A chef is going to use a mixture of two brands of Italian dressing. The first brand contains 5% vinegar, and the second brand contains 8% vinegar. The chef wants to make 300 milliliters of a dressing that is 7% vinegar. How much of each brand should she use?



First Brand: ?


Second Brand: ?

Answer:

Line A, because it is closest to most data points

Step-by-step explanation:

That is your answer because Line A is the closest to most of the data points, while Line B is more farther away. Also, the line of best fit has nothing to do with the positive or negative association.

Answer:

Line A

Step-by-step explanation:

It is the closest to the data points

Answer:

I think you should start with a table and then write all your points for x then in the next column your answers for y.

Then take your medium and start drawing.

I suggest your x's should start from 0 and increase by 1 or 2

Then when you reach a certain point then go back to 0 and start doing your negatives.

For example if y = 2x

x | y

0|0

1 | 2

2| 4

3|6

4|8

....

then

16|32

0|0

-1|-2

-2|-4

Thanks for this question. I am working my way up to brainliest answer and Master Answerer. This answer took a lot of time to type so I hope I get good review.

:)

:)

Step-by-step explanation:

Answer:

Each person will get 1/24 gallon of milk

Step-by-step explanation:

The decision between the two cities involves tradeoffs: the first city offers a wide range of class sizes but a smaller sample, while the second city has a larger sample but a narrower class size range.

The decision of which city to choose for the study involves tradeoffs. The first city allows for a wide range of class sizes, providing a comprehensive analysis of the relationship between class size and academic performance. However, the smaller sample size limits generalizability.



The second city offers a larger sample size, increasing generalizability, but with a narrower range of class sizes. Researchers should consider their specific research objectives, available resources, and constraints. If the goal is to assess the impact of extreme variations in class size, the first city is suitable. If obtaining highly generalizable results is paramount, the second city, despite the narrower range, should be chosen.



Therefore, The decision between the two cities involves tradeoffs: the first city offers a wide range of class sizes but a smaller sample, while the second city has a larger sample but a narrower class size range.

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Answer: x=14

Step-by-step explanation:Simplify both sides of the equation(Distribute),Subtract 4/5 from both sides.Multiply both sides by 5/(-1).

Answer:

y = 2x - 3

Step-by-step explanation:

y - - 3 = 2(x-0)

y + 3 = 2x

y = 2x -3

The volume of the cone is one-third the volume of the pyramid, the area of the circle is pi/4 the area of the square because the radius of the circle is half the side length of the square.

The volume of the cone is one-third the volume of the pyramid because the cone's base is a sector of the square, and the sector takes up one-third of the square's area.

Volume of a cone: The volume of a cone is equal to (1/3)πr²h, where r is the radius of the base and h is the height of the cone.

Volume of a pyramid: The volume of a pyramid is equal to (1/3)Bh, where B is the area of the base and h is the height of the pyramid.

In the problem, we are told that the area of the circle is pi/4 the area of the square. This means that the radius of the circle is half the side length of the square. We can use this information to find the volume of the cone and the pyramid.

Volume of the cone: The radius of the cone is half the side length of the square, so r = s/2. The height of the cone is h. The area of the base of the cone is (pi)(r²) = (pi)(s²/4). So, the volume of the cone is (1/3)π(s²/4)h = (1/12)πs²h.

Volume of the pyramid: The area of the base of the pyramid is the same as the area of the base of the cone, which is (pi)(s²/4). The height of the pyramid is the same as the height of the cone, which is h. So, the volume of the pyramid is (1/3)π(s²/4)h = (1/12)πs²h.

As you can see, the volume of the cone is equal to one-third the volume of the pyramid.

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Answer: 236.715

Step-by-step explanation:

1. Find the area of the middle rectangle.

Use A = bh

A = (4)(15)

A = 60

2. Find the area of the two semicircles (which equals one circle)

Use A = πr²

The diameter is given.

D = 2r

15 = 2r

r = 7.5

A = π(7.5)²

A ≈ 176.715

3. Add the area of the rectange and circle.

60 + 176.715 = 236.715

The equation of the line passing through the points (-3, -28) and (5, 44) is 9x - y = -1.

To find the equation of the line passing through the given points (-3, -28) and (5, 44), we can use the point-slope form of a linear equation.

The point-slope form is given by: y - y₁ = m(x - x₁), where (x₁, y₁) is a point on the line and m is the slope of the line.

First, let's calculate the slope (m) using the formula:

m = (y₂ - y₁) / (x₂ - x₁),

where (x₁, y₁) = (-3, -28) and (x₂, y₂) = (5, 44).

m = (44 - (-28)) / (5 - (-3))

= (44 + 28) / (5 + 3)

= 72 / 8

= 9.

Now that we have the slope (m = 9) and a point (x₁, y₁) = (-3, -28), we can use the point-slope form to write the equation:

y - (-28) = 9(x - (-3)).

Simplifying:

y + 28 = 9(x + 3).

Expanding:

y + 28 = 9x + 27.

Rearranging the terms:

9x - y = -1.

Thus, the equation of the line passing through the points (-3, -28) and (5, 44) is 9x - y = -1.

The equation of the line is 9x - y = -1.

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Inequality can be used to determine x, the greatest number of 120-kilogram crates that can be loaded onto the shipping container is  8000 + 120C <= 27500

An inequality is a relationship that allows us to contrast two or more mathematical expressions.

Knowing that;

Each carton weighs 120 kg.

The container's maximum weight when loaded is 27500 kg.

Weight of the container as it is currently loaded: 8000 kg

Now that we have merged, we have;

Solution

because 8000 grams have already been loaded kilograms

into the container

each crate weighs 120 kilograms.

so 8000 + 120C <= 27500

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The numerical expression that is equivalent to (4/5−3/8)+(−2/3−4/5) is -77/120. Alternatively, this expression can also be written as -0.64167 or -64.167%.

To solve this problem, we need to combine the like terms. First, we need to find the common denominator of the fractions in the expression. The smallest common denominator for 5, 8, and 3 is 120. We can then rewrite each fraction with 120 as the denominator.

(4/5 - 3/8) = (32/40 - 15/40) = 17/40
(-2/3 - 4/5) = (-400/600 - 240/600) = -640/600 = -32/30

Now we can substitute these equivalent expressions back into the original equation:

(4/5−3/8)+(−2/3−4/5) = (17/40) + (-32/30)

We can simplify this expression by finding the least common multiple (LCM) of 40 and 30, which is 120. We can then rewrite each fraction with 120 as the denominator.

(17/40) = (51/120)
(-32/30) = (-128/120)

Now we can substitute these new fractions back into the expression:

(51/120) + (-128/120) = -77/120

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Step-by-step explanation:

Hello!
I'd love to help you learn.
I see the formula attached is \(4*(\frac{1}{2})^{x} =-2^{x}-1\\\)

This problem is explaining you to graph, since algebraically it's a little more harder to try and find the solution.

Since they're both equal to each other, we can assign a variable like y, so we can make them into two individual lines.

You can use your scientific calculator to graph lines like this, or otherwise there are online sources (Desmos helps alot!) which can graph two equations as so.

Now that we have the corresponding system of equations, we can graph both.

\(y=4*(\frac{1}{2})^x\\ y=-2^x-1\)
Let's graph them on Desmos on the same plane. The answers are attached. Red is the first equation, blue is the second.

What determines the solutions of a system of equations?

-No solution: the two lines will never intersect/does not intersect ever, which means that there are no set point where it satisfies both equations.

-One solution: the two lines intersect once and only once, meaning that there is that one set point where the x and y values both satisfy both equations.

-Multiple solutions: the two lines will intersect each other multiple times, meaning there are multiple set points where the x and y values satisfy both equations. You usually will not have to worry about these problem sets.

-Infinite solutions: the two lines are both the same line, which means every x and y value will satisfy both equations.

Looking at the solution attached, we can see that there are no places where a system of equations intersect, therefore ruling it that they have no solution.

And to answer your last question, an asymptote is a imaginary line in which a equation can approach closely and closely, but will never touch that imaginary line. Think of a line at y=\(\frac{1}{x}\). When you graph it, you can see that the two lines never ever EVER intersect the y-axis, or x=0; giving that x=0 as a vertical asymptote.

5 laps

400 meters each lap.

So, to answer this we have to multiply the number of laps by the length of each lap:

400 m x 5 = 2,000 meters

Then we have to convert into kilometers.

Since 1 km= 1000 meters

We have to divide the value in meters by 1000:

2,000 / 1,000 = 2 km

2 kilometers

Answer:

5 laps x 400m = 2000m = 2km

answer is 2 kilometres

Step-by-step explanation:

Answer: The form of payment that Courtney can lose and not get back would be cash.

Step-by-step explanation:

The reason why cash couldn't be returned back because it doesn't have a piece of U.S money wouldn't have a specific certified owner that they can be returned to.

Other forms of payment like credit cards, debit cards, and checks have specific bank information with the card holder's name on it so if Courtney actually lost one of those, she would be most likely to receive it back without any complicated  verification process.

Therefore, Courtney would not be able to receive her cash back if she accidentally loses it. Hope this helps you with your Imagine Math homework or assignment!

-From Certified 5th Grade Honors Student

Answer:

Let P(h,k) be the point which is equidistant from the point (2,4) and the y-axis. The distance of point P(h,k) from the y-axis is h. ∴h=√(h−2)2+(k−4)2⇒h2−4h−4+k2−8k+16=h2⇒k2−4h−8k+20=0.

Hence,the locus of (h,k)is y2−4x−8y+20=0.

Step-by-step explanation:

SOLUTION:

Step 1:

In this question, we are given the following:

Solve the following equations.

Express your answer as an ordered pair in the format (a,b) with no spaces between the numbers and symbols:

Step 2:

We multiply equation 1 by 2, so we have that:

Then, we evaluate equation 3 minus equation 4, we have that:

Next, we put the value of y = 1 in equation 1, we have that:

CONCLUSION:

In ordered pair, the value of:

The required solution is x = (25/11) × log(70/17).

It is required to give exact answers, not decimals.

Therefore, the given equation is 1.7(2.8)⁴ˣ = 7(4.6)ˣ.

This can be simplified as follow

s;1.7 × (2⁹/5)⁴ˣ = 7 × (2⁴⁶/10)⁽ˣ/⁵⁾

1.7 × 2³⁶ˣ/25 = 7 × 2²³ˣ/5

Now, divide both sides of the equation by 2^23x/5;

1.7 × 2⁽³⁶ˣ/²⁵ ⁻ ²³ˣ/⁵⁾= 7

Simplify the left side;

1.7 × 2⁽¹¹ˣ/²⁵⁾ = 7

Now, divide both sides by 1.7;

2⁽¹¹ˣ/²⁵⁾ = 70/17

Take log on both sides;

log(2⁽¹¹ˣ/²⁵⁾)) = log(70/17)11x/25 × log(2) =

log(70/17)x = (25/11) × log(70/17)

Thus, the required solution is x = (25/11) × log(70/17).

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X=22

Step 1: multiply both sides by 4

(.4x-2.8/4)•(4) = (1.5)(4)

.4x-2.8=6

Step 2: add 2.8 to both sides

.4x -2.8+2.8=6+2.8

.4x=8.8

Step 3: divide both sides by .4

.4x/.4=8.8/.4

X=22

To use data in the sample as much as possible while also forcing the null hypothesis to be true, one can conduct a permutation test or use bootstrapping. These approaches allow all information in the sample to be used while still ensuring the null hypothesis is true.

One way to use the data in the sample as much as possible while also forcing the null hypothesis to be true is by conducting a permutation test. This involves randomly permuting the labels of the sample without changing the sample size, and then recalculating the test statistic under the null hypothesis for each permutation.

By repeating this process many times, we can generate a null distribution of the test statistic and estimate the p-value of the observed test statistic based on its rank in the null distribution.

Another way is by using bootstrapping, which involves resampling the data with replacement from the sample to create multiple new samples, each with the same size as the original sample. The null hypothesis is then tested on each of these resampled datasets.

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The probability that a particular lightbulb will last from 2694 to 3583 hours is 0.8425 or 84.25%.

To convert our given data into a standard normal distribution, we will use the z-score formula:

z = (x - μ) / σ

Where:

x is the value we want to convert

μ is the mean of the distribution

σ is the standard deviation of the distribution

In this case, we want to find the z-scores for 2694 and 3583. Using the formula, we get:

z(2694) = (2694 - 2961) / 259 = -1.03

z(3583) = (3583 - 2961) / 259 = 2.41

Now, we need to find the area under the standard normal curve between these two z-scores. We can use a standard normal distribution table or a calculator to find this area.

Using a calculator, we can find the probability that a particular lightbulb will last from 2694 to 3583 hours by finding the difference between the cumulative probabilities of the two z-scores:

P(2694 < x < 3583) = P(-1.03 < z < 2.41) = P(z < 2.41) - P(z < -1.03)

= 0.9918 - 0.1493

= 0.8425

This means that if we were to randomly select a lightbulb from this brand, there is an 84.25% chance that it will last between 2694 and 3583 hours.

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The solution of the given differential equation by Laplace transform is \(y(t) = (1/4) (2/5) e^(5t/2) - (1/2) t + (3/2) e^(2t) - (1/2) e^(3t) with y(0) = 2 and y'(0) = 8.\)

The differential equation is \(D²y/dt² - 5 dy/dt + 6y = 18t - 15 with y(0) = 2 and y'(0) = 8.\)

We will solve it using Laplace Transform: Applying Laplace transform to both sides of the given differential equation gives

\(L{d²y/dt²}-5L{dy/dt}+6L{y}=L{18t}-L{15}\\ ⇒ L{d²y/dt²}-5L{dy/dt}+6L{y}=18L{t}-15L{1}\)

Since \(L{d²y/dt²} = s²Y(s) - sY(0) - Y'(0) and L{dy/dt} = sY(s) - Y(0)\), we get:\((s²Y(s) - sY(0) - Y'(0)) - 5(sY(s) - Y(0)) + 6Y(s) \\= 18/s² - 15/s∴ (s² - 5s + 6)Y(s) \\= 18/s² - 15/s + sY(0) + Y'(0)\)

Substituting the initial conditions, we get:(s² - 5s + 6)Y(s) = 18/s² - 15/s + 2s + 8

Differentiate both sides with respect to s, we get:\((s² - 5s + 6)(dY(s)/ds) + (2s - 5)(Y(s)) = - 36/s³ + 15/s² + 2\)

Applying partial fractions to the left-hand side, we get

\(A/(s - 2) + B/(s - 3)(s² - 5s + 6)(dY(s)/ds) + (2s - 5)(Y(s)) = - 36/s³ + 15/s² + 2 ……(1)\)

Multiplying both sides by \((s - 3)(s - 2), we get(s² - 5s + 6) [A(dY(s)/ds) + B] + (2s - 5)[(s - 3)Y(s)] = - 36(s - 3) + 15(s - 2) + 2(s - 3)(s - 2)\)

Since \((s² - 5s + 6) = (s - 2)(s - 3), we get(s - 2)(s - 3)[A(dY(s)/ds) + B] + (2s - 5)[(s - 3)Y(s)] = - 36(s - 3) + 15(s - 2) + 2(s - 3)(s - 2)\)

For s = 3, we get B = 6For s = 2, we get A = - 3

Substituting A and B in equation (1) and simplifying, we get: \(dY(s)/ds - 2Y(s) = - 2/s + 1/s² - 2/(s - 3) + 3/(s - 2)\)

Using integrating factor, e⁻²ᵗ, we get\(e⁻²ᵗ dY(s)/ds - 2e⁻²ᵗY(s) = e⁻²ᵗ (- 2/s + 1/s² - 2/(s - 3) + 3/(s - 2))\)

Integrating both sides with respect to s, we get\(Y(s) e⁻²ᵗ = (1/4) eᵗ/2 - (1/2)s⁻¹ + (3/2) (s - 1)⁻¹ - (1/2) (s - 3)⁻¹\)

Cancelling e⁻²ᵗ on both sides, we get\(Y(s) = (1/4) e^(5t/2) - (1/2)s⁻¹ e²ᵗ + (3/2) (s - 1)⁻¹ e²ᵗ - (1/2) (s - 3)⁻¹ e²ᵗ\)

Applying inverse Laplace transform on both sides, we get

\((t) = L⁻¹{Y(s)}= (1/4) L⁻¹{e^(5t/2)} - (1/2) L⁻¹{s⁻¹ e²ᵗ} + (3/2) L⁻¹{(s - 1)⁻¹ e²ᵗ} - (1/2) L⁻¹{(s - 3)⁻¹ e²ᵗ}=(1/4) (2/5) e^(5t/2) - (1/2) t + (3/2) e^(2t) - (1/2) e^(3t)\)

Hence, the solution of the given differential equation by Laplace transform is \(y(t) = (1/4) (2/5) e^(5t/2) - (1/2) t + (3/2) e^(2t) - (1/2) e^(3t) with y(0) = 2 and y'(0) = 8.\)

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Answer: 1 5/8

Step-by-step explanation: 3/4 times 2 on the denominator and numerator is 6/8 and 7/8 plus 6/8 is 1 whole and 5/8ths

Answer:

The diagram shows measures of some of the line segments in APQR. 4.5 /62.58° Q Length of QS P Area of APQR S ㅏ Use the given information to find the measures of the unknown angles and segment shown below. Round your answers to the nearest whole number. Length of PS units 6.4 -5.0- units R units²The diagram shows measures of some of the line segments in APQR. 4.5 /62.58° Q Length of QS P Area of APQR S ㅏ Use the given information to find the measures of the unknown angles and segment shown below. Round your answers to the nearest whole number. Length of PS units 6.4 -5.0- units R units²The diagram shows measures of some of the line segments in APQR. 4.5 /62.58° Q Length of QS P Area of APQR S ㅏ Use the given information to find the measures of the unknown angles and segment shown below. Round your answers to the nearest whole number. Length of PS units 6.4 -5.0- units R units²The diagram shows measures of some of the line segments in APQR. 4.5 /62.58° Q Length of QS P Area of APQR S ㅏ Use the given information to find the measures of the unknown angles and segment shown below. Round your answers to the nearest whole number. Length of PS units 6.4 -5.0- units R units²The diagram shows measures of some of the line segments in APQR. 4.5 /62.58° Q Length of QS P Area of APQR S ㅏ Use the given information to find the measures of the unknown angles and segment shown below. Round your answers to the nearest whole number. Length of PS units 6.4 -5.0- units R units²vvvThe diagram shows measures of some of the line segments in APQR. 4.5 /62.58° Q Length of QS P Area of APQR S ㅏ Use the given information to find the measures of the unknown angles and segment shown below. Round your answers to the nearest whole number. Length of PS units 6.4 -5.0- units R units²The diagram shows measures of some of the line segments in APQR. 4.5 /62.58° Q Length of QS P Area of APQR S ㅏ Use the given information to find the measures of the unknown angles and segment shown below. Round your answers to the nearest whole number. Length of PS units 6.4 -5.0- units R units²The diagram shows measures of some of the line segments in APQR. 4.5 /62.58° Q Length of QS P Area of APQR S ㅏ Use the given information to find the measures of the unknown angles and segment shown below. Round your answers to the nearest whole number. Length of PS units 6.4 -5.0- units R units²The diagram shows measures of some of the line segments in APQR. 4.5 /62.58° Q Length of QS P Area of APQR S ㅏ Use the given information to find the measures of the unknown angles and segment shown below. Round your answers to the nearest whole number. Length of PS units 6.4 -5.0- units R units²v

Step-by-step explanation:

its E and A

Answer:

The solutions to the inequality are B, E, and F: 25, 36, and 9.

Step-by-step explanation:

The solutions to the inequality √x < 10 are the values of x that make the inequality true when plugged in. To find these values, we can square both sides of the inequality:

√x < 10

x < 10^2 = 100

So, the values of x that make the inequality true are those that are less than 100. The options that satisfy this condition are:

A. 100 (not a solution)

B. 25 (solution)

C. -100 (not a solution)

D. 105 (not a solution)

E. 36 (solution)

F. 9 (solution)

Answer:

y=3x-1

Step-by-step explanation:

slope 3

.........

Answer:

the slope is 3

Step-by-step explanation:

trust me

hola buenas tardes como está el día de hoy ? yo estoy bien gracias por preguntar, espera...hablas español verdad...?

Answer: All real numbers

Step-by-step explanation: It is pretty simple. Just see if the x can be undefined. In this case x works with every number. So, it's all real numbers

The probability that a randomly selected person from the survey prefers bacon would be 60% in this example. However, without knowing the specific numbers, we cannot calculate the probability accurately.

To determine the probability that a randomly selected person from the survey prefers bacon, we need additional information such as the total number of respondents in the survey and the number of people who prefer bacon. Without this information, it is not possible to calculate the exact probability.

The probability can be calculated by dividing the number of people who prefer bacon by the total number of respondents in the survey. If the survey provides these specific numbers, we can use the formula:

Probability = Number of people who prefer bacon / Total number of respondents

For example, if the survey includes 100 respondents and 60 of them prefer bacon, the probability would be:

Probability = 60 / 100 = 0.6 or 60%

Therefore, the probability that a randomly selected person from the survey prefers bacon would be 60% in this example. However, without knowing the specific numbers, we cannot calculate the probability accurately.

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MN+NO=MO

Where N is the midpoint of MO

Therefore:

MN = NO

MN = 8

NO = 8

8 + 8 = MO

MO = 16

Now:

MO + OQ = MQ

If O is the midpoint of MQ:

MO = OQ

OQ = 16

Therefore:

MQ = 16 + 16 = 32

Answer: A

Step-by-step explanation:

Scientific notation exponents are in order from least to greatest and 8.1 > 6

Answer:

1.01 m8

Step-by-step explanation: