. It can refer to physical quantities such as size, temperature, mass, or energy, as well as abstract qualities like loudness, brightness, or intensity. Magnitude is usually expressed as a number on a scale or as a unit of measurement, such as degrees or decibels. Magnitude can also refer to the importance or significance of an event or situation. For example, a hurricane may be said to have a magnitude of 5, or a financial crisis may have a magnitude of 10. Magnitude is an important concept in many scientific fields, such as physics and astronomy, where it is used to measure the size or power of an object or phenomenon.

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Baltimore's population in 2010 was approximately 620 thousand and has been decreasing at a rate of about 0.5% per year. (a) Write an explicit formula for the population of Baltimore t years after 2010 (i.e. t=0 in 2010), where Pt is measured in thousands of people. Pt= (b) If this trend continues, what will the city's population be in 2030? Round your answer to the nearest whole number. thousand people (c) When does this model predict Baltimore's population will reach 450 thousand? Give your answer as a calendar year (ex: 2010). During the year

Answers

ANSWER:

(a)

\(P_t=620\cdot(1-\frac{0.5}{100})^t\)

(b) 561 thousand people

(c) During the year 2074



STEP-BY-STEP EXPLANATION:

(a) We can establish the formula to determine the population as follows:

\(P_t=620\cdot(1-\frac{0.5}{100})^t\)

(b) To calculate the population, we know that the year 2030 would be t = 20 (2030-2010), therefore:

\(\begin{gathered} P_t=620\cdot(1-\frac{0.5}{100})^{20} \\ P_t=561 \end{gathered}\)

(c) In this case, we know that the value of Pt is equal to 450, we replace and solve for t, like this:

\(\begin{gathered} 450=620\cdot(1-\frac{0.5}{100})^t \\ 0.995^t=\frac{450}{620} \\ t=\frac{\ln (0.726)}{\ln (0.995)} \\ t=63.9\cong64\rightarrow2010+64=2074 \end{gathered}\)

Are we within Earth's Roche limit?

Answers

Answer:

Yes

Explanation:

Within the Earths Roche is our mass and body.

Which of the following BEST explains the energy transformation that takes place when a battery alarm clock goes off.

A. electrical energy --> chemical energy --> sound energy

B. electrical energy --> chemical energy --> mechanical energy --> sound energy

C. chemical energy --> electrical energy --> mechanical energy --> sound energy

D. it is impossible to tell without knowing what type of battery

Answers

I think it might be Either A or B im thinking B

Select the correct answer.
Which scientist discovered the relationship between electricity and magnetism?
OA.
Nikola Tesla
OB
Alessandro Volta
OC.
Hans Christian Oersted
OD
Isaac Newton

Answers

Answer:

Hans Christian Oersted

Explanation:

Nowton's third law refers to 'action reaction forces*. These forces are
always:

Answers

equal in magnitude but opposite in direction

Help me please I don’t understand

Help me please I dont understand

Answers

Answer:

a. hydroelectric power plant

what is the significance of kirchhoff's voltage law?​

Answers

Explanation:

Kirchhoff's Voltage Law (KVL) is Kirchhoff's second law that deals with the conservation of energy around a closed circuit path. ... His voltage law states that for a closed loop series path the algebraic sum of all the voltages around any closed loop in a circuit is equal to zero

What is the net force of particle q1

What is the net force of particle q1

Answers

The net force on particle 1 or charge 1 is determined as 32.73 N.

What is the  net force on particle1?

The net force acting on charge 1 is calculated by applying Coulomb's law as shown below;

Force due to charge 2;

F12 = (9 x 10⁹ x 5.16 x 10⁻⁶ x 8.99 x 10⁻⁶)/ (0.22²)

F12 = 8.625 N

Force due to charge 3;

F12 = (9 x 10⁹ x 89.9 x 10⁻⁶ x 8.99 x 10⁻⁶)/ (0.55²)

F12 = 24.1 N

The net force on charge 1 is calculated as;

F (net) = 8.625 N + 24.1 N

F (net) = 32.73 N

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Ursula is a student of Kantian philosophy who argues that we should never use people as a means to an end unless

Answers

Answer: we embrace and are simultaneously respecting their rational autonomy

Explanation:

Ursula is a student of Kantian philosophy who argues that we should never use people as a means to an end unless we embrace and are simultaneously respecting their rational autonomy

Police at a crime scene find a ceramic mug shattered on the sidewalk. They want to determine the window from which the mug fell, and they decide to make a model of the fall. Which quantitiy would be an important boundary condition for this model?

the hardness of the sidewalk where the mug landed

the time of day when the incident occurred

the final speed of the mug

the initial height of the mug above the sidewalk

Answers

Answer:

Initial height

Answer:

A: the hardness of the sidewalk where the mug landed

Explanation:

did the quick check

what are atoms mostly made of 


nucleus empty space electrons, fuzzy stuff

Answers

The core (nucleus) of an atom is made up of protons and neutrons. Protons have a charge, whereas neutrons have no charge. A cloud of charged particles known as electrons surrounds the nucleus. Electrons have a charge that is diametrically opposed to the charge on the

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Two forces are acting on an object as shown in
Fig. on the right. What is the magnitude of the
resultant force?

Answers

If the coordinates of the initial point and the end point of a vector is given, the Distance Formula can be used to find its magnitude. resultant force is the force (magnitude and direction) obtained when two or more forces are combined.

A large mining dump truck has a mass of 40,000 kg. If its engine produces
20,000N of force, how fast will the truck accelerate?

Answers

Answer:

0.5 m/s²

Explanation:

Net force = mass × acceleration

∑F = ma

20,000 N = (40,000 kg) a

a = 0.5 m/s²

Answer:

which one will not start moving faster

Explanation:

Mass is also described by physics. If you apply the same amount of force to a small sports car and to a big garbage truck.

Why does the book with more mass feel heavier in your hand

Answers

Answer:

because the book's is covered by papers

A car has a crumple zone that is 0.80 m (80 cm) long. In this car, the distance from the dummy to the steering wheel is 0.50 m. The car has a mass of 1,600 kg and the dummy has a mass of 75 kg. At the time of the crash, the car has a speed of 18 m/s. Based on the work-energy theorem, what is the smallest possible force that the dummy could experience during the crash

Answers

Answer:

F = 518.4 KN

Explanation:

From work energy theorem;

Energy = workdone

In this case, Energy is kinetic energy and has a formula ½mv²

Thus;

Fd = ½mv²

We are given;

Mass of car; m = 1600 kg

Speed of car after crash; v = 18 m/s

Distance from dummy to steering wheel; d = 0.5 m

Thus;

½ × 1600 × 18² = F × 0.5

This gives;

800 × 324 = 0.5F

F = 800 × 324/0.5

F = 518400 N

F = 518.4 KN

Answer: A -9.35

Explanation: The work-energy theorem states the work (Fd) is equal to the change in kinetic energy: Fd = ΔKE. Before the crash, the kinetic energy of the dummy is equal to one-half mass times velocity squared, or 0.5 · 75 kg · (18 m/s)2, which is equal to 12,150 J. The kinetic energy of the dummy after the crash is 0 J, so the change in kinetic energy is –12,150 J. If the crumple zone collapses completely and the dummy just misses hitting the steering wheel, then the distance d is 0.80 + 0.50 = 1.30 m. So we have:

F · d = ΔKE

F = ΔKE/d

F = –12,150 J/1.30 m = 9,346 N, or 9.35 kN

what happen to kinetic energy of a body if it speed is doubled​

Answers

Answer:

The energy possessed by a body because of its motion, equal to one half the mass of the body times the square of its speed is called its kinetic energy. Hence, when velocity is doubled, kinetic energy becomes 4 times.

Explanation:

A uniform 1200 N piece of medical apparatus that is 3.5 m long is suspended horizontally by two vertical wires at its ends. A small but dense 550 N weight is placed on the apparatus 2.0 m from one end, as shown in the figure. What are the tensions, A and B, in the two wires?

Answers

To determine the tensions in the two wires suspending the medical apparatus, we can analyze the forces acting on it.

Let's consider the apparatus to be divided into two sections: Section A (with length 2.0 m) and Section B (with length 1.5 m, which is the remaining length).

In Section A:
- The weight of the apparatus (1200 N) exerts a downward force at the center of gravity, which is 1.0 m from each end of Section A.
- The small weight (550 N) is placed 2.0 m from one end, which means it exerts a downward force 2.0 m from the same end.

In Section B:
- Only the weight of the apparatus (1200 N) exerts a downward force at the center of gravity, which is at the midpoint of Section B (0.75 m from each end).

Considering equilibrium, the sum of the clockwise moments (due to the forces) should be equal to the sum of the counterclockwise moments.

Let's calculate the tensions in the wires. Let T_A represent the tension in wire A and T_B represent the tension in wire B.

Clockwise moments (due to the forces):
- Weight of the apparatus in Section A: 1200 N * (2.0 m) = 2400 N·m
- Small weight in Section A: 550 N * (2.0 m) = 1100 N·m

Counterclockwise moments:
- Weight of the apparatus in Section B: 1200 N * (0.75 m) = 900 N·m

For equilibrium, the clockwise moments should be equal to the counterclockwise moments:
2400 N·m + 1100 N·m = 900 N·m

To find the tensions in the wires, we can consider the vertical forces:
In the vertical direction:
T_A + T_B = weight of the apparatus (1200 N) + small weight (550 N) = 1750 N

Now we have two equations:
T_A + T_B = 1750 N
T_B = 1750 N - T_A

Substituting the value of T_B in the clockwise moments equation:
2400 N·m + 1100 N·m = 900 N·m + T_A * (3.5 m)

Simplifying the equation:
3500 N·m = 900 N·m + T_A * (3.5 m)

Rearranging the equation to solve for T_A:
T_A * (3.5 m) = 3500 N·m - 900 N·m
T_A * (3.5 m) = 2600 N·m
T_A = 2600 N·m / (3.5 m)
T_A ≈ 742.86 N

Now, substituting the value of T_A in the equation T_A + T_B = 1750 N:
742.86 N + T_B = 1750 N
T_B = 1750 N - 742.86 N
T_B ≈ 1007.14 N

Therefore, the tension in wire A (T_A) is approximately 742.86 N, and the tension in wire B (T_B) is approximately 1007.14 N.

Which equation below is not valid for relating velocity,
time, displacement, and constant (or average)
acceleration?

Answers

Answer:(vi^2+d)^2=vf+a^2+2t

Explanation:

If the air inside a balloon exerts a force of 1 N on an area of 0.5 m^2 what is the pressure inside the balloon

Answers

Answer:

2 Pascal (Pa)

Explanation:

Pressure is defined as the force acting per unit area. Mathematically, it is expressed as:

Pressure (P) = Force (F) / Area (A)

Given:

Force exerted by the air inside the balloon (F) = 1 N

Area of the balloon (A) = 0.5 m^2

Plugging in the given values into the formula for pressure, we get:

P = F / A

P = 1 N / 0.5 m^2

Using basic arithmetic, we can calculate the pressure inside the balloon:

P = 2 N/m^2

So, the pressure inside the balloon is 2 N/m^2, which is also commonly referred to as 2 Pascal (Pa) since 1 Pascal is equal to 1 N/m^2.

If each wafer can hold 400 chips, what is the maximum number of chips that can be produced from one entire cylinder?

Answers

The maximum number of chips is 33,333

What is a chip?

A chip is a tiny but complex modules that store computer memory or provide logic circuitry for microprocessors.

We need to find the number of wafers that can be cut from a single crystal.

The crystal is 25cm and each wafer is 0.3mm. We perform division to get the number of wafers per crystal after getting everything into the same units. 25cm=250mm.

250mm/0.3mm=833.3333 wafers.

Each wafer yields 400 chips so we multiply 400 chips per wafer by 833.33 wafers to get 33,333 chips.

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please help answering A,B,C in screenshots thank you!

please help answering A,B,C in screenshots thank you!
please help answering A,B,C in screenshots thank you!

Answers

The slope of the graph is 0.5 m/s² and when t = 1.5 s, the predicted displacement (d) of the object is 0.75 meters.

To plot the velocity vs. time graph, we'll use the given data points:

Duration, At (s): 2.0, 4.0, 6.0, 8.0, 10.0, 12.0

Velocity, v (m/s): 6.0, 7.0, 8.0, 9.0, 10.0, 11.0

Let's plot these points on a graph:

Time (s) [x-axis] | Velocity (m/s) [y-axis]

--------------------------------------------

2.0               | 6.0

4.0               | 7.0

6.0               | 8.0

8.0               | 9.0

10.0              | 10.0

12.0              | 11.0

After plotting the points, we can connect them with a straight line to represent the motion of the object. This line represents the velocity vs. time relationship.

Now, let's calculate the slope of this line. The slope of a line represents the rate of change of the dependent variable (velocity) with respect to the independent variable (time). In this case, it gives us the acceleration of the object.

Using the formula for calculating the slope of a line:

Slope (k) = (Change in velocity) / (Change in time)

For the first two points:

Change in velocity = 7.0 - 6.0 = 1.0 m/s

Change in time = 4.0 - 2.0 = 2.0 s

Slope (k) = 1.0 m/s / 2.0 s = 0.5 m/s²

Therefore, the slope of the graph is 0.5 m/s².

Now, to answer part B, the physical significance of the slope value is that it represents the object's acceleration. In this case, the constant acceleration experienced by the object is 0.5 m/s².

Moving on to part C, we are given the equation d = kt, where d represents the displacement and t represents time. Since the object is experiencing constant acceleration, the equation can be rewritten as d = 0.5t, where 0.5 is the acceleration (k).

To predict the value of "d" when t = 1.5 s, we can substitute the value of t into the equation:

d = 0.5 * 1.5 = 0.75 meters

Therefore, when t = 1.5 s, the predicted displacement (d) of the object is 0.75 meters.

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The probable question may be:

An object is subjected to a constant acceleration along a frictionless track. A student measures its velocity (v) after specific durations (At). The student uses a graph to analyze the truck's motion.

Duration, At, (s) :- 2.0,4.0,6.0,8.0,10.0,12.0.

Velocity, v, (m/s) :- 6.0,7.0,8.0,9.0,10.0,11.0

A. Plot the velocity (in meters/sec) vs. time (seconds). The velocity is the y-axis and time is the x-axis. Use any graphing software you like or graph this data in pencil on graph paper. Excel has a nice graphing package. Calculate the slope of this graph. You will

B. What is the physical significance of the slope value computed in part A?

C. Having determined the slope of the line, you can now write d = kt. Use this equation to predict a value of "d" when t = 1.5 s.

How does a balanced equation illustrate the Law of Conservation of Mass?

Answers

The balanced equation illustrates the Law of Conservation of Mass as the mass of the products must be equal to the mass of the reactants.

The law of conservation of mass is always obeyed by a chemical equation that is balanced. This law states that the mass of the products must be equal to the mass of the reactants in order for the law to be valid. It is possible to determine whether or not a reaction is balanced by determining whether or not the number of moles of atoms across both ends of the chemical process is equivalent. If the number of moles is the same on both sides the total mass will also be the same.

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